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Business Days B/w Two Dates


How do I count the no.of business days between two dates in php.




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The problem is that I am not sure about the logic side of the problem. A crude solution that I can think up is doing something like PHP Code:

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I have people posting ads and when the ad is posted I have two fields populated at that time:

date_created
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With the date expired being 7 days after the date created. Both are in this format: 03/12/07

What I am doing is preventing someone from posting more than one ad per 7 days. I'm validating against their email address for that. But I want to display the date that they would be eligible as well as determine if they are eligible to post or not which would require comparing today's date with probably using the now() function against the date_expired in the database. If the today's date is past then no problem. If not, then it would display an error. Code:

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for ($dayval = $startdate; $dayval <=$enddate; $dayval+=$oneday){
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Does it exist something allowing to manage such contacts. Ideally, this
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database, and the contacts history (like the program called ACT! on PC
www.act.com , but it's too expensive for what we do).

Ideally, we should be able to:
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creation (please call back on monday...)
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Obviously, any item should be filled by any user, and there should be a
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The idea is to be able to fill the address when it's time to (evening,
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Link can be found at:

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Sessions Not Working In Yahoo Small Business
I developed web app using Php and used sessions. Everything works on
my test server but sessions just dont work on the clients server which
uses Yahoo Small Business to host their site.

For example:
<?php
session_start();
if (!$_SESSION['count']) {
echo "Not registered<BR>";
$_SESSION['count'] = 1;
$count = 1;
} else {
$count = $_SESSION['count']++;
}
echo "count is '$count'";
?>

Always shows count as 1.

The yahoo site uses PHP Version 4.3.6.
The only difference relevant I can see in the two sites is
session.use_trans_sid which is off on Yahoo. Enabling this with ini_set
didnt help. Saving session information in the DB using custome session
handlers didnt help either.
Any ideas as to why this may be happenning?

Other relevant php info is pasted below:

Session Support enabled
Registered save handlers files user

Directive Local Value Master Value
session.auto_start Off Off
session.bug_compat_42 On On
session.bug_compat_warn On On
session.cache_expire 180 180
session.cache_limiter nocache nocache
session.cookie_domain no value no value
session.cookie_lifetime 0 0
session.cookie_path / /
session.cookie_secure Off Off
session.entropy_file no value no value
session.entropy_length 0 0
session.gc_divisor 100 100
session.gc_maxlifetime 1440 1440
session.gc_probability 1 1
session.name PHPSESSID PHPSESSID
session.referer_check no value no value
session.save_handler files files
session.save_path /tmp /tmp
session.serialize_handler php php
session.use_cookies On On
session.use_only_cookies Off Off
session.use_trans_sid Off Off

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Offering Dates And Booked Dates In A Table As DATE Datatype Using MYSQL.
Availability dates in offering dates except booked dates. For Example: Offering dates are :

01-09-2005 to 27-09-2005
01-11-2005 to 30-11-2005

Booked dates are :

10-09-2005 to 23-09-2005

Availability dates should be

01-09-2005 to 09-09-2005
24-09-2005 to 27-09-2005
01-11-2005 to 30-11-2005

I am storing offering dates and booked dates in a table as DATE datatype using MYSQL.
So, I want the above mentioned availability dates as a result.

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Dates In Range Falling Between Existing Dates
The latest quandry I have is that I need to:

a: check whether any dates in a date range entered by a client in a form (datefrom, dateto) conflict with any existing date ranges already in the database.

-this is a check to see whether the dates that a customer is trying to book are not already booked-
Obviously its easy to get the numbers out of the database (i.e. 28/12/2006 or whatever format) and from the form but how to I convert this 'range' actually into a range I can loop through that will return true if any of the dates are the same (i.e. already booked)?

b: is similar in that I want to check how many of the clients entered dates fall into the pre assigned high, mid and low season ranges in the database and multiply each of those days by the corresponding price.

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How To Compare 2 Dates In Mysql As Mysql Treats Dates As String ?
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I've got a form that inserts data into a database. Basically what it sends is a sets of dates. What I'm wanting is another set of inputs that also sends some dates. But before it adds them to the database I want to query the dates and find all of the dates between the two given ones and add them to the database as well. Code:

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How Do You Get A List Of All Dates Between Two Dates More Than A Day Apart?
Say you have two dates, 2005-01-01 and 2005-01-24. I want to get a list or
array or all the date between and including those two dates.

I want to include this list in a query so I need it in a format like:
&#392005;-01-01', &#392005;-01-02',...

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Find Dates Between Two Given Dates
is there any way to find dates between to given dates. ie, suppose it is given 01-01-2006 and 04-01-2006 (in dd-mm-yyyy format), want to print the dates from 01-01-2006 to 04-01-2006.

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How Do You Add 7 Days To Now()?
How do you add 7 days to the now() function stored in database as 00-00-00 00:00:00

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Last 7 Days
I am trying to run a query to get the last 7 days in the following format: Code:

<a href="roundup.php?news_date=20060523">Tuesday, May 23, 2006</a><br>
<a href="roundup.php?news_date=20060522">Monday, May 22, 2006</a><br>
<a href="roundup.php?news_date=20060521">Sunday, May 21, 2006</a><br>
<a href="roundup.php?news_date=20060520">Saturday, May 20, 2006</a><br>
<a href="roundup.php?news_date=20060519">Friday, May 19, 2006</a><br>
<a href="roundup.php?news_date=20060518">Thursday, May 18, 2006</a><br>
<a href="roundup.php?news_date=20060517">Wednesday, May 17, 2006</a><br>

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How To Get -7 Days
how can i query the last seven days of my table

(table )waytogo
id (int auto increment) | dates (datetime format)
1 | 2005-11-23 08:54:32
2 | 2005-11-21 09:32:45
3 | 2005-11-12 12:43:22
4 | 2005-11-19 02:30:00

etc...

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Days In A Calender
I am trying to write a calender display that shows the days of the month accross the top of a table, and people's names down the side. One of the things I would like to do is to change the colour when the days are Saturday or Sunday. PHP Code:

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Get The Birthdays For The Next 14 Days
I have a table of members and I have their dob. Now I want to show the members which have their birthday in the next two weeks. PHP Code:

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Add Days To Date
I have a date assigned to a variable $firstPay and another variable $totalDaysTo which has the number of that I want to add to the variable $firstPay to get some future date. I'm not sure how to wright the code for this one.

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Days Calculation
i can't seem to get this what im trying to do is work out the elapsed time in DAYS from 2 dates code is:

             $time_now = time();
             $d2 = date('Y-m-d H:i:s', $time_now);
             $d1 = date('Y-m-d H:i:s', strtotime($ng_date));
             $days = ceil(($d1 - $d2) / (60 * 60 * 24));
when echoing out it produces:

2007-06-02 16:53:24
2007-08-27 18:00:51
which is right, but $days echoes out as 0.

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Days Of Week
I'm attempting to display information for today, the next day and the day after (so only three days worth). The first day is hardcoded to say now. I want the next day and the day after to be the abbreviated day (ie. Tue, Wed and so on). The problem I have with the following code is that now and the next day are the same. Thus, I have now (which is Tue), the next day (which is ALSO Tues - wrong!) and the day after is Wed. Here's the include:

$return['mydata'] = array();
for($i = 0; $i < 2; $i++) {
$attr = explode('"', $this->tag('blm:mydata',$i));
if(count($attr) > 1) {
$day = array();
$day['when'] = $attr[1];
$day['image'] = IMAGES.$this->translate($attr[11]).'.gif'
array_push($return['mydata'], $day);
}
}
return $return;

And here's the front-end page:

echo " ".$stuff['mydata'][0]['when']."<br/>

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Select Last 7 Days
I have a load of dates in my 'orders' table in this format 2006-10-25 and i need to be able write a query that would select all orders in the last 7 days - in fat it can be any number of days but that's a variable from a select menu. what i can't work out is how to write the query :

SELECT * FROM orders WHERE ord_date ..(is between x days ago and today)?

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Adding 7 Days
I have been tearing my hair out trying to work out how to add 7 days onto the current date. This is how i am calcualting the current date: PHP Code:

// Set the timezone for getting the currrent local time
    $timezone  = +9;

Code:
<input type="hidden" name="date" value="<? print gmdate("Y/m/d @ H:i:s", time() + 3600*($timezone+date("I"))); ?>">

This is being stored in the DB like this: Code:

$SQL = $SQL . " date_posted DATETIME NOT NULL default &#55612;&#57200;-00-00 00:00:00', ";

So, what I am trying to do is create a variable called "Expiry Date" which I want to be $date + 7 days .

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Days Remaining
I want to find out number of days remain from birthday(any other day).

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Days Of Week In App
recommend for a best approach to populating a Days-of-the-Week table in an event-scheduler app? in my particular case, each day of the week relates to a daily drink-special for a bar. i'm trying to figure out my order of dependencies. here's a snapshot of my tables

if i am going to add an event,i have to have it on a day of the week. that day of the week needs to have it's specials populated in order for it to exist in the Table. so, how should i go about "forcing" the Event Scheduler App User to first populate the Days-of-Week table so that when she adds data for an event, the dayys of the week will be available to input into the Event table?

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Strtotime With Days
On this - "next Thursday" is that next thursday or the next thursday ie: on wed will it show tomorrows time or the next week? PHP Code:

<?php
echo strtotime("now");
$timestamp = strtotime("now");
echo "  ";
$str = date('l dS of F Y h:i:s A', $timestamp);
echo $str;
?>

<p>

<?php
echo strtotime("next Thursday"), "";
$timestamp = strtotime("next Thursday");
echo "  ";
$str = date('l dS of F Y h:i:s A', $timestamp);
echo $str;

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Days Miss For The Day X
I want to do a script that I show me how many days miss for X. date I tried of the following form:

<?php
$date_today = date("m/d/Y");
$date_final = date("m/d/Y", mktime(0, 0, 0, 04, 20, 2007));
echo $data_final - $data_today;
?>

But the value always returned is zero.

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Hours To Man Days
I know this is prob easy but i've looked around and can't find what i am looking for, plus i'm a little bit of a newb. I have a group of total hours for a bunch of workers,, i.e each is like 280 hrs and i need to display these set of hours in another way, i need to display them in total man days instead and a man day for me is 6.5 hours now i know i can just divide 280 by 6.5 in php but that gives me something like:

43.076923076923076923076923076923 i need it to output in a format something like 43 days + 1 hour (or minutes if less than an hour)

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Days Ago Calculation?
<?php
$month = 10;
$day = 17;
$year = 2006;

$days = (mktime(0, 0, 0, date("m"), date("d"), date("Y")) - mktime(0, 0, 0, $month, $day, $year)) / 86400;
echo $days;
?>

-> Take the seconds from unixtime now, minus unixtime date, split by seconds in a day = amount of days ago Problem is, the output is: Code:

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Working Days
I need to setup a script to run on the FIRST WORKING DAY of each month. I will have the script running as a cron. I was thinking the easiest way of doing this would be to have a bit of php inside the script that detects to see if the day is the first working day of the month and just run the cron every day.

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Getting Total Days.
We have a notice form which allows people to tell us if they're going to be for a long time, containing the start day/month/year and end day/month/year. Code:

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Date + 4 Days
I need a script that reads the current date on server and computes an additional 4 days to display a date. e.g. today 29/12/05 + 4 days, the script would display 02/01/05 (or similar depending on formatting).

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How Can I Add 7 Days To Date ?
How can I add 7 days to this date ?

$today = date('M-j-Y');
echo $today;

Also trying to do this..

what I am trying to do is if a person cant go into a certain area for 7 days, and trying to figure out how many days he has left before he can get in..

I add the time in the db by using time()

HTML Code:

$checkdate = (time() - 604800);//todays date - 7days
and to get the time from db here is the variable:
$enterdate2

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How Do You Print A Date 7 Days Ago Please?
I have this code:

$today = getdate();
$month = $today['mon'];
$mday = $today['mday'];
$year = $today['year'];

echo $year-$month-$mday

which prints out the date today (2001-10-26).

How do I get it to print out what the date was 7 days ago?

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Number Of Days Interval?
I need to calculate the number of days between two unix timestamps. I.e., if they are from the same day, the interval is 0, if $then is tomorrow (where $now is today), the interval is -1, if $then is yesterday, the interval is 1, and so on. Here's my code:

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