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Update Statement Not Working On Server


this works on my machine but not where my site is hosted. They do use an older version of mysql could that be problem

update inv, newprice set inv.cost = newprice.price where inv.itemcode = newprice.itemcode

works fine on my machine her ebut on server i get error..




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Related Forum Messages:
Update Statement Not Working
Why does this simple update statement not work with a mysql version 3.23.49,
it does work when using 4.0.24..... ?

UPDATE listitem,vjbase,list SET listitem.showsec = 7 WHERE listitem.id_vjbase = vjbase.vjbase_id AND listitem.id_vjbase = 3 AND vjbase.id_viduser = 61000 AND listitem.id_list = list.list_id AND listitem.id_list = 1 AND list.id_viduser = 61000

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2 Table SELECT DISTINCT Statement Not Working
I have 2 tables:

1. plus
2. not_plus

Both have a field in common:

region

And all the other fields are different.

What I need to do is distinctly select all of the different regions from both tables and then display them in a drop down menu.

HTML and the PHP is easy and the dropdown is there

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UPDATE Not Working.
The page that sends information to the following page has a series of text inputs. The name of the input corresponds to the name of the column in the in the mysql table. There's also a hidden input, "id", that supplies the unique id number of the entry.

My script to enter data into the table and to view the table work fine. The update script runs without any errors, but doesn't alter any values. I also tried printing the value of $query and everything appears to be fine. Anyone know why this is happening? Code:

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Update And Select Not Working
an update that doesn't affect any records. As a test, I switched it to a Select statement. Both statements have the same where clause. The select statement returns the number of rows I expected to update. Here are both queries. Any help greatly appreciated.

UPDATE program_event set measure=239, measure_date='2007-01-25' WHERE program_goal_id = 112 AND measure_date >= '2007-01-22' AND measure_date < '2007-01-27'

select * from program_event WHERE program_goal_id = 112 AND measure_date >= '2007-01-22' AND measure_date < '2007-01-27'

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Update Field Isn't Working?
I've created a MySQL database that has one table, that table has two fields, the table is called system, the fields are called status and message. The database is used to populate a html table on a page, that works fine.

What I need to do though is have a form on a separate page (which i'm going to add http authentication to) with a simply form consisting of a text box, three radio buttons, and the usualy submit and reset buttons. I need to be able to update the database using this simple form.

However this isn't for adding new records, it is purely for editing the existing record as it's to edit simple warning messages to display to the visitors when there is a problem with one of the systems. The radio buttons determine which light image is displayed (green, orange, red) and the text box for the short message.

However no matter what i try it just in't updating the fields in the database, the following is the html and PHP i'm using: Code:

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AUTO_INCREMENT Not Working After Mysql Update
I have a database set up on one server and am trying to import it to another.

The working one is using 5.0.24 and the one I want to import to is using 4.0.27-standard.

I get this error on the first table:

#1064 - You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near 'DEFAULT CHARSET=latin1 AUTO_INCREMENT=3' at line 6

Is this something to do with the way AUTO_INCREMENT is specified in version 5 and is there a way to change it for version 4? If there is a simple fix for this I would appreciate a heads up if not, looks like I'll have to get the programmers in again!

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Update Not Working Within A Stored Procedure
The following query works, but not within a stored procedure, any tips?

update
ATable,BTable
set ATable.lbl= BTable.lbl, ATable.Status = "0", ATable.Code = BTable.code
where

(ATable.ID = BTable.Tapelbl)

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Update Query Not Working: SQL Error
i'm trying to do an update such as ...

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Simple Update Just Not Working /banghead
Background: I've been around the web for quite some time, but am new to PHP/MySQL. I recently purchased a zip code database for an upcoming project I'm starting here, and for some reason the CSV format turned all the zipcodes that start with a zero into 4 digits. No biggie, after hours of wrestling with cpanel MySQL import, then giving up and moving on to modifying the bigdump script I FINALLY got the import done. Now I'm trying to correct the 4 digit zip codes back into 5 digit ones.

Table name is ZipCodes, column name is ZipCode (is varchar(5) column). Here's the code I'm trying to use to update things, but it just does not perform the update for some reason.

update ZipCodes set ZipCode = &#390;' + ZipCode where char_length(ZipCode) = 4;
I've spent a few hours now reading up trying to figure out what the hell I'm doing wrong, but to no avail. I'm sure the fact that I'm a newb at MySQL isn't helping, but is it something obvious that I'm just to dumb to see at this point?

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Server Distribution Not Working
I am not able to get MYSQL running on Suse Linux Enterprise Server.

I tried stopping with the command mysqld and it reported, "Shtudown
Complete." Then when I tried to restart it with the command, "mysqld
–user=root" I get the response "mysql.host" doesn't exist. If I try
"mysqld – user=mysql", I get numerous errors.

I installed Suse Linux Enterprise Server 8 from CDROM and included all
options. I saw the MYSQL is part of the distribution so I assumed it
was set up properly. Apparently, that is not the case. I tried to
uninstall just the MYSQL and downloaded the MYSQL from the MYSQL web
site and tried to reinstall it according to the documentation but
found the SUSE Linux uninstall did not uninstall everything because I
kept getting error messages about conflicts between the MYSQL version
leftover stuff from the SUSE distribution and the newer version I
donwloded from the MYSQL site. I tried to manually delete everyting I
could but to no avail.

I gave up and reinstalled the whole SUSE Linux distribution. The very
first thing I did after the installation was complete was to try to
issue a mysql command as root and got the following:
"ERROR 2002: Can't connect to local MySQL server through socket
'/var/lib/mysql/mysql.sock' (2)"

Obviously, something is not quite right on my SUSE Linux distribution.

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Server Has Gone Away (inc. Package Size Not Working)
I'm brand brand new to MySQL, and my first order of business is to import some larger files into a database. The file is 20 megs, though I do have files I want to include that near a gig (987mb to be exact).

This is my problem:

C:Program FilesMySQLMySQL Server 5.0>mysql -u root -p xmapprobedata < probese
t.sql
Enter password: *******
ERROR 2006 (HY000) at line 1: MySQL server has gone away

I'm doing this locally so its not a time-out/connection issue. The standard protocol online to fix this problem is to increase the package size. I went into my.ini and added "max_allowed_packet=999M" to both the client and server sections. The error persists.

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BLOBS Not Working On Windows Server 2003
I have been using Windows Server 2003 to host my own websites, last weekend I finally gathered courage enough to install linux mandrake 10.1 instead. After tow painfull but rewarding days I finally installed everything and was up and running in a LAMP config, sice I developed all of my sites in WAMP everything was ok...

BUT BLOBS ARE NOT WORKING AS THEY ARE SUPOSSED TO...

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Mysqldump Server Becomes Busy For Longer Time And Site Stops Working
When I'm making a backup of mysql databases, during the dump apache is unable to load pages because mysql is no longer responding to new requests.

The backup is taking 5 minutes or so, which essentially brings down the website until it's finished. Has anyone got any suggestions on how to overcome this problem?

I'm thinking maybe if I could quickly make a copy of the database to another database within mysql, then backup the copy that was just made.

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SQL-Update-Statement
I have to update all UA-fields in the table idrz_kennzahl with primary
key idrz, where the same idrz in the table per_verwaltung with the
field Amt=12 is.I designed following statement but it doesn't work:

update idrz_kennzahl
set UA=1234
where
idrz_kennzahl.idrz =(SELECT per_verwaltung.idrz from per_verwaltung where
per_verwaltung.Amt=12

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Update With If Statement
I'm trying a statement which I cannot figure out what I'm doing wrong on. I've tried every combination that I can think of and stared myself blue with no success.

update cdr set Cost=if(mod(BillSec,6)=0,int(BillSec/6),int(BillSec/6)+1)

The idea is to update Cost with a value depending on the result of a formula. It's an empty field which gets a computed value from other fields. cdr is the table.

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Update Statement
I am currently updating a table and increasing a column value by 1, the problem is that he don't increase 1 but it does increase the double of the value specified.
Why does it performs the update like this? And how can i solve this problem?

SQL Statement Syntax used: UPDATE table_name SET column_name=column_name+1 WHERE id=1

Version of MySQL: 4.1.7 for Windows installed in Windows 2003 Server.

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What Would This Update Statement Be?
I have an array of ids formatted like 1,2,3,4,5

I have a table where there is a field that selects maybe a few of those ids, and is formatted like this: 1,3,5

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Long Old UPDATE Statement
I have the following SQL which gives me the row Im after

SELECT *
FROM staff, staffemails
WHERE staff.users_username='$user'
and staff.staff_id = staffemails.staff_id

thing is I now want to perform an update on the result of this query. Ive tried

UPDATE staffemails
SET is_registered ='0'
WHERE staff.users_username = '$user'
and staffemails.staff_id = staff.staff_id .

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Select And Update Statement
Is it possible to combine a select and update statement in mysql? If
so, what is the syntax.

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UPDATE Statement Doesn't Work
TABLE - abc

ID NAME
___________
1 hello
12 abc


UPDATE `abc` SET `ID`='5' AND `NAME`='hello' WHERE `ID`='1' AND `NAME`='hello'

wherenver I try to update this table using above sql statement, it doesn't work. I just get "Row match:1 Changed:0" message.

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Very Slow Update Statement
I am having an issue with an UPDATE statement that takes a very long time. I am using
1 table in a schema to update another table in another schema. Below are the create statements and the update statment I am using. Table and column names have been changed to protect the innocent :) Code:

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Special UPDATE Statement
UPDATE some_table st SET some_page_no=((select count(*) FROM some_table WHERE some_table_id<st.some_table_id and some_id=st.some_id and some_type='OK') div 10)+1 WHERE some_id=345 and some_type='OK'

I want to use the above to make a fast page index (10 on each page). I had something similar in mssql and it worked, but in myssql I get this error:

"You can't specify target table 'some_table' for update in FROM clause"

What have I done wrong or can the above simply not be done?

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UPDATE / JOIN STATEMENT
i have problems after updating mysql from 4.x to 5.0.19. This statement should update about 3000 rows but it only does 15 but there are definitely another 2000 rows with an older date and matching nr!

UPDATE tab1,tab2
SET tab2.newdate = NOW()
WHERE tab1.nr=tab2.nr;

I tried the variation with inner joining tab1 as well. same result.
Does anyone has an idea solving this problem? Perhaps it´s a bug?

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Select + Update In One Statement
I have these statements.

$selectdata = "SELECT * FROM imagetrack WHERE fimsid = ".$_GET["fimsid"]." AND name = '".$_GET["service"] . "'";

$query = mysql_query($selectdata) or die(mysql_error());
$update = "UPDATE imagetrack SET seen = seen+1 WHERE fimsid = ".$_GET["fimsid"]." AND name = '".$_GET["service"] . "'";

Basically i was wondering if there was a statement where i can select everything and update the seen in one statement.

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Conditions In UPDATE Statement
i have some data to be updated in a specific row - WHERE id=1

data:
$min_time, $max_time, $time, $attempts

so, i would like to calculate new avg and replace min_time with new value, if new min_time is smaller then that one stored in the database.

"UPDATE mytable SET
avg=(avg*attempts+$time) DEV (attempts+1),
min_time=**here i could use help** ??IF(min_time>$min_time)$min_time ELSE min_time??
**and similar with max_time .

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Update Statement Problem? Plz Help.
I've a simple doubt of whether can or can't i update two tables by using joins as below. the below update statement matched 2 rows one each for two tables but didn't update.

mysql> update audio join pcr_info on audio.audio_sid=pcr_info.pcr_sid set audio.
audio_pid=4896,audio.audio_prgm_num=3,audio.audio_type="MPEGLayer1",audio.audio_
sr=44.1,audio.audio_mode="1_0",audio.audio_bitrate=320,pcr_info.pcr_pid=49 where
pcr_info.pcr_prgm_num=3 and pcr_info.pcr_sid="2501" and audio.audio_pid=4896 an
d pcr_info.pcr_pid=49;
Query OK, 0 rows affected (0.00 sec)
Rows matched: 2 Changed: 0 Warnings: 0

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DELETE,UPDATE Or Other Statement In WHERE
I would like to let my admins write WHERE statements. . In panel where you can see all users of my site, admin should have input where he can put some filters in WHERE statment. E.G. standard query is
SELECT login FROM USERS .
and admin would write age > 18 and male = 'f'
. php script would conact it and it would execute
SELECT login FROM users WHERE age > 18 and male = 'f'
I have question about security of this solution. Is possible to put in WHERE statement sobe dangeurous statemetns like DELETE of UPDATE?

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Conditional Update Statement
I have a table with a field of ID numbers. I want to update this field and replace the ID numbers. For example I want every record that currently has the ID number 2,5,6,or 9 to be replaced with a 1. Every record with 1 or 4 to be replaced with 2 ...

I can't seem to form the update statement to do this. I can do them one at a time but this won't work because if I change 2,5,6, and 9 to 1 then when I run then update for 1 and 4 it will change them all. Does this make any sense?

I want some way to be able to use a condition...if id=2 or 4 or 6 set it to 1 and if id= 1 or 4 set it to 2.

My failed attempt:

mysql> update client_software set software_id=1
WHERE (software_id=2 or software_id=5 or software_id=6 or software_id=9)
AND software_id=2 WHERE (software_id=3 or software_id=7 or software_id=8)
AND software_id=3 WHERE (software_id=1 or software_id=4);

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Insert Or Update In One Statement
I sometimes find myself writing PHP code that checks for a value in a table and updates it with a new value if it exists, or insert it into the table if it doesnt. Is there any way to do this with one sql statement?

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Conditional Update Statement
MySQL Code:
UPDATE     tournamentsSET     tournament_player1 = IF (tournament_player1 = 5, 1, 0),  
    tournament_player2 = IF (tournament_player2 = 5, 1, 0), 
    tournament_player3 = IF (tournament_player3 = 5, 1, 0), 
    tournament_player4 = IF (tournament_player4 = 5, 1, 0) 
WHERE    tournament_time = 1 AND tournament_game = 1 ....

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Remote Access Not Working: Error 1251 Client Does Not Support Authentication Protocol Requested By Server
I'm trying to set up my MySQL database for remote access. I've never been a DB admin so this is all mostly new to me. I am binding to my public IP address, and I have created a new user with the following grant commands run from the mysql command line on the server:

mysql> grant all privileges on prs_data.* to 'username'@'%' identified by 'change';
Query OK, 0 rows affected (0.00 sec)
mysql> grant all privileges on prs_data.* to 'username'@'localhost' identified by 'change';
Query OK, 0 rows affected (0.01 sec)

When I try to connect remotely from another host, here's what happens:

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Convert SELECT Statement To UPDATE
How do I convert the following SELECT statement to UPDATE statement? If I'm not mistaken, UPDATE statement could not involve more than one table.

SELECT * FROM F0116 LEFT JOIN F0101 ON F0116.ALAN8=F0101.ABAN8 WHERE F0116.ALCTR='' AND F0101.ABMCU='1'

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How To Do EXPLAIN For DELETE/UPDATE SQL Statement?
Anyone know how to do EXPLAIN for DELETE/UPDATE SQL Statement?

cause I only can see execution plan from SELECT statement. And anyone know if there is third party software which allow me to see the UI execution plan like MSSQL Query Analyzer?

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Update Statement :: Affected Rows: 0
UPDATE `zipLocations` SET `z_zipCode` = '06001' WHERE `z_zipCode` =6001 LIMIT 1 ;

Field Type Attributes Null Default Extra Action
z_zipCode int(5) No 0
z_cityName varchar(50) No
s_stateAbbr char(2) No
z_countyName varchar(50) No
z_areaCodes varchar(50) No

I even went through phpmyadmin found the row clicked on the edit button for that row and updated it. and it still doesn't update.. im' thinking it has to do with the data type being INT...

Why doesn't it update it ?.. It says it was successful.
Affected rows: 0 (Query took 0.0002 sec)

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CASE Statement In Update Command
I'm trying to update one table (tbl_usage) based on information from another table (tbl_subscriptions) joined by the userID. The usage table tracks the number of times a user hits a page, and decrements the count each time. When the user has a zero count, they are redirected to a warning page.

Each week the count is reset depending on what type of license they have (licenseType) and how many of those licenses they've bought (numLicenses). A group license (G) gives them 100 hits, and an individual license (I) gives them 5 hits.

I'm trying to use a case statement to perform this count reset operation, but I can't seem to get it to work. The following case statement works just fine: Code:

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Convert A Nested Update Statement
i have a nested update statement in my sql server as follows
UPDATE DIM_EVENT .

SET INVOICE_AMOUNT =
(SELECT SUM(INV.INVOICE_AMOUNT_TOTAL)
FROM INVOICE INV
WHERE INV.INVOICE_REFERENCE_NUMBER = DIM_EVENT.OBJECT_ID
AND INV.INVOICE_AMOUNT_TOTAL IS NOT NULL)
WHERE DIM_EVENT.EVENT_TYPE_CODE IN ('OFULN', 'OAUTH', 'CRDRL');
what is the equivalent in MySQL.

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Update Statement :: Data From One Table To Other
I have two tables, and I want to take data from one table, and overwrite it onto the second. Unfortunately, my SQL is pretty weak.

The first table has a mediumtext column and a id (primary key) column. The second has an id (the same as the first), a number, and a mediumtext column.

I want to take the contents of the mediumtext field with the highest number and replace the contents of the field in the first column with it with the same id.

My instinct is to do it this way:

update forum1post p
set p.pagetext = (select query1.message
from (select pe.message, max(pe.editnum)
from forum1post_edits pe
group by p.postid) query1)
where p.pagetext = 'Why did you all flame my topic. Screw your ****ing forums.'
and p.postid = pe.postid

However, that does not work, as pe is not recognized.

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Help With Simple SQL Statement To Update Zipcodes
I have a varchar(5) field in a database called 'zip_code'. I imported some zipcodes from an Excel spreadsheet, but the spreadsheet had truncated any zipcode that started with a "0" and removed the zero, so the correct zipcode of "08993" was incorrectly placed into the record as "8993".

Would someone help me write a SQL statement to run on the field zip_code that would look at the data, if it was four characters long, add a "0" to the start and keep the remaining four characters in place?

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QUERY One Table And Update Another In ONE Statement?
ZIP_CODE:
zip_code
latitude
longitude

customers:
customer_id
...
zip_code
latitude
longitude

The lat and long in the customers table is blank. I want to lookup customers' zip code in the ZIP_CODE, get the related lat & long and update the customers table with that information. The result being that after this query is run, the customers table now has lat & long data.

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Identify Columns Changed By Update Statement
It says in the documentation that "If you set a column to the value it currently has, MySQL notices this and does not update it." is there anyway to identify what column values have changed? i.e. what columns have been updated?

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MySql Update Or Insert Statement To Modify A Word In All Caps
I have a field in my database called Subtopic. In this field I have a word LITERATURE in all caps. I need to change the word LITERATURE to LITERATURE followed by a colon then an empty space. Can someone give me the MySql statement I can paste into phpMyAdmin to make this change? Note: The Subtopic field contains the word "literature" but not in all caps because the Subtopic field is part the database that is an encyclopedia. Therefore, I want to change ONLY the word LITERATURE if the word LITERATURE is in all caps.

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Working SELECT Query Not Working With INSERT
SELECT
IF (column_1 > 0,column_1,NULL)
from table_1;

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Linux Server V/s Windows Server ( WebServer - LAMP V/s WAMP)
My client wants to use WAMP ( Windows + apache + MySQL + PHP ). But the
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I have seen some benchmark details on internet. But still they are not
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Allmost all the search done on google melts down to IIS vs Apache, My
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Reg MySQL Server Work As Local Network Or Remote Server
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