PHP :: Database Value Select In Combo Box!

PHP String Concatination With Html Select Combo Box
I have problem in PHP String concatination with html select combo
box.

There are 3 files

addressbook.sql :
concat1.php
concat2.php

In concat1.php , if we select User Name in combo box & give input as 3
in
text box.
It display following output
subhash kanade,3 sk@yahoo.com

But, it is not display in that way.
So, please see that code & tell me correction.

addressbook.sql

-- Table structure for table `addressbook`
--

CREATE TABLE `addressbook` (
`id` int(11) NOT NULL auto_increment,
`name` varchar(50) NOT NULL,
`email` varchar(50) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ;

--
-- Dumping data for table `addressbook`
--

INSERT INTO `addressbook` (`id`, `name`, `email`) VALUES (1, 'pramod
kumar', 'pk@hotmail.com'),
(2, 'vinod wagh', 'vinod@rediff.com'),
(3, 'subhash kanade', 'sk@yahoo.com'),
(4, 'ketan patil', 'kp@hotmail.com');

concat1.php

<?php

mysql_connect("localhost","root")or die("Database Failed");
mysql_select_db("pradeep")or die("Failed to Connect Database");

$arr=array("concat(concat(name,','),id)","email");

$str="select ".$arr[0].", ".$arr[1]." from addressbook";

$res=mysql_query($str) or die("resultset error");

echo "<table><tr><th>User</th><th>Email</th></tr>";
while($row=mysql_fetch_array($res)){
echo "<tr><td>".$row[0]."</td><td>".$row[1]."</td></tr>";
}

Multi Select Combo Box - Retrieving Data
I have a combo/listbox with "multiple" enabled in an HTML form and pass this to a PHP script, I should be able to access each item as $array_name[0] etc?

Thats what my book says and what I've been able to track down on Google seems to agree, but the only element I seem to be able to retrieve is $entry_select[0] (from the form below) which contains the last value selected in the combo list. Attempts to select $entry_select[1] just result in nothing printed. Code:

SELECT Error: No Database Selectedin Query: SELECT * FROM Schedule
I got the above error message after reading FAQ #10 which applied to my first error. The thing is, I thought I had selected a database. This script is copied from a tutorial, and I'm just too new at this to spot my error. PHP Code:

Populating A Select Box From A Database
I have a subscription database that allows you to edit a subscribers data. For example, you enter a search term like "Bob" and it returns a list of everyone named Bob. You click the one you want and it goes to a subscriber detail page, where all of his data is populated to a form. You can directly edit this form and click save to overwrite it.

The only issue is the select boxes (drop downs) - say I have four options in the drop down box, red, blue, green and black. On my details page for bob I end up with five, I have those four PLUS whatever was saved for his color, so it shows up twice. If Bob is green, my select box looks like:

Green
Red
Blue
Green
Black

How can I make it so that Green only shows up once?

Select One Record From A Database
I am trying to select one record from a database. This databse has like 10 tables. I do not know which table this record is in. What php and mysql syntax would I use to accomplish this?

Randomly Select From Database?
this might seem like a stupid question, i should be able to do this. but on the front page of my site i want a thing to show a few users. but i dont want it to show the same people over and over. i want it to select different people each time. any ideas?

Selective Echoing And Database Select
I have written a search engine for business listings for the company I work for. Each listing is in a database, and that works fine. The problem though is two-fold.

The first part of the problem is that not all listings utilise every column of the database, and this leaves gaps when echoing the results. This is not what i had in mind, Any ideas/help would be appreciated.

The second part of the problem is related to the first in that there is a link for any listing that has a website, but not every listing has a website, so every listing having a "Visit our Site" link is impractical and shoddy. Also, i'm not sure how to echo the url from the database effectively in the first place.

Editing Mysql Database Row With Select Box
I have a small site, this small site has a few categories, now I can add items through my online admin area fine and delete them fine, but when it comes to editting them I am having some trouble, everything is working fine except the category column, because it is a drop down box I do not know how to have the category selected during the creation progress selected all the other info is loaded.

Multiple Select From Database Where Clause
I have a website with a database full of category names...I want to be able to chose lets say 5 of these categories and use a select from database clause where I could simply enter the category names I want to use but am not sure how I would go about doing it.

I can get the list to display just the Aprilia category using the code below:

$data1->q("SELECT * FROM categories WHERE cat_name = 'Aprilia' ORDER BY cat_name asc");

However...how could I get my site to display Aprilia, Ducati, Honda, Suzuki, Yamaha?

Using PHP And MYSQL To Select From Database Using Images
I'm trying to update a main page with a list of details matching a selection from a display of images that are displayed in a small window that have been selected from an image group using a select box in the main window, however I don't know how to do this and the main page is not receiving anything when clicking on an image so it's refreshing with empty data.

I've seen many many pages giving examples of how to do this with select boxes or how to do this if only one entry uses an image shown in the small window, but the image display window is displaying many different small images not a select box and the database itself has multiple entries that use the same image. Can anyone help? I have a few instant chat programs if someone wishes to discuss this with me in real-time to see what it is I'm trying to achieve.

Tick Box, Select And Update Database.
I am trying to change the value in table with a tick box. If the tick box is selected it changes the value in the field to 'y' and if it is not selected it changes the field to 'n'.

First of all I need to bring back the current state of the field and then I need to be able to update it from 'y' to 'n' as many times as I want. Code:

Population Select Menu Using Php And Database Values
I have no idea how to go about this. so i would apreciate some help i want to populate the values in a html select menu from database values in one table

so i want all the values from 1 particular field in the database to be displayed in the select menu as separate options.

Displaying A List Of Categories From A Database In A Select Box
Could someone please tell me why this outputs nothing

<select name=categories>
<?
$cat_array = get_categories();
foreach($cat_array as $this_cat)
{
echo "<option value="";
echo $this_cat["category_id"];
echo """;
echo ">";
echo $this_cat["category_name"];
echo "
";
}
?>
</select>

==========================================================

function get_categories()
{
//get the list of categories from the database

$conn = mysql_pconnect("localhost", "user", "pwd");
$query = "select * from categories";
$result = mysql_query($query);
if(!$result)
return false;

$num_cats = mysql_num_rows($result);
if($num_cats == 0)
return false;

$result = db_result_to_array($result);
return $result;
}

//A function that returns a query to the database as an array
function db_result_to_array($result)
{
$res_array = array();
for($count=0; $row=@mysql_fetch_array($result); $count++)
$res_array[$count] = $row;

return $res_array;
}

Connecting Two Database Populated Select Menus
I am able to grab the data from the database to populate the menus individually using.
PHP Code:

Select Specific Phrase From MYSQL Database
I am working on a World of Warcraft guild's website and I am trying to create a page where players can select different kinds of gear, i.e. the gear with the most Stamina.

All the player's items are stored in the database and every item have a field in the Items-table containing the item's tooltip. This could look something like:

Boots of the Nexus Warden
Soulbound
Feet Cloth
97 Armor
+27 Stamina
+17 Intellect
Durability 35 / 35
Equip: Improves spell hit rating by 18.
Equip: Increases damage and healing done by magical spells and effects by up to 21.

I then want to select the item with i.e. the most Stamina for all the different slots; Head, Chest, Legs etc.

If I write this:
$query = mysql_query("SELECT substring(item_tooltip, LOCATE('Stamina', item_tooltip)) AS maxor FROM roster_items WHERE member_id = ེ'") or die(mysql_error());

It returns the following:
Stamina +17 Intellect Durability 35 / 35 Equip: Improves spell hit rating by 18. Equip: Increases damage and healing done by magical spells and effects by up to 21.

But I want for it to show the leading characters also (in this case "+27 " before "Stamina") and then not show anything else after the phrase "Stamina". So it shows "+27 Stamina" and nothing else for the above mentioned item. How do I accomplish this?

And then, secondly how do I then get it to show only the item with the most Stamina after it selected the above?

Hope this makes any sense.

I've tried to search these forums and found something a little along the lines of my problem but haven't been able to adjust them to my needs and I therefore need your help which will be greatly appreciated.

Reusing An Object For Common Select To Database
I've noticed that after I finished this app, I had repeated a similar task over and over and would like to modularize it. The repeated task was connecting to the database, executing a select, putting all the results of the columns into different variables of an object. PHP Code:

Simple Filter Of Database With $_GET And Select SQL
I need help with my logic statement with a simple search engine on a MySQL table.
I have three form text input fields named f_name, l_name and dept. I am using the GET method to gather data the user enters in each input field.

So far I have been able to build a check to see that the submit has been clicked but I am having trouble with assembling the SQL statement because I need for the search engine to be able to filter the results based on the information provided in 1-3 of the fields.

