PHP :: Displaying Table Field List

Get List Of Messages From One Table, Message List Indicator From
I have two tables. One has a list of messages left by users using fields named mbxno for the mailbox and msgno for the message number. I have another table that has mailbox settings for each user that contains a field named "messagelist" to indicate if they want to be included on the message list or not.

What I'm trying to create is a list of the most-recent messages with a lookup on the users table to indicate whether a message in the list should be included in the message list based on the user's mailbox settings.

SELECT messages.msgno, messages.mbxno, users.messagelist FROM messages, users WHERE (users.messagelist = Ƈ') ORDER BY msgno DESC LIMIT 100

What I'm getting, though is a list that looks like this:

mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 1114 msgno: 0412141623 msglist: 1

I think what's happening is that I'm using the wrong type of join and more rows are being created than necessary.

If I add "DISTINCT" to the query, I get a list of the most-recent messages as I expect, but the "messsagelist" value is sometimes wrong (again, probably because the data is getting jumbled). For example, the messagelist value for the second row (2214) should be 0, not 1.

mbxno: 1114 msgno: 0412141623 msglist: 1
mbxno: 2214 msgno: 0412141622 msglist: 1
mbxno: 2189 msgno: 0412141408 msglist: 1
mbxno: 0000 msgno: 0412141213 msglist: 1
mbxno: 0003 msgno: 0412141213 msglist: 1
mbxno: 2265 msgno: 0412132029 msglist: 1
mbxno: 0000 msgno: 0412131950 msglist: 1

How should I be doing this? If nothing else, what kind of join will work with a long list compared to a value from a short list?

Displaying List W/out Repeats
I'm working on a project that will allow people to upload content and make entries to a database. I want to build a menu that will display the different values for a certain field, but I know that there will be identical values throughout the table. Do I need to dump values into a separate table, or can I use the values that are there and somehow ignore the repeats?

Displaying A List Of Members Logged In
I wish to display all of the current members who are logged into the system. I figure I can do this using their session id's and matching their usernames accordingly. Or I could create a separate table containing their username and INSERT when someone logs in and DELETE when someone logs out. Then i could display the contents of the table.

Mysql Field List
We would like to be able to get the column list of a mysql Table from PHP code. I know from the mysql prompt we can get it, but we want to generate PHP code
that will retun an array of columns If there is a column descriptor containing
name, size, etc, that would be great. Something that I could loop thropugh an array in
PHP4 and get the names of all the columns in the table as well as perhaps
other column parameters as well. I believe that can be done in CGI, but want to use
PHP4.

Displaying Information From A Database In A Text Field,
I am trying to create an admin page, but before I get anywhere near that, I need to understand how to get data froma database to show up in appropriate form fields *text, textarea, etc...*

I am able to get content from my database to show up in my template, now I want to create a page that allows a user to click on a link for which they want to edit the information (name, and bio) So I want that page to show up with a simple form, a text field displaying the name, and a textarea displaying the bio information, so that they can modify it and save it to the database. how do you get the information to show up in the form fields? Code:

Displaying First 50 Characters Of A Mysql Text Field?
I have been searching for hours on the php website for a function that
will allow me to display just the first 50 chars of a mysql text field
in a results table, but i'm having no luck. I need it to create a
results page for a site i'm creating in php.

Displaying Info From User's Field In Numbers
in a loop, what would i use to like, if ina field a user has say 4 'f's (ffff) and i want it to display, You Have: 4 f(s)! but theres gonna be like, lets say the whole alphabet in there, and she can get a new 'f' every minute if she wanted...so anyone have suggestions? and in this table im haveing i have 3 fields, owner(the user) id(the letternumber) and name(the letter itself)

Displaying A List Of Categories From A Database In A Select Box
Could someone please tell me why this outputs nothing

<select name=categories>
<?
$cat_array = get_categories();
foreach($cat_array as $this_cat)
{
echo "<option value="";
echo $this_cat["category_id"];
echo """;
echo ">";
echo $this_cat["category_name"];
echo "
";
}
?>
</select>

==========================================================

function get_categories()
{
//get the list of categories from the database

$conn = mysql_pconnect("localhost", "user", "pwd");
$query = "select * from categories";
$result = mysql_query($query);
if(!$result)
return false;

$num_cats = mysql_num_rows($result);
if($num_cats == 0)
return false;

$result = db_result_to_array($result);
return $result;
}

//A function that returns a query to the database as an array
function db_result_to_array($result)
{
$res_array = array();
for($count=0; $row=@mysql_fetch_array($result); $count++)
$res_array[$count] = $row;

return $res_array;
}

Displaying A List Of All Modules (extensions) Installed
I just signed up for a web hosting service. They have PHP, but can't
tell me which modules (extensions) are installed.

Is there a function, or some other easy way, to show all modules
(extensions) that are installed? phpinfo() doesn't do this.

Limit A Database Field To Displaying Only One Time And Still Display All?
I have a data table with a field that contains the exact same text (example "some text") on several different rows. How can I display all my rows without getting duplicates of this field; I only want to display this field once. I tried to use a LIMIT, but this is not what I needed. Code:

Print Out A List Of All Mysql Field Names
I'm trying to make a drop down menu which has got a list of all field names that are in a database so you can do a search in each field seperatly but i can't find out how to do it.. can it be done with mysql_field_name and if so then anyone knows how ??

Unknown Column 'icaodesc' In 'field List'
I'm getting the following error message...

Unknown column 'icaodesc' in 'field list'

when I try to update a table from a PHP form.

What 'field list' is it referring to? My PHP script or the MySQL
table???

Here is the PHP script I'm using...

<?php

//set up table and database names
$db_name ="xxx";
$table_name ="yyy";

//connect to server and select database
$connection = @mysql_connect("localhost","user_name","password") or
die(mysql_error());
$db = @mysql_select_db($db_name,$connection)or die(mysql_error());

//build and issue query
$sql ="UPDATE $table_name SET
icaodesc ='$_POST[task_icaodesc]',
icaosource ='$_POST[task_icaosource]',
icaonote ='$_POST[task_exp_outcome]',
usposition ='$_POST[task_usposition]',
expoutcome ='$_POST[task_exp_outcome]',
usposition ='$_POST[task_usposition]',
usaction ='$_POST[task_usaction]'
WHERE task_id ='$_POST[id]'";

$result = @mysql_query($sql,$connection) or die(mysql_error());
?>

icaodesc was the NAME in the updatable form. task_icaodesc is a
"good" field in the table yyy

Comma Separated List In MySQL Field
say I have a list of categories in a field, and a page that is supposed to pull from the db based on a category. Is there any way I can do a query where it searches the contents of that field for the category in question?

like SELECT FROM table WHERE category = $category but have it search the category field (the comma separated list for each entry) for the $category var

Displaying Data From Mysql Database In A Drop Down List On Form.
I'm trying to do is display data from two different mysql tables from the same database in a drop down list on a html form. I have a fixtures table with the player1(userid), player2(userid), gameid, game, score1 and 2, what I want is to use the userid to get the players first name and surname from the members table (as it is a unique id), I need to do this bit before displaying it in the drop down. I think i need 2 querys to do this but when I have tried it it just echo's a blank value or the userid not the forname and surname that I want. I'm using the fetch_array function but just can't see where I'm going wrong, Code:

Displaying # Of Records In A Table
Can anyone throw me a link to some prefab code, or a tutorial on how I can get a page to display the number of records that meet a certain criteria.

example:
I have a page that stores information on audio FX. I'd like to include a feature that would let the users know how many items are in a particular section.

Player (10)
Items (5)
Weapons (0)
etc.

All help appreciated,

Displaying A HTML Table With PHP
I'm new to PHP and I'm trying to get my head around databases at the moment. So far I have a page that kinda takes the mickey and takes a few details from you, it then creates a cookie that can be removed later. It also prompts you to add the data you gave to a database.

All this works perfectly, but when it comes to displaying the results of the database, all I can show is the first entry in the table. Can someone please tell me how I'm supposed to see all of them?

I've read other articles but they don't make much sense to me.

BTW, the database details are as follows:

Database name: visualanteorg
Table name: people
Fields: id, name, shoe_size, job

As you will see if you choose to look at the pages, getting the information out is not a problem, it's just formatting it how I want it, so each entry appears under the other in the table.

Displaying Table In Php Code
I have a PHP script that has a drop down to select a record, then it should display some text from a database and then display a table of information below it. But, the table is displaying at the top instead. Code:

Grabbing Data From A Table And Displaying It
I'm grabbing data from a table and displaying it but I want to to spand out into multiple pages...I got it all setup but when I click on the next link nothing happens... I got it setup at "3" right now just for testing..I have 5 entries in the database.. anyways could someone help me out? here is the code:

