PHP :: Displaying Results From Database In A Particular Format

Displaying Limited Results
I have a problem that is related to limiting the results displayed in a page. I have a numbered pagination script working that has a limit etc. At the moment it is milited to displaying 8 results before producing the next link.

What I have is a table with 2 columns and 4 rows....a grid of 8. I want the results to start in the top left and then when 2 table cells have been created it will start a new row and do this for all of the results ie:

1 2
3 4
5 6
7 8

Basically, i need code that will make a new row start when 2 results have been displayed in that row.

Help With Function For Displaying Calculation Results
I am developing a betting calculator and at the moment I am working on some functions that can be used to display the HTML for the form to enter your bet and odds and the results.

I am still relatively new to PHP and I am learning all the time so sorry if this is a simple problem!

I have 3 files: calc1.php, index.php and funtions.php

Here is index.php PHP Code:

Displaying Results On Multiple Pages
I have a search query via PHP and MySQL that has list of results, but I only want to show 10 or 15 on a page. Much like Yahoo! or even here on the Devshed forums. I have been working on a system that cycles through all the results with a while loop and a counter. It only displays results >= 11 or <=20 as an example. I am passing that data (the results start point through the url) I am just worried that if the results are in the thousands this system would get very slow.Is there an easier/better way that I am not seeing?

Nesting Queries And Displaying Results.
i am in the process of trying to make a simple system to keep track of switch ports and what points they are conencted to. the problem i am having is with displaying the data from my ports table. Code:

mysql> select * from Switch_Ports;
+------+----------+---------+------------+--------+
| SwID | Port_NO | VLAN | Patch_Port | PortID |
+------+----------+---------+------------+--------+
| 1 | fa1/0/1 | staff | AA10 | 1 |
| 1 | fa1/0/2 | staff | AA12 | 2 |
| 2 | fa1/0/10 | staff | AA100 | 3 |
| 2 | fa4/0/12 | staff | BB12 | 4 |
| 3 | fa2/0/11 | student | A16 | 5 |
| 3 | fa1/0/23 | student | B14 | 7 |
+------+----------+---------+------------+--------+

SwID relates back to my Switch table, which contains dns names and stuff like that. for example i want to be able to display the ports from SwID 1 PHP Code:

Displaying Array Results In Table
I'd like to display the results of an array in a table format with the Alias, Alias Destination & Username as column headings & the results underneath. PHP Code:

Displaying X Number Of Results Per Page
What I need to do is this. I query a MySQL database and, for example, 400 results are returned. I can get it to display the number of results, but I would like to set a value to display, say 20, results per page and generate numbered links with and offset to browse through and next/previous buttons -not unlike this page. Can anyone point me in the direction of a good article or if you have it, post some code here?

Displaying Results With Decimals, And Stylizing Them.
I just have what I think is an easy question for some of you. I have a page that pulls all the entries from a specific table in the database. The results are displayed in a table. In this table there is column for "job_number" this job number is a decimal entry, i need to display the job numbers, grouped by the the numbers ahead of the decimal place and then ordered by the numbers after the decimal. I would also like to indent the decimals ONLY numbers below the under that does not have a decimal. Code:

Displaying Search Results In Pages
I am implementing search functionality in a website. ( internal search).
In that I am taking a keyword as input and searching all the pages and storing
results in an array. I want to display 10 results per page. I wrote below logic for that. Code:

Displaying MySQL Results As URLs
I'm attempting to turn the results of a query into urls, yet I keep getting this error, "Parse error: syntax error, unexpected '<' in staff.php on line 190." I've coded and recoded this, yet for some reason I cannot get this error to go away. I know it's probably simple, but what am I missing? Code:

Displaying X Number Of MySQL Results Per Page
I'm writing a search on a MySQL DB, and everything so far has just gone swimmingly. I've got a "results per page" drop down box in my form, with a few different values.

At the moment, I'm just using:

while($myrow = mysql_fetch_array($result)

to output results to screen.

I'm not too sure how to go about it, but I did have two thoughts:

1) Suck the results into a multi-dimensional array, and pass the array to a display results script (not sure if you can pass arrays to other scripts???

