PHP :: Display Results Of Survey In A Table.

Table Background Color Based On Results From MySQL Table
I am trying to get the "Did User Agree" field on a database query to be colored Green for "Agreed" Red for "Disagreed" and Blue for "Agreed (2nd Time)" .. I have my PHP setup to do the query just fine as of right now with alternating column colors, just can't seem to get the colors to work as I am hoping for. Can anyone help me get the Agreed? table's background color to the colors above? Code:

Display Results
I have created a form where the number of rows are displayed based on a value from a select box. Everything works excellent this far. however I need to take it to the next step where I display the information back into the form based on values in a mysql table. Code:

Categorical Results Display
I want to take these results and display them by category. I.e. each of these results would fall into different categories like "insurance", they are maked in the database simply with a "Y" for each category that they would appear in. I could make a page like this for each of the 20 categories, but I am sure there is a better way.
<?
if(!IsSet($start))
$start = 0;
$result = mysql_query("SELECT site_name, site_address, site_image, publish FROM sites WHERE publish = 'Y' ORDER BY site_name ASC LIMIT $start,144") or die(mysql_error());
?>
<table width="100%" border="0" cellspacing="4" cellpadding="4" align="center">
<tr>
<?
while($row = mysql_fetch_object($result))
{
echo '<td width="25%" align="center" valign="top"><a href= "',$row->site_address,'" target="_blank"><img src="samples/',$row->site_image,'"width="100" height="75" border="0"></a><br><a href= "',$row->site_address,'" target="_blank">',$row->site_name,'</a></td>'
if(++$i % 4 == 0)
echo '</tr><tr>'
}
?>
</table>

How Do I Display The Results Of A Test?
i just started learning php and have a quick question. this is my code:

$a=4;
$a==7;

what i want to know is how to display the results (either true or false). i tried print($a); but it only outputs the original variable value (in this case 4).

Display Results Vertically
I am creating a catalogue-like application and I want to display the items vertically instead of horizontally. Being somewhat new to PHP, the only thing I can think of are seperate queries for each field. Is there an easier way? Here's an example of how I want it to look.

Category 1
field1: result
field2: result
field3: result

Category 2
field4: result
field5: result

and so on and so forth....

Display The Number Of Results
How can I set the classical search engine message? Found ### results. How can I count the returned results and display them in the results page? so now has the Found 5 results or any number that the result contains.

Display Results According To Distance
I have a php/mysql driven website. On my search bar I have the option of searching by zip code. I have the function to find the radius of the surrounding zip codes. But I want to display the result along with my information from the other table.

An example would be:

I want to search for ads around my zip code for a range of 20 miles. The class I have will find all the zips and get their distances plus will sort them by closest to farthest. My problem is I want to display the records according to the distance provided. I heard of doing a sort with php but I am not sure which route to go.

I hope someone has found out how to do it, because this is the only thing left to do in order to launch the site.

How Do I Display Radio Button Results?
I have a form which uses several radio buttons to enter data. It works fine
as far as entering goes, but I can't figure out how to display which button
is checked when I view the record. I could do a if-then routine but it
seems like there should be an easier way.

Search & Display PEAR DB Results
I'm only a novice in PHP & PEAR DB, and currently stuck in an attempt to create a "search & display query PEAR DB results" page. Here's my pseudocode:

1) Display page with a searchbox and a search button.

2) Upon hitting the search button, run sql query ... Select all fields from TableA and selected fields from TableB where field1 like "searchbox" order by field1

3) If searchbox is blank
-> prompt user to enter search value
Elseif search result NOT found
-> alert user >> Record NOT found
Else
-> display results in a table (with alternating colours for each row)

4) Able to paginate the results in something like display 10, 20, 30, etc records on the same page .... the amount of records to be displayed can be manually selected by the user (via a dropdown box) ... with Previous Page, Next Page links as well.

>> How would I do that entirely in code from scratch? I've found other tutorials on doing it but it is tailored for MySQL ... but I'm using PEAR DB... the syntax is different.

>> Since I am querying two tables based on the same search value, how am i able to concatenate both the tables search results and display it inline in the display results page?

