Displaying Database Records Over Multiple Columns
I am currently using the following to generate a table with a single column with ten entries PHP Code:
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Displaying Database Information In Columns
I have a database with products in and I want iT to automatically show every product on the page. Now I am able to do this easy enough but what I am struggling to do is that I want the products to be displayed in 3 columns. I can get them to display one under the other easy enough but I want them to be in rows with 3 columns instead.
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Displaying Data From Multiple Tables, Allowing User To Narrow Down By Certain Columns
I've got a three table database, with tables member, race, and results. The site is just for a running club to record their race results and keep details on each member. I want to have a page where users can view race results, i.e. display the members name (stored in member) the race they took part in, the data of the race (stored in race), and the time they achieved (stored in results). I understand i will need a join query to do this, this isn't the part thats bothering me.. Code:
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Delete Multiple Records In The Same Database Querie?
I have some code that deletes records from the database, in a loop. However its prety inificient as it makes a seperate database call in every loop whcih is slow. PHP Code: for ($i=0; $i<count($idarray); $i++) db_query("delete from clicks where id='$idarray[$i]'"); Is their a more efficient way of doing that? It is posible to delete multiple records in the same database querie?
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Display Records From A MYSQL Database On Multiple Pages.
I am trying to display records from a MYSQL database on multiple pages. I get the following error when I attempt to display the results mysql_fetch_array(): supplied argument is not a valid MYSQL result in c:intentpubwwwrootprogeneefsires1.php on line 238 The code is shown below. I am including a file called class.pager.php for page numbers (author: Tsigo) and this part works fine. /* Now we use the LIMIT clause to grab a range of rows */ $result = mysql_query("SELECT sireid, sirename, sirethumbpic, comment_1,comment_2,comment_3 FROM beef".$start.", ".$limit);
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Displaying Multiple Items From Database
what i have is a page that has four sections. what i want to have is when the page opens, in that page i want the lastest two items for each section from a database to be displayed. the items to be displayed are an image, a title and a description. but i also want the description to be shortend to say about 25-30 words or about 100 chars, if thats easier? so in the end i have 4 sections, each showing the lastest two items for each section. would the best way to do this be to have a seperate table in the database for each of the sections? or would i be able to do it from one table? would i have to creat a query for each of the sections? e.g: SELECT * FROM table WHERE section=section
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Displaying Priorty Records And Normal Records In The One Dataset.
I have a page which displays the records from the database and uses paging to display the records in groupes of 10 per page. I now want to be able to show results depending on the database field (display) in the database (can be set to either "full" or "limited"). If the record and the field display is equal to "full" i want to then display this record at the top of the record set and display all the fields. If the record is equal to "limited" i want to display different results and they must show after all the records which are equal to "full". I can't output two different recordsets as i use paging and only want to show 10 records per page. Code:
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Get Records Betwen Two Date Columns.
Maybe is silly but I know I can find a solution here. I have this table id | datein | dateout 1 | 2007-05-11 | 2007-10-11 2 | 2007-06-11 | 2007-10-11 What I'm trying to do is get all the records between date I passed via form. I tried "Select * from dates WHERE datein >= '$datein' AND dateout <= '$dateout'"; I stored dates as DATE on the DB. I tried to use BETWEEN, but I don't know if I can use on two different columns.
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Break MySQL Records Into CSS Columns Automatically
I'm making a page of links, each assigned a category. There are two tables - "favourites_links" and "favourites_categories". This is how the links currently appear: Category 1 Name Link 1 Link 2 Link 3 Category 2 Name Link 1 Link 2 Link 3 What I want to do is break my page into columns. Basically, set a number of columns (e.g. 3), count the total records, and work out how many records to show per column. Each column should be enclosed in a <div class="column"> wrapper, which floats to the left. Code:
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what is the most efficient way to display column names from a database that only have the value '1' in its fields?? I cant seem to work it out, could someone give me a code example??
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Displaying Columns In Tables
I am currently displaying the contents of a database directly onto a webpage, is there a way i can dispaly it a bit neater, like use a few tables to align the data, what is the best method to do this, currently im just this code:
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Create Dynamic Table With 3 Columns And Unknown Number Of Records?
I'm trying to create a table with only 3 columns, but the problem is I don't know how many records will populate the table so need it to automatically create <tr> and </tr> tags every 3 records. How best can I do this? At present the code below just lists every single record in one continuous row - but as I said, I want to only display 3 records per row. Code:
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Displaying Rows Of Data As Columns?
Does anyone know of an efficient way to retreive data from a mysql db and display the record rows as collumns? I have been doing this: <display headers> <while ($row = mysql_fetch_array($result)) { > <display row 1 of result> <display row 2... } > <end table> but I want to do this instead: <col 1 header > <row 1 col 1> <row 2 col1> <row3 col1> <col 2 header> <row 1 col 2> <row 2 col2> <row3 col2> <col 3 header> <row 1 col 3> <row 2 col3> <row3 col3>
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DELETE RECORDS - Database Adding New Records
iv got the database adding new records, and now I want it to display all of the records that are there buy name and id number, then i want u to be able to type in the id number of the customer u wish to delete and it shoudl delete it, sounds good buts its not actually deleting the record. it says it does, but its not doing it. Code:
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Updating Multiple Columns.
I have this code: PHP Code: @mysql_select_db(godofgod_p_bb1) or die( "There has been an error in your request. Please try again! Error: Unable to select database."); $query = "UPDATE articles SET Email address = $email, title = $title, body = $article WHERE id = $id"; $result = mysql_query($query); mysql_close(); if($result){ echo "Modified</font>"; }else{ echo"Error: Unable to modify database</font>"; It returns with "Error: Unable to modify database" but why doesn't it execute the query correctly?
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Increment Multiple Columns
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Grouping Multiple Columns
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Adding Multiple Columns
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I'm building a database via mysql/php which brings back records of events. My problem is that I only want to show the Venue for the event once and then list the events for that venue. ie Code:
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I have a database which contains the articles on the front page in it. Well, to save clogging up the front page, I would like to display only the latest 5 articles in the table. The articles have an id field which could be ordered descending, but from then on, I have no idea what to do.
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Displaying Last Three Records
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I'm currently building a database of local businesses, I'm quite new to using php and mysql. While I'm mostly managing to stumble my through it, a couple of things are confusing me. This is one of the things. If anyone can help, that would be really great. Ok, so I've build a search page, and a results page and it works great but there is one problem. Currently it will only search through the 'name' column, but I'd also like it to search through the 'type' column at the same time. This is the code I'm using to fetch the results $colname_Businesses = "-1"; if (isset($_POST['search_par'])) { $colname_Businesses = $_POST['search_par']; } mysql_select_db($database_HBBA_DATABASE, $HBBA_DATABASE); $query_Businesses = sprintf("SELECT * FROM Businesses WHERE name LIKE %s", GetSQLValueString("%" . $colname_Businesses . "%", "text")); $query_limit_Businesses = sprintf("%s LIMIT %d, %d", $query_Businesses, $startRow_Businesses, $maxRows_Businesses); $Businesses = mysql_query($query_limit_Businesses, $HBBA_DATABASE) or die(mysql_error()); $row_Businesses = mysql_fetch_assoc($Businesses); I'm not sure what to add in to make it also search through the 'type' column or where to put that. Can anyone point me in the right direction?
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Updating One Columns With Multiple Fields
I want to update column, teamid. I am trying to update all 12 fields for teamid at same time using Form Processor (HTML). When I send it to next page to update the database, I am getting one result for all fields so I am not telling it how to update properly. The row# for each column is fixed and will not increase above 12 rows and the goal is to update team name based on seed #1-12. There is seed column next to teamid column, which is fixed and will be important for other purpose. Code:
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Pagination - Multiple Rows And Columns
i would like to paginate a set of results. i would like 12 results per page, ideally 4 columns over 3 rows. i can do the pagination and rows part no problem but am struggling with writing the columns. could any point me to a good tutorial or provide some sample code?
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MySql Querying Multiple Columns.
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Can anyone throw me a link to some prefab code, or a tutorial on how I can get a page to display the number of records that meet a certain criteria. example: I have a page that stores information on audio FX. I'd like to include a feature that would let the users know how many items are in a particular section. Player (10) Items (5) Weapons (0) etc. All help appreciated,
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Displaying Records, But Not Identical Ones.
I have a table with several rows. One column is "State", where, of course, a state is listed. I'd like to query the database and list all states in the rows, but I don't want multiple instances of the same state? How can I prevent it from showing:
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I'm trying to stick some PHP code onto next and previous buttons to display the next / previous 10 records, then using; $result = mysql_query ("SELECT * FROM property_1 WHERE area='$whatarea' LIMIT $limitit,10"); but if the above code and the buttons themselves are on the same page how do you stick PHP code on the buttons to do the limitit+10 and limitit-10 and also to call the page?
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Displaying Records In Table
I have a table that I want to display some records from my database. I have a specific spec I'd like the table to conform to, 3 cells wide. I can get the data into a cell. But my problem is, I'd like the table to have the 3 cells fill and then have the additional data create a new rows and continue on infinately.
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I have currently devised a way to display up to 3,000 records via PHP/HTML by using pagination techniques that stuff an entire DB query resultset into a $_SESSION object to use within pagination. Here's my question: How good will this work when we start dealing with more than 3,000 records? Like 5,000? 10,000? 10,000+? The $_SESSION object will obviously become too large to be manageable. What do you guys advise I do to manage this in the foreseeable future? No rush on this of course for now.
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Displaying Mysql Records:
I wondered if anyone could offer some guidance, I trying to write a php script to connect to a database, and display the records in a table. I found the code here in a php4 text, and when I run this directly through the php intrupeter, the line Successfully connected is display and 4 as the number of rows. The database table we connect to, has three field username, firstname, surname. When I tried a while loop, to display the data in a table. No values were displayed. Could anyone possibly demonstrate how to display the username, firstname, surname values in a basic table? <?php function db_connect(){ global $MYSQL_ERRNO, $MYSQL_ERROR; $link_id = mysql_connect("localhost","user04", "password04"); if(!$link_id){ $MYSQL_ERROR = "Connection failed"; ..................
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Displaying Records That Are Less Than 30 Days Old.
I have records that are dated using date('y,m,d') when they are created. Would like to only display records that are less than 30 days old. So, IF record is older than 30 days - do not display. Here is my code: $arr = $db->getArray("SELECT * FROM table WHERE id = '$id' ORDER BY date ASC");
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Sorting DB Entries Over Multiple Pages (and Columns)
I am making an image gallery, and have previously had problems sorting the database entries over several columns, that is now sorted. However, I don't know how to make the entries on page 2 to begin from image 10, page 3 to begin from image 19 etc (given that I am using a 3x3 table so 9 images per page. Here is the code that prints the URLs of the images (i am working with text, rather than IMG tags until it works): PHP Code:
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Displaying Records In A Cyclic Fashion
I use the following code in-order to display records based on the week day.My intention behing writing this one was to display 90 records in a cyclic fashion.(i.e, first 90 on monday, next 90 on tue and so on...)
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No Errors And Not Updating The Database Columns.
I have a TIMESTAMP field in MySQL, and what i'm trying to do once i've compared new data to that timestamp, I want it updated with a new timestamp. Here is the code i've used. $email_number = $row['email_id']; $new_date = date("Y m d H i s"); $update_last_email = "UPDATE mailing_list SET last_email = '" .$new_date. "' WHERE email_id ='" .$email_number. "'"; No errors, however this is not updating the database columns. Any ideas where I've gone wrong. Let me know if you need more information.
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Using The Unix Time Stamp In Two Columns In The Database
I am creating webpages that use PHP to talk to a MySQL database. I am using the unix time stamp in two columns in the database. One of those columns i am going to use PHP to return the original value to everytime. But, when retrieving a time stamp out of the MySQL database, I can straight print it out and the time stamp is correct. But when i try to use the date() commmand of PHP, and throw in the Unix timestamp as the optional 2nd parameter, i get say 2038 as the year when i should be getting 2001...What am i missing?...Since the timestamp runs into its "Y2K" type bugg in 2037 am i getting something related too this? Sine 01 + 2037 equals 2038?
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Multiple Records To One
I have a database which comprises of a routes system.. some basic fields like ID | Routenum | Departure | Destinations | Deptime | Arrtime | Comments However, I have multiple routes where the Departure and Destination are the same, only the times are different. How could I make it so that only one appears on the routes list, instead of having about 5 similar entries?
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