PHP :: File Of The Week?

Getting Day Of Week Out Of Datestamp
I currently have a datestamp in the format yyyymmdd. I want to pull the day of the week (Monday, Tuesday, etc...) out of that datestamp at any given time.

Currently my code looks like this:
$datearray = getdate($firstdatestamp);
echo $datearray["weekday"];
When $firstdatestamp = 20000501 (or the first of May, 2000) the weekday returned is Thursday when really it should be Monday!

I tried:
echo date("l", time());
and it gives me the right weekday but only for the current date. I need to pass this my datestamp and am not too sure how.

Getting Day Of The Week From A Date
I tried searching the old postings, but to no avail. I am trying to figure out a way to get the day of the week from a date. Basically, I have a date in the format of 05/02/2003 (but I can change that format easily) and I need to have my program figure out which day of the week that was. All of the dates that I have will have already passed.

Date Of The Week
Can anyone help me? I am trying to work out the timestamp for the first DATE (not day) of the current week and last date of the current week. Any ideas?

Date To Week # Fct
I'm searching a PHP function that would translate a date in the following
format yyyymmdd to the week number in the year...
ex : 20040128 => 5
i.e. jan 28th 2004 gives week nb 5 in 2004.

Week Of Year
Is there a function which returns the week of the year, given a specific date?

Getting SQL Rows For A Week
I have a database that uses two date fields for tracking information. The first field is for the addition of the record and the second is for the expiration.

I have a small section that I want to list records that will expire in the current week (or for that matter in the next 7 or 14 days). What is the syntax that I would use to call mySQL with to get that info.

Week Of The Month
I need to determine the week of the month (1-5) so I can rotate menus for a cafeteria.
Is the following, which I know prints the week rather than storing it, the simplest or easiest way to determine the week? PHP Code:

Printing Every Week
im trying to print a list of every Friday since a date defined. Let me try and explain. I want to define a date such as 2007-07-06 (which is a Friday) and then let php print each Friday since that date until today. For example, if the date defined was 2007-07-06 then it would print

2007-07-06
2007-07-13
2007-07-20
2007-07-27
2007-08-03
2007-09-14

But I want to also be able to format the date it outputs, so it might look like

Friday 06 July 2007
Friday 13 July 2007
Friday 20 July 2007
and so on.

Week Before Date
Im looking to get the date 7 days ago. I know how to do 7 days ahead:

$timeStamp = strtotime($oLastBatchDate->Last);
$timeStamp += 24 * 60 * 60 * 7;
$NextBatchDate = date("Y-m-d H:i:s", $timeStamp);

However, does anyone know how to do 7 days back?

Date And Week
I am looking for a way to determine the week of the year if i have a date.i know that
date("W"); give me the week Number but not sure how to determine the week based on the date.

Day Of The Week Program
I am trying to write a program that will give me the day of the week without using the date function. I input the date and it's supposed to spit out the name of the day of the week. Here is what I have so far. I don't know quite what to do next. Code:

Date Of The First Day From A Given Week Number
I need some help to figure out the date of the first day in a given week number. Let's say that I pick week number 23, I want to retrive the day of that monday in week 23..

I've been searching the net for days without any result.

Datetime Within Past Week
I have a series of records in a database. When each record is stored,
the datetime is logged: $date = date("Y-m-d H:i:s");

Prior to adding a new record to the database, I want to run a query to
retrieve all of the records uploaded in the last 7 days. I thought it
would be easiest to:

Pseudo Code:
$newDate = $date - 7 days;
select * from TABLE where DATE $newDate;

Problem is I can't figure out how to subtract 7 days from $date and
convert that value to a valid datetime object.

Current Week Number
how I can split the month out into 5 weeks... then to have the week number printed and when the current week ends it will increment to the next week number. For example today is 3rd of July, therefore we are in week 1 of the month. Next week will be week two. I want it to go back to 1 at the start of the next month though.

Date Out Of Week Number?
I would need to get a date out of a week number, for example for week 52 the first date, 25/12. In my system the user inputs a week number, and then I would like to display a popup list of all seven dates for that week, for her to choose from. Is there a handy function to do this, or can you think of any way to achieve this?

Handling Week Number
I have been reviewing some calenders classes and have notice that if u
uses us written class with displays week number it ll by wrong for eu.
so to my question
how do you handle week numeration depenting on country? is there any
simple solutions for this?

Mysql WEEK() Function
In mysql WEEK() function it specify the number of week of a specific
date. For example January 02, 2006 will return a value of 2. Now my
problem is how could i be able to determine the range of that value in
a week like a value of 2 will be equal to January 1, 2006 - January 7,
2006.

309833 Web Views Last Week
This number seems about 30 times higher than normal for this group.

The group usually sees 10 times less traffic than the CakePHP group.

Month From Week Number?
Has anybody here ever made or seen a function which when passed year and week number in that year returns month ?

actually what I want is all records from db starting from six months back till now and group them by weeks, and some weeks may have no record so they won't appear in resultset. But I have to display zero against these weeks.

display has to be in form of Number of Records in Week # x of Month y e.g Number of Records in Week 2 x of Month Jan So my solution is to get records from db by this query:
.. where abs(Week(Now()) - Week(RecTime)) <= 26

this works ok but I don't have any idea of which month and week of month was 6 months ago.
So I decided to get week number and year of 6 months back and then write my function get month form this info.

How To Calculate The Day Of The Week By A Given Date.
I'm currently working on a (simple) calendar system which allows registered users to add an event to the calendar. The table EVENT stores info about the author, date and description of the event.

I then managed to output a list in which only events of this year are showed and are grouped together by months. And now I only need one more thing to complete the script. I want to output for every event on which day of the week it occurs (monday - sunday). I've looked around for tutorials but haven't found a basic one.

Date Function For Week Before
Im looking to get the date of a week before a certain date For example:

$iLastDate = date("Y-m-d H:i:s ");
      $timeStamp = strtotime($iLastDate);
      $timeStamp + = 24 * 60 * 60 * 7;
      $NextBatchDate = date("Y-m-d H:i:s", $timeStamp);

This is for a week ahead, how do I do a week before?

Week Ending Dates
When a user logs on, he should have a drop down selection box of week ending dates that would include any week ending dates that he hasn’t completed time for, only going back as far to a specified date and then also the current week he is within and up to 1 week forward. The week ending dates should always be on a Sunday. The table I have is as follows;

CREATE TABLE `techs_pay_weeks` (
`tech_pay_week_id` int(11) NOT NULL auto_increment,
`tech_pay_week_ending_date` date NOT NULL default '0000-00-00',
`tech_id` int(11) NOT NULL default '0',
`tech_pay_week_hours` float NOT NULL default '0',
`tech_pay_week_amt` float NOT NULL default '0',
`tech_pay_week_approved` tinyint(4) NOT NULL default '0',
PRIMARY KEY (`tech_pay_week_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

The tech_id is held as a $_SESSION[userid] when he logs in. I understand how to advance a date, but not from a dynamic date that should always fall on a Sunday, and a current Sunday at that.

Constraint Using The Days Of The Week?
I am developing a property application where I have 5 members and only want 1 member a day to choose their property for the "property of week" section.

So I want to assign a day to each member.

Mem1 - Mondays
Mem2 - Tues
Mem3 - Wed etc..

Each member will have there own unique logon so if Mem1 logs in on Monday, they will have the "property of week" option avaliable to them. Mem2 will have it Tuesday and so on.

Work Out Day Of Week From Given Date
I'm using a date picker to choose a date. the format of the date entered into the textbox is yy/mm/dd

From this how can I work out the day of the week from the entered date? I need this as the first day has to be a sat, and if it isnt my form will tell the user to choose a saturday.

Is there a simple way of doing this?

How To Remove Entries In A DB That Are A Week Old?
I ahve a social network and I have a bulletin system, taht allows users to post bulletins that all their friedns can read... well anway, i dont want the bulletin to just sit there and take up DB space, how would i go about removing "bulletins" that are over a week old?

Automatic Display Of Events Each Week
I know how to display a list of upcoming events from a SQL database, but am wanting to display the events based on the date, eg. events happening this week only. Could someone tell me how to do this or point me in the right direction please?

How To: DELETE * FROM Table WHERE Greater Than 2 Week
I am building a module that displays the headline from a page that had the most hits last week. I was able to figure this out in PHP. I would now like to know how to delete and records that are over 2 weeks old. Anyone know how to do this in the mysql query?

Delete Entries 1 Week Old Or Older.
I have a query that's supposed to remove bulletin entries that are a week old and over, but its not working, and the "date" column is filled with "time();"

<?php mysql_query("DELETE FROM `bulletins` WHERE `date` > (time() + (3600*24*7))");?>

Getting Day Of Week From User Defined Date?
is there a way to do this? e.g. i have three drop down boxes in html asking the user for day (1-31), month, year (2007 or 2008) i then have:

// get user input
$start_day = $_POST["start_day"];
$start_month = $_POST["start_month"];
$start_year = $_POST["start_year"];
//echo $start_year;

$the_date = $start_day . "/" . $start_month . "/" . $start_year; echo $the_date; say then i get an output as 13/10/2007 if the user enters that date, is there a way to get what day of the week this is?

Calculating Start And Ending Dates For A Week
Given a week number, how do you derive the starting date and ending date? I am trying to get the reverse of the yearweek function of MySQL. The yearweek function returns the year and week given a date. For example, yearweek(񟭂-08-01') returns 200231.

Cronjob, Mail Every Week/2weeks/month
3 types of users. those that want e-mail every week, those that want it every 2 weeks, and those that want it every month. there's only one cronjob set for every week. so the every week e-mail isn't a problem. the way i figure. i need a text file to store the value PHP Code:

Code To Calculate Date Range In A Given Week
Well I'm facing a problem in calneder and want your
help. I want to calculate the date that fall in a give
week but am not able to get the method for doing so.

Let me explain it with an example. Suppose i select
teh 25th week of the present year(i.e 25th week of
year 2006) then how can i calculate the days that fall
in that week.

Using The Date Function To Find Last Week Start And End.
I need to find the start of last week (monday) and the end of last week (sunday) using the date function in a Y-m-d format.

But it needs to work this out regardless of todays date.

Finding a day in the past is not a problem if you know how many days to minus from the date function, but how can I work this to be not dependent on this fact?

Check Week Number In End Of Year And Begiining Of New Year?
I am creating a little own calendar. Now I want to add a "previous week" and "next week" functionality to the calendar.

It is easy to take $thisWeek - 1; and $thisWeek + 1;, but there has to be a check wether it is the last week of the year and it should actually be a new year and head to week number 1. HOW do I make this kind of function? I use the following string names:

$thisYear
$thisWeek

To Get A File Name, File Size, File Type...?
Is there a way to get information about a file BEFORE it is submitted to the server?
I am trying to make a upload progress bar from scratch WITHOUT THE PRON.C PHP FIX!!!
I found the file being uploaded in my NET://WINN01910//TEMP folder and I can outputs its file size in a popup with a one second refrehs, but this makes it so the USER needs to know the full file size to know if its anywehre near done.

Is there a way to get the filesize from the clients side? Possibly javascript that uses ajax to submit the values to the server before the file is sent but when it is selected?? Is there an easier way to do this and/or do you have any ajax example code of how it might work?

I also have another problem, Althoguh i can echo the filesize of what is recieved so far, I am just glob()ing the temp folder for: "php*.tmp" but is there a way to tell the tmp file so they don't see everyone's uploads?

FIle Uploads: Empty _POST And _FILES Arrays When File Too Large
Uploading of files.. AFAIU from the manual, if a file is larger than the
size defined in the form or larger than upload_max_filesize in php.ini,
that _FILES['file']['error'] should hold an INT error code.

The file upload system is working fine if the file is smaller than the
defined size, but if it's larger, then both the _POST and _FILES arrays
are completely empty:

array(0) {
}

I can obviously check to see if $_FILES is set and contains elements,
but I was hoping for more specific error handling (reason as to why the
upload failed).

Has anyone else encountered this? Any info welcomed =)

Checking File Existence Through A List Of File Locations Gathered From An Array
I've been trying to wrote a code to check the existence of some files gathered from a field in mySql database.

And I am kind a stuck at a point where I get the file locations from the database but when it passes those locations to file exist it keeps telling me the file does not exist.

Only first file exists the other 2 file does not exist to test if the code was working or not. Code:

Email With File Attachements - How To Upload File To Server From Browser?
I have a PHP script that sends an email with attachment and works great when
provided the path to the file to send.

However this file needs to be on the same server as the script.

I want to develop a webpage where people can send attachments that are
stored on their local PC.

I know I can use the <input type="file" > HTML to generate a file box that
allows the user to navigate to a file on their PC and product a file path,
but how do I then upload this file onto file server to email out with my PHP
email script?

Is there an easy way to do this?

Or can I approach this problem from a completely different angle.

Creating Link To File Or Temp File For User Download
I am designing a document management system (DMS). The files are stored
in a directory on the webserver. The filenames for the documents are
stored in a MySQL database. The DMS will track revisions from the
initial version through the updates. We must have strict permissions
set so only authorized personnel can access some documents. All of the
documents when uploaded are given totally random names such as
"114723fb5422c6bd5ed18f6.doc". Is there a way, without the webserver
creating a new file name "document_specs_ver2.doc" to have the file
download named "document_specs_ver2.doc".

If I must physically create a new file, how do I know when the
webserver would be allowed to delete it? Notes: The files will be in
several different file formats, not just "doc".

Header Function, File Download, Temp File Disappears
I have the following headers:

if (preg_match("/compatible; MSIE/i", "$browser_type")){
header("Content-Tranfer-Encoding: binary");
header("Content-type: ".$assoc["type"]."");
header("Content-Disposition: attachment; filename="".$assoc["name"].""");}
echo $assoc["file"];

which starts the download of an mp3 file in one particular case. If you do not save target as and just select 'open' the temp file is zero bytes even though the download process took a while and showd how much progress you were making. So something is happening to the temp file.

Warning: File(): URL File-access Is Disabled In The Server Configuration
Does any one know how to work around this error on a web site?

Warning: file(): URL file-access is disabled in the server configuration ...

Load .txt File From Computer And Save The File In Www/folder Director
anyone know how to add the .txt file from computer into the localhost www/Myfolder directory.

Download File And Delete File From Server With One Button Click
I want the user to be able to download a CSV file and delete the file from the server all with the click of a button. Currently, in firefox, it will just display the CSV and not delete it. In IE, it will download the CSV and not delete it. Code:

Open File, Put First 5 Lines Into A Variable, Close File...
1) I want to open a file on my server.
2) I want to read only the first 5 lines.
3) Put the first five lines into a variable.
4) Close the file.
5) Display the contents of the variable.

I know how to use the fopen() but I have big problems just trying to read the first 5 lines only? I tried many things. I downloaded some search scripts which displayed the <meta> tag only from html pages...

What is this guy doing?

Well I have a big site and content is added and changed everyday. I have a dynamic page that reads a directory for files and then puts a link (well it includes the file for reading on my php page). That works great! MY PROBLEM is that I want not only a link but a small description below it (basically the first five lines on the file)...

See so far:
Quote: if (isset ($content)) {
include ("files/$content.html");
echo "<A HREF="read.php">Back to index</A>";
} else {
echo "Opening directory, reading files, and listing them as a link";
$handle = opendir('./files');
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
echo eregi_replace (".html", "", "<A HREF="read.php?content=$file">$file</a>");
}
}
closedir($handle);
}

Open .php File With PHP Designer 2007 By Clicking The File In XP
In windows XP, I want to be able to click on a .php file and have it
opened in PHP Designer 2007,
Or right-click on it and have an "edit" menu option presented to me.
I know how to tweak the registry to do this in general, but what would
the command line look like in this specific case ?
PHP Designer does not do this automatically. It is as if the program
does not allow commandline options.
It only opens with the last file used or a menu of recently opened
files.

PHP File Upload Unexpected Error - File Too Large?
I have a short basic script to upload files. It works fine with small files,
but with longer files it gets stuck.

Here's the fragment, the input file is loaded in "$file" from an HTML form
as usual.

....
$img_str = fread(fopen($file, "r"), filesize($file));
$data = addslashes($img_str);
// --------------------- up to here the execution is correct and fast (<1
second)

$sql="INSERT INTO $table (".
" file_name,".
" file_type,".
" file_size,".
" bin_data)".
" VALUES (".
" '$file_name',".
" '$file_type',".
" '$file_size',".
" '$data')";
// --------------------- it gets stuck
here!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
mysql_query($sql) or die ("SQL error ..$sql");

I have already set the php.ini variables as follows:
memory_limit = 16M
upload_max_filesize = 6M

I also checked the execution time to max_execution_time = 300 (even though I
don't believe it should be necessary).
The server is a P4 1.8 GHz, 256MB RAM