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Displaying SELECT Results In A Formatted Table


I was wondering how to show a table with a max limit of 20 results per page. I have various data being pulled and its putting it in a table, but its displayed all in one row. I want to format it so its a 4 column/5 row table. With that I then want the page to generate a numbered list at the bottom that calculates how many pages it takes to show 20 items on each. Code:




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Loop To Print Formatted Table From Sql Results
I'm trying to create a 3 column table now, and each cell will contain info from a single record. All the records will be pulled from a mysql database.

What makes this a bit difficult is that I want the center column to be blank. Only the first and third columns will contain the results. I can't get the desired effect, and I'm not sure my loop logic is even correct. Does anyone know what's wrong with my code?
Code:

Displaying Select Information From XML Search Results
I am new to both php and xml. I have a school assignment to update an existing php-based website where I have to display search results from an online library. I can use a url search which returns an XML file that includes tags such as position, title, url, description, date, etc.

I only want to display the title, url (preferably the title should be a link to the url), and description for all of the results on my website's search results (different template as well).

What classes/functions are available to help me do this? I would appreciate any guidance as well as links to online tutorials etc. that would point me in the right direction. I have read about the general aspects of php, and I have experience with Java and C; but I don't know about xml at all.

By the way, the website is running on the school server and has php version 4. I don't think I'll be able to install php 5 but I can probably upload some helper files or something.

Displaying Array Results In Table
I'd like to display the results of an array in a table format with the Alias, Alias Destination & Username as column headings & the results underneath. PHP Code:

Displaying SQL Query Results In 3 Column Table
I would like to be able to display the results of an sql query in an html table, but the results need to be displayed in three columns, for example:

Column 1   Column 2   Column 3
Result 1     Result 2     Result 3
Result 4     Result 5     Result 6
Result 7     Result 8     Result 9

I've tried to find the answers on the internet but i can't find anything that suits my needs!

Help With Displaying Selecting A Date Range And Displaying Results
I wish to create a simple form that allows the selection of a start date and a stop date with the ability to select what columns to be displayed in the result page.

Table Background Color Based On Results From MySQL Table
I am trying to get the "Did User Agree" field on a database query to be colored Green for "Agreed" Red for "Disagreed" and Blue for "Agreed (2nd Time)" .. I have my PHP setup to do the query just fine as of right now with alternating column colors, just can't seem to get the colors to work as I am hoping for.  Can anyone help me get the Agreed? table's background color to the colors above? Code:

Displaying Limited Results
I have a problem that is related to limiting the results displayed in a page. I have a numbered pagination script working that has a limit etc. At the moment it is milited to displaying 8 results before producing the next link.

What I have is a table with 2 columns and 4 rows....a grid of 8. I want the results to start in the top left and then when 2 table cells have been created it will start a new row and do this for all of the results ie:

1 2
3 4
5 6
7 8

Basically, i need code that will make a new row start when 2 results have been displayed in that row.

Help With Function For Displaying Calculation Results
I am developing a betting calculator and at the moment I am working on some functions that can be used to display the HTML for the form to enter your bet and odds and the results.

I am still relatively new to PHP and I am learning all the time so sorry if this is a simple problem!

I have 3 files: calc1.php, index.php and funtions.php

Here is index.php PHP Code:

Displaying Results On Multiple Pages
I have a search query via PHP and MySQL that has list of results, but I only want to show 10 or 15 on a page. Much like Yahoo! or even here on the Devshed forums. I have been working on a system that cycles through all the results with a while loop and a counter. It only displays results >= 11 or <=20 as an example. I am passing that data (the results start point through the url) I am just worried that if the results are in the thousands this system would get very slow.Is there an easier/better way that I am not seeing?

