Dynamic Dropdown List Using Access
I am creating a dropdown list that is populated from an Access DB: Code:
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Microsoft Access Dropdown List
l am building a new site using PHP which has a lot of pages pulling from an Access Database. I would like to have a dropdown list that pulls exhibitions from the database and then when the user selects one it shows the rest of the details from DB just below the dropdown list, hope that makes sense. Code:
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Dynamic Dropdown And Hardcode Dropdown In Select Form
I have plenty of examples of dynamic dropdown choices but none of hardcoded dropdown choices. The ultimate goal is to have a job with various tasks and to track the status of those tasks for a given job. I've used one of the tutorials here to begin the process. Below is the code I have to add work on a given task. Perhaps I actually need to "Update" a job as opposed to "add". But the problem of the moment is I can't seem to hardcode one set of my options. This is the code I have: PHP Code:
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I have a Dropdown list with Select with 1, 2, 3, 4, after select on of them it bust to refresh the page to what you select but it don't do it. PHP Code:
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I am able to populate data in a dropdown list box using php and mysql. However, I a wondering if i can add inside some icons such as close or More records, where the drop down acts to the specified request, ie., closing the drop down or fetching some more data from backend.
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Dynamic Dropdown?
I am posting a code for dynamic dropdown by Leon Atkinson, it works fine but i have a doubt: I tried to add another functionality to it where i got stuck! Once the city also gets selected from the second drop down i wanted that on clicking the submit button it should go to some html page wrt to the city choice. Code:
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Dynamic Dropdown Box
im looking to have two drop down boxs one with makes of car and the second drop down box to automatically populate with all the model of that particular make of car. there are about 50 makes and upto 50 models per make. I just would like to know the best way to do this - javascript or use a database? it would be a lot of code todo it in javascript wouldnt it?
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Dynamic Dropdown
This may be rudimentary but I'm just trying to get my head around this without having to write a billion lines of extraneous code. I have a dropdown selection list, populated from a mySQL database, containing times in a HH:MM:SS format. The times are 30 minutes interval spanning an entire day, as in 01:00:00, 01:30:00, 02:00:00 all the way to 24:00. I have it entering fine into the database, but when I want to edit this time, I'd like to have the value in the database be marked as the CHECKED value on the dropdown so I don't have to manually re-enter the time for every edit.
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Populating Dropdown List
I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:
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Smarter Way Of Doing Dropdown List?
I've got a dropdown list that is acting as a filter on a table, so the user can select a value and the page is reloaded only showing the matching values from the database. Now when the page reloads the dropdown was set to 'all' as it was first in the list, even if I'd selected a different value, this was confusing for users, so I added an initial <option> field which pulled the correct value from $_GET (code below) - however this is a little odd as it means the value appears twice! Does anyone have a genius solution to this? I've seen a <select selected="yes"> sort of thing around, but I don't know how I can tell the php to add this value dynamically? <select size='1' name='occupation'> <option>".$_GET['occupation']."</option> <option value='All'>All</option> <option value='Student'>Students</a></option> <option value='Professional'>Professional</option> <option value='Hobbyist'>Hobbyists</option> </select>
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Mysql Dropdown List
Im trying to automatically fill a dropdown list with data from MYSQL table. Sizes Table -------- ProductId | size1 | size2 | size3 | size4 | size4 | size6 | * the 'size' rows hold a numeric value for the quantity I have of each I was hoping to only list the sizes that have a greater number than 0. I have used an auto fill select code on another project but I'm just not sure how to fill in the blanks. Code:
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Check The Dropdown List
i have a drop down list in my php code. i need to check the drop down list is set or not. for that what is the code. i heard that there is no php code for that. javascript is needed. my code is here. PHP Code: <?php $database="sms";                    /* DB name       */ $host="localhost"; $user="root";                        /* Set DB Username */ $pass="";                            /* Set DB password*/ mysql_pconnect($host,$user,$pass);  /* DB connect....*/ mysql_connect ($host,$user,$pass); mysql_select_db($database) or die( "Unable to select database"); /*DB Select*/ function orgresult() .......
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Add Variables To Dropdown List
I have a list of variables: $variable[0] $variable[1] $variable[2] The amount of variables changes so i've used $total = count($variable) to find the amount there are. How would i tell php to create a dropdown menu with the amount of options=$total and then fill the options with $variable[0] etc. I know i can use a loop to increase the value of say $i by one each time to that i can use $variable[$i] each time, i'm just stuck with adding the whole thing to a dropdown menu with the right number of option...
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Dynamic Dropdown Lists
I am recoding a greeting card website. I am using dropdowns as filters for items in a DB, so when the user picks "animals" from the "theme" dropdown, the returned cards all feature animals, and when the user picks "birthday" from the "message" option, the returned cards all feature birthday cards. However, there are some combinations that don't return any results, for example "get well" "floral" cards. Code:
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Dynamic Dropdown Menu
with help from the PHP Gurus here, I have a dynamic menu script: PHP Code: <?php $time = time() + 28800; $time_plus2 = strtotime('+ 6 days'); echo '<select name="select">' while ($time <= $time_plus2) { Â Â Â Â echo '<option value=>' . date('l, F d', $time) . '</option>' Â Â Â Â $time = strtotime(date('Y-m-d', $time) . ' + 1 day'); } echo '</select>' ?> how do I now get the days of the week to link to different pages?
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Dynamic Content Using Dropdown
I have the following dropdown menu which is populated by content or categories (with catID being the category ID) from the database. What I want to do though is when an item in the drop down list is selected, I want to show dynamic content under it. BTW, I must not emphasize on "dynamic" too much because it may seem like a DHTML thing going on here. For example, if a user selects a certain item/category in the list, I want content such as coupons in the DB which have the same catID as the category selected showing up. The coupons are discreetly placed in the DB table "coupons" with the category ID being catID and...for eg: catID --- couponname --- couponinfo --- expiredate If you are going to include any kind of javascript, please write them as well. Here is the code I am starting off with: =========================== <form name="myform"> <select name="selectID" size=10 > <? $resultcat = mysql_query("SELECT * FROM Category"); while ($myrow2 = mysql_fetch_array($resultcat)) {?><?printf("<option value=%s>%s</option>", $myrow2["catID"],$myrow2["name"]); } ?></select></form>
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Three Dynamic Dropdown Boxes
Can any one help me in dynamic drop down creating? I have three dropdowns One for Country one for state and one for location. My plan is to select the country from dropdown according to this i have load the values in state drop down from MySql table. Depending on the state i have to select the location too.
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Trying To Create Dropdown Menu From List
I am trying to create a dynamic dropdown select menu from a directory containing other directories and files. This is to select a certain page from the list so I can edit it. I only want the files in the menu. Here's what I have so far but it doesn't populate the dropdown. Code:
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Dropdown List Selected By Default?
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Dropdown List - Insert Into Mysql
I simply want to add a dropdown list where, when an option is selected, its value will be inserted into a dbase table. More specifically, asume there is a page where the user sees his order. He will be able to select the order status (pending or delivered). So, for example, if his ordered is deleivered, by selecting "delivered" option, "delivered" will be inserted into the 'Status' column. Code:
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Dynamic Dropdown Menu Glitch
I wrote this code to dynamically generate an array from files on my server and put it into a drop down menu, but the code cannot be inserted on any page anywhere without it cancelling the loading of the rest of the page. Any ideas? Here is the code: PHP Code: <? $the_array = Array(); $handle = opendir('walrus/strips/.'); while (false !== ($file = readdir($handle))) { Â Â Â if ($file != "." && $file != "..") { $file = substr($file, 0, -4); $the_array[] = $file; Â Â Â } } closedir($handle); asort ($the_array); reset ($the_array);.....
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Network Bar, Dynamic, Dropdown Menu
Basically I have a "network bar" that I place on the top of all my sites, which has a dropdown menu box to interlink all my other sites. Basically I would like to really modify this idea out more. Code:
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Auto Fill Dropdown List Error
Im using the code below to autofill a dropdown list from my MYSQL DB. The only problem is it is leaving out the first entry (alphabetically) for each $vehicle_make ? Does anyone know why this may be hapenning? Code:
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Stuck On Dropdown Menu List, Could Use Some Guidence
I have a form with some drop down list/menus. I do a check for ommissions and if found display a message to re-try. What I need is a way to show which options where chosen when the user submitted the form the first time. If someone could show me how to do the first one, I'm sure it's the same process for the second one. Here's the code:
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I have a page that uses php to look up specific fields in a specific table of a specific database based on the username. Using this, it creates a dropdown list of information belonging to that user. The fields in question each have 13 pieces of data. Based on what they click in the dropdown box, I need that specific data to pass onto hidden fields on the page. Code:
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I am tying to write a statement that will compare the values of 2 columns, and display the result in a temp table. ex. Table A has the following columns: "Minimum" and "Maximum." The temp table will hold the reult of the difference between the 2 columns of table A. Scope: I am trying to crate a drop down with the resulting data as it is incremented. If Min = 2 and Max = 7, the TEMP tab;e should get the results of 2,3,4,5,6,7. I want to have this result displayed in a drop-down list.
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Sub Headings In A Dynamic List
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Dynamic Select List
I am wanting a dynamic select list which is populated from my DB. My query is: $query = "SELECT pk, type FROM un_styles"; I want to display the type in the select list, then use the selected type. So what i am basically asking is could someone show me the code to do this please.
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Dynamic List Content
i'm making a hierarchical Order list for this i've created database where parameter_cd,parameter_desc,upper_parameter_cd my page is like this Code:
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