"Warnings" Count When Using Mysqlimport
When using mysqlimport, the final statistics include a count of
"Warnings", for example:
Connecting to foo.whatever.com
Selecting database foo
Loading data from LOCAL file: foo_userInfo.imp into foo_userInfo
foo.foo_userInfo: Records: 248 Deleted: 0 Skipped: 6 Warnings: 248
Disconnecting from foo.whatever.com
I'd like to know what the warnings were, however there doesn't appear
to be a command line option that might be used to expand the statistics
or otherwise output the text of the warnings (--verbose does not do
it).
Is there any way to view the warnings?
View Complete Forum Thread with Replies
See Related Forum Messages: Follow the Links Below to View Complete Thread
- Relations In "CASCADE", "SET NULL", "NO ACTION", "RESTRICT", "--" ?
- Apon Upload "Warnings 1"
- Single Query For No Of Hits "Today", "This Month", "This Year"
- Count Query Causing "excessive Processor Usage"
- Count User Comments In Each Category (was "help On A Query")
- Count Of *unique* Visits By Page For Each Day (was "Need Help With Query")
- How To Fix "Column Count Doesn't Match Value Count At Row 1" ?
- Add COUNT(*) To Already Existing Query (was "How To Do This")
- Count(*) Returns "Resource Id#3"
- About "Select Count(*)" Always Returns 0.
- Searching For Numbers - "close To" Or "approximate"
- REQ: MySQL 4.0 Equivilent Of "DateDiff("m", Date, Now())=1"
- Get Average Of A "count"
- Count(*) In A Select Returns "1". It Should Behave Like Select Count(*)
- Value "000" Stored As "0" In Text Field?
- What Is The Meaning Of The Letters "AB" In "MySQL AB"?
- Return A "true" Or "false"
- "Group By" Forgets "Order By"
- Analyze Warnings From Mysqlimport
- Finding Warnings/skips From Mysqlimport
- REGEXP To Find "foo-bar" And "foo Bar"
- "Select * FROM" Vs "Select Field1,field2 FROM"
- Select "german, French" Only With "german"
- "Calculated Fields" In "
- Maximum Execution Time Of 300 Seconds Exceeded (was "MYSQL Error")
- Error "Can't Find FULLTEXT Index Matching The Column List"
- Design For Stock Items And Checkin/checkout Process (was "Query Help")
- Query To Populate A Calendar (was "Wanted The Experts Opinions (that Means YOU!)")
- Searching A Comma Separated List Of Numbers (was "Brain Toot")
- Store Web Site Club Registration Data (was "MySQL Question")
- Batch Mode Feedback Of "mysql" Command Line Tool
- Full Text Search - Un-stopping Default Stop Word "first"
- Encountering 2013 Error ("Lost Connection To MySQL Server...")
- Generating DAILY Min&Max Over A Period Of Time, Based On A "DateTime" Field
- "supplied Argument Is Not A Valid MySQL Result Resource" Error
- Unable To Connect To Server (was "Novice User Problem")
- Linking Stores With Products (was "MySQL Dificult Code")
- What Is Execution Time Of A Query Based On? (was "a Mysql Question")
- List All Clients Not Assigned To Current User (was "Query Help Please")
- Unique Combinations Of Model And Make (was "Query Question")
- Return 1 Row With Concatenated String (was "Really Easy But My Minds Gone Blank")
- Adjacent Theater Seats (was "mySQL Query Issue")
- Access Denied For User 'root'@'localhost' (was "help!!! Just A Beginner..")
- How Can I "see" A Table In A Database On A Remote MySQL Server After Creating It
- How To Modify The "select" Function In The Source-code-version?
- Beta Testers Wanted For New "blueshell Data Guy Professional"
- Multi-table UPDATE Problem (was "mysql Question")
- Invalid Use Of Group Function (was "Baffled By Query Error")
- Compare 2 Tables And Find Rows Which Don't Match (was "Mysql Noob Question")
Apon Upload "Warnings 1"
I uploaded a file to my mysql-db via commandpromt (which I have done 100 times before) everything went fine exept "warnings 1" how do I see what that warning is about ??