Nesting Queries And Displaying Results.
i am in the process of trying to make a simple system to keep track of switch ports and what points they are conencted to. the problem i am having is with displaying the data from my ports table. Code:

mysql> select * from Switch_Ports;
+------+----------+---------+------------+--------+
| SwID | Port_NO | VLAN | Patch_Port | PortID |
+------+----------+---------+------------+--------+
| 1 | fa1/0/1 | staff | AA10 | 1 |
| 1 | fa1/0/2 | staff | AA12 | 2 |
| 2 | fa1/0/10 | staff | AA100 | 3 |
| 2 | fa4/0/12 | staff | BB12 | 4 |
| 3 | fa2/0/11 | student | A16 | 5 |
| 3 | fa1/0/23 | student | B14 | 7 |
+------+----------+---------+------------+--------+

SwID relates back to my Switch table, which contains dns names and stuff like that. for example i want to be able to display the ports from SwID 1 PHP Code:

Displaying X Number Of Results Per Page
What I need to do is this. I query a MySQL database and, for example, 400 results are returned. I can get it to display the number of results, but I would like to set a value to display, say 20, results per page and generate numbered links with and offset to browse through and next/previous buttons -not unlike this page. Can anyone point me in the direction of a good article or if you have it, post some code here?

Displaying Database And Getting Unwanted Results...
I want to display everyone in the database, but only if the 'level' field is larger than 0.  Well, this works fine for most of the database... but if the last entry in the database is 0, then it prints it anyways.

Is there anyway around this?  I tried adding an if statement before the last bit where I echo out the table rows, but it was killing the entire table, or still showing the same results. Code:

Displaying Results With Decimals, And Stylizing Them.
I just have what I think is an easy question for some of you. I have a page that pulls all the entries from a specific table in the database. The results are displayed in a table. In this table there is  column for "job_number" this job number is a decimal entry, i need to display the job numbers, grouped by the the numbers ahead of the decimal place and then ordered by the numbers after the decimal. I would also like to indent the decimals ONLY numbers below the under that does not have a decimal. Code:

Displaying Results From Database In A Particular Format
How do I display results from a database in a particular format.  For example the following text in this format including the lines in stored in the database:

Quote“Hello,

Welcome to the news for 11/06/07.

Thanks”
When I echo the results using the usual, <? echo $row_news[‘news’]; ?> it doesn’t echo the information in the database in the format it is stored for example it will display like this.  Quote“Hello, Welcome to the news for 11/06/07. Thanks”  How do I get it to display in the format it in displayed in the database?

Displaying Search Results In Pages
I am implementing search functionality in a website. ( internal search).
In that I am taking a keyword as input and searching all the pages and storing
results in an array. I want to display 10 results per page. I wrote below logic for that. Code:

Displaying MySQL Results As URLs
I'm attempting to turn the results of a query into urls, yet I keep getting this error, "Parse error: syntax error, unexpected '<' in staff.php on line 190." I've coded and recoded this, yet for some reason I cannot get this error to go away. I know it's probably simple, but what am I missing? Code:

Splitting Results Using Select Tag
when i can make a choice out of let say 10 in a form:

<select name=choice>
<option value=1>1
....
<option value=10>10
</select>

when i submit it will split up de results after the first loop but when i choose "next results" it does not see the value anymore and returns nothing, so how can i solve this?

Displaying A List Of Categories From A Database In A Select Box
Could someone please tell me why this outputs nothing

<select name=categories>
<?
$cat_array = get_categories();
foreach($cat_array as $this_cat)
{
echo "<option value="";
echo $this_cat["category_id"];
echo """;
echo ">";
echo $this_cat["category_name"];
echo "
";
}
?>
</select>

==========================================================

function get_categories()
{
//get the list of categories from the database

$conn = mysql_pconnect("localhost", "user", "pwd");
$query = "select * from categories";
$result = mysql_query($query);
if(!$result)
return false;

$num_cats = mysql_num_rows($result);
if($num_cats == 0)
return false;

$result = db_result_to_array($result);
return $result;
}

//A function that returns a query to the database as an array
function db_result_to_array($result)
{
$res_array = array();
for($count=0; $row=@mysql_fetch_array($result); $count++)
$res_array[$count] = $row;

return $res_array;
}

Displaying Select Multiple Box And Using Mysql Join
i have an edit page where the query lists all the information from the database about a business. each business can have multiple types so i made a many-to-many database and now i need to be able to show all the types that are in the db for each business on the edit page. here is what i have so far but it's only selecting the last type of business in the result. PHP Code:

Displaying X Number Of MySQL Results Per Page
I'm writing a search on a MySQL DB, and everything so far has just gone swimmingly. I've got a "results per page" drop down box in my form, with a few different values.

At the moment, I'm just using:

while($myrow = mysql_fetch_array($result)

to output results to screen.

I'm not too sure how to go about it, but I did have two thoughts:

1) Suck the results into a multi-dimensional array, and pass the array to a display results script (not sure if you can pass arrays to other scripts???

2) Display x number of results, then have the "Next" (or 2, 3... ) links call the search again, but displaying results x+1 - x+x.

1 sounds like too much trouble, and 2 sounds inefficient. Not too sure how else to go about it. Any info / thoughts you guys have would be much appreciated.

On a side note, how do you look at a specific row in the result?

Splitting Select Results Into Pages In PHP
I'm new to PHP and Mysql, so I was hoping someone more experienced could help me with this one.

I've gone through most of Kevin Yanks excellent tutorial on Databases, but I haven't found an answer to my question.

I'd like to split the text results of a select command into a number of pages. I'd like to display 10 jokes on one page, and then ten jokes on the next and so on.

Anybody have any ideas on how to do this? I've been searching the web for most of the morning, but haven't really found the answer I needed and I was hoping somebody could give me a hand.

How Can I SELECT Results Visible To Crawlers?
I have seen a few site search result pages come up in Google etc. when similar search criteria were entered in Google as if they were entered in the site.

Sounds Good! I thought all dynamic output and database content was invisible to spiders.

I was thinking I could do every kind of category search on my site and save each page as a static HTML page, but it's heaps of time and there must be a better php way! Also I am not sure if they would be spidered at all as they wouldn't be obviously linked to.

Arrays, Query Results And Select Box
I want/need to pre-select a drop-down box with a value if it's present in both a lookup table and user account table. After wrestling with this for a few hours I give up.

i know this can't be this complicated, but apparently i'm missing something, so if anyone can suggest a way to go about this i'd be a little more sane. The idea is to have the user value already selected then when they change the value i'll update their account.

Using Select And Where And Ordering Results Issues
I'm trying to show the most recent downloads added to my site and then ordering them by the last 5. The code below doesn't return any results. Any ideas on what i'm doing wrong? Code:

How Do I Return 10 Results Per Page Using SELECT Statement?
I'm wasn't sure whether to post this under the PHP or under the MySQL section of the forums. Since most people (I'm assuming) who write PHP script, also use MySQL, I thought I'd stick with PHP. I'm rather new to both PHP and MySQL and I'd be very grateful to anyone who can help me solve a problem I'm having at the moment. First, I'll give you an introduction to my little project...

I'm developing a database in MySQL that is used to store the song titles of all the MP3s I have on my PC. I've written a basic search feature that works well. The user has 2 options: Either he can type a special "!ALL" "parameter", that I made up, to return all the songs in the database or the user may enter a few characters in the textbox and select "song title" or "artist" etc. from a dropdown to search for a specific song title or artist etc.. Hope you are following so far? Say for example the user presses submit after typing "!ALL" to return all the song titles - there could be hundreds of results. What I want to do now is display 10 results on a page, then on the next page another 10, etc. (like a real search engine!). I've tried doing it with the LIMIT statement, but like I said I'm new to this and discovered that that is not the right way of going about it. My question is this: how would I go about returning 10 matches per page? Do I use hidden form fields? What would the SELECT statement look like? What would the PHP scripting look like to setup the "back" and "forward" navigation between the result for the search?

Select And Display Multiple Queries / Results
Howdy all, i've been looking through various sites / tutorials and through this php book I have here to try figure out whats causing this problem but haven't had any luck yet.

The problem is that its displaying the Designation as the link url instead of the jcode. Hope i explained this well. Above this bit of code has calls the individual Catagorys, if theres data in that catagory it will display it with whats below. PHP Code:

Taking SELECT Results And Turning Them Into An Array()
Does anyone know how take a mysql select statement and have the results placed into an array? I am returning 1+ rows and want to place those rows into an array so I can run a foreach() for each row and then run another foreach() for each column for each row? Code:

SELECT Statement Results Into Text File
I am trying to create a text file based off the results of a query statement from a database. See code below:

$itemq = "SELECT sdlitm, sddsc1, sduorg, sdlnid, sduncs FROM F4211 WHERE sddoco = $ordernum AND sddcto LIKE '$ordertype' ORDER BY sdlnid";
$result3 = odbc_exec($connect, $itemq);
    while (odbc_fetch_row($result3)){
    $partnum = odbc_result($result3, 1);
    $desc1 = odbc_result($result3, 2);
    $qty = odbc_result($result3, 3)/100;
    $position = odbc_result($result3, 4);
    $uncs = odbc_result($result3, 5);
    $extcost = $uncs*$qty;
    $total = ($total + ($uncs * $qty));
    $filename = "$reportnumber.txt";
    $fp = fopen($filename, "w");
    fwrite($fp, "Activity Number: $reportnumber
");
    fwrite($fp, "Warranty Type: $reason
");
    fwrite($fp, "Customer Name: $custname
");
    fwrite($fp, "$qty $partnum $desc1
");
    fclose($fp);

Everything works fine until I get to the line:

fwrite($fp, "$qty $partnum $desc1
");

This line should actually print multiple lines into the text file as these are the line items from an order. There could be anywhere from 1 to 20 lines written to the text file. As it stands, the only line items written to the text file are those of the last line found on the order. The entrie script dealing with the text file are still within the confines of the while statement curly braces. How do I write these lines out in the text file??

Paginating Random Select Query Results
I am just starting with PHP/MySQL and using Dreamweaver MX 2004.
I am selecting a subset of records from a table, then ordering them using RAND() and then displaying 6 at a time on a page. So far so good but there is one major problem, namely, when you move from page to page viewing the results the query is rerun for each page which means that you end up duplicating results.

What I want to be able to do is run the query once and then page through the returned results without duplication. Also to be able to go back & forth between pages and see the same set of results.

Here's a simplified example: Suppose I have 12 records (call them A - L).
The query : SELECT * FROM Table WHERE Criteria = 1 ORDER BY RAND()
Which returns: D F K A L F J H G C B I
So my pages should show the following:
Page 1: D F K A L F
Page 2: J H G C B I

And I should be able to switch back and forth between these pages and always see exactly the same records each time.
However what I see at the moment is:

Page 1: D F K A L F
Page 2: F B C A E D (Note duplicates from Page 1 because query has been re-run)
Page 1: C B F A K L (Note duplicates again plus results not the same as previous visit to Page 1)

Retrieving,Sorting & Displaying Multiple Results From Mutliple Tables
I need to know how to run a php / mysql query to do the following.

I have 1 database (lets call it "database" for now) within this database there are multiple tables ("News","Feature","Header_feature")

For NEWS I need only the 6 latest results pulled from that table and displayed in a table.  The "News" table has the following columns "ID","Title","Date","Body","Image"

For Feature I need only 1 result retrieved from the database and displayed under the variable $ticker as it will display as a scrolling marquee within a table.  The "Feature" table has the following columns "ID","Ticker".

For Header_feature I need only 1 result retrieved from the database and displayed in the following manner <a href="$link"><img src"$header_feature">[/url]  The "Header_feature table has the following columns "ID","image","link"

How would I code this all into 1 page?  I cant seem to get the query to do everything I want it to and display the results properly.  You can see what I have so far at www.getlivemedia.com  The $ticker is the scrolling text near the top of the page and the news is obviously the bulk of the page and $feature_image is the broken image.

Displaying # Of Records In A Table
Can anyone throw me a link to some prefab code, or a tutorial on how I can get a page to display the number of records that meet a certain criteria.

example:
I have a page that stores information on audio FX. I'd like to include a feature that would let the users know how many items are in a particular section.

