Pagination Of MySQL Records
Data is being passed to page and being displayed in a dynamic table (Adjusts based upon the number of records to display.).
Table row colors alternate; gray - white - gray. In addition, the <thead> is set up to allow for ordering of records. Now I want to add pagination; limiting the number of displayed rows to 20. Code:
View Complete Forum Thread with Replies
Related Forum Messages:
Pagination With MySQL
Well it's extremely early on Saturday morning and, well....I'm bored. :) Anyway, there have been some questions about Pagination with MySQL, so I decided to write up something real quick. I believe the comments within the code explain it all. Please excuse me if there are any typos...I'm tired ;) <?php /* Check whether the 'page' GET variable is not defined or equals zero. In either case, an error is sent and the script terminated. */ if(empty($_GET['page'])) { echo 'Page number is not defined!' exit(); } /* The following makes sure that the 'page' variable only contains numbers, therefore limiting it to just integers(whole numbers). */ else if(!preg_match("/^([0-9])+$/",$_GET['page'])) { echo 'Page is not a valid value!' exit(); } /* If the 'num' GET variable isn't defined in the URI, then the var num_per_page is by default set to 10. This utilizes the ternary operator. After the check for existence, then there is a check to make sure that the string contains only an integer using the same method as above. */ $num_per_page = (empty($_GET['num']))? 10 : $_GET['num']; if(!preg_match("/^([0-9])+$/",$num_per_page)) { echo 'Num is not a valid value!' exit(); } //Get the page number from the URI; the pages start when page=1, not page=0 $page = $_GET['page']; /* Connect to database and then select a database. You can also include this information if you want, but this is just an example ;) */ $link = mysql_connect('localhost','username','password'); mysql_select_db('database'); /* This piece is the essence of pagination. Using LIMIT in the mysql query is what we are going to use for this. The following line creates a new variable, qPage, which is the value of the page number minus one times the number of rows you want to show up on each page. For example, if page = 1 in the URI, then 1-1*10 = 0. This is the offset for the LIMIT in the query. If page = 2then 2-1*10 = 10. Since 10 is the number per page in the example, then it only makes sense to start the next limit at an offset of 10. */ $qPage = (($page-1)*$num_per_page); /* The following is the query of the pagination; this is where the magic takes place. the SELECT is self-explanatory. The LIMIT is the most important. LIMIT has the syntax LIMIT [offset],[length]. Knowing this format you should be able to follow the query now. Now for the following you are probably wondering why I added 1 to the value for the number per page. I did this simply to know if there is going to be another page after the current one. We will need this information later when we are echoing out the 'Next page' link. Note: You may want to change the query to fit your needs, however the LIMIT clause should stay the same. Everything else can be changed :) */ $query = "SELECT * FROM `table` ORDER BY `col_name` ASC LIMIT ".$qPage.",".($num_per_page+1); //You should remove the 'die(mysql_error());' part of the following after development $result = mysql_query($query) or die(mysql_error()); /* Here 'num' is set to the number of rows that the above query returned. The condition simply sees if the number of rows returned equals zero, because if it does than that means that there are no more rows for the specified LIMIT. */ $num = mysql_num_rows($result); if($num == 0) { echo 'No more results!' exit(); } /* Here's is another interesting part. At first thought one may want to use a while loop here. The only problem with the while loop is that it echos that last row that we selected in the query when we don't want it to. Instead of handling this it's easier to use a for loop instead, using the num_per_page variable as shown. Obviously you can format the HTML and PHP output however you'd like; I'm just outputting the array as an example. */ for($i = 0; $i < $num_per_page; $i++) { $row = mysql_fetch_array($result); echo '<pre>' print_r($row); echo '</pre>' } mysql_close($link); //Close the link to the MySQL database. /* This goes back to selecting that extra row in the query. If the amount selected (num) is greater than the number per page(num_per_page) than that means that there is at least one more row to be returned after the the range that you want, therefore you know you can echo the 'Next Page' link without having to worry if you are linking to a blank page or not. The rest should be self-explanatory. If you are going onto the next page, you are going to increment the page variable by one, and of course you still want to keep the current number per page otherwise you may see repeats, so you just echo that value in it's corresponding place within the url query. */ if($num > $num_per_page) { echo '<a href="index.php?page='.($page+1).'&num='.$num_per_page.'">Next Page</a>' } echo '<br/>' //Just acts as a separator for the two links ;) /* The following acts the same way as above, however instead of incrementing you are subtracting one from the page variable to 'go back' to the previous page. Obviously you do not want to 'go back' when you are on the first page to begin with, so we first check to make sure that the page value is larger than Ƈ' (our first page) before we start echoing it to the browser. */ if($page > 1) { echo '<a href="index.php?page='.($page-1).'&num='.$num_per_page.'">Previous Page</a>' } ?> There are also many other related threads on this topic. Here's a few: http://www.webmasterworld.com/forum88/5119.htm http://www.webmasterworld.com/forum88/2880.htm http://www.webmasterworld.com/php/3088021.htm http://www.webmasterworld.com/forum88/9755.htm http://www.webmasterworld.com/forum88/4255.htm http://www.webmasterworld.com/forum88/6510.htm http://www.webmasterworld.com/forum88/11904.htm If anyone can add something, please do. I know I'm missing something ;)
View Replies !
Pagination Without MySQL...
I am trying to make a simple site map - from a directory full of files.. but I have too many files in the folder, I need pagination.. I have no idea how to do this without MySQL. Code:
View Replies !
Mysql/PHP Pagination
I would like to output the rows from my MYSQL query into manageable pages, eg 30 items per page. The query is driven by a form containing numerous text boxes and selection lists. My script accesses the form variables using $var1 = $_POST['var1']; $var2 = $_POST['var2']; etc, which then are incorporated into the query which uses LIMIT to specify desired ouptut. The script works fine when the page first loads, but when I click 'next' or any other 'page link' to see more results, I get no output. When the script reloads, $var1 and $var2$ now have no data which in turn changes the overall query. I'm not sure how to preserve the form data when the script reloads itself to display remaining output.
View Replies !
Pagination Of MySQL
<?php $con = mysql_connect("***","***","***"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("b7_463487_LPS", $con); $query = mysql_query("SELECT * FROM points ORDER BY LastName ASC, FirstName ASC") or die(mysql_error()); $rows = mysql_num_rows($data); while($row = mysql_fetch_array($query)) .............
View Replies !
MySQL Pagination
I know there are probably loads of pagination how tos on this forum but I wanted to ask again, mainly so i can put it into the context of my problem. I am writing an IP logger for a website, so far the script is pretty basic. I was hoping someone here might set me off on the right direction for how to limit the number of records per page to 20 or something like that and then display a load of linsk with page numbers etc. Code:
View Replies !
MySQL Pagination Loop
Senario: I would like to display at all times four images taken from mySQL database into a table cell. Lets say I have 6 imgs total - page 1 would display img 1 - 4 and on page 2 it displays imgs 5 & 6. (I have no problem with a normal pagination) When I reach img6, I would like it to add imgs 1 & 2 in the next 2 cells, this is to keep my 4 images displayed. As you press next page, it cycles thru the 6 images and at all times displaying 4 images.
View Replies !
Mysql Results Pagination
I have a php code to split the results of a sql query over pages taht works great... But I need to add some feature, I need to add that if there are more than * pages it shows me "..." instead of the hole numbers of pages.. Code:
View Replies !
Pagination & Mysql Injection
However, I run a function I found on php.net that uses mysql_real_escape_string on all the keys of the $_POST and $_GET arrays. This pagination tutorial and all of the others I've seen have you pass the $query that you generated with your script back to the same page as a $query variable in the url. I can't figure out how to go about securing the data this way. If I run mysql_real_escape_string on $_GET['query'], I get a database error because now I have slashes where I shouldn't. If I don't use it, however, I'm just opening up a backdoor to my db, am I not? Does anyone know any good articles on pagination security? I don't want to have to rebuild the query since there are 25+ possible variables that could be in the query and that would be a pretty long url.
View Replies !
Mysql Dreamweaver Pagination
i am develop a system to store staff's information using php,mysql and dreamweaver as the tools.as i cerate the recordset using dreamweaver,how can i develop a paging for the recordset? for example i have 100 records and successfully display every 10 record at one time.However,i use only "First" and "Last" navigation to navigate through all the recordset. It is more effective if we can set the page number so user can navigate easily.For example the interface that i want is like this: << | < | 1 | 2 | 3 | > | >>
View Replies !
MySQL Search & Pagination Problems
I`ve built a script to search a db, and to show 20 results per page. The problem I`m having is that when I click to view "Page 2/3/4/5 etc" I get zero results, like the variables are being erased when I click to view the next 20 results. Page 1 of the search results: <snip> Page 2 of the search results: <snip> There's too much information to be parsed via the url ($_GET method) in my opinion, and I was wondering what, if anything I`d done wrong for the next pages to show up as blank. Code:
View Replies !
Smooth Pagination Using MYSQL,AJAX
I have a ribbon image (ribbon image means-around 6 small images in a row with previous Button in the beginning and Next button in the end) .What i want to do when i am clicking on a next button I want to display next 6 images with the running effect. Running effect means user should feel all images are going to front without reload the page(using AJAX) and same thing will happen for Previous (when some one clicking on the previous link i need to show previous 6 images with running effect using AJAX.
View Replies !
Pagination And Dropdown Menu Used In Searching Mysql
I am working on building a database made for searching. I have a text search and a dropdown box used for searching different table collumns (lets people search for certan criteria). I have that working correctly. I also only want to show 25 results per page. I have that working correctly. My problem is that when I combine the two it breaks the code. The pagination works fine without the dropdown and vice versa. I think it is due to the variable that is being used to choose the collumn in the sql query. Code:
View Replies !
PHP/MySQL Records Per Row
Is there any way to have the records pulled from a mysql database display like this in a table: record1 | record2 record3 | record4 etc: I've been thinking about this for about three months and have yet to come to a good solution.
View Replies !
How Many Records Can MYSQL 4.1.14 NT Via TCP/IP Can Hold?
how many records can MYSQL 4.1.14 NT via TCP/IP can hold? how many records per table can MYSQL 4.1.14 NT via TCP/IP can hold? how many records in a table can MYSQL 4.1.14 NT via TCP/IP can hold given the table has a field Primary key - BIGINT(20) autoincrement? need your opinion..Here are the facts: MY system is an internal one. My Server--Is only a Desktop.. Celeron 2.8 Gigahertz, 40Gig Baracuda HD, 512 MB memory.. And it serves an average of 20 users a day and it also serves me for my system development..The average records inserted per month on mYSQL is 10,000 records..We foresee that system would be used for about 10 years.
View Replies !
Counting Records In MySQL
I've been trying to write a page that checks the database and counts the number of records and if the number is less than 3000, it loads page X, but if the number is equal to 3000, it loads page Y. I know this should be a simple if/else statement but it's the checking and counting that I cannot get to work.
View Replies !
Display Records In Php/mysql
i have the mysql database with the name "wwwgosc_ton" and table with 17 field by the name "general". i want to dispaly all the records with 3 to 4 fileds and link each row to detail of the full field of that perticular records. Code:
View Replies !
Ordering Records Php/mysql
I'm trying to change the order records, via links on a php page. my code: $numID = $_REQUEST['id']; $numPos = ($_REQUEST['Pos']); if($numPos > 1){ mysql_query("UPDATE FamilyPhotoAlbum SET DisplayOrder = DisplayOrder - 1 WHERE Id = " . $numID); $numCounter = $numPos;.. I think my logic is a little off here. I can't seem to get the records to order correctly with out it skipping numbers.
View Replies !
Insert Records To MySQL
When I use the script below it doesn't insert the record into MYSQL database. I have checked the fields in the form and they are showing fine and the database is connecting without a problem. Does anyone see anything wrong with my script? $sql = mysql_query("INSERT INTO customers ('client name', 'bill to address', 'shipping address', 'phone', 'contact name') VALUES ('$clientname', '$billtoaddress', '$shippingaddress', '$phone', '$contactname')");
View Replies !
Displaying Mysql Records:
I wondered if anyone could offer some guidance, I trying to write a php script to connect to a database, and display the records in a table. I found the code here in a php4 text, and when I run this directly through the php intrupeter, the line Successfully connected is display and 4 as the number of rows. The database table we connect to, has three field username, firstname, surname. When I tried a while loop, to display the data in a table. No values were displayed. Could anyone possibly demonstrate how to display the username, firstname, surname values in a basic table? <?php function db_connect(){ global $MYSQL_ERRNO, $MYSQL_ERROR; $link_id = mysql_connect("localhost","user04", "password04"); if(!$link_id){ $MYSQL_ERROR = "Connection failed"; ..................
View Replies !
Replacing Records In Mysql
I have a web form for updating projects that feeds a bunch of mysql tables. The problem is that some of the fields on the form may generate more than one entry. So for example, I may have a project that is working into 5 countries. Code:
View Replies !
Updating Mysql Records
I have programmed the code to display the information of a particular person in the form so that he/she can change his/her details in the form and hence update his/her records.I have tried with the following code.It displays the form with the previous data. But when I submit,it blanks the fields (excepting the name,surname and dob which I have blocked from making any correction).The remaining 7 fields become blank with the last field's (ExamsPending) value to be zero. Code:
View Replies !
MySQL Consecutive Records
I have a table with columns like this: ob (datetime) temperature (float). There should be one record for each hour in a day (ob). I need to query this table and return a count of the number of consecutive records preceeding each hour within an 8 hour timeframe where the temperature > 70 degrees. I know how to get the number of records spread out during a timeframe, but I'm having trouble finding consecutive records.
View Replies !
Multiple Mysql Records
I am trying to develop a form which has the user inputing data in a columnar format. Each column has multiple fields (one for each row) there are 12 columns, I was able to submit to MySql database the first column fields. All subsequent columns would be the same field inputs but the values could be different. I need each column to be submitted to the database as a seperate record by using only one form submit.
View Replies !
How Do Iterate Through MySQL Records And Displat Them?
Basically I have a page where a person can choose from a list of stories posted by people, or they can choose to submit their own. I've managed to do the page where they can submit their on. The way i did this was to set up a mySQL database, and table in the database called stories. I then made an id (primary key), author, title, body and date field in the table. When the user submits their story its given an id (which increments on each submition) and their author, title and body fileds are sent to the database. The date key is automatically stamped in. Ive also managed to have the submition page display what they submitted by using the count(*) function, their story would be the last to be submited , so it pulls that from the database and displays it. Now what I want to do - on the page where they can pick a story, is have the page connect to the database and grab each record and display the author and title on the page next to a radio button. And have the id for the story in a hidden field or variable so when the user to chooses a particlar story it uses the id to grab the story from the database. So how do iterate through all the records in the database, and display each one?
View Replies !
Problems Updating Records In MySQL With PHP
Sorry to ask what is probably a simple answer, but I am having problems updating a table/database from a PHP/ PHTML file. I can Read From the Table, I can Insert into Table/Database, But not update. Here is a copy of the script I am using. I do not know what version of MySQL my host is running nor do I have Shell Access to it. I would like to setup a script so my website users can update thier records without my intervention. Also you may send replies to stevennyoung@yahoo.com Begin Script <?php $db = mysql_connect("localhost", "username", "password"); mysql_select_db("databasename",$db); if ($id) { if ($submit) { $sql = "UPDATE tablename SET EMail='$EMail',Username='$Username',Password='$Pas sword',Item= '$Item',Price='$Price',URL='$URL' WHERE Username='$Username'"; $result = mysql_query($sql); echo "table Updated."; } else { // query the DB $sql = "SELECT * FROM tablename WHERE Username='$Username'"; $result = mysql_query($sql); $myrow = mysql_fetch_array($result); ?> <form method="post" action="<?php echo $PHP_SELF?>"> e-Mail Address:<input type="Text" name="EMail" value="<?php echo $myrow["EMail"] ?>"><br> Username:<input type="Text" name="Username" value="<?php echo $myrow["Username"] ?>"><br> Password:<input type="Text" name="Password" value="<?php echo $myrow["Password"] ?>"><br> Item:<input type="Text" name="Item" value="<?php echo $myrow["Item"] ?>"><br> Price:<input type="Text" name="Price" value="<?php echo $myrow["Price"] ?>"><br> Item URL:<input type="Text" name="URL" value="<?php echo $myrow["URL"] ?>"><br> <input type="Submit" name="Update" value="Update table"> </form> <?php } } else { // display list of articles $result = mysql_query("SELECT * FROM tablename",$db); while ($myrow = mysql_fetch_array($result)) { printf("<a href="%s?Username=%s">%s %s</a><br> ", $PHP_SELF, $myrow["Username"], $myrow["Item"], $myrow ["URL"]); } } // Close DB Connection mysql_close() ?>
View Replies !
Grabbing Specific MySQL Records
I have set up a target page to pull information out of a mySQL database to populate the page. The problem is that it is only pulling from the first record and not the record specified. What do I have to do to pull from a specific record? I am using Dreamweaver MX to administer the site on WinXP using PHP if that information will help.
View Replies !
Sensible Method Of Inserting Records In To MySQL
I have users using a third party windows application. They can export data from this application directly to a text file (CSV). So far as I know, there is no way to make this application talk directly to the MySQL server. We're talking thousands of records here - it's not practical to have an HTML form handled by PHP which inserts the data to MySQL... or is it?? What I thought about doing was to have them export the data to the CSV file & then upload it to the web server using FTP. Once uploaded, I would have them go to a page with a PHP script which would run the command to import the data to MySQL. PHP can run shell commands, as I understand it from the manual. Perhaps this would be a bitch on Windows, though. Code:
View Replies !
& MySQL - Updating & Deleting Records
I am very new to MySQL and have built myself a small database for website update requests. The thing is Instead of having a "enter the record id # and press edit" I want to have a small edit icon at the end of each record I am displaying in a table. I've got the table data box setup at the end of the record and this is what I put in it: Code:
View Replies !
Very Slow MySQL SELECT Query After 11 Records
I have a very weird problem I moved my database to new IIS 6.0 + PHP 4.3 + MySQL 4.0 setup. I tried to check with myphpadmin if everything works fine, but I couldn't browse my table (125 records). I used SELECT option and found out that SELECT query up to 11 records is ok, but after that, even if I choose to limit query to 12 records, it just hangs. I tried selecting from the beginning of the table and from the middle - same thing, but when I run query localy on mysql console, everything works fine
View Replies !
How Do I Prevent Mysql From Printing Redundant Records?
I have a very urgent question. I am using php and mysql. Say I have a database full of names and email addresses. I want to do a query that when you type in the name or partial name, mysql will only show a name once, even if it is in the database 200 times. Then I want to click on that name and have mysql show the 200 email addresses associated with that name (which I know how to do). See below:
View Replies !
Set Session Variables From Records In A MySql Database
I am working on a memebship section for a website and I am trying to set session variables from records in a MySql database when the user logs in. I think I am missing something because try as I might the just don't work! The sever I use had Glabal variables turned on, dont know if thats an issue in this case. Heres the code on the check user page:
View Replies !
Inserting Master-detail Records In Mysql
how I can insert a master-detail record in mysql? I use an auto-increment key, but I don't know how I can find that key for inserting the detail records, I tried to make a 'highest-key' function with 'select MAX(field)...' but in php it gives the wrong key (in mysql it gives the right one).
View Replies !
Changing Data In Objectified Mysql Records
I am using this very slightly modified function found here: http://us2.php.net/mysql_fetch_object to make mySQL rows into objects of type $classname: // This takes db result rows and makes real objects of $classname type function &buildObj($result, $classname) { while($row = mysql_fetch_assoc($result)) { if ($row === null) return null; /* Create the object */ $obj =& new $classname; /* Explode the array and set the objects's instance data */ foreach($row as $key => $value) { $obj->{$key} = $value; } $objs[] = $obj; } return $objs; } This is called by a retrieve: function: function retrieve($where) { echo $query = "SELECT * FROM $this->table WHERE " . join(' AND ', $where); $result = mysql_query($query); $rows =& buildObj($result, get_class($this)); mysql_free_result($result); return $rows; } The problem I am encountering is that if I do this in my script: $listing = new Listing; $listings = $listing->retrieve(array('row > 1') ); foreach ($listing as $aListing) { $aListing->address='xxxxxxxxxxxxx' } foreach ($listing as $aListing) { print_r($aListing); } The value in $aListing->address is unchanged. However if I do this: $listing = new Listing; $listings = $listing->retrieve(array('row > 1') ); foreach ($listing as $aListing) { $aListing->address='xxxxxxxxxxxxx' $newArray[] = $aListing; } foreach ($newArray as $aListing) { print_r($aListing); } I see the update values in $aListing->address .
View Replies !
Break MySQL Records Into CSS Columns Automatically
I'm making a page of links, each assigned a category. There are two tables - "favourites_links" and "favourites_categories". This is how the links currently appear: Category 1 Name Link 1 Link 2 Link 3 Category 2 Name Link 1 Link 2 Link 3 What I want to do is break my page into columns. Basically, set a number of columns (e.g. 3), count the total records, and work out how many records to show per column. Each column should be enclosed in a <div class="column"> wrapper, which floats to the left. Code:
View Replies !
Having Trouble Looping Through Records In A MySQL Table
I'm having some trouble looping through the records of a MySQL table using PEAR DB. Here is my code: $navigationSql = "SELECT * FROM nav"; $navigation =& $db->query($navigationSql); while ($navigation->fetchInto($nav)){ define("NAVIGATION", "<a href="$nav[2]" target="$nav[3]" title="$nav[1]">$nav[1]</a><br />"); } The when I enter: print NAVIGATION; into any of my PHP scripts it should loop through the stuff in table named nav, but it is only displaying the first record and so far everything I've tried does not seem to make it loop through all of the records in the table and I can't figure out why not.
View Replies !
Select Multiple Dates' Records From MySQL DB
I need to select multiple records from a MySQL DB based on one date value that I get from a form. When I get the date from the form I need to get the values for that date and for the six days before that to display the full week's data. Code:
View Replies !
MySQL Connection - Get Some Records And Print Them To The Browser
I have a script that works but it shouldn't, and I would like to know why. I originally wrote it with a statement to connect to the database, then there's a part to select the database, then I get some records and print them to the browser. It all works fine. A couple of months ago, I commented out the connection part (I can't remember why), and it still works. I had thought that there must be a connection statement.
View Replies !
Transfer Edited Records From One MySQL Table To Another
What I need is for a user to search a certain database table for a purchase order #. The results then need to be displayed in textboxes so they can be edited as needed. Then the edited records need to be inserted into another table, and deleted from the former. I have the first two steps coded, but am having trouble figuring out how to do the third correctly. Here is my code:
View Replies !
How To Control Access To Specific Mysql Records For A User
I am just trying out a php form, when posted submits data to database. The system is we allow everyone to submit the form. As administrator I can view and edit the records. But whoever submits the form should be a registered user and he should be able to only view his records but not edit.
View Replies !
Can I Convert MySQL Db Records Into Microsoft Word Documents?
i found the solution to export file from mysql db into *.csv. but is there anyway to convert the contents into *.doc and save in my webserver and providing a link for the end users to download the word file? FYI, the database records are obtained by end users submitting the forms themselve and i saved it in my db...
View Replies !
Display Records From A MYSQL Database On Multiple Pages.
I am trying to display records from a MYSQL database on multiple pages. I get the following error when I attempt to display the results mysql_fetch_array(): supplied argument is not a valid MYSQL result in c:intentpubwwwrootprogeneefsires1.php on line 238 The code is shown below. I am including a file called class.pager.php for page numbers (author: Tsigo) and this part works fine. /* Now we use the LIMIT clause to grab a range of rows */ $result = mysql_query("SELECT sireid, sirename, sirethumbpic, comment_1,comment_2,comment_3 FROM beef".$start.", ".$limit);
View Replies !
|
TRACKER
