MYSQL :: Query Works With One Record

SQL Query Works Only In Win32!
I use MySQL from my php page and from phpMyAdmin.

In Windows Server, following query works fine. In Linux Server instead it returns error.

The SQL Query is:

SELECT DISTINCT a.id, a.container, b.container FROM folder AS a JOIN folder AS b ON a.container=b.id

The PHP error is:

You have an error in your SQL syntax near 'ON a.container=b.id' at line 1

So, I ask: If in Windows this query work fine, where is the error in the Linux version?

JOIN Query Works With 3.23 But Not 4.0.13
I have a simple join query below which queries the name of schools with count of
student numbers for each school from two tables School,Student.

select sc.name,
Sum(if(student.SNO is not null, 1, 0)) nmbr,
from school sc
left outer join student
on sc.school_id = student.school_id
group by sc.school_id

this runs just 0.30 sec with Mysql3.23 but 30Sec with Mysql 4.0.13.
i could not find a solution.But i suspect from NULL threatment.

Parentheses: Query Works With 4.1.7, But Not With 4.1.11
Since we updated to the newest MySQL version (Windows) some of our queries do not work any more.

It's reproducable by this (dummy) query:

SELECT B.ID from ((SELECT * from A) AS T1
INNER JOIN B a ON B.ID = T1.ID);

This works with 4.1.7, but not with 4.1.11, unless the parentheses are removed:

SELECT B.ID from (SELECT * from A) AS T1
INNER JOIN B a ON B.ID = T1.ID;

Does anybody know why MySQL changed its behaviour that way?

I know the parentheses in the first query are not necessary, but it would be quite difficult to search through all our queries for unnecessary parentheses.

JOIN Query Works With 3.23 But Not 4.0.13
I have a simple join query below which queries the name of schools with count of
student numbers for each school from two tables School,Student.....

GROUP_CONCAT Problem In 5.0.24 (query Works In 5.0.18)
So on my production server they are running MySQL - 5.0.24-standard. Locally I'm only running 5.0.18 but didn't figure it would be much of a problem, until I noticed that my "results" from certain searches were different with the exact same data on each MySQL version.

The query is this:

Query Help. This Works, But I Don't Think It Is Good Practice
comics:
id
date
location

comments:
id
comicid
datetime
header
comment
author

Every comic can have multiple comments. Each comic will have a comment, but there is a period of time where the comic is posted but the first comment is not yet submitted. So for argument's sake we can't assume there is any comment at all for a given comic.

I want the all the comic ids and dates before a certain date along with the most first comment entered relating to that comic.

select comics.date
, comics.id
, comments.header
from comics
left outer
join comments
on comments.comicid = comics.id
where (comics.date>=񟭇-03-01')
group by comics.id
I never defined WHICH header should be returned when many are grouped together. I just know that mysql will return the first one in this circumstance. I seem to recall reading somewhere that different databases handle this sort of thing differently, with some returning a null in that field?

I keep trying to forumate a useful subquery but keep drawing blanks just as I think I have it figured out in my head. Like I forget how the string starts by the time I mentally formulate the end....

SQL Query Works Fine With Phpmyadmin But Gives Me No Results And EOF With ASP
I have a strange problem: when I perform a sql query on my phpmyadmin it works fine and it gives me the right results. If I perform the _same_ query through my asp application I reach immediately the EOF condition without any results!

Get The First And Last Record From A Query?
I need to return a max, min, open and close in the query but I only have one column which is value. The open would be the first record and the close would be the last record. Is there a way to do this? ...

Query Last Record?
Hello I have a DB with 4 fields. id title event date.

I would like to query the last record only and display it. I am using mysql and php. The trouble I am finding is how to query the last record by id?

Query A NULL Record
Is there an easy way to test, in a query, whether all of the fields in a record are NULL?

I appreciate that it is unusual to create a table that contains all null records but the circumstance that I have requires it.

Query Help: Get Oldest Record W/ Grouping?
I'm building a system that allows a maximum of two records per unit. When a new record is created for that unit, if there are already two records the oldest record is deleted.

Thus, I'm trying to build a query that gets the oldest record for each unit, but also returns the number of records per unit. The trouble I'm having is in making sure the record I'm getting is the oldest one! I thought I could use the Order By clause to get the oldest record, but it doesn't work. In a database table where there are a total of four records:

recordID unitID recordFile recordTime

10 1 someFile1.txt 1179778828
11 3 someFile5.txt 1179778828
12 3 someFile5.txt 1179778990
13 1 someFile5.txt 1179778956
The following query:

SELECT
unitID,
COUNT(recordID) AS numRecords,
recordID AS oldestID,
recordFile,
recordTime
FROM records
GROUP BY unitID
ORDER BY recordTime DESC
Returns the following result:

unitID numRecords oldestID recordFile recordTime

3 2 12 someFile5.txt 1179778990
1 2 13 someFile5.txt 1179778956
These are the newest records, not the oldest. I'm not even sure that is a reliable case. I get the exact same result using the same query but with ASC instead of DESC!

How To Ommit First Record In Query Result?
How can I ommit the first record of a Query?

Query To Display A Record By Recent Time
Many users uploaded their files to my mysql table through php script,
my table having the details of uploading time, file name, & uploader name.

i need to find the recent uploaded file for all uploaders.

i tried with this query,

select file_name,uploded_by,MAX(date_time) from upload group by uploded_by;

it is giving the recent time, but it is not giving the latest file, it is showing first uploaded file.

Insert A Record Using MySQL Query Browser
I know I can probably type in the actual query, but I was wondering if there was a means of inserting a record without typing "insert into table_name (blah, blah2) values (blah, blah)". I'm looking for a method as easy as typing into an Excel spreadsheet or Access DB. (I know I'm gonna get bashed for mentioning Microsoft products.)

How To Write Query To Select The Max(version) For Each Unique File_name Record?
I am a MySQL newbie trying to write a query that selects file_name records
possessing the highest numbered version for that unique file_name. I show
sample data and two trial queries below. Logically I want to use
max(version) as a constraint in a Where Clause. However, the max() function
is not allowed directly in a where clause.

I have contemplated a second table to track the max version for each file
name. I would like to structure the data in an efficient manner for query
performance when the data set grows to many thousands of unique file_name
records with many hundreds of versions each........

Works
I have this and it works just fine but I cant help but think there is a much better way of accomplishing the same thing in one sweep verses 6
PHP Code:
mysql_query("update residential set bed='1' where bed like 'ONE%'");
mysql_query("update residential set bed='2' where bed like 'TWO%'");
mysql_query("update residential set bed='3' where bed like 'THREE%'");
mysql_query("update residential set bed='4' where bed like 'FOUR%'");
mysql_query("update residential set bed='5' where bed like 'FIVE%'");
mysql_query("update residential set bed='6' where bed like 'SIX%'");

Works In MYSQL 4.1 But Not In 5.0
MySQL
1054 - Unknown COLUMN 'p.manufacturers_id' IN 'on clause'
SELECT count(*) as total FROM products p, categories c, products_to_categories p2c LEFT JOIN manufacturers m on (p.manufacturers_id = m.manufacturers_id), products_description pd WHERE c.categories_status=1 AND p.products_id = p2c.products_id AND c.categories_id = p2c.categories_id AND p.products_status = Ƈ' AND p.products_id = pd.products_id AND pd.language_id = Ƈ'

Here is the query in PHP

PHP
"select p.products_id, pd.products_name, p.products_image, p.products_price, p.products_tax_class_id, p.products_date_added, p.manufacturers_id, m.manufacturers_name from " . TABLE_PRODUCTS . " p, " . TABLE_CATEGORIES . " c, " . TABLE_PRODUCTS_TO_CATEGORIES . " p2c left join " . TABLE_MANUFACTURERS . " m on (p.manufacturers_id = m.manufacturers_id), " . TABLE_PRODUCTS_DESCRIPTION . " pd where c.categories_status=1 and p.products_id = p2c.products_id and c.categories_id = p2c.categories_id and p.products_status = Ƈ' and p.products_id = pd.products_id and pd.language_id = '" . (int)$languages_id . "' order by p.products_date_added DESC, pd.products_name";

How Exactly The LIKE Keyword Works?
I have a table named Inventory and have 3 items in it containing the work w069.

I want to run a query to return the three items.

My query: Select * from Inventory where Description Like 'w069'

It doesn't seem to work, returning zero row.

UNION - Works In 4.0.16, Not In 4.1.8
I have a query that works in 4.0.16 on my web host, but not 4.1.8 on my dev. box. Web host is upgrading in 10 days.

Notes:
Server language is ColdFusion
gamedate is type DATE

SELECT DISTINCT gamedate
FROM schedule
WHERE gamedate >= now()
UNION (
(SELECT DISTINCT gamedate
FROM schedule
WHERE gamedate < now()
ORDER BY gamedate desc LIMIT 1)
ORDER BY gamedate asc LIMIT 3

The goal is to select the most recent gamedate prior to "today" and the next two game dates including "today".

SSN Changes In Database But Still Works As Key?
I have a ssn field in a table but somthing happens to the data. I use an update to enter the data and set the value to 123-12-1234 for a test but when I look in the table or I get the record from a record set it come out like -1123.

Why is this? But when I run a query and ask it to return all records which have a ssn of 123-12-1234 it returns the correct record. If this is correct then how can I display the ssn number in a java text field.

How Decimal Works
Say that we have an variable that is

var1 = 3
var2 = 3.65

var3 = var1 * var2 '--- Sum = 10.95

Now my Question!
How do I input this variable into MySQL in a COL whit DECIMAL (10,2)?
I only get the result 10.00 in the COL?
It seams that MySQL round every resout I get to .00 at the end.

If I make an varible hard ex.
var3 = "10.95"
that works but if I convert an numeric variable to string it doesnt?!?!?!
ex.
var4 = cstr(var3)

UPDATE Works In MS SQL
I use the following stament work with MSSql, but not MySql, why ?

Update mytable set mycol = 'my_Text' + mycol

Failed, mycol is varchar

Looking Up Duplicate Record Or Adding New Unique Record
CREATE TABLE tbllayer (
LayerID int(11) NOT NULL default '0',
LayerSize int(11) NOT NULL default '0',
IceTypeID int(11) NOT NULL default '0',
Fingerprint char(16) binary default NULL,
PRIMARY KEY (LayerID),
UNIQUE KEY Fingerprint (Fingerprint),
KEY IceTypeID (IceTypeID)
) TYPE=MyISAM;

We have an internet monitoring application which stores objects in the above
table, with the fingerprint an MD4 of the object. In general about 30% of
the time an object monitored is already in the table, in which case we don't
want to re-insert it, we just want to find out it's ID. The percentage may
vary between 10% and 50% though.

Currently we have a cache in our application which works like this:

- object is monitored and its fingerprint taken
- is the fingerprint in the cache? if so, take its ID from there
- if not, do a SELECT on the table - if a match is found add it to the cache
and use its ID
- if not, INSERT the record into the tablem use its ID and possibly add it
to the cache too

Ok. In general, is it better to:

- do a SELECT to see if the record exists and if not INSERT it
or
- do an INSERT, and if it fails then do a SELECT to locate the record

What about if the duplicate ratio is high or low?

Automatically Record Date Of Record Entry
I have my database table set up and I have an HTML form that is PHP driven that will add the information entered into the form into to my database table.

I have a local buy-sell-trade Website. The way it has worked is that people fill out a form and the results emailed to me. I then take the information and enter it into a Web page. I only want the ads to be displayed for 30 days. I keep the ad for a total of 6 weeks (displays for 30 days and sits in limbo for 2 weeks afterwords) and if not renewed within that 2 week limbo period - I delete it.

Entering all the ads and keeping up with the dates manually has become a burden. I've only recently began looking into databases. My hosting company provides me with phpmyadmin and mysql 5.0. I'm new to all of this but I have managed to set up a database table and a HTML form that is PHP driven that allows ads to be automatically added to the database table.

There is a lot I need to do to make this ideal, but one step at a time.

First, I need to know the date (March 02, 2006) the ad was created or added to the database table. I know that I need to add some piece of code to my php form to record this information, but what code and where do I put it? I know I will need to create an extra field in my database table to house the date - I can handle this.

I've read the date and time information here http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html

but there's a lot there and I don't know which is right for my needs. Plus, it doesn't tell me how or where to insert it into my php form (or does it?).

MySQL Delete: Works In Php 5 But Not Php 4?
I've developed a small login system using Xampp on my local machine. Everything is running great except when the admin tries to delete something. Apparently I have the wrong syntax for my deletion in mysql.

Here's my original delete statement (from mysql5):
DELETE at.* FROM access_table AS at WHERE at.client_id=2

And here's the error I get from mysql4 (I ran the command in phpmyadmin console):
#1066 - Not unique table/alias: 'at'

So I removed the aliases and re wrote my command as such:
DELETE * FROM access_table WHERE at.client_id=2

And got the following error from php4:
#1064 - You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '* FROM access_table WHERE at.client_id=2' at line 1

SHOW DATABASES Works In 4.0.14
I've been trying to solve this problem for a long time. Only thing
I did when upgrading from 3.25 to 4.0.14 I took the default my.cnf. I
did not convert the privilege tables with mysql_fix_privilege_tables.

Suddenly, the mysql started to show all databases to all users (even
though the user had access denied and could not do show tables on
them). So I started to find help and tried the
mysql_fix_privilege_tables. It didn't work properly (more than just
access denied and errors, that are ok) so I did the changes manually
conforming to source code of mysql_fix_privilege tables.

PhpMyAdmin stopped its warning about privilege tables not conforming
to current mysql version. Everything seemed ok except that SHOW
DATABASES still worked.

The users naturally all have Show_db_priv="N" in the tables. Also
trying "safe_show_database", "skip_show_database" in my.cnf and
"--skip-show-database" witch mysqld didn't help.

Exporting MS Works For MySQL
I have a MS Works database and I can't find anything useful on the PHP site for working with this type of database. I did a quick search and it seems that it can be exported for OoenOffice.org and other spreadsheet database programs but none of them give a method. Mostly selling books and MS Access.

If there is a way to access the .MWD or .DBF Microsoft works files with PHP that would be great. If that's not possible, preferably not, I'd rther switch to MySQl easily if possible. I'm still looking but it's not looking good.

Mysql.exe Sort Of Works
I have just installed MySQL (not an easy thing to do). I also have installed PHP. I use Dreamweaver8 for 2 static sites, and eventually will figure out how to use that with PHP/MySQL.
Everything seems to work fine, and I'm working my way through Janet Valade's book, "PHP and MySQL for Dummies." Everything I have tried in the book works perfectly except for the mysql.exe command.
I am in the correct folder and type mysql.exe -u root -p and am prompted for my password. When I enter my password the cursor moves to the next line and just sits there. Nothing happens. Fortunately, the window is not frozen and I can just close it.

Suddenly A Script No Longer Works
I always get the following message when starting a search in my database:

Search for titles in the mylibrary database.

Search for titles beginning with a:

V. 4.1.7 + Php4 Works, + Php5 Problems
I am running:

Mac OS X 10.3.7
apache 2.0.52
MySQL 4.1.7
php 4.9.3 & php 5.0.3

I have an html form that "POST"s data to a db.
I have a "GET" script to repopulate form for editing.
Everything works fine with php 4.9.3.

With php5.0.3 the data is "POST"ed just fine
(I used a different GUI app to check)
When I try to "GET" said data, form is returned empty?

I have all error reporting turned on = nothing.
I have all backwards-compatibility directives in
php.ini config file turned on.

Two Different Websites Connected To One Database But Only One Works...
I have been recently having problems transferring my website from one domain name to another. The first domain name was used whilst at uni, but the second is my own perosnal website. One the original website, the MySQL database allows the user to login and register new users without any problems.

However, the second website does not allow me to do this. I would consider myself a newbie when its comes to MySQL so I was wondering if the community could help me out on this one. Both websites are hosted by the same company, and both websites use the same database but my limited knowledge cannot solve this problem. Are there certain permissions I need to set or something? Can anyone help me out on this one?

Delete Using Multiple Table: Works On 4.1.20, But Not On 4.0.16
I've a simple delete query delete from joingrp as J using joingrp as J,msggrp as M
where J.msgid=M.msgid and M.parent!=0

When I tried it on phpMyadmin at ixweb, having mysql-4.1.20, it works as desired.
But when I tried it on phpMyadmin at iPowerweb, having 4.0.16, it says
#1064 - You have an error in your SQL syntax.

Check the manual that corresponds to your MySQL server version for the right syntax to use near 'as J using joingrp as J,msggrp as M where J.msgid=M.msgid Can I solve this without using any server-side loops?

My MySQL Back-end Works Very Slow
I have installed my MySQL Server in a Window XP platform running in a Pentium4 machine. When I access the database on the machine, it is working in a normal speed. But when I access the database from a client machine (still running in windows platform), it runs very slow.

Can't Update Multiple Rows Via PHP, But Works In PhpMyAdmin
My php script will update 1 row fine, but fails on 2. However, the exact same query works when pasted into phpMyAdmin.

THIS QUERY WORKS BOTH IN MY PHP AND PHPMYADMIN:

$sql = "update table set color='red' where id='1';";
$sql_do = mysql_query($sql);

THIS QUERY WORKS ONLY IN PHPMYADMIN:

$sql = "update table set color='red' where id='1'; update table set color='green' where id='2';";
$sql_do = mysql_query($sql);

I know the second query is correct, because when I copy it from my php code and paste it into phpMyAdmin, it works. But only the first query, with 1 row update, works from my php code.

Quering Works Except Need To Sort Results By Other Table...
I have the following query:

SELECT plugin_id FROM tc_plugin_lists WHERE (page_id='1' AND position='0') ORDER BY tc_plugins.sort_number ASC;

This almost works, the problem is the ORDER BY clause. It should order the results by the sort_number field from another table called tc_plugins. Now it throws an error...

SELECT items FROM other table ORDER BY other tables field values where field is same as in 'items' ASC

?

Want Only One Record Returned Per Post_id (was "Help With Query")
I can't figure out how to do this query. Help would be muchly appreciated!

I want to get the DISTINCT(post.post_id) but not sure how to do this.

Here is the query I have thus far but it's returning two records each with the same post_id but different cat_id's.

SELECT post.post_id, auth_alias, pc.cat_id, post_heading, DATE_FORMAT(post_created, '%M %d, %Y'), post_body FROM posting post LEFT OUTER JOIN post_cats pc ON post.post_id = pc.post_id WHERE post_status = Ƈ' ORDER BY post.post_created DESC LIMIT 0,5

Getting Record Before Or After The Record That Meets The Criteria
In a query I want to get all the results and then order those results by last name, but then I want to filter those results down to only the record that comes before or after the record that has 'empno' = '1259'.

I want to get all the results already ordered and then filter them down to one record either before or after (depending on what is needed) the record where 'empno' = '1259'.

Record Creates Record
I have a table that holds inventory information...primary key'd with an asset#. I have another table that I hold certain information in that I don't want in the main inventory table. I would like the second table to key itself and automatically enter a record when a device is entered.

For example, I enter a scanner in my main table, but I want the DB to then also enter that assetNumber into the second table for me.

Using "WHERE LIKE '%Word'" That *will* Use An Index... Works But Feels Stupid!
FYI, I'm using INNODB.

Let's say I have a table with a city column containing 30,000 records, and I want to provide a search form 'starts with' and 'ends with fields.

So a user would supply the following:

Starts with: Cha
Ends with: tte

And the search would find a record such as 'Charlotte'

The 'starts with' search can use an index (eg, LIKE 'Cha%'), but ends with can't (eg, LIKE '%tte').

A solution seems to be to create a city_reverse column, add a unique index on that, then perform an 'ends with' search on the city names in reverse.

For instance, the 'Charlotte' record would be stored in the city_reverse column as such:

'ettolrahC'

...and I'd perform an 'ends with' search using the unique index:

LIKE 'ett%'

The above works, but it feels stupid, and adds weight to the database. Is there an alternative?

Error With SQL Statement When Using MySQL 5.0.24 (Works Fine In MySQL 4.0)
Here is my query that worked in mySQL 4.0 but not in MySQL 5.0.24:

INSERT INTO magtallynew SET magempnum=?', magcentre='YVRRC', entrydate=&#55614;&#57158;-08-15', empnum=?', empcentre='YVRRC', connection='Rockwell', service='Express', region='dom', callertype='CSR', otherdept='', transferredcall='No', directrespdept='No', station='Not Applicable', withoutmagassist='Yes', category='Accounting', issue='Advised On Contact', comments='test'

Here is the error message I get:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'connection='Rockwell', service='Express', region='dom', callertype='CSR', otherd' at line 1

UNION, Individually Works Fine, But Not In Union
Well, I am using an UNION, and while both of the queries works fine while used individually, they don't work while in the UNION.

Here is the code -

PHP

(
SELECT *
FROM job
WHERE date_fin !=0000-00-00
ORDER BY date_fin ASC
)
UNION (
SELECT *
FROM job
WHERE date_fin =0000-00-00
ORDER BY date_creation ASC
)

What do u think guys?

Note : MySQL version 4.1.21

Note : Not working means, this part is not working => 'ORDER BY date_fin ASC', means, the returned results are not ordered as I want.

MySQL doc. tells,

To apply ORDER BY or LIMIT to an individual SELECT, place
the clause inside the parentheses that enclose the SELECT:

(SELECT a FROM t1 WHERE a=10 AND B=1 ORDER BY a LIMIT 10)
UNION
(SELECT a FROM t2 WHERE a=11 AND B=2 ORDER BY a LIMIT 10);

User Problems... Only Root User "works".
i have been trying to figure this strange problem out for a week or so. here it is.

i have a set of users with various permissions for different reasons. about 2 weeks ago, my hardware suffered a fairly nasty failure. i recovered everything. things seemed to work out. i didnt think to check my phpBB forums or my blog (or other mysql based stuff). never had any problems with the DB... so, maybe i am missing something simple here. i hope so.

what my users can do:

they can log in via command line, a gui i use on mac os x and it does not matter if it is local, or remote. they work just fine.

what all but one users cannot do:

none of my users can run phpbb or the blog stuff.. except for the root user. any other user returns the error message written in the code of which ever script i try to access telling me that "could not connect to DB" etc..

root works fine.

now, i thought maybe it was a problem with the forums and other stuff. but i cant be. same thing happens with all things... even a game server i occasionally run that keeps account info in a DB.

all these users are set up properly and have worked just fine in the past. nothing new has been installed, no conf changes..im at a loss...

How To Get The Right Record?
I have 2 tables - property_active, and property_inactive. Both tables are identical in structure.
I have a record_id, relating to a record in one or both of my tables.
I wish to do a select, whereby:
If the record relating to the given ID exists ONLY in property_active, that will be returned.
If the record exists ONLY in property_inactive, that will be returned.
If the record exists in BOTH tables, the version from property_inactive will be returned.
I have made various attempts involving UNION, COALESCE etc, but to no avail.

To Get Last But One Record?
This (obviously) returns the last record:

HTML
$result =mysql_query("select * from cms_notices ORDER BY notices_id DESC LIMIT 1") or die(mysql_error());

Against Next Record
I want to run a query to see if one field is a subset of another field. Is there a way to check if one record's field is a subset of the next record's field's value.

Specifically, I'm checking for duplicates in the database, and want to find (eg) Rob Smith == Robert Smith. So I'm going to make one field with last name + first name to get SmithRob and SmithRobert. Once I order them on that new field, SmithRob will be right before SmithRobert, and I want to flag the records where one record is a subset of the next record.

Is this possible?

Query Works With One Record

This query works great if there is one matching record in the Albums table. When there's more than one matching record it returns nothing. Code: SELECT Artists.Artist, Albums.Album_Name FROM Artists, Albums WHERE SOUNDEX('colname') = SOUNDEX(Artists.Artist) AND Albums.Artist_ID=Artists.Id

This query works great if there is one matching record in the Albums table. When there's more than one matching record it returns nothing.
Code:

SELECT Artists.Artist, Albums.Album_Name
FROM Artists, Albums
WHERE SOUNDEX('colname') = SOUNDEX(Artists.Artist) AND Albums.Artist_ID=Artists.Id