PHP :: Create Html Table With Php Result?

Query Result Displayed In HTML Table
I have a few queries that run fine & return the results I'm after. However I am unable to get them to display in rows/columns. I am sure that the results could be passed into a table using html.

$data_p = mysql_query("SELECT * FROM download WHERE dance LIKE '%$search%' OR name LIKE '%$search%'$max") or die(mysql_error());

This displays the results in one long list:

while (list($id, $name, $type,$size,$content, $dance) = mysql_fetch_array($data_p))Â Â {

Â echo "<a href="download3.php?id=$id">$name$dance</a>";
Â }

Anyone?

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Create Html Table
tryin to get a table to add a new td /td for every result from the Db. but can't for life of me figure it out...

the nubers are the results and there are 3 required infos from each entry,(abc)
so if there were 4 results it would have a 4a,4b,4c...

its prob really simple but i cant get it! how would i print it via PHP? Code:

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Create A Data Entry HTML Form For Given Table
I am working on a simple web site updating utility for a web site. Rather than hard code the data entry forms, I would like to automactically generate them based upon the table a user selects to update or insert into. What is the best way to approach this?

for "insert" should I use the MySQL DESCRIBE table command and build a form element for each field according to its data type? for "update" should I use the DESCRIBE command to build the form as above and SELECT statement to populate each element with data, or should I just use a SELECT statement to retrieve the data and use php to determine the field type and choose an appropriate form element?

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Create A Mysql Query That Will Look In A Table And Come Back With The Most Used Phrase In A Certain Cell In The Table?
How can I create a mysql query that will look in a table and come back with the most used phrase in a certain cell in the table?

4|Truck|Chevy
5|Car|Honda
6|Car|Toyota
7|Van|Chevy
8|Car|Mitsubishi
9|Truck|Toyota

I want a print out from mysql to be like this:

Car 3
Truck 2
Van 1

Is there any way to have it count up how many of each unique things there are in a cell in a table, and have it decending from the first one being the highest number?

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Create A Table Say 3 Rows 3 Cols And Put An Include In Each Table Cell
I have been playing with php includes and thought it would be interesting to create a table say 3 rows 3 cols and put an include in each table cell pointing to other sites, i thought make each cell 500px wide and i would have a page with say four news sites from different countries, so i built my table added this in
<?php include("http://www.cnn.com")?>

plus others uploaded it then sat back to watch my master peice in action, but hey guess what! includes dont quite work like that, the sites all loaded under each other and the page was veery wide, and even my nav table include had the same rollover effect as the first site in the includes.

Is there a way this can be done easily or should i forget this idea now, I have no need for this on my site I am just at the start of learning php so have tried this just for education reasons.

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How Create A Temp Table As A Copy Of A Existing Table?
how create a temp table as a copy of a existing table and then update1 field and insert the hole temp table back in the existing table? .....

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Create A Search Result On A File Directory
I am working on a project where I need to take a variable from a form, then match that variable against a directory list and return a modified list of files available that are clickable.

I have created the form - (easy part)
and I have found coding that pulls the directory list.

I am having trouble finding information on how to take that directory list a sort the results based only on the keyword that was typed in.

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Format Table With PHP Result
I have to create some kind of dynamic page, logic is next: i have integer in variable and i need to create certain number of fields based on that int. example
$variable = 6 and I need to have table with 6 fields, 4 in one row and 2 in second....my problem is how to do that, how to get new <tr> when number in bigger than 4.

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Saving A Result To Another Table
I have a script that will print out the results of a table and make a
calculation of a total of one of the columns. See example:

<?php

/* Database connection */
include(MYSQL_CONNECT_INCLUDE);

/* Select all pilots */
$query = "SELECT * FROM pilots ORDER BY pilot_num ASC";
$result = mysql_query($query);

/* Determine the number of pilots */
$number = mysql_numrows($result);

if ($number > 0) {
/* Print roster header
Change this HTML to fit your webpage layout */
print "<table>";
print "<tr>";
print "<td bgcolor=#000080 width=85 height=12
align=left>NUMBER</td>";
print "<td bgcolor=#000080 width=120 height=12
align=left>NAME /
EMAIL</td>";
print "<td bgcolor=#000080 width=130 height=12
align=left>CITY</td>";
print "<td bgcolor=#000080 width=93 height=12
align=left>COUNTRY</td>";
print "<td bgcolor=#000080 width=93 height=12
align=left>FLIGHT
TIME</td>";
print "<td bgcolor=#000080 width=75 height=12
align=left><center>STATUS</center></td>";
print "<td bgcolor=#000080 width=75 height=12
align=left><center>LOG
BOOK</center></td>";
print "</tr>";

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Mysql Table Result
I have a product page which grabs a product, lets say the ID = 1. At the bottom of the page it grabs the 2 latest products created by that user. I would like it to grab the next 2 products in the database instead of the latest. So,

Product 1

Other Products

Product 5 and Product 6.

