MySQL Result Resource
I want to build a function that, depending on the input, will either return the results from a MySQL query or do something else and return one of several messages.
My problem is checking the return value to see which is returned. Is there a php function that checks a variable to see if it is a valid MySQL result resource? I looked through the manual and couldn't find anything.
View Complete Forum Thread with Replies
See Related Forum Messages: Follow the Links Below to View Complete Thread
Invalid MySql Result Resource
I have written a php script to search a MYSQL database and with the line: $result = mysql_query ("SELECT * FROM table1 WHERE first_name LIKE '$first_name%' AND last_name LIKE '$last_name%' " ); The next line, if ($row = mysql_fetch_array($result)) { , gives me the error message "supplied argument is not a valid MySql result resource"
Supplied Argument Is Not A Valid MySQL Result Resource
Before I get in trouble, I have searched extensively for this one, in the PHP Docs, online etc. I have a simple page: <?php $un="jim"; $pw="jim"; $db="localhost"; $link = mysql_connect($db,$un,$pw) or die("Could not connect: " . mysql_error()); $sql2 = "SELECT * FROM eib.book ORDER BY bookid"; $op = mysql_query($sql2) ; $num= mysql_numrows($op); ?> When I run the page I keep getting this error: Warning: mysql_numrows(): supplied argument is not a valid MySQL result resource in C:Program FilesApache GroupApache2htdocseibphpitemadd2.php on line 34
Warning: Supplied Argument Is Not A Valid MySQL Result Resource
<? Warning: Supplied argument is not a valid MySQL result resource if (mysql_num_rows($result) >0 ) !Didnt have this problem before session_start(); if ($username && $password) { // if the user has just tried to log in $db_conn = mysql_connect("localhost", "*****", "*******"); mysql_select_db("micro_db.adf", $db_conn); $query = "select * from users " ."where name='$username' " ." and pass=password('$password')"; $result = mysql_query($query, $db_conn); if (mysql_num_rows($result) >0 ) { // if they are in the database register the username $valid_user = $username; session_register("valid_user"); } } ?>
Mysql_num_rows(): Supplied Argument Is Not A Valid MySQL Result Resource
I thought for sure I had this query correct, but for some reason, it isn't working. I get this error: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in...... I am working on a search for my DB. Nothing advance yet, just one input field for the search keyword. Here is my query:
Mysql_fetch_array(): Supplied Argument Is Not A Valid Mysql Result Resource
i recieve this error from this part of the code: mysql_fetch_array(): supplied argument is not a valid mysql result resource it's returning a long text from the database which is about 200 characters long. <?php if ($_SESSION['is_town'] = 1){ $query = "SELECT usemap FROM town WHERE town_id = " . $_SESSION['townID'][0]; $db_result = mysql_query($query); $db_usemap = mysql_fetch_array($db_result); echo $db_usemap;} ?>
Mysql_free_result Return Error Saying Not Valid Mysql Result Resource
im trying to do a query which takes rows of large amounts of text data and displays them one after another. the size of the fields is causing the page to be massive in size. so to try and reduce this im trying to use mysql_free_result to clear the contents from memory. however its returning an error saying not valid mysql data when im certain that it is. is this because im using a while loop like this...? ($row = mysql_fetch_result($result)) { mysql_free_result($result); }
Mysql_num_rows(): Supplied Argument Is Not A Valid MySQL Result Resource
I've got the following error: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wbdfdart/public_html/wbdfforum/verwijder.php on line 13 verwijder.php 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 <?php include "connect.php"; if (isset ($cat) AND isset ($topic) AND isset ($message)) { $query = "SELECT user FROM reply WHERE id='$message'"; $exec = mysql_query($query); $result = mysql_fetch_array($exec); $owner = $result["user"]; $moderator_check_query = "SELECT * FROM moderator WHERE category=$cat AND user=$myid"; $moderator_check_exec = mysql_query($moderator_check_query); $moderator_result = mysql_num_rows($moderator_check_exec); if ($moderator_result == 1 OR $owner == $myid) { $moderator = 1; } else { $moderator = 0; } if ($moderator == 1) { $replydelete_query="DELETE FROM reply WHERE id ='$id'"; mysql_query($replydelete_query) or die(mysql_error()); $topicmineen_query="UPDATE topic SET replies='replies -1' WHERE id='$topic'"; mysql_query($topicmineen_query) or die(mysql_error()); echo "<script>location.href='index.php?cat=".$cat."&topic=".$topic."&page=".$page."'</script>"; } else { echo "<script>location.href='index.php?cat=".$cat."&topic=".$topic."&page=".$page."'</script>"; }} ?>
