# Round To Nearest WHOLE Number

Nov 16, 2006T-SQL:

How to round to the nearest WHOLE number ?

so

from -- to

-------------

170 --170

96.58 --97

thanks

T-SQL:

How to round to the nearest WHOLE number ?

so

from -- to

-------------

170 --170

96.58 --97

thanks

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I have a column called as NDM$ What I want do it round it the nearest value example I am giving below

34.100->34%

39.8->40

35.4->35 some thing like that.

how to round a datetime variable to the nearest second. The solution must NOT just strip off the milliseconds, it needs to round.

Also, the solution should not be too cumbersome because it will be used in a high volume environment.

OK, this is the scenario. I have a database with many columns ( each a mean value and a standard deviation, and with it a set of coordinates that i want to retrieve ).

Then i have a value that i want to query with the database, by comparing it with the mean and its standard deviation, and it should return a few sets (lets say 2) of coordinates whereby the the value of the mean is closet to the one in the database, in order of nearest value. How should i do it, since i am not using the exact value of the mean in the database?

I know its a bit confusing the way i wrote, but anyone understand wat i am trying to say and can help, i am very grateful. I had googled around for answers but cannot find. Thanks.

How do I write sql syntax to round the last digit. For example, 12.152 should be 12.15. My current sql syntax does not round the last digit as follows:

Select tblARInvoiceDetail.UnitPrice * tblARInvoiceDetail.Quantity AS ChargeBeforeDiscount

FROM tblARInvoices INNER JOIN

tblARInvoiceDetail ON

tblARInvoices.ARInvoiceID = tblARInvoiceDetail.ARInvoiceID

The tblARInvoiceDetail.UnitPrice column is numeric;length 9;precision 18

The Quantity column is integer;length 4; precision 10;scale 0

Any Suggestions?

Thanks,

Denise

Dear Programmers,

I want to store a number of .NET type double (16,95) into the database

column of type numeric, but it is stored as integer (17) and when I call the

value in my application, it is displayed as 17. How can I solve this

problem? Thanks in advance,

Burak

How can I round up a decimal number? in SSRS reports.

View 7 Replies View RelatedHi all,

I am sorry if i am posting this error in an inappropriate froum.

Well in my asp.net intranet web application i want to enter a number to the database(sql sever 2005) that has a column(schoolkm) whose type is decimal(9, 2). Now if i want to enter the value 1.5 in the text box and enter that value to the database through interface then that value automatically rounds to 2. But when i get into the table and enter that value by hand then that value enters perfectly i.e. without rounding of. I want to know the reason and how can i cure this problem.

Regards & thanks in advance

Anybody noticed that SQL Server rounds up if the value is half waybetween two rounded values, but C#'s Decimal.Round(Decimal,Int32)rounds to nearest even number?[color=blue]>From MSDN: "When d is exactly halfway between two rounded values, the[/color]result is the rounded value that has an even digit in the far rightdecimal position. For example, when rounded to two decimals, the value2.345 becomes 2.34 and the value 2.355 becomes 2.36. This process isknown as rounding toward even, or rounding to nearest."I perform the same calculation sometimes on the web server in C# andsometimes at the database in T-SQL, but want to get the same resultfrom both calculations. Could anybody offer any strategies for dealingwith this?Thanks ~ Matt

View 3 Replies View RelatedHi

How do I get a nearest distance of a point? For example, I have two tables A and B and I want to find the nearest distance between the records of the two tables. In addition, one of the tables should also give me the distance. The data I have geo spatial data. Can this be done in SQL

Help will be appreciated

Hi, I'm making a birthdays database where I want to list everyone in it ordered by the firstcoming birthdays according to the current date.

I have all the birthday records stored in a table called bursdager and the person name is stored in the navn column and the persons birthday date is stored in the dato column.

I'm having some problems, currently I have this statement:

Code:

DECLARE @tbl TABLE (navn VARCHAR(60), dato DATETIME)

INSERT INTO @tbl

SELECT navn, dato FROM bursdager

WHERE DATEPART(month, dato) >= DATEPART(month, getdate())

ORDER BY DATEPART(month, dato), DATEPART(day, dato)

INSERT INTO @tbl -- those are the one who allready have had birthday this year

SELECT navn, dato FROM bursdager

WHERE DATEPART(month, dato) < DATEPART(month, getdate())

ORDER BY DATEPART(month, dato), DATEPART(day, dato)

SELECT * FROM @tbl

It works *allmost* as it should-- except, it still lists the last persons who had birthday first, even the days after their birthday if the month is still the same.

I thought about adding an additional check:

Code:

AND DATEPART(day, dato) >= DATEPART(day, getdate())

in the WHERE clause of the SELECT statement but that won't be correct either because it then just lists everyone based on whether the day number the person was born is higher or less than the day number of the current date.

Anyone have any suggestions? Is there an easier way to do it?

Dag

Hi

Which parameter value for the Round function do I need to pass to get it to round to the nearest thousand ?

Thanks,

Neil

I have a field with seconds in it and I need to disply it in hours which I can do by dividing it by 3600, but I am trying to figure out how to round it up to the nearest 15 minutes. I have tried a couple of things with ROUND and CEILING, but am not getting the right numbers back. Any help would be greatly appreciated.

View 3 Replies View RelatedHow would I match datetimes in records structured as follows:

Code:

Record1 AccountNo StartDateTime EndDateTime

1 1234 4/30/2012 8:00 AM NULL

2 1234 NULL 5/15/2012 8:00 AM

Desired Result:

Code:

AccountNo StartDateTime EndDateTime

1234 4/30/2012 8:00 AM 5/15/2012 8:00 AM

Of course there are multiple accounts, about 2100 in this case but they very by time periods, and multiple start and stop dates for an account. I need to get the start times and match them w/ the nearest end times but AFTER the value of the start time. Nearest end times must be forced to correspond to the nearest start time but there are some start times w/o end times and end times w/o start times due to user data entry errors. I need a solution that handles this. It is ok w/ the customer to make the assumption of nearest times supposedly going together so they can show the users the errors. I am on SQL Server 2008 R2.

I have the following tableCREATE TABLE Readings(ReadingTime DATETIME NOT NULL DEFAULT(GETDATE()) PRIMARY KEY,Reading int NOT NULL)INSERT INTO Readings (ReadingTime, Reading) VALUES ('20050101', 1)INSERT INTO Readings (ReadingTime, Reading) VALUES ('20050201', 12)INSERT INTO Readings (ReadingTime, Reading) VALUES ('20050301', 15)INSERT INTO Readings (ReadingTime, Reading) VALUES ('20050401', 31)INSERT INTO Readings (ReadingTime, Reading) VALUES ('20050801', 51)INSERT INTO Readings (ReadingTime, Reading) VALUES ('20051101', 106)GO-- list the tableSELECT ReadingTime, Reading FROM ReadingsGOIt is a table of readings of a free-running counter that istime-stamped. I need to determine the value of the reading thatcorresponds to the closest date to the supplied dateAre there more optimal/efficient ways of accomplishing this than thefollowing?DECLARE @when DATETIMESET @when = '20050505'SELECT TOP 1 ReadingTime, Reading FROM ReadingsORDER BY abs(DATEDIFF(minute, ReadingTime, @when))The above gives me the desired result of ('20050401', 31).Any suggestions would be appreciated

View 1 Replies View RelatedHi,

I have such a scenario:

- two tables with record containing car vehicle number, datetime of message and other data like weight ect.

- first table contains only two messages for one car per one day

- second has many messages for one car for one day

I would like to get a list of messages from first table but joined with the nearest (previous) record for the same car from second table.

Thanks,

Przemo

I have a date (my birthday). I would like to find the closest birthdays to mine, both before and after my birthday. I would like to list the people in my database who are the closest age to me, but in that order. So sorting my table by age and taking a row below and above my birthday is not going to work. This is because the three people below me may all have their birthday the next day, while those above me may have theirs years before mine.

Birthdays sorted by date:

05/10/1979 jim

12/01/1980 bob

10/04/1983 mike

10/05/1983 larry

11/21/1983 dan

12/07/1984 josh

05/07/1999 dylan

The order I wish to achieve is:

10/05/1983 larry

11/21/1983 dan

12/07/1984 josh

12/01/1980 bob

05/10/1979 jim

05/07/1999 dylan

Thanks in advance.

Mike

I have a table with 257 mil records with latitude and longitude data.

My goal is to find the closest intersecting values from a locations table (88 rows) and update any of the 257 mil records that are applicable with the location_Name and Location_Group_Name.

The query I have works but doesn't perform well on such a big data set.

CREATE TABLE #Positions -- Base table 257 mil rows. Actual table has 20 columns

(

IDBigInt PRIMARY KEY,

LatitudeDec(10,6),

LongitudeDec(10,6),

[Code] ....

Attached you will find the tables, test data, a function to measure distance and some queries that work but are too slow for this much data.

how to round the nearest value after round of decimal and return integer.

declare @data decimal(18,2)

set @data = 5.55

-- output

select '5'

set @data = 5.58

-- output

select '6'

Table :

ChangeID ChangeDate EquipmentID ModuleID EquipStatus

1 12/9/08 230 1789 Normal

2 13/9/08 450 1245 Normal

3 17/9/08 230 1789 Open

4 21/9/08 230 1899 Open

5 21/9/08 450 1674 Normal

6 22/9/08 450 2364 Normal

Given a date, what module was each equipment item in on that date?How do I get the date of the nearest previous event from a list like this? I got a query from one of the post in this Forum only using Cross Apply to find the nearest record from the above table based on Date i.e.

SELECT outerT.*

FROM your_table AS outerT

CROSS APPLY

(

SELECT TOP 1

equipment_id

, change_date

FROM your_table AS innerT

WHERE innerT.change_date <= @point_in_time

AND innerT.equipment_id = outerT.equipment_id

ORDER BY change_date DESC

) AS applicable_records

WHERE applicable_records.change_date = outerT.change_date

The problem is I need to get this query without using Cross Apply as i need to use the same for the LINQ which doesn't support Cross Apply.

I am getting the time difference between two dates using

DATEDIFF(second,Information.[Start Time],Information.[End Time]) / 60.00 / 60.00 AS hours,

My output looks like

1.33

0.17

1.50

etc

I'd like to round to the nearest quarter hour

1.50

0.25

.150

etc

I found in another forum that if I take the seconds and divide them by 15 then round up and multiply them by 4 I can get this done, but I can't figure out how to work it into my select statement. Anyhelp would be greatly appreciated. dbo.SLPTRANS.TimeSpent is the field I am trying to convert.

SELECT dbo.SLPTRANS.ClientID, SUM(dbo.SLPTRANS.TransValue) AS Expr1, dbo.SLPTRANS.TimeSpent AS Expr2

FROM dbo.SLPTRANS INNER JOIN

dbo.INVOICE ON dbo.SLPTRANS.InvoiceID = dbo.INVOICE.RecordID

GROUP BY dbo.SLPTRANS.ClientID

HAVING (dbo.SLPTRANS.ClientID = 405)

Is there a way that I can do this at the table level to automatically handle the rounding of seconds, etc. down to the minute automatically without having to use a trigger?

Here is a very basic example of what I am trying to do:

--example: '09-22-2007 15:07:18.850' this is the value inserted into the table by the code

select getdate()

--example: '2007-09-22 15:07:00.000' this is the value I want to store in the table

select dateadd(mi, datediff(mi, 0, getdate()), 0)

X is a float and I need to perform x/10 and round the result up to the integer. So if result is 0.4 -> 1, if 1.1 -> 2. How can I do this with SQL?

View 1 Replies View RelatedI want to do a simple thing but it seems to be behaving not as i am expectingI want to round number either up or down....e.g: 4.3 should round to 4 4.7 should round to 5when i use the round function like this: 83/17=4.88round( 83/17 , 0 ) it gives the answer as 4....when i was expecting it to be 5.... i know there is a ceiling function...but depending on the value of the division sometimes i want it to round up and sometimes round down. how can i do this? hope this makes sense. thanks

View 3 Replies View RelatedHas anyone been experiencing problems with rounding to 2 decimal places in SQL 7? I have a bunch of queries that generate web reports. Under 6.5 everything was fine. Now under 7.0 any number that needs to be rounded to 2 decimals is actually giving me several decimal places.

Here is a simplified version of what I am doing:

DECLARE @x real

DECLARE @y real

SELECT @x = 223.1

SELECT @y = 59.7

SELECT ROUND((@x/@y),2)

Result should be 3.74. But instead I am getting 3.7400000000000002

If anybody has heard if Microsoft has declared this as a known bug please let me know.

Thanks for your time.

I have the statement below which I use in an update

select (round(sum(tottime/60),2)) as ttime from vw_cms_suptime

where vw_cms_suptime.[tracking number] = 970

tracking.[tracking number]

Even though I have the round the statement returns a value

of 5.0000000000000003E-2

Is there something wrong with the round?

Hi,

I need to display the value of a certain varible rounded to two digits after decimal.

For example :

value of a is 1346.8500

I need to get the value of a as 1346.85

Please help me

hi,i have one criteria

if if i have time as 1:15 min means it has to show 1:15,if i have 1:20 min it has too be rounded and it has to show 1:30 min.

can any one give me query for this

thanks in anvance

How to round off the value .579 into .6 using round function.i tried doing it but in vain.

View 3 Replies View Relatedhow do i round off value 0.23 to 0.2.

i am using this inside a scalar function and the return type is numeric(6,2).

so how do i get 0.2 and not 0.23

Hi

I have datacloum called 'price' (float) and using the below code in my stored procedure

cast(price * 1.175 as decimal(19, 2)) as [item-price]

I am getting the price as (ex1: 23.58, ex2: 114.25, ....etc)

So How do I round the value(price) to (ex1: 23.99, ex2: 114.99)

Advance thanks

i want to round off 0.23 to 0.25 ,i am trying it with round function but can't get it.

View 3 Replies View Related
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