Displaying Select Multiple Box And Using Mysql Join
i have an edit page where the query lists all the information from the database about a business. each business can have multiple types so i made a many-to-many database and now i need to be able to show all the types that are in the db for each business on the edit page. here is what i have so far but it's only selecting the last type of business in the result. PHP Code:
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Select Multiple & Mysql
What's the sql should look like to get all possible data when using multiple select, such as: <select name="hostfield[]" multiple> PHP Code:
SELECT LEFT JOIN LIMIT WHERE?
I want to have a page with categorized items, and also limit the divide the page into sub pages (with "previous 1 2 3 next" buttons), but I couldn't do it. I have this code: "SELECT products.*,category.name FROM products LEFT JOIN category on product.categorized=category.category_number LIMIT $offset,$limit WHERE category_number='$id'") LIMIT and WHERE doesn't work. But if I delete "LIMIT $offset,$limit", I have a long page.
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I have an Intranet with the organisation I work with. In this organisation there are two departments - community department and press office. Both the community department and press office have thier own news system where they can add news in their own admin section that will appear on their homepages. Both admin section have their own DB table thus two seperate tables. I would like to select all the rows from both tables in a single SELECT statement so when I output them they will be integrated. This is not the same as a table join as their are no keys and I want the rows from both to remain seperate. Can this be done? Could someone please post an example SQL statement demonstrating this if so?
SQL Query With SELECT DISTINCT And LEFT JOIN
I'm having problems with a SELECT DISTINCT statement with an INNER JOIN. Here is the table structure for my tables: 'locked_accounts' locked_account_id uid 'la_comments' comment_id locked_case_id uid status 'user' uid username And here is my SQL: SELECT DISTINCT l.locked_case_id as locked_case_id, l.uid, u.uid as uid, u.username as username FROM la_comments l LEFT JOIN users u ON l.uid = u.uid where status = 1 What I'm trying to accomplish is getting a display of updated accounts (where status=1) and I want to display their username. In the la_comments table, there might be 50 distinct 'uid's, but I only want to display the distinct uid/username's where the status = 1. Can someone point me in the right direction on this. I've messed with this for a couple of hours and I'm at wits end. Not very bright I am when JOIN statements it comes to.
Multiple Select From Listbox And Execute A Sql Query Select Statement
Supposing i have a html form with 2 listbox and i name it status and resolution. So it goes <select name='status[]'>... <select name='resolution[]'> Then i have a another php page. $status = $_POST['status']; $resolution = $_POST['resolution']; Now my question is, how do i do the sql query statement? mysql_query("SELECT * from bugs where status=$status and resolution=$resolution"); The problem is, i select 3 options form the status listbox eg. new, closed, duplicate. And from the resolution, i chose fixed, invalid.
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I have the foll. $sql which works well. $sqla = "SELECT * FROM Customers c INNER JOIN Custaddress a USING(CID) INNER JOIN Cities t USING(CITYID) WHERE c.Company LIKE '%$customer%' ORDER BY Company asc"; But if I wish to do a sort on 3 fields in 3 different tables, i'm getting an error. $sqla = "SELECT * FROM Customers c INNER JOIN Custaddress a USING(CID) INNER JOIN Cities t USING(CITYID) WHERE c.Company LIKE '%$customer%' ORDER BY c. Company asc, t.City asc , a.Zip asc ";
Mysql - SUM And INNER JOIN
Can anyone help with this query? Here is what I am trying to do: mysql_query("SELECT code.* FROM code INNER JOIN ratings ON code.id = ratings.codeid WHERE SUM(ratings.rating) >= 50 ORDER BY code.id DESC"); Obviously this won't work because you cant use SUM in the WHERE clause, but you can see what I am trying to do. Any ideas?
Displaying A List Of Categories From A Database In A Select Box
Could someone please tell me why this outputs nothing <select name=categories> <? $cat_array = get_categories(); foreach($cat_array as $this_cat) { echo "<option value=""; echo $this_cat["category_id"]; echo """; echo ">"; echo $this_cat["category_name"]; echo " "; } ?> </select> ========================================================== function get_categories() { //get the list of categories from the database $conn = mysql_pconnect("localhost", "user", "pwd"); $query = "select * from categories"; $result = mysql_query($query); if(!$result) return false; $num_cats = mysql_num_rows($result); if($num_cats == 0) return false; $result = db_result_to_array($result); return $result; } //A function that returns a query to the database as an array function db_result_to_array($result) { $res_array = array(); for($count=0; $row=@mysql_fetch_array($result); $count++) $res_array[$count] = $row; return $res_array; }
Displaying SELECT Results In A Formatted Table
I was wondering how to show a table with a max limit of 20 results per page. I have various data being pulled and its putting it in a table, but its displayed all in one row. I want to format it so its a 4 column/5 row table. With that I then want the page to generate a numbered list at the bottom that calculates how many pages it takes to show 20 items on each. Code:
Displaying Select Information From XML Search Results
I am new to both php and xml. I have a school assignment to update an existing php-based website where I have to display search results from an online library. I can use a url search which returns an XML file that includes tags such as position, title, url, description, date, etc. I only want to display the title, url (preferably the title should be a link to the url), and description for all of the results on my website's search results (different template as well). What classes/functions are available to help me do this? I would appreciate any guidance as well as links to online tutorials etc. that would point me in the right direction. I have read about the general aspects of php, and I have experience with Java and C; but I don't know about xml at all. By the way, the website is running on the school server and has php version 4. I don't think I'll be able to install php 5 but I can probably upload some helper files or something.
Multiple Multiple Select Boxes
I'm looking to have multiple multiple-select-boxes on a page. But I can only get the contents from the last selected value within a box, via PHP. I've tried numerous methods. What am I doing wrong? You can see ALL the values present in the url: http://myserver/test.php?notify_use..._updcats=Update e.g.......
MySQL Join Question
Can't seem to figure this out. I have a MySQL query where I have Table A joined to Table B. Now, I need the rows from A more than I do B, put another way, I need the rows from Table A no matter what happens getting rows from Table B. Again, put another way, no matter whether a record doesn't exist in B, does exist in B but doesn't meet the WHERE criteria, or anything at all, I need the records from A no matter what. I have tried using LEFT JOIN and LEFT OUTER JOIN but they both don't work when records exist in B but don't meet the where criteria, therefore the JOIN fails and I lose the record from A. Is there anyway to get the JOIN I need in one query or will I need to use more than one?
LEFT JOIN (MySQL)
============= The problem: ============= I want to list the users with their country and region (If the user's country has no regions, NULL would be returned). ex: userId = 123 country = USA region = New York userid = 456 country = Japan region = NULL Japon has no regions (in my application) so "NULL" is returned. ============= The Tables: =============
Best Way To Show A Mysql Join
I have the following tables: students id, name,.... lessons id,description,.... studentslessons id,studentid,lessonid,grade I want to list the lessons of student with name="John" for example. The one way to do it is : select id from students where name="John" and grab the id. then select * from studentslessons where studentid=id; the other is select * from students,studentslessons where students.name="john" AND students.id=studentslessons.studentid Which is more efficient when using php4 and mysql 4.1? I'm using a rather old computer Pentium 800MHz.
Mysql JOIN Syntax
I am trying to JOIN two tables together using the common column "Username". My code is ECHOing all of rows of column "title". I want to just ECHO the column "title" rows that are specific to the "Username". example: I have a user named "ballhogjoni". This username is stored in a table named 'users' and in a table named 'products' under the column "Username". There is a "Username" column in each table. Code:
Variables From JOIN In Mysql
just a question on when i join 2 tables in mysql, say both of my tables have an 'id' (which most of the time they do) if i do: $id = $row['id']; how can i distinguish between the id's? i mean if table 1 has and id and table 2 has an id how would i set the variable?
Need A Thorough Explanation Of A MySQL Left Join
I have been scouring the internet trying to find a good, solid, visual explanation of a left join. I "kind of" get it but I get confused. If I could see a visual - I get confused by the on clause. I have a database of articles. 1 table is the article itself. Another is article categories, and the last is articles in categories that records the article's ID and the category ID. So I have a left join that someone else wrote that I'd desperately like to understand that looks like this:
Retrieveing Vars From Mysql Join?
I have the following problem : $some_query = mysql_query( "SELECT table1.id, table1.category, table1.author, table1.title, table2.title, table2.category FROM table1, table2 WHERE table1.category = table2.category ORDER by table1.id DESC"); while($record = mysql_fetch_array($some_query)) { $mycategory = ($record['table1.category']); $mytitle = ($record['table2.title']); echo"$mycategory"; echo"$mytitle"; } Does someone know what's wrong here ? echo don't show the requested values ....
What Join To Use For Joining Three Tables In Mysql?
I have person Table which holds address key that points to "link-table" record which holds person ID and address table record ID. I want to get precise person and precise address so I thing that is disqualifying the LEFT and RIGHT joins. Remains the INNER join but I did not see it anywhere with more then two tables. My creation: "SELECT t1.name, t2.* FROM persons AS t1, addresses AS t2, persons_addresses as t3 WHERE t3.id = t1.address AND t2.id = t3.address" does not work the way I want.(IT is basically left join [or not?]) Please, can any mysql-php GURU help me? person id = persons_addresses.person person ... field address persons_addresses id = person.address persons_addresses ... field address addresses id = persons_addresses.address Table address holds all relevant info about the address like street, zip, city key, state and country. I can imagine the use of subselect if mySQL had one, but I can not actually imagine without it [and probably is only very simple matter].
JOIN Table Results W/MySQL
I have a query with a simple JOIN. For example: SELECT * FROM Companies INNER JOIN CompanyTypes ON Companies.CompanyID = CompanyTypes.CompanyID The query returns all fields from both Companies AND CompanyTypes. I would like all fields from Companies only.
Get Most Recent Row On An Inner Join Mysql Query Based On Date
Here is my current query: SELECT tbl1.id, tbl1.username, tbl1.status, tbl1.joined, tbl2.timeDate, tbl1.directory FROM tbl1, tbl2 WHERE tbl1.id = tbl2.users_id GROUP BY tbl1.id This returns their oldest ie first login. I use this for analytics on the backend to determine user activity. So I would like a query that instead that returns the most recent tbl2.timeDate.
Displaying Results On Multiple Pages
I have a search query via PHP and MySQL that has list of results, but I only want to show 10 or 15 on a page. Much like Yahoo! or even here on the Devshed forums. I have been working on a system that cycles through all the results with a while loop and a counter. It only displays results >= 11 or <=20 as an example. I am passing that data (the results start point through the url) I am just worried that if the results are in the thousands this system would get very slow.Is there an easier/better way that I am not seeing?
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what i have is a page that has four sections. what i want to have is when the page opens, in that page i want the lastest two items for each section from a database to be displayed. the items to be displayed are an image, a title and a description. but i also want the description to be shortend to say about 25-30 words or about 100 chars, if thats easier? so in the end i have 4 sections, each showing the lastest two items for each section. would the best way to do this be to have a seperate table in the database for each of the sections? or would i be able to do it from one table? would i have to creat a query for each of the sections? e.g: SELECT * FROM table WHERE section=section
Uploading And Displaying Multiple Images
I am building a website where people can post jobs that need to be done and have laborers bid on them.... Im done with pretty much everything on the site but im having a hard time figuring out how to upload and display multiple images for each job.... I am able to upload and display one image but i can upload multiple images.... Everytime I try to do so, It only displays multiple copies of the first image that i upload. Code:
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I'm having a little problem, in my form, I have to select multiple lines in a 'select' field and post it for processing. Now in the $_POST-variable, there is only the last selected item visible. How can I post every selected line?
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I have a list box on my page which I dynamically populate from the database. My question is, if I allow people to have multiple selections from this, how would I retreive the selections that they have made? example:- if I name the select box "Jobs", would i be able to do something like:- PHP Code:
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I am trying to create a drop down list that permits a person to select multiple items from the list and have the results posted on a results page. I am using Dreamerweaver MX, PHP and a MYSQL database. I was able to select multiple items but only the last selected item would be displayed. I tried to modify the list box code and now it returns nothing. Code:
Select Multiple Code
need to be able to generate a multiple select in a form using php and then write the reults to a relation table between a resource table and a look-up table..i.e. table 1 list of resources table 2 list of options for element in table 1 table 3 a many to many resolution table between table 1 and table 2 I can do this if only one option is select from a drop down list, code below: PHP Code:
Select Multiple In A Form
When using select multiple in a form how do I retain the highlighting of the selected highlighted values after the form has been submitted? <select name="cities[]" size="4" multiple="multiple" style="font: 8pt Verdana" id="cities_id">
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I have a db with 34 tables with all the same feilds, and would like to select 1 columb from all these tables. Is this possible from a select query, if so a example would be great. You may well ask why have i 34 tables all the same, but i thought is was a good idea to set out the tables as per my catagories when i was constructing them. But now i know i can do them all from 1 table with multiple fields.
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first of all I have three tables (tournament_game, umpire_game, umpires). Updating tournament_game umpires, each game may have from two to four umpires, and those umpires can work from one to n number of games, that's why I'm using connection table umpire_game. I'd like to get selected multiple select box of umpires in game, it could be two to four options, with all umpires listed as options example: <select name=umpire_game[] size=10 multiple> <option value=$umpire_id>$umpire_name</option> <option value=$umpire_id selected>$umpire_name</option> <option value=$umpire_id selected>$umpire_name</option> <option value=$umpire_id>$umpire_name</option> <option value=$umpire_id selected>$umpire_name</option> <option value=$umpire_id selected>$umpire_name</option> PHP Code:
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how can I insert data coming from a multiple select box knowing that I need to insert other form fields at the same time. <select name="auswahl[]" size="5" multiple> <option value="bream">bream</option> <option value="eel>eel</option> <option value="pike>pike</option> .... </select>
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I have a poll script that I am in desperate need to let the users have more then one choice to the poll when they are voting...here is the original code below all i know is i have to change the type from radio to checkbox.. but other then that i'm totally lost, can anyone please give me the exact code i would need to change this I am still a real newbie as far as this stuff goes.. Code:
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I have a website with a database full of category names...I want to be able to chose lets say 5 of these categories and use a select from database clause where I could simply enter the category names I want to use but am not sure how I would go about doing it. I can get the list to display just the Aprilia category using the code below: $data1->q("SELECT * FROM categories WHERE cat_name = 'Aprilia' ORDER BY cat_name asc"); However...how could I get my site to display Aprilia, Ducati, Honda, Suzuki, Yamaha?
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I'm writing a very basic search script. I have a form field where I want to accept both first and last names. In my database, the first and last names are in separate fields. I want the query to go through both fields and come up with results. Here is the PHP code so far (only searches first name): $search = $_POST['search']; $data = mysql_query("SELECT * FROM customers WHERE fname LIKE'%$search%'"); //Display results while($result = mysql_fetch_array($data)) { echo $result['fname']; echo " "; echo $result['lname']; echo "<br>"; } How can i change this around to perform the way I need?
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I need to know how to run a php / mysql query to do the following. I have 1 database (lets call it "database" for now) within this database there are multiple tables ("News","Feature","Header_feature") For NEWS I need only the 6 latest results pulled from that table and displayed in a table. The "News" table has the following columns "ID","Title","Date","Body","Image" For Feature I need only 1 result retrieved from the database and displayed under the variable $ticker as it will display as a scrolling marquee within a table. The "Feature" table has the following columns "ID","Ticker". For Header_feature I need only 1 result retrieved from the database and displayed in the following manner <a href="$link"><img src"$header_feature">[/url] The "Header_feature table has the following columns "ID","image","link" How would I code this all into 1 page? I cant seem to get the query to do everything I want it to and display the results properly. You can see what I have so far at www.getlivemedia.com The $ticker is the scrolling text near the top of the page and the news is obviously the bulk of the page and $feature_image is the broken image.
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