2) Display x number of results, then have the "Next" (or 2, 3... ) links call the search again, but displaying results x+1 - x+x.

1 sounds like too much trouble, and 2 sounds inefficient. Not too sure how else to go about it. Any info / thoughts you guys have would be much appreciated.

On a side note, how do you look at a specific row in the result?

Displaying SELECT Results In A Formatted Table
I was wondering how to show a table with a max limit of 20 results per page. I have various data being pulled and its putting it in a table, but its displayed all in one row. I want to format it so its a 4 column/5 row table. With that I then want the page to generate a numbered list at the bottom that calculates how many pages it takes to show 20 items on each. Code:

Displaying SQL Query Results In 3 Column Table
I would like to be able to display the results of an sql query in an html table, but the results need to be displayed in three columns, for example:

Column 1 Column 2 Column 3
Result 1 Result 2 Result 3
Result 4 Result 5 Result 6
Result 7 Result 8 Result 9

I've tried to find the answers on the internet but i can't find anything that suits my needs!

Displaying Select Information From XML Search Results
I am new to both php and xml. I have a school assignment to update an existing php-based website where I have to display search results from an online library. I can use a url search which returns an XML file that includes tags such as position, title, url, description, date, etc.

I only want to display the title, url (preferably the title should be a link to the url), and description for all of the results on my website's search results (different template as well).

What classes/functions are available to help me do this? I would appreciate any guidance as well as links to online tutorials etc. that would point me in the right direction. I have read about the general aspects of php, and I have experience with Java and C; but I don't know about xml at all.

By the way, the website is running on the school server and has php version 4. I don't think I'll be able to install php 5 but I can probably upload some helper files or something.

Retrieving,Sorting & Displaying Multiple Results From Mutliple Tables
I need to know how to run a php / mysql query to do the following.

I have 1 database (lets call it "database" for now) within this database there are multiple tables ("News","Feature","Header_feature")

For NEWS I need only the 6 latest results pulled from that table and displayed in a table. The "News" table has the following columns "ID","Title","Date","Body","Image"

For Feature I need only 1 result retrieved from the database and displayed under the variable $ticker as it will display as a scrolling marquee within a table. The "Feature" table has the following columns "ID","Ticker".

For Header_feature I need only 1 result retrieved from the database and displayed in the following manner <a href="$link"><img src"$header_feature">[/url] The "Header_feature table has the following columns "ID","image","link"

How would I code this all into 1 page? I cant seem to get the query to do everything I want it to and display the results properly. You can see what I have so far at www.getlivemedia.com The $ticker is the scrolling text near the top of the page and the news is obviously the bulk of the page and $feature_image is the broken image.

Format Dates In A Database...
what is the best or easiest format for storing dates in a mysql database? I'm wanting to store a lot of things with a date value and want it to be as easy as possible to read the date from it... I've had problems with getting dates in the past because of how I stupidly stored them.

I was thinking of simply having
day/month/year

e.g:
22/05/1988or should I use a unix timestamp?

Data Format In Application Or Database?
I have found that by far the easiest way to store dates in my LAMP
application is in a text string in the database in Unixtime format.

First of all, what would be the most efficient data type to store this as?

Secondly, in terms of translating into a human readable format, is it
quicker to format the date in the application using date() or in the
database in the select query?

What Is The Proper Date Format For A Txt Database?
I would like to know what format should be used when writing to a txt file. I am trying to search between a start date and a ending date and list any variables For example.

if (($sDate <= $jdate && $eDate >= $jdate))

then I have it list the variables it will work if searching between months and days but it does not work if I have different years. I will get all years printed out.

my date format is m/d/Y 6/13/2001

If I search for example start date = 6/01/2001 and the ending date = 6/09/2001

I will get the correct month and day dates but I also get anything from the year before and including year in the future.

Date & Time Format In Database.
I'm using MySQL database, the problem is I've setup that user input the Date format in dd/mm/yyyy (example: 14may2007) and Time (example: 12:00pm). How do I convert it to Date & Time format in database format before insert into database? Sorry, noob here.

