PHP :: Dynamic Form Update

Update A Ststic HTML Form To Dynamic
I have a form which I now want to be more dynamic. The datbase tables are builtbut I cannot get the fields to populate.

When a member selects an age group from the first select statement and the dates that age group are scheduled to play a match are displayed in a second select statement. When both select ions have been made the rest of the form is displayed and can be filled in and the database updated. Code:

Ajax - Dynamic Update
I would like to request some data from a server using ajax (search
type of thing). Whilst the server is searching, I would like to
display the first results on the client side. Ideally as they come in.
What is the best way to go about such a search?...

Update Dynamic Checkboxes
I am creating a small e-mail system, where the user can create a various number of e-mailgroups and from another form the user can assign e-mailaddresses to the groups.

First I put the names of the groups into a MySQL table "emailgrouptable" - at the same time I alter another table "emailaddresstable" with the (new)names of the groups.

From the page where the user can add new addresses the names of the groups are presented dynamically based on the table "emailgrouptable" first I get the names of the groups and the total number of the groups. Code:

Dynamic Checkbox List - DB Update
I have a set of questions which are being dynamically output:

for($i=0; $i<count($question_array); $i++)
{echo $question_array[$i][question] .

"<input type='checkbox' name='question_" . $question_array[$i][id] . "' value='Y'' . "><br>";}

I then want to update each question in the DB. I want to loop through each question id and carry out the relevant action (either enable or disable). What is the best way to do this?? As I am dynamically generating the variable name (e.g. question_50) what is the best way to loop through these updating the relevant id?

Dynamic Update/insert Statement?
I'm hoping to build a dynamic sql statement for inserts and updates based on FORM values. I've done this in ASP but not sure about PHP syntax. Right now I just output the form entry results, but here's what I'm thinking for an update: PHP Code:

Dynamic Form Fields/multiple Page Form?
It is for a friends out of print booksite, where visitors can request multiple books to be searched by adding one at a time to a cart (javascript), then once all added they submit to another form where they enter their personal details and all is sent through. The problem is at the moment they cannot change whats in the cart without refreshing the browser window and losing everything.

1) present for asking how many books they want to search for
2) display multiple rows of the same input fields depending on how many books they say they want to have searched for?i.e

title|author|publisher|etc
title|author|publisher|etc
title|author|publisher|etc

3) when these are submitted they could see these above the next part of the form where they enter their details with the option to go back and delete/amend.
4) send all the info to my colleague.

if so has anyone seen a similar script that I could take a look @ to see if I can hack it to suit my needs?

Update From Form
The file below is supposed to bring up a form with the fields for a user inserted into it for editing. "edit.php?id=83" is an example of the link to it. When that link is clicked the page is empty and the is no code in the source view.

<?
include("dbinfo.inc.php");
mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="select from todo where id='".$_GET['id']."' LIMIT 1";
$result=mysql_query($query);
$num=mysql_numrows($result);
mysql_close();

$i=0;
while ($i < $num) {
$item=mysql_result($result,$i,"item");
$description=mysql_result($result,$i,"description");
$category=mysql_result($result,$i,"category");
$priority=mysql_result($result,$i,"priority");

?>

<form action="updated.php">
<input type="hidden" name="ud_id" value="<? echo "$id";?>">
Item: <input type="text" name="ud_item" value="<? echo "$item"?>"><br>
Description: <input type="text" name="ud_description" value="<? echo "$description"?>"><br>
Category: <input type="text" name="ud_category" value="<? echo "$category"?>"><br>
Priority: <input type="text" name="ud_priority" value="<? echo "$priority"?>"><br>
<input type="Submit" value="Update">
</form>

<?
++$i;
}
?>

Php Form And Update Sql
Im using a php user system from source forge and modifying it. I just want to test updating sql from a submit button. So say when button is clicked the new value either as a actual value or an addition like below can be passed to the database and then the value returned as a print or echo.

if ocassionaly managed to get the value to update (i checked the sql database) but it doest work at showing the updated value and now its completely broke.

Can anyone who understands what im trying to do either look over what ive got and correct or write a simple version of what I should be doing. Code:

Form Update
I have a form that sends data to mysql, and you get shown the submitted data. But i also want the users to be able to update their sent info, after thay see what they've sent, to make changes if something was incorrect. I want to make an update feature that will let them do that, but their is no user authentication on these pages, so i want to use php session. I don't know where to start.

I want the form data to be saved in the session, so when they go to the update page, their info is still there. I want the session to end after they update.

PHP Form Field Update...
I am sure this has been answered here somewhere, but I have searched for a good 2-3 hours and can't seem to locate a solution. Additionally, I really don't want anyone to solve this mystery for me (at least not all the way!) - But I was hoping someone could point me in the right direction here.

I am trying to figure out how to update form field information before the end user hits the submit button - for example, if they select that they are from California from the "state" drop down list, only counties from California would show up in the "county" drop down list. BTW, this is only a hypothetical example - I am only using this code to build a photo manager for my website!

Anyone able to:

1) tell me what this process is called - it's hard to search for answers when you don't know what you're looking for.

2) point me in the right direction of a solution.

Form -> Array -> Update
I have a form which lifts 20 items at a time out of a db table. Against each record I place a textbox for suggested changes, and the relevant line in the form is: PHP Code:

Update Database Using A Form
i would like to up date i have the following fields;

Prod_ID
Prod_Desc
Date_sent_in_house
Used_by_date
Supplier
Cases_sent
Cases_sold
Price_p

from a form i would like to enter new data into the database table., but unsure on how do do this can you help?

Can't Update Mysql Table Via Php Form
I have a form that updates an item pulled from a database, but after the form is posted, it does not update the mysql database with the new info, here's what I am using: Code:

How To Update MYSQL From Multi Row Form
I'm trying to update rows in MySQL using a dynamically generated form. PHP Code:

Update 2 MySQL Tables In One Form
I have a form with two fields in it. Each field updates its own table. I would like for the user to be able to enter data in either fields and the form update the appropriate tables. If one of the fields is empty then it doesn't update the table.

mcat - Updates mcatTable.mcatname
mtype - Updates mtypeTable.mtypename
PHP Code:

Form Fields To Update A Webpage
I am trying to build this mini "publishing" system and allows the user to use form fields to update a webpage (images and text) then press a button to email that webpage to a list of emails. (spamming own userbase). I will have a webpage with php code in it and the code will pull data from the db.

How can I save the file has a static html file so that I can pass it to my mail function? or can I directly pass the php page to the mail function? or what is the best way of doing this? I also have to learn how to do file upload with php aswell.

Update Page Content From A Form
I want to have a web page that uses variables from a text file as some of its content.
I want another page with a form that will allow me to updated/change the variables in the text file. I have no need to add variables using the form only change the values of existing variables.

Basically I want to make some content on one of my pages update-able using a form; not entire paragraphs just single words that I have laid out in a table. I have been told that I should just use something like mySQL for this. I do not know if it is necessary since I only want to do it to one page.

Update Form, Security Issue
I have to write secure update record php script, here are the complete
details of the website,

the website has a login system that authenticates the user, writes the
session ID for username and goes

on.

The user can post, read msg he can also update the msgs that he had
posted in the past once he is

loged in.

when user tries to update the msg, the script check MySql DB with

select * from Msg where username = session ID

suppose recorset returns msg number 1,3,5,7,9 with that perticular
username.
I pass the user to a page ...update.php?msg_id=1 and the user can
update the stuff.

Everything is working fine,

Problem

what if the user changes the url to ...update.php?msg_id=2

he can still update the record, what to do he has not posted msg id 2.
what sort of method or code

should i use to restrict him to the msg that he posted

If you feel that i am using a bad method or my database structure
should have a new field please let me

know coz I can still make changes in DB structure as well as my
scripts we are in the somewhat initial

stage of the development of the product.

Displaying Information In A Update Form
I can display the information in a table. But now I need to display it in a form, so I can edit it and then upload it to the database. I have the form from my upload page, But I can not seem to get the information to appear back in it. Code:

Dynamically Generated Form And Update Problems
In brief, in the following 2 portions of code I build a form based on data retrieved from a database. The second bit of code receives the posted data for processing and updating the database. Problem is that the update occurs for the first row of data but none of
the rest. I'm using a hidden field, written in dynamically (
name="tfHiddenId<?php echo $j ?>" ) where $j is a counter var in a loop.

When I print out the POST_VARS everything is as I want to be, fields all
named according ly, as above. Just the update either 1) only does one
row and quits or 2) updates same row with the same data over and over ( I
suspect the latter ). Apparently my counter variable is not being incremented, but only on one var, "tfHiddenId".$i , on the receiving page. Here's the code for where the form is built from the DB: PHP Code:

Form Data Array - Need To Update Table
I have a form that is dynamically generated by the fields I have in a table. This table generates the navigation for my site, and I want to create a page that will allow me to reorder and hide/show and activate/deactivate the links. The form is working and I have the form generating an array based on the data collected on submit. I need to know how to break this data apart so I can update my site navigation table with the correct values. The table looks like this:

Dynamic Form
I have one user table in my MySQL database and this is linked to a user type table containing 3 types of user. Each type of user will be required to give a different amount of data when registering.

Basically I want to create one registration form for all types of users but only show the form fields that are relevant to the individual user type. The user type will be selected from a pervious page containing a list menu with the 3 user types that is sent via GET to the registration page.

Dynamic Form
I need to create a form that takes a number that the user enters, and
duplicates a question the number of times the user entered. For
instance, if the customer enters 5 on the first page, when they press
next the form generates "How old are you?" 5 times on the page. The
customer will answer all 5 questions then press next. Finally, all the
local variables get dynamically created and written to a database.

I have already taken care of dynamically creating the question five
times. Using a simple WHILE clause, this generates the correct number
of questions. What I am having an issue with at this point, is how to
dynamically create the local variables.For instance, for the question
"How old are you?" I would need a unique variable for each instance;
using something like $Age(n). So that for five times, it would
automatically created variables $Age1 through $Age5. I have carried
over the number to the submit page by creating the variable $Number
and passing it along as hidden button on the form. $Age'$Number'
seemed to work for creating the variable, but $_post["Age'$Number'"]
doesn't work for referencing the global variable. I would need some
way of looping through and dynamically creating the variables.

Dynamic Form
I had to make a form for someone, with 42 questions each question had different form-elements. I was typing and coding for almost 3 hours..!! lets say we would make a form (formmaker.php) to dynamicly create a form with multiple questions: on the formmaker :

-first we have to enter the number of questions (max 100)
-then we have to type the question(s) in (an) input field(s)
-then we would have to select a type of answering field (textbox, checkbox, radiobuttons, file, dropdown etc. )

-it would be nice if we could select to make the question mandatory or not.
-if we choose for checkboxes or radiobuttons , it would be nice to know how much of them (no limits here !) ok..limit it to 30

-when we have selected...for example..15 checkboxes, they have to dynamicly appear on the formmaker.
-for each checkbox or radiobutton, we have to enter a value.
-finaly we have to add an email adres to each question !!! (and a BCC field) (this way, we can use one form and split and send the data to multiple recipients..!!)

-also we have to be able to dissable or enable a question. (if dissabled, it wont show on the created form..

A nice template to show a filled in form is preferable.. It would be nice to store everything in a database tabel. (for each new form a new tabel in the database) question1 id active(yes/no) questiontext fieldtype mandatory(yes/no) radio_or_checkboxvalue1(rocv1) rocv2 rocv3 rocv4 rocv5 etc.... sendto_email bcc_email
I started with the code already...here it is: Code:

Dynamic Form Value Modification
I was wondering if and then how to dynamically update form variables without having move between webpages

I am developing a print quoting system for a company and I want the options in list boxes to adapt based on the values of previous selection in the form. However it must happen immediatly without the whole page having to refresh.

For example if a person chooses paper size to be A4 then the next drop down list must only have options available for A4 pages.

I thought I would need to use Javascript for this but I can't find out how to access the server side mysql database so I get the feeling Javascript is the wrong option.

The whole site is programmed in php but php is server side so I don't don't think its possible using php specifically.

Dynamic Form Selects
How do you make dynamic for selects in php? It is in regards to a modify type scripts im writing in php/mysql.

So regular select drop downs look like so:

<select name=genericselect>
<option value="1" selected>1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>

right, well if I was pulling info from a database, how would I make is so that the 'selected' value is dynamic and comes from the database? Im sure theres a simple way of doing this.

Getting Info Out Of Dynamic Form
I am using the following code to produce a dynamic form.

