Datetime Functions...

Dec 16, 2003

Hi all,





I have a problem with date functions...





In my program I use weeks, and with this variable I need to know which is the first day of the selected week...





For example... I put week 52 in my program... how I can obtain the first day of this week? -> (22/12/2003).





I have proved with this functions...





SET DATEFIRST 1 (to configure Monday as first day of week)





SELECT DATEADD(ww,DATEDIFF(ww,0,GETDATE()),0)





With this I have the day of the current week... but I can't put my week in this function... aarrgggg.





Please help me...





Thanks a lot.

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Serious SQL Server Datetime Functions Bug...

Jan 7, 2002

Can someone tell me if this is a SQL Server bug? I tried this in both
version 7 and 2000, the results are the same.

DECLARE @timeA DATETIME
DECLARE @timeB DATETIME
DECLARE @msDiff INT

SET @timeA = GETDATE()
SET @msDiff = 0

WHILE @msDiff <= 10
BEGIN
SET @timeB = DATEADD(ms,@msDiff,@timeA)
PRINT 'If adding ' + CONVERT(VARCHAR,@msDiff) + ' milliseconds to Time
B, then Time B is ' + CONVERT(VARCHAR,DATEDIFF(ms,@timeA,@timeB)) + '
millisecond greater than Time A'
SET @msDiff = @msDiff + 1
END

This seems like a serious bug if an application depends heavily on
milliseconds comparison.

Thanks,
Aiden

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Calling Functions In SQL (DateTime, Age, DateDif)

Apr 11, 2007

Hi, I am writing a stored proc that will so a very simple search for users in the database. In my database I am storing a birthday as a datetime column called 'bday'. Users can search for people between a certain age range; say 23 - 30.

Here is my search query:


alter procedure sp_wm_quickSearch
@lookingFor int,
@mySex int,
@country varchar(500),
@ageTo int,
@ageFrom int,
@state varchar(10),
@userid int

as

select * from
wm_user a
inner join
wm_user_details b
on
a.userid=b.userid
where
a.lookingfor = 0 and
a.sex = 1 and
a.country = 'United States of America' and
a.state = 'Washington'


I found a simple function that looks like it can do what i need it to do:


CREATE FUNCTION dbo.fnYearsApart
(
@FromDate DATETIME,
@ToDate DATETIME
)
RETURNS INT
AS
BEGIN
RETURN CASE
WHEN @FromDate > @ToDate THEN NULL
WHEN DATEPART(day, @FromDate) > DATEPART(day, @ToDate) THEN DATEDIFF(month, @FromDate, @ToDate) - 1
ELSE DATEDIFF(month, @FromDate, @ToDate)
END / 12
END



MY QUESTIONS IS THIS:

How do I call this function in my query and pass it the age, and use the age as a search param. I imagine it woudl look something like this:



select * from
wm_user a
inner join
wm_user_details b
on
a.userid=b.userid
where
a.lookingfor = 0 and
a.sex = 1 and
a.country = 'United States of America' and
a.state = 'Washington' and
fnYearsApart(a.bday, Some DateTime.Now function) < 24 and > 30



but this line doesn't work: (obviously i need to replace datetime.now

fnYearsApart(a.bday, Some DateTime.Now function) < 24 and > 30


Thanks!

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Random Integer, Sample, And Datetime Functions

Jul 23, 2006

Edit: There seems to be some interaction between GROUP BY/NEWID() that can cause problems if these functions are used directly in an aggregate query. Please read the posts on this thread about this, and use caution.


This script creates three functions, F_RANDOM_INTEGER, F_RANDOM_SAMPLE, and F_RANDOM_DATETIME. The last parameter of each function must be function NEWID() to generate the random number.

Theses functions are designed for applications where it is necessary to generate random integers, random datetimes, or take random samples from sets of data. Typical applications would be software testing, inventory control, auditing, and product quality testing.

Function F_RANDOM_INTEGER returns a random integer in the range of the input parameters so that the return value is >= @START_INT and <= @END_INT. It is valid for any range of two integer values.

