How Do You Pass A Value From A Drop Down List?
I am completely new to this. I don't understand how to receive a value from a drop down list <select> menu. I have read many tutorials and none of them explain the process of receiving the sent data.
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Q. How do I create a dynamically-generated drop-down list for use in an array. I'm using PHP with a MySQL database (through phpMyAdmin) My database table is called com_courses, and I want to pull the distinct 'title' fields and have them appear as a drop down menu for the user to select in a form. Here is my array, with (at the moment) manually-entered 'titles' (which I now need to be dynamically generated from my database field: 'com_courses.title' array ( "coursetitle", "Course Title:", $EXTRA_SELECTLIST, array ("Report Writing", "Recruitment & Selection", "Presentation Skills", "Essential Telephone Skills", "Time Managememt", "Customer Care", "Other"), 0 ), I am not an experienced programmer, but can play around with php to customize programs. I've read up on arrays (I bought a "Programming with PHP and MySQL" book, but it just stops short of this problem). I can't figure this one out.
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PLEASE HELP - Drop Down List Related Question
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Can anyone out there give me a pointer regarding creating a dynamically-generated drop-down list connected to an array? And is that question as clear as chocolate spread? Here's what I've got. I'm using PHP and MySQL database. I'm customizing some calendar software, and I want the user to fill in a form by selecting a title from a drop-down list, generated by my MySQL database. However, the program I'm customizing uses arrays, which is where I'm stumped. What do I need to add to this code to make the array of titles(eg "report writing" etc) come from my database, rather than the manually-entered values that you can see here. The field I want to pull from is called com_courses.title array ( "coursetitle", "Course Title:", $EXTRA_SELECTLIST, array ("Report Writing", "Recruitment & Selection", "Presentation Skills", "Essential Telephone Skills", "Time Managememt", "Customer Care", "Other"), 0 ), I hope it's not cheeky to ask this, BTW I bought a book on Programming with PHP and MySQL, but it doesn't answer this question,
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I have not learned Javascript,just copy & paste & revise <script language="JavaScript"> function confirmDelete{ re = confirm("Delete or not?(yes,cancel)"); if (re == "0"){<?php $re1 = 0;?>}else{ <?php $re1 = 1;?>} <!--the upper line will cause the confirm windows disappearing--!> return 0; } document.writeln(confirmDelete()); </script> <?php echo "$re1 = $re1"; ?> 1. How to pass the value "re" in Javascript to $re1 in php 2. How to revise to make the confirm window appear and pass the value correctly.
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I have a series of forms I have been working with using session ID's and session variables. I need to convert this to a series of forms where cookies might be turned off so the URL needs to carry the session ID. Question : If I add the session ID to the URL that is passed, can I still use session variables or do I need to change the way I code the variables altogether?
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