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Counting Records In MySQL


I've been trying to write a page that checks the database and counts the number of records and if the number is less than 3000, it loads page X, but if the number is equal to 3000, it loads page Y.

I know this should be a simple if/else statement but it's the checking and counting that I cannot get to work. 




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I have a data table which has 8 fields:

secure_id_1_L
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secure_id_8_L

each field hold YES or NO

I want to be able to count the number of "yes" fields in each record. This is what I have so far: Code:

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Ok, I am trying to count the number of records in one of my tables. Seems simple. BUT! its not working. It returns a 2 no matter how many records are in there.

Heres the code.

<?php
$sql = "SELECT count(*) from cam";
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I would think this would work.
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Counting Rows In Mysql
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<?
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Ive also managed to have the submition page display what they submitted by using the count(*) function, their story would be the last to be submited , so it pulls that from the database and displays it.

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So how do iterate through all the records in the database, and display each one?

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Problems Updating Records In MySQL With PHP
Sorry to ask what is probably a simple answer, but I am having problems
updating a table/database from a PHP/

PHTML file. I can Read From the Table, I can Insert into Table/Database, But
not update. Here is a copy of the

script I am using. I do not know what version of MySQL my host is running
nor do I have Shell Access to it. I

would like to setup a script so my website users can update thier records
without my intervention.

Also you may send replies to stevennyoung@yahoo.com

Begin Script

<?php
$db = mysql_connect("localhost", "username", "password");
mysql_select_db("databasename",$db);

if ($id) {
if ($submit) {
$sql = "UPDATE tablename SET
EMail='$EMail',Username='$Username',Password='$Pas sword',Item=

'$Item',Price='$Price',URL='$URL' WHERE Username='$Username'";
$result = mysql_query($sql);
echo "table Updated.";
} else {
// query the DB
$sql = "SELECT * FROM tablename WHERE Username='$Username'";
$result = mysql_query($sql);
$myrow = mysql_fetch_array($result);
?>
<form method="post" action="<?php echo $PHP_SELF?>">
e-Mail Address:<input type="Text" name="EMail" value="<?php echo
$myrow["EMail"] ?>"><br>
Username:<input type="Text" name="Username" value="<?php echo
$myrow["Username"] ?>"><br>
Password:<input type="Text" name="Password" value="<?php echo
$myrow["Password"] ?>"><br>
Item:<input type="Text" name="Item" value="<?php echo $myrow["Item"]
?>"><br>
Price:<input type="Text" name="Price" value="<?php echo $myrow["Price"]
?>"><br>
Item URL:<input type="Text" name="URL" value="<?php echo $myrow["URL"]
?>"><br>
<input type="Submit" name="Update" value="Update table">
</form>
<?php
}
} else {
// display list of articles
$result = mysql_query("SELECT * FROM tablename",$db);
while ($myrow = mysql_fetch_array($result)) {
printf("<a href="%s?Username=%s">%s %s</a><br>
", $PHP_SELF,
$myrow["Username"], $myrow["Item"], $myrow

["URL"]);
}
}
// Close DB Connection
mysql_close()
?>

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I have set up a target page to pull information out of a mySQL database to populate the page. The problem is that it is only pulling from the first record and not the record specified. What do I have to do to pull from a specific record? I am using Dreamweaver MX to administer the site on WinXP using PHP if that information will help.

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PHP Mysql Outputting Records Repeatedly.
I have not messed with php/mysql in a while and have come up with a
problem I have run up against before but cannot remember the solution.
See the following page:

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how many records will a MySql database hold?

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Insert All Records From .xls File To Mysql Using Php.
I need to insert all records from .xls file to mysql using php. How could i read all records from php ? (the thing is no need to convert xls file to csv file).

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Sensible Method Of Inserting Records In To MySQL
I have users using a third party windows application. They can export data
from this application directly to a text file (CSV). So far as I know,
there is no way to make this application talk directly to the MySQL server.

We're talking thousands of records here - it's not practical to have an HTML
form handled by PHP which inserts the data to MySQL... or is it??

What I thought about doing was to have them export the data to the CSV file
& then upload it to the web server using FTP.

Once uploaded, I would have
them go to a page with a PHP script which would run the command to import
the data to MySQL. PHP can run shell commands, as I understand it from the
manual. Perhaps this would be a bitch on Windows, though. Code:

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I am very new to MySQL and have built myself a small database for website update requests. The thing is Instead of having a "enter the record id # and press edit" I want to have a small edit icon at the end of each record I am displaying in a table. I've got the table data box setup at the end of the record and this is what I put in it: Code:

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Very Slow MySQL SELECT Query After 11 Records
I have a very weird problem

I moved my database to new IIS 6.0 + PHP 4.3 + MySQL 4.0 setup. I tried to check with myphpadmin if everything works fine, but I couldn't browse my table (125 records). I used SELECT option and found out that SELECT query up to 11 records is ok, but after that, even if I choose to limit query to 12 records, it just hangs.
I tried selecting from the beginning of the table and from the middle - same thing, but when I run query localy on mysql console, everything works fine

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I have a very urgent question. I am using php and mysql.
Say I have a database full of names and email addresses. I want to do a query that when you type in the name or partial name, mysql will only show a name once, even if it is in the database 200 times. Then I want to click on that name and have mysql show the 200 email addresses associated with that name (which I know how to do). See below:

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I am working on a memebship section for a website and I am trying to set session variables from records in a MySql database when the user logs in. I think I am missing something because try as I might the just don't work!

The sever I use had Glabal variables turned on, dont know if thats an issue in this case.

Heres the code on the check user page:

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I am using this very slightly modified function found here:
http://us2.php.net/mysql_fetch_object
to make mySQL rows into objects of type $classname:

// This takes db result rows and makes real objects of $classname type
function &buildObj($result, $classname) {
while($row = mysql_fetch_assoc($result)) {
if ($row === null) return null;

/* Create the object */
$obj =& new $classname;

/* Explode the array and set the objects's instance data */
foreach($row as $key => $value)
{
$obj->{$key} = $value;
}
$objs[] = $obj;
}
return $objs;
}

This is called by a retrieve: function:

function retrieve($where) {
echo $query = "SELECT * FROM $this->table WHERE " . join(' AND ',
$where);
$result = mysql_query($query);
$rows =& buildObj($result, get_class($this));
mysql_free_result($result);
return $rows;
}

The problem I am encountering is that if I do this in my script:

$listing = new Listing;
$listings = $listing->retrieve(array('row > 1') );
foreach ($listing as $aListing) {
$aListing->address='xxxxxxxxxxxxx'
}
foreach ($listing as $aListing) {
print_r($aListing);
}

The value in $aListing->address is unchanged.

However if I do this:

$listing = new Listing;
$listings = $listing->retrieve(array('row > 1') );
foreach ($listing as $aListing) {
$aListing->address='xxxxxxxxxxxxx'
$newArray[] = $aListing;
}
foreach ($newArray as $aListing) {
print_r($aListing);
}

I see the update values in $aListing->address .

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