A Simple Outer Join

Outer Join With Where
I am willing to select all the distinct Products from the product table and in case the PC Name was the same as a @ passed PC name return ALSO the local path, Otherwise return null for the localpath field.... How I can do that?
here is my query:

SQL
SELECT  Products.Name, Products.Code,
 UserProduct.LocalPath, UserProduct.PC FROM
  Products LEFT OUTER JOIN
  UserProduct    ON
 UserProduct.ProdCode = Products.Code
this returns the same product name and product code from many users....also, I want to return distinct Product Names also.

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Do I Need An Outer Join?
I have a table that stores traffic data keyed on a char (even though I call it a tstamp). The data is coalated into hourly chunks and is viewed through a web app in monthly, daily and hourly increments.

I've been charged with creating some KPI's (Key Performance Indicators) from this data and one of them is for a given month/day/year, generate an addition figure of how many times the average traffic per period (in a column called average) is less than or equal to 5.

mysql> desc coal_counts ....

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Outer Join
hello, I am trying to run following query in mysql.

select a.name, a.record, b.data from A a, B b where a.name*=b.name and b.date='2006-07-28'



How can I do this in mysql? I looked up LEFT JOIN but still can't figure it out.

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OUTER JOIN
I have 2 tables with the corresponding columns:

1) InventoryComputers-ComputerID, ComputerSN.
2) InventoryStations-Autonum, BranchID, StationID, ComputerID.

I want to display all rows of InventoryComputers for which the ComputerID does not have an entry in InventoryStations.
So basically, I want to display those computers that do not have a station assigned to them.

I tried this sql statement, but it also displays those rows that are present in InventoryStations table, which I don't want.


SELECT * FROM InventoryComputers
LEFT OUTER JOIN InventoryStations on InventoryStations.ComputerID=InventoryComputers.ComputerID
ORDER BY InventoryComputers.ComputerID


Any ideas what is wrong??

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Outer Join
i have a main table called property, and a lookup table called ptype (property type). the propertry table has a "type" field, and a "subtype" field. both these fields look at the ptype table to get their titles.

so, i currently have the query below, but i also want to add to this the subtype. trouble is the field name is going to be the same for both the type and subtype values, so how do i get at them both?

I tried "AS subtype" after the LEFT OUTER JOIN but this didnt work.

SELECT * FROM property
LEFT OUTER JOIN ptype ON ptype.pty_id = property.pro_ptype
WHERE property.pro_id = 1

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LEFT OUTER JOIN + WHERE ?
I have problem with constructing a SQL query. I have tables with data:

mysql> SELECT * FROM category;

+----+-----------+
| id | is_active |
+----+-----------+
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 1 |
+----+-----------+

4 rows in set (0.00 sec)

mysql> SELECT * FROM category_i18n;

+------------------+----+---------+
| name | id | culture |
+------------------+----+---------+
| Agroturystyka | 1 | pl_PL |
| Bed&breakfast | 2 | pl_PL |
| Hotel | 3 | pl_PL |
| Obiekt zabytkowy | 4 | pl_PL |
+------------------+----+---------+

4 rows in set (0.00 sec)
Category table includes category id and is_active status. Category_i18n has category names translations for several cultures and the id field is a foreign key.

Now I'd like to get result like this:
mysql> SELECT c.id, ci.name FROM category c LEFT OUTER JOIN category_i18n ci ON c.id=ci.id WHERE ci.culture='pl_PL' OR ci.culture IS NULL;

+----+------------------+
| id | name |
+----+------------------+
| 1 | Agroturystyka |
| 2 | Bed&breakfast |
| 3 | Hotel |
| 4 | Obiekt zabytkowy |
+----+------------------+

4 rows in set (0.00 sec)
And in this case (culture='pl_PL') it works fine. But when I change culture to 'en_US' I don't get any results. How to change my query to select all ids from category table and join name field from category_i18n table but with culture condition. If there is no translation there should be a NULL value.

Result I'd like to get for culture='en_US':

+----+------------------+
| id | name |
+----+------------------+
| 1 | NULL |
| 2 | NULL |
| 3 | NULL |
| 4 | NULL |
+----+------------------+

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Left Outer Join
I have noticed when I do a Left Outer Join in short form that many rows
become missing as result of null values.

i.e Left Outer Join (t1,t2,t3) ON (....)

T3 being table with null values in

It seems to be all to hard when I log a bug.

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Three Table Outer Join
I have three tables:

items (id, article, etc)
deliveries (id, shipment_date, etc)
movements (item_id, delivery_id, quantity, etc)

I want to get result as following:
article | sum(quantity)

but for all articles (outer join) with condition for deliveries table(shipment_date >= '2004-08-01' for example)

It works for two table join (items and movements) without deliveries:
select i.id, sum(m.quantity) from
items i left outer join movements m on m.item_id = i.id

but how I should join "deliveries" table to add condition for shipment_date ?

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Left Outer Join
I have just converted an app from MS Access to MySql. I have using Hyperion Performance to run my queries. I have 4 tables and main table and three look up tables. when I do a left outer join to one table the query runs fine, however when I do the left outer join to more then one table it error out.

with this error message: You have an error in your sql syntax check the manual that corresponds to your Mysql server version for the right syntax to use near {oj left outer join rc_availability Al4 Al1.rc=Al4.rc} where al1.msa=al at line 1 Code:

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Left Outer Join
This is what I have come up with:

SELECT CP1.PosID, CP1.Rank, CP1.BookID, CP2.BookID AS LastWeekBook, CP1.StationID, CP1.ChartTypeID, CP1.WeekID ,
CP2.Rank AS LastWeekRank, CP2.WeekID AS LastWeek
FROM Position AS CP1
LEFT OUTER JOIN Position AS CP2 ON CP1.BookID = CP2.BookID
WHERE CP1.WeekID = {d '2007-05-08'}
AND CP2.WeekID = DATE_SUB({d '2007-05-08'}, INTERVAL 7 DAY)
AND CP1.ChartTypeID = 101
AND CP2.ChartTypeID = 101
ORDER BY Rank;

(Note: joins to other tables containing author infor and book titles etc, have been omitted for simplicity.)

Instead of returning 50 rows (one for each matching row in CP1) it returns 36 rows (only those rows where the book appears in both CP1 and CP2).

I have tried alternative join syntax as follows and all return the same result:
LEFT JOIN
INNER JOIN (36 rows would be expected)
RIGHT JOIN
RIGHT OUTER JOIN

As far as I can tell the SQL as written should be giving me the desired result but it isn't and I can't see what I might be doing wrong.

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Iso FULL OUTER JOIN
I need to do a full outer join, but have not seen this available in the fine manual. Is this type of join available?

The task is to list everyone that has departed the company in a certain date range. Sometimes a record is entered on table A, sometimes on table B, sometimes on both.

SELECT a.NAME, b.NAME FROM TABLEA A FULL OUTER JOIN TABLEB B ON A.SSN = B.SSN WHERE A.DEPART_DATE BETWEEN @BEGIN AND @END or
B.DEPART_DATE BETWEEN @BEGIN AND @END .

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Outer Join And Distinct
I just started building a website and use MySQL as my backend database. I'm having a little trouble creating an SQL query that will get the correct information out.

Here's my problem:

I have 3 tables:
people: stores the name of people who can vote
votetype: stores the type of votes there are (In favor, Against, Withheld)
decisions: the dicisions that were voted on

Then I have another table that links them all together called votes. Votes has three columns: personID, typeID and decisionID. personID and decisionID are primary key. All are foreign key to obvious tables.

I want to retrieve for a given person the votes he made for all decisions. So: a list of all decisions with the vote he or she made and a NULL if there is no vote.

So far I have this query:
SELECT DISTINCT d.ID, d.name, d.date, v.typeID AS vID, t.name FROM decisions d, votetype t LEFT OUTER JOIN votes v ON v.decisionID = d.ID WHERE (v.personID=1 OR v.personID IS NULL) AND (v.typeID=t.ID OR v.typeID IS NULL) ORDER BY d.date;

For some reason the DISTINCT doesn't work and I get a decision that is not voted for three times (once for each type while v.typeID column is NULL).

How can I fix this so each decision only shows up once?

Jurgen

-------------------------
I've found a solution:

SELECT DISTINCT d.ID, d.name, d.date, v.typeID AS vID, IF(v.typeID IS NULL,NULL,t.name) AS stem FROM decision d, votetype t LEFT OUTER JOIN votes v ON v.decisionID = d.ID WHERE (v.personID=1 OR v.personID IS NULL) AND (v.typeID=t.ID OR v.typeID IS NULL) ORDER BY d.date;

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Left Outer Join
^ just a quick question I can't find an answer for, with the mysql syntax is 'left outer join' the same as 'left join' ?

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LEFT OUTER JOIN
am using mysql and want a recordset to be displayed from a query that links three tables.
because a user can add to their selection at a later date i would like all records from a tbl_fitopt to be displayed even when there are no foreign keys in the other tables.
sql is below but at the moment it only lists records from tbl_fitopt that have keys in tbl_fitoptlink - nb i need all records from tbl_fitopt to display so a user can add/subtract from there choices.

strsql = "SELECT tbl_fitopt.fitoptid, tbl_fitopt.fitoptcost, tbl_fitopt.fitopt, tbl_stock.stockid, tbl_fitoptlink.fitoptlinkid "_

& "FROM (tbl_fitopt INNER JOIN tbl_fitoptlink ON tbl_fitopt.fitoptid = tbl_fitoptlink.fitoptid)
INNER JOIN tbl_stock ON tbl_fitoptlink.stockid = tbl_stock.stockid "_

& "WHERE tbl_stock.stockid = " & tkey & ";"

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Outer Join Syntax Error
Trying to do an outer join to retrieve info from two data bases and keep coming up with syntax errors....here's the code

$result = @mysql_query('SELECT * FROM members OUTER JOIN 2nd_location USING (members.ID = 2nd_location.ID) WHERE members.type= "RET" AND members.active="A" AND members.multi_location="Y" ');

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OUTER JOIN With Extra Conditions?
I need to get a list of products in a certain category, along with the quantity of each item already added to the shopping cart for a given session number. I'm having a heck of a time satisfying the latter condition.

shoppingCart table:
+--------+-----------+-----------+-----+
| cartID | sessionID | productID | qty |
+--------+-----------+-----------+-----+
product table:
+-----------+--------------+------+--------+
| ProductID | ProductCatID | name | Active |
+-----------+--------------+------+--------+
Here's my base query, which just gets all the products in a given category.

SELECT product.*
FROM product
WHERE `ProductCatID`='{$id}'
AND `Active`=Ƈ'
Here's the query I've got so far:

SELECT product.*, shoppingCart.qty
FROM product
LEFT OUTER JOIN shoppingCart ON shoppingCart.productID = product.ProductID
WHERE `ProductCatID` = Ɗ'
AND shoppingCart.sessionID = '{$sessionID}'
AND `Active` = Ƈ'
Obviously, this does NOT work, because it limits the query to ONLY products that have the specified sessionID. I need it to return ALL the products in the category, but give me the quanity for items in the shoppingCart table, ONLY IF the sessionID matches (otherwise it should return NULL)!

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Multiple LEFT OUTER JOIN
What is the right way to do a LEFT OUTER JOIN on both these tables to the 'Main' table where WHERE Plan.pID IS NULL and Record.rID IS NULL (primary's)

Plan
pID | _mn (foreign main key) | pType

Record
rID | _mn (foreign main key) | rDate

Main
mID (primary) | mComp

-------------------------------------
Will need: pType, rDate, mComp values as a result of the query.

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Struggling With Left Outer Join
got two tables:

T1 - User, Date, Stuff

T2 - User, Date, Other Stuff

I want to be able to select rows from T1 based on User & Date, join those rows to the data in T2, so T1.User=T2.User AND T1.Date=T2.Date. Then I want to sort the results in T1.Date order

I've no idea where to start ... anyone point me in the right direction?

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Transform SubSelect In OUTER JOIN
maybe I'm simply to dump but I could not transform this SQL-Statment
which uses a Sub-select and create on that uses an OUTER JOIN ....

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Double OUTER JOIN On The Same Table?
I'm trying to make a request with an OUTER JOIN on 2 fields at the same time:

Here are the tables:

test:
- id
- user1
- user2

users:
- id
- username

And Id like to get as result each line of the 'test' table, with the corresponding username from 'user' fir the fields user1 and user2.

Do you know how to do this without using several SELECT?

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Performance Left Outer Join
I changed a query from an equal join to a left outer join but then the performance is suddenly 10 times as slow ?? Is this normal or do I miss something ??

$query1="SELECT * FROM ";
    $query1=$query1 . "clienttable,contacttable AS co1 WHERE co1.coclid=clid ";
    $query1=$query1 . " AND clname like '$alfabetisch%' ";
    $query1=$query1 . " order by $o";

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Left Outer Join Syntax
I am trying to join a table to three other tables

Table 1 has all records
Table 2-4 must be left outer joined to table 1, not in a chain

using "other" dbs ...

select t1.a
,t2.b
,t3.c
,t4.d

from t1
,t2
,t3
,t4

Where t1.id = t2.id (+) and t1.id = t3.id (+) and t1.id = t4.id (+)

I've tried using the left outer join syntax ...

select t1.a
,t2.b
,t3.c
,t4.d

From t1
LEFT OUTER JOIN t2 using (id)
LEFT OUTER JOIN t3 using (id)
LEFT OUTER JOIN t4 using (id)

but that, of course chains t1 to t2, t2 to t3, and t3 to t4.

How can I make this join work, without the use of subqueries?

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Full Outer Join Should Work
why doesn't the following work?

mysql> select * from girls full outer join boys where girls.city = boys.city;

where :

drop table girls;
drop table boys;
create table girls (name varchar(12), city varchar(12));
create table boys (name varchar(12), city varchar(12));
insert into girls values('Mary', 'Boston');
insert into girls values('Nancy', null);
insert into girls values('Susan', 'Chicago');
insert into girls values('Betty', 'Chicago');
insert into girls values('Anne', 'Denver');
insert into boys values('John', 'Boston');
insert into boys values('Henry', 'Boston');
insert into boys values('George', null);
insert into boys values('Sam', 'Chicago');
insert into boys values('James', 'Dallas');

If needed, I can go into insert and create for you!

BTW left and right work OK!

BTW what do P1(T1,T2), P1(T1,T2) and R( mean in the following

SELECT * T1 LEFT JOIN T2 ON P1(T1,T2)
WHERE P(T1,T2) AND R(T2)

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Left Outer Join Produces
In order to eliminate duplicate values from the right of a query I tried the following:

 LEFT OUTER JOIN 
        `private_comments`  
    ON 
        `report_cards`.id IN (select distinct `private_comments`.student_id1 from `private_comments`) 

I have unique `report_cards`.id but multiples of `private_comments`.student_id1.

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Sould Someone Verify LEFT OUTER JOIN?
could someone please verify :

SELECT *
FROM Members, Submits, MNotify LEFT OUTER JOIN MemPay as mp on
(mp.MPMem_ID=Members.MemID and Members.MemID=colname and mp.MPSub_ID=MNotify.FK_SubmID)
WHERE Submits.SubmID=MNotify.FK_SubmID and Members.MemID=colname
MemPay - payment table, where
MPID | MPMem_ID (actually foreign) | MPSub_ID

Members
MemID

Submits - submitted ads
SubID

MNotify - Members become notified of individual submitted ads
MNID | FK_MemID | FK_SubmID

Members can view each MNotify.FK_SubmID (submitted ads -- the ads may be bought, and if so are found in MemPay table. MPMem_ID is the buyer primary id and MPSub_ID is the id of the submitted ad bought.)

In any case, the Member can view all submitted ads (including purchases) while the check on the LEFT OUTER JOIN values gives what he or she has bought.

While it seems to output as it should, when I check on the LEFT OUTER JOIN values with php conditional statements I've getting values oppositie of what they should (checking on NULL, <>NULL, empty, !empty)

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Workaround For Outer Join Using Filtering Subquery
I'm using mysql 4.0.x, which does not allow the following query (which works
fine in 4.1). Is there any way I can issue a single query to achieve the
same results? (I want a list of all records from table al, nulled where
there is no match in table alm, which has been filtered. Without a
subquery, the filtering occurs after the outer join, and for one specific
row from alm, I only see the nonmatching records from al where NO other alm
record matches.)

SELECT al.id, alm.idmember, al.listname
FROM addresslists AS al
LEFT OUTER JOIN
(SELECT idlist, idmember FROM addresslistmembers WHERE idmember = 4)
AS alm
ON al.id = alm.idlist

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Left Outer Join Doing Wired Things
i have two tables, tableA and tableB, i want all of tableA but regardless of if there is a record in tableB that references the record of tableA, so thats what an outer (or left, or left outer) join should do if tableA is the left table... right?

Ok first my Query:

SELECT *
FROM tableA A
LEFT OUTER JOIN tableB B
ON A.ID=B._IDa
WHERE ((B._IDb IS NULL) OR (B._IDb=3)); -- no record exists in tableB with _IDb=3

tableA is referenced by tableB's foreign key field _IDa
tableA has 27 rows, tableB has many rows but none that have _IDb=3

So I expect to get 27 rows with NULL for all fields of tableB, but i only get 18 rows!!
(all fields of tableB are, as expected, NULL, but WHY those 18?!! why not all or none?!)

Note though that B is a composite entity, where _IDa is only half of the primary key, _IDb is the other half referencing someother table that's not important for this problem.

Code:

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Slow Execution For A Left Outer Join Query
Whats likely to be the cause of slow execution for a left outer join query?

The original query joins three tables but even if I narrow it down to one it still takes a long time to execute.

$query = "select distinct materials.* from materials";
$query .= " left outer join materials_products on materials.material_id = materials_products.material_id";

There's 914 rows in the materials table and 1348 row in the materials_products table

Is it likely to take a long time for this amount of data or is there likely to be a problem in the table(s) set up or query?

---

Simple Join
Just a quick question on how to make this join work.

basically here are my two tables:

tblride:

rideid|ridename
7|Spinball
10|Air|

tblslogan:

sloganid|rideid|slogan
1|7|Its Flippin Crazy
2|10|Prepare
3|10|Now Fly

With those two tables I want to basically display in a table on my page the ridename and then in the next cell the associated slogans separated by a comma.

How can this be done? Can anyone give me an example of an sql query or some php code which could do this for me?

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Simple Join?
I need to find all the groupID's that employee ID=123 doesn't belong to
given the following table structure:

EmployeeGroup
------------------------
groupID
groupName


EmployeeGroupMap
----------------------------
groupID
employeeID

Ideas?

---

Simple Join
I have a simple join question. I need to optimize for speed. If I have two tables with a one-to-many relationship, say, [Invoice] and [Items]. And say they are joined by [Invoice]'s primary key of type AUTO_INCREMENT. Here's the question:

When I add a record in both [Invoice] and [Items], how does mysql "know" the value of the [Invoice] primary key so that it can properly insert that value in the appropriate field of [Items]?

Do I have to do a separate SELECT after I insert item in [Invoice] so I can "know" what join value to put in [Items]?

---

Simple Join
I need to find all the groupID's that employee ID=123 doesn't belong to
given the following table structure:

EmployeeGroup
------------------------
groupID
groupName


EmployeeGroupMap
----------------------------
groupID
employeeID.

---

Simple Join
I'm trying to join the vendor table whenever the equipment.vendor is equal to vendors.id. The query just shows the equipment table values and nothing from the vendors table. Did I execute the query correct?

SELECT equipment.itemid, equipment.description, equipment.vendor, equipment.reorderlevel, equipment.tonhand
FROM equipment
LEFT JOIN vendors ON vendors.id =equipment.vendor
WHERE buyer = 3

---

Simple Join Question
ON EDIT: I figured out the SQL syntax problem. But here's the rest of my question:

I'm trying to join two tables with information about birds, each of which share a field named "Name," which contains birds' scientific names. Most of the information I need comes from table gz_birds, but I also want to display common names, from gz_birds_names.NameCommonD.

If I write a query that targets table gz_birds only, then it displays every member of a particular bird family. For example, genus Falconidae might display a dozen genera...
PHP

$Children = mysql_query ("SELECT GZB.N, GZB.Name, GZB.Parent, GZB.Parent2, GZB.Rank
FROM gz_birds AS GZB
WHERE $Parent = '$URL1' Order By N, Rank");
But when I join table gz_birds_names, it displays just two children (genera)...
PHP
$Children = mysql_query ("SELECT GZB.N, GZB.Name, GZB.Parent, GZB.Parent2, GZB.Rank,
GZBN.Name, GZBN.NameCommonD
FROM gz_birds AS GZB
LEFT JOIN gz_birds_names GZBN ON GZBN.Name = GZB.Name
WHERE $Parent = '$URL1' Order By N, Rank");

---

Simple Left Join
Quote:

CREATE TABLE phpbb_anti_robotic_reg (
session_id char(32) DEFAULT '' NOT NULL,
reg_key char(5) NOT NULL,
timestamp int(11) unsigned NOT NULL,
PRIMARY KEY (session_id));

---

Simple Join Statement
I seem to be a complete idiot when it comes to join statements. Here is what I am trying to do...two tables -

TABLE tags
COLUMNS
-id
-tag

TABLE tag_assoc
-id
-article_id
-tag_id

I want to get a list of the tags for a specific article ID. The first table is simply a list of all the tags, while the second table lists relationships between an article and a tag. An article can have many tags.

---

Why Does This Simple Join Fail To Work?
I don't get any errors but the returned rows aren't the ones i expect from this query.

When i run the query below i get only two rows from news (2 and 5) while i would expect to receive all rows from news with either 0 or 1 for commentcount

I've narrowed down the problem to the join but i fail to see why the join excludes the other rows? Can anyone help me out with this one? Using MySQL 4.1.20

My Query:

SELECT
news.id,
news.title_nl,
COUNT(news_comments.id) AS commentcount
FROM
news
LEFT JOIN
news_comments
ON news_comments.news_id = news.id
GROUP BY
news_comments.news_id
news Table:

CREATE TABLE `news` (
`id` int(11) NOT NULL auto_increment,
`title_nl` varchar(255) default NULL,
`title_fr` varchar(255) default NULL,
`body_nl` text,
`body_fr` text,
`source` varchar(255) default NULL,
`user_id` int(11) default NULL,
`status` tinyint(1) default &#391;',
`type` varchar(200) default 'uitgaan',
`created` timestamp NULL default NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

INSERT INTO `news` VALUES (&#392;', 'A little on me ...', null, 'Brokerage, regal, symphony gold status housekeeping panoramic respectable status champagne gem saphire panoramic. Metropolitan le doctoral accredited marquis world lifestyle. Fine, echelon wealth de-jour ambassador lifestyle member gem wine portfolio affluent cruise. Wine gilded dynasty noble architectural opera travel cigar luxury ballroom echelon. World, genuine gilded de-jour first-class member theatre inspiring yacht. Noble distinctly suite auction philanthropic club designer echelon regal. Benefiting board imported benefiting stockmarket in cocktail portfolio diplomatatic fine townhome.

Diplomatatic townhome, tailored gold penthouse club reserved monogram pearl champagne, acumen symphony affluent le. Yacht stockmarket expensive grande, travel guests monogram diamond status in opulent doctoral gentlemen opulent imported. Opera inspiring five-star accredited champagne sheer designer club career.

Enthusiast panoramic handmade gifted pedigree lifestyle architectural investments benefactor acumen world housekeeping wine university dynasty. Investments, cuisine, cutlery private, auction marquis caviar imported elegant, rare, cutlery member diamond panoramic elegant.

Investments, butler rare housekeeping art investments in brokerage ladies enthusiast portfolio bonds. Private, architectural benefiting fashion with cigar member polo, using upper.

Dynasty enthusiast travel, symbolizing sport using, de-jour upper portfolio cuisine gifted private echelon le repertoire. Wine repertoire salon yacht, university travel board european echelon university gifted, luxury wine de-jour status. Gilded art on dynasty private, townhome.

', null, 'Den TVgids', &#392;', &#393;', 'uitgaan', &#55614;&#57159;-06-22 11:13:05');
INSERT INTO `news` VALUES (&#393;', null, 'Nieuws Test', null, 'Dit is een test van het nieuws, eens zien of het fatsoenlijk marcheert!', 'Inventis gazet', &#391;', &#393;', 'uitgaan', &#55614;&#57159;-06-13 11:15:55');
INSERT INTO `news` VALUES (&#394;', 'Datum testen', null, 'Conventio olim huic velit, enim vulputate interdico jumentum ymo, si conventio, feugiat luctus. Dignissim jus, nimis abbas importunus quis conventio dolore. Feugait et neque vindico aliquip quod sed sudo humo exerci nonummy. Iriure caecus caecus delenit, aliquip praesent, facilisi iusto oppeto decet, vindico velit. Facilisi distineo demoveo ea ea eum abigo damnum.

Nulla vel ullamcorper nulla nisl quis bis euismod hendrerit regula lenis. Ymo duis in oppeto importunus damnum blandit nimis gemino minim aliquip quadrum. Valde ad praesent dolore causa consequat abdo haero duis bene in quis ingenium duis, huic. Augue mauris dolus vindico hendrerit, roto demoveo ulciscor, delenit.

Nonummy autem praemitto, enim erat abico. Vero plaga eu illum acsi ut transverbero wisi secundum hos. Premo aliquip multo os vel, lucidus feugait, illum lenis laoreet ludus. Typicus bene opes suscipit odio fatua hos dolore hendrerit decet. Praesent magna ullamcorper eu ne secundum nisl nimis incassum reprobo obruo mauris nisl blandit feugiat. Loquor tincidunt erat, utinam nimis ideo epulae, vulputate, et ideo elit eum. Acsi, in demoveo esca zelus mos roto ut quis demoveo tation letatio interdico veniam. Erat consectetuer tation duis nulla ullamcorper.

', null, null, &#391;', &#393;', 'muziek', &#55614;&#57159;-06-14 11:22:24');
INSERT INTO `news` VALUES (&#395;', 'Nog een test van de timestamp', null, 'Timestamps in mysql ... argh!Ideo pecus, pagus sudo autem enim.

Enim odio, turpis et velit imputo nobis. Neque ludus multo nulla valde importunus ea.
Appellatio illum abico, duis, augue tego interdico exerci quia veniam rusticus nulla multo. Nulla jus, capto mara immitto aptent vel wisi abluo ut accumsan iaceo.

Facilisi iusto euismod lobortis, torqueo hos suscipit singularis hendrerit in. Occuro usitas fere minim usitas jumentum facilisi iriure facilisis ea te ut ad cui.

', null, null, &#391;', &#393;', 'uitgaan', &#55614;&#57159;-06-26 11:06:07');
INSERT INTO `news` VALUES (&#396;', 'Test nieuwtje', null, 'Dit is een test van een nieuwsbericht met een <a href="http://www.google.com">Link naar google</a> en wat <strong>tekst in het vet gedrukt</strong>.

Een nieuwe paragraag behoort ook tot de mogelijkheden', null, null, &#392;', &#393;', 'muziek', &#55614;&#57159;-06-14 10:17:15');
news_comments Table:

CREATE TABLE `news_comments` (
`id` int(11) NOT NULL auto_increment,
`news_id` int(11) NOT NULL default &#390;',
`user_id` int(11) NOT NULL default &#390;',
`created` timestamp NULL default CURRENT_TIMESTAMP,
`body` text NOT NULL,
`status` tinyint(1) NOT NULL default &#391;',
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

INSERT INTO `news_comments` VALUES (&#391;', &#395;', &#392;', &#55614;&#57159;-06-26 16:12:02', 'Dit is een test reactie', &#393;');

---

Simple JOIN Query Issues
What I want to do is have multiple tables interact with each other.

payments TABLE
id | paidfrom | paidto | paidmethod
1 | 2 | 1 | 2
2 | 3 | 1 | 3

users TABLE
userid | username
1 | Jake
2 | Todd
3 | Spencer

methods TABLE
methodid | methodstring
1 | Cash
2 | Check
3 | Credit Card

---

Join 2 Simple Queries Into A Single Query?
I would like to perform both these tasks in a single query, is there some kind of AND ? to chain multiple test criteria into a single query?......

---

Mysql, Simple Table Join - How To Loop Through Records
I've been gradually learning and using PHP for about a year and I've now decided to start learning MySQL

I've got my first database up and running, and I can display records, edit/delete/search and sort records from that database. But I want to make things a bit more complicated and start making related tables.

I've decided to re-invent the wheel and make a very simple content management system for myself, just to see if I can.

I have a table called posts, which is what I enter my table content into, consisting of headline, creation date, post text and an id field.

I've also set up a table called comments which will allow users to add comments to my posts. In the comments table there's a field called id_post - which is the id of the post that the comment relates to in the posts table

I've already got my loop set up to loop through my posts records, but I'm confused about how I go through looping to get the comments records.

How do I do the loop?

I thought about doing an SQL query to the comments table nested inside my loop through my posts results

SELECT * FROM comments WHERE id_post='$id' ORDER BY stampcreate


But I assume this isn't the most efficient way of doing things....

---

Java Code Or Pseudo Code For "Outer Join"
I want to implement the "outer join" functionality in Java. Can
somebody explain the pseudo code for the same. OR what needs to be done
to extend the hash-join Java code of equijoin.

---

Outer Joins
I can´t figure out how to create the following SQL

select a.folio, a.tipo, a.date
from solic a, order b
where a.id = b.id_sdc and b.tipo!=399 and b.tipo!=398

so far so good
besides, I want the rows from table a with no match in table b

select a.folio, a.tipo, a.date
from solic a, order b
where (a.id = b.id_sdc and b.tipo!=399 and b.tipo!=398)
or a.id not in (select id_sdc from b)

this select does not work with the version I have. I tried using the left join but couldn´t get the right rows

---

Inner Outer Joins
i have this query

CODE
SELECT distinct u.user_id, u.user_name, u.user_email
FROM tbl_users u
inner join tbl_user_options uo on (uo.user_id = u.user_id and uo.email_id = 10)
and (CAST(date_last_sent AS DATE) IS NULL and  uo.user_noreceive is null) OR (uo.user_noreceive = 0 and CAST(date_last_sent AS DATE) <= (DATE_SUB(NOW(), INTERVAL 10 DAY)))
left outer join tbl_photos p on u.user_id = p.user_id
WHERE p.user_id is null

---

Outer Joins
is there a workaround for outer joins in mysql? i've got to tables (a,b). what i want to do is select all of a and only the first match from b.

---

Inner , Outer Joins
what is the use of left inner join, right inner join ? will you please explain me ?

---

Outer Joins Return Value
Is there a way for an OUTER JOIN statement to return a value other than NULL?

---

UNION Outer Joins
I know this returns all the records in a field, and that it is the longest way to return these records, but it is the product of 2 built statements, so there is reason behind the madness.
(

SELECT DISTINCT contact. *
FROM contact
LEFT OUTER JOIN location ON ind_id = loc_indid
WHERE loc_id IS NULL
)
UNION (

SELECT DISTINCT contact. *
FROM contact
LEFT OUTER JOIN location ON ind_id = loc_indid
WHERE loc_id IS NOT NULL
)

Bascially, the first statement selects all entries in contact which do not appear in location, and the second does the reverse.

At the moment, the two statements work independantly, but once I add the UNION statemnet, it returns an error in the string after UNION.  Where am I going wrong??

---

LEFT OUTER Is Faster Than INNER Joins?
Maybe someone can explain this to me real quick. I have two identical queries, except that the join type changed. One uses inner joins:

SELECT OrderItems.product_id AS product_id
, OrderItems.code AS product_code
FROM Orders
INNER
JOIN OrderItems
ON Orders.id = OrderItems.order_id
INNER
JOIN Products
ON OrderItems.product_id = Products.id
WHERE Orders.orderdate >= UNIX_TIMESTAMP(DATE_SUB(NOW(), INTERVAL 24 HOUR))
AND Products.active = 1
GROUP
BY OrderItems.product_id
and the other uses the basic LEFT OUTER JOIN:

SELECT OrderItems.product_id AS product_id
, OrderItems.code AS product_code
FROM Orders
LEFT OUTER
JOIN OrderItems
ON Orders.id = OrderItems.order_id
LEFT OUTER
JOIN Products
ON OrderItems.product_id = Products.id
WHERE Orders.orderdate >= UNIX_TIMESTAMP(DATE_SUB(NOW(), INTERVAL 24 HOUR))
AND Products.active = 1
GROUP
BY OrderItems.product_id
When I run the two queries on the same data (using phpmyadmin), the left outer joins only take 0.12-0.13 seconds whereas the inner joins take a whopping 2.5+ seconds. I kinda thought that an inner join would be faster. I'm still bad with determining join types.... Is there a fundamental reasoning for this that I am missing?

---

Summing Two Columns From Two Left Outer Joins
I've got data from three tables. Two of them have a column that needs to be summed and displayed with the rows of the remaining table. So the raw joins of c3 and c4 from the two tables onto c1 and c2 from the third table look like this:

id c1 c2 c3 c4
1 A B 7 3
1 A B 7 8
1 A B 2 3
1 A B 2 8
And I want

id c1 c2 c3 c4
1 A B 9 11
The group by clause was working beautifully and I didn't have a problem until I threw another table into the mix (the data from c4). Now it's just summing up everything in c3 and c4 from the raw table... not particularly surprising but I'm not sure how to get around this problem

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