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Auto Fill Dropdown List Error


Im using the code below to autofill a dropdown list from my MYSQL DB.
The only problem is it is leaving out the first entry (alphabetically) for each $vehicle_make ? Does anyone know why this may be hapenning? Code:




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Auto Fill Date Dropdown List
How would I modify this code to display the years in the dropdown list like so:

current year
2006
2005
back 50 years

<select name="year" id="year">
<?PHP

for($i=date("Y");
$i<=date("Y")+2;
$i++)
if($year == $i)
echo "<option value='$i' selected>$i</option>";
else
echo "<option value='$i'>$i</option>";
?>
</select>

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One DROPDOWN SELECT Control Can It Fill In 2 Textboxes?
I have a form with text boxes and a dropdown menu with names of cities
The adjacent textbox fills by the help of a Javascript function.
My question is, how to realize the purpose of filling the adjacent texbox
for zip values. Code:

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Dynamic Fill Form Fields Depending On Dropdown Box
This question has probably already been asked, but let me ask again

I have a mysql database to which I connect with my php scripts. The
database contains articles. Name, Unit_Price and Reference

Now my client needs to order 5 items, click a button and a table with 5
lines and 3 columns appears (until now easy)

In the first column is a drop down box with a <select > and <options> in
which I store all possible names.

I would like than whenever the client changes one of the boxes (in my
case there are 5) the Unite_Price column and Reference column in the
line he just choose get automatically updated

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Auto Fill Forms?
Is it possible to auto fill form with your information.

Example:
https://login.yahoo.com/config/mail?.intl=us

Can I Log into there with my username and password from a php file and check if the word anoluck exist.

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Auto Fill Form
I need to fill a form that is on another website that I don't have any control over. Basically there are two fields on that other website. First name and lastname. Is there anyway I can auto fill that from my site? I know We can submit forms on another site using CURL. But I would like to know if i can fill the form fields on another site.

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Auto Fill A Form
I seen a website doing this but not in php so Im wondering if it is possible to open up
a page like http://mail.yahoo.com and fill in my username and password with a php script?
if possible how can i do this?

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Auto Fill And Submit Form
Can i fill a form and submit it automatically using PHP? or Suppose a PHP script uses the 'Get' to get variables, I suppose i can directly specify a value to that variable as

url/abc.php?fieldname=value

What if it uses 'Post' ?

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Radio Button Auto Fill
I need to use JavaScript or use php or what to make this work. I have a Radio button group & 2 text input boxes below the radio buttons. I have information that needs to be placed in the text boxes stored in MySQL db. In my DB I have TEAM 1's name & then TEAM 2's name already stored. The 2 radio buttons lets you choose either TEAM 1 or TEAM 2. I need the user to be able to click TEAM 2 & the 2 text boxes fill with TEAM 2's Name & if he chooses TEAM 1 then it fill with TEAM 2's name.

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Auto Fill Form Inputs
I have the drop down menu that list the person's name from the MySQL query. Next to the drop down menu I have 3 text boxes...user's name, user's sex, user's age. I want 3 text boxes to display the information that is already in the Database when I choose the user I want to see. I have the DB table that houses users information already with the information already entered. Once I click user 2 I want that user 2's name, sex, & age to be displayed in those 3 text boxes that I already have. Then if I choose user 10 I want user 10's information to populate in those 3 text boxes.

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Auto Fill 2nd Form Field From 1st Info
I want to be able to auto fill the description of an item based on the part number. I know I can do this but have to reload the page each time. Not a problem except I am not sure how to do this without submitting the form, however when I submit the form I want to go to a confirm page. Code:

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Populating A List Box Or A Dropdown List Using Php And Odbc
I need to populate a list box and/or a dropdown list on a form. I have all
the bits and pieces together, all bar the code which takes the result of a
query and creates a list box.

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Auto Populate Dropdown
How would I automate this script below so that I dont have to modify it each year (example; when the year reaches 2008)

<?
// Make the years array.
$years = range (2007, 1930);
// Make the years pull-down menu.
foreach ($years as $value) {
echo "<option value="$value">$value</option>
";
}
echo '</select>'
?>

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Dates Fill Drop Down List
I have a drop down list and would like to fill it with 12 months starting from whatever the current month is:

EG: Current month is July 2005

I would like the list to show:

July 2005
August 2005

.
.
.
July 2006

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Auto Select Dropdown Lists From Db Values
I want a simple HTML drop-down list like this: Code:

<select name="select_1">
<option name="option_1" value="option_1" selected="true">
<option name="option_2" value="option_2" selected="false">
</select>

to be able to automatically select a value according to a value in a table in the database. For example, if a MySQL table has a field named "field_1", and one of the rows has a value of "option_1" in that field, I want the list (using PHP of course) to automatically select the option name "option_1".

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Mysql Ajax Dynamic List To Fill More Than 1 Textbox With A Dif.value For Each?
Ok, I have a database: ie...

Id | cab | price | w1

1 | wall | $300 | $19

on my form I have three textboxes: input1 is cab with autocomplete, input2 is price, & input3 is w1

The way I have it now works great, I type a few letters in input1, it pulls up a list, once cab is selected it populates input1 with cab and input2 with price.

I want to know once cab is selected, if it can populate input2 with price & input3 with w1 as well? Code:

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Select From Drop List To Fill Table Column With Text -- HOW ?
I want viewers to compare state laws on a single subject.

Imagine a three-column table with a drop-down box on the top. A viewer
selects a state from the list, and that state's text fills the column below.
The viewer can select states from the drop down lists above the other two
columns as well. If the viewer selects only one, only one column fills. If
the viewer selects two states, two columns fill. Etc.

I could, if appropriate, have a separate htm page with the text for each
state -- california.htm for example. When the viewer selects California from
the drop down list, the column below would "fill" with California.htm.

Or, I could conceivably use a text or mysql database with two fields for
each record: state_name and law_text -- but it would probably be easier to
use separate htm files, since there will only be about 20 states involved,
and the "database" would never have a large number of records.

The table width would be 100% and each cell would be @33%

My site is designed with FP 2002 and runs on Apache/FreeBSD. I have just had
Apache-ASP installed but I have not yet configured or used the module.

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Dropdown List
I have a Dropdown list with Select with 1, 2, 3, 4, after select on of them it bust to refresh the page to what you select but it don't do it. PHP Code:

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Dropdown List Box
I am able to populate data in a dropdown list box using php and mysql. However, I a wondering if i can add inside some icons such as close or More records,  where the drop down acts to the specified request, ie., closing the drop down or fetching  some more data from backend.

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Populating Dropdown List
I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:

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Smarter Way Of Doing Dropdown List?
I've got a dropdown list that is acting as a filter on a table, so the user can select a value and the page is reloaded only showing the matching values from the database.

Now when the page reloads the dropdown was set to 'all' as it was first in the list, even if I'd selected a different value, this was confusing for users, so I added an initial <option> field which pulled the correct value from $_GET (code below) - however this is a little odd as it means the value appears twice!

Does anyone have a genius solution to this?  I've seen a <select selected="yes"> sort of thing around, but I don't know how I can tell the php to add this value dynamically? 

<select size='1' name='occupation'>
<option>".$_GET['occupation']."</option>
<option value='All'>All</option>
<option value='Student'>Students</a></option>
<option value='Professional'>Professional</option>
<option value='Hobbyist'>Hobbyists</option>
</select>

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Mysql Dropdown List
Im trying to automatically fill a dropdown list with data from MYSQL table.

Sizes Table
--------

ProductId | size1 | size2 | size3 | size4 | size4 | size6 |

* the 'size' rows hold a numeric value for the quantity I have of each

I was hoping to only list the sizes that have a greater number than 0.
I have used an auto fill select code on another project but I'm just not sure how to fill in the blanks. Code:

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List The The Entries Of The Dropdown Box
How can I list the the entries of the dropdown box (which are all populated) according to the time they are populated.

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Check The Dropdown List
i have a drop down list in my php code. i need to check the drop down list is set or not. for that what is the code. i heard that there is no php code for that. javascript is needed. my code is here. PHP Code:

<?php
$database="sms";                    /* DB name       */
$host="localhost";
$user="root";                        /* Set DB Username */
$pass="";                            /* Set DB password*/
mysql_pconnect($host,$user,$pass);  /* DB connect....*/

mysql_connect ($host,$user,$pass);

mysql_select_db($database) or die( "Unable to select database"); /*DB Select*/

function orgresult()
.......

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Add Variables To Dropdown List
I have a list of variables:

$variable[0]
$variable[1]
$variable[2]

The amount of variables changes so i've used $total = count($variable) to find the amount there are.

How would i tell php to create a dropdown menu with the amount of options=$total and then fill the options with $variable[0] etc.

I know i can use a loop to increase the value of say $i by one each time to that i can use $variable[$i] each time, i'm just stuck with adding the whole thing to a dropdown menu with the right number of option...

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Autopopulate Dropdown List From Database
An events-registration page with a form containing a dropdown list for upcoming events, the events will be pulled from a table which is updated by...?

what i've gathered so far is that this can be done with PHP. I am a little unclear on the concept of how this is done. How does the updated information get input into the table?

1) can this be done (updating database) through a web interface by the client, or is it something i would have to do locally and then upload. If done by the client, can he delete/edit existing information--assuming he is not familiar with code.

2) what other things aside from html(good), sql(so-so), and php(newb) will i have to know?

i've seen a lot of good tutorials here and will have access to the necessary software. I just want to know if there is anything else i should know before i dive in head first without testing the PHP water, which i assume is frigid.

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Dropdown List Of Files In Folder
I am preparing a form that includes a drop-down list consisting of the names of files in a certain folder on the server.

I only need to trap the file name (jpg), not the path and I'm not trying to upload the files or anything - simply allow the user to select one of a number of different image files (they're actually location maps).

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Dropdown List - Trying To Get Default Populated From Db.
Nooby question but when I try and get this to work (it should identify which
rows in the database have GK, MID, DEF, FWD against them and then put
SELECTED into the option value to give a default of what the entry is
currently) it just adds SELECTED to all the results as if $row["Position"]
is returning true against all four conditions? What am I doing wrong? CODE:..

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Cascade Dropdown Or Conditional List
I would like to create a conditional cascade form.  based on the selection, it can display or not display an input form for the user to enter an string of text. then at the bottom of the page (or when a user submit) connect all the sections including the input field all together (it's like a story maker?)

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Microsoft Access Dropdown List
l am building a new site using PHP which has a lot of pages pulling from an Access Database. I would like to have a dropdown list that pulls exhibitions from the database and then when the user selects one it shows the rest of the details from DB just below the dropdown list, hope that makes sense. Code:

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Trying To Create Dropdown Menu From List
I am trying to create a dynamic dropdown select menu from a directory containing other directories and files. This is to select a certain page from the list so I can edit it. I only want the files in the menu. Here's what I have so far but it doesn't populate the dropdown. Code:

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How To Create A Dynamic Dropdown List
how to create a Dynamic drop down list using Mysql.

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Dynamic Dropdown List Using Access
I am creating a dropdown list that is populated from an Access DB: Code:

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Dropdown List Selected By Default?
Does any one know how to have an item in the dropdown list selected by default?

$city_field = HTML_QuickForm::createElement('autocomplete', 'city', 'City', $cities);

$cities is an array of city names and I would like, say 'Los Angeles' selected by default.

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Dropdown List - Insert Into Mysql
I simply want to add a dropdown list where, when an option is selected, its value will be inserted into a dbase table. More specifically, asume there is a page where the user sees his order.

He will be able to select the order status (pending or delivered). So, for example, if his ordered is deleivered, by selecting "delivered" option, "delivered" will be inserted into the 'Status' column. Code:

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Change List View To Dropdown Menu
Im working on a script that has to be change so a user can choose from a dropdown menu instead of a list that now is displayed.
Here is the part that is insert on the index page.

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Stuck On Dropdown Menu List, Could Use Some Guidence
I have a form with some drop down list/menus. I do a check for ommissions and if found display a message to re-try. What I need is a way to show which options where chosen when the user submitted the form the first time.

If someone could show me how to do the first one, I'm sure it's the same process for the second one. Here's the code:

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Creates A Dropdown List Of Information Belonging To That User.
I have a page that uses php to look up specific fields in a specific table of a specific database based on the username. Using this, it creates a dropdown list of information belonging to that user. The fields in question each have 13 pieces of data. Based on what they click in the dropdown box, I need that specific data to pass onto hidden fields on the page. Code:

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Easy Comma-delimited List To Dropdown Box Converter
I was working on a simple converter when I realized that by not setting the id param of the option tag, it wasn't going to send the value of the dropdown box to my php script. I had this to start with: Code:

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Pick From A Drop Down List That Automatically Gives Options In A Second Dropdown Box
does anyone know how to create a form that allows the user to firstly pick from a drop down list that automatically gives options in a second dropdown box. eg.

'category1'
is selected from dropdown box 1,
this then populates dropdown box 2 with the options
'category1.a' or 'category1.b'

or if
'category2'
is selected from dropdown box 1
then dropdown box 2 gives the options of
'category2.a' or 'category1.b'

i f any one knows how I should code this please help, if not point me in the direction of a tutorial that can.

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Dropdown List Which Selects A Post A Title (to Edit)
I want to have a dropdown list which selects a post a title (to edit), then when you click submit I want to use POST to submit the data for that post (post title, username, subject, content) so that the edit pages form fields will already be filled with the posts data.

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Auto-incremented Mysql List?
how when you have an auto-incremented mysql list? And you know how when you delete an entry, the entry's auto-increment value just gets dropped and skipped? What I need to know is if there is a way to sort of re-number the list, preferably using a Query, such as an ALTER command or something. Code:

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Dynamic Dropdown And Hardcode Dropdown In Select Form
I have plenty of examples of dynamic dropdown choices but none of hardcoded dropdown choices. The ultimate goal is to have a job with various tasks and to track the status of those tasks for a given job. I've used one of the tutorials here to begin the process. Below is the code I have to add work on a given task. Perhaps I actually need to "Update" a job as opposed to "add".

But the problem of the moment is I can't seem to hardcode one set of my options. This is the code I have: PHP Code:

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Error Correction On Drop Down List & Sessions
Hi I'm doing a site at the mo and I have to do error correction on a form. I have most of it done except one or two bits. What I'm having trouble with is drop down lists. What happens is someone fills in the form, it's not done properly so it gets redirected back to the form. Everything works right except the drop down list. The sessions carries over alright but I can't get the drop down list session to work. It marks the session as selected but it's not displayed the first option is displayed. So if you picked Germany and America was first on the list. After being submited America would be displayed but Germany would be checked.

Here is what I got

Correction page

$_SESSION["country"] = $_POST["country"];
if($_SESSION["country"] == &#390;'){
header("Location: /acc1.php");
}

Form page

echo ' <td><select name="country" id="country" style="width: 150px;">'
if (!isset($_SESSION["courtry"])){
echo '<option value="0" checked="checked"></option>'
}

$rslt = mysql_query($dscntry);
if($rslt){
while ($rws = mysql_fetch_array($rslt)) {
if (!isset($_SESSION["country"])){
echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
}
elseif(isset($_SESSION["country"])){
if($_SESSION["country"] == $rws["countryid"]){
echo '<option value="'.$rws["countryid"].'" checked="checked">'.$rws["countries"].'</option>'
// else{
// echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
// }
}
}
}
}
echo '</select>'

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Putting Form Error Messages Into A List
I have some form validation and I want to put all the error messages that are displayed into a bulleted list. I have seen it done with more complicated validation using OOP but I don't know enough to do that. How would I add these error messages to a list if they occur? Code:

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SQL/DB Error -- [Unknown Column 'M' In 'field List']
I have a simple form element that drives me nuts. Here's the code: PHP Code:

<input type='radio' name='gender' value='M'";
    if ($usr->act_gender == 'M') { echo " checked"; } echo "> Male
&nbsp;&nbsp;&nbsp;&nbsp;
<input type='radio' name='gender' value='F'";
    if ($usr->act_gender == 'F') { echo " checked"; } echo "> Female

When the form submitted it should PHP Code:

("UPDATE act_details
SET ... gender=".$_POST['gender'].", ...
WHERE ID = '".$user."' LIMIT 1")

But I keep getting the following error: Quote:

SQL/DB Error -- [Unknown column 'M' in 'field list']

Even Thought I have such a field in my db table.

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Error: Unknown Column 'OOM210' In 'field List'
Can someone tellme why I get the following error?

Error: Unknown column 'OOM210' in 'field list'

$flightnumber is equal to OOM210...

(INSERT INTO and VALUES are on the same line, but here it is split so it is easier to compare.)

$sql = "INSERT INTO flights (flight_num, dept, dest, depticao, desticao, depttime, desttime, stops, duration, freq)
VALUES ($flightnumber,$departure,$destination,$departurecity,$destinationcity,$departuretime,$arrivaltime,$stop,$duration,$freq)";
  if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }

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Book ERROR: Unknown Column 'Fredrik' In 'field List'
In confused with this problem, My code looks like this:

$sql="INSERT INTO calendar(year, month, day, name)
VALUES('$year','$month',".$_GET['day'].",".$_SESSION['name'].");

the table structure of "calendar" is

year TINYINT(4) notnull
month TINYINT(4) notnull
day TINYINT(4) notnull
name VARCHAR(30) notnull

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Textarea Fill
I need an idea on how to accomplish this task. I have a script that I tried so many times to tweak but failed; so I am starting afresh. I am working on a project with PHP and MySQL and the table below is one of the tables in the db.

title_duty
id int not null auto increment
title varchar(255)
duty text

The table are populated with titles and their duties.
I need a php form with a dropdown menu of the titles of which when a user selects a title, the corresponding duty of the selected title, will display on a text area in the form; where the user can edit the duty. Now the form output can either be submitted to another table for selection with another form or can be a POST in another form. Any ideas on the best way to solve this nagging problem?

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Fdf Fill Out A Form
I followed the instruction of http://fooassociates.com/phpfer/html/rn20.html

I know how to fill in the data into a form on the browser of the client.
Is it possible to fill out the form on the server and to send this as a
pdf file to the client?

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How Fill SQL Database..
I've made a database with phpmyadmin. Now I want to add text to the fields i"ve made.
Can i do this trough phpmyadmin or how can i do this?

I've got these fields.
id int(11) No Null auto_increment
titel varchar(50) No Null
bericht text No Null
datum varchar(16) No Null

Can I add text to these fields from phpmyadmin? Or do i have to use php to fill it? Could someone please help me make a php page that can fill this database? My aim is not to use this, but to learn how i can do it myself.

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Fill In Alt Tags
I have been tying for ages to use php to create alt tags that pull data from a mysql database. So for instance the alt tag could show the region, price and country etc by pulling that info from a table. I have this code below but I get this error: Parse error: syntax error, unexpected T_STRING. This is the code I'm using: PHP Code:

if(!empty($a1[image]))
{
$images = explode("|", $a1['image']);
$MyImage = $images[0];
//$ListingTable .= "<img src="re_images/$MyImage" width=100 height=80 border=1>";
$ListingTable .= "<img src="thumbnails/'.$MyImage.'" width="100" height="80" border="1" alt="'.$a1['region'].', '.$a1['country'].'" />'
echo $ListingTable;
}
else
{$ListingTable .= "<img src="no_image.gif" border=1>";}

Does any know why it still isn't working?

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