Displaying Date From A Database
All I need to do is change the date so it reads, for example, May 1999 when it's displayed on the page. Code:
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Displaying DATE From Database?
I have a database field called `DATE` which has data type date. The purpose of `DATE` as you guessed is to store a date. 2007-11-31 I want to write a script to update a news article posting date. The only way to do this is to break DATE into three separate sections, $year, $month and $day How do I go about doing this? Please keep in mind, the date is already stored in the database, it does not need to be today's date. It can be any date! Lets work with 2007-11-31 as an example.
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Reading And Displaying A Date From A MySql Database
I've just started using php, and although I am very impressed by it, there are some things with which I am confounded! What I'm trying to do is read in a Date from a mySql database and then display it on screen (the Date is in the usual yyyy-mm-dd format). If I use SQL on phpadmin SELECT Date FROM details WHERE details.Name = "Paul Lee" LIMIT 0 , 30 The result comes up 2005-01-01, so this seems to work. But if I use the following: $db = mysqli_connect("localhost","root",""); @mysqli_select_db($db, "personnel") or die ( "Unable to select database" ); $query = 'SELECT Date FROM details WHERE details.Name = "Paul Lee" LIMIT 0, 30' $result=mysqli_query($db, $query); echo "<br>"; echo $result; mysqli_close($db); I get "Object id #2" displayed on screen. I have tried to use the explode function to separate the months, year and day using the "-" as a delimeter, but this doesn't work, and I can't seem to get the other php date/time functions to work either.
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i'm working on K Yank's book and, at some point, i've an insert like this: $sql = "INSERT INTO Jokes SET ... JokeDate = CURDATE()"; When i dysplay this on my webpage, the date format is YYYY,MM,DD and in my country (Portugal), the format is day, month, year How can i achieve it?
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As a final touch to my current project I am trying to display a "Last Updated: " field on the user profile pages of the website. The SQL database is updating the field last_updated automatically any time a record is altered, and this is working fine... Structure details from phpMyAdmin (in table 'users'): last_updated timestamp ON UPDATE CURRENT_TIMESTAMP No 0000-00-00 00:00:00 However when I try to output this date I get the result: Profile Updated: January 1, 1970 The code I am using is as follows... Code:
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My current code: foreach ($page['events'] as $z) { echo '<b>', $z['date'], '</b></p>'; } Which is pulling "date" from a DATE field in the database. Would like it to display as 3-22-2007 ... instead of 2007-3-22 - I know theres a quick answer out there but cant find it.
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Date Is Not Being Pulled From MYSQL Database, Instead Current Date Is Displayed!
I am having trouble pulling a date from a database using PHP at the <a href="http://www.mytuneslive.com/ameshkin69/"> following page.</a> Here is the code. As you can see, it is just making the date the current time. The values in the database are UNIX timestamp, and the DATE() function is used to convert from UNIX to readable date. Can <td width="55%" align="left" valign="top"><?php $row_comment['timestamp'] = date("n d Y g:i A");.....
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I would like to display a user specified date range e.g Monday to Monday next week or maybe Monday next month. When I have the basic function worked out I would like to get Data from a Mysql Database. here is what I have thought about. Code:
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I have successfully used strtotime to format the date on a webpage that is pulled form a MySQL database in the form yyyy-mm-dd. However, in another part of the webpage, I have to insert another date that may contain a NULL entry in the database. If I use strtotime to format this then it enters the current date, whereas I want it left blank.
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I'd quite like to have a list of dates/times showin in different timezones i.e. China: 09:56:01PM, saturday 5 Feburary India: 01:56:01AM, saturday 5 Feburary Is there anyway I an do this on the fly using PHP without having to change any sort of timezone/server config variables?
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How do I set the time display to echo the time, in the timezone the user is in and not the server time. For somereason im in eastern timezone and the host server i9s in central and the time displayed on my laptop is in central.
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Having set up some info in my database. I wanted to display the date the information was posted. Entering the data into the database the date displays in the format yyyy-mm--dd. How does one go about changing this to show dd-mm-yyyy or even something like 9-sept-05?
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i have a db that stores a date in a table with a specific column. db=test table=test_date_compare column name=date_inserted ok i hv a php form that allows user to input date and it enters in the above column (date) as in format eg: 21/03/2007 now i wat i would like to do is i would like to compare date of today and the date in the database if it is lesser then todays date it deletes that row of data. deleting the row of data i know how but the problem comes wen coparing the date i dunno how to ...
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I am looking for a way to convert a date that is stored in a MySQL database like this after useing the date() function in PHP: 2006-08-16 21:03:54 and convert it into a date this: 16 August 2006 @ 11:03:54pm Does anyone have some insight as to how I would go about doing that?
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I'd like to display a little "new" icon next to all products in a directory which are, funnily enough, new! I've got a date (timestamp) for each product which is inserted on adding a new product and updating a product. I'd like to do a conditional region using the timestamo but I'm not sure what to use - I could do === [current date] but that would only show the icon for that day and I'd like it to be there for about a week or so.
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I've only used php to display the current date but I can see that I'm not in the same timezone as the server is. Its 5 hours ahead and I can't get it to show the date as Eastern Time. I'm developing a site for a non-profit slopitch league so they can submit score sheets and track their season. 2 teams must submit a score sheet for their team within 72 hours of having played the game. Then they are not allowed to enter the score sheet without the administrator's permission. Code:
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I'm trying to display products that are pulled form a database in a certain way using only DIV tags I would like the products to display across the page in rows of 4, however when i use div tags it is just putting one on each row.. whats the best way to display in a row of 4? here is an example script of what im using to experiment with: Code:
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Displaying Database...
I work for an environmental company that is making me develope an internal site that provides various functions... Since I am not really a coder I find it hard to perform such tasks (I am primarily a graphic artist).... One of the things I need to do... is have a section that employees can go to to search our projects that we have performed.... the database will have various table headers that will include items like: Code:
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I have a small script with PHP that queries a MySQL database to pull out one row, where I want to be able to access each of the columns separately. I have tried several different variations and am able to get the entire row to print, but when I attempt to access the individual columns I get an error. Here is what I have so far: if (isset($_POST['memberNo'])): $link = mysql_connect('...','...','...'); mysql_select_db("..."); //Perform a test query $query = "SELECT * FROM users WHERE 'id' = " . $_POST['memberNo']; $result = mysql_query($query) or die(mysql_error()); $line = mysql_fetch_assoc($result); print $line; //Close connection mysql_close($link); The point of this code is to retrieve the user information to validate the login information sent in the previous form. I do not get an error with this code, but it also does not print anything. I know there is an entry in the database that matches data sent in the $_POST['memberNo'] variable, it is the only entry in the database. Changing the 'print $line;' to 'print $line["id"];' does not display anyting either.
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I want to display everyone in the database, but only if the 'level' field is larger than 0. Well, this works fine for most of the database... but if the last entry in the database is 0, then it prints it anyways. Is there anyway around this? I tried adding an if statement before the last bit where I echo out the table rows, but it was killing the entire table, or still showing the same results. Code:
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