MYSQL :: SHOW DATABASES Works In 4.0.14

SHOW DATABASES Works In 4.0.14
I've been trying to solve this problem for a long time. Only thing
I did when upgrading from 3.25 to 4.0.14 I took the default my.cnf. I
did not convert the privilege tables with mysql_fix_privilege_tables.

Suddenly, the mysql started to show all databases to all users (even
though the user had access denied and could not do show tables on
them). So I started to find help and tried the
mysql_fix_privilege_tables. It didn't work properly (more than just
access denied and errors, that are ok) so I did the changes manually
conforming to source code of mysql_fix_privilege tables.

PhpMyAdmin stopped its warning about privilege tables not conforming
to current mysql version. Everything seemed ok except that SHOW
DATABASES still worked.

The users naturally all have Show_db_priv="N" in the tables. Also
trying "safe_show_database", "skip_show_database" in my.cnf and
"--skip-show-database" witch mysqld didn't help.

Show Databases
I just installed MySQL on my home PC and I tested out the
show databases query, and it lists two:

information_schema
bbdatabank

The second one is one I created myself, but I don't understand what the
first one is. It is not listed in my 'data' folder, but mysql and test
*are*, yet they aren't listed when I type the show command. Why is that?
How can I get them listed so that I can use them, and what is the
information_schema?

SHOW DATABASES Or Similar Command
Is there a query that will show me the database that I have connected to?

Show Databases In User Account
Is there a way to only let the users see databases in there own account.
After whats the point of having a username and password if they can see
the other databases. I'm trying to setup a server with many users I want
to grant each user a database but how on earth do I stop them seeing
other databases.

MyOLEDB Doesn't Support Commands Like SHOW FIELDS, SHOW TABLES
My code is shown below, I can select * from employees but I cannot get any data back from SHOW FIELDS, I do not receive an error, in fact, something is returned but I'm not sure what. I can execute the command:

SHOW FIELDS FROM test.employees

in the Control Center just fine, even cmd.ExecuteReader will enter reader.Read() once, something is returned but what does it look like? ......

Ps -fax Show 1 Thread, Others Show 5
Where do I configure "spare servers"???

Show/not Show Option
I have a php page that displays pictures. The pictures comes from a mysql database. The way I am creating the recordset to dislpay is "Select * from tblehouse" . Now what I want to do is instead of selecting every picture from the database maybe create a new field that will take in the option of being checked or unchecked. Then have the query select only the "checked" to display. So my question to you guys is how would create a field that takes in a check box and what would be the sql statement to query just the checked records.

Works
I have this and it works just fine but I cant help but think there is a much better way of accomplishing the same thing in one sweep verses 6
PHP Code:
mysql_query("update residential set bed='1' where bed like 'ONE%'");
mysql_query("update residential set bed='2' where bed like 'TWO%'");
mysql_query("update residential set bed='3' where bed like 'THREE%'");
mysql_query("update residential set bed='4' where bed like 'FOUR%'");
mysql_query("update residential set bed='5' where bed like 'FIVE%'");
mysql_query("update residential set bed='6' where bed like 'SIX%'");

Restoring Select Databases/tables From An --all-databases Backup
I use the --all-databases switch to backup my entire database. Sometimes there's a need to restore individual databases or tables form the backup file. What command should I use for this?

Works In MYSQL 4.1 But Not In 5.0
MySQL
1054 - Unknown COLUMN 'p.manufacturers_id' IN 'on clause'
SELECT count(*) as total FROM products p, categories c, products_to_categories p2c LEFT JOIN manufacturers m on (p.manufacturers_id = m.manufacturers_id), products_description pd WHERE c.categories_status=1 AND p.products_id = p2c.products_id AND c.categories_id = p2c.categories_id AND p.products_status = Ƈ' AND p.products_id = pd.products_id AND pd.language_id = Ƈ'

