PHP :: Displaying A Table Using ID Number As Hyperlink

Table Output As Hyperlink ?
i am trying to create a table generated from a MySQL query with some of the output as hyperlinks. in this way i intend that the users of the site click to see the customers registered and then click on the "hyperlink" of their customer id, which will navigate them to details about that user on another php page. PHP Code:

Hyperlink In Table For Editing Information
What I have is a table with 3 columns, and in the first column, I have it linked to editpost.php? with the id behind it. I need to somehow get that id into the editpost page to bring up the info in 3 text boxes for the user to edit. Not sure as to how to do this. Code:

Retrieve Data From Mysql Table And Put A Hyperlink For Download
I have created a database and a table and have stored the information in mysql table.
Now my question is how do I retrieve that data from the my sql table and have a php page that when someone goes to say:download.php, he/she will be able to download the data from my mysql table? Also what if I have multiple tables in mysql that I want to be able to download from the php file?

Displaying A Message If A Number Goes Negative.
I'm trying to display a comment if my query comes up nagative, my result is displayed as a time (00:00:00 Format), I want it so that when my time goes negative (-01:00:00) it will display a comment, but when it is positive it will display the time. I already have the time displayed by using:

print $record['time_diff'];

But I'm not very clued up when it comes to if and else commands.

This is a section of my code that I can't get to work, Im sure you will see the problem straight away but I can't and have tried a few things.

$result = mysql_query($query = "SELECT timediff(time_allowed, time_used) as time_diff FROM scheduled_time WHERE scheduled_time.id = 1");
$record = mysql_fetch_assoc($result);
if ($record['time_diff']> 0){
print $record['time_diff'];
} else {
print "Time is negative";
}

Any help would be greatful.

Displaying Specific Number Of Queries.
If I wanted to only display the first 10 queries from MySQL on my webpage, how would I do that? Also, say if I wanted to only display queries 11 - 20, how would I do that?

Displaying X Number Of Results Per Page
What I need to do is this. I query a MySQL database and, for example, 400 results are returned. I can get it to display the number of results, but I would like to set a value to display, say 20, results per page and generate numbered links with and offset to browse through and next/previous buttons -not unlike this page. Can anyone point me in the direction of a good article or if you have it, post some code here?

Displaying The Number Of Featured Ads In Mysql
I was looking for away to have it display how many featured items are in a table then display that number in the admin next to the featured item check box that way the person know how many items are currently featured.

Displaying X Number Of MySQL Results Per Page
I'm writing a search on a MySQL DB, and everything so far has just gone swimmingly. I've got a "results per page" drop down box in my form, with a few different values.

At the moment, I'm just using:

while($myrow = mysql_fetch_array($result)

to output results to screen.

I'm not too sure how to go about it, but I did have two thoughts:

1) Suck the results into a multi-dimensional array, and pass the array to a display results script (not sure if you can pass arrays to other scripts???

2) Display x number of results, then have the "Next" (or 2, 3... ) links call the search again, but displaying results x+1 - x+x.

1 sounds like too much trouble, and 2 sounds inefficient. Not too sure how else to go about it. Any info / thoughts you guys have would be much appreciated.

On a side note, how do you look at a specific row in the result?

Displaying A Varying Number Of Images.. In Tables?!
I'm building a news system. I have a page to display all posts made to
category=$id, simple enough, now I wanna make an index page that looks
up all the categories from the news_topics table, displays their name,
a link to their page, and the image assigned to that category.

Here's the catch: I wanna put this in a table as the images are only a
few hundred pixels wide, so a flat list of each image would be boring
and inefficient. The thing is, we may add/remove news categories over
time, so how can I deal with this?

Would it really be easier to manually make this in HTML and change it
as/when we make modifications to the topics table?

Count Displaying Multiple 0 Instead Of Actural Number
I've been having this problem with the count, i've had it working for the other page, but that one uses a ID tag of 1 - 50. This one uses a jcode thats constantly changing. PHP Code:

Displaying # Of Records In A Table
Can anyone throw me a link to some prefab code, or a tutorial on how I can get a page to display the number of records that meet a certain criteria.

example:
I have a page that stores information on audio FX. I'd like to include a feature that would let the users know how many items are in a particular section.

Player (10)
Items (5)
Weapons (0)
etc.

All help appreciated,

Displaying A HTML Table With PHP
I'm new to PHP and I'm trying to get my head around databases at the moment. So far I have a page that kinda takes the mickey and takes a few details from you, it then creates a cookie that can be removed later. It also prompts you to add the data you gave to a database.

All this works perfectly, but when it comes to displaying the results of the database, all I can show is the first entry in the table. Can someone please tell me how I'm supposed to see all of them?

I've read other articles but they don't make much sense to me.

BTW, the database details are as follows:

Database name: visualanteorg
Table name: people
Fields: id, name, shoe_size, job

As you will see if you choose to look at the pages, getting the information out is not a problem, it's just formatting it how I want it, so each entry appears under the other in the table.

Displaying Table In Php Code
I have a PHP script that has a drop down to select a record, then it should display some text from a database and then display a table of information below it. But, the table is displaying at the top instead. Code:

Grabbing Data From A Table And Displaying It
I'm grabbing data from a table and displaying it but I want to to spand out into multiple pages...I got it all setup but when I click on the next link nothing happens... I got it setup at "3" right now just for testing..I have 5 entries in the database.. anyways could someone help me out? here is the code:

<?php

// Get connection info
include "../connect.php";
// End connection info
if(!$rowstart) $rowstart=0;
// Start database select
$result = mysql_query(
"SELECT * FROM links WHERE notactive='$notactive' order by date desc limit $rowstart,3"); //Select Database
$result2 = mysql_query("select * from links");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>"); exit(); }
// Display the text of each host
while ( $row = mysql_fetch_array($result) ) {
if ($notactive = 1) {
echo ("<table width=500 height=57 border=0 cellpadding=0 cellspacing=0>");
echo ("<tr>");
echo ("<td align=left valign=top><strong>" . $row["name"] . "</strong></td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top>" . $row["desc"] . "</td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top><a href=" . $row["url"] . ">". $row["url"] ."</a></td>"); }
echo ("</tr>");
echo ("<br><br>");
echo ("</table>");
}
if ($rowstart>$numrows)
{
echo "<A HREF=$php_self?rowstart=rowstart-3>";
echo "< Previous Page</A>";
}
echo "|";
$numrows=mysql_num_rows($result2);
if($rowstart+3<$numrows)
{
echo "<A HREF='$php_self?$rowstart=rowstart+3'>Next Page></A>";
}
?>

Displaying Information In A 1 Row/2 Column Table
I'm very new to php scripting and haven't quite figured out what I need to do here.

I need to display information in a 1 row/2 column table. I have the MySQL query working fine, but the scripting part in php is killing me!

In the first column a graphic about 70x70 will be shown (plus some additional padding). In the second column will be the description information. The second column will be around 400 pixels wide.

How do I set this up in php? It's easy enough in HTML, but I've about killed myself trying to figure out how to properly lay this out in php!

Displaying Array Results In Table
I'd like to display the results of an array in a table format with the Alias, Alias Destination & Username as column headings & the results underneath. PHP Code:

Displaying Records In A Split Table?
trying to split up results of a query into a split table. example: PHP Code:

Displaying Data In Html Table.
I wondered if anyone could offer some guidance, I trying to write a
php script to connect to a database, and display the records in a
table.

I found the code here in a php4 text, and when I run this directly
through the php intrupeter, the line Successfully connected is display
and 4 as the number of rows.

The database table we connect to, has three field username, firstname,
surname.

When I tried a while loop, to display the data in a table. No values
were displayed.

Could anyone possibly demonstrate how to display the username,
firstname, surname values in a basic table?

<?php
function db_connect(){
global $MYSQL_ERRNO, $MYSQL_ERROR;

$link_id = mysql_connect("localhost","user04", "password04");

if(!$link_id){
$MYSQL_ERROR = "Connection failed";
return 0;
}
else if(empty($dbname) && !mysql_select_db("database04")){
$MYSQL_ERROR = mysql_error();
return 0;
}
else return $link_id;
}

!$link_id = db_connect();
if(!$link_id) die(error_message('Error connecting'));

$result = mysql_query("SELECT * FROM users");
if(!$result) error_message('Error in selection');
else echo "Successfully connected. ";

$query_data = mysql_fetch_row($result);
$total_records = $query_data[0];

if(!$total_records) error_message('No records');
else echo "$total_records.";
?>

Displaying Table Field List
I got a function that displays a list of the fields in a certain mysql table. I got it off of this site. The problem is that it only displays the word Array and I'm not sure why. This is the code for the function: Code:

Displaying A URL Stored In A Table As An Image On The Page?
In a table in my database I have a column for storing the URL of an image of a product. What PHP code would I use to display the image? PHP Code:

Combining Data From Two Fields, Displaying With Another Table
What I am trying to do is pull data from two tables and display it on one page. The code below doesn't display any errors, but all it prints is the results from the first query. Ideas? Thanks.

(I also need to somehow put a variable in for the warranty table data so it is tied to the product_status table data. You can see there is a WHERE in the first query of pid, but no WHERE in the second query. That is a seperate question, though. It would make this way too long, so I will post it separately). PHP Code:

Displaying SELECT Results In A Formatted Table
I was wondering how to show a table with a max limit of 20 results per page. I have various data being pulled and its putting it in a table, but its displayed all in one row. I want to format it so its a 4 column/5 row table. With that I then want the page to generate a numbered list at the bottom that calculates how many pages it takes to show 20 items on each. Code:

Displaying SQL Query Results In 3 Column Table
I would like to be able to display the results of an sql query in an html table, but the results need to be displayed in three columns, for example:

Column 1 Column 2 Column 3
Result 1 Result 2 Result 3
Result 4 Result 5 Result 6
Result 7 Result 8 Result 9

I've tried to find the answers on the internet but i can't find anything that suits my needs!

Getting The Highest Number From A Table
I have a database table which has a column "number int(5)".

it will be inserted with different numbers -- my problem is, i wanna know how i could get the highest number value in that column ?

i was thinking about doing an ORDER BY number DESC clause mysql query and get the first row value which should be the highest. but is there any other way ?

Displaying Multiple Queries To Same Table Excluding Different Rows!
i've got a table with 224 town listings and their ID's in it from 6 counties, and I want it to displayin a 6 columned table, each county getting their own column. Anyway, here's what I've got and what's happening: PHP Code:

Counting The Number Of Records In Table
I want to count the number of records which apply to a repeating id field. (the user id remains the same, but their are several records which relate to the user. I want to know how many records in the table exist for a specified user id) Does anyone know a function for doing this?

Pulling A Cellphone Number From A Table
In my table, I have a 10 digit cellphone number stored. I want to display it on a page in this format 000-000-0000. I can not think of a way to get it displayed like this. Is there a simple way that I can not think of?

Temp Table - Random Number Generator
I am developing a data entry program where information is entered into a form, then submitted to a databse.

I need to be able to set up a temporary table which houses this data and then when all transactions are complete, the data in the temporary table is entered into my permanent table - then the temp table is deleted. (I won't get into the details as to why this has to be done this way)

Setting up the table is simple, however I ran into a bit of a wall when it comes to having several people entering data at the same time. If they were all to use the same temp table, then when one user finishes (and the table is auto-dropped) then other users data entry would be killed.

SOLUTION:
Use a random generator to name the temp tables, that way I can have several data entry users without running the risk of losing data when the temp tables are dropped.

PROBLEM
I don't know the best method to make a random number generator

Can anyone help, or suggest a simple, yet effective generator?

Insert New Row In Table After 5 Lines - Detect Whole Number?
I have a script that loops through an image directory to create a table of thumbnails. I want to start a new row after every fifth thumbnail. I assumed there was a function which identified whole numbers, but alas, there doesn't seem to be. How do I produce a short version of my long, working version below. PHP Code:

Getting The Number Of Items In MySQL Database Table.
Is there an easier way to get the number of items in a database table than
selecting all the records in it and then running mysql_num_rows on the
result?

Count,sort,diplay Number Of Records In MySQL Table
I am designing a search engine using PHP/MySQL and I am logging all search terms into a MySQL table. I was wondering how I count the number of occurences of a term in the table, and then sort and display the terms in descending order. For example, if the column in my table with search terms looked something like this:

clothes
casinos
clothes
homes
homes
clothes

How can I count and order the records so that I can display according to how many times they appear, like so:

1. clothes(3 entries)
2. home(2 entries)
3. casinos (1 entry)

Help With Displaying Selecting A Date Range And Displaying Results
I wish to create a simple form that allows the selection of a start date and a stop date with the ability to select what columns to be displayed in the result page.

Hyperlink
Im making a select statement and the outputs are in a table but i want the entry of a column to be hyperlink to take to another page Code:

Hyperlink Query
I have the following line that prints out a record with a link, when you
click the link you get more column
information in the record. I want to add another field (State) so that I can
narrow down the results. How can I pass both the hcounty as I'm doing now,
along with state? to the state7.php file?

print " <td><bgcolor=#000000><font color=#000000 font color=#000000
face=Tahoma size=2 ><A href='state7.php?searchid=$line[hcounty]'><img
src='buttondetail.gif' border=Ɔ'></img></td>
";

Replacing Www... With Hyperlink
i want to replace all entries of beginning with 'www.' and
ending with ' ' with a hyperlink to that substring such as:

www.google.com := <a href="www.google.com">www.google.com</>

can anyone tell me the easiest way to do this?

HyperLink Validatation
I am wondering what approach I could used to validate links. I am building a simple portal type index and I would like to be able to check for broken links weekly. The Database already has a field for link status. I would like to create a script that checks for broken links and changes the status so a human can follow up on it.

I am also wondering about how one would “limit” this program. I mean I don’t care if it takes 2 hours just as long as it does run rampant and cause issues with my host. Any thoughts…? I am not looking for a complete solution just a point in the right direction.

Hyperlink Per Mail
can anybody tell me how to sen a hyperlink using the php mail function.
If I send a <a ref ...> it just turns up in plain text. Whats the trick

URL Text To Hyperlink
here is what i have

$threadx = preg_replace("/((ht|f)tp://[^s&]+)/", "<a href="$1">$1[/url]", $threadx);
$threadx = preg_replace("/(S+@S+.w+)/", "<a href="mailto:$1">$1[/url]", $threadx);

can someone tell me how to make it better,
this one completly screws up existing hyperlinks and <img src=""> tags...
need to fix it somehow..

Hyperlink With Parameters
Is this how you print a hyperlink passing parameter action , id, qty to another php script? And printing HTML inside php? I giving three sample code in my program.

I use quotation around HTML TAG and code so can read by php print command.

1. Hyperlink with parameter to pass

print "<a href = "cart.php?action=Add&id=" . $column['SKU'] . "&qty=1">Add Item</a></font></td></tr>";

2. Printing HTML tag with PHP print command

print "<TR><TH>Title</TH><Price</TH><TH>Description</TH><TH>Add Item</TD></TR>";

3. Here I try to print a drop down list with Javascript onChange event. Notice that I use concatenation between HTML TAG and PHP code. I use to respesent quoatation mark.

// print the drop down that will update the qty instantly using Javascript onChange event
// the following syntax will look like this in regular HTML code
// <select name = "$column['SKU']" onChange = "upDateQty(this)"><option
Selected>i</option></select>

print "<tr width = 15% height = 25><td width = 15% height = 25><font face = verdana size = 1 color = black>";
print "<select name = "" . $column['SKU'] . ""onChange = "updateQty(this)"";

for ($i = 0; $i <= 20; $i++)
{
print "<option";
if ($rows['QTY'] == $i)
{
print "SELECTED";
}
print ">" . $i . "</option>";
}
print "</select></font></td>";

Using A Hyperlink To Retrieve Data? Is It Possible Without?
I was wondering if it is possible to get data from a database using a hyperlink instead of a form? My situation is I have a page with a list of products (data from a mysql table) and I want to keep the info on the page small so I have limited the description and left out some info. what I want is a link at the bottom of each product that says "more details" and when clicked it creates a new page on the fly to show more info. is it possible to do this without javascript? If so How.

Hyperlink And Passing Of Variables.
I know three ways to pass variables form one page to another. The first
one is to declare and set session variable. In this case if one goes to
another page (by clicking on hyperlink or pressing a button) value of a
session variable will be automatically seen on the new page. The second
way is to set hidden variables in the form and go to new page by
execution of this form (press a button or enter), and the last way,
which I know, is in the declaration of hyperlink after name of a new
page put after "?" names and values of variables. Sometimes I need
to use the third way. However I do not like that after new page is
loaded in the address line of browser one can see all variables (names
and values). Can one avoid this problem?

Hyperlink And Posting To New Page!
I have a page where I have done a successful query and get search results displayed. Now I would like a link activated so that they can click on the name and go to new page with further details about that company like address hours etc.

Hyperlink - JS Function & PHP Variable
if its possible to call a JavaScript function and pass on a PHP variable in 1 hyperlink?
I need to pass on variable: $lang=english And call JavaScript Function: javascript:loadScript1()

Executing Code Within A Hyperlink
I am writing a photo gallery and suppose 8 photos are displayed. When the
user clicks on a button under the picture, I want it to add that picture
name to a "favorites" list within the session data, but NOT leave the page
the user is on. How could I do this?

Need A Script To Tell Me Where A Hyperlink Originated
Not sure if this is a php or an html question but I'll post it anyway.

I have multiple thumbnail images on my catalogue page catalogue.php and they are
all hyperlinked to a single page called desc.php that will give an enhanced
description of the product selected.

I want the desc.php page to print the contents of a text file named ?.txt based
on which image was clicked on in my catalogue page.

example: if I click on 1.jpg in my catalogue then I want the file 1.txt to be
selected and printed on my description page.

I know how to print the contents of a textfile and I know how to disect the
strings of the filenames so that I can associate 1.txt with 1.jpg.

What I dont know is how to retrieve the name of the image file that was clicked
on the catalogue page within my script for the desc.php page

If I didn't use a hyperlink image and used a form submit button instead on my
catalogue page then of course I could use something like:

$filename = $_POST['filename']

Hope you understood all of that.