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Can't New Page To Open Using Button


Here is the code I have. Does anyone see anything wrong with it? It won't go to the url when clicked. Code:




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2. how would I get the record id after I store the new record?

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Code:

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if($_POST['myradio'] = "Currently In Place") {
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if($_POST['myradio'] = "Required Essential") {
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file name: index.php

echo "<form action='swversion.php' METHOD=POST>";
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echo "<INPUT TYPE=HIDDEN NAME='entry' VALUE='.'>
";
echo "<input type='submit' value='List Software' class = 'formstyle'>";
echo "</form>";

I wanted to add something to this little form code; How do i redirect this index.php, once I click on the submit button it will take to me swversion.php as you could see that my action is doin that. I want that to happen after 5 secs or right away. As soon as hit the button, I want to that page to go back to this index.php again.

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I'm new to using PHP so please bear with me.

I'm trying to create a hyperlink that will open a random Flash page so that users will see a different flash module each time. Here is some of the code that I wrote but I'm not sure if it'll work since I'm not very good at coding. Oh yeah, I'm not using a database either.

// random_menu.html
<head>
<?php
$i = rand(0,3);
?>
</head>
<body>
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---------------------------
// random.php
<head>
<?php
$i = $_post["i"];
if ($i = = 0){
$value = "a";
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else if ($i = = 1){
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...etc.
</head>
<body>
<object>
<param name="movie" value="$value">
<embed src="$value"></embed>
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Please help if you know how to do this.

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I have a form which takes user input. On submit, the form will run a
php script that will create a new text file using the user input.

I want this text file to popup or open in a new page. The problem is
that when the page opens it still shows the old text file, i need to
hit refresh for it to show the last user input.

the html file (greatly simplified):
<html><head>
<title>Untitled</title>
</head>
<body>
<form action="action.php" method="post">
<p>Title: <input type="text" name="Title" /></p>
<p><input type="submit" /></p>
</form>
</body>
</html>

The php file (simplified as well):
<?php

$spot_code = $_POST['Title'];

// Open the file and erase the contents if any
$fp = fopen("myfile.3dml", "w");

fwrite($fp, "<TITLE NAME=" . '"'. $spot_code .'"'. " />
");

fclose($fp);

//redirect
header( 'Location: http://localhost/mytest/myfile.html' );

?>

the text file, myfile.3dml is embedded in myfile.html (it requires a
plugin to view - it's a 3D world). When myfile.html is opened it
displays myfile.3dml but it needs to be refreshed to show the current
input.

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I've started creating scripts that allow for one page to have a form that data can be added to. A second page that allows some one else to view all the submissions that have been entered. This page also creates a submit button for each entry.

Now what I need to do is make it so that only the entry for which the submit button is connected to is carried over to a third page.

At this point using variables, each button gets a different name and value such as, button 1, button 2, button 3, ...

When I click any of the buttons all the data from all the submissions get carried over to the new page instead of only the data that that button goes with.

How do I write the code on the third page to carry over just the data that the button I click is related to?

I'm using a flat file for the data entered into the first page.

Glenn

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I have read you can solve the back button problem with the page expiration by using GET method instead of POST. When I use the GET method with form data, it doesn't work.

I have a page with a dropdown submitting to a page getting the variable via POST. Then it links to another page, and I want them to be able to come back to the second page. When I use GET instead of POST I get an error.

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I have a page with Dropdowns that are linked to a database.
After selecting one of the options and going to the next page, it will display the results of that dropdown item as pulled from the database.

If a user hits the back button, then selects a different option and hits "submit", what is listed is the results of the first selection AND the results of the second selection.
Is there a way to either:
1. Refresh the page upon hitting the back button on the browser
2. upon hitting the back button, the browser forgets the selection previouslly made.

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I have Windows XP&IE6.0.2... (SP1).

I'm coding one project with PHP.
I get "Warning: Page has Expired" when I try to get back to the "POSTed
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Better explanation:
- Pages are:
* Page A: Front-page
* Page B: Page where is www-FORM

#1.) From Page "A" I move to the page "B" by clicking link on page "A" and I
fill the form's fields
#2.) Then I click SUBMIT-button and I moved back to the page "A"
#3.) I move to the page "B" by clicking link on page "A"
#4.) I click "BACK"-button from browser
#5.) I got "Warning: Page has Expired"

I want that when I click BACK, I will be moved to the page "A" straightly
without warning
(of course then post-data can't get re-sent)

Got any idea how in PHP I can prevent this warning?

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Disable The Submit Button On A Php Page After It Has Been Clciked.
How can i disable the submit button on a php page after it has been clciked. I understand that php is server side, but can some script be sent to the page to prevent the submit button being clicked more than once?

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How do I setup a page when you open a drop down menu of options, select an option and then an image on the page changes to the selection you landed on. Code:

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Here's the code PHP Code:
<?php

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Here is an example of my code. PHP Code:

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