Player (10)
Items (5)
Weapons (0)
etc.

All help appreciated,

Displaying A HTML Table With PHP
I'm new to PHP and I'm trying to get my head around databases at the moment. So far I have a page that kinda takes the mickey and takes a few details from you, it then creates a cookie that can be removed later. It also prompts you to add the data you gave to a database.

All this works perfectly, but when it comes to displaying the results of the database, all I can show is the first entry in the table. Can someone please tell me how I'm supposed to see all of them?

I've read other articles but they don't make much sense to me.

BTW, the database details are as follows:

Database name: visualanteorg
Table name: people
Fields: id, name, shoe_size, job

As you will see if you choose to look at the pages, getting the information out is not a problem, it's just formatting it how I want it, so each entry appears under the other in the table.

Displaying Table In Php Code
I have a PHP script that has a drop down to select a record, then it should display some text from a database and then display a table of information below it. But, the table is displaying at the top instead. Code:

Select Value In A Table
In my sql table I've a list of colors: white, blue, green.....
table colors:
idcolor, coloname
1, white
2, blue
3, green.....
I've some programs sending colors for some material, but I don't want to use
them, I'd like to use my values:
example:
program gives 'dark blue' then I'd like to select blue in my table and...

Grabbing Data From A Table And Displaying It
I'm grabbing data from a table and displaying it but I want to to spand out into multiple pages...I got it all setup but when I click on the next link nothing happens... I got it setup at "3" right now just for testing..I have 5 entries in the database.. anyways could someone help me out? here is the code:

<?php

// Get connection info
include "../connect.php";
// End connection info
if(!$rowstart) $rowstart=0;
// Start database select
$result = mysql_query(
"SELECT * FROM links WHERE notactive='$notactive' order by date desc limit $rowstart,3"); //Select Database
$result2 = mysql_query("select * from links");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>"); exit(); }
// Display the text of each host
while ( $row = mysql_fetch_array($result) ) {
if ($notactive = 1) {
echo ("<table width=500 height=57 border=0 cellpadding=0 cellspacing=0>");
echo ("<tr>");
echo ("<td align=left valign=top><strong>" . $row["name"] . "</strong></td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top>" . $row["desc"] . "</td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top><a href=" . $row["url"] . ">". $row["url"] ."</a></td>"); }
echo ("</tr>");
echo ("<br><br>");
echo ("</table>");
}
if ($rowstart>$numrows)
{
echo "<A HREF=$php_self?rowstart=rowstart-3>";
echo "< Previous Page</A>";
}
echo "|";
$numrows=mysql_num_rows($result2);
if($rowstart+3<$numrows)
{
echo "<A HREF='$php_self?$rowstart=rowstart+3'>Next Page></A>";
}
?>

Grabbing Data From A Table And Displaying It
I'm grabbing data from a table and displaying it but I want to to spand out into multiple pages...I got it all setup but when I click on the next link nothing happens... I got it setup at "3" right now just for testing..I have 5 entries in the database.. anyways could someone help me out? here is the code:

<?php

// Get connection info
include "../connect.php";
// End connection info
if(!$rowstart) $rowstart=0;
// Start database select
$result = mysql_query(
"SELECT * FROM links WHERE notactive='$notactive' order by date desc limit $rowstart,3"); //Select Database
$result2 = mysql_query("select * from links");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>"); exit(); }
// Display the text of each host
while ( $row = mysql_fetch_array($result) ) {
if ($notactive = 1) {
echo ("<table width=500 height=57 border=0 cellpadding=0 cellspacing=0>");
echo ("<tr>");
echo ("<td align=left valign=top><strong>" . $row["name"] . "</strong></td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top>" . $row["desc"] . "</td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top><a href=" . $row["url"] . ">". $row["url"] ."</a></td>"); }
echo ("</tr>");
echo ("<br><br>");
echo ("</table>");
}
if ($rowstart>$numrows)
{
echo "<A HREF=$php_self?rowstart=rowstart-3>";
echo "< Previous Page</A>";
}
echo "|";
$numrows=mysql_num_rows($result2);
if($rowstart+3<$numrows)
{
echo "<A HREF='$php_self?$rowstart=rowstart+3'>Next Page></A>";
}
?>

Grabbing Data From A Table And Displaying It
I'm grabbing data from a table and displaying it but I want to to spand out into multiple pages...I got it all setup but when I click on the next link nothing happens... I got it setup at "3" right now just for testing..I have 5 entries in the database.. anyways could someone help me out? here is the code:

<?php

// Get connection info
include "../connect.php";
// End connection info
if(!$rowstart) $rowstart=0;
// Start database select
$result = mysql_query(
"SELECT * FROM links WHERE notactive='$notactive' order by date desc limit $rowstart,3"); //Select Database
$result2 = mysql_query("select * from links");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>"); exit(); }
// Display the text of each host
while ( $row = mysql_fetch_array($result) ) {
if ($notactive = 1) {
echo ("<table width=500 height=57 border=0 cellpadding=0 cellspacing=0>");
echo ("<tr>");
echo ("<td align=left valign=top><strong>" . $row["name"] . "</strong></td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top>" . $row["desc"] . "</td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top><a href=" . $row["url"] . ">". $row["url"] ."</a></td>"); }
echo ("</tr>");
echo ("<br><br>");
echo ("</table>");
}
if ($rowstart>$numrows)
{
echo "<A HREF=$php_self?rowstart=rowstart-3>";
echo "< Previous Page</A>";
}
echo "|";
$numrows=mysql_num_rows($result2);
if($rowstart+3<$numrows)
{
echo "<A HREF='$php_self?$rowstart=rowstart+3'>Next Page></A>";
}
?>

Grabbing Data From A Table And Displaying It
I'm grabbing data from a table and displaying it but I want to to spand out into multiple pages...I got it all setup but when I click on the next link nothing happens... I got it setup at "3" right now just for testing..I have 5 entries in the database.. anyways could someone help me out? here is the code:

<?php

// Get connection info
include "../connect.php";
// End connection info
if(!$rowstart) $rowstart=0;
// Start database select
$result = mysql_query(
"SELECT * FROM links WHERE notactive='$notactive' order by date desc limit $rowstart,3"); //Select Database
$result2 = mysql_query("select * from links");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>"); exit(); }
// Display the text of each host
while ( $row = mysql_fetch_array($result) ) {
if ($notactive = 1) {
echo ("<table width=500 height=57 border=0 cellpadding=0 cellspacing=0>");
echo ("<tr>");
echo ("<td align=left valign=top><strong>" . $row["name"] . "</strong></td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top>" . $row["desc"] . "</td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top><a href=" . $row["url"] . ">". $row["url"] ."</a></td>"); }
echo ("</tr>");
echo ("<br><br>");
echo ("</table>");
}
if ($rowstart>$numrows)
{
echo "<A HREF=$php_self?rowstart=rowstart-3>";
echo "< Previous Page</A>";
}
echo "|";
$numrows=mysql_num_rows($result2);
if($rowstart+3<$numrows)
{
echo "<A HREF='$php_self?$rowstart=rowstart+3'>Next Page></A>";
}
?>

Displaying Information In A 1 Row/2 Column Table
I'm very new to php scripting and haven't quite figured out what I need to do here.

I need to display information in a 1 row/2 column table. I have the MySQL query working fine, but the scripting part in php is killing me!

In the first column a graphic about 70x70 will be shown (plus some additional padding). In the second column will be the description information. The second column will be around 400 pixels wide.

How do I set this up in php? It's easy enough in HTML, but I've about killed myself trying to figure out how to properly lay this out in php!

Displaying Records In A Split Table?
trying to split up results of a query into a split table. example: PHP Code:

Displaying Data In Html Table.
I wondered if anyone could offer some guidance, I trying to write a
php script to connect to a database, and display the records in a
table.

I found the code here in a php4 text, and when I run this directly
through the php intrupeter, the line Successfully connected is display
and 4 as the number of rows.

The database table we connect to, has three field username, firstname,
surname.

When I tried a while loop, to display the data in a table. No values
were displayed.

Could anyone possibly demonstrate how to display the username,
firstname, surname values in a basic table?

<?php
function db_connect(){
global $MYSQL_ERRNO, $MYSQL_ERROR;

$link_id = mysql_connect("localhost","user04", "password04");

if(!$link_id){
$MYSQL_ERROR = "Connection failed";
return 0;
}
else if(empty($dbname) && !mysql_select_db("database04")){
$MYSQL_ERROR = mysql_error();
return 0;
}
else return $link_id;
}

!$link_id = db_connect();
if(!$link_id) die(error_message('Error connecting'));

$result = mysql_query("SELECT * FROM users");
if(!$result) error_message('Error in selection');
else echo "Successfully connected. ";

$query_data = mysql_fetch_row($result);
$total_records = $query_data[0];

if(!$total_records) error_message('No records');
else echo "$total_records.";
?>

Displaying Table Field List
I got a function that displays a list of the fields in a certain mysql table.  I got it off of this site.  The problem is that it only displays the word Array and I'm not sure why.  This is the code for the function: Code:

Displaying A Table Using ID Number As Hyperlink
i am able to insert and display data to the end user, but i am trying to let the end user edit a row. I am unsure how this is usually done, but i am have the following code to display by data

 echo "<table border='1'><thead><tr>";
            for($i = 0;$i < mysql_num_fields($sql_result);$i++)
            {
             echo "<th>".mysql_field_name($sql_result,$i).
                  "</th>";
            }
     echo "</tr></thead>
           <tbody>";
     for ($i=0;$i < mysql_num_rows($sql_result);$i++)
     {
        echo "<tr>";
        $row = mysql_fetch_row($sql_result);
        foreach($row as $value)
        {
           echo "<td>".$value."</td>";
        }
        echo "</tr>";
     }
     echo "</tbody></table>";

The user have a jump menu (combo box) to pick the table they need to show information on, so the columns displayed are going to vary, but i have a column called ID which is the same in each tables which is the index (auto increment) field.

I was thinking about using this number comnbined with a hyperlink, so the user can click it to take them to a page to edit that row.... But i have no idea how to do this, or if there is an easier way which i just do not know; or how do most people achieve what i require...

Select From A Mysql Table
I want to pull one field from a mysql table. How do I do that? Do I use SELECT? The field name is $sip_visitornum. And I want the last value that was inputted in to the db. I already have the code to get the visitor number but I don't know how to display data from the database properly. Thanks.

Merge Select From 2 Table
I've 2 tables where I want to retrieve the id and name from and merge them:

table1:
IDtable1-nametable1
1 - 578445
2 - 454545
3 - 554887

table2:
IDtable2-nametable2
X1 - 544512
X2 - 445775

The result should look like (order by nametable)
X2 - 445775
2 - 454545
X1 - 544512
3 - 554887
1 - 578445

(this result will be used for filling a combobox).
I may excecute 2 queries, put the results in an array and then order it, but
I'm sure there is a better way in MySQL, but I couldn't find it.

Select Country From Second Table
I have a form with a standard text box that i would like to turn into a drop down box that is populated from a mysql table. How do I change the code of the text box so that it looks at the table and populates the list?

Here is the code for the text box
<input type="text" name="country" size="20" maxlength="20">
The mysql table has the following fields in it:

Select * From Table When Field Is Less Than 3
i think it simple but i want to select all db entries where a certain field is less than 3?

Displaying A URL Stored In A Table As An Image On The Page?
In a table in my database I have a column for storing the URL of an image of a product. What PHP code would I use to display the image? PHP Code:

Combining Data From Two Fields, Displaying With Another Table
What I am trying to do is pull data from two tables and display it on one page. The code below doesn't display any errors, but all it prints is the results from the first query. Ideas? Thanks.

(I also need to somehow put a variable in for the warranty table data so it is tied to the product_status table data. You can see there is a WHERE in the first query of pid, but no WHERE in the second query. That is a seperate question, though. It would make this way too long, so I will post it separately). PHP Code:


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