Here is the query in PHP

PHP
"select p.products_id, pd.products_name, p.products_image, p.products_price, p.products_tax_class_id, p.products_date_added, p.manufacturers_id, m.manufacturers_name from " . TABLE_PRODUCTS . " p, " . TABLE_CATEGORIES . " c, " . TABLE_PRODUCTS_TO_CATEGORIES . " p2c left join " . TABLE_MANUFACTURERS . " m on (p.manufacturers_id = m.manufacturers_id), " . TABLE_PRODUCTS_DESCRIPTION . " pd where c.categories_status=1 and p.products_id = p2c.products_id and c.categories_id = p2c.categories_id and p.products_status = Ƈ' and p.products_id = pd.products_id and pd.language_id = '" . (int)$languages_id . "' order by p.products_date_added DESC, pd.products_name";

How Exactly The LIKE Keyword Works?
I have a table named Inventory and have 3 items in it containing the work w069.

I want to run a query to return the three items.

My query: Select * from Inventory where Description Like 'w069'

It doesn't seem to work, returning zero row.

UNION - Works In 4.0.16, Not In 4.1.8
I have a query that works in 4.0.16 on my web host, but not 4.1.8 on my dev. box. Web host is upgrading in 10 days.

Notes:
Server language is ColdFusion
gamedate is type DATE

SELECT DISTINCT gamedate
FROM schedule
WHERE gamedate >= now()
UNION (
(SELECT DISTINCT gamedate
FROM schedule
WHERE gamedate < now()
ORDER BY gamedate desc LIMIT 1)
ORDER BY gamedate asc LIMIT 3

The goal is to select the most recent gamedate prior to "today" and the next two game dates including "today".

Query Only Works Once
I'm using jsp with mysql and am querying the database for data. Everything works fine on the first try. If I click back on my browser and hit submit again on my form, I get no data.

I've tried removing the close() commands but that doesn't seem to work.

SSN Changes In Database But Still Works As Key?
I have a ssn field in a table but somthing happens to the data. I use an update to enter the data and set the value to 123-12-1234 for a test but when I look in the table or I get the record from a record set it come out like -1123.

Why is this? But when I run a query and ask it to return all records which have a ssn of 123-12-1234 it returns the correct record. If this is correct then how can I display the ssn number in a java text field.

How Decimal Works
Say that we have an variable that is

var1 = 3
var2 = 3.65

var3 = var1 * var2 '--- Sum = 10.95

Now my Question!
How do I input this variable into MySQL in a COL whit DECIMAL (10,2)?
I only get the result 10.00 in the COL?
It seams that MySQL round every resout I get to .00 at the end.

If I make an varible hard ex.
var3 = "10.95"
that works but if I convert an numeric variable to string it doesnt?!?!?!
ex.
var4 = cstr(var3)

UPDATE Works In MS SQL
I use the following stament work with MSSql, but not MySql, why ?

Update mytable set mycol = 'my_Text' + mycol

Failed, mycol is varchar

MySQL Delete: Works In Php 5 But Not Php 4?
I've developed a small login system using Xampp on my local machine. Everything is running great except when the admin tries to delete something. Apparently I have the wrong syntax for my deletion in mysql.

Here's my original delete statement (from mysql5):
DELETE at.* FROM access_table AS at WHERE at.client_id=2

And here's the error I get from mysql4 (I ran the command in phpmyadmin console):
#1066 - Not unique table/alias: 'at'

So I removed the aliases and re wrote my command as such:
DELETE * FROM access_table WHERE at.client_id=2

And got the following error from php4:
#1064 - You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '* FROM access_table WHERE at.client_id=2' at line 1

SQL Query Works Only In Win32!
I use MySQL from my php page and from phpMyAdmin.

In Windows Server, following query works fine. In Linux Server instead it returns error.

The SQL Query is:

SELECT DISTINCT a.id, a.container, b.container FROM folder AS a JOIN folder AS b ON a.container=b.id

The PHP error is:

You have an error in your SQL syntax near 'ON a.container=b.id' at line 1

So, I ask: If in Windows this query work fine, where is the error in the Linux version?

JOIN Query Works With 3.23 But Not 4.0.13
I have a simple join query below which queries the name of schools with count of
student numbers for each school from two tables School,Student.

select sc.name,
Sum(if(student.SNO is not null, 1, 0)) nmbr,
from school sc
left outer join student
on sc.school_id = student.school_id
group by sc.school_id

this runs just 0.30 sec with Mysql3.23 but 30Sec with Mysql 4.0.13.
i could not find a solution.But i suspect from NULL threatment.

Parentheses: Query Works With 4.1.7, But Not With 4.1.11
Since we updated to the newest MySQL version (Windows) some of our queries do not work any more.

It's reproducable by this (dummy) query:

SELECT B.ID from ((SELECT * from A) AS T1
INNER JOIN B a ON B.ID = T1.ID);

This works with 4.1.7, but not with 4.1.11, unless the parentheses are removed:

SELECT B.ID from (SELECT * from A) AS T1
INNER JOIN B a ON B.ID = T1.ID;

Does anybody know why MySQL changed its behaviour that way?

I know the parentheses in the first query are not necessary, but it would be quite difficult to search through all our queries for unnecessary parentheses.

JOIN Query Works With 3.23 But Not 4.0.13
I have a simple join query below which queries the name of schools with count of
student numbers for each school from two tables School,Student.....

Exporting MS Works For MySQL
I have a MS Works database and I can't find anything useful on the PHP site for working with this type of database. I did a quick search and it seems that it can be exported for OoenOffice.org and other spreadsheet database programs but none of them give a method. Mostly selling books and MS Access.

If there is a way to access the .MWD or .DBF Microsoft works files with PHP that would be great. If that's not possible, preferably not, I'd rther switch to MySQl easily if possible. I'm still looking but it's not looking good.

Mysql.exe Sort Of Works
I have just installed MySQL (not an easy thing to do). I also have installed PHP. I use Dreamweaver8 for 2 static sites, and eventually will figure out how to use that with PHP/MySQL.
Everything seems to work fine, and I'm working my way through Janet Valade's book, "PHP and MySQL for Dummies." Everything I have tried in the book works perfectly except for the mysql.exe command.
I am in the correct folder and type mysql.exe -u root -p and am prompted for my password. When I enter my password the cursor moves to the next line and just sits there. Nothing happens. Fortunately, the window is not frozen and I can just close it.

Query Works With One Record
This query works great if there is one matching record in the Albums table. When there's more than one matching record it returns nothing.
Code:

SELECT Artists.Artist, Albums.Album_Name
FROM Artists, Albums
WHERE SOUNDEX('colname') = SOUNDEX(Artists.Artist) AND Albums.Artist_ID=Artists.Id

GROUP_CONCAT Problem In 5.0.24 (query Works In 5.0.18)
So on my production server they are running MySQL - 5.0.24-standard. Locally I'm only running 5.0.18 but didn't figure it would be much of a problem, until I noticed that my "results" from certain searches were different with the exact same data on each MySQL version.

The query is this:

Query Help. This Works, But I Don't Think It Is Good Practice
comics:
id
date
location

comments:
id
comicid
datetime
header
comment
author

Every comic can have multiple comments. Each comic will have a comment, but there is a period of time where the comic is posted but the first comment is not yet submitted. So for argument's sake we can't assume there is any comment at all for a given comic.

I want the all the comic ids and dates before a certain date along with the most first comment entered relating to that comic.

select comics.date
, comics.id
, comments.header
from comics
left outer
join comments
on comments.comicid = comics.id
where (comics.date>=񟭇-03-01')
group by comics.id
I never defined WHICH header should be returned when many are grouped together. I just know that mysql will return the first one in this circumstance. I seem to recall reading somewhere that different databases handle this sort of thing differently, with some returning a null in that field?

I keep trying to forumate a useful subquery but keep drawing blanks just as I think I have it figured out in my head. Like I forget how the string starts by the time I mentally formulate the end....

Suddenly A Script No Longer Works
I always get the following message when starting a search in my database:

Search for titles in the mylibrary database.

