Query Wont Work
PHP Code:
if(mysql_query("UPDATE users SET referer_score=referer_score+1 WHERE userID='$frommysql_referer'"))
{
die(mysql_affected_rows());
im trying to figure out why refer_score isnt being iincremented as im expecting it to. i know that the value of $frommysql_referer is the right value that im expecting it to be. just it wont increment referer_score. and mysql_affected_rows() wont print anythnig to the screen
View Complete Forum Thread with Replies
Related Forum Messages:
What Query Would Work For This?
I have two tables: say Yes and No. Yes(ID, YesEmail, EmailOwner); No(ID, NoEmail); Both YesEmail and NoEmail contain email addresses. What query can retrieve all the email addresses in Yes table that are not listed in No table? Thanks in advance.
View Replies !
Cannot Get MySQL Query To Work In .asp
I have a MySQL database and in the front-end software I am using to Run MySQL, I have created a query on the tables which runs in the front-end, similar to the MS Access query grid. I now wish to pull this query on-line using .asp, but I seem to have found out that I can only pull data from tables in MySQL? ....
View Replies !
Query Doesn't Work With Mysql4
Can someone tell me what's wrong with the mysql query below? It does work on mysql 5 but gives me an error with mysql 4. SELECT rev_profile_indiv. * FROM rev_profile_indiv, rev_profile_kids_indiv WHERE 1 AND reviewing IN ( 1, 0 ) AND active IN ( 1 ) AND contract IN ( 1 ) AND UNIX_TIMESTAMP( DATE( rev_profile_kids_indiv.birthdate ) ) >= UNIX_TIMESTAMP( ��-12-15' ) AND UNIX_TIMESTAMP( DATE( rev_profile_kids_indiv.birthdate ) ) <= UNIX_TIMESTAMP( ��-12-15' ) GROUP BY rev_profile_indiv.username ORDER BY lastname LIMIT 0 , 30;
View Replies !
What Do I Need To Do To Make This Query Work?
I must've been working too long hours this week, as my flow of ideas has come to a complete stop. Its really quite simple: 2 tables - bookings , invoices These two counts gives me precisely what I want PHP $unpaid_bookings = mysql_result(mysql_query("SELECT COUNT(id) FROM bookings WHERE invoice_id = 0 AND client_id = $id AND status != Ɔ' AND finish <= '$time'"),0);$total_bookings = mysql_result(mysql_query("SELECT COUNT(id) FROM bookings WHERE client_id = $id AND status != Ɔ' AND finish <= '$time'"),0); so I present this in a ratio, $unpaid_bookings / $total_bookings... awesome now, when I try and flip the coin and show unpaid invoices over total invoices, it all falls apart once I have more than 1 booking per invoice. First i'll explain the table structure. Each booking has a column `invoice_id`, which is assigned to the primary `id` of the invoice table. So one invoice might be associated with x bookings. PHP $unpaid_invoices = @mysql_result(mysql_query("SELECT COUNT(i.id) FROM invoices i, bookings b WHERE i.id = b.invoice_id AND b.client_id = $id AND i.is_paid = Ɔ'"),0);$total_invoices = @mysql_result(mysql_query("SELECT COUNT(i.id) FROM invoices i, bookings b WHERE i.id = b.invoice_id AND b.client_id = $id"),0); Again so it works fine when 1 invoice is associated to 1 booking, but when 1 invoice is associated with say 2 bookings, the invoice count will return two instead of one. The worst part is, I know exactly why (because there are two bookings for the invoice), I just can't get around it! I've tried all sorts of joins, group by's, and i'm not having any luck. I'm trying not to be weak and add the client_id into the invoice table,
View Replies !
Query Does Not Work On Some Server Instances
query: Select * From Students Where C_Name = "XXXXXX" WHen I run this query on 2 of my computers, the result returns no rows. When I run this query on a remote machine hosted by 1and1, with a copy of the same database, the query returns the correct row. The syntax is identical.....
View Replies !
Cant Work Out Correct Select Query For ..
mysql> select * from parent_cat; +-------+----------+----------+ | catid | pname | psection | +-------+----------+----------+ | 1 | Trainers | Men | | 2 | Bags | Woman | | 4 | Boots | Woman | | 5 | Fragance | Men | +-------+----------+----------+ 4 rows in set (0.00 sec) mysql> select * from categories;; +-------+---------------------------+---------+------+ | catid | catname | section | pid | +-------+---------------------------+---------+------+ | 1 | Nile | Men | 1 | | 2 | Bags | Woman | 2 | | 4 | Boots | Woman | 4 | | 6 | Air Force I & II Trainers | Men | 1 | | 7 | Adidas Trainers | Men | 1 | | 8 | Timberland Trainers | Men | 1 | | 9 | Lacoste Trainers | Men | 1 | | 10 | Gucci & Hogen Trainers | Men | 1 | | 11 | D&G Trainers | Men | 1 | | 12 | Prada Trainers | Men | 1 | | 13 | Chanel Trainers | Men | 1 | +-------+---------------------------+---------+------+ and the following query: $pid = $_GET['catid']; $query = "SELECT categories.catid, categories.catname, categories.pid FROM categories, parent_cat WHERE categories.section = 'Men' AND parent_cat.catid=categories.pid AND categories.pid = '$pid'"; At the moment the query only returns all categories.catname when my categories.catid = 1, but returns nothing if it equals something else?
View Replies !
Degrading Sub Select Query To Work In MySQL 4
I have the following query working as intended in MySQL 5. However, I had not realised that the target server is running 4.0.2 and it's not possible to upgrade. SELECT records.player_id, records.record_id, records.game_id, records.updated, game_modes.mode_title, records.record_time, players.firstname, players.lastname, players.nickname, players.country, teams.team_title, classes.class_title, tracks.track_title, games.game_title, games.version, record_types.type_title FROM games, records, classes, teams, tracks, record_types, players, game_modes WHERE records.record_time = ( SELECT MIN(record_time) FROM records WHERE records.player_id = players.player_id AND records.game_id = 1 AND records.mode_id = 1 AND records.track_id = 1 AND records.class_id = 5 AND records.type_id = 1 GROUP BY records.player_id) AND records.track_id=tracks.track_id AND record...................
View Replies !
Query Which Gets Rows Based On A Radius, Lon And Lat Doesn't Work?
I have found this query which gets rows based on a radius. I need this for zip codes based on lon and lat's. $sql2 = "SELECT * FROM table as z WHERE (SQRT( (69.1 * (".$userLat." - z.lat)) * (69.1 * (".$userLat." - z.lat)) + (53.0 *(".$userLong." - z.lon)) * (53.0 *(".$userLong." - z.lon))) <= ".$userRadius." )"; return $sql2; $res = mysql_query($sql2, $connDB) or die(mysql_error()); $row = mysql_fetch_assoc($res); based on a test zip code gives a result like SELECT * FROM table as z WHERE (SQRT( (69.1 * (52.399834 - z.lat)) * (69.1 * (52.399834 - z.lat)) + (53.0 *(4.840762 - z.lon)) * (53.0 *(4.840762 - z.lon))) <= 100 ) the lat and lon of the test zip code are right. As you can see z.lat and z.lon don't get any value. And these would be every lat and lon in table. In my db table lon and lat are decimal(10,6) type with a default value of 0.000000
View Replies !
Reformatting Email Address To Work On SELECT Query
This is probably basic, but so far I cant find any articles about this. I want to "SELECT * FROM dbase WHERE emailaddress = $email;" $email is a feed from PHP, and will contain a string like "some.one@someplace.com" Apparently with $email as a normal string, it gives an error saying: "You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '@someplace.com)' at line 1" I reckon it's the dots and the @s that terminate the syntax and making it not work. How can i get out of this problem? Is there any function I can call to solve this? Or probably a little bit of more programming?
View Replies !
Bug Work
I've got this bug http://bugs.mysql.com/bug.php?id=27861. I know they've made a fix and it's going to come out in the next version but is there any way I can fix this myself?
View Replies !
How Does Sql Work Exactly?
Well what exactly does sql do when you create a table for like a login (user) What does the tables and stuff do. Do they just create like a library to store that users information so they can log back in to site or w/e....
View Replies !
Subselect Does Not Work
i am trying to remove values from a list menu if the join table d= oesnt have keys when a key is selected for instance: locations locationID locations_join locationID shotlistID SELECT SQL_NO_CACHE l.locationID , l.location FROM locations l LEFT JOIN lo= cations_join lj ON l.locationID =3D lj.locationID WHERE l.locationID NOT IN= (select locationID FROM locations_join WHERE shotlistID IN (5069)) ORDER B= Y l.location ASC. so when shotlistID is selected all the keys from the locations_join joined = to the shotlistID would be remove from the locations list please help, i'm = trying to do this in one query saving from getting all the keys into an arr= ay then checking if the values arent in the array when generating the list.
View Replies !
Date_add Does Not Work
I'm using mySQL 5.0, with a database of UNIX timestamps. Can someone explain this to me? This query works great: SELECT from_unixtime( 1132277574 ) But this one breaks: SELECT date_add(from_unixtime( 1132277574 ), interval 1 week) Telling me, oh-so-helpfully, that the error is near "'week)'". (It doesn't work when I use "1 weeks" either.)Does the from_unixtime simply not work with the date_add function, or is there some arcanity to this syntax that I'm missing?
View Replies !
Getting Log File To Work
I am putting log = "C:Program FilesMySQLMySQL Server 5.0sql.txt" into my .ini files and mysql wont start. I cant work out the syntax to tell mysql to ouput all the queries to a log file.
View Replies !
How Does Synchronizing Work?
I have a question; currently we want to run our central database from two different locations as opposed to one currently. I am trying to figure out how to synchronize the two locations. My question is: if two (or more) locations create new clients locally, each location will thus create a new client-numbers on their own active operational database. This opens the possibility that each locations will create identical client-numbers; of course being different clients altogether.
View Replies !
Mysql_connect Does Not Work
I have searched through the forum and tried the suggestions that have been made for this issue but I am about ready to give up! I have installed Apache 2.0.52, PHP 5.0.3, and MySQL 4.0.23 on Windows XP. I uncommented extension=php_mysql.dll in the php.ini file and copied libmysql.dll into both C:WindowsSystem32 and C:WindowsSystem. My phpinfo.php test works fine so I know PHP and Apache are working together. I do not see any MySQL references on that entire page. From previous posts I know I should. Needless to say, mysql_connect(...) does not work, it gives an undefined function error. I apologize if this should have been posted in the PHP forum instead. If it is a PHP issue, I will repost this there.
View Replies !
Work In MySql
This query works fine in SQL Server, will it work in MySql? SELECT a.total, b.browsertotal, b.browser, (b.browsertotal / a.total) * 100 AS browserpercent FROM (SELECT Count(id) As total FROM MyTable) a, (SELECT count(id) as browsertotal, browser FROM MyTable GROUP BY browser) b I dont have MySQL and I am trying to help someone out.
View Replies !
Getting PHP & MySQL To Work Together
I am trying to get PHP to write into MySQL database. Right now it does not seem that it is doing such, MySQL doesnt appear when I bring up the PHPInfo() page. I have removed semi-colons before the Mysql.dll extension in php.ini, and I have made sure that PHP is in the windows PATH. What else do I need to do to get this stuff running?
View Replies !
Sql Statement Doesn't Work
When i was using a previous version of mysql (3.something) this sql statement worked fine. strSQL = "SELECT COUNT(*) as COUNTER FROM prayerrequest where dateexpires <= '" & sDate & "'" sDate equals todays date. But after installing the new version (4.1) of mysql this statement no longer works. I went as far as stepping through all dates and comparing them and it wouldn't work. "1/11/2005" from the database did not equal sDate which was "1/11/2005".. The only way I could get it to work was to use the asp/vb function FormatDateTime on dateexpires and then compare it with sDate. Does mysql not return a different var type? Is there anyway I can convert dateexpires in the above sql statement so I can compare it with sDate?
View Replies !
Cannot Get 3 Where Statement To Work
I am having a problem with MySQL 5. I cannot get 3 where statements to work with my database. Any two of the three work fine and return records as they are supposed to but when I add a third clause (all clauses are AND) I get absolutely no records at all and no error message. I don't understand what could be causing this and can use any help offered. SELECT this, that, otherthing FROM myTable WHERE something = "this" AND somethingelse = "that" AND yetsomethingelse > 0 ORDER BY RAND() LIMIT 3;
View Replies !
Join Doesn't Seem Work
I have some issues with a simple query, but I just can't figure out why the query doesn't return expected results. Here is the situation: I have a table look like this: TRANSACTION(UNIQUE_ID(PK), CUSTOMER_ID, EMP_ID, TRANS_TYPE, TRANS_DATE, POSTED_DATE, AMOUNT_CHARGED, AMOUNT_PAID, TRANS_LOC, TRANS_ID_CHARGE, TRANS_ID_PAYMENT) Some rules for the data in the table: - The TRANS_TYPE indicates if it is a charge or payment(C charge, P for payment). For a payment, there is a unique TRANS_ID_PAYMENT, and for same transaction, the charge record holds same TRANS ID in the TRANS_ID_CHARGE field. - The TRANS_LOC is for location where the charge happened. But for a payment record, this field is null. which means, payment records and charge records can't be linked together through location. - TRANS_DATE is the date the transaction happened. For a payment record, this field is also null. - A charge record and a payment record for same transaction usually have different POSTED_DATE since they are posted most likely on different days. - AMOUNT_PAID could be less than AMOUNT_CHARGED for same transaction since customers can have an installment payment plan. Here is my query: SELECT DISTINCT A.CUSTOMER_ID, A.AMOUNT_PAID FROM TRANSACTION A WHERE A.TRANS_TYPE = 'C' AND A.TRANS_DATE BETWEEN '2007-01-01' AND '2007-09-30 AND A.LOC_ID = 1 UNION ALL SELECT DISTINCT A.CUSTOMER_ID, A.AMOUNT_PAID FROM TRANSACTION A, TRANSACTION B WHERE A.TRANS_TYPE = 'P' AND B.TRANS_TYPE = 'C' AND B.TRANS_DATE BETWEEN '2007-01-01' AND '2007-09-30 AND B.LOC_ID = 1 AND A.CUSTMER_ID = B.CUSTOMER_ID AND A.EMP_ID = B.EMP_ID AND A.TRANS_ID_PAYMENT = B.TRANS_ID_CHARGE The purpose of this query is to pair all the charge and payment records for the same transaction that happened between a certain period of time. But the results show that there are some dangling payment records that are not linked to any charge records.
View Replies !
Min Max Does Not Work For Me For Timestamp
I have such a table: id timestamp value person regardless or entering this SELECT id, MIN(timestamp),value FROM table GROUP BY person or this SELECT id, MAX(timestamp),value FROM table GROUP BY person The timestamp value may be properly pulled, yet, the value field is always the same. Meaning, not the value associated wuth the MIN or MAX timestamp value is shown, but the very first for that person. How is that possible?
View Replies !
Why Does This Grant All Does Not Work?
I've created a new user like this: create user myuser identified by 'xxxxx'; commit; Now I'd like to give him all privileges to a certain database: grant all on db210216204.* to 'myuser'@localhost; Now I get an error message: ERROR 1133 (42000): Can't find any matching row in the user table What am I doing wrong? The database exists: mysql> show databases -> ; +--------------------+ | Database | +--------------------+ | information_schema | | baka | | db210216204 | | mysql | | test | +--------------------+ 5 rows in set (0.13 sec)
View Replies !
LD_PRELOAD Doesn't Work
LD_PRELOAD doesn't seem to work with /usr/sbin/mysqld. It works for other programs, but when it comes to mysqld, I always get the same error saying that the object cannot be preloaded, so ignored. I checked that mysqld is not a setuid binary. Is mysqld doing something funny or did I miss anything?
View Replies !
Auto_Increment Doesn't Work Any More!
After upgrading from 5.0.11.beta to 5.0.15 on a Windows 32 system, I can't use the auto_increment feature any more; for example, phpMyAdmin gives the following error message: "#1366 - Incorrect integer value: '' for column 'ID' at row 1". Other php clients also (WordPress, MediaWiki...) don't work.
View Replies !
Logging Doesn't Work
I have WinXP, and MySQL 5.0.18 running as a service. I followed the instructions for setting up general query log file (mysqld --log), and the file was created (Nebo.log), but it does not display any logs. This is all I have after executing a few queries: Nebo.log mysqld, Version: 5.0.18-log. started with: Tcp port: 3306 Unix socket: (null) Time Id Command Argument Can anyone offer any help?
View Replies !
WHERE EXISTS Does Not Work.
SELECT id,name FROM tcesports_groups WHERE EXISTS (SELECT * FROM tcesports_teams WHERE tcesports_teams.gid=tcesports_groups.id); i get this: You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near 'EXISTS (SELECT * FROM tcesports_teams WHERE tcesports_teams.gid Strucuture of the both tables: tcesports_teams ------------------- gid smallint(6) img varchar(100) mod mediumint(9) pos smallint(6) tcesports_groups ------------------- id smallint(5) name varchar(100) currently the entries for id or gid are just 2digits long (1-99) so im a bit confused what throws this error. im using mysql 4.0 branch
View Replies !
Getting MySQL To Work..
I downloaded version 4.1.7, opened the manual, followed the instructions, and installed it. Then, when I opened up the "MySQL Server Instance Config Wizard", I set it all up. I press the "Configure" button, and it runs up the point where it creates the Service. Then, it gives this message"Could not start the service MySQL. Error: 0". I've ran a Google search on the error message, but have found nothing. I'm running Windows XP. If there's any more information you need about my computer setup, go ahead and ask.
View Replies !
Difference Of Work
My provider has passed on version 4.1.7 and the inquiry of the following kind has ceased to work for me: SELECT goods.id, goods.name FROM goods LEFT JOIN category ON goods.id = category.goods AND category.razdel=2 WHERE category.goods IS NULL. Before all worked correctly, on the version 3.x, what could exchange? Where a problem?
View Replies !
Sentence Doesn't Work
I'm using mysql 4.0.21 and Toad to run this query. The message i'm receiving is that there is a Syntax error, where? select a.id_opcion, a.nombre, a.campo, a.visible, b.id_usuario, if(b.ancho is null, 50, b.ancho) as ancho, b.posicion from det_rmen as a left join (select * from rmen_usu where id_usuario = 'generico') as b on (a.id_opcion = b.id_opcion and a.campo = b.campo) where (b.id_usuario='generico') or (b.id_usuario is NULL) order by id_opcion, posicion;
View Replies !
Date() Just Won't Work
I have this line while ($qry = mysql_fetch_array($results)) { // if (strtotime($qry['loginDateTime']) <= (time() + 86400*31)) { $login .= 'Name: '.$qry["FirstName"].' '.$qry["LastName"].' ('.$qry["JoinDate"]?date("d/m/Y", strtotime($qry["JoinDate"])).') '.$qry["Email"].''.$qry["rep_NBR"].' ('.$qry["State"].') '; //} } And when I run it I receive [quoteParse error: parse error, unexpected ';' in e:emailMembersPending.php on line 43[/quote]
View Replies !
Why Does This Work In PhpMyAdmin But Not In PHP?
This is driving me absolutely crazy. I am using the following query which works fine in phpMyAdmin in the SQL section SELECT date, amount, description FROM invoices WHERE unique_key = 48781048 when I enter it like this in PHP it comes up with the error below $query = "SELECT date, amount, description FROM invoices WHERE unique_key = 48781048"; $result = mysql_query($query) or die (mysql_error()); Unknown column 'unique_key' in 'where clause' I've even tried using the PHP code that phpMyAdmin generates and that doesn't even work.
View Replies !
SET NULL Doesn't Work
I have this table: MySQL CREATE TABLE `users` ( `id` INT(11) NOT NULL AUTO_INCREMENT, `login` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `name` VARCHAR(30) NOT NULL, `email` VARCHAR(30) NOT NULL, `icq` INT(9) UNSIGNED DEFAULT NULL, `personal_stream_id` INT(11) NOT NULL, `TIME` DATETIME NOT NULL, `url_name` VARCHAR(30) DEFAULT NULL, `avatar` VARCHAR(20) DEFAULT NULL, PRIMARY KEY (`id`), UNIQUE KEY `id` (`id`), UNIQUE KEY `login` (`login`), UNIQUE KEY `email` (`email`), UNIQUE KEY `icq` (`icq`), CONSTRAINT `users_fk` FOREIGN KEY (`id`) REFERENCES `photos` (`user_id`) ON DELETE CASCADE ON UPDATE CASCADE ) ENGINE=INNODB DEFAULT CHARSET=latin1; The constraint is linking this table: MySQL CREATE TABLE `photos` ( `id` INT(11) NOT NULL AUTO_INCREMENT, `name` VARCHAR(20) NOT NULL, `user_id` INT(11) DEFAULT NULL, `streams_id` INT(11) NOT NULL, `description` TEXT, `hardware_id` INT(11) DEFAULT NULL, `ratings_id` INT(11) DEFAULT NULL, `thread_id` INT(11) DEFAULT NULL, `url_name` VARCHAR(20) DEFAULT NULL, `views` INT(11) DEFAULT NULL, PRIMARY KEY (`id`), UNIQUE KEY `id` (`id`), KEY `ratings_id` (`ratings_id`), KEY `user_id` (`user_id`), KEY `streams_id` (`streams_id`) ) ENGINE=INNODB DEFAULT CHARSET=latin1; It works, but as you can see, the constraint ondelete action is set to CASCADE, which is not good - it is bad to delete all photos when the user is deleted, I want the database to set user_id value to NULL using the SET NULL action - PHP frontend should display something like "User deleted" then. But when I try to alter the constraint to SET NULL, EMS SQL Manager I'm using shows a very strange error like "Can't create table '.dfk#sql-8e4_4.frm' (errno: 150)". Similiar error is shown when I try to link unsigned int with not unsigned int.
View Replies !
Making ODBC Work
When trying to set up programs (dbQwikSite, Adobe Designer) to work with ODBC databases, I encounter the following during setup of the programs: "it connects, but if I set the initial catalog to any database it says: "Test connection failed because of an error initializing provider. Catastrophic Failure." But when I connect with the initial catalog field empty it connects successfully.How do I fix this problem?
View Replies !
Getting Group By To Work With Order By
Trying to get a simple query going using group by and order by I need to retrieve the latest record ordered by datetimestamp desc but grouped by my nodeID column... my data is thus; 7000802818, 2005-10-10 17:13:43 4, 2005-10-10 17:13:44 4, 2005-10-10 17:13:45 5, 2005-10-10 17:13:4 the first column being the nodeID, the second being the datetimestamp... I cant seem to get the bleeder to work :( Can anyone offer any assistance ?
View Replies !
A Hash At The End Of A Fieldname Does Not Work
My Linux MYSQL 3.23.52 database server is working OK generally. However, in a database I have a field name that ends with a # (hash UK as opposed to £ which is a pound UK) i.e. [empnumber#] If I "select * from emptable" it works fine and the empnumber# field is listed correctly with all the other fields. If I "select empnumber# from emptable" I get returned "unknown column 'empnumber' in 'field list'" (#1054) from Access 2000. If I use Mysql on the server I get similar results. I cannot change the field names as these are constrained by the fact that this is not a new design of database.
View Replies !
ORDER BY With Match() Doesn't Work
Something like the following does not sort the results: select * from properties where match(location) against('"main st"' in boolean mode) order by location; The results are not sorted by location. If I sort by some other field not specified in a match()/against() pair, the sort works. Shows up in MySQL 4.1 compiled for Windows and Linux. Is this a known bug, and are there any workarounds that I can try without source diving?
View Replies !
MySQL Doesn't Work In XAMPP
Ok i downloaded xampp, which has php,apache and mysql all in one, but mysql doesnt work... but ne way when i type my localhost i get the xampp screen which must mean that apache is working fine but what do i do now? im really confused between mysql and apache.
View Replies !
Stored Routine Does Not Work
Could someone please let me know what is wrong with the following routine. CREATE PROCEDURE ToVerifyEmployee(IN surname VARCHAR(15),IN email VARCHAR(40),OUT query INT) BEGIN DECLARE strA VARCHAR(15); DECLARE strB VARCHAR(40); SET strA = ''; SET strB = ''; SELECT LastName, EmailAddress FROM Employee INTO strA, strB IF(strA = surname AND strB = email) THEN SET query = 1; ELSE SET query = 0; END IF; END; I get the following error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 3. I cannot find the error. Also I did not change the delimiter to something else than ; before declaring the procedure. I'll be grateful for all help.
View Replies !
MySQL To Work On My Localhost
I am doing my first web site in PHP after having developed countless sites w/ ASP and Access. I am running Windows XP Pro on my laptop with IIS 5.x I believe. THe web site I am going to be revising is on an Apache server I believe. I say I believe as the hosting company reps. don't speak English and are not so co-operative. So what I intend to do is to fully develop the site on my local host with the intent of then transferring it over. Are there anythings I MUST know before going this route? Also, where do I begin with getting mySQL to work on my localhost? Is it similar to Access whereas I just dbl click a file and it opens a nice handy application like access to work in the tables, etc?
View Replies !
How Does Record Locking Work?
I am having record locking issues - I need to be able to do it! I have spent a fair amount of time reading the available documentation and posts (at various sites), but not gotten any clear answers. So I have several questions about this whole subject: 1. Is there anywhere in the MySQL documentation that covers all aspects of record locking, including by engine? 2. Does "SELECT...LOCK IN SHARE MODE" or "SELECT...FOR UPDATE" lock records with any engines OTHER than InnoDB? 3. The way Sarah from AB MYSQL describes "SELECT...LOCK IN SHARE MODE" and "SELECT...FOR UPDATE" in another "record locking" post, it is NOT clear if the "lock" stops a "SELECT" from finding the record. So, does the lock simply stop the UPDATE or LOCK of the record by another process, or does it also stop the READ (via SELECT or anything else) from other processes? And, is that different for different engines? 4. From the documentation I've read, the assumption is that the UPDATE is "atomic", i.e., that no concurrent access by another process can occur between the testing of and the setting of the value field(s). Is that how it works? And, does it work that way with all engines?
View Replies !
UPDATE Statement Doesn't Work
TABLE - abc ID NAME ___________ 1 hello 12 abc UPDATE `abc` SET `ID`='5' AND `NAME`='hello' WHERE `ID`='1' AND `NAME`='hello' wherenver I try to update this table using above sql statement, it doesn't work. I just get "Row match:1 Changed:0" message.
View Replies !
SELECT `*` Not Work On New Server
I wrote some code a long time ago that used SELECT `*` from blah blah blah. I'm building a new server with a new installation on MySQL 4 and for some reason this piece of code wasn't working. I looked into it, and turns out only SELECT * not SELECT `*` works on this new server. Now I realise this is probably my crappy coding, but is there some variable I can turn on/that is different between the servers that makes this happen? I've used this code on loads of servers and never had a problem, and would rather not go through all my code fixing this error
View Replies !
Can't Get Init_connect='AUTOCOMMIT=0' To Work
I've got 4.1.3 installed on Linux.. everything fine so far except for getting the init_connect string to work. I followed the instructions on http://dev.mysql.com/doc/mysql/en/Server_system_variables.html and added the below line to my '/etc/my.cnf' file under [mysqld]: init_connect='SET AUTOCOMMIT=0' When I restart the server and start mysql, I can see that the init_connect was read: mysql> select @@init_connect; +--------------------+ | @@init_connect | +--------------------+ | SET AUTOCOMMIT=0| +--------------------+ However, the Autocommit variable is still 1! mysql> select @@AUTOCOMMIT; +-----------------+ | @@AUTOCOMMIT| +-----------------+ | 1| +-----------------+ Anyone seen this before or know what's wrong?
View Replies !
|
TRACKER
