I'm trying to run a dyncamic query that returns all records within a specific distance of a certain point. The longitude and latitude of each record is stored in the database. The query is constructed from two dynamic variables $StartLatitude and $StartLongitude with represent the starting point.
I know that this may be a stupid question but I have yet to find the exact answer. Within the SSMS the servers are displayed in the registered servers. I register the server and then connect successfully. What I don't understand is although the server is running or the sql server agent is running the green dot with the white arrow is completely white. I can click on the server and look at the databases so I know that the server is running. This happens on remote servers and servers here at our location. Does anyone know why the white dot is not green with a white arrow? I'm just curious to know why this is like that. Thanks for any help you can provide.
Hi How do I get a nearest distance of a point? For example, I have two tables A and B and I want to find the nearest distance between the records of the two tables. In addition, one of the tables should also give me the distance. The data I have geo spatial data. Can this be done in SQL Help will be appreciated
My question may sound silly but I am new to data mining so I do not know much. Can I define a custom distance measure for a clustering algorithm ie. k-means ? I have created some clr utds and I want to try a clustering algorithm on them. Can I do this? How is the distance calculated ?
Hi, please, it is possible to know the edit distance used in the fuzzy lookup/grouping. On this forum I read fuzzy lookup use 4-gram with fix size. Does exist any document explaining how fuzzy lookup calculate the similarity? In other word, what kind of edit distance, algorithm is used by fuzzy lookup/grouping? I hope I was enough clear with my poor english. Thanks All
Is there a recommended practice for mirroring in regards to distance? Is it best practice to mirror with both nodes at the same physical location and use another method for failing over to a remote location or can one just put the other node in the mirror a few thousand miles away? I'm suspecting not.
I'm looking to find out how I'd go about setting up a database where avisitor to my site could punch in their postal code, and find out how farthey are from another postal code. For example, AutoTrader has this featureI believe to tell you how far the vehicle is from you. Dating sites havethem so you can do proximity searches.Anyone have any ideas where I could start? I'm thinking the post office,but if anyone else has suggestions, I'm open to hear them.Thanks!
I am new to data mining so please excuse my ignorance. Lets assume
- i have created a cluser model
- identified 3 clusters ( a, b, c)
- each record consists of 15 columns
- collecting new records( 15 variables) real time
what i would like to do is plot these new records programmatically as i collect them realtime. I assume this new record will belong to one of these three clusters. I believe we can find the cluster this new record belongs to by ' SELECT Cluster()....' and distance from the center of the cluster by ClusterDistance(). To plot this on a 2-dimentional space i need (x, y).
I am trying to use the haversine function to find the distance betweentwo points on a sphere, specifically two zip codes in my database. I'mneither horribly familiar with SQL syntax nor math equations :), so Iwas hoping I could get some help. Below is what I'm using and it is,as best as I can figure, the correct formula. It is not however,giving me correct results. Some are close, others don't seem right atall. Any ideas?SET @lat1 = RADIANS(@lat1)SET @log1 = RADIANS(@log1)SET @lat2 = RADIANS(@lat2)SET @log2 = RADIANS(@log2)SET @Dlat = ABS(@lat2 - @lat1)SET @Dlog = ABS(@log2 - @log1)SET @R = 3956 /*Approximate radius of earth in miles*/SET @A = SQUARE(SIN(@Dlat/2)) + COS(@lat1) * COS(@lat2) *SQUARE(SIN(@Dlog/2))SET @C = 2 * ATN2(SQRT(@A), SQRT(1 - @A))/*SET @C = 2 * ASIN(min(SQRT(@A))) Alternative calculation*/SET @distance = @R * @Cthnx,cjrsumner
See here www.merriampark.com/ld.htm for information about the algorithm. This page has a link (http://www.merriampark.com/ldtsql.htm) to a T-SQL implementation by Joseph Gama: unfortunately, that function doesn't work. There is a debugged version in the also-referenced package of TSQL functions (http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=502&lngWId=5), but this still has the fundamental problem that it only works on pairs of strings up to 49 characters.
CREATE FUNCTION edit_distance(@s1 nvarchar(3999), @s2 nvarchar(3999)) RETURNS int AS BEGIN DECLARE @s1_len int, @s2_len int, @i int, @j int, @s1_char nchar, @c int, @c_temp int, @cv0 varbinary(8000), @cv1 varbinary(8000) SELECT @s1_len = LEN(@s1), @s2_len = LEN(@s2), @cv1 = 0x0000, @j = 1, @i = 1, @c = 0 WHILE @j <= @s2_len SELECT @cv1 = @cv1 + CAST(@j AS binary(2)), @j = @j + 1 WHILE @i <= @s1_len BEGIN SELECT @s1_char = SUBSTRING(@s1, @i, 1), @c = @i, @cv0 = CAST(@i AS binary(2)), @j = 1 WHILE @j <= @s2_len BEGIN SET @c = @c + 1 SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j-1, 2) AS int) + CASE WHEN @s1_char = SUBSTRING(@s2, @j, 1) THEN 0 ELSE 1 END IF @c > @c_temp SET @c = @c_temp SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j+1, 2) AS int)+1 IF @c > @c_temp SET @c = @c_temp SELECT @cv0 = @cv0 + CAST(@c AS binary(2)), @j = @j + 1 END SELECT @cv1 = @cv0, @i = @i + 1 END RETURN @c END
I need to be able to take the latitude and logitude of two locations and compare then to determine the number of miles between each point. It doesn't need to account for elevation, but assumes a flat plane with lat and long.
Does anyone have any algorithms in T-SQL to do this?
Hi All, Does anyone have a Stored Procedure that works perfectly to retrieve all zipcodes within a specified zipcode and distance radius - a zipcode and radius is passed and the Store Procedure result shows all zipcodes that falls within that range.
This table contains invoices for both customers and vendors. Both invoices have $amounts . The customer invoices are duplicates which resuts in duplicate amount. How can I remove the duplicate amount from the customer side and keep a distinc invoice for customers .
hi, im currently on sql hell right now. im having a hard time learning this sql thingie....
...the thing is this: im currently using the book ASP.NET Unleashed and most of the examples there are on SQL. what i was trying to do before was convert everything to OleDb to fit the ms access which i have right now.
unfortunately, some of the codes seem not to work properly. maybe its because of im using OleDb...
so what i did was i downloaded the MSDE sp3 package and installed it on my PC. now that i have an sql server for my WebMatrix, i just dont know what to do next? i mean, where do i put the sql sample databases like northwind and pubs???
im really confused about this sql thing. i really hate it.
http://www.iqub.comThis is a wicked program . great price too ... Check it out....IQub Browser Professional Edition is a feature-rich applicationproviding online multidimensional analysis. By connecting directly toMicrosoft's SQL Server MS-OLAP/Analysis Server cubes, or to localcubes, you can explore large volumes of summarized data quickly andefficiently. With Professional Edition you can create local cubecopies from MS-OLAP/Analysis Server cubes, perfect for company widedistribution or taking on the road.CheersChris
I have two servers both with different collation. Server A being SQL_Latin1_General_CP1_CI_AS and the live server and Server B being Latin1_General_CI_AS and a dev server. Now i have a load of data on the dev which i'm query to see if its on the live server. select * from ServerA.Table1 where Col1 in (select Col1 from ServerB.Table1)
I get this Error message. Cannot resolve the collation conflict between "Latin1_General_CI_AS" and "SQL_Latin1_General_CP1_CI_AS" in the equal to operation.