PHP :: Array For Menu - Need Number Of Row.

Returning An Array To Populate A Drop Down Menu
Scenario: two related tables (Many) 'patient' and (one) 'doctor'. In the patient table, each row has an entry for doctor_id.

I have created a drop down menu on my patient form to input the doctor_id. The dropdown only shows the doctors' names.

This menu is generated by a SELECT statement on the doctor table. The result of SELECT goes into an array, and then each element of the array is inserted into the dropdown with a 'while' loop. This works fine.

However, I wish this dropdown to set itself to the correct doctor's name, when I retrieve a previously inputted patient record. That is, if patient 'Smith' is allocated to doctor 'Neo', the record is then saved, and later I retrieve the record: I wish to see doctor's name (Neo) as the default in the dropdown menu.

Print Array In List/menu Form Object
how i print a full column array into a list/menu form object, so that the text links to their respective page.....it is basically for a list of interviews so you click on the band name and then goto the interview page.

[PEAR:QuickForm] Dynamically Change A Dropdown Menu According To Another Menu?
I've been using QuickForm for a few months now and I am now given a
new challenge:

I've got a search form with a dozen of dropdown menus, the first
dropdown menu being "Brand". If you select either Brand A, B, C, D...
Z, the second dropdown menu "Model" must be dynamically changed to
model AA, AB, AC, AD..., according to the models manufactured by the
brand selected in the first box.

I've seen that done on quite a few sites, but never found if QuickForm
had a quick & clean way of doing that.

Array Splitting By Number
I have an array of numbers. There can be anything from 1 to n.

I need to split this array into seperate arrays in chunks of 100.

Of course if there is < 100 then I just need the one array with that total in i.e. say the first array has 48 then there will be only ine chunk with 48. The following code just shows that I can do it but very basically.

Also each number is then to be comma seperated within the new array. Except for the last one which at the moment the code below does not take into account.

Check If Number Is In An Array
how can i check if a specified number is in an array e.g

number =5
searching in array (1,2,3,4,5)

I know how to do it for a mysql query, but I need to do it in PHP, anyone kno how i could do this. Also say I have several numbers I want to check are in the array, how would I do this.

Pull 1 Number From An Array
I'm trying to set an array of a series of 6 single or double digit part numbers and match it against a user input selection of part numbers. For example, if the user is looking for part numbers 10,9,43,7,6 from an item that has part numbers 10,14,16,31,43,50 then it would highlight that part numbers 10 and 43 are a match, but so far it's only highlighting 1. Code:

Counting The Number Of Elements In An Array
I have 10 text field form elements and have put them in an array by giving them the same name - ie name="att_name[]"

When the user submits - I then loop through the array and print results :

foreach ($att_name as $value) {
echo $value.'<br/>'}

This works fine but I want to count the number of elements in the submitted array. So of the 10 textfields - if the user fills out 5 of them and submits - I want to get an element count of 5 -

I have tried using count($att_name) but that returns a value of 10 - I'm assuming it counts each textfield as an element. But I need to know how many elements are in the array that is submitted.

Random Number Excluding Specified Value In Array
the most efficient way to generate a random number
from a range that will not return values specified in an array?

How To Get The Number Of Values In An Array After I Use Explode
I have the following variable which has three areacodes in it:

$areacode = "305,954,786"

$array = explode(",", $areacode);

after i explode $areacode, How to get the info. how many areacodes are there in($areacode). in the above example it is 3 area codes (305, 954, 786)

$array[0] equals 305
$array[1] equals 954
$array[2] equals 786

Sorting Though Array Returning Hightes Number
OK. I need to get data from a table row and then sort though it finding the highest value (number). This is how far I got.

Getting A (non-radio) Button's Index Number From Array
If you could assist me with the following situation,

I have a table of data retrieved from database displayed on screen.
To each row of data, I have added action buttons, such as "Edit",
"Add", and "Comment". Since I do not know how many rows of data will
be retrieved - and therefore how many buttons I need - I am using
button arrays for each button, like so:
echo "<input type="submit" value="Comment" name="Comment[]" />";

In the php file that processes the input from this form, I have the
following code, which I was under the impression would give me the
index in the Comment array of the button that was fired.
if (isset($_POST['CommentMedicalHistory']))
{
$indexOfComment = each($_POST['CommentMedicalHistory']);
echo "index = {$indexOfComment['key']}";
}
Unfortunately, it is returning 0 as the index all the time, even when
I do not click on the Comment button in the first row.
Do you know by any chance how I could get the correct index of the
button that was pressed from the array?

