Tracking Forums, Newsgroups, Maling Lists
Home Scripts Tutorials Tracker Forums
 
  HOME    TRACKER    PHP




Code Returning False Mysql Result


I'm working on code which will allow users to "rate" something, for instance, on a scale of 1-5. When they click on a star (1-5), it sends them to the following PHP script, with ?rid=&rating=

rid is the id of the item they are rating, and rating is the integer 1, 2, 3, 4, or 5. Problem is... even with an empty db table, it returns "Rating added successfully." - but doesn't add anything. If I add a row with uid=1 rid=2 and rating=3, and am logged in as uid=1, it still says "Rating added successfully.", and does nothing. It SHOULD HAVE updated the existing row and told me so. Code:




View Complete Forum Thread with Replies

See Related Forum Messages: Follow the Links Below to View Complete Thread
Returning 1 Result From MySQL
I know the usual way of receiving results from MySQL, useing a while loop e.g.

$sql = "SELECT * FROM users WHERE email='joe@hotmail.com'";
$result = mysql_query($sql,$connection);
while ($row = mysql_fetch_array($result)){
echo $row["firstname"];
echo $row["lastname"];
echo $row["email"];}

BUT, if I know they only 1 result is going to be returned, is there a way to do this without using a while loop? So if I only wanted to get only the firstname of the person with email joe@hotmail.com. can I do this without a while loop or do I have to use one?

Script Not Returning Correct Numerical Result
I am working on a script to calculate returns on bets. This involves entering odds, stake etc. The problem I am having is with adding a new element into the calculation. In betting their is something called a Rule 4. This occurs in some races and diminsihes the retrun but there is no need to go into details.

Basically, here is how it works: There is a race with odds of 2/1 and a rule 4 of 20 cents is in place. With the betting rules this means that the odds must be multiplied by 1 - rule 4. In this case the rule 4 is .20 so 1 - .20 = .80 You now have to mulpiply the odds by .80 We only multiply the first number os in the case that is 2 (for a 5/1 bet it would be 5 etc)

.80 * 2 = 1.6 is the correct answer. This calculates ok in part of my script but when it gets to the second part on the same page it is returning 1.28 instead. PHP Code:

$result = $stmnt->fetchAll(); Returning Duplicate Keys For A Single Query
For some reason when I do a fetchall on a PDO query the array returned
has duplicated keys. see below.

Returning Value While Still Executing Code
Anyone know of a way to return data to a browser and then continue processing code. For example in classic ASP they have:

<%
Response.write('THE BROWSER CAN SEE THIS');
// sending final response to the browser
Response.end;
// this will still execute even though the browser no longer is waiting for a response
my_function();
%>

I would like to immediately return a value to the browser and then run cleanup code without the browser having to wait. When I use the exit() or die() or return() functions in PHP it will end the code right at that point which is great because the browser gets a response back quickly but the remaining code never gets executed.

Returning A Script Of Code As A String In An Array?
The below code is part of a pagination script in a function. I want to return this section in an array value but I am not sure how its done. I included what I have been trying.. Code:

Code To Make Table Rows Of A Result Appear In Alternating Colours...
How can I get it so that when I run a search, and the results come back in table format, the rows are alternating colours, like on Devshed's forums? I believe there was some code here some time ago saying how to do it..

Mysql- Returning First 200 Characters?
how do i return the first x amount of characters from a field in a mysql database?

PHP-MySQL: Returning ID When New Record Is Made?
Let's say I create a new record in a table like this:
mysql_query("INSERT INTO table (col1) VALUES ('example')",$conn);

....that had an auto-incrementing, unique identifying column named "ID"
that would be populated with a unique number upon insertion...

How can I get the unique number it assigned to that record returned for
futher use?

MySQL Query Not Returning All Results
I have a user table in the DB, for example:

+---------+----------------+-------------------+
|     uid     |     username     |       firstname       |
|----------+----------------+------------------+
|       1     |       cobby        |       Andrew          |
|       2     |       admini        |     test-account    |
+---------+-----------------+------------------+

If, in phpMyAdmin, I query:
   SELECT `username` FROM `users`;

It will return results correctly (cobby and admini, respectively).
But if I make a simple PHP script, such as:

<?php

mysql_connect('localhost', 'cobby', 'dbpass');
mysql_select_db('testdb');

$query  = mysql_query('SELECT `username` FROM `users`');
print_r(mysql_fetch_assoc($query));

?>

It only returns:
Array ( [username] => admini )

Why does it only return the second result? I have a feeling I'm doing something really silly, but I looked over this test script and its got me stumped.