Function F_RANDOM_SAMPLE returns a 1 or a 0 to determine if a sample should be selected, based on the input sample rate. Input parameter @SAMPLE_RATE should be between 1 and 999,999. The sample rate determines how many samples should be selected out of each 1,000,000 samples. A sample rate below 1 will never select a sample, and a sample rate above 999,999 will always select a sample. A sample rate of 1,000 = 0.1%, 50,000 = 5%, 63,775 = 6.3775%, 100,000 = 10%, and 500,000 = 50%.

F_RANDOM_DATETIME returns a random datetime value >= @START_TIME and < @END_TIME. It is valid for any datetime range. Input parameters default, if null, to @START_TIME = '19000101' and @END_TIME = '19000102’. The datetime is random to the level of clock ticks (1/300 of as second). Note that the latest time is not included in the range of datatime values that can be returned. This is to allow selection of times within adjacent time periods, without having to specify times to the level of milliseconds. This means a range of 1990-12-01 01:00:00.000 through 1990-12-01 02:00:00.000 will never return a value of 1990-12-01 02:00:00.000.

The NEWID() function is the basis of the random numbers. These functions should not to be considered random for purposes of data encryption or other high security applications. However, they should be adequate for business applications of the types mentioned above. I conducted extensive testing with the functions where I generated millions of results, analyzed the results various ways to look for non-random patterns, and I saw no evidence of non-random results.

The script also includes a demo of each function, and sample output from the demos is also included.

The demo script uses the number table function, F_TABLE_NUMBER_RANGE, available on this link:
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=47685





if objectproperty(object_id('dbo.F_RANDOM_INTEGER'),'IsScalarFunction') = 1
begin drop function dbo.F_RANDOM_INTEGER end
go
create function dbo.F_RANDOM_INTEGER
(
@START_INTint,
@END_INTint,
@NEWIDuniqueidentifier
)
returns
int
as
/*
Function: F_RANDOM_INTEGER

This function returns a random integer
value >= @START_INT and <= @END_INT.

Valid for any integer range.

Requires newid() to be input parameter @NEWID
to generate the random number.

-- Return random integer between -100, 200000
select [Random Integer] =
[dbo].[F_RANDOM_INTEGER](-100, 200000,newid())
*/
begin

declare @sn bigint
declare @en bigint
declare @mod bigint
declare @rand_bigint bigint
declare @rand_result int

-- Set default values for input dates if they are null
if @START_INT is null begin set @START_INT = 0 end
if @END_INT is null begin set @END_INT =1000000 end

-- Set order of input parameters so that return value is always
-- the same no matter what order the input values are passed.
if @START_INT > @END_INT
select @sn = @END_INT, @en = @START_INT
else
select @sn = @START_INT, @en = @END_INT

-- Return start int if start int = end int
if @sn = @en return @sn

-- Get modulus
select @mod = @en-@sn+1

-- Get random bigint from input parameter @NEWID
select @rand_bigint = abs(convert(bigint,convert(varbinary(20),@NEWID)))


-- Get random integer
select @rand_result = @sn+(@rand_bigint%@mod)

return @rand_result

end
go
grant execute on dbo.F_RANDOM_INTEGER to public
go

if objectproperty(object_id('dbo.F_RANDOM_SAMPLE'),'IsScalarFunction') = 1
begin drop function dbo.F_RANDOM_SAMPLE end
go
create function dbo.F_RANDOM_SAMPLE
(
@SAMPLE_RATEint,
@NEWIDuniqueidentifier
)
returns
int
as
/*
Function: F_RANDOM_SAMPLE

This function returns a 1 or a 0 to determine if a sample
should be selected, based on the sample rate. It is designed
to select random samples at a specific rate.

Input parameter @SAMPLE_RATE should be between 1 and 999,999.
The sample rate determines how many samples should be
selected out of each 1,000,000 samples. A sample rate below 1
will never select a sample, and a sample rate above 999,999 will
always select a sample. 1,000 = 0.1%, 50,000 = 5%, 63,775 = 6.3775%,
100,000 = 10%, and 500,000 = 50%

Requires newid() to be input parameter @NEWID
to generate the random number.

-- Select sample 200,000 times in 1,000,000 samples (20%)
select [Random Sample] =
[dbo].[F_RANDOM_SAMPLE](200000,newid())
*/
begin

declare @rand_bigint bigint

-- Get random bigint from @NEWID
select @rand_bigint = abs(convert(bigint,convert(varbinary(20),@NEWID)))


-- Select sample if the modulus of @rand_bigint is less than the sample rate
return case when @rand_bigint%1000000 < @SAMPLE_RATE then 1 else 0 end

end
go
grant execute on dbo.F_RANDOM_SAMPLE to public
go

if objectproperty(object_id('dbo.F_RANDOM_DATETIME'),'IsScalarFunction') = 1
begin drop function dbo.F_RANDOM_DATETIME end
go
create function dbo.F_RANDOM_DATETIME
(
@START_TIMEdatetime,
@END_TIMEdatetime,
@NEWIDuniqueidentifier
)
returns
datetime
as
/*
Function: F_RANDOM_DATETIME

This function returns a random datetime
value >= @START_TIME and < @END_TIME.

Valid for any datetime range.

Input parameters default, if null, to:
@START_TIME'19000101'
@END_TIME'19000102'

Requires newid() to be input parameter @NEWID
to generate the random number.

-- Return random time between 08:30 and 12:00
select [Random Time] =
[dbo].[F_RANDOM_DATETIME]('08:30:00.000','12:00:00.000',newid())
*/
begin

declare @st datetime
declare @et datetime

declare @hours int
declare @ms int
declare @ticks bigint
declare @rand_ticks bigint
declare @rand_bigint bigint

declare @remaining_ticks int
declare @return_hours int
declare @return_ms int

-- Set default values for input dates if they are null
if @START_TIME is null begin set @START_TIME = '19000101' end
if @END_TIME is null begin set @END_TIME = '19000102' end

-- Set order of input parameters so that return value is always
-- the same no matter what order the input values are passed.
if @START_TIME > @END_TIME
select @st = @END_TIME, @et = @START_TIME
else
select @st = @START_TIME, @et = @END_TIME

-- Return start time if start time = end time
if @st = @et return @st

-- Get hours boundary difference.
-- Subtract 1 from diff, before dividing by 2 and multiplying by 2
-- so the milliseconds remaining is always positive and
-- hours is always >= zero.
set @hours = ((datediff(hh,@st,@et)-1)/2)*2

-- Get remainder milliseconds
set @ms = datediff(ms,0,@et-dateadd(hh,@hours,@st))

-- Convert remainder milliseconds to
-- SQL Server 'clock ticks' of 1/300 of a second
set @ticks = ((@ms/10)*3) + ((@ms%10)/3)

-- Add hours * tick per hour (3600*300) to give total
-- ticks between @START_TIME and @END_TIME
set @ticks = @ticks + (@hours * 0000001080000 )

-- Get random bigint from input parameter @NEWID
select @rand_bigint = abs(convert(bigint,convert(varbinary(20),@NEWID)))

-- Get random number of ticks
select @rand_ticks = @rand_bigint%@ticks

-- Get hours component of random ticks
select @return_hours = @rand_ticks/1080000

-- Get left over ticks after removing hours.
select @remaining_ticks = @rand_ticks%1080000

--Convert remaining clock ticks back to milliseconds
select @return_ms = ((@remaining_ticks/3)*10) + floor(((@remaining_ticks%3)*3.5))

-- Return the random time between the start and end time
return dateadd(ms,@return_ms,dateadd(hh,@return_hours,@st))

end
go
grant execute on dbo.F_RANDOM_DATETIME to public
go

print '-----------------------------------------------------------------'
print ' Demo F_RANDOM_INTEGER function'
print '-----------------------------------------------------------------'
print ''

declare @t table ([Random Integer] int not null )

insert into @t
select
-- Get integert in range of 1 to 10,000,000
[Random Integer] =
[dbo].[F_RANDOM_INTEGER](1,10000000,newid() )
from
-- Function F_TABLE_NUMBER_RANGE
-- available in Script Library forum
F_TABLE_NUMBER_RANGE(1,100000)


select
[Right Int] = [Random Integer]%10,
[Count] = count(*)
from
@t a
group by
[Random Integer]%10
order by
1,2

select
[Million Range] = [Random Integer]/1000000,
[Count] = count(*)
from
@t a
group by
[Random Integer]/1000000
order by
1,2

go
print '-----------------------------------------------------------------'
print ' Demo F_RANDOM_SAMPLE function'
print '-----------------------------------------------------------------'
print ''

declare @t table ([Sample Taken] int not null )

insert into @t
select
-- Sample rate = 6.3775%
[Sample Taken] = [dbo].[F_RANDOM_SAMPLE](63775,newid())
from
-- Function F_TABLE_NUMBER_RANGE
-- available in Script Library forum
F_TABLE_NUMBER_RANGE(1,100000)

select
[Sample Taken],
[Result Count] = count(*)
from
@t a
group by
[Sample Taken]
order by
1,2


go

print '-----------------------------------------------------------------'
print ' Demo F_RANDOM_DATETIME function'
print '-----------------------------------------------------------------'
print ''
select
Random_Datetime =
convert(varchar(23),[dbo].[F_RANDOM_DATETIME]( a.ST, a.ET,newid() ) ,121) ,
[Start] = convert(varchar(23),a.ST ,121) ,
[End] = convert(varchar(23),a.ET ,121) ,
a.Comment
from
(
select ST = getdate(), ET = getdate()+2 ,
Comment = 'Now thru 2 days from now' union all
select '20060101', '20060102' , 'One day diff' union all
select '20030101', '20030101' ,'Both times same' union all
select '20030101', '20030108' ,'One week diff' union all
select '20021228', '20030104' ,'One week diff' union all
select '20010701', '20010713' ,'12 day diff' union all
select '20010701', '20010714' ,'13 day diff' union all
select '20010630', '20010713' ,'13 day diff' union all
select '19901201 01:00:00.000', '19901201 02:00:00.000' ,'1 hour diff' union all
select '19901201 01:00:33.003', '19901201 02:00:33.003' ,'1 hour diff' union all
select '19901201 01:00:00.000', '19901201 01:30:00.000' ,'30 min diff' union all
select '19901201 01:00:33.447', '19901201 01:30:33.447' ,'30 min diff' union all
select '19901201 01:00:00.000', '19901201 01:05:00.000' ,'5 min diff' union all
select '19901201 01:00:29.123', '19901201 01:05:29.123' ,'5 min diff' union all
select '19901201 01:00:00.000', '19901201 01:01:00.000' ,'1 min diff' union all
select '19901201 01:00:00.000', '19901201 01:00:01.000' ,'1 sec diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.100' ,'100 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.050' ,'50 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.023' ,'23 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.020' ,'20 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.013' ,'13 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.010' ,'10 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.007' ,'7 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.003' ,'3 ms diff' union all
select '20030101', '20030201' ,'One month diff 31 days' union all
select '20030101', '20040101' ,'One year diff' union all
select '20050101', '20070101' ,'Two year diff' union all
select '20060101', '20060301' ,'2 month diff' union all
select null, '20060101' ,'Start time null' union all
select '20060102', null ,'End time null' union all
select null, null ,'Both null' union all
select '17530101', '99991231 23:59:59.997' ,'Max datetime diff' union all
select '99991231 23:59:59.997','17530101' ,'Max datetime diff reversed'
) a


Demo Results:


-----------------------------------------------------------------
Demo F_RANDOM_INTEGER function
-----------------------------------------------------------------


(100000 row(s) affected)

Right Int Count
----------- -----------
0 9929
1 10055
2 10009
3 10082
4 9919
5 10022
6 9914
7 9985
8 10098
9 9987

(10 row(s) affected)

Million Range Count
------------- -----------
0 10009
1 9985
2 10142
3 10047
4 9967
5 9907
6 10078
7 10071
8 9790
9 10004

(10 row(s) affected)

-----------------------------------------------------------------
Demo F_RANDOM_SAMPLE function
-----------------------------------------------------------------


(100000 row(s) affected)

Sample Taken Result Count
------------ ------------
0 93669
1 6331

(2 row(s) affected)

-----------------------------------------------------------------
Demo F_RANDOM_DATETIME function
-----------------------------------------------------------------

Random_Datetime Start End Comment
----------------------- ----------------------- ----------------------- --------------------------
2006-07-24 08:21:22.593 2006-07-23 17:54:47.283 2006-07-25 17:54:47.283 Now thru 2 days from now
2006-01-01 06:44:36.897 2006-01-01 00:00:00.000 2006-01-02 00:00:00.000 One day diff
2003-01-01 00:00:00.000 2003-01-01 00:00:00.000 2003-01-01 00:00:00.000 Both times same
2003-01-05 01:57:02.183 2003-01-01 00:00:00.000 2003-01-08 00:00:00.000 One week diff
2003-01-01 20:02:05.550 2002-12-28 00:00:00.000 2003-01-04 00:00:00.000 One week diff
2001-07-02 11:35:11.147 2001-07-01 00:00:00.000 2001-07-13 00:00:00.000 12 day diff
2001-07-02 16:39:57.433 2001-07-01 00:00:00.000 2001-07-14 00:00:00.000 13 day diff
2001-07-06 12:33:53.087 2001-06-30 00:00:00.000 2001-07-13 00:00:00.000 13 day diff
1990-12-01 01:15:42.530 1990-12-01 01:00:00.000 1990-12-01 02:00:00.000 1 hour diff
1990-12-01 01:02:21.647 1990-12-01 01:00:33.003 1990-12-01 02:00:33.003 1 hour diff
1990-12-01 01:21:06.267 1990-12-01 01:00:00.000 1990-12-01 01:30:00.000 30 min diff
1990-12-01 01:26:17.983 1990-12-01 01:00:33.447 1990-12-01 01:30:33.447 30 min diff
1990-12-01 01:00:56.327 1990-12-01 01:00:00.000 1990-12-01 01:05:00.000 5 min diff
1990-12-01 01:03:20.423 1990-12-01 01:00:29.123 1990-12-01 01:05:29.123 5 min diff
1990-12-01 01:00:21.617 1990-12-01 01:00:00.000 1990-12-01 01:01:00.000 1 min diff
1990-12-01 01:00:00.443 1990-12-01 01:00:00.000 1990-12-01 01:00:01.000 1 sec diff
1990-12-01 01:00:00.050 1990-12-01 01:00:00.000 1990-12-01 01:00:00.100 100 ms diff
1990-12-01 01:00:00.000 1990-12-01 01:00:00.000 1990-12-01 01:00:00.050 50 ms diff
1990-12-01 01:00:00.010 1990-12-01 01:00:00.000 1990-12-01 01:00:00.023 23 ms diff
1990-12-01 01:00:00.017 1990-12-01 01:00:00.000 1990-12-01 01:00:00.020 20 ms diff
1990-12-01 01:00:00.007 1990-12-01 01:00:00.000 1990-12-01 01:00:00.013 13 ms diff
1990-12-01 01:00:00.000 1990-12-01 01:00:00.000 1990-12-01 01:00:00.010 10 ms diff
1990-12-01 01:00:00.003 1990-12-01 01:00:00.000 1990-12-01 01:00:00.007 7 ms diff
1990-12-01 01:00:00.000 1990-12-01 01:00:00.000 1990-12-01 01:00:00.003 3 ms diff
2003-01-14 09:00:09.520 2003-01-01 00:00:00.000 2003-02-01 00:00:00.000 One month diff 31 days
2003-08-27 11:47:04.100 2003-01-01 00:00:00.000 2004-01-01 00:00:00.000 One year diff
2006-11-23 03:57:21.737 2005-01-01 00:00:00.000 2007-01-01 00:00:00.000 Two year diff
2006-01-12 08:50:40.717 2006-01-01 00:00:00.000 2006-03-01 00:00:00.000 2 month diff
1933-11-15 13:39:10.050 NULL 2006-01-01 00:00:00.000 Start time null
1997-05-28 06:42:32.407 2006-01-02 00:00:00.000 NULL End time null
1900-01-01 01:50:42.743 NULL NULL Both null
2758-10-18 13:50:47.987 1753-01-01 00:00:00.000 9999-12-31 23:59:59.997 Max datetime diff
8426-03-24 13:51:08.407 9999-12-31 23:59:59.997 1753-01-01 00:00:00.000 Max datetime diff reversed

