Tracking Forums, Newsgroups, Maling Lists
Home Scripts Tutorials Tracker Forums
 
  HOME    TRACKER    MYSQL




SSN Changes In Database But Still Works As Key?


I have a ssn field in a table but somthing happens to the data. I use an update to enter the data and set the value to 123-12-1234 for a test but when I look in the table or I get the record from a record set it come out like -1123.

Why is this? But when I run a query and ask it to return all records which have a ssn of 123-12-1234 it returns the correct record. If this is correct then how can I display the ssn number in a java text field.




View Complete Forum Thread with Replies

See Related Forum Messages: Follow the Links Below to View Complete Thread
Two Different Websites Connected To One Database But Only One Works...
I have been recently having problems transferring my website from one domain name to another. The first domain name was used whilst at uni, but the second is my own perosnal website. One the original website, the MySQL database allows the user to login and register new users without any problems.

However, the second website does not allow me to do this. I would consider myself a newbie when its comes to MySQL so I was wondering if the community could help me out on this one. Both websites are hosted by the same company, and both websites use the same database but my limited knowledge cannot solve this problem. Are there certain permissions I need to set or something? Can anyone help me out on this one?

Works
I have this and it works just fine but I cant help but think there is a much better way of accomplishing the same thing in one sweep verses 6
PHP Code:
 mysql_query("update residential set bed='1' where bed like 'ONE%'");
mysql_query("update residential set bed='2' where bed like 'TWO%'");
mysql_query("update residential set bed='3' where bed like 'THREE%'");
mysql_query("update residential set bed='4' where bed like 'FOUR%'");
mysql_query("update residential set bed='5' where bed like 'FIVE%'");
mysql_query("update residential set bed='6' where bed like 'SIX%'"); 

Works In MYSQL 4.1 But Not In 5.0
MySQL
1054 - Unknown COLUMN 'p.manufacturers_id' IN 'on clause' 
SELECT count(*) as total FROM products p, categories c, products_to_categories p2c LEFT JOIN manufacturers m on (p.manufacturers_id = m.manufacturers_id), products_description pd WHERE c.categories_status=1 AND  p.products_id = p2c.products_id AND c.categories_id = p2c.categories_id AND  p.products_status = Ƈ' AND  p.products_id = pd.products_id AND pd.language_id = Ƈ'

Here is the query in PHP

PHP
"select p.products_id, pd.products_name, p.products_image, p.products_price, p.products_tax_class_id, p.products_date_added, p.manufacturers_id, m.manufacturers_name from " . TABLE_PRODUCTS . " p, " . TABLE_CATEGORIES . " c, " . TABLE_PRODUCTS_TO_CATEGORIES . " p2c left join " . TABLE_MANUFACTURERS . " m on (p.manufacturers_id = m.manufacturers_id), " . TABLE_PRODUCTS_DESCRIPTION . " pd where c.categories_status=1 and p.products_id = p2c.products_id and c.categories_id = p2c.categories_id and p.products_status = Ƈ' and p.products_id = pd.products_id and pd.language_id = '" . (int)$languages_id . "' order by p.products_date_added DESC, pd.products_name";

How Exactly The LIKE Keyword Works?
I have a table named Inventory and have 3 items in it containing the work w069.

I want to run a query to return the three items.

My query: Select * from Inventory where Description Like 'w069'

It doesn't seem to work, returning zero row.

UNION - Works In 4.0.16, Not In 4.1.8
I have a query that works in 4.0.16 on my web host, but not 4.1.8 on my dev. box. Web host is upgrading in 10 days.

Notes:
Server language is ColdFusion
gamedate is type DATE

SELECT DISTINCT gamedate
FROM schedule
WHERE gamedate >= now()
UNION (
(SELECT DISTINCT gamedate
FROM schedule
WHERE gamedate < now()
ORDER BY gamedate desc LIMIT 1)
ORDER BY gamedate asc LIMIT 3

The goal is to select the most recent gamedate prior to "today" and the next two game dates including "today".

Query Only Works Once
I'm using jsp with mysql and am querying the database for data. Everything works fine on the first try. If I click back on my browser and hit submit again on my form, I get no data.

I've tried removing the close() commands but that doesn't seem to work.

How Exactly The LIKE Keyword Works?
I have a table named Inventory and have 3 items in it containing the work w069.

I want to run a query to return the three items.

My query: Select * from Inventory where Description Like 'w069'

It doesn't seem to work, returning zero row.

How Decimal Works
Say that we have an variable that is

var1 = 3
var2 = 3.65

var3 = var1 * var2   '--- Sum = 10.95

Now my Question!
How do I input this variable into MySQL in a COL whit DECIMAL (10,2)?
I only get the result 10.00 in the COL?
It seams that MySQL round every resout I get to .00 at the end.

If I make an varible hard ex.
var3 = "10.95"
that works but if I convert an numeric variable to string it doesnt?!?!?!
ex.
var4 = cstr(var3)

UPDATE Works In MS SQL
I use the following stament work with MSSql, but not MySql, why ?

Update mytable set mycol = 'my_Text' + mycol

Failed, mycol is varchar

MySQL Delete: Works In Php 5 But Not Php 4?
I've developed a small login system using Xampp on my local machine. Everything is running great except when the admin tries to delete something. Apparently I have the wrong syntax for my deletion in mysql.

Here's my original delete statement (from mysql5):
DELETE at.* FROM access_table AS at WHERE at.client_id=2

And here's the error I get from mysql4 (I ran the command in phpmyadmin console):
#1066 - Not unique table/alias: 'at'

So I removed the aliases and re wrote my command as such:
DELETE * FROM access_table WHERE at.client_id=2

And got the following error from php4:
#1064 - You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '* FROM access_table WHERE at.client_id=2' at line 1

SQL Query Works Only In Win32!
I use MySQL from my php page and from phpMyAdmin.

In Windows Server, following query works fine. In Linux Server instead it returns error.

The SQL Query is:

SELECT DISTINCT a.id, a.container, b.container FROM folder AS a JOIN folder AS b ON a.container=b.id

The PHP error is:

You have an error in your SQL syntax near 'ON a.container=b.id' at line 1

So, I ask: If in Windows this query work fine, where is the error in the Linux version?

SHOW DATABASES Works In 4.0.14
I've been trying to solve this problem for a long time. Only thing
I did when upgrading from 3.25 to 4.0.14 I took the default my.cnf. I
did not convert the privilege tables with mysql_fix_privilege_tables.

Suddenly, the mysql started to show all databases to all users (even
though the user had access denied and could not do show tables on
them). So I started to find help and tried the
mysql_fix_privilege_tables. It didn't work properly (more than just
access denied and errors, that are ok) so I did the changes manually
conforming to source code of mysql_fix_privilege tables.

PhpMyAdmin stopped its warning about privilege tables not conforming
to current mysql version. Everything seemed ok except that SHOW
DATABASES still worked.

The users naturally all have Show_db_priv="N" in the tables. Also
trying "safe_show_database", "skip_show_database" in my.cnf and
"--skip-show-database" witch mysqld didn't help.

JOIN Query Works With 3.23 But Not 4.0.13
I have a simple join query below which queries the name of schools with count of
student numbers for each school from two tables School,Student.

select sc.name,
Sum(if(student.SNO is not null, 1, 0)) nmbr,
from school sc
left outer join student
on sc.school_id = student.school_id
group by sc.school_id

this runs just 0.30 sec with Mysql3.23 but 30Sec with Mysql 4.0.13.
i could not find a solution.But i suspect from NULL threatment.

Parentheses: Query Works With 4.1.7, But Not With 4.1.11
Since we updated to the newest MySQL version (Windows) some of our queries do not work any more.

It's reproducable by this (dummy) query:

SELECT B.ID from ((SELECT * from A) AS T1
INNER JOIN B a ON B.ID = T1.ID);

This works with 4.1.7, but not with 4.1.11, unless the parentheses are removed:

SELECT B.ID from (SELECT * from A) AS T1
INNER JOIN B a ON B.ID = T1.ID;

Does anybody know why MySQL changed its behaviour that way?

I know the parentheses in the first query are not necessary, but it would be quite difficult to search through all our queries for unnecessary parentheses.

JOIN Query Works With 3.23 But Not 4.0.13
I have a simple join query below which queries the name of schools with count of
student numbers for each school from two tables School,Student.....

SHOW DATABASES Works In 4.0.14
I've been trying to solve this problem for a long time. Only thing
I did when upgrading from 3.25 to 4.0.14 I took the default my.cnf. I
did not convert the privilege tables with mysql_fix_privilege_tables.

Suddenly, the mysql started to show all databases to all users (even
though the user had access denied and could not do show tables on
them). So I started to find help and tried the
mysql_fix_privilege_tables. It didn't work properly (more than just
access denied and errors, that are ok) so I did the changes manually
conforming to source code of mysql_fix_privilege tables.

PhpMyAdmin stopped its warning about privilege tables not conforming
to current mysql version. Everything seemed ok except that SHOW
DATABASES still worked.

The users naturally all have Show_db_priv="N" in the tables. Also
trying "safe_show_database", "skip_show_database" in my.cnf and
"--skip-show-database" witch mysqld didn't help.

All *.frm files in mysql database have the same md5 as those generated
by scripts/mysql_install_db.

Exporting MS Works For MySQL
I have a MS Works database and I can't find anything useful on the PHP site for working with this type of database. I did a quick search and it seems that it can be exported for OoenOffice.org and other spreadsheet database programs but none of them give a method. Mostly selling books and MS Access.

If there is a way to access the .MWD or .DBF Microsoft works files with PHP that would be great. If that's not possible, preferably not, I'd rther switch to MySQl easily if possible. I'm still looking but it's not looking good.

Mysql.exe Sort Of Works
I have just installed MySQL (not an easy thing to do). I also have installed PHP. I use Dreamweaver8 for 2 static sites, and eventually will figure out how to use that with PHP/MySQL.
Everything seems to work fine, and I'm working my way through Janet Valade's book, "PHP and MySQL for Dummies." Everything I have tried in the book works perfectly except for the mysql.exe command.
I am in the correct folder and type mysql.exe -u root -p and am prompted for my password. When I enter my password the cursor moves to the next line and just sits there. Nothing happens. Fortunately, the window is not frozen and I can just close it.

Query Works With One Record
This query works great if there is one matching record in the Albums table. When there's more than one matching record it returns nothing.
Code:

SELECT Artists.Artist, Albums.Album_Name
FROM Artists, Albums
WHERE SOUNDEX('colname') = SOUNDEX(Artists.Artist) AND Albums.Artist_ID=Artists.Id

GROUP_CONCAT Problem In 5.0.24 (query Works In 5.0.18)
So on my production server they are running MySQL - 5.0.24-standard. Locally I'm only running 5.0.18 but didn't figure it would be much of a problem, until I noticed that my "results" from certain searches were different with the exact same data on each MySQL version.

The query is this:

Query Help. This Works, But I Don't Think It Is Good Practice
comics:
id
date
location

comments:
id
comicid
datetime
header
comment
author

Every comic can have multiple comments. Each comic will have a comment, but there is a period of time where the comic is posted but the first comment is not yet submitted. So for argument's sake we can't assume there is any comment at all for a given comic.

I want the all the comic ids and dates before a certain date along with the most first comment entered relating to that comic.

select comics.date
, comics.id
, comments.header
from comics
left outer
join comments
on comments.comicid = comics.id
where (comics.date>=&#392007;-03-01')
group by comics.id
I never defined WHICH header should be returned when many are grouped together. I just know that mysql will return the first one in this circumstance. I seem to recall reading somewhere that different databases handle this sort of thing differently, with some returning a null in that field?

I keep trying to forumate a useful subquery but keep drawing blanks just as I think I have it figured out in my head. Like I forget how the string starts by the time I mentally formulate the end....

Suddenly A Script No Longer Works
I always get the following message when starting a search in my database:

Search for titles in the mylibrary database.

Search for titles beginning with a:

V. 4.1.7 + Php4 Works, + Php5 Problems
I am running:

Mac OS X 10.3.7
apache 2.0.52
MySQL 4.1.7
php 4.9.3 & php 5.0.3

I have an html form that "POST"s data to a db.
I have a "GET" script to repopulate form for editing.
Everything works fine with php 4.9.3.

With php5.0.3 the data is "POST"ed just fine
(I used a different GUI app to check)
When I try to "GET" said data, form is returned empty?

I have all error reporting turned on = nothing.
I have all backwards-compatibility directives in
php.ini config file turned on.

Delete Using Multiple Table: Works On 4.1.20, But Not On 4.0.16
I've a simple delete query delete from joingrp as J using joingrp as J,msggrp as M
where J.msgid=M.msgid and M.parent!=0

When I tried it on phpMyadmin at ixweb, having mysql-4.1.20, it works as desired.
But when I tried it on phpMyadmin at iPowerweb, having 4.0.16, it says
#1064 - You have an error in your SQL syntax.

Check the manual that corresponds to your MySQL server version for the right syntax to use near 'as J using joingrp as J,msggrp as M where J.msgid=M.msgid Can I solve this without using any server-side loops?

My MySQL Back-end Works Very Slow
I have installed my MySQL Server in a Window XP platform running in a Pentium4 machine. When I access the database on the machine, it is working in a normal speed. But when I access the database from a client machine (still running in windows platform), it runs very slow.

SQL Query Works Fine With Phpmyadmin But Gives Me No Results And EOF With ASP
I have a strange problem: when I perform a sql query on my phpmyadmin it works fine and it gives me the right results. If I perform the _same_ query through my asp application I reach immediately the EOF condition without any results!

Can't Update Multiple Rows Via PHP, But Works In PhpMyAdmin
My php script will update 1 row fine, but fails on 2. However, the exact same query works when pasted into phpMyAdmin.

THIS QUERY WORKS BOTH IN MY PHP AND PHPMYADMIN:

$sql = "update table set color='red' where id='1';";
$sql_do = mysql_query($sql);

THIS QUERY WORKS ONLY IN PHPMYADMIN:

$sql = "update table set color='red' where id='1'; update table set color='green' where id='2';";
$sql_do = mysql_query($sql);

I know the second query is correct, because when I copy it from my php code and paste it into phpMyAdmin, it works. But only the first query, with 1 row update, works from my php code.

Quering Works Except Need To Sort Results By Other Table...
I have the following query:

SELECT plugin_id FROM tc_plugin_lists WHERE (page_id='1' AND position='0') ORDER BY tc_plugins.sort_number ASC;

This almost works, the problem is the ORDER BY clause. It should order the results by the sort_number field from another table called tc_plugins. Now it throws an error...

SELECT items FROM other table ORDER BY other tables field values where field is same as in 'items' ASC

?

Using "WHERE LIKE '%Word'" That *will* Use An Index... Works But Feels Stupid!
FYI, I'm using INNODB.

Let's say I have a table with a city column containing 30,000 records, and I want to provide a search form 'starts with' and 'ends with fields.

So a user would supply the following:

Starts with: Cha
Ends with: tte

And the search would find a record such as 'Charlotte'

The 'starts with' search can use an index (eg, LIKE 'Cha%'), but ends with can't (eg, LIKE '%tte').

A solution seems to be to create a city_reverse column, add a unique index on that, then perform an 'ends with' search on the city names in reverse.

For instance, the 'Charlotte' record would be stored in the city_reverse column as such:

'ettolrahC'

...and I'd perform an 'ends with' search using the unique index:

LIKE 'ett%'

The above works, but it feels stupid, and adds weight to the database. Is there an alternative?

Error With SQL Statement When Using MySQL 5.0.24 (Works Fine In MySQL 4.0)
Here is my query that worked in mySQL 4.0 but not in MySQL 5.0.24:

INSERT INTO magtallynew SET magempnum=?', magcentre='YVRRC', entrydate=&#55614;&#57158;-08-15', empnum=?', empcentre='YVRRC', connection='Rockwell', service='Express', region='dom', callertype='CSR', otherdept='', transferredcall='No', directrespdept='No', station='Not Applicable', withoutmagassist='Yes', category='Accounting', issue='Advised On Contact', comments='test'

Here is the error message I get:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'connection='Rockwell', service='Express', region='dom', callertype='CSR', otherd' at line 1

UNION, Individually Works Fine, But Not In Union
Well, I am using an UNION, and while both of the queries works fine while used individually, they don't work while in the UNION.

Here is the code -

PHP

(
SELECT *
FROM job
WHERE date_fin !=0000-00-00
ORDER BY date_fin ASC
)
UNION (
SELECT *
FROM job
WHERE date_fin =0000-00-00
ORDER BY date_creation ASC
)

What do u think guys?

Note : MySQL version 4.1.21

Note : Not working means, this part is not working => 'ORDER BY date_fin ASC', means, the returned results are not ordered as I want.

MySQL doc. tells,

To apply ORDER BY or LIMIT to an individual SELECT, place
the clause inside the parentheses that enclose the SELECT:

(SELECT a FROM t1 WHERE a=10 AND B=1 ORDER BY a LIMIT 10)
UNION
(SELECT a FROM t2 WHERE a=11 AND B=2 ORDER BY a LIMIT 10);

User Problems... Only Root User &quot;works&quot;.
i have been trying to figure this strange problem out for a week or so. here it is.

i have a set of users with various permissions for different reasons. about 2 weeks ago, my hardware suffered a fairly nasty failure. i recovered everything. things seemed to work out. i didnt think to check my phpBB forums or my blog (or other mysql based stuff). never had any problems with the DB... so, maybe i am missing something simple here. i hope so.

what my users can do:

they can log in via command line, a gui i use on mac os x and it does not matter if it is local, or remote. they work just fine.

what all but one users cannot do:

none of my users can run phpbb or the blog stuff.. except for the root user. any other user returns the error message written in the code of which ever script i try to access telling me that "could not connect to DB" etc..

root works fine.

now, i thought maybe it was a problem with the forums and other stuff. but i cant be. same thing happens with all things... even a game server i occasionally run that keeps account info in a DB.

all these users are set up properly and have worked just fine in the past. nothing new has been installed, no conf changes..im at a loss...

Could Not Connect To The Database, Please Recheck The Settings You Specified. Also Make Sure That A Database With The Name You Specified Already Exists On The Database Server. PhpAdsNew Will Not Create The Database For You, You Must Create It Manually
The error message I get above is the same everytime when trying to install phpAdsnew. I have tried everything. I am hosted through yahoo! and have actually succesfully installed scripts before even though I know nothing about it. Now that I have a "auto-install", it does not work. Yahoo! also offers php-nuke with the auto-install where you just click a few buttons, and I get a similar error stating that it can not conect to the database.

Please can anyone help me and tell me what I am doing wrong?

Database Transfer Between Oracle 8 Database And MySQL Database
Is it somebody out there who has made a migration from an Oracle server to an MySQL server??

The scenario is as simply:

I've got a Oracle 8 server with a database with content that I want to transfer to a MySQL database. No special data, constraints etc that MySQL not will handle.

My solution is to reverse engineer the database from ERStudio and then produce a SQL script that will insert the data into the MySQL engine.

But I can't do this, because the customer want me to do a PL/SQL script that does this, even if he never have worked with Oracle.. So the question is.. Do someone know a simplier way to do this or do I have to teach myself PL/SQL and make a script that produces a MySQL sql script ?

Create Error: Access Denied For User: '@localhost' To Database 'database Name'
I have already installed the php4, apache and mySQL on windowsXP SP2.
when I wanted to create database through PHP code it showed me error like this "Create Error: Access denied for user: '@localhost' to database 'database name'" and I can't even create database using mySQL either.

Script For Uploading Data From Local Database To Production Database
I am using MYSQL 4.0 for my local and production databases. I want to extract selected records from selected tables from local database and upload them to my production database on daily basis. In other words, I want to upload data which is entered in local database on daily basis to my production database.

How To Apply New Database Structure To An Existing Database, Without Overwriting Data?
I am writing a simple blog software application. We released a version of this software a while ago.

It comes with a sql-tables.sql file, that you can just import into your mysql database and it will setup all the tables for you, for a fresh installation. We made the sql file by just doing an export I believe, without exporting the data that was in OUR database.

Well, since then several people have downloaded and installed our software, and are using it.

We are about to release a new version soon, however. Since it is all still under development, many things have changed in our database structure. We've added new tables, and modified or even removed fields from existing tables.

So for the new release, we're going to include a new sql-tables.sql file obviously, so that for fresh installations they can still install it just like normal.

However, the question is... how do you "upgrade" all the previous version's users's databases, without losing any of their data?

Is there anyway to export just the structure of our current database... then somehow apply it so that it just goes through and changes another database to match the new structure?

Or any ideas at all how to do this?

How To Convert MS Access Database To Mysql Database??
now i have more than ten thousand data in MS Access database and now i heed change it in to mysql database!So do you know how to that?I think i not time to key in back this all data because it is imposible la,because more than 10 thousand data la!

Converting Ms Access Database To Mysql 5 Database
I've imported a ms access database into a table in a mysql database.
The access database contains a field that holds date/time values in
'general date' format. These all show up at 01/01/1970 in the mysql
database. I believe the field in mysql is wanting UTC and shows
numbers when looked at from the sql command line (i.e. March 13, 2006,
5:31 pm is shown as 1142289086). How do I get the access data into
that format so it will import properly?

Cannot Select Database: No Database Selected
This is the error I get in multiple locations on my website. I am using postnuke for my website. I get this error when I try to access my PostCalendar, PNaddressbook, the modules area in the admin screen, the permissions area in the admin screen, and the blocks area in my admin screen. I had a backup of the entire postnuke folder when it was working. I replaced it with the functional postnuke backup and the problem still exists. I know it isn't Postnuke. The only possible problem could be in MySQL.

Database Error : No Database Selected
I am trying to install an application called weberp on my website.

I have writen a script to test that the database name, user name, and password are all correct, and mysql is there and running okay.

I entered a script into myphpadmin to establish the database. All the tables, and so forth, were created with no errors.

How To Convert .dbf Database To Mysql Database
i want to convert .dbf database to mysql database. i have my college results in .dbf format file. i want to convert it from .dbf to .sql .

Database Error : No Database Selected
I am using myphpadmin to try and install weberp on a website.

I keep getting this error, and I can't figure out why.

The username, password, and database name; are all correct. The script to set up the database ran with no problems.

Extracting Data From Large SINGLE-table Database To MULT-table Relational Database
I have a very large single-table database of articles that I want to convert to a multi-table, relational database.

The existing single-table database contains fields for article author, article source, and article category, where several 'author', 'source', and 'category' IDs repeat dozens of times for hundreds of different articles.

I want to create seperate tables for author, source, and category and populate the new tables by extracting data from the original single-table database by unique ID field.

I figured out how to use INSERT and SELECT to pull data in new tables, but can't figure out how to pull only a single instance of a unique author, source, and category to create master reference tables for author/source/category.

Convert Ver 4.0 Database To Ver 4.1 Database
I do not know if this is the correct forum to ask this in or not.
We have changed hosts and the old hosting company was running MySQL version 4.0.27 standard and our new host is running MySQL version 4.1.22 Standard.
We have a database from the old host that we need to convert to MySQL ver 4.1.22 so we can use it on the new host.
We were running a older version of SugarCRM on the old host but we upgraded when we went to the new host and the new version of SugarCRM will not work with the copy of our old database file. It says that it needs MySQL version 4.1.2 or higher.
Is there any way to convert the old data base.

How To Copy Mysql Database Table To Another Mysql Database
i have database named(rocky) in the other domain how can i copy it in nessan database in the other domain.

Dropping Database Called &quot;database&quot;
I have finally managed to install and configure mysql on my pc for testing but need to import data from an Access Database.

I first found out that I had to create a new user and grant priviledges to it - which means I could connect.

My next stage was using the migration tool to import the data.

This did not go so well...

Firstly, many of the table names had spaces in them which means that they are effectively useless in mysql.

So I thought I would start again, ensuring that the tables are first renamed in Access.

I then went to show databases and, during the migration process, it has given the imported data the default name of "database".

I now have a major problem deleting it as it thinks the name is an instruction!

Anyone know how to get over this issue?

Move Table From A Database To Another Table In A Database
I am currently developing a project as I am only a web designer.

I need to move a table from a database to another table in a database.

I am using SQL Server 2005 Express. How is this done?

I have been stuck for months trying to figure this out!

I have even bought SQL Server Express 2005 for Dummies and cannot figure this out!

I need someone to hold my hand and walk me through this literally! Or give me syntax code to do this.

Database
I'm working on a table which contains every member of our website. The table has 5 fields.

Name
Rank
Joindate
Picture
Information

The last one is the one that is bewildering me. You see, my goal is to have the information show up for each member's page. Now this information is several paragraphs long for each member. My question is how I should go about putting the information in the table. Should the information itself be in a .txt file and the url to it be in the table? What datatype should I use for the url, varchar? Is there a completely different way to do this?


Copyright © 2005-08 www.BigResource.com, All rights reserved