MySQL (DB) Result Sorting
I'm doing is taking results (fetching rows) from my mySQL database. But what I want to do is sort the results according to last name. So basically the table structure looks something like this:
id (primary key)
fullname
A example rows could be:
1
John Smith
2
Mary Jane
Now what I want to do is sort the results in PHP based on last name. I'm using the Pear DB for connecting to my mySQL database. Based on the example rows I gave, Mary Jane would go first, and then John Smith. How would I go about doing this? I was beginning to split the result based on spaces, and the last word to explode, but how would I truly do this?
View Complete Forum Thread with Replies
See Related Forum Messages: Follow the Links Below to View Complete Thread
MySQL Sorting
I'd like to do is divide results from a MySQL query over multiple pages, each holding a certain number of results. Now I have a PHP script that uses the MySQL command LIMIT in the query to get # results at a time (which also means not all the results are returned every time, just a few, obviously this is a good thing for speed/load so I wanna keep it that way). The MySQL manual states that if you use LIMIT # with ORDER BY, MySQL will end the sorting as soon as it has found the first # lines Ok I could've posted this on the MySQL forum first but actually I was wondering whether someone has a solution in PHP for this?
PHP/MySql Sorting Difficulties
I have written a sorting engine which displays non expired records, but im having difficulties getting it to work. It was working fine until I added pagination, and now it seems to have gone to pot. The script works by getting todays date, and based on the users selection from the drop down menu, calculates the number of pages, and records the users sort preference. The correct number of links to different pages are then generated, and the pages are populated based on the users sort preference, or so I thought... The first page of results is sorted correctly, but on the second and subsequent pages, this isnt always the case. This causes results to be appearing in the wrong order, or not at all in some cases. Ive included my source code, if anyone see's anything which is glaringly obvious, or feels like giving me a hand fixing this id very much appreciate it :) <!-- This is the HTML Form where the user selects if they wish to sort or search for records --> .......
MySQL Query Sorting
I was curious if there is a way to sort out duplicates in data returned by an query. I have a database, basically a mailing list database and when I query the database for the emails addresses, I get the returns echoed to the page as expected, but it looks like some people have signed up multiple times. So I have duplicates in my echoed list. Is there a way to have the data sort so the duplicates do not appear, and the email will only appear once on the list? I don't want people to be getting 5 of the same emails from me.
Paginating And Data Sorting With Php/mySQL
I have a main menu full of information which is paginated 20 records per page. I'm trying to make the query so that the user can sort the data by links located at the top of the page. "What's My Problem?" - It works, when I select the link it sorts by whatever I have selected as I want but... The Problem - It only sorts one page and doesn't continue on, when I click page two the values are reset. This is a new operation to me so if anyone could offer a suggestion I'd appreciate it. The Question - How do I sort paginated data and make it so the data stays sorted throughout the 20 or so pages?
Sorting Arrays Retrieved From A MySQL Db
I am trying to make a news system. I have done it, but the news are listed with the last on at the bottom. This makes it kind of troublesome to read the latest news when you enter the site and there are a lot of news items, cause you would have to scroll down. PHP Code:
Listing/Sorting MySQL Output
I have a page that gets a list of magazine article titles stored in a MySQL database. The output is sorted and formatted all nicey nice. I am wondering if there is an easy way, or some trick, that I can use to place headings in between the category listings for the articles. Allow me to explain. Let's say there are 15 articles 5 of them are category A; five of them are category B; the last five are category C. Right now I am sorting them fine. With one database call can I insert an image or text header (and possibly an <a href>) between A and B to denote the next category? I can do it with several database queries, but I'd like to avoid that if possible.
Dynamic MySQL Nav Menu Sorting
I have this dynamic menu and I want to change the order of the menu items... I added a column in the database wich has an integer value for ordering the menuitems. But the only way is by hardcoding them into the database. I would like a way to sort them with drag-and-drop or with up/down arrows. Do you think that except PHP & MYsql I will need Javascript as well ? Any ideas how to do that ?
Sorting A Table Into An Array In Mysql
Can someone tell me how to sort a table using a while function. This is what i want to do. I have table that has 17 fields, the first two are id and date and the rest of date..but what i want to do is take the data and sort it by the date and put the rest of the data under that date. example: date Data date Data I asume the array will look like this result[0][0] result[0][1] result[1][0] result[1][1] and so on .....
Getting Result From Mysql
I am using this code to get some data from a mySQL database. Which seems pefectly valid to me. Here it is: Code:
MySQL Result Resource
I want to build a function that, depending on the input, will either return the results from a MySQL query or do something else and return one of several messages. My problem is checking the return value to see which is returned. Is there a php function that checks a variable to see if it is a valid MySQL result resource? I looked through the manual and couldn't find anything.
MySql Result In Textarea
I have a script to display mysql query results in a table. I'd like to display the results in a scrollable textarea. Is there a way to do this?
Returning 1 Result From MySQL
I know the usual way of receiving results from MySQL, useing a while loop e.g. $sql = "SELECT * FROM users WHERE email='joe@hotmail.com'"; $result = mysql_query($sql,$connection); while ($row = mysql_fetch_array($result)){ echo $row["firstname"]; echo $row["lastname"]; echo $row["email"];} BUT, if I know they only 1 result is going to be returned, is there a way to do this without using a while loop? So if I only wanted to get only the firstname of the person with email joe@hotmail.com. can I do this without a while loop or do I have to use one?
Total Result Php Mysql
PHP Mysql limit the result to 5 I can display the 5 results using a do & while which it ok. I want to list the total or all the results without using a do or while this is so I can combine the results and remove duplicate words from the total results I.E. Do & While row result 1 this is the top 2 this is the bottom 3 this is the middle 4 this is the end 5 this is the finish This is what I want to do: result this is the top this is the bottom this is the middle this is the end this is the finish modified result:: this is the top bottom middle end finish
Invalid MySQL Result
I keep getting the following two errors: Warning: Supplied argument is not a valid MySQL result resource in /home/xxx/public_html/articlepro/newarticle.php on line 75 Warning: Supplied argument is not a valid MySQL result resource in /home/xxx/public_html/articlepro/newarticle.php on line 84 Here's the code which I think is causing the problem. PHP Code:
Modifying MySQL Result - But Not The DB
How can I modify a MySQL data set returned by mysql_query? I am basically doing a while loop over the rows, changing one field, and then doing a mysql_data_seek back to the beginning of the set before returning it. However, later calls to mysql_fetch_assoc still return the orginal data, meaning that (I assume) I am changing a copy of the data rather than the result set itself. Taking the reference (i.e. $record =& mysql_fetch_assoc($result);) did not help. I have read a large quantity of the posts in the php.net site, googled, and read my PHP books - but have come up short on this one. Yes, I know it's better to simply modify the DB. However, I'm working with an existing code base which is very complicated, and want to cherry pick one very well tested feature by making a change in the result set only under special circumstances.
Substr() With A MySQL Result?
I am trying to limit the amount of text exhoed from a MySQL database column. From reading around it appears the substr() should be able to do this Code:
Mysql Result Into Array?
I have a shopping cart script sending info to a processor. I need to send the qty's and item name's in some sort of string via a single variable to the process form. i.e. (3) Hipster Turnips, (6) Butter Milk Baby Brains, (2) Super Freaks Code:
Result From Mysql Into Foreach?
when using mysql_fetch_array($result) I usually toss that into a while loop like so while($row = mysql_fetch_array($result)){ ... } however I was wondering if there was a way to put it in a foreach statement like so foreach(mysql_fetch_array($result) as $row){ ... } Is that legit? Will this work?
Linking To A MySQL Result
I had it the other day but now altered the code for my real database and it stopped working. Here is the first page which lists the 10 most recent news stories: <?php require ('get_connected.php'); $sql = mysql_query ("SELECT title, story_id FROM news ORDER BY story_id DESC LIMIT 0, 10"); while ($row = mysql_fetch_assoc($sql)){ echo "<a href='view.php?id={$row['story_id']}'>" . ucwords(strtolower($row['title'])) . "</a><br>"; } ?> And here is the page that should be displaying the news story based on story_id selected by the user.....
Using MYSQL Result To Send Mail
I have wrote a program to load a number of email address from the MYSQL database. And I have use "$mail = mysql_query("select email from user;",$link_ID); Now, I want to use mail() to send email to those e-mail account I got. What should I do for this?
Date Formatting From Mysql Result
always in the past I have done my date formatting from the query like so: DATE_FORMAT(dateField, '%W, %b %e, %Y') AS realDate I have tried formatting the straight date result with PHP like so: having fetched results with mysql_fetch_array, $newDate=$result["dateField"]; $formattedDate=date($newDate, 'm/d/y'); This doesn't work and simply returns the unformatted date as it is stored in the database.
Invalid MySql Result Resource
I have written a php script to search a MYSQL database and with the line: $result = mysql_query ("SELECT * FROM table1 WHERE first_name LIKE '$first_name%' AND last_name LIKE '$last_name%' " ); The next line, if ($row = mysql_fetch_array($result)) { , gives me the error message "supplied argument is not a valid MySql result resource"
Display Of Mysql Table Result...
I have a mysql table of articles with fields: - recordID - department - articleTitle - articleText Using PHP, I'm attempting to get the results of the table to display as follows: Department 1 - articleTitle 1 - articleTitle 2 - etc.... Department 2 - articleTitle 1 - articleTitle 2 - etc.. I figure I should use a while loop but can't figure out how to exit/reset the loop when a new 'department' is encountered in the $result.
Replacing Array With Mysql Result
I wanted to repalce the following line of code $data = array(40,21,17,14,23); with for($i=0;$i<$numrows;$i++) { //print(mysql_result($result,$i,2));print("<br>"); array_push($data,mysql_result($result,$i,2));} where mysql_result($result,$i,2) is the value and when i print it displays the values. But $data array is the Y axis value for drawing a chart. Here I wanted to replace the hard coded value with values from mysql but the second code does not function. Does anybody have idea how can I replace the $data array or what may be the problem with my coding The first one works but the second one does not work but in both cases it does not display any error.
Same Mysql Query Doesn't Always Return A Result
We have no access to a mysql NG on my provider's server, so we ask here: We have a long query (long in text) with a UNION between 2 select. We have been informed that some times the query doesn't return any result. We have tried on our server and we always get a result. BUT, trying on the hosting server, many times the query doesn't return any result and doesn't get any error. Any idea ? does Union have any problem ? how to check if the query failed ? My hoster said that sometimes the table can be locked (if the server is overloaded) and then mysql doesn't return any result, but this seems to me an aberration. the query takes about 0.0050 sec to execute when it doesn't return any result, and 0.030 when I get results
Mysql Search Close Result
I've to find in a table the "closer" result given some text. Here is a little example: given the text "Batman socks" I've to find the best matching result in choices like: -"mickey socks" -"robin socks" -"batman black socks" ->this should be found -"batman wallet" -"batman" or given the text "leather shoes" I've to find the best matching result in choices like: -"socks" -"shoes" ->this should be found -"pants" -"shirts" -"leather wallet"
Mysql Problem Understanding Result And Id?
I can't understand why the output from this is not ƍ'? $query = "SELECT * FROM contacts"; $result = mysql_query($query); echo mysql_result ($result, 7, "id"); I also tried adding "ORDER by id" but I still can't get it to echo 7.
MySQL Result Printing In For-loop
I have a script that count and print every week in a selected year. Now i want to connect this to the returned result from a MySQL query. Code to explain what I am trying to accomplish: Code:
How Do I Return Result Of Mysql Row Deletion
The data entered by a user on form 1 on page1.php is posted to delete.php to remove that row from a table. After the SQL operation the user is returned to page1.php. How can I determine the success or failure of the SQL operation so I can display an appropriate response message to the user?
Different Result For MySQL And PHP String Comparison
I have issued an SQL statement "SELECT email FROM mailing_list ORDER BY email ASC"; By right the order of the email should be sorted from smallest to largest. However I got different results when I used record that was ranked higher to compare against record that was ranked lower. I got opposite results. Code:
Mail A Set Of Addresses From A MYSQL Result
I'm populating a field in MYSQL that collects email addresses for a certain topic and saves them like this: mail1@mail.com|emailaddress2@mail.com|email3@email.com - Basically what I'd like to do is explode the data, and set up a mailer from PHP that informs each of the addresses individually that there has been an update to the topic. I *don't* want each of the mail addresses to be visible to all the recipients on the list, so simply inserting the data into the TO: field won't do, because then all the addresses are visible, causing security concerns. Code:
Allow The User To Sort A Mysql Result
So what i got going on is a database that has, things about a video game, including the image location. what i want to do is have a nav bar up top, so the user can select a differnt way of sorting the mysql result, from like ASC to DESC, or sort by genre.
MySQL Result Can't Be Returned From Class Method.. ?
I've been messing around with objects and classes lately and can't figure out why this wont work. I have index.php which uses the pbMySQL class (pbMySQL.class.php) and methods: Code: include("lib/pbMySQL.class.php"); $db = new pbMySQL; $db->pbMySQL_open("localhost","user","pass"); $db->pbMySQL_useDB("database"); // $q=$db->pbMySQL_query("SELECT * FROM pbn_news ORDER BY id DESC"); $q=mysql_query("SELECT * FROM pbn_news ORDER BY id DESC"); if(isset($q)) { while($row=mysql_fetch_array($q)) { print $row['name']."<br> "; } } else { print "query returned FALSE"; } $db->pbMySQL_close(); My problem is that when I use the first query method (which is commented; uses the pbMySQL_query() method) I do not get the mysql result returned, but if I use the same query without the method, I get the result. Here is the method from my class: Code: function pbMySQL_query($query) { if(!isset($this->conn) || !isset($query)) { print "Error : argument(s) missing.<br> "; } else { $this->query = mysql_query($query,$this->conn) or die("Error : query failed.<br> mysql said: <i>".mysql_error()."</i><br> "); if(isset($this->query)) { return $this->query; } else { return FALSE; } } } The method returns FALSE and I don't understand why. Is it something in particular I have to do different when using a class?
Error Message - 0 Is Not A MySQL Result Index
Could anyone explain what this might mean? Warning: 0 is not a MySQL result index I have a simple form set up where a user types in a keyword and then a page is displayed based on the keyword. See below: HTML page: <html> <head> <title></title> </head> <body> <form action="submitform.php3" method="GET"> <p><strong><font face="verdana, arial, ms sans serif" size="1">id#</font>:</strong> <input type="text" name="keyword" size="15" maxlength="25"> <input type="submit" value="Go!"> </p> </form> </body> </html> submitform.php3 page: <?php mysql_connect ("localhost", "username", "password"); mysql_select_db (dbname); $result=mysql_query("SELECT $url FROM table WHERE keyword LIKE '%$keyword%'"); list($url)=mysql_fetch_row($result); ?> The concept is really simple. A user types in an keyword and that page is displayed. There is a database set up with a table that has two columns. One is "keyword" and the other is "url" For example row 1 the keyword is abc, and the url is http://www.abc.com.
How To Get Mysql Query Result Into Temp. Txt File
I did a lite search in the archive but didn't find anything specific to my problem. Here is what I am trying to do: I've got a table with about 25k entries of company addresses. I need to be able to pull specific data out of the table and put it in a temporary text file and then display the result in the browser for the user to save locally. The query part and the format of the data is all simple enough but I am having trouble figuring out how to get the data from the query into a temporary text file and then displaying that file. here is what I whipped up but it obviously doesn't work: Code: <? $tmpfname = tempnam("/path/to/file/", "FOO"); $list = mysql_query("select * from FH_LIST where State='AK'"); while ($list_results = mysql_fetch_array($list)) { $data = blah blah blah; fwrite($tmpfname, ".$data "); } fopen($tmpfname, "r"); fpassthru($tmpfname); ?> I get an error message saying: Warning: Supplied argument is not a valid File-Handle resource (referring to $data).
Setting A Maximum Limit On A Php/mysql Result?
I am using PHP and MySQL to do this script. I want to have a table that contains only numbers for data and then add them all up as a result to display and that I have accomplished with no problem and then I want to display a percentage of that number to the public however that also I have accomplished with no problem using round()... The problem is I am trying to set a maximum number that it displays. I want it to display 1-500 no matter what the number is or the decimal it may have is provided it doesnt exceed 500 but once it does I want it to display 500 as the limit so even if it is say 674 I want it to only display 500. How would I go about doing this? The sql I am using for the adding is SELECT SUM which works just fine and I am using round( $total_number *.15, 2) to display the percentage number of 15%.
PHP4/MySQL Formatting Result Set Output
I am currently coding a Photo Gallery project in PHP 4 and using MySQL to store information about the uploaded photos. My problem is that I am trying to get the images to be displayed in multiple columns accross the page, say 4-5 columns of small thumbnail images instead of all in one column as I have at present.
Warning: MySQL: Unable To Save Result Set In
I'm running PHP/MySQL/Apache on my home system on Windows for testing purposes. As a run a specific query, I get this error: Warning: MySQL: Unable to save result set in C:apachehtdocsfinal.php on line 129 Warning: Supplied argument is not a valid MySQL result resource in C:apachehtdocsfinal.php on line 132 I know the second result means the specified query cannot be found, and I'm guessing for some reason MySQL cannot save the query. Here is my code. PHP Code:
Mysql+php Newbie: 2 Tables As 1 Result To Count... How To?
I need to check for username in 2 tables (user_basic and user_temp) before I can alow incoming user to register new username, well, here is what I had before I'w created temporary table: $uname_check = mysql_query("SELECT uname FROM user_basic Where (uname='$uname')"); if (mysql_num_rows($uname_check) > 0) { ... but now, that mysql_num_rows isn't "working"... now I have this lines: $uname_check = mysql_query("SELECT uname.user_basic,uname.user_temp FROM user_basic,user_temp Where (uname='$uname')"); if (mysql_num_rows($uname_check) > 0) { ... and I'm geting this worning and my script fails in checking: "mysql_num_rows(): supplied argument is not a valid MySQL result resource in..."
Warning: MySQL: Unable To Save Result Set
I'm getting this error: Warning: MySQL: Unable to save result set in /www/hosts/wwwroot/mainPage.php on line 11 Here is what line 11 looks like: $articles = mysql_query("select entryID from articles where siteID like 'senior'");
MySQL Result To Real Array In Function
I'd like to create a function which input is the result of a mySQL query. The output should be exactly the same, only not a mySQL result array, but a 'real' array. So it should also get the fieldnames returned by mySQL and use those as keys. I can't get things to work properly: it should return a multidimensional array, like $result_array[1] = array( [field1] => field1 value, [field2] => field2 value, etc. ) somehow my result is (with code below) $result_array[1] = array( [0] => field1 value, [field1] => field1 value, [1] => field2 value, [field2] => field2 value, etc. ) +++++ code ++++++ $get_res= mysql_query(QUERY); if( $res = mysql_fetch_array( $get_res ) ) { do{ $result[] = $res; }while( $res = mysql_fetch_array( $get_res ) ); }; foreach( $result as $key => $value ){ print_r($value); };
Assign MySQL Function Result To PHP Variable
I know to use: mysql_fetch_row($result) to convert a row from a SQL query result set into an array for use with PHP. but in the case of SQL queries that return one value, such as calls to MySQL functions, is there another PHP mysql api function I should use. For example, right now I use a "workaround" technique from PHPBuilder: $result=mysql_query("SELECT COUNT(*) FROM tablename"); list($numrows)=mysql_fetch_row($result); Rather than using this "workaround" code is there a way to simply assign the result of the MySQL function query to a variable. $result=mysql_query("SELECT COUNT(*) FROM tablename"); $numrows=mysteryfunction($result);
MySQL, Check If The Result/row Is Present/not Empty
I am using the following code to check if the result is present if not display error message. $num_rows = mysql_num_rows($result); if ($num_rows == 0){ header(error.php ) /// redirect to error message } however this does not seem to work. BUT! when i do this $num_rows = mysql_num_rows($result); if ($num_rows > 0){ header(error.php ) /// redirect to error message } then it works but for the wrong reason. i need it to redirect to the error message if their is no result e.g. no rows displayed.
MySQL Result Is Empty, But The Query Is Correct
I have written a script that grabs info from a database, and outputs it to a form. I figured I'd tidy things up a bit, and use a function to handle the queries, where I had previously hardcoded almost the same query several times. Code:
|
TRACKER