Search for titles beginning with a:

V. 4.1.7 + Php4 Works, + Php5 Problems
I am running:

Mac OS X 10.3.7
apache 2.0.52
MySQL 4.1.7
php 4.9.3 & php 5.0.3

I have an html form that "POST"s data to a db.
I have a "GET" script to repopulate form for editing.
Everything works fine with php 4.9.3.

With php5.0.3 the data is "POST"ed just fine
(I used a different GUI app to check)
When I try to "GET" said data, form is returned empty?

I have all error reporting turned on = nothing.
I have all backwards-compatibility directives in
php.ini config file turned on.

Two Different Websites Connected To One Database But Only One Works...
I have been recently having problems transferring my website from one domain name to another. The first domain name was used whilst at uni, but the second is my own perosnal website. One the original website, the MySQL database allows the user to login and register new users without any problems.

However, the second website does not allow me to do this. I would consider myself a newbie when its comes to MySQL so I was wondering if the community could help me out on this one. Both websites are hosted by the same company, and both websites use the same database but my limited knowledge cannot solve this problem. Are there certain permissions I need to set or something? Can anyone help me out on this one?

Delete Using Multiple Table: Works On 4.1.20, But Not On 4.0.16
I've a simple delete query delete from joingrp as J using joingrp as J,msggrp as M
where J.msgid=M.msgid and M.parent!=0

When I tried it on phpMyadmin at ixweb, having mysql-4.1.20, it works as desired.
But when I tried it on phpMyadmin at iPowerweb, having 4.0.16, it says
#1064 - You have an error in your SQL syntax.

Check the manual that corresponds to your MySQL server version for the right syntax to use near 'as J using joingrp as J,msggrp as M where J.msgid=M.msgid Can I solve this without using any server-side loops?

My MySQL Back-end Works Very Slow
I have installed my MySQL Server in a Window XP platform running in a Pentium4 machine. When I access the database on the machine, it is working in a normal speed. But when I access the database from a client machine (still running in windows platform), it runs very slow.

SQL Query Works Fine With Phpmyadmin But Gives Me No Results And EOF With ASP
I have a strange problem: when I perform a sql query on my phpmyadmin it works fine and it gives me the right results. If I perform the _same_ query through my asp application I reach immediately the EOF condition without any results!

Can't Update Multiple Rows Via PHP, But Works In PhpMyAdmin
My php script will update 1 row fine, but fails on 2. However, the exact same query works when pasted into phpMyAdmin.

THIS QUERY WORKS BOTH IN MY PHP AND PHPMYADMIN:

$sql = "update table set color='red' where id='1';";
$sql_do = mysql_query($sql);

THIS QUERY WORKS ONLY IN PHPMYADMIN:

$sql = "update table set color='red' where id='1'; update table set color='green' where id='2';";
$sql_do = mysql_query($sql);

I know the second query is correct, because when I copy it from my php code and paste it into phpMyAdmin, it works. But only the first query, with 1 row update, works from my php code.

Quering Works Except Need To Sort Results By Other Table...
I have the following query:

SELECT plugin_id FROM tc_plugin_lists WHERE (page_id='1' AND position='0') ORDER BY tc_plugins.sort_number ASC;

This almost works, the problem is the ORDER BY clause. It should order the results by the sort_number field from another table called tc_plugins. Now it throws an error...

SELECT items FROM other table ORDER BY other tables field values where field is same as in 'items' ASC

?

Using "WHERE LIKE '%Word'" That *will* Use An Index... Works But Feels Stupid!
FYI, I'm using INNODB.

Let's say I have a table with a city column containing 30,000 records, and I want to provide a search form 'starts with' and 'ends with fields.

So a user would supply the following:

Starts with: Cha
Ends with: tte

And the search would find a record such as 'Charlotte'

The 'starts with' search can use an index (eg, LIKE 'Cha%'), but ends with can't (eg, LIKE '%tte').

A solution seems to be to create a city_reverse column, add a unique index on that, then perform an 'ends with' search on the city names in reverse.

For instance, the 'Charlotte' record would be stored in the city_reverse column as such:

'ettolrahC'

...and I'd perform an 'ends with' search using the unique index:

LIKE 'ett%'

The above works, but it feels stupid, and adds weight to the database. Is there an alternative?

Error With SQL Statement When Using MySQL 5.0.24 (Works Fine In MySQL 4.0)
Here is my query that worked in mySQL 4.0 but not in MySQL 5.0.24:

INSERT INTO magtallynew SET magempnum=?', magcentre='YVRRC', entrydate=&#55614;&#57158;-08-15', empnum=?', empcentre='YVRRC', connection='Rockwell', service='Express', region='dom', callertype='CSR', otherdept='', transferredcall='No', directrespdept='No', station='Not Applicable', withoutmagassist='Yes', category='Accounting', issue='Advised On Contact', comments='test'

Here is the error message I get:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'connection='Rockwell', service='Express', region='dom', callertype='CSR', otherd' at line 1

UNION, Individually Works Fine, But Not In Union
Well, I am using an UNION, and while both of the queries works fine while used individually, they don't work while in the UNION.

Here is the code -

PHP

(
SELECT *
FROM job
WHERE date_fin !=0000-00-00
ORDER BY date_fin ASC
)
UNION (
SELECT *
FROM job
WHERE date_fin =0000-00-00
ORDER BY date_creation ASC
)

What do u think guys?

Note : MySQL version 4.1.21

Note : Not working means, this part is not working => 'ORDER BY date_fin ASC', means, the returned results are not ordered as I want.

MySQL doc. tells,

To apply ORDER BY or LIMIT to an individual SELECT, place
the clause inside the parentheses that enclose the SELECT:

(SELECT a FROM t1 WHERE a=10 AND B=1 ORDER BY a LIMIT 10)
UNION
(SELECT a FROM t2 WHERE a=11 AND B=2 ORDER BY a LIMIT 10);

Only Show Duplicates Once
is there any way of showing duplicates only once ?

-- let's say, i have a database of cars, and they search by year...

so, i create a select form that contains the years, but, the years can't show twice or more in that select form..

How Can You Show SUBTOTALS?
How can you show SUBTOTALS in the same column as the data, NOT in a
separate column?

I need to SUBTOTAL in the same column as one of the the data columns,
like the subtotals 700 and 800 under Field 3 below (I really have 21
columns). Also I must show one blank row after each resulting group:

Field1 Field2 Field3 Field4
entry1 data2.1 100 data4.1
entry2 data2.2 400 data4.2
entry3 data2.3 200 data4.3
700
[B L A N K R O W H E R E]
entry4 data2.4 500 data4.4
entry5 data2.5 300 data4.5
800
[B L A N K R O W H E R E]

How can you do this?

How To Show The Warnings?
when i load data into a table using:

mysql> load data local infile ... into table ...,

Mysql gives me:

Query OK, 839 rows affected..
Records: 839 Deleted: 0 Skipped: 0 Warnings: 34

Is there a way to show the 34 warnings to find out what the problem is with the intput data file?

I tried:

mysql> show warnings;

but it did not work.

Show Procedure
I have got some procedures stored in the file. How can read the source code of that procedure using the command line?

How To Show Warning
I create one table, on the screen, it shows query ik, but has 1 warnings, it there any way I can check the details of the warnings by some commands. Code:

Show Statement
I downloaded MySQL a few weeks ago and I'm running it on Linux and Windows now. So far I like what I see. However for newbies like me some things don't make sense.

I can do:
show databases;
show tables;
show create table <tblName>
show create procedure <procName>;
show create function <functionName>;
show triggers;

But I can't do:
show users;
show views;
show procedures;
show functions;
show triggers;
show create user <userName>;

SHOW In A Browser
I am running 5.0.41 community nt and have hit a problem which I am sure is simple to solve but I cannot find the answer.

I want to run and display the results of a SHOW SLAVE STATUS G on a web browser, this is for a regular system check. We could do it via the command prompt but I would like to put the whole operation on a browser screen.