(33 row(s) affected)





CODO ERGO SUM

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SQL Server 2005: CLR Functions Vs SQL Functions

May 26, 2006

I was playing around with the new SQL 2005 CLR functionality andremembered this discussion that I had with Erland Sommarskog concerningperformance of scalar UDFs some time ago (See "Calling sp_oa* infunction" in this newsgroup). In that discussion, Erland made thefollowing comment about UDFs in SQL 2005:[color=blue][color=green]>>The good news is that in SQL 2005, Microsoft has addressed several of[/color][/color]these issues, and the cost of a UDF is not as severe there. In fact fora complex expression, a UDF in written a CLR language may be fasterthanthe corresponding expression using built-in T-SQL functions.<<I thought the I would put this to the test using some of the same SQLas before, but adding a simple scalar CLR UDF into the mix. The testinvolved querying a simple table with about 300,000 rows. Thescenarios are as follows:(A) Use a simple CASE function to calculate a column(B) Use a simple CASE function to calculate a column and as a criterionin the WHERE clause(C) Use a scalar UDF to calculate a column(D) Use a scalar UDF to calculate a column and as a criterion in theWHERE clause(E) Use a scalar CLR UDF to calculate a column(F) Use a scalar CLR UDF to calculate a column and as a criterion inthe WHERE clauseA sample of the results is as follows (time in milliseconds):(295310 row(s) affected)A: 1563(150003 row(s) affected)B: 906(295310 row(s) affected)C: 2703(150003 row(s) affected)D: 2533(295310 row(s) affected)E: 2060(150003 row(s) affected)F: 2190The scalar CLR UDF function was significantly faster than the classicscalar UDF, even for this very simple function. Perhaps a more complexfunction would have shown even a greater difference. Based on this, Imust conclude that Erland was right. Of course, it's still faster tostick with basic built-in functions like CASE.In another test, I decided to run some queries to compare built-inaggregates vs. a couple of simple CLR aggregates as follows:(G) Calculate averages by group using the built-in AVG aggregate(H) Calculate averages by group using a CLR aggregate that similatesthe built-in AVG aggregate(I) Calculate a "trimmed" average by group (average excluding highestand lowest values) using built-in aggregates(J) Calculate a "trimmed" average by group using a CLR aggregatespecially designed for this purposeA sample of the results is as follows (time in milliseconds):(59 row(s) affected)G: 313(59 row(s) affected)H: 890(59 row(s) affected)I: 216(59 row(s) affected)J: 846It seems that the CLR aggregates came with a significant performancepenalty over the built-in aggregates. Perhaps they would pay off if Iwere attempting a very complex type of aggregation. However, at thispoint I'm going to shy away from using these unless I can't find a wayto do the calculation with standard SQL.In a way, I'm happy that basic SQL still seems to be the fastest way toget things done. 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=========================
sqlceoledb30.dll 00CB0000 35000 A
sqlceca30.dll 00CF0000 75000 A
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=========================
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