"Supplied Argument Is Not A Valid MySQL Result Resource"
this is one of the first scripts im writing completely by myself but its driving me crazy. the errors its returning are: Quote: Warning: Supplied argument is not a valid MySQL result resource in c:apachehtdocsquiz_chap12_view.php on line 16 There are currently in the table: PHP Code:
Another Invalid Result Resource
Sorry to ask a debugging question, but I've been fooling with this thing all day, and I can't see what the problem is. $query is passed from search form: $result = mysql_query("select id, date, title, text, reviewer, email, score, cover, url, url_title, hits, type, creator, release, upc, quote from one7_reviews where title LIKE '%$query%' OR description LIKE '%$query%' OR creator LIKE '%$query%' OR url_title LIKE '%$query%' ORDER BY title ASC"); $num = mysql_num_rows($result); I keep getting "Supplied argument is not a valid MySQL result resource "
MySQL Error - Supplied Argument Is Not A Valid MySQL-Link Resource
I am getting the error Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in /home/server7/public_html/71/arranholloway/database4.php on line 7 I tested my code on local computer and there were no problems, the error message only appeared when I loaded it onto my web hosters server. I'm new to PHP so its probably something simple but any help would be appreciated.
MySQL Query Resource Usage
Ok assuming that we are either using connection pooling or persistant connections, how much CPU power would be used up making say 100 queries in on a connection. What would be the resource difference between that, and making a query that returns 100 rows?
Not A Valid MySQL Resource Link?
I get this error: Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home/.grable/vzoom/virtualzoom.net/include/functions.php on line 10 Code:
Mysql Error - Not A Valid Resource
On some sites i am getting this error: mysql_fetch_array(): supplied argument is not a valid MySQL result resource The fix seems to be using a '@': @mysql_fetch_array() Why is it some sites or versions of php require this character? Should i always use it?
PDF Upload To MYSQL: Not A Valid Stream Resource
I am writing a law firm client management system. Part of my program allows me to upload a file to my website and to associate that file with a client so that the client can access the file over the web. I have successfully been able to upload .doc files, .gif files, and other file types using the script that I will post below. I have been successful in uploading files such as gif images and other small files. When I try to upload larger files, specifically a 4 mb pdf file, I get the following error: Warning: fread(): supplied argument is not a valid stream resource in /home/ddicicco/public_html/LMS/uploadtest.php on line 26 Warning: fclose(): supplied argument is not a valid stream resource in /home/ddicicco/public_html/LMS/uploadtest.php on line 28 code:
Not A Valid MySQL-Link Resource Warning
I am trying to find whats causing the following warning: Warning: mysql_close(): supplied argument is not a valid MySQL-Link resource in /home/php/public_html/mysql.class.php on line 15 Code:
Getting Result From Mysql
I am using this code to get some data from a mySQL database. Which seems pefectly valid to me. Here it is: Code:
MySql Result In Textarea
I have a script to display mysql query results in a table. I'd like to display the results in a scrollable textarea. Is there a way to do this?
Returning 1 Result From MySQL
I know the usual way of receiving results from MySQL, useing a while loop e.g. $sql = "SELECT * FROM users WHERE email='joe@hotmail.com'"; $result = mysql_query($sql,$connection); while ($row = mysql_fetch_array($result)){ echo $row["firstname"]; echo $row["lastname"]; echo $row["email"];} BUT, if I know they only 1 result is going to be returned, is there a way to do this without using a while loop? So if I only wanted to get only the firstname of the person with email joe@hotmail.com. can I do this without a while loop or do I have to use one?
Total Result Php Mysql
PHP Mysql limit the result to 5 I can display the 5 results using a do & while which it ok. I want to list the total or all the results without using a do or while this is so I can combine the results and remove duplicate words from the total results I.E. Do & While row result 1 this is the top 2 this is the bottom 3 this is the middle 4 this is the end 5 this is the finish This is what I want to do: result this is the top this is the bottom this is the middle this is the end this is the finish modified result:: this is the top bottom middle end finish
Invalid MySQL Result
I keep getting the following two errors: Warning: Supplied argument is not a valid MySQL result resource in /home/xxx/public_html/articlepro/newarticle.php on line 75 Warning: Supplied argument is not a valid MySQL result resource in /home/xxx/public_html/articlepro/newarticle.php on line 84 Here's the code which I think is causing the problem. PHP Code:
MySQL (DB) Result Sorting
I'm doing is taking results (fetching rows) from my mySQL database. But what I want to do is sort the results according to last name. So basically the table structure looks something like this: id (primary key) fullname A example rows could be: 1 John Smith 2 Mary Jane Now what I want to do is sort the results in PHP based on last name. I'm using the Pear DB for connecting to my mySQL database. Based on the example rows I gave, Mary Jane would go first, and then John Smith. How would I go about doing this? I was beginning to split the result based on spaces, and the last word to explode, but how would I truly do this?
Modifying MySQL Result - But Not The DB
How can I modify a MySQL data set returned by mysql_query? I am basically doing a while loop over the rows, changing one field, and then doing a mysql_data_seek back to the beginning of the set before returning it. However, later calls to mysql_fetch_assoc still return the orginal data, meaning that (I assume) I am changing a copy of the data rather than the result set itself. Taking the reference (i.e. $record =& mysql_fetch_assoc($result);) did not help. I have read a large quantity of the posts in the php.net site, googled, and read my PHP books - but have come up short on this one. Yes, I know it's better to simply modify the DB. However, I'm working with an existing code base which is very complicated, and want to cherry pick one very well tested feature by making a change in the result set only under special circumstances.
Substr() With A MySQL Result?
I am trying to limit the amount of text exhoed from a MySQL database column. From reading around it appears the substr() should be able to do this Code:
Mysql Result Into Array?
I have a shopping cart script sending info to a processor. I need to send the qty's and item name's in some sort of string via a single variable to the process form. i.e. (3) Hipster Turnips, (6) Butter Milk Baby Brains, (2) Super Freaks Code:
Result From Mysql Into Foreach?
when using mysql_fetch_array($result) I usually toss that into a while loop like so while($row = mysql_fetch_array($result)){ ... } however I was wondering if there was a way to put it in a foreach statement like so foreach(mysql_fetch_array($result) as $row){ ... } Is that legit? Will this work?
Linking To A MySQL Result
I had it the other day but now altered the code for my real database and it stopped working. Here is the first page which lists the 10 most recent news stories: <?php require ('get_connected.php'); $sql = mysql_query ("SELECT title, story_id FROM news ORDER BY story_id DESC LIMIT 0, 10"); while ($row = mysql_fetch_assoc($sql)){ echo "<a href='view.php?id={$row['story_id']}'>" . ucwords(strtolower($row['title'])) . "</a><br>"; } ?> And here is the page that should be displaying the news story based on story_id selected by the user.....
Using MYSQL Result To Send Mail
I have wrote a program to load a number of email address from the MYSQL database. And I have use "$mail = mysql_query("select email from user;",$link_ID); Now, I want to use mail() to send email to those e-mail account I got. What should I do for this?
Date Formatting From Mysql Result
always in the past I have done my date formatting from the query like so: DATE_FORMAT(dateField, '%W, %b %e, %Y') AS realDate I have tried formatting the straight date result with PHP like so: having fetched results with mysql_fetch_array, $newDate=$result["dateField"]; $formattedDate=date($newDate, 'm/d/y'); This doesn't work and simply returns the unformatted date as it is stored in the database.
Display Of Mysql Table Result...
I have a mysql table of articles with fields: - recordID - department - articleTitle - articleText Using PHP, I'm attempting to get the results of the table to display as follows: Department 1 - articleTitle 1 - articleTitle 2 - etc.... Department 2 - articleTitle 1 - articleTitle 2 - etc.. I figure I should use a while loop but can't figure out how to exit/reset the loop when a new 'department' is encountered in the $result.
Replacing Array With Mysql Result
I wanted to repalce the following line of code $data = array(40,21,17,14,23); with for($i=0;$i<$numrows;$i++) { //print(mysql_result($result,$i,2));print("<br>"); array_push($data,mysql_result($result,$i,2));} where mysql_result($result,$i,2) is the value and when i print it displays the values. But $data array is the Y axis value for drawing a chart. Here I wanted to replace the hard coded value with values from mysql but the second code does not function. Does anybody have idea how can I replace the $data array or what may be the problem with my coding The first one works but the second one does not work but in both cases it does not display any error.
Same Mysql Query Doesn't Always Return A Result
We have no access to a mysql NG on my provider's server, so we ask here: We have a long query (long in text) with a UNION between 2 select. We have been informed that some times the query doesn't return any result. We have tried on our server and we always get a result. BUT, trying on the hosting server, many times the query doesn't return any result and doesn't get any error. Any idea ? does Union have any problem ? how to check if the query failed ? My hoster said that sometimes the table can be locked (if the server is overloaded) and then mysql doesn't return any result, but this seems to me an aberration. the query takes about 0.0050 sec to execute when it doesn't return any result, and 0.030 when I get results
Mysql Search Close Result
I've to find in a table the "closer" result given some text. Here is a little example: given the text "Batman socks" I've to find the best matching result in choices like: -"mickey socks" -"robin socks" -"batman black socks" ->this should be found -"batman wallet" -"batman" or given the text "leather shoes" I've to find the best matching result in choices like: -"socks" -"shoes" ->this should be found -"pants" -"shirts" -"leather wallet"
Mysql Problem Understanding Result And Id?
I can't understand why the output from this is not ƍ'? $query = "SELECT * FROM contacts"; $result = mysql_query($query); echo mysql_result ($result, 7, "id"); I also tried adding "ORDER by id" but I still can't get it to echo 7.
MySQL Result Printing In For-loop
I have a script that count and print every week in a selected year. Now i want to connect this to the returned result from a MySQL query. Code to explain what I am trying to accomplish: Code:
How Do I Return Result Of Mysql Row Deletion
The data entered by a user on form 1 on page1.php is posted to delete.php to remove that row from a table. After the SQL operation the user is returned to page1.php. How can I determine the success or failure of the SQL operation so I can display an appropriate response message to the user?
Different Result For MySQL And PHP String Comparison
I have issued an SQL statement "SELECT email FROM mailing_list ORDER BY email ASC"; By right the order of the email should be sorted from smallest to largest. However I got different results when I used record that was ranked higher to compare against record that was ranked lower. I got opposite results. Code:
Mail A Set Of Addresses From A MYSQL Result
I'm populating a field in MYSQL that collects email addresses for a certain topic and saves them like this: mail1@mail.com|emailaddress2@mail.com|email3@email.com - Basically what I'd like to do is explode the data, and set up a mailer from PHP that informs each of the addresses individually that there has been an update to the topic. I *don't* want each of the mail addresses to be visible to all the recipients on the list, so simply inserting the data into the TO: field won't do, because then all the addresses are visible, causing security concerns. Code:
Allow The User To Sort A Mysql Result
So what i got going on is a database that has, things about a video game, including the image location. what i want to do is have a nav bar up top, so the user can select a differnt way of sorting the mysql result, from like ASC to DESC, or sort by genre.
MySQL Result Can't Be Returned From Class Method.. ?
I've been messing around with objects and classes lately and can't figure out why this wont work. I have index.php which uses the pbMySQL class (pbMySQL.class.php) and methods: Code: include("lib/pbMySQL.class.php"); $db = new pbMySQL; $db->pbMySQL_open("localhost","user","pass"); $db->pbMySQL_useDB("database"); // $q=$db->pbMySQL_query("SELECT * FROM pbn_news ORDER BY id DESC"); $q=mysql_query("SELECT * FROM pbn_news ORDER BY id DESC"); if(isset($q)) { while($row=mysql_fetch_array($q)) { print $row['name']."<br> "; } } else { print "query returned FALSE"; } $db->pbMySQL_close(); My problem is that when I use the first query method (which is commented; uses the pbMySQL_query() method) I do not get the mysql result returned, but if I use the same query without the method, I get the result. Here is the method from my class: Code: function pbMySQL_query($query) { if(!isset($this->conn) || !isset($query)) { print "Error : argument(s) missing.<br> "; } else { $this->query = mysql_query($query,$this->conn) or die("Error : query failed.<br> mysql said: <i>".mysql_error()."</i><br> "); if(isset($this->query)) { return $this->query; } else { return FALSE; } } } The method returns FALSE and I don't understand why. Is it something in particular I have to do different when using a class?
Error Message - 0 Is Not A MySQL Result Index
Could anyone explain what this might mean? Warning: 0 is not a MySQL result index I have a simple form set up where a user types in a keyword and then a page is displayed based on the keyword. See below: HTML page: <html> <head> <title></title> </head> <body> <form action="submitform.php3" method="GET"> <p><strong><font face="verdana, arial, ms sans serif" size="1">id#</font>:</strong> <input type="text" name="keyword" size="15" maxlength="25"> <input type="submit" value="Go!"> </p> </form> </body> </html> submitform.php3 page: <?php mysql_connect ("localhost", "username", "password"); mysql_select_db (dbname); $result=mysql_query("SELECT $url FROM table WHERE keyword LIKE '%$keyword%'"); list($url)=mysql_fetch_row($result); ?> The concept is really simple. A user types in an keyword and that page is displayed. There is a database set up with a table that has two columns. One is "keyword" and the other is "url" For example row 1 the keyword is abc, and the url is http://www.abc.com.
How To Get Mysql Query Result Into Temp. Txt File
I did a lite search in the archive but didn't find anything specific to my problem. Here is what I am trying to do: I've got a table with about 25k entries of company addresses. I need to be able to pull specific data out of the table and put it in a temporary text file and then display the result in the browser for the user to save locally. The query part and the format of the data is all simple enough but I am having trouble figuring out how to get the data from the query into a temporary text file and then displaying that file. here is what I whipped up but it obviously doesn't work: Code: <? $tmpfname = tempnam("/path/to/file/", "FOO"); $list = mysql_query("select * from FH_LIST where State='AK'"); while ($list_results = mysql_fetch_array($list)) { $data = blah blah blah; fwrite($tmpfname, ".$data "); } fopen($tmpfname, "r"); fpassthru($tmpfname); ?> I get an error message saying: Warning: Supplied argument is not a valid File-Handle resource (referring to $data).
Setting A Maximum Limit On A Php/mysql Result?
I am using PHP and MySQL to do this script. I want to have a table that contains only numbers for data and then add them all up as a result to display and that I have accomplished with no problem and then I want to display a percentage of that number to the public however that also I have accomplished with no problem using round()... The problem is I am trying to set a maximum number that it displays. I want it to display 1-500 no matter what the number is or the decimal it may have is provided it doesnt exceed 500 but once it does I want it to display 500 as the limit so even if it is say 674 I want it to only display 500. How would I go about doing this? The sql I am using for the adding is SELECT SUM which works just fine and I am using round( $total_number *.15, 2) to display the percentage number of 15%.
|
TRACKER
