MYSQL :: Select From Another Table If Rows Do Or Do Not Exist

Delete Rows From Table A, Which Dont Exist In Table B (base On Column X)
I have 2 tables identically structured.

A & B

Table A, has column: Product (product code) as primary key

Table B doesn't.

Apart from that they have the exact same fields.

There's also a column: supplier

I want to

Delete * from table A, where does not exist in B (based on column: Product) & where supplier = apples

So to elaborate. Table A is my main table, but it now contains outdated products from supplier apple. Table B has the latest list of products from supplier apple. So I want to remove old products from A that supplier apple no longer makes.

mysql version 4.0.27

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Selecting Rows From One Table With A Key That Doesn't Exist In Another.
I'm trying to select rows from one table that does not have a key in another table.

For instance:

I have a hospital table with two columns, id and name.

I have a patients table with three columns, id, name, and locationid.

Now I want to find those hospitals that have no patients. So I want to get those hospitals whos id does not equal any of the locationid's in the patients table.

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How To Select Default Value If The Given Entry Doesn't Exist In Table?
user | data
----------------------
root | data1
mike | data2
default | data3
----------------------
I need to select some data from the data column for a user, which is very simple:
> select data from table where user='mike'
Problem: when a user doesn't not exist in the table, the select query has to return data for "default" user (also in the table) and I don't know how to do it. So, it should be something like this:
> select data from table where <if john exists user='john'> <else user='default'>
in the table above, user 'john' doesn't exist and this query is supposed to return 'data3' value.
I've read that "if/then", "if exists" statements are used in procedures only,

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Joins To Rows That Don't Exist
I want to join two tables together, but if the secondary table doesn't have a row that matches, I want the primary table's row to still be returned, with the values for the secondary row being their default values. How do I accomplish that?

For example:

if I have two tables:

t1: defaults:(a=0,b=0)
+---+---+
| a | b |
+---+---+
| 1 | 3 |
| 2 | 4 |
+---+---+

t2: defaults:(a=0,c=0)
+---+---+
| a | c |
+---+---+
| 1 | 7 |
| 3 | 8 |
+---+---+

I want to execute a query like:
SELECT t1.a,t1.b,t2.c FROM t1 JOIN t2 USING(a)

But I want the result set to be
+---+---+---+
| a | b | c |
+---+---+---+
| 1 | 3 | 7 |
| 2 | 4 | 0 |
+---+---+---+

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Incrementing Rows That May Not Exist
I'm sure there's a very simple solution to this, I just haven't been able to find one I understand yet.

I have a table with 3 columns, the first two are used as an index, and the third is a counter. So far so good:

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Why Does The Slow Query Log Show More Rows Than Exist?
# Time: 070528 17:14:57
# User@Host: counter[counter] @ localhost []
# Query_time: 3 Lock_time: 0 Rows_sent: 7 Rows_examined: 120647
SELECT SQL_CACHE `webpageUrl`, `webpageName`, COUNT(*) AS `count`, (COUNT(*) / (SELECT COUNT(*) FROM _1_log)) AS `pct` FROM _1_log GROUP BY `webpageUrl` ORDER BY `count` DESC LIMIT 7;

mysql> select count(*) from _1_log;
+----------+
| count(*) |
+----------+
| 111824 |
+----------+
1 row in set (0.00 sec)

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What Query To Check If Any Rows Exist Satisfying WHERE Clause?
I'm looking for a query that will check if any rows exists in a table according to a WHERE condition. I know I can use COUNT(*) but then mysql will do unnecessary task of counting all the rows whereas I just need true or false. So far I did this:

SELECT COUNT(*) AS exists FROM mytable WHERE ...
Sometimes I just select the first row and check later in php how many rows have been returned:

SELECT some_col FROM mytable WHERE ... LIMIT 1
But I cannot do this check (or can I?) in sql alone and I have problems when I want to use this in a subquery, for example:

SELECT id,
name,
(SELECT COUNT(*) FROM mytable WHERE ...) AS exists
FROM othertable
WHERE surname='xxx'
Can I do the same without using COUNT(*)? I would like a query that returns 0 or NULL if no rows were found, or 1 (or some other value) if 1 or more rows were found.

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Select Rows Not In Second Table
I want to select all records in a "User" table that are not in the "Groups" Table.

Select
users.USERID,
users.NAME
From
users
Outer Join groupmembers ON users.USERID = groupmembers.empid
Where
groupmembers.groupid <> '9'

In therory this would return me all users not in group 9, but I am getting an error in my SQL... I dont really understand Left - Right - and Outer joins but I have tried all three... I could do this in 3 queries - Create a Temp Table - Delete Records w/ 9 in group ID ... Select remaing records.... But there must be a better way...

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Select Every 3 Rows From A Table.
I have a bit of a problem, Iam doing a match results page with data from mysql.

My table Name: JuniorMatchResults

Data Colums: id, date, venue, position (1,2 or 3), weight.

What i wanto to do is output this information in my website such as you would have the 1st 3 positions outputted in a table, the the next set of 3 in a table and so on.

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Select Double Rows In One Table In One Query
I try to select double rows in the same table within one query. I can do it with 2 query's but i wonder if it's possible with one?

The table 'admin_category:

Quote:
id name sub
1 cd 0
2 dvd 0
3 action 1
4 new 1
5 general 2

The current query which i use:

PHP Code:

Â SELECTÂ a.nameÂ ASÂ sub,Â b.nameÂ ASÂ category
FROMÂ admin_categoryÂ a
LEFTÂ JOINÂ admin_categoryÂ bÂ ONÂ a.subÂ =Â b.id
WHEREÂ a.idÂ =Â '4'Â

What i try to reach with above query is that row 4 will be selected, take the name of it (new) and also the main category (b.name as category) by doing a left join on the same table where the sub id = the id.

The output of above query is:

sub = new
category = NULL

(Category should be 'cd' but it's not)

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Select Rows From One Table Which Not Exists In Antoher
How do I select functions that website with website_id = 1 doesn't have.

The correct answer will be function_id = 4 since functions_to_websites contains function_id = 1 to 3 for website_id = 1

And if I add another row in functions which is not mentioned in functions to websites it should be returned aswell. Code:

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Select Rows Where A Field Value Exists In Another Table
I have a table with a column of email addresses I have a second table with a column of email addresses I want to select all the rows in the first table whose email value exists in the second table Can't get a query to do this without an error,

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Select Based On Two Rows In Mapping Table
I have a many to many relationship between a resource and tag:

resource - 1:M - tagged_resource - M:1 - tag

So a resource can have many tags and a tag can belong to many resources. The data would look like this:

RESOURCE TABLE
id: 1
name: resource1

TAG TABLE
id: 1
tag: new
id: 2
tag: tested

TAGGED_RESOURCE
resourceID: 1
tagID: 1
resourceID: 1
tagID: 2

How can I select the single row from the RESOURCE TABLE which has the tags 'new' and 'tested' in the TAGGED_RESOURCE TABLE?

I have tried using 'IN' but it acts like an OR operator rather than AND.

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Select Where Exist
I have this tables:

category (id,name)
message (id,text,category_id)

I need a query like this :

insert into message set text='mytext',cid='$cid' where "cid exist in category"

I need some thing like this "cid exist in category"

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How To Insert If A Value Does Not Exist And Select If It Does?
Basically, I am doing a users table with an ID and a name for now.

I want to create a stored function that returns the ID of a user and creates the user if it does not already exist.

The way I do it for now is:

Select the user record by name.
If we had one, return its ID.
If not, insert a new user record and return its ID.

But I am worried about concurrency. What if another thread runs the same function while this one is between steps 2 and 3? TWO user records would be created for the same user. That would be bad.

I added a UNIQUE index to the username, but this means that the stored function will just error in a case like this, instead of returning the already existing user. This is also undesirable.

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SELECT, If Not Exist, INSERT
1) SELECT ID WHERE pageurl='...' LIMIT 1;
2) if(ID is empty):
INSERT INTO ... (pageurl) VALUES ('...');
ID=mysql_last_insert_id();

Is there a more efficient way of doing this?

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Adding Missing Rows In Table In 1 Select (+ Join) Command.
Hi all! Here's what I need to do :

I have two tables :
A B
a b c d
---- ----
1 z 1 k
2 x 5 l
3 c 6 j

I need a SELECT with JOIN that would give me :
A
a b
----
1 z
2 x
3 c
5 NULL
6 NULL

so I need to add the missing rows from the A.a and B.c JOIN,
how can I do that ?

I can't use a Union 'cause I can't use MySQL version 4.

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Applying A WHERE Clause To Several Rows On A Joined Table To Select A Single Row
I have one table which is users for example

id | username

and another table called ratings for example

user_id | title | rating

and I want to select users who have rated more than one thing... I can do this easily if I want to select users who have rated just one title using the following query

SQL Code:
SELECT * FROM users INNER JOIN ratings ON users.id = ratings.user_id WHERE ratings.title="blah" GROUP BY users.id

but cannot think of a way to do this for more than one rating. Doing

SQL Code:
SELECT * FROM users INNER JOIN ratings ON users.id = ratings.user_id WHERE ratings.title="blah" AND ratings.title="blahblah" GROUP BY users.id

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SELECT JOIN Where A Record Doesn't Exist
I have two tables. A company table and a table with a list of modules that links to the company table.

I have had think about this but not come up with any sort of solutions. How to I select all companys where a company module record doesn't exist.

i.e.
Company1 module1 module2
Company2 module1 module2
Company3 module1 module2
Company4 module1 module3

So how would I select only Company4 where there is no module2. Please note there is many to one relationship between company and module, i.e many module to 1 company.

If I use something like
SELECT * FROM company, modulelist WHERE modulelist.module!=module2 it doesn't appear to work.

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Select Values For A Column That Doesn't Exist
have two tables of data:

a,b,c

and you have a new table that has all the original columns as the first table, plus a new column:

a,b,c, d

let's say that there is no data that currently exists for column d.

Is there a way that I can specify a single value on my select query of the first table (a,b,c) that creates a result set that has a default value and a d column (a,b,c, d=0)?

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Does The Table Exist
iam developing a servlet for accessing a database (iam using MySql database),
and iam wondering, how do i know if i have a certain table in thr database or not!!!
i mean how can i check if i have a certain table in the database!!! abf if dont have it, what is the error msg that i receive, so i can handel the situation !

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Delete If Table Exist
I would like to delete rows only if table exist to prevents errors.

Also I would like to add column only if it doesn't already exist.

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Check If Table Is Exist Or Not
May this question exist....But i confused...I want to check whether the table is exist or not ....

Like i run a project , on that project i create a mysql tables while run time.... on that i want to chech a table is exist or not...

if employee table is exist ....

exit;

else

create table employee

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Does Table Exist Code?
I ran across this code to check if a table exists. I'm thinking there has to be a better way...maybe something like DoesTableExist("MyTable") = true or false.

Comments?

global $exists;
$exists = 0;
$dataset = mysql_query('SHOW TABLES') ;
while( $row = mysql_fetch_row($dataset) )
{
if ( $row[0] == "mos_tbd_tags" ) {
$exists = 1;
break;
}
}

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1146 Table Db.1 Does Not Exist..
Create a table in MySQL v5 using MySQL Control Center. When I try to open it, it opens OK but complains that a table (db.1) does not exist. I KNOW it doesn't exist. I DON'T WANT it to exist. I frankly couldn't care too hoots about not finding a table that I don't want and doesn't exist, so WHY must MySQL insist on telling me a non-existant table doesn't exist?

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UNION Of Table That Doesn't Exist
SQL Statement A:
select fileid from tbl_MetaData_200809

SQL Statement B:
select fileid from tbl_MetaData_200810

Result of Statement A results in:
+--------+
| fileid |
+--------+
| 1 |
+--------+
1 row in set (0.00 sec)

Result of Statement B results in:
ERROR 1146 (42S02): Table 'archive.tbl_MetaData_200810' doesn't exist

But, (SQL Statement A) UNION (SQL Statement B) also results in:
ERROR 1146 (42S02): Table 'archive.tbl_MetaData_200810' doesn't exist

What are my options here, execute the UNION statement and test the warning message and exclude table that doesn't exist and re-run command?

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Error: Table Does't Exist
I have just installed the MySQL 5 beta. I am getting a strange error.

I have a database names UDI with a table called test. The test table has 2 fields ID which is an autoinc field/int(10) unsigned/Primary Key, and Data which is an nvarchar(100) field.
When I enter the select statement:

select * from test

The error window displays the error message:

ERROR 1146: Table 'udi.1' does not exist.

Although I get the error, the result set is returned.Why is MySQLCC giving me the error ?

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Temporary Table Does Not Exist
I've had this code running for over a year and now, all of a sudden, it no longer works.
I'm using PHP and MySQL 3.23.58 which my host provides. Code:

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Selecting Ids From One Table That Don't Exist In Another
I have 2 tables, they are both linked together and my life would be so much easier if they were just one big table, but they're not They have a one-to-one relationship between them and I need to find out the records in table 1 which don't have corressponding values in table 2. How can I do this?

SELECT id FROM table1 WHERE id NOT IN table2
Will that do it?

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Table Doesn't Exist ERROR
I'm getting a "Table doesn't exist" error. The name of the table is "sitesearch"
But the table does exist! Strange...

So I executed :

mysql
SHOW TABLES

...and used PHP var_dump() to output the array fetched. The var_dump() gave me this :

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Error 1146: Table Does Not Exist
OS XP Pro SP2
MYSQL Ver: 5.0.0-alpha nt

Whenever I view a table or run a query in the Control Center (0.9.4-beta) I
get the following error:

[ShipNet] ERROR 1146: Table 'shipnet.1' doesn't exist

table shipnet.1 indeed does not exist but I can't understand why it's
looking for it. Any ideas?

FYI coincidently shipnet1 is the name of my computer.

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Table Doesn't Exist After Renaming Database
I have renamed my database from songsdb to songs by renaming the folder under MySQLMySQL Server 5.0datasongsdb to songs (stopped the server before doing so). Now when I restart, I see songs database, show tables shows all tables, but desc command gives error: ERROR 1146 (42S02): Table 'songs.djs' doesn't exist!

Whatelse am I to change to recognize these tables? I'm using 5.0.16-nt version on Windows XP.

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Error 1146 Table Doesn't Exist
I made a backup of my db with 11 tables. I made some tests with the original tables, like delete data from some. After the tests I copied and pasted the backup to the original place. Now when I command: use mydatabase; Mysql goes ok. When I command: show tables; Mysql shows me the eleven tables in the db. But when I command:

select * from my table; Mysql returns to me the following message ERROR 1146 (42S02):

Table 'mydatabase.mytable' doesn't exist
What can I do to fix the problem?

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Table 'test.event' Doesn't Exist
I'm evaluating MySQL 5.0.37-community-nt MySQL Community Edition (GPL).
For some reason I get this error. I don't recall doing anything in particular to cause this to happen. I can see the table in with the show tables; command. However, I can't select from it, insert into it or drop the table.
Can anyone tell me what caused this and how to correct it?

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Mysqlorary Table Created But Doesn't Exist?
I am trying to create a mysqlorary table with:

CREATE mysqlORARY TABLE t2 SELECT col1 as col2 FROM t1;

This appears to work, but when I then run a

'SELECT * FROM t2' query I get told that t2 doesn't exist. What I am I doing wrong?

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Prevent Values That Do Not Exist In Another Table
products
manufacturer
category

Example:

CREATE TABLE categories (category_ID int(6) AUTO_INCREMENT NOT NULL PRIMARY KEY, category_Name varchar(25));

CREATE TABLE products (product_ID int(6) AUTO_INCREMENT NOT NULL PRIMARY KEY, product_Name varchar(30), quantity varchar(10), price float(5,2), category int(6), manufacturer int(6));

CREATE TABLE manufacturer (manufacturer_ID int(6) AUTO_INCREMENT NOT NULL PRIMARY KEY, manufacturer_Name varchar(30));

mysql> select * from products; select * from categories; select * from manufacturer; .....

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Only Showing Records That Do Not Exist In Another Table
How do I show a listing of all records within one table that do not exist within a second table?

For example:

Table A
----------
apple
orange
pineapple
banana

Table B
----------
orange
cherry
lime
banana

I want all records in A that do not exist within B to show. thus I should have the results of:

apple
pineapple

What would my sql statement be if my column name was "fruit"?

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Insert Values Only If They Do Not Already Exist In Table
I want to insert some values from one table (A) into another table (b). However there are some values in table A which exist two times in table A. I only want to insert values one time. So If a certain field value also exist in some other row (same fieldname) then I don't want to insert it twice. It doesn't matter which of the two rows will be inserted.

Can this be done with MySQL? Maybe with some Control Flow Functions?

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Insert No Duplicates And Only If Not Already Exist In Other Table
is there a way to combine these two querie in one query?

I want to do this both:

SELECT *
FROM inventimport WHERE PC_volgnr NOT IN (SELECT dev_volgnr FROM dev) AND PC_volgnr <> 'geen pc aan' Order by inv_id

AND

SELECT DISTINCT PC_volgnr
FROM inventimport

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Table 'mysql.host' Doesn't Exist
Working with mySQL 3.23.58 on Linux, I get this error when trying to start mysqld:
--------------------
060716 03:07:21 mysqld started
060716 03:07:21 /usr/local/mysql/libexec/mysqld: Table 'mysql.host' doesn't exist
060716 03:07:21 mysqld ended
---------------------

This Linux machine has been working ok for months, and it stopped suddenly.

I don't've any idea about how to fix it, and I don't find any '/etc/my.conf' file
into this machine. The install directory is '/usr/local/mysql'.

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#1146 - Table 'inhous1_demo1.Admins' Doesn't Exist
i have table 'admins' in database. when i execute query like----->

-->SELECT *FROM `admins`;
i got result.
but
when i write query like---->
---> SELECT *FROM `Admins`;
i got error #1146 - Table 'inhous1_demo1.Admins' doesn't exist .

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[ERROR] Table Mysql.servers Does Not Exist
have installed WAMP 2.0 and everything seems to work fine. I am learning PHP and MySQL. I am also using hMail server to send mail. Everytime I try to send an email using a PHP script I get the following message (Error querying database). This is what I get in the MySQL Log:

090218 16:50:35 InnoDB: Started; log sequence number 0 46409
090218 16:50:35 [ERROR] Can't open and lock privilege tables: Table 'mysql.servers' doesn't exist
090218 16:50:35 [ERROR] Incorrect definition of table mysql.event: expected column 'sql_mode' at position 14 to have type

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Mysql Table Doed Not Exist Problem
I am trying to "select" from a mysql table called "quiz".

I can execute the query successfully from command prompt.
select * from quiz;

but using JDBC, I am getting error
Table 'mysql.quiz' doesn't exist

Can anyone tell me why it is accessing "mysql.quiz" instead of "quiz".
what should i do now to tell mysql to look into quiz instead of "mysql.quiz".

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If Record Exist In 2 Tables, Use Column Of Table B
I have 2 tables A and B...
Table A: A_id, field1, field2, ..., status
Table B: B_id, A_id,..., status

I need to select all info from table A. And if a record exist in table B, i need to use the status value of that table instead of the one in table A.

Im not sure how to do it...with EXISTS or CASE?

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#1146 Table 'mysql.user' Doesn't Exist
I am really frustrated, I am trying to learn MYSQL and I can't even create a freaking username. I am trying with the following command ( I googled it):

CREATE USER 'user1'@'localhost' IDENTIFIED BY 'pass1';
I created the database mysql. It comes out with the error when I typed that line:

#1146 - Table 'mysql.user' doesn't exist

Why is it coming up with that error? All I want is create a username for the table mysql. I tried that in both phpmyadmin, and mysql console command.

I am using WAMP 2.0 on my Windows XP computer.

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ERROR 1146 (42S02): Table 'spnau_dev.spde_user' Doesn't Exist
I used the migration tools try to migrate tables. There are a table can't be create because of the constraint. I fixed it and create the table under the schema and then continue the migration. After migration completed and when I select, drop the table, I got this error. when I drop the schema, I also got the error.

ERROR 1146 (42S02): Table 'spnau_dev.spde_user' doesn't exist

This table is innodb type. we are using version 5.0.27-standard.

when I show table in the schema, I can see the table.

in the information_schema.table. I saw the table. But the information is all not right.

'', 'spnau_dev', 'spde_user', 'BASE TABLE', '', , '', , , , , , , , '', '', '', '', , '', 'Table 'spnau_dev.spde_user' doesn't exist'

Can someone help me on this ?

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DROP TABLE IF EXISTS Tablename - Error If Talbe Doesn't Really Exist
I'm working on e program which is using some mysqlorary tables.
In certain processes it's necessary to drop some of them.
For that purpose I use

DROP TABLE IF EXISTS foo

If I execute the command, while there is no table named 'foo' I get the following error:

Unknown table 'foo'.

If I understood the manual right 'IF EXISTS' should prevent me from getting such an error?

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SELECT Rows With Field Different From Previous Rows
I have a table (sens_samples) with mysqlerature sensor samples taken every 5 minutes. Rows are: id (INT), sensor_id (INT), timestamp (DATETIME), mysql(FLOAT) and over_mysql(BOOL).

I want to make a query to get ONLY the rows when over_mysql field changed from "previous" row value. I know that database rows are UNORDERED, but ORDER BY can "place" them in a given order.

My query may be "syntactically" something like: SELECT timestamp, mysql FROM sens_samples WHERE "PREV_ROW".over_mysql <> over_mysql AND sens_id = 1 ORDER BY id;

How can I get it using MySQL?

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Fatal Error: Can't Open Privilege Tables: Table 'mysql.host' Doesn't Exist
When I start the MySQL server it gets stopped immediately logging the following error.
050607 15:27:43 InnoDB: Started
050607 15:27:43 Fatal error: Can't open privilege tables: Table 'mysql.host' doesn't exist
050607 15:27:43 Aborting

050607 15:27:43 InnoDB: Starting shutdown...
050607 15:27:45 InnoDB: Shutdown completed

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Don't Select Rows That Match Both Columns But DO Select Rows That Don't Match Both
I suppose it is because it is 2:30 AM but I'm having a bit of trouble figuring out the SQL I need to write. I am usually pretty good at this. Here's what I'm having trouble with.

My app includes a Poll system built from scratch. Each question will run for one month. the month that the poll will run is kept in 2 columns in my table... runMonth and runYear.

What i'm having trouble doing is selecting the rows that don't match both the current runMonth and current runYear.

My Table...

id.............Question...........runMonth...........runYear
1..............QA...................1......................2007
2..............QB...................2......................2007
3..............QC...................3......................2007
4..............QD...................4......................2007 (current month and year)
5..............QE...................5......................2007
6..............QF...................6......................2007

I can simply get the question for the current month...

SELECT * FROM table WHERE runMonth = 4 AND runYear = 2007;
but if I try to get all others using

SELECT * FROM table WHERE runMonth != 4 AND runYear != 2007
I get an empty result set. As I should because there is nothing there that the runYear != 2007 doesn't knock out. The result set I am looking for is

id.............Question...........runMonth...........runYear
1..............QA...................1......................2007
2..............QB...................2......................2007
3..............QC...................3......................2007
*********************(remove runMonth4 and runYear 2007)
5..............QE...................5......................2007
6..............QF...................6......................2007

What am I missing?

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Select From Another Table If Rows Do Or Do Not Exist

Here is my statement so far: ....