PHP :: Getting Info Out Of Dynamic Form

Dynamic Content - Writing DB Info To A Page
I'm writing a website that works on similar lines as a dating site, where end users can enter their details and what they want to sell, which is then submitted on to a webpage, any people that are interested in that product, contact us and we then pass the lead to the person who is doing the selling. So basically teh site is acting as a middle man.

I have done the database bit where the end user enters his details, we get emailed his details and his id (which is a an auto increment field) then there is a page called view.php which pulls up his details on a web page and there is then a submit and decline button. Teh decline button is the easy part, but the bit that I'm stuck on now is the submit part. And thus here is my question how do i write information that is held on a database to a webpage. But this webpage has to ADD and and not OVERWRITE what is already there as we want to create a listing? Code:

Php Form Info...
have a form, with a text input "fieldname".
method POST

$var = $_POST["fieldname"]

$var is then used to search in mysql

select * from table where jobtype like '$var%'
OR jobtype like '%$var%'
OR jobtype like '%$var'
OR jobtype like '$var' order by date asc;

basically i'm doing a search for any string that matches the searched
input, being at the beginning, middle or end of the jobtype column.

query works great, except when the string contains the 4-letter word
'info' such as information or informative
then the mysql query breaks down and give the usual:

Error performing query: You have an error in your SQL syntax. Check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'ORDER BY date ASC' at line 1

Now after much debugging, i found out that the php _POST variable
treats anything with info as a numner of 0 value.
inf is treated as text, nformation is treated as text, but anything
with info gets a 0 value.

Searched php.net and couldn't find anything related to this feature,
looked under security to see if it was related to that, but nothing.

Dynamic Form Fields/multiple Page Form?
It is for a friends out of print booksite, where visitors can request multiple books to be searched by adding one at a time to a cart (javascript), then once all added they submit to another form where they enter their personal details and all is sent through. The problem is at the moment they cannot change whats in the cart without refreshing the browser window and losing everything.

1) present for asking how many books they want to search for
2) display multiple rows of the same input fields depending on how many books they say they want to have searched for?i.e

title|author|publisher|etc
title|author|publisher|etc
title|author|publisher|etc

3) when these are submitted they could see these above the next part of the form where they enter their details with the option to go back and delete/amend.
4) send all the info to my colleague.

if so has anyone seen a similar script that I could take a look @ to see if I can hack it to suit my needs?

Persistent Form Info
I have some forms that have different parts, and it decides which parts to display through the url ie form.php?showpart=1, showpart=2, etc. If I want to show another part and change the url all the form info goes away. I'm a self taught PHP guy, I'm decent but not amazing. My current solution is to use AJAX to write/modify a cookie everytime the user writes something and bring that in when they change the page. Is there an easier way?

Printing Out Info From A Form
I have this php function that reads a text file for input to create a form. I am trying to get the form to print out the data on a separate page, but all I get is a blank page. Am I calling the page correctly, or is this even possible to do? Code:

Referer And Keyword Info Sent Via Form?
I've learned that HTTP_REFERRER, at least in my tests, returns the page visted on the current domain before the form page, not the domain visited before the current domain, so that hasn't been useful. I don't know how I would get keywords in this case. I've searched around for scripts or tutorials and have been surprised to find nothing helpful

The site in question has a separate stats package, but it doesn't track converting keywords and that's really what I'm after. There isn't high volume traffic, so getting them individually via a form (rather than input into a database) isn't a problem.

My question is really whether what I'm trying to do is possible with a few lines of code, or have I underestimated the complexity of the task?

Populating A Form Wth Database Info
I've coded a piece of code which populates a form with data read from the database:

$connection=mysql_connec ("localhost", "f2821842", "f2821842");
$result=mysql_select_db("QUERIES");
$query=mysql_query("Select * from Emp_Details where emp_num = '$employnum'");
while($row=mysql_fetch_array($query))
{$empname=$row['emp_name'];}

<form name="webregform" action="webadmin2.php" method="post">
<input name="requiredname" type="text" size="30" value="<?php echo "$empname"; ?>">
</form>

When I echo the $requiredname, I get spaces and no data, and I know that $empname is not a space-it does read a value in a database. 1. How can I get $requiredname to print a value?

Insert Form Info Into Database
i am trying to enter info from a form into a mysql database. when i submit the form, a new row is created, but the information isn't contained in it? any thoughts? PHP Code:

Filling Form With Database Info
I have a table with 5 fields for a tour business activity list
: (1) id -table key (2) name (3)description (4)picture -text link not
binary(5) country. I would like to create a form that takes all the
activitys an puts it neatly down on site in checkboxes so user can
select activtys.this will be linked to form mail.i would like the
activitys to be seperated by the country they r in?

Some Users Can't Enter Info Through My Form To My DB
I set up a comment page on my site and most users can enter comments. the page refreshes and shows the comments below. however, some users can't enter comments. what should I be looking for to resolve this?

Validating Form Info Before Inserting It Into Database
I have been trying to create a PHP application where you can add customer contacts to a MySQL database.

Now, my problem began when I created a form where the user can add in a customer's name and info to the database. In an effort to alert the user that they may be adding a customer that is already setup in the database, knowing that some of the customers may have the same names, e.g. there is more than one Bobby Ray Brown, I decided to add a script that queries the "customers" table in the database and searches for all results that match the input from the user. Code:

PHP Displaying Info Input On HTML Form
I'm in an exercise where I've created an order form in HTML. The form displays properly and allows me to input certain test order info just fine. The relevant lines in the HTML form are: Code:

Getting Form Info Into A Mysql Select Statement
I'd like to get user input from an html form into a mysql select
statement. Here's where I'm stumped:

$result = mysql_query("SELECT * FROM dept WHERE notes LIKE
'%search-string%'",$db);

I need to get the user's input into the '%search-string%' section, but I
do not understand how to do this. I can hard-code a specific search
string and it will work, but I want the users to be able to dynamically
define the search-string. So, I created a basic html form and used the
post method to grab their input, but now I can't insert that input into
the mysql select statement. Any ideas? I think it should be easy, I just
don't know how to do it. I've tried this:

$result = mysql_query("SELECT * FROM dept WHERE notes LIKE
'%$_POST["search"]%'",$db);

But it doesn't work. Below is the form in html and the php file:

<html>
<title>Search Test</title>
<head>
</head>
<body>
<form action="search-db.php" method="POST">
<p>Enter Your Search: <input type=text name=search></p>
<input type="submit">
</form>
</body>
</html>
-----------------------------------------------------------
<html>
<body>
<?php
$db = mysql_connect("localhost", "Anonymous");
mysql_select_db("computers",$db);
$result = mysql_query("SELECT * FROM dept WHERE notes LIKE
'%surplus%'",$db);
echo "<table border=1>
";
while ($myrow = mysql_fetch_array($result)) {
printf("<tr><td><b>%s</b></td></tr>
", $myrow[notes]);
}
echo "</table>
";
?>
</body>
</html>

Upload And Email Form Info At The Same Time
I need to upload something and also have an email sent at the same time after filling out a form. So they will fill out a form, decide what they want to upload and then hit the submit button and it will upload the file to my directory, where I can get to it, and then it will also email me the information I had them fill out in the form at the same time. Is that possible? What code would I use?

Taking Info From A Form, Saving It In A DB And Writing It To A .css
What I need to do is take "site info" from a form, save it to a database table called siteinfo, and then write style information based on the variables. Code:

File Form - Keep Local Path Info On Reload
Is there a way to retain the local path info for a file form when the page reloads?

Using Form To Post Info And Pic's (Warning: Unable To Fork)
I have created an admin form which allows the admin to update info and pic's to his site but I am having trouble with the update_pic script. When I pass along the form to the php script it gives me the following error message:

"Warning: Unable to fork [C:WINDOWSTEMPphp30.tmp /full/path/to/joesauto/images/anime_dvd_icongif.gif] in c:inetpubwwwrootadd_data.php on line 39"

This is line 39: exec("cp $picture /full/path/to/joesauto/images/$picture_name");
This is the form I used which was taken from this site. Code:

Dynamic Form
I have one user table in my MySQL database and this is linked to a user type table containing 3 types of user. Each type of user will be required to give a different amount of data when registering.

Basically I want to create one registration form for all types of users but only show the form fields that are relevant to the individual user type. The user type will be selected from a pervious page containing a list menu with the 3 user types that is sent via GET to the registration page.

Dynamic Form
I need to create a form that takes a number that the user enters, and
duplicates a question the number of times the user entered. For
instance, if the customer enters 5 on the first page, when they press
next the form generates "How old are you?" 5 times on the page. The
customer will answer all 5 questions then press next. Finally, all the
local variables get dynamically created and written to a database.

I have already taken care of dynamically creating the question five
times. Using a simple WHILE clause, this generates the correct number
of questions. What I am having an issue with at this point, is how to
dynamically create the local variables.For instance, for the question
"How old are you?" I would need a unique variable for each instance;
using something like $Age(n). So that for five times, it would
automatically created variables $Age1 through $Age5. I have carried
over the number to the submit page by creating the variable $Number
and passing it along as hidden button on the form. $Age'$Number'
seemed to work for creating the variable, but $_post["Age'$Number'"]
doesn't work for referencing the global variable. I would need some
way of looping through and dynamically creating the variables.

Dynamic Form
I had to make a form for someone, with 42 questions each question had different form-elements. I was typing and coding for almost 3 hours..!! lets say we would make a form (formmaker.php) to dynamicly create a form with multiple questions: on the formmaker :

-first we have to enter the number of questions (max 100)
-then we have to type the question(s) in (an) input field(s)
-then we would have to select a type of answering field (textbox, checkbox, radiobuttons, file, dropdown etc. )

-it would be nice if we could select to make the question mandatory or not.
-if we choose for checkboxes or radiobuttons , it would be nice to know how much of them (no limits here !) ok..limit it to 30

-when we have selected...for example..15 checkboxes, they have to dynamicly appear on the formmaker.
-for each checkbox or radiobutton, we have to enter a value.
-finaly we have to add an email adres to each question !!! (and a BCC field) (this way, we can use one form and split and send the data to multiple recipients..!!)

-also we have to be able to dissable or enable a question. (if dissabled, it wont show on the created form..

A nice template to show a filled in form is preferable.. It would be nice to store everything in a database tabel. (for each new form a new tabel in the database) question1 id active(yes/no) questiontext fieldtype mandatory(yes/no) radio_or_checkboxvalue1(rocv1) rocv2 rocv3 rocv4 rocv5 etc.... sendto_email bcc_email
I started with the code already...here it is: Code:

Dynamic Form Value Modification
I was wondering if and then how to dynamically update form variables without having move between webpages

I am developing a print quoting system for a company and I want the options in list boxes to adapt based on the values of previous selection in the form. However it must happen immediatly without the whole page having to refresh.

For example if a person chooses paper size to be A4 then the next drop down list must only have options available for A4 pages.

I thought I would need to use Javascript for this but I can't find out how to access the server side mysql database so I get the feeling Javascript is the wrong option.

The whole site is programmed in php but php is server side so I don't don't think its possible using php specifically.

Dynamic Form Selects
How do you make dynamic for selects in php? It is in regards to a modify type scripts im writing in php/mysql.

So regular select drop downs look like so:

<select name=genericselect>
<option value="1" selected>1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>

right, well if I was pulling info from a database, how would I make is so that the 'selected' value is dynamic and comes from the database? Im sure theres a simple way of doing this.

Form With Dynamic Questions
I've a mysql table where i stored a list of questions. My php script
executes a query which yields a different number of questions every time; i
used the loop function to create an input field for each question in the
form; and dynamically referencing each input name with the question number
i.e. question 1 is called q1, question 2 named q2, and so on.
The data is submitted using POST. I then try to retrieve all the answers by
doing a loop and using something like echo '$_POST['q'.$n.'']' except the
syntax doesnt seem to work.

Dynamic Form Update
I have the following form in which i need to updateitems.
The problem is that i do not know how many elements will be in the form
(generated dynamically)

eg
<input type = "hidden" name ="id1" value="1"><input type ="qty1" value ="1">
<input type = "hidden" name ="id2" value="2"><input type ="qty2" value ="1">
<input type = "hidden" name ="id3" value="3"><input type ="qty3" value ="5">
<input type = "hidden" name ="idn" value="n"><input type ="qtyn" value ="1">

how do i generate an array for a foreach loop to update the values in PHP
so that i can use it to create a Update query
eg
///begin loop
$sql = "UPDATE `table` SET `qty` = `$qtyn` WHERE `id` = `$idn`";
// end loop

Dynamic Form Items
I am trying to create A form that its fields will depend on a
form menu.
for example.
/***********************************************/
<form name="form1" method="post" action="">
<select name="select">
<option value="1">option 1</option>
<option value="2">option 2</option>
<option value="3">option 3</option>
</select>

Text field 1<input type="text" name="textfield">
Text Field 2<input type="text" name="textfield2">
Text Field 3 <input type="text" name="textfield3">
Text Field 4 <input type="text" name="textfield4">

<input type="submit" name="Submit" value="Submit">
</form>
/***********************************************/
When the option 1 is selected only the textfields 1 and 2 to appear,
when option 2 is selected only textfields 1 and 3 to appear and so on... any
combination I would like.

I tried puting the textfields in "if" statments but i don't like it. its too
messy PHP and HTML code.
Any Ideas of how this could be done better ? If someone did something
similar before and has a relative link it would be good as well.

Dynamic Form Pulldown
I'm building a form and need to have the options in a pulldown menu pulled from a mysql database, i understand the basics of sql and have used forms before, i just need to see an example to get me on my way.

Dynamic Form Processing
Im writing a script for processing a form created by a csv file. this form is created through a loop, where $num is the place in the loop. Code:

Dynamic Form Fields
I want to have it setup so when the user clicks this link a value is sent via get and that value is put through a for loop to generate an additional form field: Code:

Dynamic Form And $_REQUEST
My current project needs to run on both windows and linux. I figured out that windows needs $_REQUEST to read the form elements. This worked well until parsing a dynamically built form with checkboxes named: cb0, cb1, cb2, etc.

I can't figure out how I can use $_REQUEST to read the form elements, when I try $_REQUEST[$i] for example all values of the array elements are 'cc'. No idea where this comes from as cc is never used as a value?

Form Field Dynamic Population And PHP
I have a form that dynamically generates a drop down from a table column called suppliers.

Products supplied by each supplier vary so what I want to try and achieve is that once a supplier has been selected a second drop down on the same page is populated with data from the same table / different column with that suppliers products.
(I am trying to avoid refreshing the page)

I have not supplied any code at this stage as I am not sure whether PHP is capable of doing this by itself or whether javascript would need to be incorporated.

POST Form To Dynamic Page Name
I've got a simple form with an HTML OPTION block. I'd like to POST the
form to a page whose name is based on the OPTION they select.

So for example say the user selected this option, I'd like to POST the
form to a page named "memory.php".

echo "<option value="memory">Memory Utilization</option>";

Reset Dynamic Search Form
i have a search form that has a set of checkboxes and a set of select boxes. the checkboxes correspond to a select box and activates the select box once checked. when i submit the search form to display the results on the same page, the elements are echoed back into the form so the user can see what search criteria he/she search for: Code:

Identifying Dynamic Form Fields
User goes to page which is a form that asks for some basic info regarding returning products for credit/exchange, and also asks for how many products are going to be returned. Upon submitting, a return authorization form is presented to them with the specified number of product fields. I now want to take the input from this form and email it to myself, as well as, display a confirmation page to the user. The problem I have is a can't say, for instance, echo "$field_name"; because field_name will get created dynamically after the user specifies how many products to return. For example, say the user says 5 products, this will generate a form with field names like:

return_code0 inv_num0 qty0 product0 cre_exch0 stockout0
return_code1 inv_num1 qty1 product1 cre_exch1 stockout1
return_code2 inv_num2 qty2 product2 cre_exch2 stockout2 and so on....

These get created with a for() loop. Once this form is submitted, how can I address the field names? Code:

Dynamic JS Form And $_POST Array
I have a form that I am altering after page load with javascript. Basically I have a button that inserts another text field into the form which the user can fill out. Its for a calendar, and I'm allowing them to optionally add multiple days for an event. Each box that is created has the same name with [] on the end to make it an array.

When I view the post array with print_r($_POST), only the first textbox's value shows up. This is the only textbox in the form when the page loads.
Simplified example:

<form name="calform" action="process.php" method="post">
<input name="startday[]" type="text" class="bordered" size="25" />
<input type="button" onclick="add_one_more()" value="Add another date" />

// if the user hits the add button it adds this input field after pageload

<input name="startday[]" type="text" class="bordered" size="25" />

</form>
And here's what I'd get from that form

Array
(
[startday] => Array
(
[0] => test1
))

A button inside the form basically adds another <input> tag between the <form> tags. Why isn't PHP seeing the data?

Dynamic Form Option List
I want to create a dynamic drop down option list in a form, but I just can't wrap my head around this.

Both of the below scripts work as intended, but how do I make the mySql query results work with my existing script? Yes, I know I must replace the "$options = array" part in the top piece of code, but I need a little more guidance than that. Code:

Dynamic Form - How To Set Values Of A List
I have a form with a list/menu in it that is populated with records from a database. The items in list#2 are based upon what is selected in list#1.

I have been able to use a combination of php and javascript to get it to work, but the javascript reloads the page to get list #2 to refresh - and that clears out any other fields that have been filled in. Instead of javascript being called for the 'onchange' event for list #1, I'd rather it call php when list#1 is changed and so reset the values in list#2.

OPTIONS:
1. I thought I could have a php function that is called (i.e. onchange="<?php reload();?>" but I can't figure out how to set the values of the list from within the php function. How to reference form objects with php?

Putting Info Into A DB / Passing Info Between Pages
I have run into an issue...I have posted previously, but my scenario has changed.

Here is the situation...

If a user clicks on a link ('abc123' for example) I want to insert into my database some predefined information about 'abc123' - I have assigned a value that is echoed in future pages for 'abc123'.

So, what I need is some mechanism to, when a user clicks 'abc123', have a pre-defined username and password be entered into the database. I need this so future pages can utilize the session values.

How To Process Dynamic Form Field Names
Let me start by saying I don't have a lot of PHP experience, and am just starting to fumble my way around some of this stuff... I'm sure this has been asked a number of times, but after 2 days of searching the internet, I just haven't found a solution that makes sense, so I am hoping someone here can help me.

I have a pretty simple project schedule sort of web page that lists a number of tasks & 4 dates associated with each task. (planned start, planned complete, actual start, actual complete.

The page is built dynamically based on what is in a mysql database, and the dates listed are form fields, with the intent that a person with access can change any number of these dates.

Each task has an id associated with it, so when i build the form, I name the form field <task_id>-<date type>. so, for example, for task id = 10 I have 4 related form fields:

10-planned_start
10-planned_complete
10-actual_start
10-actual_complete

This basic pattern is repeated for all the tasks (up to 100 right now, but it could grow slightly).

Once all the form fields have been updated, and the user clicks submit I want to update the data in the database with the appropriate data.

So, my questions is:

1) How can I process this form, when I don't know what the names of the fields are going to be, and/or how many fields there are?

2) Is there a good way to identify only those fields that have changed and do updates on only those fields, or am I "stuck" updating all the records, even those where the dates have not changed from when the form was built?

How To Get A Dynamic Javacript Form Variables Seperated In PHP
PROBLEM: I have this form that allows the user to dynamically create
additional fields (see javascript code bellow). I am trying to retrieve
the values entered into these fields from my php script. I ultimatly
need to pick out the variables and place the values into my php script
page. I have worked with a little code I found on php.net (see php code
below), but I wan unable to grasp the knowledge on how to seperate the
variables in the address bar. Please reply.

QUESTION: How do I create variables in my php script from my dynamic
javascript form?

PHP CODE:
foreach($_GET as $name => $value) {
print "$name : $value<br>";
}

JAVASCRIPT CODE:
<HEAD>
<!-- Begin
function createForm(number) {
data = "";
inter = "'";
if (number < 16 && number > -1) {
for (i=1; i <= number; i++) {
if (i < 10) spaces=" ";
else spaces=" ";
data = data + "URL " + i + " :" + spaces
+ "<input type='text' size=10 name=" + inter
+ "url" + i + inter + "'><br>";
}
if (document.layers) {
document.layers.cust.document.write(data);
document.layers.cust.document.close();
}
else {
if (document.all) {
cust.innerHTML = data;
}
}
}
else {
window.alert("Please select up to 15 entries.");
}
}

Dynamic Form Option Diapearing On Submit
when i submit one option field after inserting a option value and an amount the previous one i had done disappears causing me lose all the information that i had typed in and i was wondering how i could keep the information alive as well as keep the newly created form fields from diapearing, PHP Code:

Update A Ststic HTML Form To Dynamic
I have a form which I now want to be more dynamic. The datbase tables are builtbut I cannot get the fields to populate.

When a member selects an age group from the first select statement and the dates that age group are scheduled to play a match are displayed in a second select statement. When both select ions have been made the rest of the form is displayed and can be filled in and the database updated. Code:

Dynamic Fill Form Fields Depending On Dropdown Box
This question has probably already been asked, but let me ask again

I have a mysql database to which I connect with my php scripts. The
database contains articles. Name, Unit_Price and Reference

Now my client needs to order 5 items, click a button and a table with 5
lines and 3 columns appears (until now easy)

In the first column is a drop down box with a <select > and <options> in
which I store all possible names.

I would like than whenever the client changes one of the boxes (in my
case there are 5) the Unite_Price column and Reference column in the
line he just choose get automatically updated

Dynamic Dropdown And Hardcode Dropdown In Select Form
I have plenty of examples of dynamic dropdown choices but none of hardcoded dropdown choices. The ultimate goal is to have a job with various tasks and to track the status of those tasks for a given job. I've used one of the tutorials here to begin the process. Below is the code I have to add work on a given task. Perhaps I actually need to "Update" a job as opposed to "add".

But the problem of the moment is I can't seem to hardcode one set of my options. This is the code I have: PHP Code:

I Need Info...
I want to write a very simple PHP script that just picks random images from a directory, you know what i mean. So I'd like to know where I could find information about this in the PHP manual maybe?

PHP - SSL Info
How do i know if ssl has been enabled in a WAMP configuration using PHP ?

Looking In $var For Certain Info
I pulled certain collums from my database. The value of the collums is either Y or N. I want to figure out on each $var how many Y's there are. I don't care how many N's.

At the end I'm going to add up all the Y's of all the VARs for stats. Whats the best way of counting Y's in a $var?

Server-Side Form Submission - Form Submits To Form, Which Autosubmits. BAD!
I have a php form from which the user fills out their name and address and clicks "Submit".

The form goes to a page that stores the data in a mySQL database, then, using hidden fields, populates another form and actives with a javascript onLoad=submit() to send the information on to the final destination.

I cannot control or edit the final destinations web page, which is why the interim page is needed.

What I would like is for the user to fill out the form, and upon submission have the data recorded into the database and have the data passed on in a "form like way" on to the final destination BY THE SERVER, not by the use of a hidden form page that auto submits.

Any suggestions?

Here is the interim page's code below:

<?
$link = @mysql_connect($db_host_name, $db_name, $the_decoded_password) or die;
@mysql_select_db($db_name) or die;

$query = "INSERT INTO web_link VALUES ('', '$a', '$b', '$c','$d', '$e', '$f', '$g', '$h')";
$result = @mysql_query($query) or die;
?>
<html>
<head>
</head>
<body onLoad="document.contactme.submit();">
<form name="contactme" method="post" action="http://www.test.com/cgi/storethisdata" >
print "<input type="hidden" name="first_name" value="$first_name"><br>";
print "<input type="hidden" name="last_name" value="$last_name"><br>";
print "<input type="hidden" name="email" value="$email"><p>";
print "<input type="hidden" name="phone" value="$phone"><p>";
?>
</form>
</body>

</html>