<?php

// Get connection info
include "../connect.php";
// End connection info
if(!$rowstart) $rowstart=0;
// Start database select
$result = mysql_query(
"SELECT * FROM links WHERE notactive='$notactive' order by date desc limit $rowstart,3"); //Select Database
$result2 = mysql_query("select * from links");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>"); exit(); }
// Display the text of each host
while ( $row = mysql_fetch_array($result) ) {
if ($notactive = 1) {
echo ("<table width=500 height=57 border=0 cellpadding=0 cellspacing=0>");
echo ("<tr>");
echo ("<td align=left valign=top><strong>" . $row["name"] . "</strong></td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top>" . $row["desc"] . "</td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top><a href=" . $row["url"] . ">". $row["url"] ."</a></td>"); }
echo ("</tr>");
echo ("<br><br>");
echo ("</table>");
}
if ($rowstart>$numrows)
{
echo "<A HREF=$php_self?rowstart=rowstart-3>";
echo "< Previous Page</A>";
}
echo "|";
$numrows=mysql_num_rows($result2);
if($rowstart+3<$numrows)
{
echo "<A HREF='$php_self?$rowstart=rowstart+3'>Next Page></A>";
}
?>

Displaying Information In A 1 Row/2 Column Table
I'm very new to php scripting and haven't quite figured out what I need to do here.

I need to display information in a 1 row/2 column table. I have the MySQL query working fine, but the scripting part in php is killing me!

In the first column a graphic about 70x70 will be shown (plus some additional padding). In the second column will be the description information. The second column will be around 400 pixels wide.

How do I set this up in php? It's easy enough in HTML, but I've about killed myself trying to figure out how to properly lay this out in php!

Displaying Array Results In Table
I'd like to display the results of an array in a table format with the Alias, Alias Destination & Username as column headings & the results underneath. PHP Code:

Displaying Records In A Split Table?
trying to split up results of a query into a split table. example: PHP Code:

Displaying Data In Html Table.
I wondered if anyone could offer some guidance, I trying to write a
php script to connect to a database, and display the records in a
table.

I found the code here in a php4 text, and when I run this directly
through the php intrupeter, the line Successfully connected is display
and 4 as the number of rows.

The database table we connect to, has three field username, firstname,
surname.

When I tried a while loop, to display the data in a table. No values
were displayed.

Could anyone possibly demonstrate how to display the username,
firstname, surname values in a basic table?

<?php
function db_connect(){
global $MYSQL_ERRNO, $MYSQL_ERROR;

$link_id = mysql_connect("localhost","user04", "password04");

if(!$link_id){
$MYSQL_ERROR = "Connection failed";
return 0;
}
else if(empty($dbname) && !mysql_select_db("database04")){
$MYSQL_ERROR = mysql_error();
return 0;
}
else return $link_id;
}

!$link_id = db_connect();
if(!$link_id) die(error_message('Error connecting'));

$result = mysql_query("SELECT * FROM users");
if(!$result) error_message('Error in selection');
else echo "Successfully connected. ";

$query_data = mysql_fetch_row($result);
$total_records = $query_data[0];

if(!$total_records) error_message('No records');
else echo "$total_records.";
?>

Displaying A Table Using ID Number As Hyperlink
i am able to insert and display data to the end user, but i am trying to let the end user edit a row. I am unsure how this is usually done, but i am have the following code to display by data

echo "<table border='1'><thead><tr>";
for($i = 0;$i < mysql_num_fields($sql_result);$i++)
{
echo "<th>".mysql_field_name($sql_result,$i).
"</th>";
}
echo "</tr></thead>
<tbody>";
for ($i=0;$i < mysql_num_rows($sql_result);$i++)
{
echo "<tr>";
$row = mysql_fetch_row($sql_result);
foreach($row as $value)
{
echo "<td>".$value."</td>";
}
echo "</tr>";
}
echo "</tbody></table>";

The user have a jump menu (combo box) to pick the table they need to show information on, so the columns displayed are going to vary, but i have a column called ID which is the same in each tables which is the index (auto increment) field.

I was thinking about using this number comnbined with a hyperlink, so the user can click it to take them to a page to edit that row.... But i have no idea how to do this, or if there is an easier way which i just do not know; or how do most people achieve what i require...

Getting Field Count From A Table.
I've searched through devshed but haven't found a reference to how to query a database for the contents of a table, then count the number of fields in that table. Can someone help?

Say, for instance, the call was FileName.php?table=Vendors

In FileName.php, once you'd done all the happy connect stuff,

$result = mysql_query("SELECT * FROM $table",$db);

how would you count the fields in the result, regardless of the number of rows?

I thought I could use mysql_fetch_row($result), then, with a single row selected count through the $myrow[] until they ceased to exist. Is this doable? It seems this would be fairly straightforward. Is there an easier/faster/better way? I'm still thumbing through my php/mysql tomb working on the problem but haven't found an obvious solution. Your thought are sincerely appreciated.

Get Max Value In MySQL Table Field
I have a 2-field table "pageref".

The fields are: "pagerefno" - which is index and primary key, and "url".

I need to find the max value in "pagerefno", so wrote the following code:

$query ="SELECT max(pagerefno) FROM pageref";
$result = mysql_query($query) or die ("Error in query: $query. " .
mysql_error());
$row = mysql_fetch_row($result);
echo row[0];

But this results in a blank screen. I'd be grateful for a steer, here.

Nonexistant Field In Table
I have a script that updates some mysql tables using input from a text file. The query that's giving me trouble is this one:

"UPDATE $table SET `$f` = '$v' WHERE id = '$new_id'"

where $f is the name of the field and $v is the value. The problem is, some of the information in the file is outdated, so some fields don't exist anymore. If I try to run the update with a field that doesn't exist, the script halts and I get an error.

Is there any way to have the script ignore this and just keep going?

How To Get A Field In The Last Row Of Mysql Table.
There is a certain field that I wish to get in the last row (it will always be in the last row, even if I add to the table) of my mysql table. How do I output this? I assumed that I would be using a LIMIT command and a DESCRIBE command, however I looked at mysql.com and couldn't find anything .

Select * From Table When Field Is Less Than 3
i think it simple but i want to select all db entries where a certain field is less than 3?

Set Variable Name Use Field Name From Table
I have a query string that sets the value of Variables below:

if ($DB == "Departments") {
$tracking_id = $data22['tracking_id'];
$dept_name = $data22['dept_name'];}

simple and straight forward. Now I would like to set a loop that would set the variable name and value based on the field names in the table queried.

if ($DB == "Departments") {
$querystring = "Select * from ".$DB;
$result=mysql_query($querystring);
while(($field = mysql_fetch_field($result))) {
$field->name = $data22[$field->name];}}

can I set the variable name using the $field->name if so how? I have tried this code with no luck and no luck searching. This is a small example. I have queries with fifteen plus fields. This would also remove the need to modify this code if a field needs to be added to the table. And yes I have had to add fields to the tables.

Displaying A URL Stored In A Table As An Image On The Page?
In a table in my database I have a column for storing the URL of an image of a product. What PHP code would I use to display the image? PHP Code:

Combining Data From Two Fields, Displaying With Another Table
What I am trying to do is pull data from two tables and display it on one page. The code below doesn't display any errors, but all it prints is the results from the first query. Ideas? Thanks.

(I also need to somehow put a variable in for the warranty table data so it is tied to the product_status table data. You can see there is a WHERE in the first query of pid, but no WHERE in the second query. That is a seperate question, though. It would make this way too long, so I will post it separately). PHP Code:

Displaying SELECT Results In A Formatted Table
I was wondering how to show a table with a max limit of 20 results per page. I have various data being pulled and its putting it in a table, but its displayed all in one row. I want to format it so its a 4 column/5 row table. With that I then want the page to generate a numbered list at the bottom that calculates how many pages it takes to show 20 items on each. Code:

Displaying SQL Query Results In 3 Column Table
I would like to be able to display the results of an sql query in an html table, but the results need to be displayed in three columns, for example:

Column 1 Column 2 Column 3
Result 1 Result 2 Result 3
Result 4 Result 5 Result 6
Result 7 Result 8 Result 9

I've tried to find the answers on the internet but i can't find anything that suits my needs!

Select From Table Where Field = String
How to select all lines containg a string (located in $pastmove) in the
moves column.

I tried several ways, for example:

$requete="SELECT moves, opening_id FROM suitemove where moves like
'%".$pastmove."%'";

but did not succeed;

How To Get Oracle Table Field Definition
from SQL*Plus, i use:

DESCRIBE MyTable

and I get this result (example):

Syntax For MIN And MAX Values Of A Field In A Table
I wish to assign a variable name to the MIN and MAX values of a field
in a table. The type is int(7).

I am extracting the field with many others with the following code
from a php call.

$ml_collect='SELECT * FROM ml_lopp LEFT JOIN scfmforening ON
(scfmforening.scfmnum=ml_lopp.scfmnum) LEFT JOIN ml_newtidplats ON
(ml_newtidplats.loppnum=ml_lopp.loppnum) ORDER BY date1,
ml_lopp.loppnum'

$ml_upg=mysql_query($ml_collect);

mysql_close();

The field is contained within the table ml_lopp and it is called
loppnum

I have been trying combinations of this to extract the min and max of
the field from the $ml_upg variable which includes all of the data to
be processed.

$lownum=mysql_result($ml_upg,MIN('loppnum'));
$hghnum=mysql_result($ml_upg,MAX('loppnum'));;

Which does not work.

Pulling Data From The Last Field Of A Table
What is the command to view the last result in a table using a DB query?

Table Example
TABLE PEOPLE
>ID
>NAME
>POINTS

one thing, it cant be ORDER BY id DESC

If at all possible it has to be
SELECT * FROM people WHERE name=jon && id=**last id**

**last id** = Last id where the name jon was found.

How Do I Select The Last Field Of A Mysql Table ?
how do i select the last field of a mysql table ?

Iinsert The Auto_increment Field Into Another Table?
I have 2 tables ('customer' and 'regcustomer') and 1 form. The user fills in the form with all their details and the script should insert their credentials into the 'customer' table, which has an auto_increment field for the 'customerid'. I then want the script to take the 'username' and 'password' specified in the form, AND the 'customerid' generated in the 'customer' table and insert it into the 'regcustomer' table.

The credentials are inserting successfully into the 'customer' table and the 'customerid' is automatically being generated there. I just can't get the generated 'customerid' to insert into the 'regcustomer' table.

Here's the code that's generating the error:

$query1 = "SELECT last_insert_id(customerid) FROM customer";
$result1 = mysql_query($query1);
//echo $result1;
$row = mysql_fetch_array($result1);
$result2 = $row['customerid'];
$datapoint = mysql_result($result2, 0, customerid);

$result3 = "INSERT INTO regcustomer (username, password, $datapoint)
VALUES
('$_POST[username]','$_POST[password]','$_POST[customerid]')";

The error message i'm getting is:
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in....in line 25

Line 25 is the [$datapoint = mysql_result($result2, 0, customerid);] line. I think it doesn't like the '0' argument here as it's turned to red in my editor!

How Do You Insert A Value From Drop Down List To SQL Table?
I am a bit new to PHP and SQL so this may seem like a dumb question.

I have already created a drop down list as part of a form which is
automatically populated with values taken from a separate database. When a
user goes onto this page and either leaves the default value or selects a
value from the drop down list and presses the submit button, I would like
that selected value to be stored into a database which I have already
created in SQL.

Just to let you know that I can do the above using a text field but just
don't know how to do it with drop down list.

If your going to explain any coding then it may help if I give you the names
of certain items that are involved.

Database is called "Company"
Field within database is called "Name"

Displaying Multiple Queries To Same Table Excluding Different Rows!
i've got a table with 224 town listings and their ID's in it from 6 counties, and I want it to displayin a 6 columned table, each county getting their own column. Anyway, here's what I've got and what's happening: PHP Code:

How To Assign Data In A Table Field To A Variable
what exactly do i do to only retrieve information from a table and assign it to a variable? I don't want to manipulate the data in any way, just display it on the page.

Table Display Grouped By Specific Field
I operate a youth sports website and i display my current alignments in a long running list of teams (one field within my table) with association divisions (another field within table).

I would like to group them by divisions, like a two column table for better clarification.

Dynamic List Populated By MySQL Table
I am building my first php page and I've ran into problems trying to create a dynamic drop down list for an INSERT page. My page is based on this example from mysql.com.

I want to populate the list from a table in MySQL, but when I test the page the list only contains the first record. If anyone can help me out, or recommend an easy way to create dynamic menus/lists, I will be very grateful.

This code appears above the FORM ACTION:

$NearMajorCity = mysql_query("SELECT NearMajorCity_ID, NearMajorCity FROM NearMajorCity");

This code is within the FORM:

<SELECT NAME="NearMajorCity" SIZE=1>
<OPTION SELECTED VALUE="">Select One
<OPTION VALUE="">---------
<?php
while ($NearMajorCity = mysql_fetch_array($NearMajorCity)) {
$NearMajorCity_ID = $NearMajorCity["NearMajorCity_ID"];
$NearMajorCity = $NearMajorCity["NearMajorCity"];
echo("<OPTION VALUE='$NearMajorCity_ID'>$NearMajorCity
");
}
?>
</SELECT>

I want to be able to view the names of the Major Cities in the list, but I want the NearMajorCity_ID inserted into the table.

Displaying Table Field List

I got a function that displays a list of the fields in a certain mysql table. I got it off of this site. The problem is that it only displays the word Array and I'm not sure why. This is the code for the function: Code: