PHP :: 2 Drop Down List Where Need Query Database

Displaying Data From Mysql Database In A Drop Down List On Form.
I'm trying to do is display data from two different mysql tables from the same database in a drop down list on a html form. I have a fixtures table with the player1(userid), player2(userid), gameid, game, score1 and 2, what I want is to use the userid to get the players first name and surname from the members table (as it is a unique id), I need to do this bit before displaying it in the drop down. I think i need 2 querys to do this but when I have tried it it just echo's a blank value or the userid not the forname and surname that I want. I'm using the fetch_array function but just can't see where I'm going wrong, Code:

Drop Down List
I want to read a directory for available files and then get the filenames and put them in a drop down list. Whatever the user will select will be the value of the variable $selected. I already found the code to read directories: Code:

Php And Drop Down List
I am coding an email form on a site. A user enters their name and contact email and then selects from a drop down list to which particular email the message should be sent: User1, User2, User3. Then the user types out a message and hits submit. My problem is that I am unsure as to how to grab the selection in the drop down list and pull the selection and place it like this: "$selection@domain.com". Here is the php code:

Drop Down Box To A List Box
i have this drop down box that displays the relevant info from the table that its loading. But the drop down box isn't quite so wise to use if there hundreds of rows. So what i wanted to do was change it to a list box instead ... would any one know how to do that? Code:

A Dynamic Drop Down List
I need to create a dynamic drop down list. By this i mean that the webpage html form = select style will recieve all the values as based on a query to a mysql database. I have no problems quering the data base with PHP, But i need to make some kind of for loop that will add a new value to the selct form for each result from the database. my thought process go like this.

1. call data base to guery. (no problem)

2. make variable variables that will be created according to the number of results (these variables must be created according to results of query, not a problem i think)

3. make a form like this

<form action = ***** method = post>
<select name = ******>
<option value = "This is a query result"> This is a query result> //This is the part i need to using a for loop and variable variables
</select></form>

so my problem is part 3, cause is this all done in PHP, or if i had all these variables, can i do this in HTML? Can i make a for loop in PHP that would break into HTML during these parts?

2 Drop Down List Using MYSQL
I have a model table with the following fields: MODEL_ID, MAKE_ID, NAME.
And a make table with the following fields:
MAKE_ID, NAME.

The first drop down list (make) to select a make of a car i.e. Chevrolet, Ford. When a make is selected, then all the model for that paticular make appear in the second drop down list.

PHP And MYSQL Drop Down List
I need a script to create a drop down list which has vehicle makes. The vehicle make list should feed a vehicle model list so when I select a make all the models for the make appear in the model list. I have a make table which has MAKE_ID, make NAME and a model table which has MODEL_ID, MAKE_ID and model NAME.

I tried using a script using javascript array but wherever I have a query that pulls the NAME from the database there's always a carriage return after the NAME which messes up the javascript array. I'd rather do it all with PHP if possible. If not please give me one that works and I don't have to spend hours troubleshooting.

Very Simple Drop-down List...
Hi! I'm having a problem with a very simple drop-down list since the
page comes out with no elements in the drop-down but giving no errors.
This is the code:

<form name="year_search_form" method="post" action="results.php">
<select name="select_year" id="select_year">
<?
$query="SELECT * FROM table ORDER BY year";
$result = mysql_query($query) or die ("Error in query: $query. "
..mysql_error());

while ($line = mysql_fetch_array($result)) {
print ("<OPTION value=".$line['year']."></OPTION>"); }
?>
</select>
</form>

Drop Down List From An Array
I want the array to contain a valid year of birth for anyone between the ages of 16 and 80. I'm pretty sure this code is correct.(though it might be a bit sloppy to all you pros) Code:

Drop Down List With Months
I am trying to create a drop down list that has December 2006 as the first option and then goes up month and years till the current month and year (September 2007).

Putting List Into Drop Down
I am working on a directory of businesses which has 8 main categories and each category has several sub-categories. Example: Dining is a Category with Pizza, Fast Food, Chinese, etc. I have the sub-categories brought up in just a list on the left side of the page and when the user clicks on a sub-category it takes them from client_list.php to client_filter.php only showing businesses in that sub-category of the main category.

So only pizza places listed under dining. However, I want to change the list to a (form) select box and then have the user click on the sub-category they want and then it takes them to the client_filter.php page to list only those bussinesses in that sub-categorie. So after that long explanation how do I change my code to do that. Here is my current code:

Insert From An Drop-down List
i have a table in wich i've inserted city's name.then i have an registration form in wich i want to display an dropdown list with the cities from the table, and if one city is selected to be automaticly added in the second table. how can i do that?

Custom Drop Down List
I am trying to get categories from the database and show them in a drop down list showing root category then their sub category underneath. Code:

Folder List Drop-Down
I am developing a PHP/MySQL project and as part of my initial setup and configuration scripts, the users can select a skin for the application, and a variable value ($skin) is updated to set the current skin, this works ok on it's own, but currently the user must manually type the skin name in a free-text box.

Ideally this needs to be a drop-down option box, and I would like this to be populated by listing the sub-folders within the '/skins' folder, so that it's always up to date. The folder structure looks like this:

/skins
/skins/skin1
/skins/skin2
/skins/skin3

How can I use PHP to generate a list of the current sub-directories in 'skins' and populate the drop-down list?

How Do You Pass A Value From A Drop Down List?
I am completely new to this. I don't understand how to receive a value from a drop down list <select> menu. I have read many tutorials and none of them explain the process of receiving the sent data.

Drop Down List Of Months
I am trying to create a drop down list with 12 months as the contents. I need to be able to determine what the latest month is and then put the 11 months before into it (in the correct order). For example, it is September 2007 obviously at the moment, so that will need to be the last and latest month in the list. The other 11 will be in reverse order going back to August 2006.

Chained Drop Down List Working Example
Could some PHP guru please help me? I looking for a good working
example of chained dropdown list.

Dynamic Drop-down List In Array
Q. How do I create a dynamically-generated drop-down list for use in
an array.

I'm using PHP with a MySQL database (through phpMyAdmin)

My database table is called com_courses, and I want to pull the
distinct 'title' fields and have them appear as a drop down menu for
the user to select in a form.

Here is my array, with (at the moment) manually-entered 'titles'
(which I now need to be dynamically generated from my database field:
'com_courses.title'

array (
"coursetitle",
"Course Title:",
$EXTRA_SELECTLIST,

array ("Report Writing", "Recruitment & Selection", "Presentation
Skills", "Essential Telephone Skills", "Time Managememt", "Customer
Care", "Other"),
0
),

I am not an experienced programmer, but can play around with php to
customize programs. I've read up on arrays (I bought a "Programming
with PHP and MySQL" book, but it just stops short of this problem). I
can't figure this one out.

Populating A Drop Down List With The Year
i'm trying to loop the years from 1960 - 2010 with the function get_year() below:
PHP Code:

Automatically Drop Down A List Of Phrases
I would like to know why when I go to a site like altavista.com and start to type in a phrase to search on does it automatically drop down a list of phrases that I have previously searched on, and how do I get rid of these from showing when I go to search.

I removed all of my cookies that were stored in my temporary internet folder. Is there somewhere else I should be looking. I am using IE 5.0 on a windows 98 machine.

How Do You Insert A Value From Drop Down List To SQL Table?
I am a bit new to PHP and SQL so this may seem like a dumb question.

I have already created a drop down list as part of a form which is
automatically populated with values taken from a separate database. When a
user goes onto this page and either leaves the default value or selects a
value from the drop down list and presses the submit button, I would like
that selected value to be stored into a database which I have already
created in SQL.

Just to let you know that I can do the above using a text field but just
don't know how to do it with drop down list.

If your going to explain any coding then it may help if I give you the names
of certain items that are involved.

Database is called "Company"
Field within database is called "Name"

Load Runner, Drop Down List
Can anyone send me the script for supplying the values in drop down
list of the web page?
I have couple of drop down list controls in my web page. I need to
supply multiple values for each dropdown list in my script. How can i
do that? can you send me the script for this?

PLEASE HELP - Drop Down List Related Question
I am creating a dynamic dropdown
list using a code snippet(Section A) as below:
Section A:
$sql_query=mysql_query("SELECT DISTINCT semester, year from
schoolproject_pics ORDER BY year
DESC");
echo "<select name="semester" onchange="GoTo()">";
echo "<option value="$semester">-Semester Year-</option>";
while($data = mysql_fetch_array($sql_query)){
if($data[semester]==@$semester && $data[year]==@$year){
echo "<option value
selected="$data[semester]">$data[semester]:$data[year]</option><BR>";
}
echo "<option
value="$data[semester]">$data[semester]:$data[year]</option>"; }
echo "</select>";
mysql_free_result($sql_query);

The 'GoTo()' Javascript re-draws the same page with the chosen values
of 'semester' and 'year' so that
the values can be recovered by $_HTTP_GET_VARS, stored in two hidden
variables and then used in
another query to create another dynamic drop-down list, as in code
snippet (Section B).

$semesternow=$HTTP_GET_VARS['semester'];
$yearnow=$HTTP_GET_VARS['year'];
if((isset($semesternow) and strlen($semesternow) 0) and
(isset($yearnow) and strlen($yearnow) 0)){
print("<input type="hidden" ID="semesterchosen"
value="$semesternow">");
print("<input type="hidden" ID="yearchosen"
value="$yearnow">");
$sql_query2=mysql_query("SELECT DISTINCT school from
schoolproject_pics
WHERE semester='$semesternow' AND
year='$yearnow'");
echo "<select name="school" onchange="GoMore()">";
echo "<option value="$school">-- School --</option>";
while(list($school) = mysql_fetch_array($sql_query2)){
echo "<option value="$school">$school</option>";
}
echo "</select>";
mysql_free_result($sql_query2);

Now the question:
When the page is re-drawn, how can the values of semester and year
previously chosen, be displayed in the first drop down list. I tried to
do it using the following, but it does not do anything:

f($data[semester]==@$semester && $data[year]==@$year){
echo "<option value
selected="$data[semester]">$data[semester]:$data[year]</option><BR>";
}

How To Display .txt Info Into Drop Down List
list out all the items from a file (data.txt) into drop down box for user to select.

Eg. inside (data.txt) has
Apple
Orange
Strawberry
etc...

How do I create a drop down list that can call out everything from data.txt (until end of file)??

Multiple Drop Down List Problem And MySQL
I am trying to populate around 30 drop down lists via a single query to a mySQL database. The problem is how to make sure that each drop down list only display it's relevant data. for example the table is as follows:

Trying To Select Names From A Drop Down List And Display Them
So, I already have the code written where I have a drop down menu with names in it. I want to be able to select multiple names from the drop down list and have them display in a table below the drop down menu. First off, I can't get one name to display, not to mention multiples. :p How may I accomplish this?

CODE:

Error Correction On Drop Down List & Sessions
Hi I'm doing a site at the mo and I have to do error correction on a form. I have most of it done except one or two bits. What I'm having trouble with is drop down lists. What happens is someone fills in the form, it's not done properly so it gets redirected back to the form. Everything works right except the drop down list. The sessions carries over alright but I can't get the drop down list session to work. It marks the session as selected but it's not displayed the first option is displayed. So if you picked Germany and America was first on the list. After being submited America would be displayed but Germany would be checked.

Here is what I got

Correction page

$_SESSION["country"] = $_POST["country"];
if($_SESSION["country"] == Ɔ'){
header("Location: /acc1.php");
}

Form page

echo ' <td><select name="country" id="country" style="width: 150px;">'
if (!isset($_SESSION["courtry"])){
echo '<option value="0" checked="checked"></option>'
}

$rslt = mysql_query($dscntry);
if($rslt){
while ($rws = mysql_fetch_array($rslt)) {
if (!isset($_SESSION["country"])){
echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
}
elseif(isset($_SESSION["country"])){
if($_SESSION["country"] == $rws["countryid"]){
echo '<option value="'.$rws["countryid"].'" checked="checked">'.$rws["countries"].'</option>'
// else{
// echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
// }
}
}
}
}
echo '</select>'

Dynamic Drop-down List With Array - Question
Can anyone out there give me a pointer regarding creating a
dynamically-generated drop-down list connected to an array?

And is that question as clear as chocolate spread?

Here's what I've got. I'm using PHP and MySQL database. I'm customizing
some calendar software, and I want the user to fill in a form by
selecting a title from a drop-down list, generated by my MySQL
database. However, the program I'm customizing uses arrays, which is
where I'm stumped.

What do I need to add to this code to make the array of titles(eg
"report writing" etc) come from my database, rather than the
manually-entered values that you can see here.

The field I want to pull from is called com_courses.title

array (
"coursetitle",
"Course Title:",
$EXTRA_SELECTLIST,

array ("Report Writing", "Recruitment & Selection", "Presentation
Skills", "Essential Telephone Skills", "Time Managememt", "Customer
Care", "Other"),
0
),

I hope it's not cheeky to ask this,
BTW I bought a book on Programming with PHP and MySQL, but it doesn't
answer this question,

How To Response Immediately When I Select The Drop-box List
Do you have any idea when I try to select a drop box list, the data
will show up in the following textbox immediately?

eg.

Name:
---------------
drop-box list | <- when i select one of them
---------------

Age:
---------------
Textfield 1 | <- pop up immediately
---------------

Address:
---------------
Textfield 2 |
---------------

Saving/Loading Data In Drop-down List
I have a drop-down list with set values. When there is a corresponding value in my database when the page loads I want the drop-down list to pick the appropriate value from the list. Instead it always defaults to the first value. Can anyone give me an example of how to do this?

Also, one time after adding a variable to a classes file this symbol: ï»¿ started showing up on all of my pages. Has anyone seen this before? I can't find any information on the web about it.

Populate A Drop Down List In A Form On The Basis Of A First Selection
I have developed a form to register a property in a db. The form needs the selection of a country and then based on that selection the selection of regions from the selected country. I have a program which allows selection of a country and then a region but it uses java script which I would like to avoid. I also just wanted one submit button if possible. Code:

Select From Drop List To Fill Table Column With Text -- HOW ?
I want viewers to compare state laws on a single subject.

Imagine a three-column table with a drop-down box on the top. A viewer
selects a state from the list, and that state's text fills the column below.
The viewer can select states from the drop down lists above the other two
columns as well. If the viewer selects only one, only one column fills. If
the viewer selects two states, two columns fill. Etc.

I could, if appropriate, have a separate htm page with the text for each
state -- california.htm for example. When the viewer selects California from
the drop down list, the column below would "fill" with California.htm.

Or, I could conceivably use a text or mysql database with two fields for
each record: state_name and law_text -- but it would probably be easier to
use separate htm files, since there will only be about 20 states involved,
and the "database" would never have a large number of records.

The table width would be 100% and each cell would be @33%

My site is designed with FP 2002 and runs on Apache/FreeBSD. I have just had
Apache-ASP installed but I have not yet configured or used the module.

Drop Down Box Query
I am trying to do a drop drown box query where if you select a certain game type then the records in the database that have that game type are displayed in a table below. My drop boxs work fine, its the query to display the data that is troubling me. Here is my code:

Query Using Drop Down Menu
can i query a table based on a drop down list?

i have a list of agents that i just want a simple drop down list to show the records they entered....

right now i just have the entire table showing all records in a html table format...but i want a drop down list so that if they only want to see the ones they entered, they can just select their name and poof...only theirs are shown...

Dynamic Drop Down Boxes With Php Query
I need to build a dynamic page with 2 drop down boxes on it where the contents of the second drop down box are dependent upon the selection made in the first drop down box (the first box contains districts/regions and the second box contains towns/cities). The customer wants this to happen on a single screen but can this be done with PHP?

The above question is already answered by many people and they want me to use Javascript.
My doubt is the second box shoud query the list from a table in mysql using php. How do i do that?

Trying To Make Populated Drop Down Box Query
My host is Godaddy, sql 4.1 - trying to create a populated drop down list that when submitted, displays the info row by row. I can populate the list, and when I post it takes me to the next page. The php on the next page makes the table header but there is no data underneath.

There is data in the table cause I can display it all on another php page I have. Code:

Drop Down Menu Where The Items Are From A MySQL Select Query
I am just starting programming in PHP and wonder if it is possible to have a
drop down menu where the items are from a MySQL select query.

I am registering people for a weekend seminar and want to have a list of
valid weekends to choose from on the form.

Any pointers to scripts or PHP references that will help would be
appreciated.

I am using the book "Build your Own Database Driven Website Using PHP &
MySQL" to get me started, but also need recommendations for a general primer
to php.

Drop-down Of Database Problem
I'm trying to create a drop-down of the 'members' column of the 'roster' table. As you'll see it looks completly ****ed up and in no way works. PHP Code:

Drop Down Populated By Database
Hopefully someone can help me with this: I currently have a php
file that pulls a query from the field "category" from my database.
this file is called category.php. I am trying to populate a drop down
box in another page (called add_subpage.php) from the results of the
category page. the code below is on the add_subpage.php file: (It was
my best guess and does not work)

<select name="category">
<option value="CAT"<?php include 'category.php' ?>></option>
</select>

Can anyone tell me how to make this drop down populate from the
category php file?

Drop Down Populated By Database
I currently have a php
file that pulls a query from the field "category" from my database.
this file is called category.php. I am trying to populate a drop down
box in another page (called add_subpage.php) from the results of the
category page. the code below is on the add_subpage.php file: (It was
my best guess and does not work)

<select name="category">
<option value="CAT"<?php include 'category.php' ?>></option</select>

Can anyone tell me how to make this drop down populate from the
category php file?

Drop Down With Assigned Value From Database
I have a database that has customers in it. When they purchase things from me, each purchase is either "online" or "onsite". So a selection must be made as either "online" or "onsite" when the item is entered into the database. Often, I have to update this value for an item later on from "online" to "onsite" and vice versa.

Is there anyway to populate the "Type" field with whatever the value is in the datablse for this particular item purchased, then allow someone to select "online" or "onsite" from the dropdown if it needs to be edited? Code:

Adding From Drop Down To Database
i have a script where if you select one of the drop downs, if you have the cash in your credits it will update the database as you having one of them. HOWEVER every time it goes on it gives the player a steak house without clicking on it.

anyone? Code:

Populating A Drop Box With Results From Database
I have a MySQL database with a table (category) with two fields, catId (int) and category (char(50)). What I want to do is to get all category names in this database and place all of them into a dropdown box on a web page so that the user can choose from the list of available categories.

Drop Down Menu Validation Against Database
I want to do a query which selects the config.maps table.field WHERE ladder_id = $ladder_id. I can do this fine, but the next bit is slightly harder.

The maps are stored as an array, separated by commas. I can explode these commas to put the maps in to an array called $maps but how can I then check that a value inputted from the drop down menu matches one of these maps?

I cannot do:

if ($dropdown = $maps[1] || $dropdown = $maps[2] || $dropdown = $maps[3]) {

// Continue

}

Horizontal Drop Down Menu From Database?
I've been searching now for months and have just given up. I've also tried to create my own menu using pre-made drop down menu software then using dreamweaver to try and get the values from a database but have had no success.

I've made a CMS which allows users to greate sub menu items, and then sub-sub menu items to those submenu items. And now the final thing to do is create the drop down menu on the front end of the site.

Is there a particular site or software package that anyone could point me to that is very good and allows you to create the menu's based on data in a database? So it will allow me to select which table contains the main buttons, which table contains the sub menu items, and also the sub-sub menu items.

Database Driven Drop Down Menu
I'm trying to create a database driven drop down menu. I feel I'm on to the right path but my code doesn't seem to work. I've looked around and haven't seen where I'm making the mistake. Any one care to take a look? Code:

Dynamically Populate Drop-down List And Dynamically Include Html File
We have a drop down list on a PHP page, with several product names, and
when people click one item, we will refresh the same page with the
product name as parameter, and in turn we want to include a HTML file
into the content area of the same page.

I know it is recommended to put everything into database, but we want
the web site to be very "portable", so the drop-downlist and the
content should both in text files.

Let's say the drop-down list will be poplulated from the product.txt
file, and there will be a file for each corresponding item in the
drop-down list. From the user point of view, if he wants to add a new
product, he will just need to open the product.txt file, and add a new
line with the product name, "Laptop", then add a new text file named
"laptop" in the same folder which contains the HTML fragment to be
included in the content area.

What is the easiest way to do this?

Scriptaculous Drag Drop And Database Integeration!
I'm working on a drag and drop feature with the scriptaculous
javascript library. And I was wondering if someone could help me! :(

Here is some test code. Basically, when someone takes something from
the left side and puts it in the right side, I just want to run a
database query.

I have NO IDEA how to do this because of my limited javascript
experience.

<script
src="http://www.mytuneslive.com/_NEW/MORPH/javascripts/prototype.js"
type="text/javascript"></script>
<script
src="http://www.mytuneslive.com/_NEW/MORPH/javascripts/effects.js?1.7.0b1"
type="text/javascript"></script>
<script
src="http://www.mytuneslive.com/_NEW/MORPH/javascripts/scriptaculous.js"
type="text/javascript"></script>
<link rel="stylesheet"
href="http://www.wiki.script.aculo.us/stylesheets/application.css"
type="text/css" media="screen" />
<div style="height:200px;">
<div style="float:left;">
<h3>This is the first list</h3>
<ul class="sortabledemo" id="firstlist"
style="height:150px;width:200px;">
<li class="green" id="firstlist_firstlist1">Item 1 from first
list.</li>
<li class="green" id="firstlist_firstlist2">Item 2 from first
list.</li>
<li class="green" id="firstlist_firstlist3">Item 3 from first
list.</li>
</ul>
</div>
<div style="float:left;">
<h3>And now the second list</h3>
<ul class="sortabledemo" id="secondlist"
style="height:150px;width:200px;">
<li class="orange" id="secondlist_secondlist1">
<span class="handle">DRAG HERE</spanItem 1 from second list.
</li>
<li class="orange" id="secondlist_secondlist2">
<span class="handle">DRAG HERE</spanItem 2 from second list.
</li>
<li class="orange" id="secondlist_secondlist3">
<span class="handle">DRAG HERE</spanItem 3 from second list.
</li>
</ul>
</div>

How To Grad Information From Mysql Database With Drop Down Menu's?
i am trying to do is like this website http://www.chippeduk.com/ in the search area (bottom right), where the user selects a make (all fields grab from the database), then selects a model, then they select the fine tune, then they click search this will bring up the information about the car they have chosen. How would i do this, would i use multiple tables and then link them together via an id? i am new to PHP/MySQL but very willing to learn.