PHP :: Form Field Dynamic Population And PHP

Dynamic List Population
how do you populate a list dynamically? for example I have the following in a table but I can't get them into the list after the query is performed.

<form action="">
<select name="cars">
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="fiat">Fiat</option>
<option value="audi">Audi</option>
</select>

Multiple Dynamic Drop Down Population
I have a table with 3 pieces of data that I would like to use to
dynamically populate 3 drop downs using javascript. The fields are
state, orgname, office. If it's not already obvious, I'd like orgname
drop down to change when a state is selected and I would like office
drop down to change when an orgname is selected. I can do this with
multiple tables but am having difficulty getting it to work when the
data is in the same table. Below is the code to get state and orgname
from separate tables(the code reflects one table and is broken in the
below state). It's the best I can come up with and I can see why it
doesn't work but I know there must be a way to pull all the pieces from
a single table.

<code>
$list=$_SESSION['list'];
if(isset($list) and strlen($list) 0){
$quer=mysql_query("SELECT DISTINCT orgname,org_id FROM organization
WHERE state=$list ORDER BY orgname");
}else{$quer=mysql_query("SELECT DISTINCT orgname FROM organization ORDER
BY orgname"); }
$quer2=mysql_query("SELECT DISTINCT state FROM organization ORDER BY
state");

//first drop down
echo "<select name='state' onchange="reload(this.form)"><option
value=Ɔ'>Select one</option>";
while($state = mysql_fetch_array($quer2)) {
if($state['org_id']==@$list){echo "<option selected
value='$state[state]'>$state[state]</option>"."<BR>";}
else{echo "<option value='$state[state]'>$state[state]</option>";}
}
echo "</select>";

//next drop down
echo "<select name='org'><option value=''>Select one</option>";
while($org = mysql_fetch_array($quer)) {
echo "<option value='$org[org_id]'>$org[orgname]</option>";
}
echo "</select>";
</code>

How To Process Dynamic Form Field Names
Let me start by saying I don't have a lot of PHP experience, and am just starting to fumble my way around some of this stuff... I'm sure this has been asked a number of times, but after 2 days of searching the internet, I just haven't found a solution that makes sense, so I am hoping someone here can help me.

I have a pretty simple project schedule sort of web page that lists a number of tasks & 4 dates associated with each task. (planned start, planned complete, actual start, actual complete.

The page is built dynamically based on what is in a mysql database, and the dates listed are form fields, with the intent that a person with access can change any number of these dates.

Each task has an id associated with it, so when i build the form, I name the form field <task_id>-<date type>. so, for example, for task id = 10 I have 4 related form fields:

10-planned_start
10-planned_complete
10-actual_start
10-actual_complete

This basic pattern is repeated for all the tasks (up to 100 right now, but it could grow slightly).

Once all the form fields have been updated, and the user clicks submit I want to update the data in the database with the appropriate data.

So, my questions is:

1) How can I process this form, when I don't know what the names of the fields are going to be, and/or how many fields there are?

2) Is there a good way to identify only those fields that have changed and do updates on only those fields, or am I "stuck" updating all the records, even those where the dates have not changed from when the form was built?

Phpmyadmin/MySQL - Dynamic Date Field?
I am a relative newbie for php/MySQL, and most of what
I am doing is based on being self-taught using someone else's
well-written code, and my own googling the answers to my questions.

I'm doing a php/MySQL page that reads data out of a MySQL database.
Longer term, I'll do a data-entry screen allowing me to modify the
database or add new records. For now, I'm just using phpmyadmin to data
enter stuff.

Is there a way to set up a date field, Last_Update, that would
automatically update to today's date any time a record was added or
changed using phpmyadmin?

Not sure if I'm asking the question clearly. What I want would be that,
let's say that I add a new record today, April 23. The Last_Update
field for the record would automatically be April 23. If I go in and
modify and part of that record on April 29, Last_Update automatically
changes to April 29 for that record.

If that's not possible, then how in php/MySQL would I display on a web
page "Information last updated on mm/dd/yyyy" based on the contents of
the database?

Hiding An Empty Dynamic Image Field
How do you hide a empty dynamic image field on a page. This will mean that page will display images that have been uploaded and the empty image field will not appear if the user does'nt upload an image. I need some sort of if statement that says if the rsNews['newsImage'] does not contain an image, then show nothing on the page. But if the user uploads an image, show it. Code:

Add Form Field Values Into Php Seesion Variable Before Submitting The Form
I have php page which is basically a simple html form containing some text fields.The user will type in values in it and submit it .Now what i want is that just at the time of submittion i want to assign the form field values in session variables.

I nwwd this b'coz the form is being submitted into a cgi script which has been given to me.Now the cgi script is an executable one and i am unable to view or change its content,Its functionability is to change a password for a linux user account .Now the cgi script after completing the job is redirected to another html page.What i have to do is that i need to trap the user input and update the values in a mysql database .Now if i can assign the values in a session variable then i can do the updatation from some later pages.

Dynamic Form Fields/multiple Page Form?
It is for a friends out of print booksite, where visitors can request multiple books to be searched by adding one at a time to a cart (javascript), then once all added they submit to another form where they enter their personal details and all is sent through. The problem is at the moment they cannot change whats in the cart without refreshing the browser window and losing everything.

1) present for asking how many books they want to search for
2) display multiple rows of the same input fields depending on how many books they say they want to have searched for?i.e

title|author|publisher|etc
title|author|publisher|etc
title|author|publisher|etc

3) when these are submitted they could see these above the next part of the form where they enter their details with the option to go back and delete/amend.
4) send all the info to my colleague.

if so has anyone seen a similar script that I could take a look @ to see if I can hack it to suit my needs?

PHP / Javascript Menu List Population
I would like a web page to have 2 menu lists

The contents of the second menu list depending on the selection made in
the first.

The contents of the second would be populated from a database.

I am fairly new to programming using PHP, Javascript and MySQL but I am
sure what I am asking has been done before. Could someone please give
me some pointers or direct me to a tutorial.

Multi Drop Down Menu Population
I am having problems getting the 3rd and 4th drop downs to work properly. What am I doing wrong? Also is there an easier way to do this using one table insead of multiple SQL tables? Code:

Population Select Menu Using Php And Database Values
I have no idea how to go about this. so i would apreciate some help i want to populate the values in a html select menu from database values in one table

so i want all the values from 1 particular field in the database to be displayed in the select menu as separate options.

Dynamic Form
I have one user table in my MySQL database and this is linked to a user type table containing 3 types of user. Each type of user will be required to give a different amount of data when registering.

Basically I want to create one registration form for all types of users but only show the form fields that are relevant to the individual user type. The user type will be selected from a pervious page containing a list menu with the 3 user types that is sent via GET to the registration page.

Dynamic Form
I need to create a form that takes a number that the user enters, and
duplicates a question the number of times the user entered. For
instance, if the customer enters 5 on the first page, when they press
next the form generates "How old are you?" 5 times on the page. The
customer will answer all 5 questions then press next. Finally, all the
local variables get dynamically created and written to a database.

I have already taken care of dynamically creating the question five
times. Using a simple WHILE clause, this generates the correct number
of questions. What I am having an issue with at this point, is how to
dynamically create the local variables.For instance, for the question
"How old are you?" I would need a unique variable for each instance;
using something like $Age(n). So that for five times, it would
automatically created variables $Age1 through $Age5. I have carried
over the number to the submit page by creating the variable $Number
and passing it along as hidden button on the form. $Age'$Number'
seemed to work for creating the variable, but $_post["Age'$Number'"]
doesn't work for referencing the global variable. I would need some
way of looping through and dynamically creating the variables.

Dynamic Form
I had to make a form for someone, with 42 questions each question had different form-elements. I was typing and coding for almost 3 hours..!! lets say we would make a form (formmaker.php) to dynamicly create a form with multiple questions: on the formmaker :

-first we have to enter the number of questions (max 100)
-then we have to type the question(s) in (an) input field(s)
-then we would have to select a type of answering field (textbox, checkbox, radiobuttons, file, dropdown etc. )

-it would be nice if we could select to make the question mandatory or not.
-if we choose for checkboxes or radiobuttons , it would be nice to know how much of them (no limits here !) ok..limit it to 30

-when we have selected...for example..15 checkboxes, they have to dynamicly appear on the formmaker.
-for each checkbox or radiobutton, we have to enter a value.
-finaly we have to add an email adres to each question !!! (and a BCC field) (this way, we can use one form and split and send the data to multiple recipients..!!)

-also we have to be able to dissable or enable a question. (if dissabled, it wont show on the created form..

A nice template to show a filled in form is preferable.. It would be nice to store everything in a database tabel. (for each new form a new tabel in the database) question1 id active(yes/no) questiontext fieldtype mandatory(yes/no) radio_or_checkboxvalue1(rocv1) rocv2 rocv3 rocv4 rocv5 etc.... sendto_email bcc_email
I started with the code already...here it is: Code:

Form Field To Array
Ok, two questions:

1) I have a mulitple select form field. It is named 'artists[]' and it produces the array artists[$i] correct? now i want to make the array into a single variable named $artists that containes the array in a CSV format with no ending comma.

how do i do that?

2) Is it possible to browse for a directory and pass it though a script as text? not a file, just a directory?

PHP Form Field Update...
I am sure this has been answered here somewhere, but I have searched for a good 2-3 hours and can't seem to locate a solution. Additionally, I really don't want anyone to solve this mystery for me (at least not all the way!) - But I was hoping someone could point me in the right direction here.

I am trying to figure out how to update form field information before the end user hits the submit button - for example, if they select that they are from California from the "state" drop down list, only counties from California would show up in the "county" drop down list. BTW, this is only a hypothetical example - I am only using this code to build a photo manager for my website!

Anyone able to:

1) tell me what this process is called - it's hard to search for answers when you don't know what you're looking for.

2) point me in the right direction of a solution.

Form Field Testing
I have this site which people submit sites to it. What I need is for when they submit their info to the form, they enter their url into the form field and then next to that there is a test button, when they click this button in a new window it will load their site. I know there is a way to do this with java and php but not sure how to do it.

Also is there a way to have it so their site is scanned and if it contains popups they will be denied access to join?

Form Field Value Containing Backslash
I have recently taken up PHP programming, and I got stuck on the
following.
<?
$p_body = (isset ($_POST['body' ]) && ($_POST['body'] != '')) ?
$_POST['body'] : 'Enter your text here'
$p_name = (isset ($_POST['name' ]) && ($_POST['name'] != '')) ?
$_POST['name'] : 'Enter name'
$p_mail = (isset ($_POST['mail' ]) && ($_POST['mail'] != '')) ?
$_POST['mail'] : 'Enter email'
$output = <<<CODEREH
<form method="POST" action="doform.php">
<p><input type="TEXT" name="name" value="$p_name" /></p>
<p><input type="TEXT" name="email" value="$p_mail" /></p>
<p><input type="TEXT" name="body" value="$p_body" /></p>
<p><input type="SUBMIT" value="Store it!" /></p>
</form>
CODEREH;
$invalid_body=array('','Enter your text here');
$invalid_name=array('','Enter name');
$invalid_mail=array('','Enter email');
if (validate($p_body,$invalid_body) && validate($p_name,$invalid_name)
&& validate($p_mail,$invalid_mail)) // fields not entered correctly
{
//process form data and provide link to continue (or enter another
set of data)
exit;
}
// data not entered correctly
echo "All fields must be entered!";
?>

If either field contains backslashes, they are duplicated when the
form reloads.
Each successive form submission becomes , \, \\ etc etc

Why does this happen and how do I fix the variables to show the
original data each time?
I know I am a newbie, probably an easy one for this group.

Form Field Set Focus?
I'm still something of a newbie to html/php/mysql.

I have a php/html form with several fields of type "input". If the user
enters improper data in a particular field and clicks the Submit button,
the php script has to trap it and return a javascript error message box
with an OK button. That part I've already got down.

But, you know how in Visual Basic you can set the focus on the offending
field on a form, so if the user gets a Message Box with an error message
and clicks OK, the form goes something like,

myForm!myField.SetFocus

Is there an equivalent way in php/html way do this?

Splitting A Form Field
I am coding a form which stores info in a mysql DB. The form is ment to post and edit info on antiquarian books. My title field (<TEXTAREA>, so i can't give a maximum of characters) cannot contain more than 255 characters, but some books might have a longer title. I want to cut off all chars that exceed 255 (words should remain intact) and paste them into the description field.

How can I accomplish this? I can count the chars with strlen , but how do I chop off the chars which exceed the maximum, keeping the words intact and paste them in another field?

Variable In Form Field
I want to put a variable as the content of a hidden field. I realise that normally you would just open up a set of php tags and echo the variable in which I have done in the past, although I need the whole form in php tags as I have made the form a function in order to hide it with sessions when no body is logged in. This seems to be causing a problem as I can't get the content of the variable into the field its just echoing the actual statement in. Code:

Form Field Validation
When validating user input I check it's not empty and then run 'mysql_real_escape_string($s)', I was then going to make sure that it is only alphanumeric, but I wanted to allow certain other characters as well. Realising this must be done before the mysql escape check, what characters should be blocked because they are dangerous, I can only really think of quotes and $. The real escape check should handle the quotes issue, so is the $ an issue or not?

Dynamic Form Value Modification
I was wondering if and then how to dynamically update form variables without having move between webpages

I am developing a print quoting system for a company and I want the options in list boxes to adapt based on the values of previous selection in the form. However it must happen immediatly without the whole page having to refresh.

For example if a person chooses paper size to be A4 then the next drop down list must only have options available for A4 pages.

I thought I would need to use Javascript for this but I can't find out how to access the server side mysql database so I get the feeling Javascript is the wrong option.

The whole site is programmed in php but php is server side so I don't don't think its possible using php specifically.

Dynamic Form Selects
How do you make dynamic for selects in php? It is in regards to a modify type scripts im writing in php/mysql.

So regular select drop downs look like so:

<select name=genericselect>
<option value="1" selected>1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>

right, well if I was pulling info from a database, how would I make is so that the 'selected' value is dynamic and comes from the database? Im sure theres a simple way of doing this.

Getting Info Out Of Dynamic Form
I am using the following code to produce a dynamic form.

$result = mysql_query("SELECT id,weight,date FROM weekly_data WHERE
weight IS NULL AND subscr_id = '$toss' AND date <= now()");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
print"<table width=ï`%' id='catchup' border=Ɔ' cellspacing=Ɔ'
cellpadding=Ɔ'>";
print "<form name='form1' id='form1' method='post'
action='catchupprocess.php'>";
print"<tr>";
print"<td></td>";
print"<td>Weight</td>";
print"<td>Date</td>";
print"<td>Waist</td>";
print"<td>Measure</td>";
print"<td></td>";
print"</tr>";
while ($row = mysql_fetch_array ($result)){
//echo $result;
print"<tr>";
print"<td>";
print"<input name='".$row['id']."' size=Ɗ' type='text'
value='".$row['id']."'/>";
print"</td><td>";
print"<input type='text' size=ƌ' name='weight".$row['id']."'
value=''/>";
print"</td><td>";
print"<input type='text' size=ཆ' value='".$row['date']."'/>";
print"</td><td>";
print"<input type='text' size=Ɖ' name='waist".$row['id']."'
value=''/>";
print"</td><td>";
print"<input type='text' size=ƌ' value='$measure'/>";
print"</td><td>";
print"<input type='hidden' size=ཆ' value=''/>";
print"</td>";
print"</tr>";
}
print"<tr>";
print"<td> </td>";
print"<td><input name='Reset' type='reset' value='Reset'></td>";
print"<td> </td>";
print"<td><input name='submitcatchup' type='submit'
value='Submit'></td>";
print"<td> </td>";
print"</tr>";
print"</form>";
print"</table>";
?>

Form With Dynamic Questions
I've a mysql table where i stored a list of questions. My php script
executes a query which yields a different number of questions every time; i
used the loop function to create an input field for each question in the
form; and dynamically referencing each input name with the question number
i.e. question 1 is called q1, question 2 named q2, and so on.
The data is submitted using POST. I then try to retrieve all the answers by
doing a loop and using something like echo '$_POST['q'.$n.'']' except the
syntax doesnt seem to work.

Dynamic Form Update
I have the following form in which i need to updateitems.
The problem is that i do not know how many elements will be in the form
(generated dynamically)

eg
<input type = "hidden" name ="id1" value="1"><input type ="qty1" value ="1">
<input type = "hidden" name ="id2" value="2"><input type ="qty2" value ="1">
<input type = "hidden" name ="id3" value="3"><input type ="qty3" value ="5">
<input type = "hidden" name ="idn" value="n"><input type ="qtyn" value ="1">

how do i generate an array for a foreach loop to update the values in PHP
so that i can use it to create a Update query
eg
///begin loop
$sql = "UPDATE `table` SET `qty` = `$qtyn` WHERE `id` = `$idn`";
// end loop

Dynamic Form Items
I am trying to create A form that its fields will depend on a
form menu.
for example.
/***********************************************/
<form name="form1" method="post" action="">
<select name="select">
<option value="1">option 1</option>
<option value="2">option 2</option>
<option value="3">option 3</option>
</select>

Text field 1<input type="text" name="textfield">
Text Field 2<input type="text" name="textfield2">
Text Field 3 <input type="text" name="textfield3">
Text Field 4 <input type="text" name="textfield4">

<input type="submit" name="Submit" value="Submit">
</form>
/***********************************************/
When the option 1 is selected only the textfields 1 and 2 to appear,
when option 2 is selected only textfields 1 and 3 to appear and so on... any
combination I would like.

I tried puting the textfields in "if" statments but i don't like it. its too
messy PHP and HTML code.
Any Ideas of how this could be done better ? If someone did something
similar before and has a relative link it would be good as well.

Dynamic Form Pulldown
I'm building a form and need to have the options in a pulldown menu pulled from a mysql database, i understand the basics of sql and have used forms before, i just need to see an example to get me on my way.

Dynamic Form Processing
Im writing a script for processing a form created by a csv file. this form is created through a loop, where $num is the place in the loop. Code:

Dynamic Form Fields
I want to have it setup so when the user clicks this link a value is sent via get and that value is put through a for loop to generate an additional form field: Code:

Dynamic Form And $_REQUEST
My current project needs to run on both windows and linux. I figured out that windows needs $_REQUEST to read the form elements. This worked well until parsing a dynamically built form with checkboxes named: cb0, cb1, cb2, etc.

I can't figure out how I can use $_REQUEST to read the form elements, when I try $_REQUEST[$i] for example all values of the array elements are 'cc'. No idea where this comes from as cc is never used as a value?

Form Field Content And Sessions
I've searched for this and found similar problems, though not quite what I'm after.

Basically, I'm using sessions for logins, keeping user data readily available etc. but when a user submits a form and then uses the back button to return to the form (if an error is given through some fields not being filled for example), the form fields are emptied unlike normally when it keeps the data you submitted.

Is the solution to this simply the session_cache_limter() trick or is their a better, more backwards-compatible solution? I ask as I'm running PHP 4.0.1 at the moment so haven't been able to try it yet.

Any help/suggestions are much appreciated.

Autmatic Form Field Fill
I have two fields in a form. The first is the email field the second is the username.
Now I want the username field to be filled automatically with the part before "@" of the first field.
So if someone fills in "brain@domain.com" the second field has to be filled with "brain".

How To Limit Form Field Input?
I'm wondering if there is an easy way to limit a user's input in a text field to 1000 characters?

Form Text Field Validation
I've got a form and I'm now trying to validate the text fields in it. The field I want to validate is for someones name, so there should only contain letters. Below is the function I've written to handle this. Code:

How To Hide 'hidden' Form Field?
I am sending the user's password in form's hidden field as Code:

<input type=hidden name="studen_pass" value="readfromdatabase">

but i dont want anyone to read it via watching its source code. is there any trick to hide it with php so that no one can read the password hidden field value by watching page's source code.

Increment A Text Field In A Form
I am creating an intranet which shows active projects and allows people to add new projects. If users want to add a new project, they fill in a form but what I want the form to display in the ProjectNumber field (which is a var char field & not the primarykey) is the last Job Number incremented by 1.

For example if the last ProjectNumber was TS0014, then the default value in the ProjectNumber field should be TS0015 - this way users know what the next job number is.
At present, the last job number in my table is TS0014. Below is the code i'm using but for some reason in the Job Number field in the form Im getting TS001? WHY? Code:

Form Field Text Output
How can I get html code in an editable form field to display properly? Specifically: I have text that is echoed to a form field via <? echo $text ?>

The user can then edit that text and submit. However <BR> is showing up as a literal <BR> and should be a linefeed. Is there a way to have this display properly?

Example: LINE ONE<BR>LINE TWO
should display as
LINE ONE
LINE TWO

Note that this is only a problem in the form field. It displays properly when echoed outside of the form.

How To Get Un-escaped Text From A Form Field
I have a php script that gets the text from a form field:

<?php

include("global.inc.php");

pt_register( 'POST', 'test1');
echo $test1;

?>

The text comes back fine, just some characters (', " and ) are now escaped
(', " and ). The problem is that I need the he text to be exactly as it
was entered by the user. I could process the text myself, and replace the
escaped characters, but I'd like first to understand why this is happening
and if there is a way to disable this behavior and get the unmodified text
directly.

Php - Mysql Form Field Generator
does anyone know of a simple function/class that will take config
options: table name and the database connection stuff(or whatever)
It will then print out appropriate form fields to allow editing of a
row?

The reason being is that in the admin section of a website I am
building we are constantly adding columns to a table...It is used for
keeping config options of the site. We do not wanna update the form
each time we add a column.

Web Mail Form Problem With One Field...
The code below is in my contactform.php file which takes variables from a contact form built in flash on my website. Three of my fields work correctly, but the phone field does not. It is always displayed as blank in the resulting email. I've tested the variable being sent from the swf on flash and the telephone variable is populated. Can anyone see the error in this code regarding $phone? Code:

HTML Form Field Value And Php Array
I am creating a html form which has 5 html list menu and menu value get store in array after hitting submit button. The value stores in PHP array and then print on same page and then after re checking the value If i want modification then click the edit button and value re store in the same html form.

Here we are not using the database. If it is possible then please provide me the code and if there is any other solution to this problem them please guide me. for above problem please avoid the java script in php code.

Form Field *required* Validation
I have php form I'm trying to edit. Some of the fields on this form is required, and some aren't. I want to adjust it so none of the field is required. But I am not able to find the place to set this value.

Following are 2 piece of the code for 2 fields, 1 is required and 2nd is optional. Please help me determin where I might be able to adjust the validation. Code:

Strpos To Validate A Form Field
I am trying to validate a form field. I have provided an example below. Basically I want to check that 'a' ($findme) is the 1st and 2nd character in the string (0 and 1 position).

<?php
$mystring = 'aakjhabc'
$findme = 'a'
$pos = strpos($mystring, $findme);
// Note our use of ===. Simply == would not work as expected
// because the position of 'a' was the 0th (first) character.
if ($pos === 0) {
echo "The string '$findme' is the $pos digit";
} else {
echo "The string '$findme' was found in the string '$mystring'";
echo " and exists at position $pos";
}
?>

I am wondering, can strpos be used to find the specific character more than once in the string? As you see above, the 'aa' is the first 2 characters in the string. $pos equals 0 because it finds the first 'a' in the string, and I guess it doesn't look for the 2nd 'a'? If strpos can't be used for what I want, what other method can I use? I'd like to keep it in an IF statement and relatively simple. Any help much appreciated. Thanks for reading.

POST Form To Dynamic Page Name
I've got a simple form with an HTML OPTION block. I'd like to POST the
form to a page whose name is based on the OPTION they select.

So for example say the user selected this option, I'd like to POST the
form to a page named "memory.php".

echo "<option value="memory">Memory Utilization</option>";

Reset Dynamic Search Form
i have a search form that has a set of checkboxes and a set of select boxes. the checkboxes correspond to a select box and activates the select box once checked. when i submit the search form to display the results on the same page, the elements are echoed back into the form so the user can see what search criteria he/she search for: Code:

Identifying Dynamic Form Fields
User goes to page which is a form that asks for some basic info regarding returning products for credit/exchange, and also asks for how many products are going to be returned. Upon submitting, a return authorization form is presented to them with the specified number of product fields. I now want to take the input from this form and email it to myself, as well as, display a confirmation page to the user. The problem I have is a can't say, for instance, echo "$field_name"; because field_name will get created dynamically after the user specifies how many products to return. For example, say the user says 5 products, this will generate a form with field names like:

return_code0 inv_num0 qty0 product0 cre_exch0 stockout0
return_code1 inv_num1 qty1 product1 cre_exch1 stockout1
return_code2 inv_num2 qty2 product2 cre_exch2 stockout2 and so on....

These get created with a for() loop. Once this form is submitted, how can I address the field names? Code:

Dynamic JS Form And $_POST Array
I have a form that I am altering after page load with javascript. Basically I have a button that inserts another text field into the form which the user can fill out. Its for a calendar, and I'm allowing them to optionally add multiple days for an event. Each box that is created has the same name with [] on the end to make it an array.

When I view the post array with print_r($_POST), only the first textbox's value shows up. This is the only textbox in the form when the page loads.
Simplified example:

<form name="calform" action="process.php" method="post">
<input name="startday[]" type="text" class="bordered" size="25" />
<input type="button" onclick="add_one_more()" value="Add another date" />

// if the user hits the add button it adds this input field after pageload

<input name="startday[]" type="text" class="bordered" size="25" />

</form>
And here's what I'd get from that form

Array
(
[startday] => Array
(
[0] => test1
))

A button inside the form basically adds another <input> tag between the <form> tags. Why isn't PHP seeing the data?

Dynamic Form Option List
I want to create a dynamic drop down option list in a form, but I just can't wrap my head around this.

Both of the below scripts work as intended, but how do I make the mySql query results work with my existing script? Yes, I know I must replace the "$options = array" part in the top piece of code, but I need a little more guidance than that. Code: