PHP :: PLEASE HELP - Drop Down List Related Question

Php And Drop Down List
I am coding an email form on a site. A user enters their name and contact email and then selects from a drop down list to which particular email the message should be sent: User1, User2, User3. Then the user types out a message and hits submit. My problem is that I am unsure as to how to grab the selection in the drop down list and pull the selection and place it like this: "$selection@domain.com". Here is the php code:

Drop Down Box To A List Box
i have this drop down box that displays the relevant info from the table that its loading. But the drop down box isn't quite so wise to use if there hundreds of rows. So what i wanted to do was change it to a list box instead ... would any one know how to do that? Code:

A Dynamic Drop Down List
I need to create a dynamic drop down list. By this i mean that the webpage html form = select style will recieve all the values as based on a query to a mysql database. I have no problems quering the data base with PHP, But i need to make some kind of for loop that will add a new value to the selct form for each result from the database. my thought process go like this.

1. call data base to guery. (no problem)

2. make variable variables that will be created according to the number of results (these variables must be created according to results of query, not a problem i think)

3. make a form like this

<form action = ***** method = post>
<select name = ******>
<option value = "This is a query result"> This is a query result> //This is the part i need to using a for loop and variable variables
</select></form>

so my problem is part 3, cause is this all done in PHP, or if i had all these variables, can i do this in HTML? Can i make a for loop in PHP that would break into HTML during these parts?

2 Drop Down List Using MYSQL
I have a model table with the following fields: MODEL_ID, MAKE_ID, NAME.
And a make table with the following fields:
MAKE_ID, NAME.

The first drop down list (make) to select a make of a car i.e. Chevrolet, Ford. When a make is selected, then all the model for that paticular make appear in the second drop down list.

PHP And MYSQL Drop Down List
I need a script to create a drop down list which has vehicle makes. The vehicle make list should feed a vehicle model list so when I select a make all the models for the make appear in the model list. I have a make table which has MAKE_ID, make NAME and a model table which has MODEL_ID, MAKE_ID and model NAME.

I tried using a script using javascript array but wherever I have a query that pulls the NAME from the database there's always a carriage return after the NAME which messes up the javascript array. I'd rather do it all with PHP if possible. If not please give me one that works and I don't have to spend hours troubleshooting.

Very Simple Drop-down List...
Hi! I'm having a problem with a very simple drop-down list since the
page comes out with no elements in the drop-down but giving no errors.
This is the code:

<form name="year_search_form" method="post" action="results.php">
<select name="select_year" id="select_year">
<?
$query="SELECT * FROM table ORDER BY year";
$result = mysql_query($query) or die ("Error in query: $query. "
..mysql_error());

while ($line = mysql_fetch_array($result)) {
print ("<OPTION value=".$line['year']."></OPTION>"); }
?>
</select>
</form>

Drop Down List From An Array
I want the array to contain a valid year of birth for anyone between the ages of 16 and 80. I'm pretty sure this code is correct.(though it might be a bit sloppy to all you pros) Code:

Drop Down List With Months
I am trying to create a drop down list that has December 2006 as the first option and then goes up month and years till the current month and year (September 2007).

Putting List Into Drop Down
I am working on a directory of businesses which has 8 main categories and each category has several sub-categories. Example: Dining is a Category with Pizza, Fast Food, Chinese, etc. I have the sub-categories brought up in just a list on the left side of the page and when the user clicks on a sub-category it takes them from client_list.php to client_filter.php only showing businesses in that sub-category of the main category.

So only pizza places listed under dining. However, I want to change the list to a (form) select box and then have the user click on the sub-category they want and then it takes them to the client_filter.php page to list only those bussinesses in that sub-categorie. So after that long explanation how do I change my code to do that. Here is my current code:

Insert From An Drop-down List
i have a table in wich i've inserted city's name.then i have an registration form in wich i want to display an dropdown list with the cities from the table, and if one city is selected to be automaticly added in the second table. how can i do that?

Custom Drop Down List
I am trying to get categories from the database and show them in a drop down list showing root category then their sub category underneath. Code:

Folder List Drop-Down
I am developing a PHP/MySQL project and as part of my initial setup and configuration scripts, the users can select a skin for the application, and a variable value ($skin) is updated to set the current skin, this works ok on it's own, but currently the user must manually type the skin name in a free-text box.

Ideally this needs to be a drop-down option box, and I would like this to be populated by listing the sub-folders within the '/skins' folder, so that it's always up to date. The folder structure looks like this:

/skins
/skins/skin1
/skins/skin2
/skins/skin3

How can I use PHP to generate a list of the current sub-directories in 'skins' and populate the drop-down list?

How Do You Pass A Value From A Drop Down List?
I am completely new to this. I don't understand how to receive a value from a drop down list <select> menu. I have read many tutorials and none of them explain the process of receiving the sent data.

Drop Down List Of Months
I am trying to create a drop down list with 12 months as the contents. I need to be able to determine what the latest month is and then put the 11 months before into it (in the correct order). For example, it is September 2007 obviously at the moment, so that will need to be the last and latest month in the list. The other 11 will be in reverse order going back to August 2006.

Chained Drop Down List Working Example
Could some PHP guru please help me? I looking for a good working
example of chained dropdown list.

2 Drop Down List Where Need Query Database
there is drop down list box linked to the database where it displays the state of a country and once the user clicks on the particular state, there purpose to be radio button displaying the locations available of that state, the location displayed in radio buttons are from the database. currently the source code i'm using is (which uses a submit button to query the database but i does not want the submit button it purpose to work using Code:

Dynamic Drop-down List In Array
Q. How do I create a dynamically-generated drop-down list for use in
an array.

I'm using PHP with a MySQL database (through phpMyAdmin)

My database table is called com_courses, and I want to pull the
distinct 'title' fields and have them appear as a drop down menu for
the user to select in a form.

Here is my array, with (at the moment) manually-entered 'titles'
(which I now need to be dynamically generated from my database field:
'com_courses.title'

array (
"coursetitle",
"Course Title:",
$EXTRA_SELECTLIST,

array ("Report Writing", "Recruitment & Selection", "Presentation
Skills", "Essential Telephone Skills", "Time Managememt", "Customer
Care", "Other"),
0
),

I am not an experienced programmer, but can play around with php to
customize programs. I've read up on arrays (I bought a "Programming
with PHP and MySQL" book, but it just stops short of this problem). I
can't figure this one out.

Populating A Drop Down List With The Year
i'm trying to loop the years from 1960 - 2010 with the function get_year() below:
PHP Code:

Automatically Drop Down A List Of Phrases
I would like to know why when I go to a site like altavista.com and start to type in a phrase to search on does it automatically drop down a list of phrases that I have previously searched on, and how do I get rid of these from showing when I go to search.

I removed all of my cookies that were stored in my temporary internet folder. Is there somewhere else I should be looking. I am using IE 5.0 on a windows 98 machine.

How Do You Insert A Value From Drop Down List To SQL Table?
I am a bit new to PHP and SQL so this may seem like a dumb question.

I have already created a drop down list as part of a form which is
automatically populated with values taken from a separate database. When a
user goes onto this page and either leaves the default value or selects a
value from the drop down list and presses the submit button, I would like
that selected value to be stored into a database which I have already
created in SQL.

Just to let you know that I can do the above using a text field but just
don't know how to do it with drop down list.

If your going to explain any coding then it may help if I give you the names
of certain items that are involved.

Database is called "Company"
Field within database is called "Name"

Load Runner, Drop Down List
Can anyone send me the script for supplying the values in drop down
list of the web page?
I have couple of drop down list controls in my web page. I need to
supply multiple values for each dropdown list in my script. How can i
do that? can you send me the script for this?

How To Display .txt Info Into Drop Down List
list out all the items from a file (data.txt) into drop down box for user to select.

Eg. inside (data.txt) has
Apple
Orange
Strawberry
etc...

How do I create a drop down list that can call out everything from data.txt (until end of file)??

Multiple Drop Down List Problem And MySQL
I am trying to populate around 30 drop down lists via a single query to a mySQL database. The problem is how to make sure that each drop down list only display it's relevant data. for example the table is as follows:

Trying To Select Names From A Drop Down List And Display Them
So, I already have the code written where I have a drop down menu with names in it. I want to be able to select multiple names from the drop down list and have them display in a table below the drop down menu. First off, I can't get one name to display, not to mention multiples. :p How may I accomplish this?

CODE:

Error Correction On Drop Down List & Sessions
Hi I'm doing a site at the mo and I have to do error correction on a form. I have most of it done except one or two bits. What I'm having trouble with is drop down lists. What happens is someone fills in the form, it's not done properly so it gets redirected back to the form. Everything works right except the drop down list. The sessions carries over alright but I can't get the drop down list session to work. It marks the session as selected but it's not displayed the first option is displayed. So if you picked Germany and America was first on the list. After being submited America would be displayed but Germany would be checked.

Here is what I got

Correction page

$_SESSION["country"] = $_POST["country"];
if($_SESSION["country"] == Ɔ'){
header("Location: /acc1.php");
}

Form page

echo ' <td><select name="country" id="country" style="width: 150px;">'
if (!isset($_SESSION["courtry"])){
echo '<option value="0" checked="checked"></option>'
}

$rslt = mysql_query($dscntry);
if($rslt){
while ($rws = mysql_fetch_array($rslt)) {
if (!isset($_SESSION["country"])){
echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
}
elseif(isset($_SESSION["country"])){
if($_SESSION["country"] == $rws["countryid"]){
echo '<option value="'.$rws["countryid"].'" checked="checked">'.$rws["countries"].'</option>'
// else{
// echo '<option value="'.$rws["countryid"].'">'.$rws["countries"].'</option>'
// }
}
}
}
}
echo '</select>'

Dynamic Drop-down List With Array - Question
Can anyone out there give me a pointer regarding creating a
dynamically-generated drop-down list connected to an array?

And is that question as clear as chocolate spread?

Here's what I've got. I'm using PHP and MySQL database. I'm customizing
some calendar software, and I want the user to fill in a form by
selecting a title from a drop-down list, generated by my MySQL
database. However, the program I'm customizing uses arrays, which is
where I'm stumped.

What do I need to add to this code to make the array of titles(eg
"report writing" etc) come from my database, rather than the
manually-entered values that you can see here.

The field I want to pull from is called com_courses.title

array (
"coursetitle",
"Course Title:",
$EXTRA_SELECTLIST,

array ("Report Writing", "Recruitment & Selection", "Presentation
Skills", "Essential Telephone Skills", "Time Managememt", "Customer
Care", "Other"),
0
),

I hope it's not cheeky to ask this,
BTW I bought a book on Programming with PHP and MySQL, but it doesn't
answer this question,

How To Response Immediately When I Select The Drop-box List
Do you have any idea when I try to select a drop box list, the data
will show up in the following textbox immediately?

eg.

Name:
---------------
drop-box list | <- when i select one of them
---------------

Age:
---------------
Textfield 1 | <- pop up immediately
---------------

Address:
---------------
Textfield 2 |
---------------

Saving/Loading Data In Drop-down List
I have a drop-down list with set values. When there is a corresponding value in my database when the page loads I want the drop-down list to pick the appropriate value from the list. Instead it always defaults to the first value. Can anyone give me an example of how to do this?

Also, one time after adding a variable to a classes file this symbol: ï»¿ started showing up on all of my pages. Has anyone seen this before? I can't find any information on the web about it.

Populate A Drop Down List In A Form On The Basis Of A First Selection
I have developed a form to register a property in a db. The form needs the selection of a country and then based on that selection the selection of regions from the selected country. I have a program which allows selection of a country and then a region but it uses java script which I would like to avoid. I also just wanted one submit button if possible. Code:

Select From Drop List To Fill Table Column With Text -- HOW ?
I want viewers to compare state laws on a single subject.

Imagine a three-column table with a drop-down box on the top. A viewer
selects a state from the list, and that state's text fills the column below.
The viewer can select states from the drop down lists above the other two
columns as well. If the viewer selects only one, only one column fills. If
the viewer selects two states, two columns fill. Etc.

I could, if appropriate, have a separate htm page with the text for each
state -- california.htm for example. When the viewer selects California from
the drop down list, the column below would "fill" with California.htm.

Or, I could conceivably use a text or mysql database with two fields for
each record: state_name and law_text -- but it would probably be easier to
use separate htm files, since there will only be about 20 states involved,
and the "database" would never have a large number of records.

The table width would be 100% and each cell would be @33%

My site is designed with FP 2002 and runs on Apache/FreeBSD. I have just had
Apache-ASP installed but I have not yet configured or used the module.

Displaying Data From Mysql Database In A Drop Down List On Form.
I'm trying to do is display data from two different mysql tables from the same database in a drop down list on a html form. I have a fixtures table with the player1(userid), player2(userid), gameid, game, score1 and 2, what I want is to use the userid to get the players first name and surname from the members table (as it is a unique id), I need to do this bit before displaying it in the drop down. I think i need 2 querys to do this but when I have tried it it just echo's a blank value or the userid not the forname and surname that I want. I'm using the fetch_array function but just can't see where I'm going wrong, Code:

Dynamically Populate Drop-down List And Dynamically Include Html File
We have a drop down list on a PHP page, with several product names, and
when people click one item, we will refresh the same page with the
product name as parameter, and in turn we want to include a HTML file
into the content area of the same page.

I know it is recommended to put everything into database, but we want
the web site to be very "portable", so the drop-downlist and the
content should both in text files.

Let's say the drop-down list will be poplulated from the product.txt
file, and there will be a file for each corresponding item in the
drop-down list. From the user point of view, if he wants to add a new
product, he will just need to open the product.txt file, and add a new
line with the product name, "Laptop", then add a new text file named
"laptop" in the same folder which contains the HTML fragment to be
included in the content area.

What is the easiest way to do this?

Drop Down Lists Changing Depending On Other Drop Downs
I want to have a drop down system like this one. But without the radio buttons.

I want to have 3 drop downs but have no idea how to go about it. I assume I will need to activate some sort of Javascript on the onChange event of the option drop downs.

Related Items
I noticed a lot of websites show "Related Items" on each product page. I want to know how usually do you implement it. Should I add a field in the mysql table to hold the "Related Items" information? What's the best solution?

Rand() Related
I do not know how to perform a probability check.

This is indirectly related to PHP.

I would like generating a rand ID using rand() and a combo of letters and number. To keep it simple I wish to only use 6 chars So the question is:

What is the probability that out of 100k such rand IDs a duplicate could be generated?

I could indeed match it VS previously DB stored but if the frequency of possible duplication is somehow great then it becomes detrimental and I need finding a way with less duplication potentiality....

XSS Related Attack.
I have started to study sessions and as I understood it works in the
following way:

Let us consider two files first.php and second.php. By clicking on a
link in the file first.php user pass to the file second.php. We want
PHP programs in second.php can see values of variables which (values)
have been set in the first.php. It can be done in the following way:
·Both files have to start with session_start();.
·Variables whose values are set in the first.php and have to be
seen in the second.php have to be declared as session_register(
"variable_name" ); (before value of variable is set).
·In the place in first.php where we make link to second.php we
need to write second.php?.SID (instead of second.php). In this case
values of variables can be passed from first.php to second.php even if
user prohibits saving cookies.

As I understood it is better to replace SID by strip_tags(SID). In this
case one can avoid an XSS related attack. But I do not know what is
this attack and what strip_tags does.

Related Search
how do I do a search related results? I mean, just briefly which function I need.

Related Table Problems
I know there is a "easy" way to do this but Im stumped and I hope you can help. I have 2 tables in mySQL. Table one is pages, table two is bb. Pages has a field in it call bb_id. I want to be able to show the corresponding row from bb with the appropriate page_id. For some reason it will dispaly the data from the last row from the bb table.

I've looked into joining them but Im new to PHP and had no success. Could someone explain how I'm supposed to these relate two tables?

Query Related To Ebay Php API 's
I am using Sandbox EBay Php API's....

I want to check Seller's login is correct or not ....

Should Sandbox tech. supports this ?

Also following error is occured while retriving the
"Seller's list" :

Fatal error: Class 'XsltProcessor' not found in C:Program FilesApache
GroupApache2htdocsebaySellerGetSellerList.php on line 37...........

Md5 Prob - Display Related
I have set up a basic user registration form on my site URL and all the info ins successfully transferred to the MySQL database.

The problem is that after a user has submitted his info a confirmation page loads URL telling the user their username and password. The thing is it displays the md5, i.e. the encryted password. Is there an alternative to md5 that will also add an encytped password to the db or is there a reverse operation I can run on the md5?

I have only been learning for the past few days so go easy. Below is the 'submitform.php' php code I use. PHP Code:

Mysql Related Question
just wondering:

I have a database, containing the following fields:

name
address
zip
email

and a template for my page, containing the following tags:

[[name]] [[address]] [[zip]] [[email]]

Would there be a quick way to replace those tags with the data read from the
database without doing this:

$line=mysql_get_row($res) ; // provided we already have connection and data
selected
$html_to_show=preg_replace("/[[name]]/",$line[0],$html_to_show);
$html_to_show=preg_replace("/[[address]]/",$line[1],$html_to_show);
$html_to_show=preg_replace("/[[zip]]/",$line[2],$html_to_show);
$html_to_show=preg_replace("/[[email]]/",$line[3],$html_to_show);

(never mind the preg here or any typo's. this is a quick question)

Reason for me to ask, though code above works:
I need to create something dynamic. I would like to scan and replace every
instance in my template, looking like a tag ( [[some_tag_name]] ) by
the value of it's corresponding fieldname from my table.
I am really wondering how, but there's got to be an easier way to do this.
Currently I have 61 fields in one table and that kinda works towards RSI if
I have to code it all like this.

Problem Related To OCILogon ()
My objective is to try to connect to the oracle database and if an
error occurs go to another page. The code follows

$conn = OCILogon($user,$passwd,$db); // <---- Line 34

if (!$conn) {
$err = OCIError();
header("Location: dbproblem.php?error=$err[text]");
}

The problem is, whenever the OCILogon() fails, I'm not able to
redirect to dbproblem.php because OCILogon has already sent the error
message to the client, thus resulting in the following message

Warning: Cannot modify header information - headers already sent by
(output started at /path/to/validate.php:34)

Is there anyway that I can stop OCILogon() from sending the error?

|FAQ| Zip Code Related Questions
Q: How to find the distance between two zip codes/cities?
Q: How to find list of cities/zip codes that are with in the particular
radius from given city/zip code?

A: In spherical trigonometry, we have haversine formula, which provides
relationship between the radius of the sphere and any two points on the
sphere (longitude and latitude of the points). So, if we take the earth
as a sphere and have longitude and latitude of any two cities, we can
find the distance approximately.

Developed countries like U.S. have census data that contains the zip
code, longitude and latitude of a particular city (along with
population data); this in turn helped a lot to find the distance
between any two cities or any two zip codes using the database. Not to
mention, even many commercial zip code databases are available for that
purpose.

Once we have the Zip code database, it's merely a calculation over the
data.

Session Related Problem
i am facing a serious problem while trying to make my site live which contains PHP pages. The pages which is working perfectly fine in localhost and intranet is not working when i put it in live. database connection also correct as i can able to display information on the page from it. Main problem in my search page and login pages. When i search i won't get anything even when data is there.No error also. My insert scripts also not working. Also i am not able to login with a username and password .Important thing to be noted is that everything is working fine in localhost and intranet. Code:

Time Related Script
I'm thinking of making a script that will rotate banners every hour.

The way I see it is:

get time;
if first number (hour)is positive ie. -->12:00
banner one
else
banner two....

IIS/Apache Related Problem
My development environment is XP/IIS and the destination system is
Unix/Apache

Should I expect to have any problems and what?

PHP's Configure (GD Related)
I'm trying to compile PHP 4.3.4 with support of GD (including zlib, jpeg,
png, freetype2, t1). I've compiled all the required libraries and they're
all sitting in /usr/local/lib, which can be confirmed by running
ldconfig -v.

Now I have a problem of figuring out which configure options to use.

For example, for freetype the following options are available:
--with-freetype2
--with-ttf
(there is also --enable-freetype-4bit-antialias-hack, but it's experimental
and prolly not necessary or is it? )

Similarly for zlib:
--with-zlib-dir
--with-zlib

What options am I to use for compiling the components mentioned above?

Bad Php Behaviour With Related Paths
I'm trying to include some files in an included file. Think of some scripts
like this

/index.php
/scripts/logging.php
/scripts/config.php
/scripts/db_access.php

index.php includes 'scripts/logging.php' and logging.php includes
'config.php' ºi 'db_access.php'.

My problem is that from within logging.php the php will try to include the
file '/config.php' and not '/scripts/config.php' because logging.php is
included in '/index.php' in the first place.

I would use absolute paths in the included file names, built with
$_SERVER['DOCUMENT_ROOT'], but I don't really know where my pages are on
the web server. I just know they are somewhere under DocumentRoot.

How can I write pages that can translate local paths to virtual paths and
that can be moved from one place to another in the virtual directory
hierarhy and still function corectly ?

How can I write pages that know about each other's URI's and that do not
care where they are placed on the webserver with respect to DocumentRoot ?