MYSQL :: Unknown Option -- Log-bin

Mysql: Unknown Option '--ndbcluster'
Running into some issues while configuring my cluster....

I'm setting up a cluster with two storage nodes and one management node...
The problem I'm having is that when I try to open MySQL on one of the storage nodes I get this error...

mysql: unknown option '--ndbcluster'

but i do not get this error on the other storage node and i am able to access MySQL on it.

The my.cnf file looks like this:

[mysqld]
datadir=/var/lib/mysql
socket=/var/lib/mysql/mysql.sock
# Default to using old password format for compatibility with mysql 3.x
# clients (those using the mysqlclient10 compatibility package).
old_passwords=1

[mysql.server]
user=mysql
basedir=/var/lib

[mysql_safe]
err-log=/var/log/mysqld.log
pid-file=/var/run/mysqld/mysqld.pid

#Options for MySQLD process
[MYSQL]
ndbcluster #run ndb engine
ndb-connectstring=x.x.x.x #location of MGM node

#Options for ndbd process
[MYSQL_CLUSTER]
ndb-connectstring=x.x.x.x #location of MGM node

If anyone can let me know what the problem is it would be greatly appreciated...
I'm running Fedora Core 4 and MySQL 5.0.19 MAX

Solaris 8 Daemon Fails Because Unknown Option?
I guess people did not see my post from the install thread... I am really really stuck now! Does anyone work on Solaris???

Whatever option I use to start the daemon I get this:

050310 15:27:35 mysqld started
050310 15:27:35 [ERROR] /opt/mysql/bin/mysqld: unknown option '--~'

Please Help

Note that I am using the binaries from this site.

Error In Command Line: Mysql: Unknown Option '--ansi'
Whenever I try to run 'mysql' from the command line (windows server 2k3), I get the following message: mysql: unknown option '--ansi'

This occurs if I try to start mysql with just the mysql command or if i try to specify a user, password, and db.

OPTION Value
Here's the connection string I use commonly with my VFP9 apps connecting to a MySQL5 backend:

DRIVER={MySQL ODBC 3.51 Driver};SERVER=localhost;UID=mike;PWD=foxrocks;DATABASE=mydb;option=131609

I was wondering what other values for the OPTION parameter folks use? Sometimes, I get some flakiness, so I was searching for a consensus on "best option value to use."

Binary Log Off Option ?
I am using mysql version 4.0.22.
Which file to access and modify If i want to disable binary logs which are created in mysqlvar ?

Sql Option ALLOW_INVALID_DATES
how to implelent 'ALLOW_INVALID_DATES' option for sql mode?
I was able to run

SET GLOBAL sql_mode='ANSI';

but can't get the syntax of ALLOW_INVALID_DATES ...

Can't Set The Table Option
I've use the command CREATE TABLE as follow:

CREATE TABLE test(myid varchar(20)) DEFAULT CHARSET=latin1

and

CREATE TABLE test(myid varchar(20)) DEFAULT CHARACTER SET latin1

I've got an error message with the 2 commands above saying that I've used the wrong syntax near the "DEFAULT CHARSET=latin1" clause. I've read the MySQL Document and figured out those commands have the right syntax, not wrong.

Could anyone please tell me how to create a table with DEFAULT CHARSET=latin1.
( I have use MySQl ver 4.0 ).

Subselect In 4.0.12-max With -- New Option
I was reading the manual and it said that the subselect is only
available in 4.1 or using the 4.0.12 with the mysqld =96new command line
to start it.

But it doesn=92t working!! So I downloaded the 4.1 alpha version with =
the
same problem. The error is:

ERROR 1064: You have an error in your SQL syntax. Check the manual that
corresponds to your MySQL server version for the right syntax to use
near =85.

Any ideas? I need subselect working.

--force Option
I'm using a batch file to insert data into my database.
I read in the manual that using the --force option makes mysql to continue processing the batch file, although there was an error like "table does not exist" or something like that.

However I noticed that mysql still quits if it tries to insert data in a table that not exists.

I'm using mysql 5.0.19 under a windows xp system

the command i'm executing is as follows:

mysql -u root --force databasename < "path/to/batch.sql"

MySQL Replacement Option
I want to replace a character "/" with &frasl; in my database, is there any option to do that.

Local-infile Option
I´m using mysql 3.23.58 and I want to enable the local-infile option.
The manual on dev.mysql.com says the following to that:

.....
If you use LOAD DATA LOCAL in Perl scripts or other programs that read
the [client] group from option files, you can add the local-infile=1
option to that group. However, to keep this from causing problems for
programs that do not understand local-infile, specify it using the
loose- prefix:

[client]
loose-local-infile=1
......

