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Drop Down Lists


I have a drop down list with the town options 'Bury' and 'Ipswich' as
shown below.

When selecting one of the options, its value is passed to variable
$townsearch.

How do I change the drop down list so the option selected last time is
then the current one shown in the drop down box?

<body>

<?php $townsearch = $_get['town']; ?>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="get">

<select size="1" name="town">

<option>ipswich</option>
<option>bury</option>
&nbsp;
</select>&nbsp;

<input type="submit" value="GO" />

</form>




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I can't find an answer to my quesiton anywhere.

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Email Lists
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Ordering Lists
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Less-expensive Way To Set Up Defaults In Lists Etc?
I'm currently setting up default selections in <select> lists by
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.....

function Routine ( $defaultvals )
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for ( $i= etc. )
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(I've elided a lot of syntax, but you get the idea)

That seems slow and tedious. Does anyone know a cheaper way?

Quote's Invoices Lists...
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Now this is the part I'm stuck on. I'm thinking maybe something like an
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Maybe is there java script where you can open a new window and then
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Mailing Lists Under Apache
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Multiple Lists Selection
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Classes And Dropdown Lists
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If You're Good With Arrays And Lists, This One's For You
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Sorting Alphabetically Backwards Lists
This code runs @ http://www.ckoogle.com but the trouble is once I get
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<?php

echo '<form action="index.php" method="post">'
echo '<textarea name="input" cols="12" rows="20">'
echo '</textarea><br>'
echo '<input type="submit" value="Submit">'
echo '</form>'

if( isset( $_POST["input"] )){
$my_array = $_POST["input"];
$my_array=strrev($my_array);
$my_array=explode("
", $my_array);
print_r($my_array);
sort($my_array);
print_r($my_array);
for($cnt=0; $cnt < count($my_array); $cnt++)
{
echo(strrev($my_array[$cnt]));
echo('<br>');
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?>

How To Get Hotmail/Yahoo/Aol Contact Lists ?
is there anyone familiar with the part how does most of the match
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Detecting Checkboxes And Option Lists
I am trying to figure out how to detect a <Form> check box being checked in a PHP script.  Likewise, I am trying to figure out how to detect which option was chosen in a <option> list of drop-down items in a form. Code:

Auto-update Shopping Lists
I have a shopping list, or multiple shopping lists, that users and sort and add/delete items from.

I know how to add/move/delete items, but that is with a submit button. Is there a way, probably through AJAX, that the mySQL tables will be updated automatically as things are changed?

Pulling Options Lists From Mysql Tables
I've set up a form to load data into my db, but rather than hard code the options lists for three of the form fields, I'd like to pull that information from three lookup tables. This will allow whoever is inputting data to do a simple update for the three lookup tables, and speed enter the data into the form for the fourth (data) table without having to alter the code in the form.

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display "Single Pony" and return "1" to the CompClass field if Single Pony is selected
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in EventScores), and have the key field content loaded with the data into the data table. Once I've figured the coding for one, I can duplicate the effort for the other two tables.

I have seen PHP coding inserted inside php code. I've never seen this particular practice in any other language I've programmed in. Is this how a connect/query is handled inside a form which is inside a php script? <?PHP <form><?PHP ?> </form> ?> ??

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</select>

....then further down the page:

<select name="selection_2">
<option value="12">Curly</option>
<option value="8">Larry</option>
<option value="36">Moe</option>
</select>

Currently I am doing this, which works but seems sloppy:

<select name="selection_1">
<?
while($employees=mysql_fetch_assoc($qry_rslt)) {
/* ADD NAMES TO DROPDOWN WITH emp_id's AS THEIR VALUES */
?><option
value="<?=$employees['emp_id']?>"><?=$employees['name']?></option><?

/* CREATE ANOTHER ARRAY WITH THE emp_id AS THE KEY */
$emp_list_2[$employees['emp_id']]=$employees['name'];
}
?>
</select>

Then on the second drop-down:

<select name="selection_2">
<?
foreach($emp_list_2 as $key => $emps) {
?>
<option value="<?=$key?>"><?=$emps?></option>
<?
}
?>
</select>

Drop Down Box
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I am trying to populate a drop-down from a database and repeat this drop-down five times. The first drop-down gets populated but the others don't. I tried to reset the array, but I am still new to PHP and not sure if I am doing correct. Code:

Drop Down Box
The purpose of this application: I need 2 combo boxes, one with months, and one with years. When the user chooses both a month and a year, a page is displayed with certain numbers that are retrieved from a database. Those numbers correspond to the specific month and year. For example, January 1998 produce "12", but February 2001 might display "73".

So I guess I'm asking 2 questions. The first is just a general outline of how someone might go about doing this (to see if i'm on the right track in my thinking). The second, and more important question is for someone to please explain to me how do I get the values chosen in the drop down boxes to correspond to specifc fields in a database?

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i've got a drop down box that is populated by the results of a mysql querie but for some reason it only shows the first word. so if i have the results;

test 1
test 2
test 3

it will just display test, Code:

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Im trying to create a drop down box which at the end has a Other option. If Other is selected I want the variable which is set from the drop down box to be set to whatever is typed in, in the input box below by the user e.g:

<select name="team_name"><option value='' selected disabled>Select Team Name</option>
<option value="1st XI">1st XI</option>
<option value="2nd XI">2nd XI</option>
<option value="3rd XI">3rd XI</option>
<option value="Other>Other</option>
</select>

I dont really want to use Java or AJAX, is there anyway in which this can still be done?

Drop Down Box
I have a couple of drop down boxes which you select the option you want, that value is then stored in the database. If you make a mistake there is an edit option which once clicked shows the form with the information filled in/selected.

However my problem is that when you edit, although the current option which was previously entered into the drop down box is set as the starting value, which is disabled, if you dont change the drop down box the value is deleted rather than held as it hasnt changed. Code:

One Drop Down Box Effecting Another.
I am trying to have one drop down box effected by another drop down box on one page only. I would like a user to select their state from a drop down box, then depending on what state they choose, I would like the list of cities from another drop down box to be displayed that are linked to that state in a mysql database. The purpose is to keep the list of cities to choose from small, they should not have to waid through a list which contains cities in other states.

Drop-down Menus
How can I create drop-down menus in PHP?

Drop Down List
I want to read a directory for available files and then get the filenames and put them in a drop down list. Whatever the user will select will be the value of the variable $selected. I already found the code to read directories: Code:

Selecting From A Drop Down Box
I have a drop down box populated with names of towns from my db (MySQL) all that is working fine. My problem is I do not know how I select a town in the box and have it take me to that web page on my site.

Drop Down Menu(add Cat)
I have DB to add category and forum to edit the terms that in the cat so I add this code in the edit forum to change the cat of the term by choose the cat from drop down menu
PHP Code:

How To Get Value From Drop Down Box To E-mail With Php
I have a form that includes a drop down box. I can get all of the other
values to show up in an e-mail except for the drop down box values. Can
someone please help? -- I know the HTML isn't the greatest. The website
was originally created in FrontPage and the form broke. I'm just trying
to help out and fix it for a friend.

sendmail.php ....

PHP And Drop Down Menus
I've looked through the forum rather extensively and my qestion is similiar to the question by Brian_F and answer by "saintaw" a couple of days ago in this forum. I already have a functional page that has several dynamic drop-down menus from which the user selects a topic of interest.

My question is how to reference their choice from the drop down menus in order to display the results of their choice. I would like the user to be able to choose a subcategory with one of the drop down menus and then be able to view the questions related to that subcategory.

I currently have a nested for loop which displays the categories and subsequent drop-down menus for each category, and I'm using PHP and MySQL to do the dirty work. code:

Drop Downs
trying to get dropdowns to appear and getting no where! I have a script with a config file that has a list of options. I have added a list of ages like so:

$age[0]= 18;
$age[1]= 19;
$age[2]= 20;

I now want to include these in a page in a drop down menu and have tried this code :

$ageshow .= "<option>$age</option>";
echo "<tr bgcolor =$bg2>";
echo "<td class="classadd1"><div class="maininputleft">Age:</div></td>";
echo "<td class="classadd2"><select name="in[sfield]">";
echo "$ageshow</select> ";
echo "</td>";
echo "</tr>";

this does not list the ages but just has array in the drop down. What am I doing wrong?

Php And Drop Down List
I am coding an email form on a site. A user enters their name and contact email and then selects from a drop down list to which particular email the message should be sent: User1, User2, User3. Then the user types out a message and hits submit. My problem is that I am unsure as to how to grab the selection in the drop down list and pull the selection and place it like this: "$selection@domain.com". Here is the php code:

Drop Down Menu
I have a page that uses php to look up specific fields in a specific table of a specific database based on the username. Using this, it creates a dropdown list of information belonging to that user. The fields in question each have 13 pieces of data. Based on what they click in the dropdown box, I need that specific data to pass onto hidden fields on the page. Code:

PHP-MySQL Drop-Down Box
I'm using PHP to dynamically make a drop down box of users in a table. The first row is displayed with all the users. However, on the second row non of the users are listed in the drop down box. It only works on the first.

Drop Down Menu
I'm struggling to get this to work. It is suppose to show only $name and not $name and $email PHP Code:

Drop Down Menu
I am implementing a website with dreamweaver. I dont know much about
programming but I can handle scripts and manupilate.

does anyone know a website that i can get a free drop down menu script
to use on the website's navigation?

Drop Down Menu
I have 2 drop down boxes on my site. I want the selection of the
first one to populate the second box.

Extended Drop Down
I've picked up some scripts from this forum regarding drop down lists (thanx!), and now I'm wondering if anyone can explain to me how to do the following:

Table:
+---+-----+
|ID |NAME |
+---+-----+
|1 |name1|
|2 |name2|
|3 |name3|
+---+-----+

I fetch values from NAME to a drop down list without problems. Then I want to select the corresponding ID (depending on which NAME-value I've selected) into a hidden(?) field to use later on in a submit.php page which is sent to another table in the db.

Extracting Value From A Drop Down Box
I am having problems extracting the values from a drop down box and based on the value obtained there are some operation done. Code:

Drop Down Menu
What i would like to do is look in a file and see what the name's of the files are in there and have them put in to a drop down menu. Dose some one know of a tutorial on this or how to do it?


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