PHP :: Displaying # Of Records In A Table

Displaying Priorty Records And Normal Records In The One Dataset.
I have a page which displays the records from the database and uses paging to display the records in groupes of 10 per page.

I now want to be able to show results depending on the database field (display) in the database (can be set to either "full" or "limited"). If the record and the field display is equal to "full" i want to then display this record at the top of the record set and display all the fields.

If the record is equal to "limited" i want to display different results and they must show after all the records which are equal to "full". I can't output two different recordsets as i use paging and only want to show 10 records per page. Code:

Displaying Some Records Once Only
I'm building a database via mysql/php which brings back records of events. My problem is that I only want to show the Venue for the event once and then list the events for that venue. ie Code:

Displaying Unique Records
I've got a database table named 'sales' where each sale has these fields:

Displaying Records, But Not Identical Ones.
I have a table with several rows. One column is "State", where, of course, a state is listed. I'd like to query the database and list all states in the rows, but I don't want multiple instances of the same state? How can I prevent it from showing:

Displaying The Next/previous Records
I'm trying to stick some PHP code onto next and previous buttons to display the next / previous 10 records, then using;

$result = mysql_query ("SELECT * FROM property_1 WHERE area='$whatarea' LIMIT $limitit,10");

but if the above code and the buttons themselves are on the same page how do you stick PHP code on the buttons to do the limitit+10 and limitit-10 and also to call the page?

Displaying Records After 2 Days
I trying to display only records that are 2 days old so the owner of the site can preview new records before they are available to others, this is what I've got so far...
$sqlquery = "SELECT headline, news, date_format(date,'%M %D %Y') as time FROM $table WHERE date < NOW() ORDER BY date DESC";

is there a way to extend it by 1 or 2 days, i've tried the TO_DAY function but couldn't get it to work either.

Displaying Records In A Cyclic Fashion
I use the following code in-order to display records based on the week day.My intention behing writing this one was to display 90 records in a cyclic fashion.(i.e, first 90 on monday, next 90 on tue and so on...)

Displaying Records From Text File
I have the following Code which reads in information from a text file: PHP Code:

Displaying Database Records Over Multiple Columns
I am currently using the following to generate a table with a single column with ten entries PHP Code:

Counting Records In A Table
Ok, I am trying to count the number of records in one of my tables. Seems simple. BUT! its not working. It returns a 2 no matter how many records are in there.

Heres the code.

<?php
$sql = "SELECT count(*) from cam";
$result = mysql_query($sql);
?>

I would think this would work.
I have also tried mysql_num_rows, and max(), and sum()...
a little help would be appreciated, and why is it returning a 2?

AJAX To Display New Records In A Table
Instead of refreshing the entire page to show the new fields in a
table, I was wondering if it would be possible to use AJAX to display
the new records in a table.

For example:

Messages are entered into the DB. I use PHP to create a table that
displays the messages.

Instead of refreshing the entire page to show the table with new
messages, how can I use AJAX to show the new messages in the table
without refreshing the entire page?

Counting The Number Of Records In Table
I want to count the number of records which apply to a repeating id field. (the user id remains the same, but their are several records which relate to the user. I want to know how many records in the table exist for a specified user id) Does anyone know a function for doing this?

Linking Multiple Records From Another Table
I'm not sure I'm even thinking about this the right way, but here goes:

I have a table of users. Each one of these users may be associated
with none, one, or many records in another table I call a todo table.
table user = 'id', 'name', 'bla bla bla','todo_list'
table todo = 'id','title','other info'

Suppose user 'id=1253' has on his todo list items 756,241, and 672. I
create a string 756,241,672 and store that string in the user's
todo_list field. Then when I want to display the todo items I get the
string with a query, bust it up into an array, iterate the array and
query the todo table.

I have a gut feeling I'm making it way more complicated than need be.
But I can't think of any other way to do it

Table Join Count Records.
got my counting records script just the way I want it, now I've read all the posts on Joins, and read the manual and mysql.com.... but can't seem to get the right number to come out.

I have two tables: table1 & table 2

table one has a field called ID and field two has a field called relID (this is the link between them) I want to count all of the records in table two where the relID is equal to the table 1 ID field. I thought this would do it, but the number it returns is wrong:
PHP Code:

Copy Select Records To New Table
In the table Step I have multiple records for each given id. I want to save the current list of records for an id to a new Step_Old table so I can look back at what I had at a given point in time, since the records for an id in the Step table will change over time.