Returning An Array Indexed By Numbers With MySql
Anyone know how to get an array indexed by numbers (i.e. - NON - Associative)? Seems like it should be able to be done with a function - but I haven't been able to find one.

MySQL Query Returning Empty Column
Here's my code:

$query_get_machine = sprintf("SELECT machines.ID, machines.NotifyID, machines.Name, notify.ID, notify.`Data` FROM machines RIGHT JOIN notify ON machines.notifyID = notify.ID WHERE machines.ID = %s", GetSQLValueString($colname_get_machine, "int"));

Can anyone tell why the notify.`Data` column might be returned empty? All others display as they should.

Error Using Header("", FALSE) To Show Multiple Images From MySQL Db
Many people seems to have problems when displaying multiple images from their database (mySQL db). Often you can read error statements like "Header already sent out ...". To solve this, people often propose to use include files.

To keep the scipt it would be nice not having this problem, being able to sent out multiple headers to a browser without getting these error messages. In the PHP4 manual, we can read an option that can be added to the header statement, Header("xxx",FALSE). It would enable multiple headers to be sent out.

For instance the following statement:

while ($product = db_fetch_object($result)) {
header("Content-type: pv($product->filetype)",false);
echo pv($product->image)"
}

However, it doesn't work. Anybody has any idea why? Does anybody use this option FALSE with success?

Getting Result From Mysql
I am using this code to get some data from a mySQL database. Which seems pefectly valid to me. Here it is: Code:

MySQL Result Resource
I want to build a function that, depending on the input, will either return the results from a MySQL query or do something else and return one of several messages.

My problem is checking the return value to see which is returned. Is there a php function that checks a variable to see if it is a valid MySQL result resource? I looked through the manual and couldn't find anything.

MySql Result In Textarea
I have a script to display mysql query results in a table. I'd like to
display the results in a scrollable textarea. Is there a way to do
this?

Total Result Php Mysql
PHP Mysql
limit the result to 5
I can display the 5 results using a do & while which it ok.

I want to list the total or all the results without using a do or while

this is so I can combine the results and remove duplicate words from the
total results

I.E.
Do & While
row result
1 this is the top
2 this is the bottom
3 this is the middle
4 this is the end
5 this is the finish

This is what I want to do:
result
this is the top this is the bottom this is the middle this is the end this
is the finish

modified result::
this is the top bottom middle end finish

Invalid MySQL Result
I keep getting the following two errors:

Warning: Supplied argument is not a valid MySQL result resource in /home/xxx/public_html/articlepro/newarticle.php on line 75

Warning: Supplied argument is not a valid MySQL result resource in /home/xxx/public_html/articlepro/newarticle.php on line 84

Here's the code which I think is causing the problem. PHP Code:

Size Of Mysql Result Set
How do I find the size of a mysql result set using php.

MySQL (DB) Result Sorting
I'm doing is taking results (fetching rows) from my mySQL database. But what I want to do is sort the results according to last name. So basically the table structure looks something like this:

id (primary key)
fullname

A example rows could be:
1
John Smith

2
Mary Jane

Now what I want to do is sort the results in PHP based on last name. I'm using the Pear DB for connecting to my mySQL database. Based on the example rows I gave, Mary Jane would go first, and then John Smith. How would I go about doing this? I was beginning to split the result based on spaces, and the last word to explode, but how would I truly do this?

Modifying MySQL Result - But Not The DB
How can I modify a MySQL data set returned by mysql_query? I am
basically doing a while loop over the rows, changing one field, and
then doing a mysql_data_seek back to the beginning of the set before
returning it. However, later calls to mysql_fetch_assoc still return
the orginal data, meaning that (I assume) I am changing a copy of the
data rather than the result set itself. Taking the reference (i.e.
$record =& mysql_fetch_assoc($result);) did not help.

I have read a large quantity of the posts in the php.net site,
googled, and read my PHP books - but have come up short on this one.