Displaying From Database!
I'm trying to display products that are pulled form a database in a certain way using only DIV tags I would like the products to display across the page in rows of 4, however when i use div tags it is just putting one on each row.. whats the best way to display in a row of 4? here is an example script of what im using to experiment with: Code:

Not Displaying First Record In Database
this code is not showing up first record in database:
the table should start off by clan id = 1 and clan name = name1
page: PHP Code:

Displaying Content From Database
need some simple help with displaying content from a mySQL database using PHP. i want to know how to write a php script to display the latest entry in a table to an html page. and also how to adapt the script to display the latest x amount of entries.

Displaying Date From A Database
All I need to do is change the date so it reads, for example, May 1999 when it's displayed on the page. Code:

Problem Displaying Image From Database
I used the code below to pull out an image from a mysql database
but nothing shows on the page and there was no error message to
indicate any problem.What could be wrong.The image is actually in the
database with all the details:

<?php
if(isset($_GET[loginid]))
{
$con=mysql_connect("localhost","name","pass");
if(!$con)
{
die('Could not connect to database:'.mysql_error());
}
mysql_select_db("datab",$con);
$id = $_GET[loginid];
$query = "SELECT name, type, size, content " .
"FROM image WHERE id= '$id'";
$result = mysql_query($query) or die('Error, query failed');
$file=mysql_fetch_array($result);
$name=$file['name'];
$type=$file['type'];
$content=$file['content'];
header('Content-length: '.strlen($content));
header("Content-type: $type");
header("Content-Disposition: inline; filename=$name");
echo $content;
}
mysql_close($con)
?>

Displaying Values From A Database From An Include
I've got a URL going to a template, e.g. www.mydomain.com/product.php?id=product_a

where the template is product.php the tag after the ? refers to the product that should be displyed in the template, in this case product_a

Inside the template (product.php) I've got:-

<? $url = $id.".htm"; include("$url"); ?>

This works fine so far. How ever I've also got an include inside the the template (product_a.php), called product_info.php, which is another php file that displays the product version and the platforms that it sits on. so in the the include (product_info.php) I have:-

<?php

$db = mysql_connect("localhost", "username", "password");
mysql_select_db("DATABASE",$db);
$result = mysql_query("SELECT version FROM table1 WHERE id = id",$db);

do { if ($myrow[0] != "") { echo "$myrow[0]n"; } }

while ($myrow = mysql_fetch_array($result));?>

however this displays all the version numbers within the table (for every product)

I just want it to display the version number of the value of $id (www.mydomain.com/product.php?id=product_a)

Displaying Image Stored In Database
The user can browse and upload an image and the image is stored successfully in a seperate binary table (with userid and bin_data, filesize, filename, filetype). The photo is displayed properly when I point my broswer to a script called fileshow.php:
PHP Code:

Problem Displaying One Column Of One Row From A Database With PHP.
I have a small script with PHP that queries a MySQL database to pull
out one row, where I want to be able to access each of the columns
separately. I have tried several different variations and am able to
get the entire row to print, but when I attempt to access the
individual columns I get an error. Here is what I have so far:

if (isset($_POST['memberNo'])):
$link = mysql_connect('...','...','...');
mysql_select_db("...");

//Perform a test query
$query = "SELECT * FROM users WHERE 'id' = " . $_POST['memberNo'];
$result = mysql_query($query) or die(mysql_error());

$line = mysql_fetch_assoc($result);
print $line;

//Close connection
mysql_close($link);

The point of this code is to retrieve the user information to validate
the login information sent in the previous form. I do not get an
error with this code, but it also does not print anything. I know
there is an entry in the database that matches data sent in the
$_POST['memberNo'] variable, it is the only entry in the database.

Changing the 'print $line;' to 'print $line["id"];' does not display
anyting either.

Displaying Database Information In Columns
I have a database with products in and I want iT to automatically show every product on the page. Now I am able to do this easy enough but what I am struggling to do is that I want the products to be displayed in 3 columns. I can get them to display one under the other easy enough but I want them to be in rows with 3 columns instead.

Displaying Multiple Items From Database
what i have is a page that has four sections. what i want to have is when the page opens, in that page i want the lastest two items for each section from a database to be displayed. the items to be displayed are an image, a title and a description. but i also want the description to be shortend to say about 25-30 words or about 100 chars, if thats easier?

so in the end i have 4 sections, each showing the lastest two items for each section.

would the best way to do this be to have a seperate table in the database for each of the sections? or would i be able to do it from one table?

would i have to creat a query for each of the sections?
e.g:
SELECT * FROM table WHERE section=section

Displaying A List Of Categories From A Database In A Select Box
Could someone please tell me why this outputs nothing

<select name=categories>
<?
$cat_array = get_categories();
foreach($cat_array as $this_cat)
{
echo "<option value="";
echo $this_cat["category_id"];
echo """;
echo ">";
echo $this_cat["category_name"];
echo "
";
}
?>
</select>

==========================================================

function get_categories()
{
//get the list of categories from the database

$conn = mysql_pconnect("localhost", "user", "pwd");
$query = "select * from categories";
$result = mysql_query($query);
if(!$result)
return false;

$num_cats = mysql_num_rows($result);
if($num_cats == 0)
return false;

$result = db_result_to_array($result);
return $result;
}

//A function that returns a query to the database as an array
function db_result_to_array($result)
{
$res_array = array();
for($count=0; $row=@mysql_fetch_array($result); $count++)
$res_array[$count] = $row;

return $res_array;
}

Reading And Displaying A Date From A MySql Database
I've just started using php, and although I am very impressed by it,
there are some things with which I am confounded!

What I'm trying to do is read in a Date from a mySql database and then
display it on screen (the Date is in the usual yyyy-mm-dd format).

If I use SQL on phpadmin
SELECT Date
FROM details
WHERE details.Name = "Paul Lee"
LIMIT 0 , 30

The result comes up 2005-01-01, so this seems to work.
But if I use the following:

$db = mysqli_connect("localhost","root","");
@mysqli_select_db($db, "personnel") or die ( "Unable to select
database" );
$query = 'SELECT Date FROM details WHERE details.Name = "Paul Lee"
LIMIT 0, 30'

$result=mysqli_query($db, $query);

echo "<br>";

echo $result;

mysqli_close($db);

I get "Object id #2" displayed on screen.
I have tried to use the explode function to separate the months, year
and day using the "-" as a delimeter, but this doesn't work, and I
can't seem to get the other php date/time functions to work either.

Displaying Information From A Database In A Text Field,
I am trying to create an admin page, but before I get anywhere near that, I need to understand how to get data froma database to show up in appropriate form fields *text, textarea, etc...*

I am able to get content from my database to show up in my template, now I want to create a page that allows a user to click on a link for which they want to edit the information (name, and bio) So I want that page to show up with a simple form, a text field displaying the name, and a textarea displaying the bio information, so that they can modify it and save it to the database. how do you get the information to show up in the form fields? Code:

Displaying Database Records Over Multiple Columns
I am currently using the following to generate a table with a single column with ten entries PHP Code:

Previous And Next Links And Displaying Database Information
I would like to display a listing of files on a web page as follows:

If there is only one file: display the section name and then display the
current file.

If there is more than one file (for the first page): display the section
name, the current file and a few archive files.

If there is more than a page full (for each additional page): display the
section name, and the next set of archive files.

This is the code I have been working with (it's a bit ugly, suggestions are
welcome). For some reason the second page of listings skips the first item.
1st page lists items 0 through 4, second page skips item 5 and starts
displaying item 6.