Display Search Results In Pages
im doing a query on a table that searches articles from the database, and i was wondering how i could display the results as groups of ten, so the next ten search matches are displayed when the user presses a page number.

3 Comlumn Display Results With Pagination
I have the following code that works perfectly. I would like to add an easy pagination feature that limits the number of items, counts the number of records and makes links and pages for the next page. Code:

Display Number Of DB Results Beside A Link?
For an example, if you look at www.menupages.ie they give you a preview of how many results are found for each link.

ie:

Ballsbridge Restaurants (52)
Blackrock Restaurants (17)
Clondalkin Restaurants (18)
Clontarf Restaurants (17)

How is this achieved. I take it that it must be a select count on the DB for each row but that seems pointless, is there an easy way to achieve this?

Display Only Mysql_num_rows Results #-# (or Similar)
I have this mysql database. It works great, the stuff outputs how I want. But I'm making a news website and I need to change the articles each month.

I'm putting all the articles into one database, then into each page as tables (ie: news, opinion, sports, etc.), then the articles each have their own row. On the homepage here it outputs all 5 articles from the news table, but I only want it to output result numbers (blah) through (whatever). Code:

Display Results From Multiple Tables
I have two tables, one table (article_cat) has four fields ("id", "title", "feature1", and "feature2") and the other table has six fields (articles) has ("id", "cat_id", "title", "content", "feature1", and "feature2").

I am looking to display the "title" from the "article_cat" table that has "feature1" with a value of 1. And I want to display beneath that all the "title" results from the "articles" table where "feature1" has a value of 1. I have tried this a thousand ways with no luck. Code:

Limiting Results, And Display Page Numbers
How do I make it so only 50 items display per page. And if there's more than 50, it displays a link "page 2", "page 3" and so on? I know how to limit results with MySQL but how do I generate pages for the next 50 within the PHP code?

Select And Display Multiple Queries / Results
Howdy all, i've been looking through various sites / tutorials and through this php book I have here to try figure out whats causing this problem but haven't had any luck yet.

The problem is that its displaying the Designation as the link url instead of the jcode. Hope i explained this well. Above this bit of code has calls the individual Catagorys, if theres data in that catagory it will display it with whats below. PHP Code:

Checkboxes In A Form To Determine Whether To Display In Results
I am making an effort to put checkboxes in my form that will determine whether to display that column or not. This is my first time doing this with PHP and I am hoping you gurus can assist. I have gotten some extremely great assistance in the past, so I am looking forward to any recommendations.

currently my form is as follows:

Display Results From A Database On Multiple Pages
I am new to PHP and Mysql but am really determined to learn these techniques. I have some script that reads and displays results from the databse onto a page. However, I really wish to limit the number of results that are displayed to 10 per page and then have the next/privious links under the results. With these results, the results under the email field should be hyperlinked so that the person viewing the results should double click on the email link and send the person an email. How can i do that? I have to learn this technique.

The code is:-

Display Results From Text File In Multiple Pages
i use a string, eg "&&&" to mark pages in a text file. i use $count to count the above string. how can i display the contents of this file in multiple pages (by identifying the above string or any other method)?

Query Array, Sort Results And Display In Seperate Tables
The problem I have it breaking out the results and displaying them (broken out) alphabetically in seperate tables. For instance, I have generated (bookmarked) tables, one for each letter (A-Z) and want to display all recordsets with say, last name
beginning with "A" in one 2 column table, "B" in another 2 column table, and so on... each
table would have two columns (with 2 background colors alternating), each cell containing values of one recordset.

Even more tricky is if I have an odd number of cells, still generating the last cell with empty values (for asthetics). And can anyone say "sort" (yes, I am nuts)? The ability to sort the whole mess by any column value. I have looked at freeware and other third part apps, but they can only do what I already can do (mine is actually cleaner) but not as complicated.

ASP.NET & PHP - Php Xml Table Display
I hope that there is someone fluent in both php and asp.net who can help me bridge a gap.

In asp.net it is fairly easy to take a simple xml file and display it as a table [or datagrid], using something like:

void Page_Load()
{
String xmlFilename = @"C:...example.xml";
DataSet newDataSet = new DataSet();
newDataSet.ReadXml(xmlFilename);
DataGrid1.DataSource = newDataSet;
DataGrid1.DataBind();
}

followed by:

<asp:DataGrid id="DataGrid1" runat="server"></asp:DataGrid>

I would like to know how to do this in php.

Place The Results In Another Table
I am trying to take the results from a query and place the results in another table.
I want to take all the results from $row join them together. is this possible to do?
And can the results be stored with the information from the print statement? (<br> from each row) Code:

Colour Top 3 Results In A Table
I'm currently trying to make a poker league whats seem to be going well.

I have populated a table with the league results, but would like 1st position in gold, 2nd in silver and 3rd in bronze. These will be the first three rows of the table, as the data has already been arranged in the correct order.

I'm a little unsure how to go about doing this, and wondered if anyone could point me in the right direction. Code:

Sorting Table Results
I tried searching Google for some stuff about sorting table results.
I want to be able to click the different headers and sort the results by each field. Anyone know some good sites/tutorials?

PHP & Table Display Problems
Simple PHP script which selects data from a DB and outputs the data into a nice simple html table formatted using css classes. Now the odd bit..

Works fine on my machine everytime but on others the HTML formatting goes to pot on the odd line, like the font is too big, or the background color has gone, or a cell is missing which puls the remaining cells one in from the right misaligning the table.
Now the even odder bit... When you view source on the bad page, the HTML is absolutely perfect. Any ideas?

Dynamically Generated Results Table
I'm trying to write a script that dynamically generates HTML tables depending on the results from an SQL query. So far, I have managed to set the HTML table headers to be the same as those in the MySQL table. [thanks to rod k -cheers !]

Now i'm trying to put the results in the table. Basically, I need a MySQL function to retrieve data and put it into the table until there is no data left....

(At the moment I am using "mysql_fetch_array()", but with this it is necessary to know the names of the columns to retrieve the information for each result set. Since my table is dynamic and should be able to build itself from different MySQL tables, the column names aren't fixed and so i can't use this to put the data in the tables...)

Creating A Link Within Table Results?
I am using php and mysql. Does anyone have any pointers on how to include links within table results that point to additional information also pulled from the same db table?

I have some extensive info that I want to query. The intial results are going to be displayed in a simple wire frame html table layout. I would like each row to include a link that will take the reader to a more detailed version of the data for that particular row, and that more detailed data will of course come from the same db table. My problem is I don't know how to setup the code to create such link.

Displaying Array Results In Table
I'd like to display the results of an array in a table format with the Alias, Alias Destination & Username as column headings & the results underneath. PHP Code:

Putting Database Results In A 5x1 Table
I have a db of tens of thousands of entries. It's not too hard to pull
all the entries and build a table that displays them one at a time, but
in my case, that will be a huge waste of space. What I want to do is
put one record in each of the columns. I thinks it's possible to do
because I have seen very elaborate thumbnail gallery scripts to do this.
I just want to be able to put two or three strings of text from each
record into each row, and a checkbox. Here's sample of what I mean:

<table width="76%" border="1" cellspacing="1" cellpadding="1">
<tr>
<td>$record1Line1<br>$record1$Line2<br>
<input type="checkbox" name="$record1checkbox" value="checkbox"></td>
<td>$record2Line1<br>$record2$Line2<br>
<input type="checkbox" name="$record2checkbox" value="checkbox"></td>
<td>$record3Line1<br>$record3$Line2<br>
<input type="checkbox" name="$record3checkbox" value="checkbox"></td>
<td>$record4Line1<br>$record4$Line2<br>
<input type="checkbox" name="$record3checkbox" value="checkbox"></td>
<td>$record5Line1<br>$record5$Line2<br>
<input type="checkbox" name="$record5checkbox" value="checkbox"></td>
</tr>
</table>

I want to pull about 200 records at a time from the db and display as
described above. How can I tell php to take five records from my result
set and display above, then loop through the result set until I'm done?

JOIN Table Results W/MySQL
I have a query with a simple JOIN.

For example:

SELECT * FROM Companies
INNER JOIN CompanyTypes ON Companies.CompanyID = CompanyTypes.CompanyID

The query returns all fields from both Companies AND CompanyTypes. I would
like all fields from Companies only.

Getting Data From A Table Based On The Results From Another?
This is the second part of my problems with a top ten list: I'm making a site for guitar effects. I'm trying to make a list of the top ten effects pedals, based on how many effects settings (patches) people have submitted for each pedal. There are two tables, pedals and patches:

I want it to select patches and find out which "pedal_id" is most common, then select that pedal ID from pedals, echo some tuff, then do the query again, except search for the SECOND most popular value, echo it, then the third, echo it, etc etc etc

Results From Two Db Tables Into One Html Table?
I have a query below that gets its results and puts them in a table. The current results are from two fields in a db table. I am wondering if it is possible to create a second query to get results from a different db table and echo them out in the same html table as the ones already there? Code:

AJAX To Display New Records In A Table
Instead of refreshing the entire page to show the new fields in a
table, I was wondering if it would be possible to use AJAX to display
the new records in a table.

For example:

Messages are entered into the DB. I use PHP to create a table that
displays the messages.

Instead of refreshing the entire page to show the table with new
messages, how can I use AJAX to show the new messages in the table
without refreshing the entire page?

Display Content From A MySQL Table
I have copied a script out of a book and then modified it to fit my needs. But I keep getting a parse error and don't know how to fix it. I am trying to take content from a MySQL table and order it by the name. Here is the script I have: Code:

Display Of Mysql Table Result...
I have a mysql table of articles with fields:

- recordID
- department
- articleTitle
- articleText

Using PHP, I'm attempting to get the results of the table to display as follows:

Department 1
- articleTitle 1
- articleTitle 2
- etc....

Department 2
- articleTitle 1
- articleTitle 2
- etc..

I figure I should use a while loop but can't figure out how to exit/reset the loop when a new 'department' is encountered in the $result.

How To Display Random Data Table Row
I would like to be able to display a random database row in an ad system I am thinking about developing. Here is MySQL code that I create:

<?php
mysql_connect("localhost","username","password");
mysql_select_db("databaseName");
mysql_query("SELECT * FROM dateTableName ORDER BY RAND() LIMIT 1");?>

Is this correct and what would be my next step to make a single random row display. I am sure I would use echo or print the database variables in some fashion. I the past I have been using the mysql_fetch_array method, but I am not quit sure how to do this now.

What Is The Best Way To Display Specific Info From A Table?
I am hosting a youth sport site and I want to display schedules by select teams.

I thought that I would want a drop down menu to select one of our 35 divisions, then a secondary search by team of that previously selected division menu.

My schedule is in a table with the fields:
* division
* date
* time
* home_team
* h_score
* visiting_team
* v_score
* field

I see problems, since secondary drop down menu would have to search two different fields. Any suggestions and hint to where I would even start?

Output Query Results To Html Table
I have a MySQL table "products" and I want to output product's data to html table as below:
- A products contain 4 fields: image, name, description, price.
- 4 products is nested in 1 html table 4 rows x 4 columns.

Code:

List Db Results Vertically In 2-column Table
i'd like to display mysql query results in a two column table, however, with the results displaying vertically starting in column 1 then continuing into column 2.

Loop To Print Formatted Table From Sql Results
I'm trying to create a 3 column table now, and each cell will contain info from a single record. All the records will be pulled from a mysql database.

What makes this a bit difficult is that I want the center column to be blank. Only the first and third columns will contain the results. I can't get the desired effect, and I'm not sure my loop logic is even correct. Does anyone know what's wrong with my code?
Code:

Printing Mysql_fetch_array Results In Multicolumn Table
I'm not sure if this qualifies as a mysql or a php question so I'm
asking in both groups.

I am pulling the results of a mysql query from my database and want to
print the results into a two column table. I know how to get the results
into a single column table just fine using:

while($row = mysql_fetch_array($result)) {
print "<table border=2><tr><th>" . $row[name];
print "<tr><td>";
print mysql_field_name($result, 0) . ": " . $row[ID]."<br>";
print mysql_field_name($result, 1) . ": " . $row[name]."<br>";
print mysql_field_name($result, 2) . ": " . $row[address]."<br>";
print mysql_field_name($result, 3) . ": " . $row[city]."<br>";
print mysql_field_name($result, 4) . ": " . $row[telephone]."<br>";
print "</td></tr>";
print "</table>
";
print "<br><br>";
}

and it works fine. But my efforts to get the reults into a two column
setup have become frustrating. My latest attempt was:

while($row = mysql_fetch_array($result)) {
print "<table border=2 width=ྖ%'>";
print "<tr>";
print "<td>";
print "<b>" . $row[name] . "</b><br>";
print mysql_field_name($result, 0) . ": " . $row[ID]."<br>";
print mysql_field_name($result, 1) . ": " . $row[name]."<br>";
print mysql_field_name($result, 2) . ": " . $row[address]."<br>";
print mysql_field_name($result, 3) . ": " . $row[city]."<br>";
print mysql_field_name($result, 4) . ": " . $row[telephone]."<br>";
print "</td>";
print "<td>";
print mysql_field_name($result, 0) . ": " . $row[ID]."<br>";
print mysql_field_name($result, 1) . ": " . $row[name]."<br>";
print mysql_field_name($result, 2) . ": " . $row[address]."<br>";
print mysql_field_name($result, 3) . ": " . $row[city]."<br>";
print mysql_field_name($result, 4) . ": " . $row[telephone]."<br>";
print "</td>";
print "</tr>";
print "</table>
";
print "<br><br>";
}

Formatting Mysql_fetch_array Results In HTML Table
This looks like a simple problem, but I just can't seem to wrap my
head around it.

I'm trying to build a table dynamically, based on a result set from
mysql. There will be 9 results for a full page, with 3 table rows of 3
table cells. One result per cell. But all of the pages won't be full.

Here's one of many ways I've tried to do it:

<html>
<head>
<title>test</title>
</head>
<body>
<table width="100%" border="1">
<?php

include_once('db.inc.php');

$query = "SELECT DISTINCT title FROM mytable LIMIT 9";
$result = mysql_query($query);

while ($row = mysql_fetch_array($result)) {
$title = $row['title'];
}

for ($i = 0; $i < 3; $i++) {
print ' <tr>' . "
";

for ($e = 0; $e < 3; $e++) {
print ' <td align="center">' . "
".
' title : ' . $title . "
".
' </td>' . "
";
}
print ' </tr>' . "
";
}

?>
</table>
</body>
</html>

This prints out 3 rows of three like I hoped, but $title is the same
in all 9 cells. I also have tried it with the for loops inside the
while loop, which prints out 9 rows of 9 cells 9 times!

Displaying SELECT Results In A Formatted Table
I was wondering how to show a table with a max limit of 20 results per page. I have various data being pulled and its putting it in a table, but its displayed all in one row. I want to format it so its a 4 column/5 row table. With that I then want the page to generate a numbered list at the bottom that calculates how many pages it takes to show 20 items on each. Code:

Displaying SQL Query Results In 3 Column Table
I would like to be able to display the results of an sql query in an html table, but the results need to be displayed in three columns, for example:

Column 1 Column 2 Column 3
Result 1 Result 2 Result 3
Result 4 Result 5 Result 6
Result 7 Result 8 Result 9

I've tried to find the answers on the internet but i can't find anything that suits my needs!

Display Sql Query Output In Html Table
As evident from a previous post, I am a php noob. I would like to
display MySQL query results in an html table with one of the row values as a
category and the rest of the data displayed under the relevant category.

I can get as far as displaying the data in a nice readable format but I
don't know how to have the records placed under their corresponding
category. This is my code thus far (sans the html output):

....ORDER BY cat ASC'
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
printf("%s Class: %s Description: %s", $row["cat"]$row["title"],
$row["desc"]);
}

Display Results Of Survey In A Table.

Is it possible to have them fill in a survey with about 10 form fields, then display the results of everyone's survey in a table that can be sorted by different criteria so new users to the site can instantly see which one of our services is better for them.

Is it possible to have them fill in a survey with about 10 form fields, then display
the results of everyone's survey in a table that can be sorted by different criteria
so new users to the site can instantly see which one of our services is better for them.