Now the question... does anyone have a slick way to do this, or do I need to Select all the records I want to save and then save them one by one with a while loop into the Step_Old table?

Checking $_POST Against Records In Table
I have a table containg name, description, url which contains many records When I submit a new form, I want it to check the url fields in the table and check it against what I have posted. Therefore something like

$check_table = function here to get all urls

if($_POST['url'] == $check_table) {
return false;
} else {
return true}

However, how do I get all the urls and get it to check each one?

Having Trouble Looping Through Records In A MySQL Table
I'm having some trouble looping through the records of a MySQL table using PEAR DB. Here is my code:

$navigationSql = "SELECT * FROM nav";
$navigation =& $db->query($navigationSql);
while ($navigation->fetchInto($nav)){
define("NAVIGATION", "<a href="$nav[2]" target="$nav[3]" title="$nav[1]">$nav[1]</a><br />"); }

The when I enter:
print NAVIGATION;

into any of my PHP scripts it should loop through the stuff in table named nav, but it is only displaying the first record and so far everything I've tried does not seem to make it loop through all of the records in the table and I can't figure out why not.

How To Access And Modify And Add Records In MySQL Table From A Windows Client?
The MySQL table is located in a Linux Server OS, so I need the
information from that table for updating Paradox tables in Windows OS.
If a PHP program in the Linux Server can save a file with the
information I need, can I make a PHP program in Windows OS to get the
saved file or even better, to access the table in the Linus Server OS?...

Count,sort,diplay Number Of Records In MySQL Table
I am designing a search engine using PHP/MySQL and I am logging all search terms into a MySQL table. I was wondering how I count the number of occurences of a term in the table, and then sort and display the terms in descending order. For example, if the column in my table with search terms looked something like this:

clothes
casinos
clothes
homes
homes
clothes

How can I count and order the records so that I can display according to how many times they appear, like so:

1. clothes(3 entries)
2. home(2 entries)
3. casinos (1 entry)

Automatic Delete From MySQL Database Table Expired Records?
I have a question . . .

how can i delete from MySQL database table automatic expired records ?
?

One think is to make a service that deleting the expired records . . .

Any other method ?

Displaying A HTML Table With PHP
I'm new to PHP and I'm trying to get my head around databases at the moment. So far I have a page that kinda takes the mickey and takes a few details from you, it then creates a cookie that can be removed later. It also prompts you to add the data you gave to a database.

All this works perfectly, but when it comes to displaying the results of the database, all I can show is the first entry in the table. Can someone please tell me how I'm supposed to see all of them?

I've read other articles but they don't make much sense to me.

BTW, the database details are as follows:

Database name: visualanteorg
Table name: people
Fields: id, name, shoe_size, job

As you will see if you choose to look at the pages, getting the information out is not a problem, it's just formatting it how I want it, so each entry appears under the other in the table.

Displaying Table In Php Code
I have a PHP script that has a drop down to select a record, then it should display some text from a database and then display a table of information below it. But, the table is displaying at the top instead. Code:

Grabbing Data From A Table And Displaying It
I'm grabbing data from a table and displaying it but I want to to spand out into multiple pages...I got it all setup but when I click on the next link nothing happens... I got it setup at "3" right now just for testing..I have 5 entries in the database.. anyways could someone help me out? here is the code:

<?php

// Get connection info
include "../connect.php";
// End connection info
if(!$rowstart) $rowstart=0;
// Start database select
$result = mysql_query(
"SELECT * FROM links WHERE notactive='$notactive' order by date desc limit $rowstart,3"); //Select Database
$result2 = mysql_query("select * from links");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>"); exit(); }
// Display the text of each host
while ( $row = mysql_fetch_array($result) ) {
if ($notactive = 1) {
echo ("<table width=500 height=57 border=0 cellpadding=0 cellspacing=0>");
echo ("<tr>");
echo ("<td align=left valign=top><strong>" . $row["name"] . "</strong></td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top>" . $row["desc"] . "</td>");
echo ("</tr>");
echo ("<tr>");
echo ("<td align=left valign=top><a href=" . $row["url"] . ">". $row["url"] ."</a></td>"); }
echo ("</tr>");
echo ("<br><br>");
echo ("</table>");
}
if ($rowstart>$numrows)
{
echo "<A HREF=$php_self?rowstart=rowstart-3>";
echo "< Previous Page</A>";
}
echo "|";
$numrows=mysql_num_rows($result2);
if($rowstart+3<$numrows)
{
echo "<A HREF='$php_self?$rowstart=rowstart+3'>Next Page></A>";
}
?>

Displaying Information In A 1 Row/2 Column Table
I'm very new to php scripting and haven't quite figured out what I need to do here.

I need to display information in a 1 row/2 column table. I have the MySQL query working fine, but the scripting part in php is killing me!

In the first column a graphic about 70x70 will be shown (plus some additional padding). In the second column will be the description information. The second column will be around 400 pixels wide.

How do I set this up in php? It's easy enough in HTML, but I've about killed myself trying to figure out how to properly lay this out in php!

Displaying Array Results In Table
I'd like to display the results of an array in a table format with the Alias, Alias Destination & Username as column headings & the results underneath. PHP Code:

Displaying Data In Html Table.
I wondered if anyone could offer some guidance, I trying to write a
php script to connect to a database, and display the records in a
table.

I found the code here in a php4 text, and when I run this directly
through the php intrupeter, the line Successfully connected is display
and 4 as the number of rows.

The database table we connect to, has three field username, firstname,
surname.

When I tried a while loop, to display the data in a table. No values
were displayed.

Could anyone possibly demonstrate how to display the username,
firstname, surname values in a basic table?

<?php
function db_connect(){
global $MYSQL_ERRNO, $MYSQL_ERROR;

$link_id = mysql_connect("localhost","user04", "password04");

if(!$link_id){
$MYSQL_ERROR = "Connection failed";
return 0;
}
else if(empty($dbname) && !mysql_select_db("database04")){
$MYSQL_ERROR = mysql_error();
return 0;
}
else return $link_id;
}

!$link_id = db_connect();
if(!$link_id) die(error_message('Error connecting'));

$result = mysql_query("SELECT * FROM users");
if(!$result) error_message('Error in selection');
else echo "Successfully connected. ";

$query_data = mysql_fetch_row($result);
$total_records = $query_data[0];

if(!$total_records) error_message('No records');
else echo "$total_records.";
?>

Displaying Table Field List
I got a function that displays a list of the fields in a certain mysql table. I got it off of this site. The problem is that it only displays the word Array and I'm not sure why. This is the code for the function: Code:

Displaying A Table Using ID Number As Hyperlink
i am able to insert and display data to the end user, but i am trying to let the end user edit a row. I am unsure how this is usually done, but i am have the following code to display by data

echo "<table border='1'><thead><tr>";
for($i = 0;$i < mysql_num_fields($sql_result);$i++)
{
echo "<th>".mysql_field_name($sql_result,$i).
"</th>";
}
echo "</tr></thead>
<tbody>";
for ($i=0;$i < mysql_num_rows($sql_result);$i++)
{
echo "<tr>";
$row = mysql_fetch_row($sql_result);
foreach($row as $value)
{
echo "<td>".$value."</td>";
}
echo "</tr>";
}
echo "</tbody></table>";

The user have a jump menu (combo box) to pick the table they need to show information on, so the columns displayed are going to vary, but i have a column called ID which is the same in each tables which is the index (auto increment) field.

I was thinking about using this number comnbined with a hyperlink, so the user can click it to take them to a page to edit that row.... But i have no idea how to do this, or if there is an easier way which i just do not know; or how do most people achieve what i require...

Displaying A URL Stored In A Table As An Image On The Page?
In a table in my database I have a column for storing the URL of an image of a product. What PHP code would I use to display the image? PHP Code:

Combining Data From Two Fields, Displaying With Another Table
What I am trying to do is pull data from two tables and display it on one page. The code below doesn't display any errors, but all it prints is the results from the first query. Ideas? Thanks.

(I also need to somehow put a variable in for the warranty table data so it is tied to the product_status table data. You can see there is a WHERE in the first query of pid, but no WHERE in the second query. That is a seperate question, though. It would make this way too long, so I will post it separately). PHP Code:

Displaying SELECT Results In A Formatted Table
I was wondering how to show a table with a max limit of 20 results per page. I have various data being pulled and its putting it in a table, but its displayed all in one row. I want to format it so its a 4 column/5 row table. With that I then want the page to generate a numbered list at the bottom that calculates how many pages it takes to show 20 items on each. Code:

Displaying SQL Query Results In 3 Column Table
I would like to be able to display the results of an sql query in an html table, but the results need to be displayed in three columns, for example:

Column 1 Column 2 Column 3
Result 1 Result 2 Result 3
Result 4 Result 5 Result 6
Result 7 Result 8 Result 9

I've tried to find the answers on the internet but i can't find anything that suits my needs!