But when I do that the I can restart the mysql-Server but starting of
mysqladmin says the following:

Unrecognized option local-infile

The same message with loose-local-infile=1.

When I start the server with --local-infile=1 and then starting the
mysql-Client with --local-infile=1 on the shell everything is OK and I
can use the LOAD DATA LOCAL Syntax.

What is wrong? Why it is an unregognized command? I need the LOAD DATA
LOCAL because I want to use mysql with Perl.

Disable -- User Option
I would like to use unix user names to login to mysql. If I create a mysql user xxadmin and leave the password empty other unix users can use the xxadmin with the --user option . How can I make sure that only the unix user xxadmin can login as mysql user xxadmin ?

Error =SET OPTION SQL_BIG_SELECTS=1
I add a few more test records to my db.... the result the following error message...

Vbscript Runtime error 'ASP 0185 : 3219'

General error: The SELECT would examine too many records and probably take a very long time. Check your WHERE and use SET OPTION SQL_BIG_SELECTS=1 if the SELECT is ok

Well to the best of my knowledge my WHERE could not be more simple and all the tables concerned don't have that many records.

I've scanned the net but cannot find an obvious answer. Any clues... if I need to use "SET OPTION... how do I do this within ASP. Code:

Browse Option Not Shown?
However, some fields won't let me browse what are in the fields. I have full admin access tot the website. If any1 doesn't know what im talking about, I could post a screenshot, if nessessary.

Mysql --force Option
I'm using a batch file to insert data into my database.
I read in the manual that using the --force option makes mysql to continue processing the batch file, although there was an error like "table does not exist" or something like that.

However I noticed that mysql still quits if it tries to insert data in a table that not exists.

I'm using mysql 5.0.19 under a windows xp system

the command i'm executing is as follows:

mysql -u root --force databasename < "path/to/batch.sql"
Xema

Joining User Option Lists
I have a niggly problem that I can't quite work out which I'm sure has a simple answer (have to be missing something).

I have a table of 7 categories, each with a unique ID and name.
A seperate table is a category/user mapping table which maps users to a category.

For example, if a user is a a member of 4/7 categories, they have 4 rows in the mapping table, each one with their userID/catID in it.

What I'm attempting to do is select a list of ALL categories and join (where applicable) the category map so I can present all options regardless of whether the user is a member of a particular category or not (but I do need to know if they are or not).

PHP

SELECT *
FROM categories
LEFT JOIN category_map ON categories.id = category_map.c_id
WHERE category_map.u_id=10

I had some success with adding OR category_map.u_id IS NULL but returns odd results when there are 0 rows present for a user in the category_map table.

Printing A Result After An Option Has Been Submitted
My goal is this.- To print another field value 'scriptcode', of the same row after an option 'scriptnaam' is submitted.

The first part isn't the problem. I do get all the data 'scriptnaam' in a select field.
But to distillate, a result 'scriptcode' out of it ???

If someone could help me a bit further with that, that would be great.
I like to mention, that I've just started with PHP/MYSQL, so my knowledge about it is limited. Code:

MySQL Performance - Option Setting
I set OPTION=3 in my connection string as recommended by MySQL
(http://dev.mysql.com/doc/refman/5.0...parameters.html)
for a VB application.

OPTION=3 is Don't Optimised Column Width (1) and Return Matching Rows (2).

I found this to be very slow on a database with just 27,000 records. It took
approx. 12 seconds to read 27,000 records.

When I change the OPTION to 8 (Allow Big Results), it took just 3 seconds to
read 27,000 records. BUT now my application cannot update records anymore
and getting random errors on transactions.

I try setting OPTION=11 (all 3 options added together) and the speed went
back to being slow.

Slave-load-tmpdir Option
I have just installed mysql server 5.0. However, when I was trying to start the server by invoking mysqld, it complained that a directory/file is not found.

I then viewed the variable names and found that the slave-load-tmpdir variable was pointing to a non-existing path. I have tried

mysqld --slave-load-tmpdir=<my new path> --standalone

but whenever I restart the mysqld, the variable is still defaulted to that old path....what should I do to change the default setting for this variable?

Check Table Command - When To Use Which Checking Option
I'm trying to decide which check table option to use for a DB-health-check script for my product. This script is to be run periodically to find and repair damaged tables. My product uses only MySQL, i.e. it does not interact with another DB. I need to find the check table option that would find damaged tables with the highest possible performance.

The 13.5.2.3 CHECK TABLE Syntax documentation states the following:
MEDIUM Scan rows to verify that deleted links are okay. This also calculates a key checksum for the rows and verifies this with a calculated checksum for the keys.

What are they referring to with the word "links"? Are they talking about links to MS Access tables? How do I know if my tables have links? Does the MEDIUM option scan rows only to check deleted links? If so, if I don' t have "deleted links", should I not use this option? By running in MEDIUM mode, will the tables be locked while "check table" is working?

For the other options - CHANGED, FAST, QUICK - will "check table" lock the tables? What access do I have to the tables while check table is running?

Symbolic Links With Windows XP Or Option Datadir
How do you make symbolic links work ?

Drop Down Menu: Option Equal To All Others In The List
I would like to create a drop down menu in a form that selects distinct arrays from a columname, inserts them into a drop down menu, but then I also want one of the options to be equal to all of the rest. I would end up with a drop down structured like this:

All colors
Red
Blue
Green
Purple

Root Login Does Not Work Correctly Without -h Option
For example, I would expect to be able to sign in by using.

mysql -u root -p

The above gives me accessed denied.

Now, I need to do.

mysql -h <hostname> -u root -p

It seems like a simple problem that I have not been able to solve by searching here and google.

Show All Entries, Then Give An Edit Or Delete Option
I want to show all the entries that are in a database. below each of them I want a radio button that when checked will either allow them to edit or delete the entry. How might I do this?

Enable The Option Flag Return Matching Rows
I would like to know if it's possible to enable the "Return matching rows" flag with a connection string. With a dsn connection i already know how can i do this.

Binding Option Button Controls On Unbound Forms
I am using an MS Access 2002 as a Frontend to a MYSQL 5.0.18 database server backend. I am attempting to set up unbound forms using a dsn-less ADO connection. I have been able to bind the textbox and combobox controls to the fields within my form however I am having difficulties binding boolean field types to my option button controls.

1) Has anyone had any success in binding option button controls to MySQL boolean fields?

2) On another point, in the unbound forms do you set up your own navigation controls or are you able to utilize the standard form navigation controls provided by Access.Again it seems the option button controls do not stay synchronized to the current record.

3) Also after creating a recordset and binding it to my form and binding the controls, I close the recordset and the connection object.After making changes to a current record, if I navigate to the next record in the recordset any changes I made in the previous record are automatcially reflected in the MYSQL tables. The user is not prompted to save changes; it does it automatically.I'm new to using ADO and was surprised to see that this was possible since the connection object had been closed.How do you go about preventing the direct writing to MySQL without informing the user that they are doing so?Where is the code for the navigation buttons events?Is it possible to 'hook' into them?

Best Way To Deal With Linking Tables And Foreign Keys When InnoDB Is Not An Option.
Title covers most of it.

On database insertion I suffer from a lack of transactions, which means I can enter the data into the primary database, then have the database fail with exactingly bad timing and fail when I am making my entries in other tables or the linking table.

On data deletion I suffer from a lack of foreign key constraints so again the database can fail after I delete my entry from my main table, but before I enter the data for my linking tables.

My biggest conern is that I end up with data in the linking tables but not in the main table. Then if I tried to re-enter that main entry with those linking table entries I would get an error due to duplication of the primary key (concacted id of the two foreign keys) in my linking table.

I am considering elaborate if loops in my php to try and catch errors and delete the whole entry if the errors occur. The problem being that the errors will occur when the database is misbehaving so my odds that the delete will work might be somewhat low.

Has anyone else had to work withou InnoDB much in scenarios like this?

Unknown Variable
Hi I am getting an error trying to set a vairable in /etc/my.cnf

I appended this line under mysqld
CODEft_boolean_syntax="+ -><()~*:""&|"

Unknown SQL Type
For some reason i get this error for queries when i run them in VB.NET. But when i run the query in MySQL Query Analyzer it works perfectly fine. Is anyone familiar with this error Unknown SQL type - 0.

Unknown Column
i was using an older version of mysql on my laptop and working on a portal project,
all was going well, no problems even using php5,
i have now upgraded to mysql 5.0.18 and when i try and access the profile page of the forum i get this error....
i'll past the query first then the error i am now getting.

Quote:if ($user_result = db_fetch_array(db_query("select user.*,groups.online_template_large,session.url,session.sessionid from user,groups left join session on session.userid=user.userid where user.userid='$_REQUEST[id]' and user.groupid=groups.groupid order by session.lastactivity desc limit 1")))

Unknown Column XXX In 'on Clause' - :(
I use mySql 5 and i get this particular error
error: Unknown column 'p.ID' in 'on clause'
when i'm using the below statement
"select p.title, p.url, p.ID, p.category, p.submitted_user_id ,pc.cat_title ,u.username, u.ID, pc.ID as cat_id, from posts p, post_cats pc, users u left join post_votes pv on pv.post_id=p.ID left join post_comments pcom on pcom.post_id=p.ID where pc.ID=p.category and u.ID=p.submitted_user_id ";

Unknown Column Error
I m receiving an unknown column 'foo' in 'where clause' error on the following PHP script.
Can anyone shed any light as to why, because I am stumped.

The following code creates a select box.

function ItemsbyBrand() {
print "<label>Search by Brand</label>
";
print "<form action="">
";
print "<select id="manufacturer" name="manufacturer" onChange="top.location = 'brand.php?brand='+document.getElementById('manufacturer').value;">
<option value="0">Please choose...</option>
";
$resultid = mysql_query("SELECT manufacturer FROM stock GROUP BY manufacturer");
if($resultid) {
while($row=mysql_fetch_array($resultid)) {
printf ("<option value="%s">%s</option>
", $row["manufacturer"],$row["manufacturer"]);
}
}
print "</select>
</form>
";
}
brands.php contains this

<?php BrandResults($_GET["brand"]);
and BrandResults is

function BrandResults($brand) {
$q = sprintf("SELECT stid,name,retailprice,catlist.cat FROM stock LEFT JOIN catlist ON stid = stock WHERE manufacturer=%s ORDER BY retailprice ASC", $brand);
$resultid = mysql_query ($q);
if($resultid) {
BrandResultsName($brand);
if(mysql_num_rows($resultid) > 0) {
ProductTemplateCat ($resultid);
}
else {
print "<p>The are currently no items within these search terms</p>
";
}
}
else print mysql_error();
}
function BrandResultsName($sres) {
printf ("<h2>Items by %s</h2>",$sres);
}

Unknown Column (assigning Using AS)
SELECT
u.user_id,
u.user_name,
(
SELECT COUNT(friend_from)
FROM friends
WHERE friend_from = u.user_id
) AS friends_added,
(
SELECT COUNT(user_referered)
FROM users
WHERE user_referered = u.user_id
) AS friends_referered,
friends_added + (friends_referered * 10) AS points
FROM users u

Quote:

#1054 - Unknown column 'friends_added' in 'field list'

Unknown Why This Error Is Happening
unknown column 'g.id' in 'field list'
in this SQL?

CREATE TABLE teamScoresH2H
(
SELECT
t1.id as team_1_Id,
t2.id as team_2_Id,
COUNT(DISTINCT g.id) AS nbrOfGames,
SUM(IF(g.homescore > g.visitorscore, 1,0)) AS Wins,
SUM(IF(g.homescore < g.visitorscore, 1,0)) AS Losses,
SUM(IF(g.homescore = g.visitorscore, 1,0)) AS Ties,
SUM(IF(g.homescore > g.visitorscore, 3, IF(g.visitorscore = g.homescore, 1, 0))) AS Score
FROM
teams t1
INNER JOIN teams t2 ON t1.id <> t2.id
LEFT JOIN games g ON (g.homeid = t1.id AND g.visitorid = t2.id) OR (g.homeid = t2.id AND g.visitorid = t1.id)
WHERE
(t1.division='AA' OR t2.division='AA') AND
(t1.division='AA' OR t2.division='AA') AND
(g.homescore not in (999,777) or g.homescore is null)
GROUP BY
t1.id, t2.id
)

Unknown Column In 'on Clause'
I have seen this a couple of times and what throws me for the loop is the column IS in the table.

Unknown column 'cm.state_id' in 'on clause'

select cm.*, o.userid,c.printable_name country_name, s.printable_name
state_name, email_add as owner_email from b2gcar_mst cm, b2gcountry c,
b2gowner_mst o left join b2gstate s on (cm.state_id=s.state_id) where
cm.country_id=c.country_id and cm.owner_id=o.owner_id and cm.cid=Ɔ'

Unknown Collation Problem
#1273 - Unknown collation: 'bJxHZ6M1mX6hwAXAbRdZA-J98V3_0AdfyjflUKgmpbk.'

And every time the string 'bJxHZ..." is different.

I installed and upgraded my system but still doesn't work.

I supposed the problem was in my.cnf and realized I didn't have a collation in that file, so I added

default-character-set = latin1
character-set-server = latin1
collation-server = latin1_spanish_ci

And, it worked but after a reboot, I get the same error.

My system is openSuSE 10.2, mysql 5.0.26 and apache 2.2.3

#1109 - Unknown Table
The query below works perfectly on MySQL - 4.0.16-nt but on MySQL - 4.1.19-standard, I get the following error :

Quote:
#1109 - Unknown table 't7' in order clause

Deleting Some Unknown Caracters ?
I have a lot of fields where I want to delete 4 random numbers.

So, these fields for example :

1- "Client : 5841 TX"
2- "Client : 9822 TX"
3- "Client : 0330 TX"
4- "Client : 4987 TX"

Have to be like :

1- "Client : TX"
2- "Client : TX"
3- "Client : TX"
4- "Client : TX"

Is this possible ? I tried this but it didn't make it :

UPDATE `table` SET field = REPLACE (field,'Client : % TX','Client : TX')
WHERE field LIKE '%Client%TX%'

Do you think it's possible ?

Another Variable [unknown Column]
hav put variables in my WHERE statements before
and not had a prob...however

1)get vars from page

x_userlogin = request.Form("x_userlogin")
x_userpw = request.Form("x_userpw")

Unknown Column Error?
Unknown column 'ip' in 'on clause'

SELECTing A Single Unknown Value
I'm trying to find the best method of determining if two people are from the same area, my setup goes as follows I have a member table, a location table and a m2l (member to location) relation table which simply has an id, a member_id, and a location_id

I would like to be able to search if, given 2 member ids, they have a location id in common, since one member may have many locations. Is there a way to SELECT * FROM location, m2l WHERE location.id=m2l.location_id AND member.id='1' OR member.id='2'

is there a way I can SELECT only 1 location id which still satisfies the member.id='1' or member.id='2'? Since I don't know if they have any locations in common, i can't explicitly specify a location id...

One Value, Unknown Number Of Instances
Say I want to have a DB that keeps track of how many pints (of prune juice) I drink (okay, bad example) Each pint will have a size and the amount of time it took to drink, but I don't know how many pints I will have in each instance.

Would I have a table for Pint that had pint_size and drink_time, and then a table DrinkingSession that had num_of_pints? But then how would I log the time for each pint?

Could I write a DrinkingSession table that had pint1, pint2 pint3, etc?

Phpmyadmin: Size Unknown
When I import mysql data from a dump file into mysql, then phpmyadmin under structure shows sizes as unknown. I googled for this, but could not find a good answer.

How do I get the information to show in phpmyadmin?

Unknown VALUES Number
I have to insert some rows in a two columns table in the form (a,b) where a is fixed and b has n different values; my query should appears like:

INSERT INTO `table` (`id_a`,`id_b`) VALUES ('1','1'),('1','2'),('1','3'),...,('1','n')

the list of values for b come from a PHP script and are listed in a comma-separated string:

1,2,3,4,...,n

how can I modify my query to insert the rows using that string?
I thought about something like:

INSERT INTO table (`id_a`, `id_b` ) VALUES ('1', IN(appendTheStringHere)) .

MySQL Password Unknown
Unsure what to do next.

1. Apache running in task bar.
2. PHP info function brought expected results.
3. Clicking on MySQL Command Line Client brings up a DOS box that says:

Enter password:

When typing either the only password I would have used upon installing OR using nothing and pressing ENTER, the box disappears with a loud computer default beep, then nothing.

Unknown Column 'some_value' In 'where Clause'
As I navigate through my (still built..) web site, i've created a link that directs to : /show_title?action=show&id=".title_id."
that leads to a page where I run the query:
$id = $_GET['id'];
"SELECT title_name from titles WHERE title_id = $id"
and i get:
--> Unknown column 'CDA15FD' in 'where clause'
although when I move the cursor on the link I get:
/show_title?action=show&id=CDA15FD
and CDA15FD DOES exist in my db!

Strange 'unknown Column' Error
PHP

$sql = "SELECT COUNT(*) FROM klanten WHERE username = '$_POST[newid]'";
    $result = mysql_query($sql);
    if (!$result) {
        error('A database error occurred in processing your '.
              'submission.If this error persists, please '.
              'contact xxx.' . mysql_error());

and I swear there is a column called username. Still, I get an error saying that column username is not there.

Anyone has an idea what might be wrong ?

I just added the column. Does the server need time to refresh or sth ?

Unknown Option -- Log-bin

Trying to use the mysql command-line client with a MySQL 5.0.21 database on Windows 2003 Server, and am getting the error message: mysql: unknown option '--log-bin' What does this mean and how can I get my command-line client back?

Trying to use the mysql command-line client with a MySQL 5.0.21 database on Windows 2003 Server, and am getting the error message:

mysql: unknown option '--log-bin'

What does this mean and how can I get my command-line client back?