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Nested MySQL Queries Create Issue With Validity Of Result Index?
I am iterating through a result set to generate a second set of queries but
no matter what I do I get the error

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
resource

even though if I echo the query to the browser and cut and paste it into the
command line I get valid results.

Do I have to store the first result in an array before doing the second set?

while ($i < mysql_num_rows($result)) {
$PIDs[$id]['ClientName'] = $client;
$PIDs[$id]['ProjectName'] = mysql_result($result, $i, 'Name');
$PIDs[$id]['PID'] = mysql_result($result, $i, 'PID');
$thisPID = $PIDs[$id]['PID'];
$PIDresult = ("SELECT * from hours WHERE PID = '$thisPID'") or
die(mysql_error());
$j=0;
while ($j < mysql_num_rows($PIDresult)) {
$PIDs[$id]['PID']['Comments'] = mysql_result($PIDresult, $j,
'Comments');
$j++;
}
$i++;
}
}

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Grab Content From HTML Table And Place Into MySQL Table?
I am in the process of helping a co-worker upgrade some of his old static html pages into dynamic MySQL driven pages. He currently has a lot of pages with huge tables displaying data. Does anyone know if there is a script or class that can convert a table to a .sql file for upload?

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Select Result On Empty Table?
can't remember how to do this, doing a select on a db like so.

$query = "SELECT user_id FROM tool_user WHERE user_name = '$user_name'";
$query = mysql_query($query) or die("eek");

which will work if there is at least one entry in the database table, however how do i return a result id the table is empty? do i need to use @mysql_query($query) and then something after that?

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Display Of Mysql Table Result...
I have a mysql table of articles with fields:

- recordID
- department
- articleTitle
- articleText

Using PHP, I'm attempting to get the results of the table to display as follows:

Department 1
- articleTitle 1
- articleTitle 2
- etc....

Department 2
- articleTitle 1
- articleTitle 2
- etc..

I figure I should use a while loop but can't figure out how to exit/reset the loop when a new 'department' is encountered in the $result.

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Strange Result From Table Query
I have a simple query that I am restricting to the first 4 character, however instead of the first 4 characters I am getting only the characters from the end of the field.

The information in the field resembles: 4285-002

My result should be: 4285

What I am getting is: -002

The following is the code to pull the dat from field 'Dest':
$dest=odbc_result($rs1, 'Destination');
$deststrcount=1;
$deststr = $dest;
$deststr = str_split($deststr,4);
foreach($deststr as $destv){
if ($deststrcount<="1"){
$desttext=$destv;
$destnew = "DEST[1,$deststrcount] $desttext";

$strcount=$strcount+1;
}

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Link Result Table Of 2 Queries
If I have 2 table, I can easily linked them with where something = something. But I have 2 tables that I generated from complicated queries, and now I want to link them together too with where something = something. How will the MYSQL query look like?

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Problem Displaying Result In Table
im trying to display some data in a table (php + mysql) this is the code to create the table Code:

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PHP-MySQL Result Set Truncated In HTML
There is a truncation error of my Web Application using PHP 5.04, MySQL 5.022, and HTML(IE 6.0) whereby the MySQL Result Set is being truncated on the HTML page, even though the CSS Div Page Height is set to 'auto' which is supposed to grow the HTML page height to the size necessary to display the contents within the page.

The query count is correct, but the list is being truncated on the html page. This happens for MySQL Results on some HTML pages but not for others, despite the fact that they all use the same CSS Div. Code:

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Store Result Of SELECT Stament To Be Used To UPDATE Another Table
im trying to update a field of a table which is done through the results of a select statement. I need to be able to a store the results of the select statement which can then be used to determine if an update another table is initiated. This is where i have got so far: Code:

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Creating Table Rows Based On Query Result
I am trying to create a simple table with a fixed number of columns (5) but the number of row will depend on the results of the query. I have tried various examples found here or there and I can't get them to work. Code:

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Recreate The Query For Each Day In Order To Show The Result In A Table
I would like to get a count for every element filled on that day but however i am unsure how to make this query to the mysql db. for example every thing filed on a monday or for each given day of the week may be better. table field is called date and is in datetime format Y-d-m H:i:s

how would i complete this query to get it to look for each even if i had to recreate the query for each day in order to show the result in a table. PHP Version 4.3.11 being used
PHP Code:

Select count (something) as total from database where ?

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Send Mysql Query Result Displayed In A Table
I have just created a shopping cart and I would like to send my user the receipt of there order by email. The receipt is generated by a mysql query and is displayed within a table. I have worked out how to send a html using simple HTML code as my â€œ$messageâ€� variable: $success = mail($to, $subject, $message, $headers);

But I can not get it to send my mysql query result displayed in a table. How can i create the result of my mysql query and make it a simple variable i.e $message.

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Code To Make Table Rows Of A Result Appear In Alternating Colours...
How can I get it so that when I run a search, and the results come back in table format, the rows are alternating colours, like on Devshed's forums? I believe there was some code here some time ago saying how to do it..

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Displaying Last Result From A Mysql Table With A Limit Of 10 Results Per Page
I want to show the last post in a mysql table. And i am displaying them with a limit of 10, i.e. 10 results per page. Now i have a problem figuring it out what would be the starting point of the results display in this case. Code:

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Echo Result Set As HTML Image Source Inside Javascript
I'm attempting to echo an HTML table with images in one cell and data in the other.
The data shows fine but the images do not. When I view the echoed HTML source I have nothing between my "". Code:

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HTML Table From Database Table
I need an html table that outputs all the events in my database table and shows their id number, title, and timestamp. What would be the easiest way to do this? I was thinking something like: Code:

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Create Table Using PHP
use mysql_query ? what's the parameter of string query ?

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Create DB Table
how to create a table in a SQL database using PHP3. I can login via telnet and create a table but that is sorta worthless considering that I'd like to be able to do it via a browser instead. Would someone please post some quick code to point me in the right direction?

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SQL Create Table From Pdf
I would like to use a routine which has as input a pdf form file and returns
the SQL statement to create the table for a SQL database.

Did someone know such a tool?

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Create DB But Not Table
I am still having trouble with WAMP. It will let me create a DB using the command prompt but not tables. This makes no sense because if you can create a database, why on earth would you not be able to create a table in that database. I have looked in the config.inc.php file and it doesn't look like there are any denies. I am stumped on this one.

I have uninstalled WAMP, deleted the WAMP folder, did a search on the c: drive to verify there were no remaining php config files, re installed WAMP, rebooted and tried to go to phpMyadmin. The task is Forbidden. I did this same thing on my home computer and I can get to phpMyadmin, can query tables already there, can create DB's but not tables. I cannot even get a table added with PHP code however, other PHP forms and functions work just fine.

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Create Table SQL
How do I code SQL for creating a table in MS SQL server?

SQL Server giver error - 'Incorrect syntax near auto_increment'

Here's what I have.

CREATE table location( location_ID int not null auto_increment primary key);

Also how do I set up a grant statement?

GRANT CREATE ON dbname.* TO training identified by 'training'

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Create Table Like
WE ARE TRYING TO CREATE A NEW TABLE WITH THE SAME STRUCTURE AS AN EXISTING TABLE AND ARE TRYING:

CREATE TABLE XX LIKE SISTOCK;

AND WE GET A SYNTAX ERROR. WE ARE RUNNING mysql 4.0.2.5.

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Create Table
PHP - I'm trying to create a MySQL table like an existing MySql table. My PHP code is

$query = "CREATE TABLE '".$new_db."'.'".$new_name."' LIKE '".
$old_db."'.'".$old_name."'";
echo mysql_error()." ";

When I run in the browser I get -

You have an error in your SQL syntax near
''forest_client_XXX000001'.'accounts' LIKE
'forest_client_fds000003'.'accounts'' at line 1

The $new_db, $old_db and $old_name all do exist.

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Create A Table From PHP
I'm trying to create a table from a PHP script.[color=blue] >From what I read in my book about PHP and MySQL I[/color] should do something like that:

$sql_query="CREATE TABLE '$num' (
'variable1' mediumint(6)unsigned NOT
NULL,

'variable2' smallint(6)unsigned NOT NULL,
PRIMARY KEY(numero),
)";
First I tried without the 'primary key' and the '' for
the names of the variables. My script was not creating
the table so I decided to add the '' and the "primary
key". It was still not working. Then I've found that
this is working:

$sql_query = 'CREATE TABLE $num ('
. ' `variable1` DATE NOT NULL'
. ' )'

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CREATE Table With PHP Script
I'm trying to write a PHP script that will create tables, so I'm working of a test script at the moment and I've been trying to use some code from a phpBB script to do this as while mysql has a nice mysql_create_db function they have no create_table function, not that I can find anyway.
I can't find a similar problem from searching here either :-(

The code I'm using is below...

<?php
include ("../cgi-bin/connect.inc");
$tables = array ("test" => "CREATE TABLE test (
testing varchar(20),
)");
$result = mysql_query($tables);
if ($result) {echo "YEY";}
else {
echo("Error: " .
mysql_error() . "");
exit(); }
?>

and it returns this...

Error: You have an error in your SQL syntax near 'Array' at line 1

Something simpler such as

<?php
include ("../cgi-bin/connect.inc");
CREATE TABLE test (
country varchar(40) NOT NULL,
UNIQUE country (country)
);
?>

just gives an error on the 3rd line

If anyone can point me in the right direction as to how to create tables with PHP scripts, which I know must be possible as phpBB manages fine.

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How To Create A MySQL Table With PHP?
How to create a MySQL table with PHP?

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MySQL Table Create
Here is the code I'm trying to create the database with (I'm using phpMyAdmin so I just select the file I want to use and press submit and it creates the tables).

CREATE TABLE bips (
banned_ip varchar(15) NOT NULL);

CREATE TABLE messages (
entry_id double(16,4) DEFAULT Ɔ.0000' NOT NULL auto_increment,
name varchar(25) NOT NULL,
email varchar(35) NOT NULL,
icq int(11) NOT NULL,
http varchar(50) NOT NULL,
message mediumtext NOT NULL,
when int(12) NOT NULL,
ip varchar(15) NOT NULL,
UNIQUE entry_id (entry_id),
PRIMARY KEY (entry_id));

------------------------
phpMyAdmin gives me an error with that, (none of those tables exists btw)... the error is

MySQL said: You have an error in your SQL syntax near 'when int(12) NOT NULL, ip varchar(15) NOT NULL, UNIQUE entry_id (entry_i' at line 8 .

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Create A Table Dynamically
I am trying to create a table dynamically- meaning that a user will be able to add or delete rows via an admin tool. For now, the number of columns will be a fixed number. I figure I can store each row of information in a database and then keep some type of index to keep track of column inserts, deletions, etc. Does this make sense? Does any one have any ideas on how to accomplish this?

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CREATE TABLE Problem
I have a problem creating mySQL tables with PHP. I am making an app
where a user can create a project. Pressing "submit" on proj_form.php
goes to proj_add.php where a couple of things happen. The project's
meta information is put into a project table, mysql_insert_id() gets
the $proj_ID, and a table named that $proj_ID is created to hold all
of that project's tasks. Here is my code to create the table for a
project's tasks:

// 2) Create a table for the tasks of the new project
$sql = "CREATE TABLE $proj_ID (
task_ID int unsigned NOT NULL auto_increment,
task varchar(40),
person varchar(10),
notes varchar(255),
PRIMARY KEY (`task_ID`))";

Here is the error message that creates:
You have an error in your SQL syntax near ' ( task_ID int unsigned NOT
NULL auto_increment, task' at line 1

It has to do with trying to create a table named $proj_ID. How do I
get that to work?

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Create Mysql Table
I'm trying to create a mysql table in php. i have no problems doing a select, insert or anything else. i just don't know what the proper code is to create a table if it even exists.

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Create & Populate Table?
I am trying to do two things with one form:

1. Create a table in a MySQL database
2. Populate it at the same time

So far I have been able to create it, but the population isn't going so well. Here is the basic code I am using. PHP Code:

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Why Doesn't My Create Table Work
with the following script to create a table:

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Create Table From Variable
I need to know, how I can to do to create a table in PHP, taking de
name for this table from a form variable.

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Create A New Table Automatically
How do i create a new table automatically using php code in a script ?

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Create A One Column Table
Using the following code, how do I create a one column table, with "Firstname, Lastname & Sex" as the heading.

Also, how do I display the row data (i.e Firstname etc) using the following format?: Code:

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Create Temporary Table
Im trying to implement a series of drop/create temporary tables on php.Â Here is the steps via mysql:

mysql>DROP TEMPORARY TABLE IF EXISTS tmp_tbl1;
mysql>CREATE TEMPORARY TABLE tmp_tbl1 SELECT uid,src FROM tblSource WHERE start BETWEEN '2007-11-16 00:00:00' AND '2007-11-16 23:59:59';
mysql>SELECT * FROM tblMain JOIN tmp_tbl1 ON tmp_tbl1.uid=tblMain.uid;

This is my php script:

$qryDrop = "DROP TEMPORARY TABLE IF EXISTS tmp_tbl1";
$qryCreate = "CREATE TEMPORARY TABLE tmp_tbl1 SELECT uid,src FROM tblSource WHERE start BETWEEN '2007-11-16 00:00:00' AND '2007-11-16 23:59:59'";
$qryMain = "SELECT * FROM tblMain JOIN tmp_tbl1 ON tmp_tbl1.uid=tblMain.uid";

mysql_query($qryDrop,$con);
mysql_query($qryCreate,$con);
$res=mysql_query($qryCreate,$con);
; --- snip

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