$result = mysql_query("SELECT id,weight,date FROM weekly_data WHERE
weight IS NULL AND subscr_id = '$toss' AND date <= now()");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
print"<table width=ï`%' id='catchup' border=Ɔ' cellspacing=Ɔ'
cellpadding=Ɔ'>";
print "<form name='form1' id='form1' method='post'
action='catchupprocess.php'>";
print"<tr>";
print"<td></td>";
print"<td>Weight</td>";
print"<td>Date</td>";
print"<td>Waist</td>";
print"<td>Measure</td>";
print"<td></td>";
print"</tr>";
while ($row = mysql_fetch_array ($result)){
//echo $result;
print"<tr>";
print"<td>";
print"<input name='".$row['id']."' size=Ɗ' type='text'
value='".$row['id']."'/>";
print"</td><td>";
print"<input type='text' size=ƌ' name='weight".$row['id']."'
value=''/>";
print"</td><td>";
print"<input type='text' size=ཆ' value='".$row['date']."'/>";
print"</td><td>";
print"<input type='text' size=Ɖ' name='waist".$row['id']."'
value=''/>";
print"</td><td>";
print"<input type='text' size=ƌ' value='$measure'/>";
print"</td><td>";
print"<input type='hidden' size=ཆ' value=''/>";
print"</td>";
print"</tr>";
}
print"<tr>";
print"<td> </td>";
print"<td><input name='Reset' type='reset' value='Reset'></td>";
print"<td> </td>";
print"<td><input name='submitcatchup' type='submit'
value='Submit'></td>";
print"<td> </td>";
print"</tr>";
print"</form>";
print"</table>";
?>

Form With Dynamic Questions
I've a mysql table where i stored a list of questions. My php script
executes a query which yields a different number of questions every time; i
used the loop function to create an input field for each question in the
form; and dynamically referencing each input name with the question number
i.e. question 1 is called q1, question 2 named q2, and so on.
The data is submitted using POST. I then try to retrieve all the answers by
doing a loop and using something like echo '$_POST['q'.$n.'']' except the
syntax doesnt seem to work.

Dynamic Form Items
I am trying to create A form that its fields will depend on a
form menu.
for example.
/***********************************************/
<form name="form1" method="post" action="">
<select name="select">
<option value="1">option 1</option>
<option value="2">option 2</option>
<option value="3">option 3</option>
</select>

Text field 1<input type="text" name="textfield">
Text Field 2<input type="text" name="textfield2">
Text Field 3 <input type="text" name="textfield3">
Text Field 4 <input type="text" name="textfield4">

<input type="submit" name="Submit" value="Submit">
</form>
/***********************************************/
When the option 1 is selected only the textfields 1 and 2 to appear,
when option 2 is selected only textfields 1 and 3 to appear and so on... any
combination I would like.

I tried puting the textfields in "if" statments but i don't like it. its too
messy PHP and HTML code.
Any Ideas of how this could be done better ? If someone did something
similar before and has a relative link it would be good as well.

Dynamic Form Pulldown
I'm building a form and need to have the options in a pulldown menu pulled from a mysql database, i understand the basics of sql and have used forms before, i just need to see an example to get me on my way.

Dynamic Form Processing
Im writing a script for processing a form created by a csv file. this form is created through a loop, where $num is the place in the loop. Code:

Dynamic Form Fields
I want to have it setup so when the user clicks this link a value is sent via get and that value is put through a for loop to generate an additional form field: Code:

Dynamic Form And $_REQUEST
My current project needs to run on both windows and linux. I figured out that windows needs $_REQUEST to read the form elements. This worked well until parsing a dynamically built form with checkboxes named: cb0, cb1, cb2, etc.

I can't figure out how I can use $_REQUEST to read the form elements, when I try $_REQUEST[$i] for example all values of the array elements are 'cc'. No idea where this comes from as cc is never used as a value?

Need To Update Multiple Mysql Records With A Single Form Submit
I have a wish list like a shoping caty based on a mysql databse where i retrieve records with php I need to update the quantity which is in a text fields :

input type = text name = quantity[] value = $quantity
input type = checkbor value = $id name = id[]

I need to update quantities based on the primary id represented with id with a single submit.

Form Field Dynamic Population And PHP
I have a form that dynamically generates a drop down from a table column called suppliers.

Products supplied by each supplier vary so what I want to try and achieve is that once a supplier has been selected a second drop down on the same page is populated with data from the same table / different column with that suppliers products.
(I am trying to avoid refreshing the page)

I have not supplied any code at this stage as I am not sure whether PHP is capable of doing this by itself or whether javascript would need to be incorporated.

POST Form To Dynamic Page Name
I've got a simple form with an HTML OPTION block. I'd like to POST the
form to a page whose name is based on the OPTION they select.

So for example say the user selected this option, I'd like to POST the
form to a page named "memory.php".

echo "<option value="memory">Memory Utilization</option>";

Reset Dynamic Search Form
i have a search form that has a set of checkboxes and a set of select boxes. the checkboxes correspond to a select box and activates the select box once checked. when i submit the search form to display the results on the same page, the elements are echoed back into the form so the user can see what search criteria he/she search for: Code:

Identifying Dynamic Form Fields
User goes to page which is a form that asks for some basic info regarding returning products for credit/exchange, and also asks for how many products are going to be returned. Upon submitting, a return authorization form is presented to them with the specified number of product fields. I now want to take the input from this form and email it to myself, as well as, display a confirmation page to the user. The problem I have is a can't say, for instance, echo "$field_name"; because field_name will get created dynamically after the user specifies how many products to return. For example, say the user says 5 products, this will generate a form with field names like:

return_code0 inv_num0 qty0 product0 cre_exch0 stockout0
return_code1 inv_num1 qty1 product1 cre_exch1 stockout1
return_code2 inv_num2 qty2 product2 cre_exch2 stockout2 and so on....

These get created with a for() loop. Once this form is submitted, how can I address the field names? Code:

Dynamic JS Form And $_POST Array
I have a form that I am altering after page load with javascript. Basically I have a button that inserts another text field into the form which the user can fill out. Its for a calendar, and I'm allowing them to optionally add multiple days for an event. Each box that is created has the same name with [] on the end to make it an array.

When I view the post array with print_r($_POST), only the first textbox's value shows up. This is the only textbox in the form when the page loads.
Simplified example:

<form name="calform" action="process.php" method="post">
<input name="startday[]" type="text" class="bordered" size="25" />
<input type="button" onclick="add_one_more()" value="Add another date" />

// if the user hits the add button it adds this input field after pageload

<input name="startday[]" type="text" class="bordered" size="25" />

</form>
And here's what I'd get from that form

Array
(
[startday] => Array
(
[0] => test1
))

A button inside the form basically adds another <input> tag between the <form> tags. Why isn't PHP seeing the data?

Dynamic Form Option List
I want to create a dynamic drop down option list in a form, but I just can't wrap my head around this.

Both of the below scripts work as intended, but how do I make the mySql query results work with my existing script? Yes, I know I must replace the "$options = array" part in the top piece of code, but I need a little more guidance than that. Code:

Dynamic Form - How To Set Values Of A List
I have a form with a list/menu in it that is populated with records from a database. The items in list#2 are based upon what is selected in list#1.

I have been able to use a combination of php and javascript to get it to work, but the javascript reloads the page to get list #2 to refresh - and that clears out any other fields that have been filled in. Instead of javascript being called for the 'onchange' event for list #1, I'd rather it call php when list#1 is changed and so reset the values in list#2.

OPTIONS:
1. I thought I could have a php function that is called (i.e. onchange="<?php reload();?>" but I can't figure out how to set the values of the list from within the php function. How to reference form objects with php?

How To Update Form Input Field Background Colour On Validation Error
I have been searching for form validation scripts for ages and all th ones that I like are far too complicated and inflexible so I decided to stick with my own which is easier to understand.

The only thing I don't like which i have seen on better form validation scripts is that and fields with errors are highlighted. i can only presume that they have used php to set the background color of the input field or textarea.

How would I add some code to change the background colour of form elements if an error is found? Here is my code which validates the form but doesn't change form elements colours. Code:

How To Process Dynamic Form Field Names
Let me start by saying I don't have a lot of PHP experience, and am just starting to fumble my way around some of this stuff... I'm sure this has been asked a number of times, but after 2 days of searching the internet, I just haven't found a solution that makes sense, so I am hoping someone here can help me.

I have a pretty simple project schedule sort of web page that lists a number of tasks & 4 dates associated with each task. (planned start, planned complete, actual start, actual complete.

The page is built dynamically based on what is in a mysql database, and the dates listed are form fields, with the intent that a person with access can change any number of these dates.

Each task has an id associated with it, so when i build the form, I name the form field <task_id>-<date type>. so, for example, for task id = 10 I have 4 related form fields:

10-planned_start
10-planned_complete
10-actual_start
10-actual_complete

This basic pattern is repeated for all the tasks (up to 100 right now, but it could grow slightly).

Once all the form fields have been updated, and the user clicks submit I want to update the data in the database with the appropriate data.

So, my questions is:

1) How can I process this form, when I don't know what the names of the fields are going to be, and/or how many fields there are?

2) Is there a good way to identify only those fields that have changed and do updates on only those fields, or am I "stuck" updating all the records, even those where the dates have not changed from when the form was built?

How To Get A Dynamic Javacript Form Variables Seperated In PHP
PROBLEM: I have this form that allows the user to dynamically create
additional fields (see javascript code bellow). I am trying to retrieve
the values entered into these fields from my php script. I ultimatly
need to pick out the variables and place the values into my php script
page. I have worked with a little code I found on php.net (see php code
below), but I wan unable to grasp the knowledge on how to seperate the
variables in the address bar. Please reply.

QUESTION: How do I create variables in my php script from my dynamic
javascript form?

PHP CODE:
foreach($_GET as $name => $value) {
print "$name : $value<br>";
}

JAVASCRIPT CODE:
<HEAD>
<!-- Begin
function createForm(number) {
data = "";
inter = "'";
if (number < 16 && number > -1) {
for (i=1; i <= number; i++) {
if (i < 10) spaces=" ";
else spaces=" ";
data = data + "URL " + i + " :" + spaces
+ "<input type='text' size=10 name=" + inter
+ "url" + i + inter + "'><br>";
}
if (document.layers) {
document.layers.cust.document.write(data);
document.layers.cust.document.close();
}
else {
if (document.all) {
cust.innerHTML = data;
}
}
}
else {
window.alert("Please select up to 15 entries.");
}
}

Dynamic Form Option Diapearing On Submit
when i submit one option field after inserting a option value and an amount the previous one i had done disappears causing me lose all the information that i had typed in and i was wondering how i could keep the information alive as well as keep the newly created form fields from diapearing, PHP Code:

Dynamic Fill Form Fields Depending On Dropdown Box
This question has probably already been asked, but let me ask again

I have a mysql database to which I connect with my php scripts. The
database contains articles. Name, Unit_Price and Reference

Now my client needs to order 5 items, click a button and a table with 5
lines and 3 columns appears (until now easy)

In the first column is a drop down box with a <select > and <options> in
which I store all possible names.

I would like than whenever the client changes one of the boxes (in my
case there are 5) the Unite_Price column and Reference column in the
line he just choose get automatically updated

Have To "actions" Or Run Two Types Of Queries (select,and Update) On The Same Form?
I had a brilliant idea on one of my pages that selects some data from
my mysql database.
I first set the page up to display some info and an image, just one
item, with a row of data, etc.

then I thought it would be nice to do a select, and perhaps an update
(the title of the image) on the same page.

I am wondering if I am having the wrong idea. I have a form, with two
submit buttons, one selects an image, and some info. the other will
update the image title for the given image (id, and p).
I am seeing that I have a mistake here, since it seems the update
query will run as well as when the select query is run (select button
clicked). this overwrites my image titles in the db.

I have the wrong idea, but have not seen how to do this "right". I
could use another php page for update, but I am guessing this can be
done from the same page.

Below is my poor code - i am not an expert programmer!!! any help,
suggestions will be helpful.

<?php

$img = $_REQUEST["img"];
$p = $_REQUEST["p"];

echo '<div class="input">'."".'</div>'
//connection files for mysql
@include 'c:/php/includes/db.inc'
@include 'c:/php/includes/error.inc'
//***@include '/usr/local/php/include/db.inc'
//***@include '/usr/local/php/include/error.inc'
//@require_once '/usr/local/php/include/size_image.php'

Dynamic Dropdown And Hardcode Dropdown In Select Form
I have plenty of examples of dynamic dropdown choices but none of hardcoded dropdown choices. The ultimate goal is to have a job with various tasks and to track the status of those tasks for a given job. I've used one of the tutorials here to begin the process. Below is the code I have to add work on a given task. Perhaps I actually need to "Update" a job as opposed to "add".

But the problem of the moment is I can't seem to hardcode one set of my options. This is the code I have: PHP Code: