List Weeks Of Year Using Calendar Function
I've been asked to design a small site which contains a page with a list of dates to show a visitor if accommodation (running from Saturday - Friday) is booked or available. Something like this:
2007
2nd Jan - 8th Jan - Available
9th Jan - 15th Jan - Available
16th Jan - 22nd Jan - Booked
23rd Jan - 29th Jan - Available
5th Feb - 11th Feb - Available
12th Feb - 17th Feb - Available
etc, etc
I'd like to dynamically create the list of dates using the php calendar functions and a mysql database so that each row (52 in total?) could be flagged 'booked' or 'available' allowing easy updating using a back end form. Ideally the page showing the list would have a link taking the visitor to another page showing the following year's dates. Each list would always show a year to view and always run from Jan to Dec.
View Complete Forum Thread with Replies
Related Forum Messages:
How To Display Calendar 12 Weeks In Advance?
I want to display 12 weeks in 2 weeks from today as a calendar. So if today is August 3rd, I want to see a calendar starting from August 17th + 12 weeks. (I could also use 3 months instead of 12 weeks, whatever is easier to code) Any idea on how to do that?
View Replies !
Calendar To Show Limited Months And Weeks
I'm looking for a simple PHP script/snippet, I've tried Googling but no luck as of yet. Basically it just needs to display 9 months: this month and the next eight months (and of course when it turns to May, April will disappear and another month will be added on the end). It only needs to display Monday to Friday for each week. The table cell for each day needs to say the day number, e.g. 12.
View Replies !
Calendar Displaying A Whole Year?
I'm reasonably new to php and have been looking everywhere for tutorials on creating calendars. I've found so many, but they're all relatively the same, where they only display one month at a time. If anyone could point me in the direction off a tutorial where I can create a calendar to display a whole year in one go, instead of one month that would be absolutely great. I'd quite like a tutorial instead of a simple download, because I can learn more by going through it all. I don't need any fancy stuff like events. It's litterally just a calandar with nothing on it but the dates.
View Replies !
Printing Full Year Calendar?
I use a calendar script, Keith Deven's PHP Calendar. I've modified it to incorporate events into it and everything works great. The problem I'm having trouble with is when I print the year long calendar. For some reason it only reads the dates in the database for the current month, in this case March and it outputs the same days for every single month. Code:
View Replies !
Printing Entire Calendar Year
I'm using Keith Deven's calendar and I'm having trouble showing the whole year. The code he gives on his site to accomplish this is: PHP Code: <table style="margin: auto"> <tr> <?php for($month=1; $month<=12; $month++){ ?> <td style="vertical-align: top"> <?php $weblog->printCalendar($year, $month); ?> </td> <?php if($month%3 == 0 and $month<12){ ?> </tr><tr> <?php } ?> <?php } ?> </tr> </table> I include the main source located in a file called calendar.php as well. Now I get an error: Code: Fatal error: Call to a member function printCalendar() on a non-object in I:ApachehtdocsAHS est.php on line 5
View Replies !
Make The Calendar Print An Entire Year
I'm trying to use the genious codes of a calendar script on my website... The source-codes and origin of this calendar is at: Web Site For Script How could I make the calendar print an entire year... Whilst also showing the pages to which days are linked? I have tried using the code the author has outlined on his page to no avail. Any suggestions?
View Replies !
Calendar Type List/menu
how do i do 3 list type menu one with the 12 months next with the days in that month and the year. so want i want is when people select a month the next list show the days as soon the pick the month.
View Replies !
Check Week Number In End Of Year And Begiining Of New Year?
I am creating a little own calendar. Now I want to add a "previous week" and "next week" functionality to the calendar. It is easy to take $thisWeek - 1; and $thisWeek + 1;, but there has to be a check wether it is the last week of the year and it should actually be a new year and head to week number 1. HOW do I make this kind of function? I use the following string names: $thisYear $thisWeek
View Replies !
Calendar Function Gets To 10-30 Then Keeps Repeating 10-30 ?
I need a function that takes the date and returns the week number of the year. For example you would pass the date 2005-06-19 and it would return 25. I started with a working calendar script and tried to tweak it to return the week number. It worked for a while then for some unknow reason (i must have done something) it would start repeating the date 10-30. Here is what I have so far. Also note that the find date code is not in place here. Code:
View Replies !
Calendar In Table Or Function To Print?
Creating "weekly log" of sort. The user enters data into a form, then submits it to a table. This tables contains the date the user entered the data and all the other information. The results of this table are displayed in "weekly" increments (Sunday - Saturday or Monday - Sunday) Here's my question... If the user HAS NOT entered any information for a particular day I still want to print out the "date" (ie: Sunday, December 25, 2005) If the user HAS entered data then I simply display the information in the appropriate date. Code:
View Replies !
Starting A Year Loop With Last Year
I have the following which loops through the present year and adds two more years on: However, I want it to be exactly the same but to start from last year rather than this year. Is this possible? Code:
View Replies !
Getting A Query By Weeks
Im trying to figure out how to write a query to get results by weeks. For example, If I wanted to see the results for this week, I would need to find the beginning of the week and the end of the week. The query Im wanting to build will only show the current week, but it will change dynamically as days go by. So whatever day you look at the list, it will grab that weeks worth of results. I think I can use the date('w') to get the day of the week and then either subtract it to 0 or add it to get the sum of 6 and then use those counts to modify the start and end dates. Or can date('W') be used where it gives me the week of the year? I dont know about using that one because I wouldnt be able to get any dates.
View Replies !
3 Weeks From This Date
I am having trouble creating a script that every three weeks will update itself. What I am trying to do is have the date change on a three-week basis. Example: Today's date is January 8th, 2006, and the set date is on January 21st, 2006. When the day is on January 21st, 2006, the page automatically says February 4th, 2006. How do I do this?
View Replies !
Select Two Weeks Of Records
ok - so i've got some entries with dates in my db. I thought i had it but its not quite there yet. If today is 20061017 and i want to look 3 weeks into the future its not as simple as addings 21 days. How can i get the month to change automatically after it reaches the last day of the month? Code:
View Replies !
Formula To Add A Number Of Weeks To A Date
I was trying to use the following formula to add a number of weeks to a date, where $b is the number of weeks. date('Y-m-d', strtotime($Expiry_Date)+$b*86400*7) However sometimes it added one day less than it should have done. $Expiry_Date was always a Saturday and sometimes the answer was a Saturday and sometimes the previous Friday.
View Replies !
Display Birthdays Coming Up In The Next Couple Of Weeks?
I wonder if someone could help a novice to create a bit of code that will display birthdays coming up in the next couple of weeks? I have a mysql database with a date of birth(dob) date field but unsure how to check that field against the present date I only have at present, and don't knoe if this is right? while ($row = mysql_fetch_array($result2)) { $dob=$row["dob"]; list($year, $month, $day)= explode("-", $dob); $birth_day = "$day"; $birth_month = "$month"; $birth_year = "$year"; } Obviously I only need the day and month values but is there a pre built function to do this for me?
View Replies !
Function List With Associated Extension
I want to create an application that will scan a series of .php files, look the functions availiable in them, and display which extensions it is using (don't know how to avoid user made conflicted name functions). Is there a table which has the name of the extension and the functions included in the particular extension..? Is there a way that I can get a new list if an extension upgrades and adds new functions..? And what about PEAR..? I don't really know how it works, but I think it adds some functions too. Can I do the same with the php extensions..?
View Replies !
ASP2PHP Function List Reference
PHP so I thought I would make a Reference List of some of the functions. Below is what I have so far. ASP Functions PHP Functions ==================== =============== Left(str,length) substr(str,start,length) Right(str,length) substr(str,start,length) Mid(str,start,stop) substr(str,start,length) Len(str) strlen(str) Trim(str) trim(str) LTrim(str) ltrim(str) RTrim(str) rtrim(str) UCase(str) strtoupper(str) LCase(str) strtolower(str) InStr(str,value) ---DON'T KNOW---
View Replies !
Function To Write Option List
i have problem with the following function by where i was not able to get the $id display from database. and i have no problem with $data. is there anything got to do with primary key? shouldn't be right? then it would be sytax error? but i checked for so many times but still can't figure out what's wrong with it. id tinyint(2) - primary key data char(100 ) function writeOptionList( $table,$field ) { global $connect; $result = mysql_query( "SELECT $field FROM $table", $connect ); if (! $result ) { print "failed to open $table<p>"; return false; } while ( $a_row = mysql_fetch_array( $result ) ){ print "<option value="$a_row[id]""; print ">$a_row[data] "; } }
View Replies !
Calling A Php Function From A Form Selection List
I have a function that will read records from the database and populate an area of my webpage based on a value selected from a list box. I have got it to work fine if the user hits a submit button but I was wondering if it possible to perform the function dynamically each time the user changes the value in the list box.
View Replies !
Function That Return A List Of Categories In Links
I have a class that has two functions. the first will return a list of categories in links and also attempt to put the category ids from the mysql_fetch_array() function into a new array to store all the ids. The second function attempts to create a new array which contains the total amount of users assigned to a category based on the array of ids that were previously stored. Basically in the users table the is a field called cat_id which is the id of the category they are assigned to. So i need to count how many users with the same cat id exist for all categories. Anyway here is my PHP. The returning of category links are fine, but the attempt at storing the ids is not. I suppose im trying to create a multi-dimensional array?? Code:
View Replies !
Debugging - Get A Stack Trace Or Function Call List.
I would like to get a stack trace or function call list. when an error occurs in a php script. what are most of you doing? Writing your own debugging or using things like xdebug (which i couldn't get working)? And if you write your own is there a way to get the filename and line number? Also, are people using try/catch statements? Coming from C++/java that is what i am used to, just curious as to what people are doing with php and any tips you might have.
View Replies !
Day Of Year Count
I have a script that reports that day on which a post expires as: 2000-06-12. What i would like to do is post it instead as: Expires in: 11 Days. So basically, I'm looking for a PHP3 way to do a Day of year Subtraction. I know with MySQL its: (TO_DAYS(Expires) - TO_DAYS(Current_Date)) is there a way to do it without going back into MySQL, using PHP3? OR how to i configure my Select so that it will automatically output "Expires" date as a the day count UNTIL expires.
View Replies !
Last Day Of Year Date Bug?
Guys, the line below just returned "Dec 07" as the date for one month back from today. Hardly life-threatening, but any thoughts? <?php print date("M `y", mktime(0, 0, 0, date("m")-1, date("d"), date("Y")));?> AS...
View Replies !
Date Plus 1 Year
I am writing the date to my database and would like a second field exactly 1 year from the date that row was created, i am using timestamp(6) for the date which is fine, but for the future date i dont really want timestamp because the rows get updated and consequently the dates. It is basically a membership scheme with one years use of an item so the second date will be the end of the subscription. Or possibly some other way round the problem.
View Replies !
Month Year
I am providing a drop down list to the user with values such as Oct-2004 Nov-2004 Dec-2004 n so on if the user selects nov-2004 the month november n year 2004 should get stored in my MySQL database.(precisely which data type should i use to efficiently store month as well as year? However if the current month is november the drop-down should not contain options such as october or september. How do I do this?
View Replies !
Year In A (****) Format
(1950) (1975) (2000) (2001) etc etc This sort of year will be somewhere in a one line string . How do i search for a year like this thats between 2 curved brackets. While i could use strpos to find the first curved bracket then then check if theres a ) five letters along. some sort of wildcard method would obviously be much better .
View Replies !
Year Week
i´ve two variables the year and the week (2003 and 5) that means the 5th week of the year 2003. now i need the start- and enddate of the 5th week of year 2003.
View Replies !
Same Day Last Year Problem
Today is Thursday 16-Feb-06. The same thursday last year is 17-Feb-05. Because I am comparing daily sales between years, I need to know the date of the same weekdayname as last year, so that I am comparing Saturdays with Saturdays, Sundays with Sundays, etc ie, 16-feb-06 goes to 17-feb-05 28-july-06 goes to 27-july-05 and so on I have tried all sorts of dateadd(��-01-01'...etc, and I am all out of ideas.
View Replies !
Select Year
How do I select a year if my date field is stored "yyyy-mm-dd". I tried the below and no records show. WHERE daysOff.dayOff= YEAR(��')
View Replies !
YEAR Database
I have a search I've created for a database. One of the options is to search by year ��',��',��', etc. The page: search.php?year=$year&news_category=$news_category isn't working if they leave the year blank. The first option in the drop-down form for news is set to value="". What I would like to do is if they select the value="" option for news to display all results, regardless of year, where news_category=$news_category My query is. SELECT * FROM news WHERE YEAR(news_date)=" . $_GET['year'] . " AND news_category = " . $_GET['news_category'] . "
View Replies !
Mysql Year
Datatype Category: DATE/TIME Datatype Info: A year in 2- or 4-digit format (default is 4-digit). The allowable values are 1901 to 2155, 0000 in the 4-digit year format, and 1970-2069 if you use the 2-digit format (70-69). MySQL displays YEAR values in YYYY format, but allows you to assign values to YEAR columns using either strings or numbers. (The YEAR type is unavailable prior to MySQL Version 3.22.) See section 6.2.2.4 The YEAR Type. The above is about mysql year type. So if I input the value is run say 1800, it will give me the 0000 even I set up the default value of that field (type: year) to be NULL. So for a valid year value, I need to test the range either "1901"<$input<"2155" "00"<$input<"99", otherwise, I will set it to NULL. Then I will not have the "0000" shown in my year type field.
View Replies !
Group By Year
I have a list of items in a db that has a date stamp column in the following format 0000-00-00. The list is getting long so I would like to out put the year first, and ask the user click the year to see the items for that year only. How do I scan my table and output the years only? Is it something like: PHP Code: SELECT DISTINCT YEAR(my_date) FROM mytable DESC.
View Replies !
Changing Year In Php
I recently purchased a ladder script and the problem is, the "Match Scheduler" shows the year as 2003/2004. I asked the owner of the script and I was told to edit the .php file that contains this information, but when I looked in it, I saw nothing that showed 2003 or 2004. Is there something I'm missing? I've included the.
View Replies !
Change Of Year
I have a script that pulls content for CURRENT month and PREVIOUS month from db. Now, it only considers current month two weeks into the month. So if today is Feb. 1, it'll use January as CURRENT MONTH, but if it were Feb. 15 it'll make FEB a current month. To get the right content I need a MONTH ($checkMonth) and YEAR($currentYear). Everything worked fine until the year change and moths started going from 1 again and the previous month became 12. I am lost as of now trying to untangle my own mess. I'm sure it all can be simplified a lot! I'm at your mercy, here's what I've got: Code:
View Replies !
Run Year In Loop
PHP Code: Date of Barth :: <select name="RegYear"> <?php for ($i=0; $i<=100; $i++) { SelectedYear=""; range (1900,date("Y")); } ?> </select>
View Replies !
Grouping By Year
I am having a hard time figuring this one out. I have a database of information that one column is a timestamp. I want the information displayed in groups by year, then month and date like: 2006 -9/16 -9/15 -8/3 2005 -5/14 -4/10
View Replies !
Year Months
<h3><?php echo $arrl["Byear"]; ?></h3> <ul class="rlinks"> <?php for($i=-3;$i<2;$i++) { ?> <li> <a href="agend_desporto.php?modifier=<?php echo($i); ?>"><?php echo(trata_month(date(m)+$i)); ?></a> </li> <?php } ?> </ul> and I want to separate the months for years if necessary. How can I do this?
View Replies !
|
TRACKER