Displaying Multiple Queries To Same Table Excluding Different Rows!
i've got a table with 224 town listings and their ID's in it from 6 counties, and I want it to displayin a 6 columned table, each county getting their own column. Anyway, here's what I've got and what's happening: PHP Code:

Help With Displaying Selecting A Date Range And Displaying Results
I wish to create a simple form that allows the selection of a start date and a stop date with the ability to select what columns to be displayed in the result page.

Grab Content From HTML Table And Place Into MySQL Table?
I am in the process of helping a co-worker upgrade some of his old static html pages into dynamic MySQL driven pages. He currently has a lot of pages with huge tables displaying data. Does anyone know if there is a script or class that can convert a table to a .sql file for upload?

Table Background Color Based On Results From MySQL Table
I am trying to get the "Did User Agree" field on a database query to be colored Green for "Agreed" Red for "Disagreed" and Blue for "Agreed (2nd Time)" .. I have my PHP setup to do the query just fine as of right now with alternating column colors, just can't seem to get the colors to work as I am hoping for. Can anyone help me get the Agreed? table's background color to the colors above? Code:

Outputting A Table Or Form Using SHOW FIELDS FROM Table
In the code the MySQL database was queried using "SHOW FIELDS FROM table" which and the returned results of column names was then use to build an output for a form and a table with php using a series of if statements along the lines of if the returned field name matches something echo a text input field.

I have never seen this done this way before, so I want to get the opinion of the devshed user. Does it seem like an unsual long process to build up a form. Is there a security advantage doing it this way? Has anyone ever done it this way before?

Finding Matches In A Table And Then Moving That Match To Another Table?
Ok, I have a database that has a table called critiera in this table
is to fields on is ID and the other is critiera.

Now I want to filter out all the one that don't apple to the list and
move the one that match to a different database.

I know how to open a connection, close, select

but I don't know how I would inside of a database use another one as
the way to create the list of critieras....

Mysql Fetch_field Gets Table Alias, Not Real Table Name
After a SQL 'select .... from tablename alias'
the mysql_fetch_field function returns a value $result=>table which
will contain the alias, not the actual table name.
Is there a way to get the actual table name ?

I am running mysql 4.1 and php 4.4

Grab Data From A Table, Echo, Then Insert It Into A New Table...
I'm trying to do is count the number of times usernames shows up in a table. I then want to reinsert that information into a different table with the Username in column1 & the occurrences in column2 for every user that is echoed on the page. Code:

Using PHP To Sort Data In MySQL Table 1 By Values In Table 2
I have a MySQL database with 2 tables in it. products and prices.. Products has a field in it called 'prodno'. Prices has a field in it called 'prodid'.

There is one of each item in products and each product has it's own unique 'prodno'

There are multiple instances of each product's pricing in prices.. One for each price.. So if a product had multiple prices depending on quantity it would have an entry for each price.. Example:

id = 1
prodid = 7001
qty = 300
price = 12.5

id = 2
prodid = 7001
qty = 400
price = 15.5

I was wondering if I could query the database getting info from the products table but sort it according to the prices in the prices table.

Kinda like doing a "SELECT * FROM products" ordering it by the lowest price value from each item..

This is all very confusing to me, and I'm the one writing it. Let's try one last time..

Query the database selecting * from products (I plan on using all the info in products) and ordering them by the lowest price for each item in the prices table. I've tried sorting the results of just a basic SELECT * FROM products using Javascript and PHP but with pagination in the results it makes it a bit hard.

Update Table While Insert Data To Another Table
it seem like mine coding din work.
[php]<?

include("checkin.html");
$conn=mysql_connect('localhost','root','') or die ('Could not connect to server');
$today = date("Y.m.d");
mysql_select_db('hms', $conn);

$ok = mysql_query("INSERT INTO check_in(ID,room_no,datein)values ('$ID','$room','$today')", $conn);

if( $ok ){

$up = mysql_query("UPDATE studtable SET checked = 'checkin' where [ID] = '%ID');

if(mysql_affected_rows( $up ) == 1)
{
echo'Checked IN!'
}else { echo'No such student to check in' }}
else { echo'Check In FAILED, please check again'}?>[php]

How To Transfer A Data With An Id To Another Table From A Table?
how am i going to transfer let say a name identified using the suer id and copy the name to the other table having the same user id>?

How Can I Find A Name From One Table In A Text From Another Table?
I have one table with a description field and other info, and I also have another table with a list of names and picture url:s. When I display the text description on my site I'd like to know if there are a match with a name from the 'names' table in the text. Code: