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Dropdown Menu Without Submit Button


How do I get a dropdown menu to submit with the selection of an option rather than pushing the submit button.?




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Hello. I have a drop down list :
<select>
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The problem is once an item is selected  and the submit button is pressed, the dropdown refreshes and goes back to the first option which is 'Apple' in this case. I want the value picked to stay selected after the submit button is pressed.

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<form method="post" action="/picked.php?pick_num=".<php? $value ?
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<table width="100%">
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<INPUT TYPE='RADIO' NAME='pick_1' VALUE=&#391;'>Day;
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I was wondering if it is possible to use something like Javascript to make it so you don't have to click the submit button on a form to make it submit, while using php and mysql. e.g. Code:

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Dropdown Menu
i seem to be having some problems on finding how this ajax drop down menu i seen at Anime-Eden.com.

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I have a list of contacts which are sorted by name. I was hoping to create a dropdown menu in which someone can sort the list of contacts by office, city, state, and contact type. Is this possible? (I am sure it is, but I am not sure what the concept is called so I may research how to do it).

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I want to populate a dropdown menu with countries that are in one column of my table. I know how to do that, but I can't find how to eliminate multiple items. Some countries appear several times in different rows, but I only want each available country to be shown once in my dropdown list.

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what i am trying to do is to make a system with a few input pages and edit and read pages..

so right now i got the input/edit/read pages working. (yay) But now I want to have on 1 input page a dropdown menu that reads its information from the database. and that if i go to the page i can select a value out of the db and submit that inside my form and that it reminds the value if i view or edit the page.

So what i got now is a little system that is able to add/remove/edit a value inside a field called "drop01"

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with help from the PHP Gurus here, I have a dynamic menu script:

PHP Code:

<?php
$time = time() + 28800;
$time_plus2 = strtotime('+ 6 days');

echo '<select name="select">'
while ($time <= $time_plus2)
{
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}
echo '</select>'
?>

how do I now get the days of the week to link to different pages?

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Assigning A Dropdown Menu
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Values From DB Into A Dropdown Menu?
Here's my database which shows which type of cards have been issued to a football player in my database: Code:

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Populating Dropdown Menu From Db
Okay, I am trying to populate a drop down menu with items from a table in my db. I have a table called "teacher" which has the following info: I use the following code to grab the info from the teacher table. Code:

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2 Questions. Dropdown Menu And # Of Rows.
1. I have a table named pics and a column named name, just to let you know for use. I want to take the data from each row in the name column and insert it into a dropdown menu.

I know how I could do it, but I would have to go:

Code:
<SELECT NAME="name" SIZE="1">
<OPTION SELECTED><?php $name[10 ?>
<OPTION><?php $name[1] ?>
<OPTION><?php $name[2] ?>
<OPTION><?php $name[3] ?>
<OPTION><?php $name[4] ?>
<OPTION><?php $name[5] ?>
<OPTION><?php $name[6] ?>
</SELECT>
but then I could make too many or too less. I want it to automatically adjust to the number of rows.

2.What is the code needed to find out how many rows are in a table?

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Searching Database With Two Dropdown Menu
I have searched the whole forum for the script. Please let me know if there is any script .

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Unwanted URLs In URL Dropdown Menu
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http://www.somesite.com?username=john&password=12345 What I only want is:
http://www.somesite.com/

I know that Hotmail.com doesn't show all of the pages that have been visited, all it shows in the list is hotmail.com, so I think it is possible to do this, but I don't know how.

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Make A Dropdown-menu Filter?
I have a dropdown menu which is supposed to filter a table to show results for professionals, students or all. But I don't really know what I'm doing.  This is what I have so far. Code:

Initially, I was able to filter for students or professionals, but since trying to have an all option (students and professionals) it has gone to pot, and I keep getting errors.  I know that my quotation marks are not right, but I can't think of a solution. I would be more than happy to see any ideas, even if they are completely different to mine!

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i wanted to query my db, and then add values to drop down menu, where when they select what they want in the dropdown, it will bring them to another page accounts.php where they will have more options.

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Dropdown Menu <selected Name="...
I have a dropdown menu like this one:

<select name="country" tabindex="6" id="select_country">
<option value="">- Country List -</option>
<?php 
$query = "SELECT * FROM country ORDER BY country ASC";
$result = mysql_query($query) or die('Error, query failed');
while ($row = mysql_fetch_array ($result)) {
$country = $row['country']; ?>
<option value="<?php echo $country ?>"><?php echo $country ?></option>

After I have selected one country and I hit the submit button it go back to the default value in the box, what I want is to show the selected value in box until I selected another value.

If the default value is Australia when I start this page, I then select USA and hit the submit button it reset to the default value "Australia", but I want it to show USA as long I not select anything else. I have tried to use session in selected="<?php echo $_SESSION['country']; ?>" but it didnt work.

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Trying To Create Dropdown Menu From List
I am trying to create a dynamic dropdown select menu from a directory containing other directories and files. This is to select a certain page from the list so I can edit it. I only want the files in the menu. Here's what I have so far but it doesn't populate the dropdown. Code:

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Selecting Item In Dropdown Menu
Im having problems trying to select a specific option in the drop down menu which has been populated with a list pulled from the 'category' table in the db. The option that needs to be selected is pulled from an id in a 'item' table, relating to the aformentioned category table.

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Dynamic Dropdown Menu Glitch
I wrote this code to dynamically generate an array from files on my server and put it into a drop down menu, but the code cannot be inserted on any page anywhere without it cancelling the loading of the rest of the page. Any ideas? Here is the code: PHP Code:

<? $the_array = Array();
$handle = opendir('walrus/strips/.');
while (false !== ($file = readdir($handle))) {
   if ($file != "." && $file != "..") {
$file = substr($file, 0, -4);
$the_array[] = $file;
   }
}
closedir($handle);
asort ($the_array);
reset ($the_array);.....


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Network Bar, Dynamic, Dropdown Menu
Basically I have a "network bar" that I place on the top of all my sites, which has a dropdown menu box to interlink all my other sites. Basically I would like to really modify this idea out more. Code:

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Tree View Dropdown Menu
I have such a categories MySQL table: ID | name | parent and have such a function that displays the categories in a SELECT element as a drop-down menu:

function DD_ProjectCategories($parent=0) {
include("db.php");
$query = "SELECT ID,name FROM categories";
$result = mysql_query($query) or die(mysql_error());
echo '<select name="parentcategory">'
echo '<option value="">Choose a parent category</option>'
echo '<option value="0">Root Category</option>'
while ($row = mysql_fetch_array($result)) {
echo "<option value="$row[0]""; if ($parent == $row[0]) {echo " selected"; } echo ">$row[1]</option>";
}
echo "</select>";
unset($query,$result,$row);
}.....

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Im working on a script that has to be change so a user can choose from a dropdown menu instead of a list that now is displayed.
Here is the part that is insert on the index page.

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How To Pass The Value Of Selected Dropdown Menu To Another File?
there is a php-myql script that list the mysql databases in the drop-down menu, use wil select one and the submit button should pass the value or variable $db_name to the test.php, this script list the databases in the drop-down menu but when i select one and then click on submit cannot pass the db_name to the test.php:

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Stuck On Dropdown Menu List, Could Use Some Guidence
I have a form with some drop down list/menus. I do a check for ommissions and if found display a message to re-try. What I need is a way to show which options where chosen when the user submitted the form the first time.

If someone could show me how to do the first one, I'm sure it's the same process for the second one. Here's the code:

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Duplicates In A Dropdown Menu Populated From My Database
I've been searching to figure out how not to have duplicates in a dropdown menu populated from my database. This is what I have, but how do I change it to get rid of duplicates.

<?php
$result = mysql_query("SELECT City FROM residential order by City");
echo "<select MULTIPLE NAME="City_code">";
while($row = mysql_fetch_array($result)){

echo "<option name="City" value="$row[City]">$row[City]</option>";

}
?>
</select>

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Pagination And Dropdown Menu Used In Searching Mysql
I am working on building a database made for searching. I have a text search and a dropdown box used for searching different table collumns (lets people search for certan criteria). I have that working correctly.

I also only want to show 25 results per page. I have that working correctly. My problem is that when I combine the two it breaks the code. The pagination works fine without the dropdown and vice versa. I think it is due to the variable that is being used to choose the collumn in the sql query. Code:

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Submit A Form Without The Submit Button
Is there a way to submit a form without the submit button?  Do I have to use the javascript - document.formname.submit();

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How To Submit A Form Without A Submit Button
how i can submit a form without using a submit button, i have to use this in one of my ongoing project.

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I want to submit a form but without a submit button. That's to say, I want that by giving a definite code in a field and then press <ENTER> the form will be submitted.
For Example

<form name="search_form" method="post" action="search.php">
.....
....
Code: <input type="text" name="code" onKeyPress="if (event.keyCode ==
13) {document.search_form.submit()};">

....
....

How can I do it without a submit button?

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Is there a difference between a person clicking the submit button in a form or hitting the enter key to submit the form?

I have a form that gives a blank page when someone doesn't fill out the form and presses the enter key, but gives you an error code and redisplays the form if you click the submit button with your mouse.

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Populate Dropdown W/o Submit
Ive got some arrays; one array is most of the U.S states. the other arrays are names of clinics my company has within the selected state. I want to be able to select a state from a drop down and have another drop down next to it that will populate itself automatically.... without having to press a submit button.

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Choose From A Dropdown Menu Of Encryption/decryption Cyphers
I've written a php page which allows users to type in a text string and a key, then choose from a dropdown menu of encryption/decryption cyphers, and a method (encrypt, decrypt). The whole thing works, except the mcrypt command doesn't work. here is my mcrypt command:

if ($method == 0) {
//Encrypt
$output = mcrypt_ecb ($algorithm, $key, $input, MCRYPT_ENCRYPT);
} else {
//Decrypt
$output = mcrypt_ecb ($algorithm, $key, $input, MCRYPT_DECRYPT);
}

Here's a list of what the variables may be:

$algorithm = MCRYPT_3DES
$key = "plain text"
$input = "more plain text"

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Combining A Radio Button Search With A Dropdown
a. I have a form where a user has to select a company name to update.

b. Currently, i use a code where the first few alphabets of the company name are typed, a radio button used to selected one of the results that pop up and then another 2 scripts update the data.

c. Is it possible to select company name and update on the same form ? Code:

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Button Menu To Run Event
This code runs and plays a WAV file whenever someone loads my webcam page.  I would also like to add 3-4 Buttons that when clicked would run the code to different wav files. (IE WAVE1.WAV or WAVE2.WAV e.t.c.) What am I missing? Code:

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Submit Button - How To Submit One Form And Then The Form Data Goes To Other Sites
I'm trying to find a way how to submit one form and then the form data goes to other sites. Here is an Example below! I got Sites (Main),(A),(B)&(C) I want to fill in the form on site (main) and it sends to sites (A) (B) and (C).

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Submit The Drop Down Menu Info To Db?
What I have is a status(drop down menu) you should be able to select from drop down and it will update the status field in db. Code:

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Submit Button Bug?
I think I've find a very VERY strange bug with form submit buttons (only tested on IE 5.5.). I've got a form in which a password can be changed, which updates a record in MySQl.

If you click the submit button, the page works fine. If you press enter whilst the submit button is highlighted, it works fine. However, if you're inside the text field where you're changing the password and you then press enter, it tries to submit the form but doesn't do anything!

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The Submit Button?
I've just been looking a different ways to submit forms, however I find that all is not how it should be... In this incarnation, I have some php script that pulls information from a previous form so I can display it before submitting the data to a database, how ever if I do this: Code:

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All about two submit button. don't know how php manage this but asp does this: PHP Code:

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Submit Button
i want to have 3 submit fields,and a submit button,please tell me how to do this.my other question is how to connect this submit button info,to be written in a table in my Database.i have 3 fields in the table in my DB-"number", "comment" and |"date",if this could be of any help.

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I have a form with several buttons all named submit with difrent values. form action ="post" I should be able to get the selected button by  $a = $_REQUEST['submit']; but nothing. why?

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I have a submit button that when clicked will open a different page (at the same time passing some hidden values). The field value that will be pass to another page is retrieved from table and the value could be an HTML code. But instead of just storing the value to the field (and just display only the button), it display the HTML output.

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Submit Button HELP
I've been here 5 hours now. I have a flash web page.. the variable on every input text field is already set to the same name to which I included in the php server file. it sends email...and it directs me to the page index as I want it to. but why are my fields not being sent to me included in the email.. is there something Im forgetting. in flash 8. I have the button setup SEND USING POST..The text fields set up to 0 characters...and expressin is not checked... I tried adding characters to the text fields... but did not make a difference...also..i have a dummy page setup for now.
here it is.

http://www.mgmediaworks.com/process.html

<?
$to = $_REQUEST['to'] ;
$subject = $_REQUEST['subject'] ;
$body = $_REQUEST['body'] ;
mail( "sandro@mgmediaworks.com", "Feedback Form Results",
$message, "From: $email" );
header( "Location: http://www.mgmediaworks.com" );
?>

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Button Vs Submit
I'm working on a form which input type=submit --> it will work as I want to. (send data to db and go to another page) Here is a problem. I want to use the other button called 'back' to bring data back to previous page. In case the user needs to change the data before submitting. What should i use. I've alredy tried input type=button but it doesn't work. It does nothing.

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Submit Button In PHP
<input type="submit" value="Search"/ onclick="this.disabled='disabled'">

But it just greys out the button and does not process the form.  Also, is it possible to create a message under the button that says something like "Hang tight. this might take a minute."

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