PHP :: Display Results From Query In HTML-table

Getting Results To Display In Two Columns Of A HTML Table
How can i get the following script to display in two columns of a HTML table? At the moment i have it displaying in one column. If there are 5 results from the DB then the left HTML table column will display the 1st, 3rd and 5th result. The right HTML table column will display the 2nd and 4th results. Code:

Output Query Results To Html Table
I have a MySQL table "products" and I want to output product's data to html table as below:
- A products contain 4 fields: image, name, description, price.
- 4 products is nested in 1 html table 4 rows x 4 columns.

Code:

Display Sql Query Output In Html Table
As evident from a previous post, I am a php noob. I would like to
display MySQL query results in an html table with one of the row values as a
category and the rest of the data displayed under the relevant category.

I can get as far as displaying the data in a nice readable format but I
don't know how to have the records placed under their corresponding
category. This is my code thus far (sans the html output):

....ORDER BY cat ASC'
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
printf("%s Class: %s Description: %s", $row["cat"]$row["title"],
$row["desc"]);
}

Display Results Of Survey In A Table.
Is it possible to have them fill in a survey with about 10 form fields, then display
the results of everyone's survey in a table that can be sorted by different criteria
so new users to the site can instantly see which one of our services is better for them.

Query Array, Sort Results And Display In Seperate Tables
The problem I have it breaking out the results and displaying them (broken out) alphabetically in seperate tables. For instance, I have generated (bookmarked) tables, one for each letter (A-Z) and want to display all recordsets with say, last name
beginning with "A" in one 2 column table, "B" in another 2 column table, and so on... each
table would have two columns (with 2 background colors alternating), each cell containing values of one recordset.

Even more tricky is if I have an odd number of cells, still generating the last cell with empty values (for asthetics). And can anyone say "sort" (yes, I am nuts)? The ability to sort the whole mess by any column value. I have looked at freeware and other third part apps, but they can only do what I already can do (mine is actually cleaner) but not as complicated.

Displaying SQL Query Results In 3 Column Table
I would like to be able to display the results of an sql query in an html table, but the results need to be displayed in three columns, for example:

Column 1 Column 2 Column 3
Result 1 Result 2 Result 3
Result 4 Result 5 Result 6
Result 7 Result 8 Result 9

I've tried to find the answers on the internet but i can't find anything that suits my needs!

Results From Two Db Tables Into One Html Table?
I have a query below that gets its results and puts them in a table. The current results are from two fields in a db table. I am wondering if it is possible to create a second query to get results from a different db table and echo them out in the same html table as the ones already there? Code:

How To LIMIT Results In Html Php/sql Query?
I need to limit results in the following query type:

http://www.somewhere.com/php/sql-a....ql_order=&pos=1

I found a reference that says I should be able to use LIMIT x[,y], but
I don't know where/exactly how to add that to the string. Once I know
what it's supposed to look like, and can write something to generate
it.

If someone could post an example using the above and limiting the
output to 100 records starting at position.

Formatting Mysql_fetch_array Results In HTML Table
This looks like a simple problem, but I just can't seem to wrap my
head around it.

I'm trying to build a table dynamically, based on a result set from
mysql. There will be 9 results for a full page, with 3 table rows of 3
table cells. One result per cell. But all of the pages won't be full.

Here's one of many ways I've tried to do it:

<html>
<head>
<title>test</title>
</head>
<body>
<table width="100%" border="1">
<?php

include_once('db.inc.php');

$query = "SELECT DISTINCT title FROM mytable LIMIT 9";
$result = mysql_query($query);

while ($row = mysql_fetch_array($result)) {
$title = $row['title'];
}

for ($i = 0; $i < 3; $i++) {
print ' <tr>' . "
";

for ($e = 0; $e < 3; $e++) {
print ' <td align="center">' . "
".
' title : ' . $title . "
".
' </td>' . "
";
}
print ' </tr>' . "
";
}

?>
</table>
</body>
</html>

This prints out 3 rows of three like I hoped, but $title is the same
in all 9 cells. I also have tried it with the for loops inside the
while loop, which prints out 9 rows of 9 cells 9 times!

Divide Mysql Results Into Rows In An Html Table
I need to divide my mySQL results into rows with 4 results on each row. Its for a small image gallery script, I wanna show 4 thumbnails per row. I have all the code ready to get the info and show it, I just need an example of how I can take the data from the table and have it automatically go to a new row every 4 entries.

Display Database Output In Mutli Column Html Table
I am building an HTML form using data from a mysql query. The data to be displayed on the form is 1 column from the db - but multiple rows. Because there are many rows (well, only about 100+) in the table I want to be able to put 2 or 3 (space permitting) rows from the result on each row of the HTML table with a checkbox beside each entry from the db table. The idea is that the user will scroll down the list and check up to 4 or 5 boxes before submitting the form and I didn't want them to have to scroll ALLLL the way to the bottom (100+ rows). I understand how to get data from a db table and put it into an html table, but I cannot figur out how to put more than 1 row from the result on to the same row of the html table.

I hope I haven't confused anyone reading this -- If I am way off base with what I am trying to do please give me alternatives. I am trying to avoid paginating the data for a couple reasons a) clicking a next and/or prev button is more hassle than just scolling down a list and b) the data in the column being displayed is only about 35 - 40 characters and it seems to be if i only placed one result row on each html table row, there would be a lot of wasted space.

Table Background Color Based On Results From MySQL Table
I am trying to get the "Did User Agree" field on a database query to be colored Green for "Agreed" Red for "Disagreed" and Blue for "Agreed (2nd Time)" .. I have my PHP setup to do the query just fine as of right now with alternating column colors, just can't seem to get the colors to work as I am hoping for. Can anyone help me get the Agreed? table's background color to the colors above? Code:

Grab Content From HTML Table And Place Into MySQL Table?
I am in the process of helping a co-worker upgrade some of his old static html pages into dynamic MySQL driven pages. He currently has a lot of pages with huge tables displaying data. Does anyone know if there is a script or class that can convert a table to a .sql file for upload?

Display Results
I have created a form where the number of rows are displayed based on a value from a select box. Everything works excellent this far. however I need to take it to the next step where I display the information back into the form based on values in a mysql table. Code:

Categorical Results Display
I want to take these results and display them by category. I.e. each of these results would fall into different categories like "insurance", they are maked in the database simply with a "Y" for each category that they would appear in. I could make a page like this for each of the 20 categories, but I am sure there is a better way.
<?
if(!IsSet($start))
$start = 0;
$result = mysql_query("SELECT site_name, site_address, site_image, publish FROM sites WHERE publish = 'Y' ORDER BY site_name ASC LIMIT $start,144") or die(mysql_error());
?>
<table width="100%" border="0" cellspacing="4" cellpadding="4" align="center">
<tr>
<?
while($row = mysql_fetch_object($result))
{
echo '<td width="25%" align="center" valign="top"><a href= "',$row->site_address,'" target="_blank"><img src="samples/',$row->site_image,'"width="100" height="75" border="0"></a><br><a href= "',$row->site_address,'" target="_blank">',$row->site_name,'</a></td>'
if(++$i % 4 == 0)
echo '</tr><tr>'
}
?>
</table>

How Do I Display The Results Of A Test?
i just started learning php and have a quick question. this is my code:

$a=4;
$a==7;

what i want to know is how to display the results (either true or false). i tried print($a); but it only outputs the original variable value (in this case 4).

Display Results Vertically
I am creating a catalogue-like application and I want to display the items vertically instead of horizontally. Being somewhat new to PHP, the only thing I can think of are seperate queries for each field. Is there an easier way? Here's an example of how I want it to look.

Category 1
field1: result
field2: result
field3: result

Category 2
field4: result
field5: result

and so on and so forth....

Display The Number Of Results
How can I set the classical search engine message? Found ### results. How can I count the returned results and display them in the results page? so now has the Found 5 results or any number that the result contains.

Display Results According To Distance
I have a php/mysql driven website. On my search bar I have the option of searching by zip code. I have the function to find the radius of the surrounding zip codes. But I want to display the result along with my information from the other table.

An example would be:

I want to search for ads around my zip code for a range of 20 miles. The class I have will find all the zips and get their distances plus will sort them by closest to farthest. My problem is I want to display the records according to the distance provided. I heard of doing a sort with php but I am not sure which route to go.

I hope someone has found out how to do it, because this is the only thing left to do in order to launch the site.

How Do I Display Radio Button Results?
I have a form which uses several radio buttons to enter data. It works fine
as far as entering goes, but I can't figure out how to display which button
is checked when I view the record. I could do a if-then routine but it
seems like there should be an easier way.

Search & Display PEAR DB Results
I'm only a novice in PHP & PEAR DB, and currently stuck in an attempt to create a "search & display query PEAR DB results" page. Here's my pseudocode:

1) Display page with a searchbox and a search button.

2) Upon hitting the search button, run sql query ... Select all fields from TableA and selected fields from TableB where field1 like "searchbox" order by field1

3) If searchbox is blank
-> prompt user to enter search value
Elseif search result NOT found
-> alert user >> Record NOT found
Else
-> display results in a table (with alternating colours for each row)

4) Able to paginate the results in something like display 10, 20, 30, etc records on the same page .... the amount of records to be displayed can be manually selected by the user (via a dropdown box) ... with Previous Page, Next Page links as well.

>> How would I do that entirely in code from scratch? I've found other tutorials on doing it but it is tailored for MySQL ... but I'm using PEAR DB... the syntax is different.

>> Since I am querying two tables based on the same search value, how am i able to concatenate both the tables search results and display it inline in the display results page?

Display Search Results In Pages
im doing a query on a table that searches articles from the database, and i was wondering how i could display the results as groups of ten, so the next ten search matches are displayed when the user presses a page number.

3 Comlumn Display Results With Pagination
I have the following code that works perfectly. I would like to add an easy pagination feature that limits the number of items, counts the number of records and makes links and pages for the next page. Code:

Display Number Of DB Results Beside A Link?
For an example, if you look at www.menupages.ie they give you a preview of how many results are found for each link.

ie:

Ballsbridge Restaurants (52)
Blackrock Restaurants (17)
Clondalkin Restaurants (18)
Clontarf Restaurants (17)

How is this achieved. I take it that it must be a select count on the DB for each row but that seems pointless, is there an easy way to achieve this?

Display Only Mysql_num_rows Results #-# (or Similar)
I have this mysql database. It works great, the stuff outputs how I want. But I'm making a news website and I need to change the articles each month.

I'm putting all the articles into one database, then into each page as tables (ie: news, opinion, sports, etc.), then the articles each have their own row. On the homepage here it outputs all 5 articles from the news table, but I only want it to output result numbers (blah) through (whatever). Code:

Display Results From Multiple Tables
I have two tables, one table (article_cat) has four fields ("id", "title", "feature1", and "feature2") and the other table has six fields (articles) has ("id", "cat_id", "title", "content", "feature1", and "feature2").

I am looking to display the "title" from the "article_cat" table that has "feature1" with a value of 1. And I want to display beneath that all the "title" results from the "articles" table where "feature1" has a value of 1. I have tried this a thousand ways with no luck. Code:

Limiting Results, And Display Page Numbers
How do I make it so only 50 items display per page. And if there's more than 50, it displays a link "page 2", "page 3" and so on? I know how to limit results with MySQL but how do I generate pages for the next 50 within the PHP code?

Select And Display Multiple Queries / Results
Howdy all, i've been looking through various sites / tutorials and through this php book I have here to try figure out whats causing this problem but haven't had any luck yet.

The problem is that its displaying the Designation as the link url instead of the jcode. Hope i explained this well. Above this bit of code has calls the individual Catagorys, if theres data in that catagory it will display it with whats below. PHP Code:

Checkboxes In A Form To Determine Whether To Display In Results
I am making an effort to put checkboxes in my form that will determine whether to display that column or not. This is my first time doing this with PHP and I am hoping you gurus can assist. I have gotten some extremely great assistance in the past, so I am looking forward to any recommendations.

currently my form is as follows:

Display Results From A Database On Multiple Pages
I am new to PHP and Mysql but am really determined to learn these techniques. I have some script that reads and displays results from the databse onto a page. However, I really wish to limit the number of results that are displayed to 10 per page and then have the next/privious links under the results. With these results, the results under the email field should be hyperlinked so that the person viewing the results should double click on the email link and send the person an email. How can i do that? I have to learn this technique.

The code is:-

Display Results From Text File In Multiple Pages
i use a string, eg "&&&" to mark pages in a text file. i use $count to count the above string. how can i display the contents of this file in multiple pages (by identifying the above string or any other method)?

Getting Too Many Results From A Query!
This is very peculiar -- for some reason, I'm getting 6-8 results from each
of these queries, although only one listing matches. I have a pair of forms
on one page:

<FORM>
Search for lastname: ____________ [Submit]
</FORM>
<FORM>
Search for email: ________________ [Submit]
</FORM>

This goes to a searchresults.php page:

if ($searchname !== "") {
$query="SELECT artistID,firstname,lastname,email,city,state,count ry
from artists WHERE lastname='$searchname'";
$result=mysql_query($query) or die(mysql_error("Could not execute
query."));
while($row = mysql_fetch_array($result)) {
$alt_artistID = $row['artistID'];
$alt_firstname = $row['firstname'];
$alt_lastname= $row['lastname'];
$alt_email = $row['email'];
$alt_city = $row['city'];
$alt_state = $row['state'];
$alt_country = $row['country'];
echo "<CENTER><HR>".$alt_artistID."<BR>"
.$alt_firstname." ".$alt_lastname."</A><BR>"
.$alt_email."<BR>"
.$alt_city.", ".$alt_state." ".$alt_country."<BR>
<A HREF=delete.php?aritstID=".$alt_artistID.">DELETE THIS
LISTING?</A><BR></CENTER>";
}
}

The second section is identical except for:
if ($searchemail !== "") {
$query="SELECT artistID,firstname,lastname,email,city,state,count ry
from artists WHERE email='$searchemail'";
etc...
}

I don't understand why I would get 6-8 records when you can look at them and
see that all but one clearly do not match...?

Using Query Results
Can you use a queries results only once? In this script I'm looping through a query and saving some values in an array. A little further through the script I need to use the same query for output. When I loop through nothing is echo'd to the browser. When I output a row count it shows that the correct number of records, so they must still be there.

ASP.NET & PHP - Php Xml Table Display
I hope that there is someone fluent in both php and asp.net who can help me bridge a gap.

In asp.net it is fairly easy to take a simple xml file and display it as a table [or datagrid], using something like:

void Page_Load()
{
String xmlFilename = @"C:...example.xml";
DataSet newDataSet = new DataSet();
newDataSet.ReadXml(xmlFilename);
DataGrid1.DataSource = newDataSet;
DataGrid1.DataBind();
}

followed by:

<asp:DataGrid id="DataGrid1" runat="server"></asp:DataGrid>

I would like to know how to do this in php.

Place The Results In Another Table
I am trying to take the results from a query and place the results in another table.
I want to take all the results from $row join them together. is this possible to do?
And can the results be stored with the information from the print statement? (<br> from each row) Code:

Colour Top 3 Results In A Table
I'm currently trying to make a poker league whats seem to be going well.

I have populated a table with the league results, but would like 1st position in gold, 2nd in silver and 3rd in bronze. These will be the first three rows of the table, as the data has already been arranged in the correct order.

I'm a little unsure how to go about doing this, and wondered if anyone could point me in the right direction. Code:

Sorting Table Results
I tried searching Google for some stuff about sorting table results.
I want to be able to click the different headers and sort the results by each field. Anyone know some good sites/tutorials?

Display Query
I am trying to select all from and display result in table form on screen, then to link to an update query. I am getting the following error

Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING on from the following line
echo "id : $row['id'] ";

The script is a copy and paste from PHP Simple only making changes to the record names. Code:

Query Results In 2 Columns?
I'm struggling to figure out how to do this properly. I have done a mySQL
query to extract a list of names, and done a mysql_num_rows to determine how
many results I've gotten. I want to split the list in to two columns. I've
created $percol = $mysql_num_rows/2 but I'm not quite sure how to "loop"
through the first half of the list, echo </td><td> and then list the
balance. Can anyone give me some guidance on how best to structure this?

Finding The Results Of A Query
I am working on a script that will query a database for a FNAME/LNAME
combo. If it finds the combo, I need it to do one set of instructions.
If it doesn't find it, I need it to do something else. What I can't
figure out is what variable to check against. Here is what I have for
the relevant part of the script:

$connection = mysql_connect($hostname, $username, $password);
mysql_select_db($databasename) or die ("Cannot connect to database"
..mysql_error());
$query="SELECT FNAME, LNAME FROM (table) WHERE FNAME=('$FName') AND
NAME=('$LName')";
$result = mysql_query($query) or die('Query failed: ' . mysql_error());
mysql_close($connection);

I tried checking the value of $result to see if it changed depending on
whether or not it found the selection. It does not. I just can't figure
out what to use for:

if (some expression){
perform this code
}
else{
do this
}

Grouping Results Of Query
I'm brand new to PHP (just starting today to convert tons of
ColdFusion/Access code to PHP/MySQL). There is a function in
Coldfusion that I can't find an equivalent to in PHP. Here is
what I am trying to do:

If I have a query that results in this information:
State Firstname Lastname
Idaho Terry Pratchet
Vermont Dan Brown
Vermont Bob Smith
Virginia Alice Johnson
Virginia David Jones

I would like to output the info like this:

But all I can find in PHP is a way to loop through the query
and show every row... if you are familiar with Coldfusion,
what I am looking for is something similar to this:

<CFOUTPUT GROUP='State'>
#State#<BR>
<CFOUTPUT>
#Firstname# #Lastname#
</CFOUTPUT>
<BR>
</CFOUTPUT>

Is there a function that does this in PHP, or do I need to
write code that watches the value of 'State' and manually
takes care of things whenever it changes?

ODBC Query Results
Consider the following:

<?

$username = "foo";
$password = "bar";
$host = "db";

$connect = odbc_connect("$host", "$username", "$password") or die;

$query = "SELECT id, name, address, city, state, comments1, comments2
FROM data.table1, data.table2 WHERE id = ô˜'";

$result = odbc_exec($connect, $query);

while(odbc_fetch_row($result)){
$id = odbc_result($result, 1);
$name = odbc_result($result, 2);
$address = odbc_result($result, 3);
$city = odbc_result($result, 4);
$state = odbc_result($result, 5);
$zip = odbc_result($result, 6);
$comments1 = odbc_result($result, 7);
$comments2 = odbc_result($result, 8);
print("ID: $id<br>Name: $name<br>Address: $address<br>City:
$city<br>State: $state<br>Zip: $zip<br>Comments1:
$comments1<br>Comments2: $comments2<br>
");

}
?>

Only one record is returned from data.table1 (containing the id, name,
address, city, state, & zip). However, there are multiple records
returned from data.table2 (records from comments1 & comments2). What
is happening is that when I run this script, all of the data returned
from data.table1 is printed over & over again along with each record
returned from data.table2. How can I make it such that id, name,
address, city, state & zip are only printed once - and allow comments1
& comments2 to be printed multiple times for each occurance in the
database?

I've thought about just creating a second database query for the
records in data.table2, however I need the join I'm getting by using
the existing query.

For what it's worth, I'm connecting to a DB2 database using PHP /
Apache on Linux.

I'm confused by this.

Losing Query Results!
If I make a query;

$result = mysql_query($theQuery, $db);

and then make use of the query results like so;

while ($row = mysql_fetch_row($result)) {

//do something with query results}

I can't use $result again, I have to make another query! Why is this and is there any way around it?

Multiple Sql Query Results
I'm trying to do a query from 2 databases. Basically i have
catagories within 2 databases. If both catagories return 0 rows then it
does nothing but if one or both have rows returned then i need it to
echo a result. I guess where i'm wondering if there's an OR statement i
can use or something to that effect...

something like

if($numrows == 0 OR $numrows2 == 0) {
echo ('');
}else{
echo ('$result');

SQL Query - Results From Another PHP Page ?
Can I store this PHP code in another page, then refernece it on
multiple pages using Require or Include ???

//results from sql query
for ($i=0; $i<$number; $i++) {
$ID = mysql_result($result,$i,"ID");
$CompanyName = mysql_result($result,$i,"1");
$ContactName = mysql_result($result,$i,"2");
$Phone = mysql_result($result,$i,"3");
$HomePhone = mysql_result($result,$i,"4");
$MobilePhone = mysql_result($result,$i,"5");
$AltPhone = mysql_result($result,$i,"6");
$SecondContact = mysql_result($result,$i,"7");
$SecondPhone = mysql_result($result,$i,"8");
$ThirdContact = mysql_result($result,$i,"9");
$ThirdPhone = mysql_result($result,$i,"10");
$Notes = mysql_result($result,$i,"11")

Sql Query Results And Scrolling
I make a mySQL database query and display the first 10 results. Then
the user can click on "next" link to get the next 10 results. How can
I do that without issuing the sql query again? Can I keep the results
from the first query?

Query In PHP Won't Return Results In There's Only 1
$sql = 'SELECT `PageTitle` '
$sql .= 'FROM `Pages` '
$sql .= 'WHERE `PageID` = 1 LIMIT 0, 30'

I have run this query in MySQL control panel and it works perfectly.
When I try to do it via PHP I get no results.

If I select all rows (i.e I don't specify a "WHERE") I get one fewer
rows returned than there actually are.

Display Results From Query In HTML-table

I'm working with PHP3 and Oracle 8. Can anyone tell me how to display the results from a query into my HTML-table?