Count Query Causing "excessive Processor Usage"
For the second time in the past 6 months my hosts have shut down my site because it was apparently causing a shared mySQL 5 server to max out at 100% usage. I'm not much a programmer, know even less about mySQL and obviously don't have access to the server from the back end but I'd appreciate any advice as to whether it is my query that is causing the problem: Set rsMail = objConnC.Execute("SELECT * ,(SELECT COUNT(*) FROM comments WHERE comments.submissionID = submissions.submissionID AND comments.commentInclude = 1) as CommentCount FROM submissions WHERE PigeonHole = 'mailbag' AND Status <> 'hold' ORDER BY submissionID DESC LIMIT 20") Apart from two instances, this query has been working fine on a page that receives between 10,000 and 30,000 visits a day. The site is running on Windows and coded in ASP but is calling a separate mySQL server.
Count User Comments In Each Category (was "help On A Query")
I would really appreciate if someone could help me out on this one. this are my tables: comments Comment_ID Video_ID Comment_Text Comment_UserID .... video Video_ID Category_ID ..... category Category_ID Category_Name I'm trying to get a user's count of comments for each category, ordered by the number of comments DESC. basically, I want to show the top categories where the user has posted the highest number of comments. so far this query gets me the category name of where the user has posted: PHP $SQLTemp = "SELECT Category_Name FROM category WHERE Category_ID IN ( SELECT DISTINCT ( Category_ID ) FROM video WHERE Video_ID IN ( SELECT DISTINCT ( Video_ID ) FROM comments WHERE Comment_UserID = $id ) )"; THANKS!!
Count Of *unique* Visits By Page For Each Day (was "Need Help With Query")
Using MySQL 4.1 I have a table 'orders' with the following fields: ipaddress pagenum xtime (which is just the yearmonthday) this is the query: SELECT distinct pagenum,ipaddress,xtime,count(pagenum) AS pagenumtotal FROM `orders` group by pagenum,xtime ORDER by xtime, pagenum asc What I am trying to do is return a count of *unique* visits by page for each day. This query returns a count of *all* visits by page for each day, including repeats. So if a visitors hits a certain page on the site 10 times and adds a record 10 times, the count result will include all 10 records in the count. I want this to only count as 1.
How To Fix "Column Count Doesn't Match Value Count At Row 1" ?
I've been trying to install a portal to my installation of Invision Power Board, and I keep coming up with this problem. I post here for two reasons: firstly is that no one is responding over at the portal creator's thread and I need help, second is that this error looks like a mySQL error that could be solved without the need of the creator if possible. Here is the error returned: mySQL query error: INSERT INTO `ibf_portal_box` VALUES (1, 'lang.last_topics', '<box><menu>10,20,30,50</menu> <topics_show>10</topics_show> <order>last_post</order> <exforums></exforums> </box>', 0, 'middle', '*', 0, 4, 'last_topics', '1') mySQL error: Column count doesn't match value count at row 1 mySQL error code: Date: Tuesday 21st of December 2004 08:43:10 PM I am very new to mySQL and don't really understand it. What is wrong with the above that it is trying to insert, and how is it fixed?
Add COUNT(*) To Already Existing Query (was "How To Do This")
I have this query: PHP SELECT entries.*, categories.*, uploads.*, entries.blog_id FROM entriesINNER JOIN categories ON (categories.category_id = entries.category_id) LEFT JOIN uploads ON(uploads.blog_id = entries.blog_id) LEFT JOIN images ON (images.blog_id = entries.blog_id) ORDER BY entries.date_submitted DESC LIMIT 3 Now i want to add this PHP SELECT COUNT(*) FROM comments but i dont know how to add it into the already existing query. The messages table has a column blog_id column in it so i could do a join like thisd LEFT JOIN comments ON PHP (comments.blog_id = entries.blog_id) but i dont know how to get the first bit in there
Count(*) Returns "Resource Id#3"
I have table: CREATE TABLE users( id INT NOT NULL PRIMARY KEY AUTO_INCREMENT, nick varchar(32), passw varchar(32), email varchar(128), email_poskytovatel varchar(64)); and I want to read variabile id . I am using command SELECT Count(id) FROM users. But it returns "Resource id#3". Where is my problem?
About "Select Count(*)" Always Returns 0.
my mysql version is: Ver 14.7 Distrib 4.1.14, for pc-linux-gnu (i686) using EditLine wrapper OS: uname -a Linux backup_srv1 2.4.29 #4 SMP Thu Mar 24 10:31:26 CST 2005 i686 unknown unknown GNU/Linux Desc: My statement is "SELECT COUNT(1) FROM t_card_info_035 WHERE Fcommodity_id = 0x1111 AND Fseller_uin =111111 AND Fdeal_id = 12345;" my client is a daemon, when it started, it can return the correct result, (such as 4 ) but after two or three days later, it always returns 0. I had gdb into it and find that the result in the result row is 0. but when I restart my daemon program, it will be ok again. This made me crazy... it is a mysql c API bug or something else? My daemon client is programmed by c++ , and use the c API to connect mysql. I had check that there is nothing wrong with my code, and it has no memory leak or somthing else.
Searching For Numbers - "close To" Or "approximate"
I would like to know how to search a table for records where a particular field is "close to" a particular number. For instance, let's say I have a table containing students and their most recent test scores. I'd like to see students who scored 7/10. That's easy enough (select * from table where score = 7). I'd also like to run another query to identify other students whose scores are not 7 but "close to" 7. Ie students who scored 6 or 8. As an added bonus, I'd like to be able to do a related search that shows students who scored 7, then shows the other students ordered by how "close" they are to 7. Ie students who scored 6 or 8 are "closest" matches, and students who scored 1 are "furthest". I hope this makes sense! Is there any pre-existing MySQL command that will do this? Or will I have to run separate queries for each value?
REQ: MySQL 4.0 Equivilent Of "DateDiff("m", Date, Now())=1"
I have a query that works in the rest of the SQL world "SELECT invoice.*, invoice.Date FROM invoice WHERE (DateDiff("m", Date, Now())=1);" which will give me all of last month's invoices. However it doesn't work with MySQL 4.0. While "SELECT Invoice.* FROM invoice WHERE (Month(Invoice.Date) = ((Month(Now()))-1))" Is a close substituent, it will blowup in January. Anyone have an equivalent expression for MySQL 4.0?
Get Average Of A "count"
How to get average of a count(user); Following syntax run very well $records = mysql_query( "SELECT user,action,count(user) FROM log where date='$datetr2' and action='add' group by action,user") But now I also want avg(count(user)), but it didn't work $records = mysql_query( "SELECT user,action,count(user) ,avg(count(user)) FROM log where date='$datetr2' and action='add' group by action,user") count(user) only get hot many times a user log into the webside a day. Right now I want to know the average times of user logging into the web within month. I don't know to get average number. avg() function doesn't work here.
Count(*) In A Select Returns "1". It Should Behave Like Select Count(*)
i'm trying to make a query work properly but I got lost: SELECT *,count(*) FROM cancons c, musics m, discos d, r_discos_cancons rdc WHERE c.c_id_music = m.m_id AND rdc.rdc_id_disc = d.d_id AND d.d_id_music = m.m_id AND m.m_id = 24 GROUP BY c_id note: cancons (ca) = songs (en) discos (ca) = cd's (en) music (ca) = musician (en) don't worry for the WHERE part. i need it because of the foreign keys. this query returns a table with the title of the song and some more data. on the right side, I get another column called "count(c_id)" with the number "1" in it for each row. That's supposed to be due to the "group by" clause, I think. I'd like to get the table with the songs, as usual, and, with the same query, I'd like to get the total number of rows selected.
Value "000" Stored As "0" In Text Field?
I've managed to import my data from a CSV using SQLyog Enterprise, however, I have a problem with the table storing the text value "000", MySQL truncates it to "0", unfortunately, I need the value to be stored as "000", does anyone know of any way that I can force the field to store all the characters, rather than treating it as a number? Surely a text field should treat any numbers stored within it as text?
Return A "true" Or "false"
i wanna do a "select", where if the script finds any matches, i dont wanna know about them. Instead, i just want it to return a a value: true (1) ou false (0). ie.: $sth = $dbh->prepare("SELECT * FROM maps WHERE name='algo' LIMIT 1"); $sth->execute(); if (match is true) { print "True Match. A match was found"; } else { print "False Match. No matches were found."; }
"Group By" Forgets "Order By"
I'm trying to build a simple RSS reader for a client and am running into some serious problems with the GROUP BY in MySQL. Basically I have two tables: one that holds all the entries and one that holds all the feeds. Then what I can do is say: [MYSQL]SELECT * FROM entries WHERE feed_id='13' ORDER BY date DESC[/MYSQL] That will select all the entries that belong to feed #13. This is fine, but what I'm doing now is building a library that will display the feed_id with the latest entry with that id. So I would think it would be something like the following: [MYSQL]SELECT * FROM entries GROUP BY feed_id ORDER BY date DESC[/MYSQL] That should get me the single latest entry from each feed_id. However it's forgetting the ORDER BY clause all together and seemingly ordering it by the auto-incrememnt value in the entries field.
Analyze Warnings From Mysqlimport
Is there a possibility to analyze the warnings that I receive when I'm importing data to a mysql database by mysqlimport.I can find the complete data in the database but the message I receive from the mysqlimport allways tells me ...Records: 157 Deleted: 0 Skipped: 0 Warnings: 157 I think that there is just one column that produces these warnings but I don't know which column is responsible for this.
Finding Warnings/skips From Mysqlimport
I'm importing ~2000 rows using mysqlimport with the following syntax: mysqlimport -d -v --ignore -u root -p[rootpw] [database] [tablename].txt Connecting to localhost Selecting database [database] Deleting the old data from table [tablename] Loading data from SERVER file: /[path]/[tablename] into [tablename] [database].[tablename]: Records: 1780 Deleted: 0 Skipped: 39 Warnings: 1178 Disconnecting from localhost But even with verbose on it doesn't tell me what the warnings are, or what rows were skipped. Where can I find that information?
REGEXP To Find "foo-bar" And "foo Bar"
Does somebody know how to solve this: select * form geo,places where geo.name = places.name Where geo.name could be New York and geo.places could be New-York
"Select * FROM" Vs "Select Field1,field2 FROM"
No matter how many fields I want to retrieve from the table I always use "Select * FROM Table" instead of "Select field1,field2 FROM Table". Are there any disadvantages of always using "Select * FROM Table"?
"Calculated Fields" In "
o I want to create a table "totals" with three following fields: Field 1 => quantity Field 2 => unit_price Field 3 => quantity*unit_price o I thought I could do something like: =CODE============================= CREATE TABLE totals ( quantity INT, unit_price DOUBLE, total DOUBLE AS quantity*unit_price ); ================================== o It fails with the following error: =REPORT=========================== ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS quantity*unit_price)' ================================== Question1: Is it possible to declare "calculated fields" at "table creation" ? Question2: If yes, how to do so?
Maximum Execution Time Of 300 Seconds Exceeded (was "MYSQL Error")
I have a huge database 400mb+ in size which i have exported into a .sql file. I tried to run this export script into a new database and it runs fine until three quarters into the scripts execution and the following error appears: ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '<br / > <b>Fatal error</b>: Maximum execution time of 300 seconds exceeded in <b' at li ne 1 I believe this error may relate to "delayed_insert_timeout = 300". How do I increase this limit in mysql - maybe it may solve the problem but then again it may not . Any advice is most gratefully appreciated - As you can imagine if the script runs fine for 3/4 of it and then an error appears, stating the error is on line 1, it will take me days to go through the whole script (hundreds of thousands of rows) to find the error as I assume the error does not reside on line 1 as this line would have been executed. I am running the script on mysql 5, and via source /path/****.sql on linux.
Error "Can't Find FULLTEXT Index Matching The Column List"
I'm trying to use fulltext search with mysql match() against() but i keep getting this error Can't find FULLTEXT index matching the column list even though i already altered the table to make the column im searching FULLTEXT any ideas?
Design For Stock Items And Checkin/checkout Process (was "Query Help")
I'm currently in the process of trying to bodge together a simple(ish) stock system to be used on a company intranet but I've ground to a halt with a particular problem. Using a MySQL database I've got tables with 11 fields, including 'Quantity' (self explanatory) and BookOut. Now this BookOut field contains information on the user who has booked out an item including the users name, the date/time etc The problem I have is this. If an item has a quantity of 7 and a user books out 1, then his/her info is stored in BookOut but when another user books out another 1 of said item at a later stage then the previous BookOut info is overwritten. Is there a way in that everytime another item is booked out that a new line is created within a specific field? } if(!sizeof($error)){ $update_SQL = "Update joystick Set BookOut = '" . mysql_real_escape_string($BookOut) . "', PCserial = '" . mysql_real_escape_string($PCserial) . "', Quantity = Quantity - " . $Quantity . ", MachineNo = '" . mysql_real_escape_string($MachineNo) . "', Date = now() WHERE ID = " . $ID; if(! @mysql_query($update_SQL)){ $error[] = "Update SQL failed"; } The above is the query I am currently using. I'm not totally proficient with .php and have already had a lot of help getting this far.
Query To Populate A Calendar (was "Wanted The Experts Opinions (that Means YOU!)")
I am building my first calendar for a client to list All their events on a month to month basis. There are several tables of data that I need to query to populat the calendar from: Events, Committee Meetings, Lectures, and Group Actions. I was wondering: #1) Is it more effecient to query all the tables once and to store the results into an array that I can check as I loop through and output the days for the calendar? #2) OR, is it better to query all the tables for each day as I loop through and construct the calendar ouput? After formulating my question it seems like a no-brainer: That option #1 would be the most effecient, but I still would like to know your opinions. Especially if you have made a calendar before.
Searching A Comma Separated List Of Numbers (was "Brain Toot")
I'm at burnout point and simply cannot remember how to do this in a MySQL query. I have as an input from a form: Ƈ,4,6,8,55,74,11123' Basically a comma separated list of numbers The table I'm accessing has multiple records with a column called 'areas' this column for each may contain some of multiple of these input form numbers. e.g. row 1 Ɖ,1,76,77,89,400' row 2 Ƈ,2,7,8,55' row 3 Ƈ,4,6,8,55,74,11123' I need to return any row that has at least 1 matching value from the form input list. I literally staring at the screen after a marathon coding stretch and cannot get the mind in gear.
Store Web Site Club Registration Data (was "MySQL Question")
I am working on a website for a club. One thing that they want included in the site is a way for people to register online for the club and their services and for this information to be put into a database for the owners to view. Is this something that I can do with MySQL?
Batch Mode Feedback Of "mysql" Command Line Tool
while writing a bash shell script to backup some databases and I am having slight problems with the mysql command line tool's feedback. Here goes command line: #!/usr/bin/env bash mysql -ubackup -e "UPDATE `mydb`.`sysvar` SET `val`='backup' WHERE `var`='updateState' AND `val`='0';" The backspaces are nescessary for the shell, otherwise it'd interpret whatever is inclosed in --> ` <--- as command. The problem is, I need to know wether a line has changed or not. The command always returns 0 (that is a success in Unix/Linux) if it was successfully executed, no matter wether or not a line had been changed, and produces no output at all. Could anyone tell me how I get that info?
Encountering 2013 Error ("Lost Connection To MySQL Server...")
I have a nightly job that performs backups on my MySQL servers. There are three production MySQL instances on different machines. My backups have been running successfully for months (until now). However, on last night's backups for one instance, a couple of database/schemas (appear to have) backed up successfully, but the larger schemas failed, as follows: ======================================= Backup of schema dhunt was successful in 0 seconds Backup of schema mysql was successful in 0 seconds Backup of schema support_appl was successful in 0 seconds Error: Backup of schema support_dict was not successful (1115 seconds): mysqldump: Got error: 2013: Lost connection to MySQL server during query when retrieving data from server Error: Backup of schema test was not successful (0 seconds): mysqldump: Got error: 2002: Can't connect to local MySQL server through socket '/var/lib/mysql/mysql.sock' (2) when trying to connect ======================================= I re-ran the backup cron job with the same results. Does anyone have any troubleshooting suggestions?
Generating DAILY Min&Max Over A Period Of Time, Based On A "DateTime" Field
how to print the minimum and maximum of a specific field, between two datetimes (both having the time 02:00:00) - so I did this: WHERE ((tblvalues.dtLPDateTime)>="2006-01-01 02:00:00" And (tblvalues.dtLPDateTime)<"2006-01-03 02:00:00")) Now I want to print those min and max values but for each day in this cycle, i mean, for this example, there would be two records like: Day Min Max 2006-01-01 02:00:00 -> 2006-01-02 02:00:00 | 40 | 59 2006-01-02 02:00:00 -> 2006-01-03 02:00:00 | 49 | 68 where at this point i`m getting min=40 and max=68
"supplied Argument Is Not A Valid MySQL Result Resource" Error
i am getting this error with the following code: $query = "SELECT title, firstname, surname, address1, address2, address3, postcode," ."tel, mobile, email" ."FROM user" ."WHERE username='$valid_user'"; us.skill_id=s.skill_id" $result=mysql_query($query); $num_rows=mysql_num_rows($result); $row=mysql_fetch_array($result); The error is referring ot the last 2 lines of this script.
Unable To Connect To Server (was "Novice User Problem")
I've been reading Kevin Yank's Build Your Own Database Driven Website and am unable to connect to the MySQL server as he describes in Chapter 4 (p. 74-75). After modifying his code to produce a mysql_error, I get: Unable to connect to server at this time.Client does not support authentication protocol requested by server; consider upgrading MySQL client Even though I am using the latest MySQL server (5.0). My ?php $dbcnx = @mysql_connect('localhost', 'root', 'my_actual_password'); if (!$dbcnx) { exit('<p>Unable to connect to server at this time.' . mysql_error() . '</p>'); } if (!@mysql_select_db('ijdb')) { exit('<p>Unable to locate the joke database at this time.</p>'); } ?> <p>Here are all the jokes in our MySQL database:</P. <blockquote> <?php $result = @mysql_query('SELECT joketext FROM joke'); if (!$result) { exit('<p>Error performing query: ' . mysql_error() . '</p>'); } while ($row = mysql_fetch_array($result)) { echo '<p>' . $row['joketext'] . '</p>' } ?>
Linking Stores With Products (was "MySQL Dificult Code")
I have a MySQL database dificult (for me anyway..). I have a ecommerce site with a table of products. Now I want to create a new table with a list of stores where clients can find near home those products. In a limit situation I can have a list of all products indexed in one store (and the products list is increasing everyday, the same with the list of store...). I want this feature to be capable of introdution of new products in a store that already as several products. My idea is to develop 3 tables: Products +----+-----------+--------------+ | id | name | description | +----+-----------+--------------+ | 1 | xxxxx | aasa... | | 2 | vvvvvv | asasasasas... | +----+-----------+--------------+ Stores +----+-------------------+-----------+ | id | store | address | +----+-------------------+----------+ | 1 | aaaaa | street1... | | 2 | bbbbbb | street2... | +----+-------------------+-----------+ Linking stores with products +----+-------------------+-------------+ | id | store id | products id | +----+-------------------+-------------+ | 1 | 1 | 1;2 | | 2 | 2 | 2 | +----+-------------------+-------------+ Can I implement this in MySQL? I mean how can (if I can) place several ids in a field? and how can I do the query in order to list the products inside a store? Hope that I made my self clear. If not please do not hesitate to request further information.
What Is Execution Time Of A Query Based On? (was "a Mysql Question")
when selecting data from the database, does the time taken to retrieve it vary from 56k connections to T3 connections? or does it all depends ont he general server speed/amount of connections on the db? im not sure if ive explained that in the best way for people to understand but im sure someone will get what i mean
List All Clients Not Assigned To Current User (was "Query Help Please")
I have two tables like this: *clients -- client_id -- client_name *manage -- user_id (multiple entries possible) -- client_id To assign clients to users there is a entry in the manage table of the user_id and client id. I want to list all the client_ids and client_names that are not assigned to the current user_id say 1.
Unique Combinations Of Model And Make (was "Query Question")
I'm trying to write a query and was wondering if someone could help me formulate it. Here is an example table I'm working with: Table: vehicles Model Make Ford Taurus Ford Taurus Ford F150 Chevy Tahoe Chevy Blazer Chevy Tahoe I want a query that returns all unique combinations of model and make. So the result set should be: Model Make Ford Taurus Ford F150 Chevy Blazer Chevy Tahoe I know how to return distinct values for one variable, but not for two like that. Any help is greatly appreciated.
Return 1 Row With Concatenated String (was "Really Easy But My Minds Gone Blank")
I'm creating a website for my local American Football team and the database structure is as follows: CREATE TABLE players ( `PlayerId` tinyint unsigned NOT NULL, `Jersey` tinyint unsigned, `FirstName` varchar(12), `LastName` varchar(20), `ContactNumber` varchar(12), `Email` varchar(40), PRIMARY KEY(`PlayerId`) ); CREATE TABLE playerposition ( `PlayerId` tinyint unsigned NOT NULL, `PositionId` tinyint unsigned NOT NULL, PRIMARY KEY (`PlayerId`, `PositionId`) ); CREATE TABLE positions ( `PositionId` tinyint unsigned NOT NULL, `PosAbbr` varchar(3) NOT NULL, `PosLong` varchar(30) NOT NULL, PRIMARY KEY (`PositionId`) ); Now each player can play a multitude of positions say PlayerA can play QB, RB and TE. My query is as follows: SELECT pl.PlayerId, Jersey, FirstName, LastName, PosAbbr FROM players pl, playerposition pp, positions po WHERE pl.PlayerId = pp.PlayerId AND pp.PositionId = po.PositionId Now it will return 3 rows for PlayerA, 1 row for each position they play. What I want it to return is 1 row with a concatenated string of their positions something like QB/RB/TE. My mind has just gone blank. Can anybody enlighten me on this. P.S. I'm running 4.1 on the server.
Adjacent Theater Seats (was "mySQL Query Issue")
Having not been working with more than a simple SELECT * from table query, I am having a few issues when it comes to using more complex queries. I am currently using a query to select seats from a database using the following query: $query1 = mysql_query("SELECT struct.seatid, struct.row, struct.seatnum FROM seats as seat LEFT JOIN structure as struct USING (seatid) WHERE seat.showtimeid=".(int) $_GET['id']." && seat.available = Ƈ' && seat.timelimit < $minutes2 ORDER BY seat.seatid ASC"); For each record that is selected I want to check if either of the seats either side of it are also selected, if not then it is not to be shown. I have added a while loop below the above query and run another query following it (not sure if that makes sense, so I will paste it below!) while($rows = mysql_fetch_assoc($query1)){ $minusseat = $rows[seatid] - 1; $plusseat = $rows[seatid] + 1; $queryminusseat = mysql_query("SELECT * from seats LEFT JOIN structure WHERE seat.showtimeid=".(int) $_GET['id']." && seat.available = Ƈ' && seat.seatid == $minusseat && seat.timelimit < $minutes2"); $num_rows = mysql_num_rows($queryminusseat)or die(mysql_error()); echo "$num_rows"; //if($minusnum > 0){ //echo "$minusseat <b>" . $rows[seatid] ."</b> $plusseat <br/>"; //} else { //echo "<font color=red>$minusseat <b>" . $rows[seatid] ."</b> $plusseat <br/></font>"; //} } The code above is used below the initial query and the following error is being displayed: Quote: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:Program Filesxampphtdocsprojectprototype1 ickets.php on line 154 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE seat.showtimeid=1 && seat.available = Ƈ' && seat.seatid == 1 && seat.time' at line 1
Access Denied For User 'root'@'localhost' (was "help!!! Just A Beginner..")
Hello i recently installed WAMP5 to handle my phpmysqlapache localhost sever. but when i go to the control panel and clicked the localhost and phpmyadmin everything seems fine because i can see the phpinfo window and also the phpmyadmin.. but not when i clicked the SQLite Manager.Unable to connect to database manager. Could not connect: Access denied for user 'root'@'localhost' (using password: YES).
How Can I "see" A Table In A Database On A Remote MySQL Server After Creating It
I used the following SQL to create a new table in a database on a remote MySQL server by copying one already there. I know the table exists SOMEWHERE in cyberspace. I can read its data, write to it, delete from it. But I cannot see it. The only way I know it exists is by running this SQL from Access 97 pass through query: SELECT ALL new_tbl.name FROM new_tbl The database resides on a MySQL server that was created with a single table (named test) in it for testing purposes. I ran the following SQL to create another copy of the table in the same database named: new_tbl CREATE TABLE new_tbl SELECT * FROM test; I cannot see the new table in the Access 97 database window under the Tables Tab. Anybody know how to overcome this? Its a severe drawback to programming efforts not to KNOW what tables are in your database.
Beta Testers Wanted For New "blueshell Data Guy Professional"
We are seeking beta testers for our upcoming "blueshell Data Guy Professional". This new application is an extension to our award-winning universal database editor "blueshell Data Guy" (bDg) valuable for database professionals like DBA's, developers etc. Although bDg serves almost all databases, we're planning to focus the beta on MS SQL Server, Oracle, MySQL, Sybase Anywhere, Advantage DB Server, DB2 and Jet. Nevertheless, if you want to test it against any other DBMS, please let us know. These are the main features of bDg Professional: - All features of bDg Standard like schema browsing using a tree view, table view and edit, table design, import, export, desktop connectivity etc. (See http://www.blueshell.com/Product.asp?Prod=bDg for product details) - "SQL Cook" to assist you in entering valid SQL statements (something between Intellisense and a wizard) - Design (edit) objects like stored procedures, functions, packages, triggers and sequences - Easy design of table relationship (foreign keys).
Multi-table UPDATE Problem (was "mysql Question")
$sql = "UPDATE char_lair , char_main m SET l.zip_id='$zip', l.lair_addr='$address', m.alias='$alias', m.real_name='$name', m.align='$align' WHERE m.id = $cid AND m.lair_id = l.id"; I am using mysql v.3.23, I got error in this code but can't find the solution. The message displayed in browser is: --------------------------------------------------- UPDATE char_lair , char_main USING char_lair l, char_main m SET l.zip_id='z3', l.lair_addr='a3', m.alias='ch3', m.real_name='rn3', m.align='good' WHERE m.id = 2 AND m.lair_id = l.idYou have an error in your SQL syntax near ' char_main USING char_lair l, char_main m SET l.zip_id='z3', l.lair_addr='a3'' at line 1 ========================================= Is there any syntax error?
Invalid Use Of Group Function (was "Baffled By Query Error")
trying to figure out why I keep getting this error with the following query: SELECT c.account_id,a.name,a.company,SUM(c.agent_product_time) AS mins FROM account a LEFT JOIN calls c ON c.account_id = a.id WHERE c.calldate >= DATE_SUB(NOW(),INTERVAL 14 DAY) AND c.agent_id = 2 AND SUM(c.agent_product_time) >= '500' GROUP BY c.account_id ORDER BY mins ERROR: #1111 - Invalid use of group function
Compare 2 Tables And Find Rows Which Don't Match (was "Mysql Noob Question")
I have a products table and a products_description table. They both have products_id as primary key. However, products_description table has more products_id keys then the products table. How do i compare the 2 tables and show just the products_id that dont match from products_descripition table? SELECT products.products_id, products_description.products_id FROM products, products_description WHERE products.products_id != products_description.products_id; I tried that query but got some wierd results and also the results gave me 2 columns when I just want one.
|