Update Statement Not Working
Why does this simple update statement not work with a mysql version 3.23.49,
it does work when using 4.0.24..... ?
UPDATE listitem,vjbase,list SET listitem.showsec = 7 WHERE listitem.id_vjbase = vjbase.vjbase_id AND listitem.id_vjbase = 3 AND vjbase.id_viduser = 61000 AND listitem.id_list = list.list_id AND listitem.id_list = 1 AND list.id_viduser = 61000
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UPDATE Not Working.
The page that sends information to the following page has a series of text inputs. The name of the input corresponds to the name of the column in the in the mysql table. There's also a hidden input, "id", that supplies the unique id number of the entry. My script to enter data into the table and to view the table work fine. The update script runs without any errors, but doesn't alter any values. I also tried printing the value of $query and everything appears to be fine. Anyone know why this is happening? Code:
Update Field Isn't Working?
I've created a MySQL database that has one table, that table has two fields, the table is called system, the fields are called status and message. The database is used to populate a html table on a page, that works fine. What I need to do though is have a form on a separate page (which i'm going to add http authentication to) with a simply form consisting of a text box, three radio buttons, and the usualy submit and reset buttons. I need to be able to update the database using this simple form. However this isn't for adding new records, it is purely for editing the existing record as it's to edit simple warning messages to display to the visitors when there is a problem with one of the systems. The radio buttons determine which light image is displayed (green, orange, red) and the text box for the short message. However no matter what i try it just in't updating the fields in the database, the following is the html and PHP i'm using: Code:
SQL Update Command Not Working
I need to update the price in one table from a field in another. 2 Tables named: newpricelist pricelist I have 3 common fields in both, item, description and price. I need to match the item field and take the price from "newpricelist" table and update the price field in the "pricelist" table. Here is my syntax (it says it will only update 1 record): UPDATE PRICELIST INNER JOIN NEWPRICELIST ON NEWPRICELIST.ITEM = PRICELIST.ITEM SET PRICELIST.PRICE = NEWPRICELIST.PRICE;
Simple Update Just Not Working /banghead
Background: I've been around the web for quite some time, but am new to PHP/MySQL. I recently purchased a zip code database for an upcoming project I'm starting here, and for some reason the CSV format turned all the zipcodes that start with a zero into 4 digits. No biggie, after hours of wrestling with cpanel MySQL import, then giving up and moving on to modifying the bigdump script I FINALLY got the import done. Now I'm trying to correct the 4 digit zip codes back into 5 digit ones. Table name is ZipCodes, column name is ZipCode (is varchar(5) column). Here's the code I'm trying to use to update things, but it just does not perform the update for some reason. update ZipCodes set ZipCode = Ɔ' + ZipCode where char_length(ZipCode) = 4; I've spent a few hours now reading up trying to figure out what the hell I'm doing wrong, but to no avail. I'm sure the fact that I'm a newb at MySQL isn't helping, but is it something obvious that I'm just to dumb to see at this point?
Update Not Working Within A Stored Procedure
The following query works, but not within a stored procedure, any tips? update ATable,BTable set ATable.lbl= BTable.lbl, ATable.Status = "0", ATable.Code = BTable.code where (ATable.ID = BTable.Tapelbl)
What Would This Update Statement Be?
I have an array of ids formatted like 1,2,3,4,5 I have a table where there is a field that selects maybe a few of those ids, and is formatted like this: 1,3,5
Update Statement
I am using excel to update an online mysql table. I am having an issue with my update statement and I don't understand why. When I run the statement, I am getting a run time error. In the description of the error, the statement is reading as I would expect it to - but it is not working. usqlstring = "(UPDATE company set company = '" & ucompany & "' WHERE prospect_id='" & updateid & "')"
Update With If Statement
I'm trying a statement which I cannot figure out what I'm doing wrong on. I've tried every combination that I can think of and stared myself blue with no success. update cdr set Cost=if(mod(BillSec,6)=0,int(BillSec/6),int(BillSec/6)+1) The idea is to update Cost with a value depending on the result of a formula. It's an empty field which gets a computed value from other fields. cdr is the table.
Update Statement
here is a update statement I have... UPDATE support_test SET cat_id=42 WHERE cat_id = 4 It works fine, only thing is I need to update more numbers but I don't want to overwrite the updated numbers. Example, I want to update 42 to 6 but want to update the original 6's to 12. I have about 30+ numbers that need to be changed, any way to go about this?
SQL-Update-Statement
I have to update all UA-fields in the table idrz_kennzahl with primary key idrz, where the same idrz in the table per_verwaltung with the field Amt=12 is. I designed following statement but it doesn't work: update idrz_kennzahl set UA=1234 where idrz_kennzahl.idrz = (SELECT per_verwaltung.idrz from per_verwaltung where per_verwaltung.Amt=12
Update Statement
I am currently updating a table and increasing a column value by 1, the problem is that he don't increase 1 but it does increase the double of the value specified. Why does it performs the update like this? And how can i solve this problem? SQL Statement Syntax used: UPDATE table_name SET column_name=column_name+1 WHERE id=1 Version of MySQL: 4.1.7 for Windows installed in Windows 2003 Server.
Update Statement
i have the following problem. in a table i have 3 columns. first a nvarchar field (6 characters) which is filled with point of sales (pos) numbers. the second one is an ip-adress like 10.192.17.30. the third column i want to create based on the second column, means i have to substract e.g. 3 of the ip-number. e.g. the ip-numer is 10.192.17.30 so in the third column should stand 10.192.17.27.
Update Statement
I have two tables, and I want to take data from one table, and overwrite it onto the second. Unfortunately, my SQL is pretty weak. The first table has a mediumtext column and a id (primary key) column. The second has an id (the same as the first), a number, and a mediumtext column. I want to take the contents of the mediumtext field with the highest number and replace the contents of the field in the first column with it with the same id. My instinct is to do it this way: update forum1post p set p.pagetext = (select query1.message from (select pe.message, max(pe.editnum) from forum1post_edits pe group by p.postid) query1) where p.pagetext = 'Why did you all flame my topic. Screw your ****ing forums.' and p.postid = pe.postid However, that does not work, as pe is not recognized.
SQL-Update-Statement
I have a litte problem with my sql-database! I have to update all UA-fields in the table idrz_kennzahl with primary key idrz, where the same idrz in the table per_verwaltung with the field Amt=12 is. I designed following statement but it doesn't work: update idrz_kennzahl set UA=1234 where idrz_kennzahl.idrz = (SELECT per_verwaltung.idrz from per_verwaltung where per_verwaltung.Amt=12).
Update Statement
UPDATE `zipLocations` SET `z_zipCode` = '06001' WHERE `z_zipCode` =6001 LIMIT 1 ; Field Type Attributes Null Default Extra Action z_zipCode int(5) No 0 z_cityName varchar(50) No s_stateAbbr char(2) No z_countyName varchar(50) No z_areaCodes varchar(50) No I even went through phpmyadmin found the row clicked on the edit button for that row and updated it. and it still doesn't update.. im' thinking it has to do with the data type being INT... Why doesn't it update it ?.. It says it was successful. Affected rows: 0 (Query took 0.0002 sec)
Update Statement
UPDATE products_to_categories SET products_to_categories.categories_id = 666 FROM products, products_to_categories WHERE products_to_categories.products_id = products.products_id AND products.products_model = 'PAC-P6512'
Update Statement
Can someone please let me know what is wrong with the following statement? UPDATE user_attribute, user SET user_attribute.value = user.login WHERE user_attribute.userid = user.id; I keep getting a syntax error but don't see the mistake made.
Update Statement
this works on my machine but not where my site is hosted. They do use an older version of mysql could that be problem update inv, newprice set inv.cost = newprice.price where inv.itemcode = newprice.itemcode works fine on my machine her ebut on server i get error..
Conditional Update Statement
I have a table with a field of ID numbers. I want to update this field and replace the ID numbers. For example I want every record that currently has the ID number 2,5,6,or 9 to be replaced with a 1. Every record with 1 or 4 to be replaced with 2 ... I can't seem to form the update statement to do this. I can do them one at a time but this won't work because if I change 2,5,6, and 9 to 1 then when I run then update for 1 and 4 it will change them all. Does this make any sense? I want some way to be able to use a condition...if id=2 or 4 or 6 set it to 1 and if id= 1 or 4 set it to 2. My failed attempt: mysql> update client_software set software_id=1 WHERE (software_id=2 or software_id=5 or software_id=6 or software_id=9) AND software_id=2 WHERE (software_id=3 or software_id=7 or software_id=8) AND software_id=3 WHERE (software_id=1 or software_id=4);
DELETE,UPDATE Or Other Statement In WHERE
I would like to let my admins write WHERE statements. . In panel where you can see all users of my site, admin should have input where he can put some filters in WHERE statment. E.G. standard query is SELECT login FROM USERS . and admin would write age > 18 and male = 'f' . php script would conact it and it would execute SELECT login FROM users WHERE age > 18 and male = 'f' I have question about security of this solution. Is possible to put in WHERE statement sobe dangeurous statemetns like DELETE of UPDATE?
Update Statement Problem? Plz Help.
I've a simple doubt of whether can or can't i update two tables by using joins as below. the below update statement matched 2 rows one each for two tables but didn't update. mysql> update audio join pcr_info on audio.audio_sid=pcr_info.pcr_sid set audio. audio_pid=4896,audio.audio_prgm_num=3,audio.audio_type="MPEGLayer1",audio.audio_ sr=44.1,audio.audio_mode="1_0",audio.audio_bitrate=320,pcr_info.pcr_pid=49 where pcr_info.pcr_prgm_num=3 and pcr_info.pcr_sid="2501" and audio.audio_pid=4896 an d pcr_info.pcr_pid=49; Query OK, 0 rows affected (0.00 sec) Rows matched: 2 Changed: 0 Warnings: 0
Very Slow Update Statement
I am having an issue with an UPDATE statement that takes a very long time. I am using 1 table in a schema to update another table in another schema. Below are the create statements and the update statment I am using. Table and column names have been changed to protect the innocent :) Code:
Special UPDATE Statement
UPDATE some_table st SET some_page_no=((select count(*) FROM some_table WHERE some_table_id<st.some_table_id and some_id=st.some_id and some_type='OK') div 10)+1 WHERE some_id=345 and some_type='OK' I want to use the above to make a fast page index (10 on each page). I had something similar in mssql and it worked, but in myssql I get this error: "You can't specify target table 'some_table' for update in FROM clause" What have I done wrong or can the above simply not be done?
Select + Update In One Statement
I have these statements. $selectdata = "SELECT * FROM imagetrack WHERE fimsid = ".$_GET["fimsid"]." AND name = '".$_GET["service"] . "'"; $query = mysql_query($selectdata) or die(mysql_error()); $update = "UPDATE imagetrack SET seen = seen+1 WHERE fimsid = ".$_GET["fimsid"]." AND name = '".$_GET["service"] . "'"; Basically i was wondering if there was a statement where i can select everything and update the seen in one statement.
Conditions In UPDATE Statement
i have some data to be updated in a specific row - WHERE id=1 data: $min_time, $max_time, $time, $attempts so, i would like to calculate new avg and replace min_time with new value, if new min_time is smaller then that one stored in the database. "UPDATE mytable SET avg=(avg*attempts+$time) DEV (attempts+1), min_time=**here i could use help** ??IF(min_time>$min_time)$min_time ELSE min_time?? **and similar with max_time .
SQL Statement For A Selective Update
I have a table with a field called 'imagepath', in this table is data represented by the two following path types: 1. J:DIRDIRDIR and 2. 172.21.2.7DIRDIRDIR What I need to do is udpdate the data to represent the following: 172.21.10.1DIRetc. In other words don't update the dir paths just update the mapped dirve and old unc to the new unc.
UPDATE Statement Doesn't Work
TABLE - abc ID NAME ___________ 1 hello 12 abc UPDATE `abc` SET `ID`='5' AND `NAME`='hello' WHERE `ID`='1' AND `NAME`='hello' wherenver I try to update this table using above sql statement, it doesn't work. I just get "Row match:1 Changed:0" message.
If Condition In Update Statement
I have a table with three fields - stockLevel, backOorder and allocated (there are other fields but these are the inportant ones here). Is it possible to create a SQL update query that will deduct a qty from the stockLevel if there is sufficient stock and if not deduct as much as possible and put the this amount on allocated and the remainder on backOrder?
Long Old UPDATE Statement
I have the following SQL which gives me the row Im after SELECT * FROM staff, staffemails WHERE staff.users_username='$user' and staff.staff_id = staffemails.staff_id thing is I now want to perform an update on the result of this query. Ive tried UPDATE staffemails SET is_registered ='0' WHERE staff.users_username = '$user' and staffemails.staff_id = staff.staff_id .
UPDATE / JOIN STATEMENT
i have problems after updating mysql from 4.x to 5.0.19. This statement should update about 3000 rows but it only does 15 but there are definitely another 2000 rows with an older date and matching nr! UPDATE tab1,tab2 SET tab2.newdate = NOW() WHERE tab1.nr=tab2.nr; I tried the variation with inner joining tab1 as well. same result. Does anyone has an idea solving this problem? Perhaps it´s a bug?
MySQL/PHP - SQL UPDATE Statement
I am trying to update one field in my table in MySQL. I cannot get this field to update. Can someone possibly tell me what is wrong with my SQL statement? $SQL="UPDATE umcritsurv SET IQ_Use_Q9='$IQ_Use_Q9' WHERE fldAuto='54'";
Help With Simple SQL Statement To Update Zipcodes
I have a varchar(5) field in a database called 'zip_code'. I imported some zipcodes from an Excel spreadsheet, but the spreadsheet had truncated any zipcode that started with a "0" and removed the zero, so the correct zipcode of "08993" was incorrectly placed into the record as "8993". Would someone help me write a SQL statement to run on the field zip_code that would look at the data, if it was four characters long, add a "0" to the start and keep the remaining four characters in place?
QUERY One Table And Update Another In ONE Statement?
ZIP_CODE: zip_code latitude longitude customers: customer_id ... zip_code latitude longitude The lat and long in the customers table is blank. I want to lookup customers' zip code in the ZIP_CODE, get the related lat & long and update the customers table with that information. The result being that after this query is run, the customers table now has lat & long data.
UPDATE Statement To A Single Position
I am running into problems trying to write SQL to update a single position within a field for throusands of records. Thousands of records on a table have an incorrect number in a field (UIDY) and I am looking for the most simple way to update them all. If it were only a single record, I would execute the following: Update MF_VEND_ADDR_DOC set UIDY = '&4027&7608&7607&1609&VC19&VC19000055&&0&999&M' where UIDY = '&4025&7608&7607&1609&VC19&VC19000055&&0&999&M' The only difference in those two lines is that I want to change the &4025& to &4027&. Does anyone know of a way to update thousands of similar records by updating the 5th position in the UIDY field, thus eliminating the need to list out each UIDY value?
CASE Statement In Update Command
I'm trying to update one table (tbl_usage) based on information from another table (tbl_subscriptions) joined by the userID. The usage table tracks the number of times a user hits a page, and decrements the count each time. When the user has a zero count, they are redirected to a warning page. Each week the count is reset depending on what type of license they have (licenseType) and how many of those licenses they've bought (numLicenses). A group license (G) gives them 100 hits, and an individual license (I) gives them 5 hits. I'm trying to use a case statement to perform this count reset operation, but I can't seem to get it to work. The following case statement works just fine: Code:
Convert A Nested Update Statement
i have a nested update statement in my sql server as follows UPDATE DIM_EVENT . SET INVOICE_AMOUNT = (SELECT SUM(INV.INVOICE_AMOUNT_TOTAL) FROM INVOICE INV WHERE INV.INVOICE_REFERENCE_NUMBER = DIM_EVENT.OBJECT_ID AND INV.INVOICE_AMOUNT_TOTAL IS NOT NULL) WHERE DIM_EVENT.EVENT_TYPE_CODE IN ('OFULN', 'OAUTH', 'CRDRL'); what is the equivalent in MySQL.
Nested Select In Update Statement
my nested Select-Update-Statement doesn't work. I think it's because the SELECT-Statement returns an empty set.. is there a posibillity to run this statement if there is no empty set and insert NULL if it is? Or is there another error at all? CODEUPDATE proj_user_suche SET acronym = (SELECT name FROM acronym LEFT OUTER JOIN link_acronym ON acronym.id_acronym = link_acronym.id_acronym WHERE projekte_nr="23") WHERE id_proj_user_suche="17"
Convert SELECT Statement To UPDATE
How do I convert the following SELECT statement to UPDATE statement? If I'm not mistaken, UPDATE statement could not involve more than one table. SELECT * FROM F0116 LEFT JOIN F0101 ON F0116.ALAN8=F0101.ABAN8 WHERE F0116.ALCTR='' AND F0101.ABMCU='1'
MySql Update Or Insert Statement To Modify A Word In All Caps
I have a field in my database called Subtopic. In this field I have a word LITERATURE in all caps. I need to change the word LITERATURE to LITERATURE followed by a colon then an empty space. Can someone give me the MySql statement I can paste into phpMyAdmin to make this change? Note: The Subtopic field contains the word "literature" but not in all caps because the Subtopic field is part the database that is an encyclopedia. Therefore, I want to change ONLY the word LITERATURE if the word LITERATURE is in all caps.
!= Not Working?
SELECT d.cache_diff, d.cache_name, d.cache_type, d.cache_last_found FROM geocaches d LEFT JOIN logvisit ON d.cache_id=logvisit.cache_id WHERE d.cache_status = 0 && logvisit.log_type != 'Found' && logvisit.log_owner_id = 64 This returns zero rows. Its true that records in logvisit.log_type for this user are only FOUND but I am trying to display cache information for all other caches (in geocaches table) that the user did not log FOUND in logvisit. So, basically if the user logged against 3 caches and there are 10 caches available to log agains then I want to display only the remaining 7. Is JOIN the way to go on this one?
LIKE '[0-9]%' Not Working
Here is the SQL query: Code: SELECT * FROM member WHERE username LIKE '[0-9]%' Returns 0 rows. I've tried this on 4.1.7-nt as well as 4.0.22-standard; neither work. And yes, there are records in the table that should match that pattern.
Not Working
I have 4.1.10a on my local machine and the following WHERE clause works fine: Code: WHERE wk1 IN (select max(wk1) from wkpts where teamid = w.teamid) But when I upload it to my web site, I get an sytax error at 'select max(wk1) from...' My web host has MySQL version 4.0.20-standard. Can someone tell me why it would work locally, but not on my web host's server? Thank you.
LIKE '%$var%' Not Working
I am trying to create an sql statement to return values on either side of the variable. Code: $sql = "SELECT * FROM principals LIKE companyName = '%{$_POST['companyName']}%'"; The error was: Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIKE companyName = '%Mike%'' at line 1
Select As Where Not Working!
SELECT CONCAT(RIGHT(dt,4),'-',MID(dt,4,2),'-',LEFT(dt,2)) AS dateavail FROM atable WHERE dateavail = ��-06-01' (dt is a date in format dd/mm/yyyy - the concat bit works fine) Microsoft OLE DB Provider for ODBC Drivers error ?e14' [MySQL][ODBC 3.51 Driver][mysqld-4.1.19-standard-log]Unknown column 'dateavail' in 'where clause' Also, if I get it to work, how do I convert the 2 strings to date so I can look for < and > ?
Doing A JOIN Not Working
I have 2 tables, one contains columns that holds the ID to the other table so eg Table 1 (images) id | imagepath -------------- 1 dir/hair.png 2 dir/face.png Table 2 (buildImages) userid | hair | face 1 1 2 So i'd just like to retrieve a row like dir/hair.png, dir/face.png where userid = 1 does that make sense? Oh, the title of this thread is kind of wrong, shoudl be how do I do this join :P
DATE_SUB() Is Not Working Right For Me.
My `date` column is in date/time format 2007-12-14 19:55:00 When I try to select only the records added in the last 5 hours, I get records from more than 24 hours ago. I know I am EST zone and the server is PST zone, but something else is wrong. This is my WHERE clause: WHERE `date` > DATE_SUB(CURRENT_DATE, INTERVAL 5 HOUR)
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