I could use if statements with some and clauses but that would mean that I would have to account for each combination. Something like

If(($_GET[‘f_name’] != “”) || ($_GET[‘l_name’] !=) || ($_GET[‘dept] !=)){

$sql = "SELECT * FROM facform WHERE f_name LIKE '$_GET[f_name]',
l_name LIKE '$_GET[‘l_name]', dept LIKE '$_GET[dept]' ”;}

The problem with this is that I would have to get every combination and it’s not very scalable. How can I create this SQL statement dynamically? Code:

Error In Generating Table From Database Select Statment
I am trying to dynamically create a table with the results from a select statement. Below is the code that is not working. Any help would be oh so greatly appreciated. This is for a final at school which is due in an hour. This is the only thing I can't seem to make work. Code:

Select Specific Snippet Of Text, Replace With A Database Result
I'm having some problems trying to do something; I just can't think of a way to do it. Basically, I want to search for a specific snippet of text in a body of text, then replace it with the requested database result with some thrown in HTML.

Users will be able to type the following (or something along these lines, depending on what works best): [image=12345]Insert caption here[/image]

Then I need it to search for the requested image in the appropriate table and return the image's url (for an example, let's say the table is called "images", and the columns required are "imageid" and "imageurl". Code:

Combo Box Value
On my site, if you click on a link i want you to be taken to a contact form that contains a combo box, but what I want to do is predefine what value of a possible five selections is set... What is the best way of doing this?

If And While Combo
I want to combine an IF statement with a WHILE condition.. They work fine seperate but i can't seem to combine them the way i want. Look @ my code so far: Code:

Combo Box
I am allowing users insert data into a database using a form. I want one of the fields "department" to display all existing departments in the database in a combo box for users to choose from and also have a field in the combo box for them to add a new department. Is there a way for me to do this in using php?

Combo Box?
how to make combo box link with my database? I want my data appear when drag down the combo box Can someone help me with the code i should use???

Combo Box Values
I have values in a combo box where datas are coming
loaded dynamically. When an user selects a particular value and press search, even after refreshing the page, I want to keep the value same as the user selects. For example suppose if I selects
value PHP from combo box, after submitting the combo box should
value highlighted must be PHP. IS there any way I can do this?

PHP/MySQL Combo
How come sometimes I get the following error:

Fatal error: out of dynamic memory in yy_create_buffer() in Unknown on line 0

My code works most of the time, its a combination of PHP and mySQL, i have no function named "yy_create_buffer". And the worst problem with this error message, is that when that error comes up, its the ONLY thing that comes up.

Other error messages at least they show up inside my page and they say what I specify the error messages to say. This type of error message would look totally unprofessional on the site I'm developing and I'm curious is there anyway to prevent this or somehow pinpoint the cause.

I'm starting to lose faith in PHP/mySQL . I'm starting to doubt whether the PHP environment is effective for a search engine which searches what will be a relatively large database.

Combo Boxes Question
I am wondering how I can make the whole array appear in the code that is below with the database entry to be selected. At the moment it just displays the database entry.

Populating Two Combo Boxes
I have one combo box (Category) which is populated by a MySQL table using php. I am trying to use the onchange javascript to submit the value selected so that I can populate the other combo box (sub-category) based on what was previously choosen. So can anybody give me a clue on how to submit the first boxes value so that the second can see what was selected (javascript function).

Combo Box / Text Box Php Mysql
this is the the code, now here is the final result.... I get one combo box
<?php require_once('..library_databaseConnectionsonli nequote.php'); ?>
<?
function select_cases_price ()
{
$qy = "SELECT SellingPrice, Description FROM cases";
$rs = mysql_query ($qy) or die (mysql_error ());
while (mysql_fetch_array ($rs))
{ $select .= "<option value='{$r[0]}'>{$r[0]}</option>";
$prices[] = $r{1};
}
return array ($select, $prices);
}
?>

On your web page, call the function.

<? list ($select, $prices) = select_cases_price (); ?> And a bit of JS:
<script>
function showPrice() {
array prices (<? echo $prices ?>);
var i = document.form.item.selectedIndex; document.form.SellingPrice =
prices[i]; </script>

<select name="Description" onUpdate="showPrice()"> <? echo $select; ?>
</select> <input type="text" name="SellingPrice" value="">

Combo Box Value On Page Reload
I am new to php and mySQL so this is probably something very basic that I'm
missing. Basically, on the page I have 2 combo boxes but 1 of them is not
getting the value passed when the page is reloaded so the database can be
updated. I am echoing the field names passed and the field "theDriver" is
there but it's empty. I've include the code parts where I believe the
problem should be but I'm stumped and I've been trying to solve this for 2
days without success. Would someone mind examing the following code and
tell me what I've done wrong?

Following code constructs the combo box on the page from a MySQL table:
<?PHP
$table = "tblEmployees";
$Link = mysql_connect ($host, $user, $password);

$Query = "select concat(empID,' ',empFirstName,'
',empLastName)
as full_name from $table WHERE empTitle =
'Driver'";
$results = mysql_db_query($database, $Query, $Link);
?>

    <b>Driver:</b>
<select name = "theDriver" size="1">
<Option Value=" ">Select One:</option>

<?PHP
for($u=0;$u<mysql_num_rows($results); $u++)
{
$driver=mysql_result($results,$u,'full_name');
?>
<option value="<?PHP echo($ID); ?>"><?
echo($driver); ?></option>
<?PHP
}
?> //end php

</select>

When Page is reloaded the following code is run but the combo box titled
"theDriver" is empty

foreach($_POST as $field => $value)
{
echo $field; //field names from form
echo "; ";
if ($field == "theDriver")
{
echo " - here's the driver for ya: ";
$$field = strip_tags(trim($value));
echo $$field;
$pos = strpos($driver, ";");
echo "<br> the ; is in pos $pos <br>";.......

Dynamic Combo Boxes
i have a problem with creating some dynamic combo boxes. i have a form and the user enters the number of printers required, on the recieving page i display that many combo boxes ready for their input...but the problem is its not generating the correct number of combo boxes for some reason. i think i'ts because i need to reset the cursor on the result set so it can whip through the printers again but am not sure. please see following code:

Php Checkbox And Textbox Combo
I have a form which asks:

How did you know about us?

--friend
--flyer, where_______
--web
--other, _______

I want to store in the db whether the user checked the box and on
certain questions, store the additional description, as indicated by
the _____

How do I go about in doing this? I need help getting the values to
perform an INSERT in the mysql table using php.

How To Validate A Html Combo Box
I have a combo box on my html page that i would like to validate through php processing.
the name of my combo box group is "location" how would i use an IF statement to validate the contents of this combo box?

Mysql Dynamic Combo Box
i want to have a combo box that is populated by certain filelds of a mysql table. how is this done using mysql, php. i saw some other posts about using, javascript. must i?

the table that it is calling from isn't updated very often. also, one other note. i want 4 columns of the table represented in the 1 drop down box, so that users have a more specific description of the row they are selecting.

Creating Simple Combo Box
Very new to PHP and would like to create a combo box in which:

1. I have set an intial value (e.g. "mollusca") and
2. the user has the capability of adding additional values to the list.

Add/edit Combo Form--opinions Wanted
I would like to use the same form for adding new records and editing
existing records. New form values are contained in $_POST. Database values
are contained in an associated array. It seems to me that in order to use
the same form for both tasks, I need to assign the form field values to page
variables. The flow might look something like this:

if $_POST

$variable1 = $_POST['field1'];
$variable2 = $_POST['field2'];

else if $rows

$variable1 = $row['field1'];
$variable2 = $row['field2'];

Combo/list Box Showing Values Selected
I have a combo box being populated dynamically through php using a mysql database, and everything works fine.

My question is: How would i make it keep the values selected, once the user hits the submit button? For example, let's say i have a combo box with the values 1 2 3 4 5 in it. The user selects Ɖ' and hits the submit button (which posts to the same page). At that point, i'd like the combo box to still have Ɖ' selected, instead of resetting itself.

Retrieve Data From Multiple Tables Via Combo
I am working on a small project to create a single web page which retrieves data from 3 tables.

The first table is retrieved by a combo box. It only contains the primary key of the table. I know how to get the data in the combo.

The second table contains other information, related to the primary key of table 1. I know how to retrieve all the data, but not how to retrieve only the data of the selected primary key. I think I should work with a WHERE clause in the SELECT statement, but I have no idea how to get to the selected value.

The third table should work in a similar way, so when I have an answer for the second table, I can also use it for the third table.

Multiple Select From Listbox And Execute A Sql Query Select Statement
Supposing i have a html form with 2 listbox and i name it status and resolution.

So it goes <select name='status[]'>... <select name='resolution[]'>

Then i have a another php page.
$status = $_POST['status'];
$resolution = $_POST['resolution'];

Now my question is, how do i do the sql query statement?

mysql_query("SELECT * from bugs where status=$status and resolution=$resolution");

The problem is, i select 3 options form the status listbox eg. new, closed, duplicate. And from the resolution, i chose fixed, invalid.

Select Statement - Select Random ID #
I have made up a page that pull info on 13 branches of stores onto one main page. It's basically there to display all the branches on one page... then you click on the one you're interested in and then you go to a more detailed page.

Back to the main page. On the top, there's kind of a featured branch that has a bigger picture and bigger title but it's still getting pul pulled from the same table etc etc etc.

In order for me to avoid favortism to one branch (and for other branches to start complaining) I want to ramdomized the order every time someone came to page but I have no idea how.

right now I have a super simple select statement.

Make Selected Option Stay Selected In A Combo After Submit
I have 3 comboboxes, one for the day, other for the month and another one for the year. Every time i select a value for the three of them and press the "Submit" button, they reset to the default option. Anyway this can be solved?

Multiple-combo - Multiple Mail Recipients
I am new to scripting but trying to create a page that lets users create an e-mail (mailto after having chosen from two drop-down menus (arrays).

I have managed to do so in HTML by using a Java script borrowed from Randall Wald (http://www.rwald.com).

However, I don't want the e-mail addresses to appear in the page to avoid spam. Is there a way to do so by using PHP?

P.S.: The first array contains (University A, University B) and the second array (Faculty, Staff, Students), i.e. 6 different e-mail addresses

What Is Indexing In Mysql And How It Will Be Useful And How We Can Retrieve Database Content Easily From A Database Table Containing About 5lakhs Datas
I need to select data from a database table containing huge amount of
data. Now I am storing data using one primary key and I am just using
simple select statement, and this process gives me the output but it is
taking long to execute the query. As much I had heared I want to use
some indexing or cluster indexing which might help me but I am not so
familiar with these things.

Images In Database Vs. Image References In Database
i kept all of the uploaded images as files on the server, and created links to them in the database. I have been changing things around now (especially directories) and I am thinking of storing the images in the actual database. I read somewhere that this can be considered a bad practice, so i was wondering what the consensus here was. In my opinion, modifying all of the code to point to the correct directories everytime a page location changes seems like a pain in the a**.

Database Search -text Database...
Can anybody tell me how to search a flat file database delimited by |. I have exploded the data and managed to get it into a table but want to restrict the final table contents by a search.

The table code at the moment is below - I'd be using a htm file to submit the data. and hopefully be able to search by partial searches eg big would return big and bigfoot. Code:

SELECT *
If I have a lot of articles, all with a unique IDs.

First I would like to search for that ID, I could do

SELECT * from ARTICLE where ID = xx

But I also want to display the 5 articles before and after that article.

SELECT * from ARTICLE where ID > xx LIMIT 0, 10
and
SELECT * from ARTICLE where ID < xx LIMIT 0, 10

(I choose a limit of 10 in case the ID is one of the first one or one of the
last one, that way I will always have at least 10 articles).

Is it possible to do the above in one single query?

Should I even bother doing that? does it make the whole operation faster to
do it that way?

Select Box
I have a problem that I'm not quite sure what algorithm will help me on. I'm
bringing in records from MySQL using PHP and need to spit this records into
a select box. Fairly simple, here's my code for the first select box:

<option selected
value="<?=$currentCatID?>"><?=$currentCategoryName?><option>
<?php
while($rowGetCat = mysql_fetch_array($resultGetCat)){
if($rowGetCat['pCatID'] != $currentCatID){
echo "<option
value="".$rowGetCat['pCatID']."">".$rowGetCat['pCatName']."</option>";
}
}
?>
</select>

Problem is - based on their choice with the first select box, I need to
query the DB and populate a second select box. So basically, I need a 2nd
select box that is populated on the fly based on their choice from the first
select box. The only solutions I have found so far use their own form, and
the form I have now has numerous other options and values that I need to
save the state of for editing.

I was thinking AJAX might help, or maybe just regular javascript, but
without having the entire page reload I'm not sure.

Sub Select
I have this line of code:

$result = mysql_query("SELECT jobnumber, projectname, description FROM timesheets WHERE description IN(SELECT distinct jobnumber, projectname FROM timesheets)",$db);

But this returns nothing. What I want it to do is display the 3 fields jobnumber, projectname and description where the jobnumber,projectname combination is unique.