Yes, I know it's better to simply modify the DB. However, I'm working
with an existing code base which is very complicated, and want to
cherry pick one very well tested feature by making a change in the
result set only under special circumstances.

Substr() With A MySQL Result?
I am trying to limit the amount of text exhoed from a MySQL database column. From reading around it appears the substr() should be able to do this Code:

Mysql Result Into Array?
I have a shopping cart script sending info to a processor. I need to send the qty's and item name's in some sort of string via a single variable to the process form.
i.e. (3) Hipster Turnips, (6) Butter Milk Baby Brains, (2) Super Freaks Code:

Result From Mysql Into Foreach?
when using mysql_fetch_array($result)

I usually toss that into a while loop like so

while($row = mysql_fetch_array($result)){
...
}
however I was wondering if there was a way to put it in a foreach statement like so

foreach(mysql_fetch_array($result) as $row){
...
}
Is that legit? Will this work?

Linking To A MySQL Result
I had it the other day but now altered the code for my real database and it stopped working.

Here is the first page which lists the 10 most recent news stories:

<?php
require ('get_connected.php');
$sql = mysql_query ("SELECT title, story_id FROM news ORDER BY story_id DESC LIMIT 0, 10");
while ($row = mysql_fetch_assoc($sql)){
echo "<a href='view.php?id={$row['story_id']}'>" . ucwords(strtolower($row['title'])) . "</a><br>";
}
?>

And here is the page that should be displaying the news story based on story_id selected by the user.....

Speeding Up Query/code (query Within Result Set)
I'm looking for ideas on how to speed up this script. Basically it finds all the zip codes in a zipcode table, then looks for all the records in another table with those zip codes.

Right now it finds all the zips then within that WHILE, it looks for a record in another table with that zip: PHP Code:

Using MYSQL Result To Send Mail
I have wrote a program to load a number of email address from the MYSQL database. And I have use
"$mail = mysql_query("select email from user;",$link_ID);

Now, I want to use mail() to send email to those e-mail account I got. What should I do for this?

Date Formatting From Mysql Result
always in the past I have done my date formatting from the query like so:

DATE_FORMAT(dateField, '%W, %b %e, %Y') AS realDate

I have tried formatting the straight date result with PHP like so:

having fetched results with mysql_fetch_array,

$newDate=$result["dateField"];
$formattedDate=date($newDate, 'm/d/y');

This doesn't work and simply returns the unformatted date as it is stored in the database.

Invalid MySql Result Resource
I have written a php script to search a MYSQL database and with the line:

$result = mysql_query ("SELECT * FROM table1
WHERE first_name LIKE '$first_name%'
AND last_name LIKE '$last_name%' " );
The next line,
if ($row = mysql_fetch_array($result)) { , gives me the error message

"supplied argument is not a valid MySql result resource"

Performance Of Fetching MySQL Result
Is there a real performance difference between mysql_fetch_array(), mysql_fetch_object(), and mysql_fetch_row()?

Display Of Mysql Table Result...
I have a mysql table of articles with fields:

- recordID
- department
- articleTitle
- articleText

Using PHP, I'm attempting to get the results of the table to display as follows:

Department 1
- articleTitle 1
- articleTitle 2
- etc....

Department 2
- articleTitle 1
- articleTitle 2
- etc..

I figure I should use a while loop but can't figure out how to exit/reset the loop when a new 'department' is encountered in the $result.

Replacing Array With Mysql Result
I wanted to repalce the following line of code $data = array(40,21,17,14,23); with

for($i=0;$i<$numrows;$i++)
{
//print(mysql_result($result,$i,2));print("<br>");
array_push($data,mysql_result($result,$i,2));}

where mysql_result($result,$i,2) is the value and when i print it displays the values. But $data array is the Y axis value for drawing a chart. Here I wanted to replace the hard coded value with values from mysql but the second code does not function. Does anybody have idea how can I replace the $data array or what may be the problem with my coding The first one works but the second one does not work but in both cases it does not display any error.

Same Mysql Query Doesn't Always Return A Result
We have no access to a mysql NG on my provider's server, so we ask here:

We have a long query (long in text) with a UNION between 2 select.

We have been informed that some times the query doesn't return any result.
We have tried on our server and we always get a result. BUT, trying on the
hosting server, many times the query doesn't return any result and doesn't
get any error.

Any idea ? does Union have any problem ? how to check if the query failed ?
My hoster said that sometimes the table can be locked (if the server is
overloaded) and then mysql doesn't return any result, but this seems to me
an aberration.

the query takes about 0.0050 sec to execute when it doesn't return any
result, and 0.030 when I get results

Mysql Search Close Result
I've to find in a table the "closer" result given some text.

Here is a little example:

given the text "Batman socks" I've to find the best matching result in
choices like:
-"mickey socks"
-"robin socks"
-"batman black socks" ->this should be found
-"batman wallet"
-"batman"

or given the text "leather shoes" I've to find the best matching result in
choices like:
-"socks"
-"shoes" ->this should be found
-"pants"
-"shirts"
-"leather wallet"

Mysql Problem Understanding Result And Id?
I can't understand why the output from this is not &#397;'?

$query = "SELECT * FROM contacts";
$result = mysql_query($query);
echo mysql_result ($result, 7, "id");

I also tried adding "ORDER by id" but I still can't get it to echo 7.

MySQL Result Printing In For-loop
I have a script that count and print every week in a selected year. Now i want to connect this to the returned result from a MySQL query. Code to explain what I am trying to accomplish: Code:

How Do I Return Result Of Mysql Row Deletion
The data entered by a user on form 1 on page1.php is posted to
delete.php to remove that row from a table. After the SQL operation
the user is returned to page1.php.

How can I determine the success or failure of the SQL operation so I
can display an appropriate response message to the user?

Different Result For MySQL And PHP String Comparison
I have issued an SQL statement "SELECT email FROM mailing_list ORDER BY email ASC";
By right the order of the email should be sorted from smallest to largest. However I got different results when I used record that was ranked higher to compare against record that was ranked lower. I got opposite results. Code:

Mail A Set Of Addresses From A MYSQL Result
I'm populating a field in MYSQL that collects email addresses for a certain topic and saves them like this:

mail1@mail.com|emailaddress2@mail.com|email3@email.com

- Basically what I'd like to do is explode the data, and set up a mailer from PHP that informs each of the addresses individually that there has been an update to the topic.

I *don't* want each of the mail addresses to be visible to all the recipients on the list, so simply inserting the data into the TO: field won't do, because then all the addresses are visible, causing security concerns. Code:

Allow The User To Sort A Mysql Result
So what i got going on is a database that has, things about a video game, including the image location. what i want to do is have a nav bar up top, so the user can select a differnt way of sorting the mysql result, from like ASC to DESC, or sort by genre.

MySQL Result Can't Be Returned From Class Method.. ?
I've been messing around with objects and classes lately and can't figure out why this wont work.

I have index.php which uses the pbMySQL class (pbMySQL.class.php) and methods:
Code: include("lib/pbMySQL.class.php");

$db = new pbMySQL;
$db->pbMySQL_open("localhost","user","pass");
$db->pbMySQL_useDB("database");

// $q=$db->pbMySQL_query("SELECT * FROM pbn_news ORDER BY id DESC");
$q=mysql_query("SELECT * FROM pbn_news ORDER BY id DESC");

if(isset($q)) {
while($row=mysql_fetch_array($q)) {
print $row['name']."<br>
";
}
} else {
print "query returned FALSE";
}

$db->pbMySQL_close();

My problem is that when I use the first query method (which is commented; uses the pbMySQL_query() method) I do not get the mysql result returned, but if I use the same query without the method, I get the result. Here is the method from my class:
Code: function pbMySQL_query($query) {
if(!isset($this->conn) || !isset($query)) {
print "Error : argument(s) missing.<br>
";
} else {
$this->query = mysql_query($query,$this->conn) or die("Error : query failed.<br>
mysql said: <i>".mysql_error()."</i><br>
");
if(isset($this->query)) { return $this->query; } else { return FALSE; }
}
}

The method returns FALSE and I don't understand why. Is it something in particular I have to do different when using a class?

How Can I Populate A Listbox With The Result Of Mysql Query?
I would like to populate a listbox with the result of a mySQL Query.

Error Message - 0 Is Not A MySQL Result Index
Could anyone explain what this might mean?

Warning: 0 is not a MySQL result index

I have a simple form set up where a user types in a keyword and then a page is displayed based on the keyword. See below:

HTML page:
<html>
<head>
<title></title>
</head>
<body>
<form action="submitform.php3" method="GET">
<p><strong><font face="verdana, arial, ms sans serif" size="1">id#</font>:</strong> <input
type="text" name="keyword" size="15" maxlength="25"> <input type="submit" value="Go!"> </p>
</form>
</body>
</html>

submitform.php3 page:
<?php
mysql_connect ("localhost", "username", "password");
mysql_select_db (dbname);
$result=mysql_query("SELECT $url FROM table
WHERE keyword LIKE '%$keyword%'");
list($url)=mysql_fetch_row($result);
?>

The concept is really simple. A user types in an keyword and that page is displayed. There is a database set up with a table that has two columns. One is "keyword" and the other is "url" For example row 1 the keyword is abc, and the url is http://www.abc.com.

How To Get Mysql Query Result Into Temp. Txt File
I did a lite search in the archive but didn't find anything specific to my problem. Here is what I am trying to do:

I've got a table with about 25k entries of company addresses. I need to be able to pull specific data out of the table and put it in a temporary text file and then display the result in the browser for the user to save locally.

The query part and the format of the data is all simple enough but I am having trouble figuring out how to get the data from the query into a temporary text file and then displaying that file. here is what I whipped up but it obviously doesn't work: Code:
<?
$tmpfname = tempnam("/path/to/file/", "FOO");
$list = mysql_query("select * from FH_LIST where State='AK'");
while ($list_results = mysql_fetch_array($list)) {
$data = blah blah blah;
fwrite($tmpfname, ".$data
");
}

fopen($tmpfname, "r");
fpassthru($tmpfname);
?>

I get an error message saying:
Warning: Supplied argument is not a valid File-Handle resource (referring to $data).

Setting A Maximum Limit On A Php/mysql Result?
I am using PHP and MySQL to do this script. I want to have a table that contains only numbers for data and then add them all up as a result to display and that I have accomplished with no problem and then I want to display a percentage of that number to the public however that also I have accomplished with no problem using round()...

The problem is I am trying to set a maximum number that it displays.

I want it to display 1-500 no matter what the number is or the decimal it may have is provided it doesnt exceed 500 but once it does I want it to display 500 as the limit so even if it is say 674 I want it to only display 500. How would I go about doing this?

The sql I am using for the adding is SELECT SUM which works just fine and I am using round( $total_number *.15, 2) to display the percentage number of 15%.

PHP4/MySQL Formatting Result Set Output
I am currently coding a Photo Gallery project in PHP 4 and using MySQL to store information about the uploaded photos. My problem is that I am trying to get the images to be displayed in multiple columns accross the page, say 4-5 columns of small thumbnail images instead of all in one column as I have at present.

Warning: MySQL: Unable To Save Result Set In
I'm running PHP/MySQL/Apache on my home system on Windows for testing purposes. As a run a specific query, I get this error:

Warning: MySQL: Unable to save result set in C:apachehtdocsfinal.php on line 129

Warning: Supplied argument is not a valid MySQL result resource in C:apachehtdocsfinal.php on line 132

I know the second result means the specified query cannot be found, and I'm guessing for some reason MySQL cannot save the query. Here is my code. PHP Code:

If Result Of Mysql Query Is Only One Row/column, Why Use An Array?
If I'm doing a very specific select statement, which I know will only ever return one value, can I get that resulting bit of data without storing it in an array or object?
If not, is mysql_fetch_array() the fastest method for getting this one value?

Mysql+php Newbie: 2 Tables As 1 Result To Count... How To?
I need to check for username in 2 tables (user_basic and user_temp)
before I can alow incoming user to register new username, well, here is
what I had before I'w created temporary table:

$uname_check = mysql_query("SELECT uname FROM user_basic Where
(uname='$uname')");
if (mysql_num_rows($uname_check) > 0) { ...

but now, that mysql_num_rows isn't "working"...
now I have this lines:

$uname_check = mysql_query("SELECT uname.user_basic,uname.user_temp FROM
user_basic,user_temp Where (uname='$uname')");
if (mysql_num_rows($uname_check) > 0) { ...

and I'm geting this worning and my script fails in checking:
"mysql_num_rows(): supplied argument is not a valid MySQL result
resource in..."


Copyright © 2005-08 www.BigResource.com, All rights reserved