PHP :: How To Response Immediately When I Select The Drop-box List

Select From Drop List To Fill Table Column With Text -- HOW ?
I want viewers to compare state laws on a single subject.

Imagine a three-column table with a drop-down box on the top. A viewer
selects a state from the list, and that state's text fills the column below.
The viewer can select states from the drop down lists above the other two
columns as well. If the viewer selects only one, only one column fills. If
the viewer selects two states, two columns fill. Etc.

I could, if appropriate, have a separate htm page with the text for each
state -- california.htm for example. When the viewer selects California from
the drop down list, the column below would "fill" with California.htm.

Or, I could conceivably use a text or mysql database with two fields for
each record: state_name and law_text -- but it would probably be easier to
use separate htm files, since there will only be about 20 states involved,
and the "database" would never have a large number of records.

The table width would be 100% and each cell would be @33%

My site is designed with FP 2002 and runs on Apache/FreeBSD. I have just had
Apache-ASP installed but I have not yet configured or used the module.

Drop Down List
I want to read a directory for available files and then get the filenames and put them in a drop down list. Whatever the user will select will be the value of the variable $selected. I already found the code to read directories: Code:

Php And Drop Down List
I am coding an email form on a site. A user enters their name and contact email and then selects from a drop down list to which particular email the message should be sent: User1, User2, User3. Then the user types out a message and hits submit. My problem is that I am unsure as to how to grab the selection in the drop down list and pull the selection and place it like this: "$selection@domain.com". Here is the php code:

Drop Down Box To A List Box
i have this drop down box that displays the relevant info from the table that its loading. But the drop down box isn't quite so wise to use if there hundreds of rows. So what i wanted to do was change it to a list box instead ... would any one know how to do that? Code:

Drop Down Select
I am working on a small script to load all members names into a drop down list, this I have acheived so far. What i'm looking to do is make this so that when I select a name from the list I have a submit button which opens up a member edit form which I have created. Code:

A Dynamic Drop Down List
I need to create a dynamic drop down list. By this i mean that the webpage html form = select style will recieve all the values as based on a query to a mysql database. I have no problems quering the data base with PHP, But i need to make some kind of for loop that will add a new value to the selct form for each result from the database. my thought process go like this.

1. call data base to guery. (no problem)

2. make variable variables that will be created according to the number of results (these variables must be created according to results of query, not a problem i think)

3. make a form like this

<form action = ***** method = post>
<select name = ******>
<option value = "This is a query result"> This is a query result> //This is the part i need to using a for loop and variable variables
</select></form>

so my problem is part 3, cause is this all done in PHP, or if i had all these variables, can i do this in HTML? Can i make a for loop in PHP that would break into HTML during these parts?

2 Drop Down List Using MYSQL
I have a model table with the following fields: MODEL_ID, MAKE_ID, NAME.
And a make table with the following fields:
MAKE_ID, NAME.

The first drop down list (make) to select a make of a car i.e. Chevrolet, Ford. When a make is selected, then all the model for that paticular make appear in the second drop down list.

PHP And MYSQL Drop Down List
I need a script to create a drop down list which has vehicle makes. The vehicle make list should feed a vehicle model list so when I select a make all the models for the make appear in the model list. I have a make table which has MAKE_ID, make NAME and a model table which has MODEL_ID, MAKE_ID and model NAME.

I tried using a script using javascript array but wherever I have a query that pulls the NAME from the database there's always a carriage return after the NAME which messes up the javascript array. I'd rather do it all with PHP if possible. If not please give me one that works and I don't have to spend hours troubleshooting.

Very Simple Drop-down List...
Hi! I'm having a problem with a very simple drop-down list since the
page comes out with no elements in the drop-down but giving no errors.
This is the code:

<form name="year_search_form" method="post" action="results.php">
<select name="select_year" id="select_year">
<?
$query="SELECT * FROM table ORDER BY year";
$result = mysql_query($query) or die ("Error in query: $query. "
..mysql_error());

while ($line = mysql_fetch_array($result)) {
print ("<OPTION value=".$line['year']."></OPTION>"); }
?>
</select>
</form>

Drop Down List From An Array
I want the array to contain a valid year of birth for anyone between the ages of 16 and 80. I'm pretty sure this code is correct.(though it might be a bit sloppy to all you pros) Code:

Drop Down List With Months
I am trying to create a drop down list that has December 2006 as the first option and then goes up month and years till the current month and year (September 2007).

Putting List Into Drop Down
I am working on a directory of businesses which has 8 main categories and each category has several sub-categories. Example: Dining is a Category with Pizza, Fast Food, Chinese, etc. I have the sub-categories brought up in just a list on the left side of the page and when the user clicks on a sub-category it takes them from client_list.php to client_filter.php only showing businesses in that sub-category of the main category.

So only pizza places listed under dining. However, I want to change the list to a (form) select box and then have the user click on the sub-category they want and then it takes them to the client_filter.php page to list only those bussinesses in that sub-categorie. So after that long explanation how do I change my code to do that. Here is my current code:

Insert From An Drop-down List
i have a table in wich i've inserted city's name.then i have an registration form in wich i want to display an dropdown list with the cities from the table, and if one city is selected to be automaticly added in the second table. how can i do that?

Custom Drop Down List
I am trying to get categories from the database and show them in a drop down list showing root category then their sub category underneath. Code:

Folder List Drop-Down
I am developing a PHP/MySQL project and as part of my initial setup and configuration scripts, the users can select a skin for the application, and a variable value ($skin) is updated to set the current skin, this works ok on it's own, but currently the user must manually type the skin name in a free-text box.

Ideally this needs to be a drop-down option box, and I would like this to be populated by listing the sub-folders within the '/skins' folder, so that it's always up to date. The folder structure looks like this:

/skins
/skins/skin1
/skins/skin2
/skins/skin3

How can I use PHP to generate a list of the current sub-directories in 'skins' and populate the drop-down list?

How Do You Pass A Value From A Drop Down List?
I am completely new to this. I don't understand how to receive a value from a drop down list <select> menu. I have read many tutorials and none of them explain the process of receiving the sent data.

Drop Down List Of Months
I am trying to create a drop down list with 12 months as the contents. I need to be able to determine what the latest month is and then put the 11 months before into it (in the correct order). For example, it is September 2007 obviously at the moment, so that will need to be the last and latest month in the list. The other 11 will be in reverse order going back to August 2006.

Select Data In Drop-down Box
I have a two text box and one select box.

two text box will be filled with date values. (in the form of
dd-mm-year)
First text box is called "start date"
Second is "end date"

Thus, I want to put dates between "start date" and "end date" in select
box.

Is there any way to put automatically in option field?
My idea is, first calculate the date difference
and then, add date till startdate + difference.

Chained Drop Down List Working Example
Could some PHP guru please help me? I looking for a good working
example of chained dropdown list.

2 Drop Down List Where Need Query Database
there is drop down list box linked to the database where it displays the state of a country and once the user clicks on the particular state, there purpose to be radio button displaying the locations available of that state, the location displayed in radio buttons are from the database. currently the source code i'm using is (which uses a submit button to query the database but i does not want the submit button it purpose to work using Code:

Dynamic Drop-down List In Array
Q. How do I create a dynamically-generated drop-down list for use in
an array.

I'm using PHP with a MySQL database (through phpMyAdmin)

My database table is called com_courses, and I want to pull the
distinct 'title' fields and have them appear as a drop down menu for
the user to select in a form.

Here is my array, with (at the moment) manually-entered 'titles'
(which I now need to be dynamically generated from my database field:
'com_courses.title'

array (
"coursetitle",
"Course Title:",
$EXTRA_SELECTLIST,

array ("Report Writing", "Recruitment & Selection", "Presentation
Skills", "Essential Telephone Skills", "Time Managememt", "Customer
Care", "Other"),
0
),

I am not an experienced programmer, but can play around with php to
customize programs. I've read up on arrays (I bought a "Programming
with PHP and MySQL" book, but it just stops short of this problem). I
can't figure this one out.

Populating A Drop Down List With The Year
i'm trying to loop the years from 1960 - 2010 with the function get_year() below:
PHP Code:

Automatically Drop Down A List Of Phrases
I would like to know why when I go to a site like altavista.com and start to type in a phrase to search on does it automatically drop down a list of phrases that I have previously searched on, and how do I get rid of these from showing when I go to search.

I removed all of my cookies that were stored in my temporary internet folder. Is there somewhere else I should be looking. I am using IE 5.0 on a windows 98 machine.

How Do You Insert A Value From Drop Down List To SQL Table?
I am a bit new to PHP and SQL so this may seem like a dumb question.

I have already created a drop down list as part of a form which is
automatically populated with values taken from a separate database. When a
user goes onto this page and either leaves the default value or selects a
value from the drop down list and presses the submit button, I would like
that selected value to be stored into a database which I have already
created in SQL.

Just to let you know that I can do the above using a text field but just
don't know how to do it with drop down list.

If your going to explain any coding then it may help if I give you the names
of certain items that are involved.

Database is called "Company"
Field within database is called "Name"

Load Runner, Drop Down List
Can anyone send me the script for supplying the values in drop down
list of the web page?
I have couple of drop down list controls in my web page. I need to
supply multiple values for each dropdown list in my script. How can i
do that? can you send me the script for this?

PLEASE HELP - Drop Down List Related Question
I am creating a dynamic dropdown
list using a code snippet(Section A) as below:
Section A:
$sql_query=mysql_query("SELECT DISTINCT semester, year from
schoolproject_pics ORDER BY year
DESC");
echo "<select name="semester" onchange="GoTo()">";
echo "<option value="$semester">-Semester Year-</option>";
while($data = mysql_fetch_array($sql_query)){
if($data[semester]==@$semester && $data[year]==@$year){
echo "<option value
selected="$data[semester]">$data[semester]:$data[year]</option><BR>";
}
echo "<option
value="$data[semester]">$data[semester]:$data[year]</option>"; }
echo "</select>";
mysql_free_result($sql_query);

The 'GoTo()' Javascript re-draws the same page with the chosen values
of 'semester' and 'year' so that
the values can be recovered by $_HTTP_GET_VARS, stored in two hidden
variables and then used in
another query to create another dynamic drop-down list, as in code
snippet (Section B).

$semesternow=$HTTP_GET_VARS['semester'];
$yearnow=$HTTP_GET_VARS['year'];
if((isset($semesternow) and strlen($semesternow) 0) and
(isset($yearnow) and strlen($yearnow) 0)){
print("<input type="hidden" ID="semesterchosen"
value="$semesternow">");
print("<input type="hidden" ID="yearchosen"
value="$yearnow">");
$sql_query2=mysql_query("SELECT DISTINCT school from
schoolproject_pics
WHERE semester='$semesternow' AND
year='$yearnow'");
echo "<select name="school" onchange="GoMore()">";
echo "<option value="$school">-- School --</option>";
while(list($school) = mysql_fetch_array($sql_query2)){
echo "<option value="$school">$school</option>";
}
echo "</select>";
mysql_free_result($sql_query2);

Now the question:
When the page is re-drawn, how can the values of semester and year
previously chosen, be displayed in the first drop down list. I tried to
do it using the following, but it does not do anything:

f($data[semester]==@$semester && $data[year]==@$year){
echo "<option value
selected="$data[semester]">$data[semester]:$data[year]</option><BR>";
}

How To Display .txt Info Into Drop Down List
list out all the items from a file (data.txt) into drop down box for user to select.

Eg. inside (data.txt) has
Apple
Orange
Strawberry
etc...

How do I create a drop down list that can call out everything from data.txt (until end of file)??

Select Table From Drop Down Menu
I'm trying to select a table to submit form data to from a pull down menu. How do I submit the table along with the input data? I know I need to modify this line ($sql = " INSERT INTO $dnc "; )somehow to use the table selected in the pulldown menu. Code:

Default Select Drop Down Menu?
I have a drop down menu populated via a script that pulls all categories from the category table. However, when a user clicks to view a specify category (i.e. Toys), I want the drop down menu to display toys as the default value. Code:

Auto-setting A Select Drop-down
I have 3 select menus for dates, I need to be able to auto set (on load) which number in the dropdown is selected, for example, if the date I pass to the page is this:

01/15/2007

I would use explode("/", $date) to get each number, I know for a fact that the format will always be (month)/(day)/(year), so no worries with that, but then how would I make it so that January is selected automatically, as is 15th, and the year 2007, in the drop-down menus?

Multiple Drop Down List Problem And MySQL
I am trying to populate around 30 drop down lists via a single query to a mySQL database. The problem is how to make sure that each drop down list only display it's relevant data. for example the table is as follows:

Error Correction On Drop Down List & Sessions
Hi I'm doing a site at the mo and I have to do error correction on a form. I have most of it done except one or two bits. What I'm having trouble with is drop down lists. What happens is someone fills in the form, it's not done properly so it gets redirected back to the form. Everything works right except the drop down list. The sessions carries over alright but I can't get the drop down list session to work. It marks the session as selected but it's not displayed the first option is displayed. So if you picked Germany and America was first on the list. After being submited America would be displayed but Germany would be checked.

Here is what I got

Correction page

$_SESSION["country"] = $_POST["country"];
if($_SESSION["country"] == Ɔ'){
header("Location: /acc1.php");
}

Form page

echo ' <td><select name="country" id="country" style="width: 150px;">'
if (!isset($_SESSION["courtry"])){
echo '<option value="0" checked="checked"></option>'
}

$rslt = mysql_query($dscntry);
if($rslt){
while ($rws = mysql_fetch_array($rslt)) {
if (!isset($_SESSION["country"])){
echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
}
elseif(isset($_SESSION["country"])){
if($_SESSION["country"] == $rws["countryid"]){
echo '<option value="'.$rws["countryid"].'" checked="checked">'.$rws["countries"].'</option>'
// else{
// echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
// }
}
}
}
}
echo '</select>'

Dynamic Drop-down List With Array - Question
Can anyone out there give me a pointer regarding creating a
dynamically-generated drop-down list connected to an array?

And is that question as clear as chocolate spread?

Here's what I've got. I'm using PHP and MySQL database. I'm customizing
some calendar software, and I want the user to fill in a form by
selecting a title from a drop-down list, generated by my MySQL
database. However, the program I'm customizing uses arrays, which is
where I'm stumped.

What do I need to add to this code to make the array of titles(eg
"report writing" etc) come from my database, rather than the
manually-entered values that you can see here.

The field I want to pull from is called com_courses.title

array (
"coursetitle",
"Course Title:",
$EXTRA_SELECTLIST,

array ("Report Writing", "Recruitment & Selection", "Presentation
Skills", "Essential Telephone Skills", "Time Managememt", "Customer
Care", "Other"),
0
),

I hope it's not cheeky to ask this,
BTW I bought a book on Programming with PHP and MySQL, but it doesn't
answer this question,

Saving/Loading Data In Drop-down List
I have a drop-down list with set values. When there is a corresponding value in my database when the page loads I want the drop-down list to pick the appropriate value from the list. Instead it always defaults to the first value. Can anyone give me an example of how to do this?

Also, one time after adding a variable to a classes file this symbol: ï»¿ started showing up on all of my pages. Has anyone seen this before? I can't find any information on the web about it.

Populate A Drop Down List In A Form On The Basis Of A First Selection
I have developed a form to register a property in a db. The form needs the selection of a country and then based on that selection the selection of regions from the selected country. I have a program which allows selection of a country and then a region but it uses java script which I would like to avoid. I also just wanted one submit button if possible. Code:

Drop Down Menu Where The Items Are From A MySQL Select Query
I am just starting programming in PHP and wonder if it is possible to have a
drop down menu where the items are from a MySQL select query.

I am registering people for a weekend seminar and want to have a list of
valid weekends to choose from on the form.

Any pointers to scripts or PHP references that will help would be
appreciated.

I am using the book "Build your Own Database Driven Website Using PHP &
MySQL" to get me started, but also need recommendations for a general primer
to php.

Displaying Data From Mysql Database In A Drop Down List On Form.
I'm trying to do is display data from two different mysql tables from the same database in a drop down list on a html form. I have a fixtures table with the player1(userid), player2(userid), gameid, game, score1 and 2, what I want is to use the userid to get the players first name and surname from the members table (as it is a unique id), I need to do this bit before displaying it in the drop down. I think i need 2 querys to do this but when I have tried it it just echo's a blank value or the userid not the forname and surname that I want. I'm using the fetch_array function but just can't see where I'm going wrong, Code:

Select List
I'm creating a form that has three select lists. The first one has two values EMAIL and SMS. What I want to do is have the two other select lists (named EMAIL and SMS) work so that if EMAIL is selected only e-mail select list can be altered and vice versa with the SMS.

How can I do this? I know to use disabled in <select> -tag, but how can I check the what the value is (and the value changes) and then act acording to it?

Select List With A Loop
I want to accomplish a function that creates a select list with a loop of results from the DB, I have that, it is: PHP Code:

List Box Multiple Select
I am trying to create a drop down list that permits a person to select multiple items from the list and have the results posted on a results page. I am using Dreamerweaver MX, PHP and a MYSQL database. I was able to select multiple items but only the last selected item would be displayed. I tried to modify the list box code and now it returns nothing. Code:

Select List/Menu Using PHP And MYSQL
Here is my code:

<select name="country" class="sidelinks">
<?php
do
{
?>
<option value="<?php echo $row_AllCountries['country_ID']." ";?>"<?php if ($row_AllCountries['country_ID'] = $acountry) { echo "selected"; }?> >
<?php echo $row_AllCountries['countryname'];?></option>
<?php
}
while ($row_AllCountries = mysql_fetch_assoc($AllCountries));
?>
</select>

A few words to describe:
-$row_AllCountries['country_ID'](get from MySQL) is a unique country ID number
-$row_AllCountries['countryname'](get from MySQL) is the name of the country
-$acountry is the country ID number that i want to be selected when the form loads

I have all the values and country names named OK...the only problem is that when the form loads it selects the last country.

Displaying A List Of Categories From A Database In A Select Box
Could someone please tell me why this outputs nothing

<select name=categories>
<?
$cat_array = get_categories();
foreach($cat_array as $this_cat)
{
echo "<option value="";
echo $this_cat["category_id"];
echo """;
echo ">";
echo $this_cat["category_name"];
echo "
";
}
?>
</select>

==========================================================

function get_categories()
{
//get the list of categories from the database

$conn = mysql_pconnect("localhost", "user", "pwd");
$query = "select * from categories";
$result = mysql_query($query);
if(!$result)
return false;

$num_cats = mysql_num_rows($result);
if($num_cats == 0)
return false;

$result = db_result_to_array($result);
return $result;
}

//A function that returns a query to the database as an array
function db_result_to_array($result)
{
$res_array = array();
for($count=0; $row=@mysql_fetch_array($result); $count++)
$res_array[$count] = $row;

return $res_array;
}

Popup Window List Of Values To Select
What i need to do is bring up a popup window with a list of values(values looked up from the database). The user should be able to select one of the values from the list and the value then populate a text box on the calling form.

Insert Data From Multiple Select List
Am trying to insert data into a mysql database from a multiple select list. How would i do this? Code:

Retrieving Full Entry From Multiple Select List
I have a list box with multiple selects. I define the name as numList[]. I
get the values from

$picked = $_POST['numList'];

It retrieves values for all those selected.

If the entries are, say,
First
Second
Third

and the first and third are select then $picked[0] has "First" and
$picked[1] has "Third".
If, however, the entries are:

First one
Second one
Third one

Then the values are for $picked[0] and $picked[1] are "First" and "Third"
respecticely.
How do I retrieve the entire value and not just the first word?

Retrieving Contents Of Select List On Form Submit
On an HTML form, I have a select list that is fed dynamically with
detail records when the master record is displayed on the form.

There is also a second lookup list, and want to allow the user to
dynamically select from this list and add to the first list. I also
want the user to be able to dynamically remove from and reorder the
first list. I think I can do all of this with JavaScript.

The question I have, is how can I retrieve the contents of the first
list when the user submits the form? I need to get it back into a php
array so I can update and add the proper database records.

Dynamically Populate Drop-down List And Dynamically Include Html File
We have a drop down list on a PHP page, with several product names, and
when people click one item, we will refresh the same page with the
product name as parameter, and in turn we want to include a HTML file
into the content area of the same page.

I know it is recommended to put everything into database, but we want
the web site to be very "portable", so the drop-downlist and the
content should both in text files.

Let's say the drop-down list will be poplulated from the product.txt
file, and there will be a file for each corresponding item in the
drop-down list. From the user point of view, if he wants to add a new
product, he will just need to open the product.txt file, and add a new
line with the product name, "Laptop", then add a new text file named
"laptop" in the same folder which contains the HTML fragment to be
included in the content area.

What is the easiest way to do this?