function display_table($sec_id, $num_item){
GLOBAL $link;
$updir = "../uploads/"; //maybe this should be a GLOBAL variable???
if (isset($_GET['start'])){$start = $_GET['start'];}else{$start = 0;}
//GLOBAL $start;
//query DB
$query_total = "SELECT file_id
FROM files
WHERE file_section_id =" . $sec_id ;
$query = "SELECT file_id, file_meeting_date, file_meeting_time,
file_title, file_modified, file_section_id, sec_name, sec_id,
sec_disp_archive
FROM files f, section s
WHERE f.file_section_id =" . $sec_id . " AND f.file_section_id = s.sec_id
ORDER BY file_modified DESC LIMIT " . $start . "," . $num_item;
$result = mysqli_query( $link, $query ) or die(mysqli_error($link));
$result_total = mysqli_query( $link, $query_total ) or
die(mysqli_error($link));
$num_rows = mysqli_num_rows($result_total);
//print $query;
//create hyperlinks and display table
//display current file
/* print "START: " . $start . "NUMBER: " .$num_item . " ROWS: " .
$num_rows;*/
/*$obj = mysqli_fetch_object($result);*/
if ($num_rows > 1){ //Display current and archive files
//only display current table if start is not set (not on page 1)
$obj = mysqli_fetch_object($result);//Call DB
$content = "<div id ='MainContent'><p><b>" . $obj->sec_name .
"</b></p><table width=ï`%' border=Ƈ'>";
if (!isset($_GET['start'])||$_GET['start']==0){
//for 1st item display file info
$content.= "<tr><td colspan=Ɖ' align='center'>Current</td></tr>";
$content.= "<tr bgcolor='#CCCCCC'><td width=ཝ%'>Meeting Date</td><td
width=ཝ%'>Meeting Time</td><td width=ཞ%'>File</td></tr>";
$content .= "<tr><td>" . date("F jS,
Y",strtotime($obj->file_meeting_date)) . "</td><td>" . date("g:i
A",strtotime($obj->file_meeting_time)) . "</td><td><a href='" . $updir .
$obj->file_title . "'>" . "View Current File" . "</td><tr>";
$content .="</table>";
print "START: " . $start . "NUMBER: " .$num_item . " ROWS: " . $num_rows;
//DEBUG

Displaying Block Of Text From MySQL Database
I would like to create a details.php page that displays all my products. I understand how to get the title, price, description etc from mySQL. But my problem is how do I get a list of data? For example say I want to display the features of a product in point form (list). What is the best way to do this? How do most common websites do this? Code:

Getting Results From MySQL Database In PHP
I am trying to write a php page which connects to a MySQL
Database which is supposed to get the results from a table within a
database and display the results in a table.

Below is the code that I am using:

Database Search Results
i have a paid to read website,im hosting it off my own pc..as a member you can search offers and complete them, heres where i need some help..when a member clicks submit and the offer goes to an offerdone table i need the offer to hide from them so they cant do it again,also that same offer needs to hide in the search results as well...is there somthing like onclick hide and for the results something like if duplicate hide from search or if offer found in this table hide from results...

there are 2 tables one will all my offers the other with offer they have done,also this needs to apply for each member account.i am new to all this and have made it this far to have my site up and going but im looking for those extra catchs i could really use,so that a member cant repeat an offer they have already done,

Limit A Database Field To Displaying Only One Time And Still Display All?
I have a data table with a field that contains the exact same text (example "some text") on several different rows. How can I display all my rows without getting duplicates of this field; I only want to display this field once. I tried to use a LIMIT, but this is not what I needed. Code:

Having Trouble Alphabetizing Results From A My SQL Database
I'm a beginner and I'm having trouble figuring out the sort command (assuming that's what I'll need to alphabetize my results from a database.) Any helpful input is welcome.

Grouping Database Results In Pagination
I'm dealing with a situation where I can potentially have over 3000
results to display from a database. I'm successfully paginating the
results, 10 at a time, but don't want to display 300+ page links at the
bottom.

How can I group the pages to show, for example, the first 10 pages,
followed by a "next 10" link?

i.e., Page: 1 2 3 4 5 6 7 8 9 10 > >> Next 10

My current code:

Sorting Database Query Results
I want to know if it is possible to sort query results so that the records with a value in a certain field is displayed first and the records with the field empty thereafter.

Showing Image With Database Results
I am trying to retrieve data from a MySQL database and have got it working. Only thing is I would also like to display an image for each row. Each record has a file number and the images are all saved in an image folder and are named with the actual file number.

EG there is a record with file number 1111 and there is an image called 1111.gif in the images folder. I have included my code below. If someone can tell me how to include some html code to show the image in my php code. Code: