How To Get Last Insert ID In MYSQL Table
May I know how to retrieve the last inserted ....
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I am having and issue getting this code working. It seems rather simple but I cannot figure out why only one sql statement is exectuing and the insert statements the other 2 are not exectuting and updating the other 2 tables. I need to do this. I need to update one table, then from that I need to retrieve the mysql_insert_id or just get the id of the last record in the tabe. There is an auto increment column that gets assigned a unique id each time a record is inserted. I need this id number then I need it to place data into 2 other tables that will use this value as a reference. here is the code:
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I've got a form in which a couple of the address fields can be empty when the form is submitted... I haven't actually managed to get the Insert statement to work yet (see other post..), but I know this seems to also be causing problems. I have set up the table fields for these 2 address form fields to be Yes under the NULL column, but it still gives the almighty: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' , London, W1, UK, 9991, 007, 'warstormer@hotmail.com'' at line 1 Code:
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I'm trying to have my php script insert into 2 tables at once, it's for a picture database. Is it actually possible to insert into 2 tables at once? If so what would the sql statement look like.
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it seem like mine coding din work. [php]<? include("checkin.html"); $conn=mysql_connect('localhost','root','') or die ('Could not connect to server'); $today = date("Y.m.d"); mysql_select_db('hms', $conn); $ok = mysql_query("INSERT INTO check_in(ID,room_no,datein)values ('$ID','$room','$today')", $conn); if( $ok ){ $up = mysql_query("UPDATE studtable SET checked = 'checkin' where [ID] = '%ID'); if(mysql_affected_rows( $up ) == 1) { echo'Checked IN!' }else { echo'No such student to check in' }} else { echo'Check In FAILED, please check again'}?>[php]
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i managed to get bits a pieces and managed to get this script to nearly work. I put together this script which a)gets a no. of fields to create 2) creates those fields 3) on submission it checks for blank fields & may display error msg 4) also it checks in the db for duplicates & may display error msg 5) if all good it submits to db. Here comes my dilemma. 1, 2, 3 and 4 work fine however the final part 5 doesnt work at all. 5 works if 3 and 4 are taken away for some reason. I am sure there i am missing something. Can someone please take on the challenge and direct me to where i could be going wrong. PHP Code:
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I want to build a questionnaire with php. My problem is that the second page where i insert the results into the database doesnt work. Code:
Mulitiple Table Insert
I have a table that when you add a new department it will add the name to the table and assign the row and id based on an auto_increment column. From there you need to get the value of the last insert id. SO what I did was use the msql_insert_is() function. and assigned it to a variable. I then used that variable in my next query because this vaule is a forigen key in another table. Here is my code it should be exectued if you where to post this page with the value of $department_id = "" then the section of script in question will execture. Essentially need it to grab this id number and then place it into 2 more insert statements that should execute immediately after the first insert statement. Then only insert id that I would need is the one produced in the first insert statement what an auto increment value is assigned to the same table as the department_name Code:
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I'm trying to do two queries at once utilizing data from a form. I'm creating a new row in one table, and I need to reflect the ID number and other supplementary data to an existing record in another table. Is there a way to string two queries together so they execute at the same time? Here's what I've been trying so far: Code:
Multiple Table Insert
I have a table that when you add a new department it will add the name to the table and assign the row and id based on an auto_increment column. From there you need to get the value of the last insert id. SO what I did was use the msql_insert_is() function. and assigned it to a variable. I then used that variable in my next query because this vaule is a forigen key in another table. Here is my code it should be exectued if you where to post this page with the value of $department_id = "" then the section of script in question will execture. Essentially need it to grab this id number and then place it into 2 more insert statements that should execute immediately after the first insert statement. Then only insert id that I would need is the one produced in the first insert statement what an auto increment value is assigned to the same table as the department_name Code:
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I am trying to populate data from an array into a table, but i cant figure out what i am doing wrong. //mysql query $sql = "SELECT charge_location.dept_code, charge_location.week, Sum(charge_location.total_hrs_paid) AS sum_of_total_hrs_paid, Sum(charge_location.hrs_non_chargeable) AS sum_of_hrs_non_chargeable FROM charge_location GROUP BY charge_location.dept_code, charge_location.week"; $result = mysql_query($sql); $num_results = mysql_num_rows($result); //populate the stats_table for($i=0; $i<$num_results; $i++){ $row = mysql_fetch_array($result); mysql_query("insert into stats_summary values( ($row[dept_code]), ($row[week]), ($row[sum_of_total_hrs_paid]), ($row[sum_of_hrs_non_chargeable])) "); } PS i get no errors when it executes, just fails to populate the table.
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How Do You Insert A Value From Drop Down List To SQL Table?
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The following lines of code don't return an error but they also do not insert the row into the database: $SQLText="Insert into member (MailingID, MemberID, [File As], EMail, LetterID, AudienceID, DateSent, Sent) Select $MailingCode, $row[0], '".$row[5]."', '".$row[6]."', $LIDToInsert, $AIDToInsert, '".$DateSent."', 1;"; print '<br>'.$SQLText; $rs_upd=odbc_exec($link, $SQLText); if (!$rs_upd) die("Couldn't update database"); I've tested the resulting $SQLText string in Access directly and it works find there so this must be a PHP or ODBC issue.
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I have a script that loops through an image directory to create a table of thumbnails. I want to start a new row after every fifth thumbnail. I assumed there was a function which identified whole numbers, but alas, there doesn't seem to be. How do I produce a short version of my long, working version below. PHP Code:
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I have a MySQL database with 2 tables in it. products and prices.. Products has a field in it called 'prodno'. Prices has a field in it called 'prodid'. There is one of each item in products and each product has it's own unique 'prodno' There are multiple instances of each product's pricing in prices.. One for each price.. So if a product had multiple prices depending on quantity it would have an entry for each price.. Example: id = 1 prodid = 7001 qty = 300 price = 12.5 id = 2 prodid = 7001 qty = 400 price = 15.5 I was wondering if I could query the database getting info from the products table but sort it according to the prices in the prices table. Kinda like doing a "SELECT * FROM products" ordering it by the lowest price value from each item.. This is all very confusing to me, and I'm the one writing it. Let's try one last time.. Query the database selecting * from products (I plan on using all the info in products) and ordering them by the lowest price for each item in the prices table. I've tried sorting the results of just a basic SELECT * FROM products using Javascript and PHP but with pagination in the results it makes it a bit hard.
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I have a system from a company called ProTx they provide online credit card transactions. I have their PHP code, and have had to change some parts of this to work correctly but am getting stuck on this part. This code, is part of a page that sends off some variables to their server and expects a response. I am able to send the variables, and get the response but I want to put them into a database so that I have all refunds seperate from all orders. PHP Code:
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I can't figure why an INSERT query won't work. This is the table: downloads ---------------- id - int(10) - auto_increment category - char(1) file - text date - varchar(20) user - varchar(50) desc - text These are the variables: $category = "1"; $file_name = "cow.gif"; $date = "0000-00-00 00:00"; $login = "fresh"; $desc = "Bertha the cow."; This is the code: PHP Code:
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Ok... i want to insert info into a db using php and mysql... I can connect to the db using most of this code the only thing i am having trouble with is the 'mysql_result'.... If anyone could help. that would be great... thanks. This is the code im using... my sql statement is fine but im not sure what php code to use... <?php $db = mysql_connect(sql,username,password); $sql = "INSERT INTO tblMyTable (name,address) VALUES ($strName,$strAddress)"; $res = mysql_db_query(username, $sql) ***here is my problem... what goes here? mysql_result($res,0); ***that was my guess but its not working.. ?> I couldnt find the code in the manual.. If anyone could help that would be great thanks
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