How To Return Number Of Distinct Elements In PHP Array
I need to structure a table differently depending whether the card is available only with one inside (e.g. blank) or whether it's available with two (e.g. blank & happy birthday).

I have an SQL query returning the message, so I want to check whether there is more than one distinct value in an array. The array exists already (e.g. $row['message']). Does anyone know a suitable function for this? Like, count_distinct_results... Originally I started off struggling with a separate SQL, which didn't seem to return the expected number:

$query4="select count(card_msg) from xyz where image_id='$id2'";
$result4=mysql_query($query4) or die ("Error in query " . mysql_error());
$row4=mysql_fetch_assoc($result4); )

How To Get The First 2 Numbers From A Float-number Which Is Inside An Array
I am making an app in which numbers suplied by the user get divided, added etc. The result displays a floting-point-number.

I need to get the first 2 numbers of that result(which is inside a variable) to pass on onto a different fuction but i dont know how to do this.

Pulldown Function That Builds A Pulldown Menu From An Array
I have a pulldown function that builds a pulldown menu from an array variable called $options. The trick is that I am trying to bring the array like this:

$options=array('page1','page2',page3')

How can I get the syntax to be like what is needed in the array function from a SQL query.
I have tried this.

$result=sql_query("select location from locations where parentid=Ɔ'", $dbi);
$options=array(list($states))=sql_fetch_array($result,$dbi);

OUTPUT: Only the first part of the array ($states[1]) gets displayed instead of the whole list from the query. Any ideas on how to fix this??

Using Array_intersect() Without Keeyping Keys From The Array1, I.e. Re-number Intersect Array Keys.
I only use indexed arrays.

When I use array_intersect function, of $a3 = array_intersect( $a1,
$a2 ), I just need the vales of intersect array and let keys to be
re-numberred from 0.;

I found the intersect array $a3 have the correct values but keep the
keys of $a1. When I use
for loop from $index=0 to sizeof ($a3)-1, by $a3[$index], php reports
"undefined offset " problem.

How can I re-number the keys of $a3 from 0 to sizeof($a3)-1;

Replace Hex Number Or Decimal Number In A String ?
String may contain alphanumeric values. What is the bestway to replace a hex number such as 0x122aaa and decimal number such as 5678 with a string "blah" Example: I want to replace below--

wr_thru1 data or mask mismatch!! for addr=0x00000b73a0540 & mdfid:11
with
wr_thru1 data or mask mismatch!! for addr=hexVal & mdfid:decVal

Order Number Or Tracking Number
I need to create some kind of random number within a persons session that can be inserted into a customer id column for their orders, customer, and credit card tables.

Unless their is a better way to link a customers information together between a few tables besides using auto increment. Things could get screwed up for me if I use auto increment, especially if someone submits their information but does not actually place an order.

My question is " How can I create a random order number that can be used within a persons session and will stay the same throughout the whole program for that one person? "

Database Stores Default Number Everytime, But I Havent Set A Default Number??
Im having some problems with my database. Everytime i store a number which is longer than 10 numbers the script or database puts this number into the database: 2147483647. Its does this everytime no mather how i write the numbers and nomather how long the number is, it just needs to be over 10.

I have set any default value in the database and to be sure i havent i tried deleting the table, but same thing happends again???

Getting Another Menu
how can I do to create another menu with the results from the options they choose?
For example, they are looking for their grades so they choose in a first menu the carreer, in other menu the grade, and then when they finish choosing the grade, It appear automaticaly in other menu all the names of the subjects concerned to te carreer and grade given.

Php Menu
How do I have The menu and the context information display at the same time? Code:

Populate One Menu From Another
I thought this would be simple and there would be advice / tutorials
everywhere for this, but now that I'm working on it, I can't find any
reference except for ASP or Javascript code. PHP/MySQL - 3 form select
menus: Project, Categories, Subcategories. When a Project is selected, the
Categories list is populated based on Project selected, then Subcategories
list is populated based on Category selected. I see this all over the Net,
but through 10 books, there isn't anything specific. I think I get lost
with some of PHP structure since I've been using DW - I end up editing most
of it in order to follow it, but DW works pretty good for getting initial
testing done. I just can't seem to find further guidance on this. So far I
have:

Drop Down Menu(add Cat)
I have DB to add category and forum to edit the terms that in the cat so I add this code in the edit forum to change the cat of the term by choose the cat from drop down menu
PHP Code:

Collapsing Menu
I have written the code to do this however I am completely at a loss to do one particular thing. To best explain what the problem is I will give you an overview of how the menu hangs together.

The menu looks like this:

Menu-submenu
I've to create a simple site with menu-submenu.

The submenu are shown in a "dropdown" object that use "<ul><li>"....

Here is the structure:

group1
menu1
menu2
group2
menu1
menu2
menu3
.....

by selecting the link group1, group1->menu1, group1->menu2 I'd like on a
left pane the submenus structure of the group1, but not the substructure of
the menu2 etc.

What's the simple way to create it ? I'd like to modify only once and have
this working on all my site (I use a simple template using a table).

Dropdown Menu
I want to upload a feild values into a dropdownmenu. can anyone help me how to write in php code.

Drop Down Menu
I have a page that uses php to look up specific fields in a specific table of a specific database based on the username. Using this, it creates a dropdown list of information belonging to that user. The fields in question each have 13 pieces of data. Based on what they click in the dropdown box, I need that specific data to pass onto hidden fields on the page. Code:

Drop Down Menu
I'm struggling to get this to work. It is suppose to show only $name and not $name and $email PHP Code:

Drop Down Menu
I am implementing a website with dreamweaver. I dont know much about
programming but I can handle scripts and manupilate.

does anyone know a website that i can get a free drop down menu script
to use on the website's navigation?

Template Menu
I'm trying to decide witch way to do my menu for my program.... see some menu will be accessed by certain users with certain power... but i cant seem to decide with way to do it because... the menu is also template based ( $template = new template( menu.shtml )) anyone has done this in a way to keep the template system integrated and only show certain menus according to there users prv?

Dynamic Menu CSS
I am trying for a long time now, to find a way of creating a dynamic drop
down menu. I have the CSS part ready and working and also I have the first
level of the menu working.
the problem I have is how can I submit the id from the first level menu in
order to make the query and create the second level and so on menu.

I am trying to avoid Javascript but I can't see another way at the moment...
What I want to achieve is to produce the menu on HOVER if that is not
possible on click will be ok as well.
Do any of you have an idea ?

This is the code I have :
**********************************************
<div id="menu">
<ul>
<li><h2>Products</h2>
<ul>
<?php do { ?>
<li><a href="?cat_id=<?php echo
($row_product_categories['prod_category_id']); ?>"title="<?php echo
strtoupper($row_product_categories['prod_category_name']); ?>"><?php echo
ucfirst($row_product_categories['prod_category_name']); ?></a></li>
<?php }
while ($row_product_categories =
mysql_fetch_assoc($rs_product_categories)); ?>
<ul>

<?php do { ?>
<li><a href="index.php?id=<?php echo ($row_products['prod_id']);
?>"title="<?php echo strtoupper($row_products['prod_name']); ?>"><?php echo
ucfirst($row_products['prod_name']); ?></a></li>
<?php }
while ($row_products = mysql_fetch_assoc($rs_products)); ?>

</ul>
</li>
</ul>
</li>
</ul>
</div>
**************************************************

Drop Down Menu
I have 2 drop down boxes on my site. I want the selection of the
first one to populate the second box.

Drop Down Menu
What i would like to do is look in a file and see what the name's of the files are in there and have them put in to a drop down menu. Dose some one know of a tutorial on this or how to do it?

Drop Down Menu
I have a problem with a drop down menu, I have 2 drop down menu's if 1 select in dropdown menu 1 a catagorie then I must give this to menu 2 and then there must be things in menu to with catagorie from menu 1 I just want when I clicked menu 1 the php file refreshed en gives the catagorie with the refreshed file but HOW?

Menu/submenu
I wish to make a menu (in php), and every time a menu-item is selected, a
sub-menu will be visible.

Triple Menu
I'm going to have a website that will have a very dynamic menu structure (one that could change every few minutes) and it is essential that everytime the menu is built, the updated database entries are included.

Background: The site is a homework study site that gives study tools, etc. So lets say that i want to look up the Math (subject or "class"), Pre-Algebra ("course"), CPM ("curriculum"), i would first select Math in the first drop down menu, then Pre-Algebra in the second, and then CPM in the third. In the second and Third boxes however, there will be other courses and curriculums to choose from. Those will be updated very regularly and i do not want to do this manually. Code:

Drop Down Menu?
Im looking for a script for a site im making that will make a drop down menu which I can customise the color of. Simple, like a border and background color, but is friendly with all types of IE explorer.

Drop Down Menu
I am using the following code to loop 12 months backwards from the current month in a drop down list - using the get method.

I'm having difficulties trying to get the option selected once I have submitted the form. For example, I am using this to filter months, so once a month has been selected and submitted, the first option in my drop down list is displayed and not the one that was selected and submitted. So basically, I need to be able to select a month > hit submit and when the form returns, have the drop down list show me the selected item. Code:

Using Jump Menu
I am using a jump menu to select multiple drop down boxes in a form which are related to the choice you make in the first drop down box. The problem is that the page reloads and everything before this tag is cleared. I want to be able to repost the data. I know that I need to use sessions in my code but I dont know exactly how to use them for this case. Code:

Drop Down Menu
i want a drop down menu that will select which database is needed for that page..

see i have a site im making for a clan that plays like 10 different games and i wanna have 1 index but the dropdown menu will be at the beginning and when a player goes to the site they can choose which game they play so they can check the news and stuff.. the drop down menu should choose which database is needed? can this be done or will i have to make 10 different index.php pages?

Drop Down Menu
does anyone have the code to have drop down navigation on a website?

Vertical Menu
anyone here has done a vertical menu using php with mysql database? something like this:

menu1
> submenu1
> submenu2
> submenu3
menu2
>submenu4
>submen5

then when you click the menu it shows/ hide the submenu.

Echoing Value To List Menu
Hi, I was wondering can I echo out value from db to list menu and how?

Mysql Php Dynamic Menu
I am trying to write a script that will create dynamically a menu from MySQL
database. The database table is a product categories table and it has the folowing filed:

category_id, parent_category_id, category_name (some other fileds are there
as well but these are enough to figure out the logic)

I know that I have to store all the product_categories records in a temp
array and then some how go through them and store the level of each record
in the menu....

If you have done something like that I suppose you know what I mean and I
would much appreciate to give me a hint here ...
I had a look in the phpLayersMenu from sourceforge but it is really advanced
OO code and I cannot understand the logic....

My target is to create a Tree menu with no pre - defined number of
records...

Dynamic Navigation Menu
I need to build a dynamic menu that will include certain links depending on what variables are in the URL. This is doable - right?

For example: catalog.php?product=widget&color=green

Menu would look like:

Green Widgets
Brand 1 Green Widget
Brand 2 Green Widget
Brand 3 Green Widget
etc.

Any help would be greatly appreciated!

Php Drop Down Menu Variable
I have been playing with one script for more than two weeks. It is a simple poll script.
Once the user has selected from a drop down menu...it is mailed to me. The problem is that I only get the first word of their choice! That defeats the purpose of having the poll!

Echo Drop Down Menu
What I do is when the form is posted (php_self) it does its check and if there are errors, ie. user has not filled in required data, it takes them back to the form but the text fields are already filled in with what they have already typed.

But the drop down menus default back to the PLEASE CHOOSE option, how can I get my drop down menu to be what they have just selected. The reason I need this is there are 6 drop down menus for different things on the page and a user would get fed up having to reselect each one when they have not filled in a field. Code: