PHP :: Get All Entries From Today (mysql)

Sort Results By Date/time, Limit 5 Database Entries Of Today &/or Upcoming Days
I'm designing a website for my fraternity and in the database I have entries which contain past events, todays events, and upcoming events. My problem is that I can not figure out how to sort the query results to display:

1) only past events based on the CURRENT DATE
2) only the events which fall on the CURRENT DATE or after, limiting the results to 5 entries
3) all events that fall on CURRENT DATE or afterwards

Example:
Today is September 15, 2007

Problem 1) Displaying all events that happened before September 15, 2007
Problem 2) Displaying only 5 results that fall on September 15, 2007 or after
Problem 3) Displaying all events that are happening on or after September 15, 2007

And obviously I would like the CURRENT DATE to change depending on what date it is, currently.

Ok so now I've been very redundant in my explanation of my problem here is the code and a link to what that particular page looks like. Code:

MySQL Dont Show Older Than Today
I'm making a database for upcoming shows. so, what I wonder now, is there a way to show only upcoming shows, and just exclude the shows older than todays date? what I've got atm is: Code:

Deleting Entries From Mysql
I have business listings that I have pulled from a database(MySQL) and printed to the page, in an admin page, for review. I'm trying to write a script to add and one to delete the listing.

I get an SQL error, 'check the manual for blah blah near " on line 1'

Here is the 'delete script:

MYSQL Entries Won't Update
I am trying to update some entries in a mysql database that will append the filename to the end of a thumbnail directory entry. So for example /images/thumb/ would become /images/thumb/12345.jpg.

I am stumped because the below code gives no php or mysql errors but the entries are not updated in the mysql db! Code:

Multi Entries Update To Mysql
Could someone help me to figure out how to upgrade multi entries to Mysql by using PHP?

Say, I have a table on Mysql

id Priority
1 Okay
2 wait
3 later
4 asap
5 hold

Now I want to upgrade that table to:

id priority
1 hold
2 asap
3 okay
4 wait
5 later

Is it possible to upgrade multi entries with one submitt button? If yes, could you tell me how it could be done.

I knew I could do it by each entry (submitt button).

Update priority set priority='$priority' where id = '$id'

Selecting 4 Random MySQL DB Entries?
I have a table set up in my MySQL database called 'features'. This table has 10 entries, but I only want to select 4 random rows and display them out in tables.

Limiting User Mysql Entries
I have a script i'm making which is going to be used to search for reciprocal links on different sites and I have user levels such as free, paid, ect... I want to make it so that if the person signs up as a free user they can only add like 2-3 domains to be searched for their links. How would I limit the number of domains allowed to be searched? Would I limit the number of mysql entries allowed in the table for the domains?

Populating Dropdown With Mysql Entries
I would like to create a combobox in Flash which is populated with mysql data and programmed with php. For example: There are 3 entries in database .ie. apple, bannana, peach. Now these I want in combobox in Flash MX/flash5.

Day View Calendar / Mysql Entries
I am trying to create a day view of a lab resource reservation system. So far, I've been able to generate a day view table with php, using variables for start time, end time and periods. Periods represent intervals on the day view.

I have two columns in the table: the first one starts at the start time (say 8:00) and there is a row for every time until the end time, each row time being increased by the period, ie. 8:00, 8:30, 9:00 where the period is 30 minutes and the end time is 9:00.

My second column in the table is filled with unix timestamps representing the date for that particular row, so the 8:00 row on July 1, 2007 is represented by a timestamp of 1183291200. I then created variables to represent start and end times and date of a reserved lab resource. I did a little switch statement in my second column of my table saying, if that row's timestamp equals the start or end time of my reserved resource, than give it a certain style.

All well and good, except I need to tie this into a mysql database where the reservation details (start, end, date) are stored. Where I am getting fuzzy is how to integrate the query results from the database into my little system. I would like to have that second column pick up the results from my query and display the reservations, but I'm not sure now to do that. I'd like to post the code here, but I'm not sure how to post php code on these forums without getting yelled at for doing it wrong (I did that once, can you tell?)

Select All Unique Collumn Entries In Mysql
Can anyone tell me how you can query mysql for all unique entries into
a particular table collumn. Ive checked the manual but had no luck!

INSERT Into Mysql Alway Make Two Entries
I code some site and because Im a freak I made my own session-handling.
When a user open up my site it will check if there is a ssid in the url
if not generate one. this will be done by a function generate_ssid() and works fine.
next step is to register the ssid in the table session
this will be done by the following code:
******************************
function ssid_register($ssid,$login,$uid,$admin){

$connect = mysql_connect( $GLOBALS["db_host"],
$GLOBALS["db_user"],
$GLOBALS["db_password"])
or die($GLOBALS["db_error"]);
mysql_select_db($GLOBALS["db_name"],$connect) or die($GLOBALS["db_error"].'<br>ErrorCode s.001-con');
$result = mysql_query("INSERT INTO session SET ssid='$season',ip='$rip'",$connect);
echo ($rs);
return;
}
********************************
I redesigned the INSERT INTO part into all possible syntax but everytime I look into the db, there are two entries with two DIFFERENT ssids.
The only way it works correct is to dont use a variable on the first place.
Means if I use ssid='godhelpmetofindaworkingsolution' it works great but is not realy what I want.

As told above a "INSERT INTO session (ssid) VALUES ($ssid)" also has the effect of two new db-entries.

Populate MySQL With Multiple Text Box Entries
I have about 300 rows of mysql data which I have chosen to diplay with a text box at the end of each row, that is available for adding comments. I would like to be able to add comments to entries and then have an update scripte that would take the text box, named "MC" and place the data in its row identified by a hidden field which would corrrespond to the Primary Key of the MySQL Database. I've done something similar using check box arrays, ie. Checkbox name="MC[]"

My question is whether I can write a script that would test for a value in the corresponding text box, and update the MySQL data accordingly. I have also provided in my display script that if the MC column is already populated in MySQL it will not display in the form.

Number Of Identical Entries In MySQL DB Column
How do you display the number of times a particular entry appears in a column of a database?

Deleting Duplicate Entries From MySQL Database Table
The topic is related to MySQL database.

Suppose a table "address" contains the following records

-------------------------------------------------------
| name | address | phone |
-------------------------------------------------------
| mr x | 8th lane | 124364 |
| mr x | 6th lane | 435783 |
| mrs x | 6th lane | 435783 |
| mr x | 8th lane | 124364 |
-------------------------------------------------------

Quote:

Looping Until Today
I want to loop through dates, stopping at the current date

I set the enddate like this
$enddate=date('Y-m-d');

which prints out as &#55614;&#57158;-04-01'

$l['cc_startdate'] comes from a DB with the column in date format

but when i do
for ($dl=$l['cc_startdate'];$dl < $enddate;$dl++)
{
print $dl;
blah

}

Today / Yesterday
What I am trying to do is show todays date as today and yesterdays date as yesterday. for example:

if ($row['postdate'] = date('Y-m-d') {
echo "Today";
} else if { ($row['postdate'] = date('Y-m-(d-1')[not sure of proper code yet still learning]);
echo "Yesterday";
} else {
echo $row['postdate'];
}

Record From Today 0 Time ()
I have the date stored using time () which produces an 11 digit long number which is then stored in the database as an 11 digit integer in an "int" field.

I'm just trying to work out how I can find all records from today according to their int time value.

Today, Yesterday And Tomorrow
OK, have a problem with setting variables that will change automatically for $today, $tomorrow and $yesterday....when I do a search by a MySQL date (20011008) it works, but I have tried multiple ways to set those variables, with no luck.

I either need help solving this problem, OR.....is there a way to simply go by NOW and use items before and after now? That would be a workaround that I could manage.

I Can Get Today In A Number Variable Out Of 365?
Is there a way I can get today in a number variable out of 365?

I'm not sure if that makes sense, so example:

January 1 would be 1

December 31 would be 365...

How Do You Select All Records After Today?
I want to select records from the database using: PHP Code:

All Records From Today Using Time()
I have the date stored using time () which produces an 11 digit long number which is then stored in the database as an 11 digit integer in an "int" field. I'm just trying to work out how I can find all records from today according to their int time value.

Checking TimeStamp Against Today
How can I check if a date/time unix timestamp in the format of:

$mytime = "1186439997";

Is within 5 days of the current unix timestamp? Basically I need to check if the passed in timestamp was generated within 5 days of today?

Date Dropdown From Mysql Date Entries
For the PHP gurus out there, here is what I want to do: create a dropdown list of available dates from a mysql database date entries. But the dropdown/s should have 3 separate fields in month, day and year which in effect shows only those months, days and years that have corresponding entries from the database.

Planning to use this in the archive section of an online news publication so people can select issues to view via dropdown list that have corresponding entries only.

How To Figure Out If Today Is 1st, 2nd, 3rd Thurs Of The Month?
My brain is frozen on a convenient way to figure out if today is the
1st, 2nd, 3rd, 4th, or last Thursday of the month. Basically I need
something that will figure this out for any given day for any given month.

date() has everything BUT a 0-5 return for this.

Today.php Test Error. HTTP Headers
Trying to install on xp pro with IIS. Have mysql working. I tested it with the tutorial for installing from this forum.

When I open the test script, today.php I get
"The specified CGI application misbehaved by not returning a complete set of HTTP headers. The headers it did return are"' and theres is nothing after that but a black page.

The today.php consists of

<HTML><HEAD><TITLE>Today's Date</TITLE></HEAD><BODY><P>Today's Date (according to this Web server) is<?php
echo( date("l, F dS Y.") );
?></BODY></HTML>

Ive been over and over the php.ini and my.ini and cant figure it out.

PHP Scripts To Diplay Items From XYZ Date Til Today
I'm trying to work out the SQL command script to display all items from a fixed time period til the current date.

Something like...

$sql_query = "SELECT * FROM mytable WHERE dateAdded like 'todays date - 60 days'";

Expired Article - Comparing Today To Expire Date
On my front page I have a list of articles that are pulled from my database. I have just added a column (expires) to the db in order to remove outdated articles.

I'd like to compare today's date to the expires date in my WHERE statement to exlude all articles where the expires date is older than today. But I'm at a loss right now on getting it to work.

Check Date From Input Must Greater Or Equal Today Date?
I have 3 select box. Code:

<select name="day">
<option value="1">1</option>
<option value="2">2</option>
.......
<option value="31">31</option>
</select>

<select name="month">
<option value="01"> Jan </option>
<option value="02"> Feb </option>
.....
</select>

<select name="year">
<option value="2002">2002 </option>
<option value="2003">2003</option>
</select>

When I select and click submit in form. I will have 3 variable :

$day, $month and $year

How can I check the day that I choose in form must equal or greater than today date? If it less than today date. I must print error message to user.

Script For "updated Today" Blogroll?
Hi all - I'm new to PHP and I'm trying to make a page of blog links that show (1) the most recent posts for each blog, and (2) whether that blog was updated recently.

I am happy to say I've accomplished objective #1 by using the magpie XML parser, and I now have a php page that links to the most recent blog posts from several blogs.

My issue is with objective #2. I've seen some scripts that create blogrolls using blo.gs to show recency, but I don't want a whole blogroll - I just want a simple script that says something like "if the blog was updated today, do this, otherwise, do that".

Is anyone familiar with such a script? Or do people have other ideas of how to do this?

Limit The Entries
How can I limit the number of entries into the database, so after the limit is reached a text like "sorry limit is reached" is displayed, if the limit is not reached a form is displayed.

Duplicate Entries
I am currently using the form below for people to enter data into mysql, at the moment this has no methed of checking to see if the data they enter already exists, can anyone provide help as to how to this? PHP Code:

Approval Of Entries
I'm designing my first PHP and MYSQL application. It is going to be a database of singing groups. I'm going to allow individuals to enter thier groups info into the database. However, I'd like to be able to set up an admin screen that would allow me to approve each entry first before it can be viewed. As well as let me do some other admin functions, such as edit records, delete records. Any suggestions?

File Entries
I want to open a local file and add lines of text to the top of it, before any previous text in the file. How?

Duplicate SQL Entries
I have a buddy system on my site and I have found that duplicate buddies can be added into the database. Here how I have this set up:

user 1 want to add user 2 as a buddy.
user 1 goes to user 2's page and clicks "add as buddy"
A PM goes to user 2 and asks him if he accepts or declines
if user 2 clicks accept a php script is run

Problem:
This script need to detect if that buddy already exists, if so do nothing or overwrite the original. Right now it just adds the entry again. I am using a very simple table:

UID BID
---------
1 | 2

This would mean user id 1 has a buddy with a buddy id 2

Here is the non-functional code:

$query = mysql_query("UPDATE buddies SET uid='$uid', bid='$bid' WHERE uid='$uid' && bid='$bid'");
print "Buddy Has been overwritten";
//would prefer it not do anything at all if entry exists
if ($query == 0)
{
// No records updated, so add it
$query = mysql_query("INSERT INTO buddies (uid, bid) VALUES ('$uid', '$bid')");
print "Buddy Added";}

Add Entries To Array
What I want to achieve:
A select list in a form should grow with every data entry.
Example:

I have a list of towns to choose from for a single entry.
If there is a town, not in the list, I would like to have the option to enter one in a text field.

Next time I approch the input form, the newly entered town shows up in the select list.

What do I have to do, to expand the select list (resp. the table behind)?

Getting Total Number Of Entries
Hello, Im trying to retrieve and echo the total amount of cars in the database with PHP Code:

Displaying Entries In Rows Instead Of On Top Of Each Other
I'm altering a voting script for our dog rescue so that we can hold an online photo contest. I'm very new to php & mysql..kinda just muddling my way about with this.

I want to display the entries in a row across about 4 or 5 photos and then keep it going that way, but I haven't a clue as to how to do this....

Multiple Blank Entries?
When I go to my secondary page of results after I fill info out on a form on
the first, I get 3 blank entries automatically inserted into the mysql
tables. This second form has these blank entries printing up each time even
if I go in to the second page w/o filling out any info on the first. Is
there a way I could prevent these blank entries from being automatically
entered? Like some code that says that if something is blank then not to
have it entered into the tables? or something easier?

Deleting Entries In A Database
I've got the reading and writing to a database working but want to delete entries ..... how would this be done?

Selecting Duplicate Entries
I'm having the following problem: Let's assume I have a table with 3 fields: ID (type int), NAME(type varchar), EMAIL (type varchar) in a mysql db. The fields have the following data stored:

1, jack, jack@jack.com
2, tom, jack@jack.com
3, jack, jack@jack.com
.
2000, jack, jack@jack.com

Now let's say I have like some thousand entries like that one above with each one containing different data. So if there are entries which have the same email adress, how I can I select exclusively those entries with the duplicate data in it? So the result of a selection should look something like this: (If I want to show the selection results in html): PHP Code:

Multiple Entries For Same User?
I am creating this form, and instead of having a huge list of input boxes for visitors to fill out, I am wondering if it is possible to have the user click on add another button, and a new submittion will be added to that persons file.

Removing File Entries
I am using php3 and someone told me that php3 does not support foreach. In that matter, how would i go about grabbing lines from a file, iterating through all the entries and only delete the one that matches a string. I was thinking of a for() statement but I do not know what the php equivalent of perl's splice() is?

Extracting Database Entries
I have a non-profit's web site that wishes to allow their members to
fill out information regarding summer camp information (name, contact
info, mailing info, physician's name, etc) online and submit it. I can
handle taking the info with PHP and putting it into a mySQL database easily.

But what has me stuck is that they want the ability to print out hard
copies of selected submissions (their choice) if they need to.

Would I have to display all the database entries in a form on a new page
with a select box next to each entry and have them pick that way, then
loop through and print out the selected ones or is there a better, more
direct (read: easier) way to accomplish this?

Does this sound like something for which there may be a pre-written PHP
script that can be altered?

Ignoring Duplicate Entries
I have this samll piece of code that gets the last 5 post from a forum and presents them on the home page. But i am not sure how to prevent duplicate entries from appearing on it. PHP Code:

Retaining Checkbox Entries
I have a table with entries that are ever increasing and each one has an ID number and I want to be able to associate any of those ID numbers to a file, so I created a pages that shows the ID numbers, 100 at a time. Seeing that there are over 800 entries, I have paginated the results and give the user the ability to move back and forward thru the entries to check off which of the IDs they want to use.

However, if IDs on the first page are checked and then the user moves to the second page to check some more, if they go back to the first page, the IDs are unchecked.

- how to keep track and display which of the IDs were checked and
- how to send the information of which ones were chosen to the next step of the process for adding to the table.

Array From Database Entries
All I need is to create an array with the results from a database column.

Stop Repeat Entries
Can you stop pulling out exactly the same data from a database, for
example, if you had 2 entries which had the name Chris,

Deleting Entries In The Address Bar
I am sick and tired of looking at all that clutter that automatically pops up on my address bar, how do i get rid of all those enteries?

(PDO) Database Entries Are Not Possible, Even Without Errorfeedback!
I am trying to insert with PDO-Sqlite rows through a form. I can do
whatever I want, I don't find the sollution where I made the error.
Perhaps somebody of you could help me?!

However, the database is created with sqlite, and the entries should be
done with PDO_SQLITE. However, no entries are done anyways and I am one
step going nuts, specially because I don't receive no warning or
errormessage on the screen.

Code:

<?php
require_once('HTML/Form.php');
require_once('I18N/UnicodeString.php');
require_once('HTML/Table.php');

class Formular
{
private $ServerVar = array("Auswahl","Betreff","Eingabe");

function __construct()
{

$this->ServerVar["Auswahl"] = $_GET['Auswahl'];
$this->ServerVar["Betreff"] = $_GET['Feld'];
$this->ServerVar["Eingabe"] = $_GET['Eingabe'];
$this->MeinFormular();

//$this->sqdb();
if(($this->ServerVar["Betreff"] === null) or
($this->ServerVar["Eingabe"] === null))
{
$this->MeineDB();
$this->TextFeld();
}
elseif (($this->ServerVar["Betreff"] === "") or
($this->ServerVar["Eingabe"] === ""))
{
$this->MeineDB();
$this->TextFeld();
}

else
{
$Auswahl = $this->ServerVar["Auswahl"];
$Betreff = $this->ServerVar["Betreff"];
$Eingabe = $this->ServerVar["Eingabe"];
$this->MeineDB2($Auswahl,$Betreff,$Eingabe);
$this->TextFeld();
}