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Passing Objects Form One Page To Another


Is it possible to transfer objects derived from a class form one page to
another?

I made 2 testscripts:

person.php
-------------------------------------
<?php

class person {

private $_name;

public function setName($name) {

$this->_name = $name;

}

public function getName() {

return $this->_name;

}

}

$p = new person();

$p->setName("Jim");

$safep = urlencode(serialize($p));

header("Location:person2.php?data=".$safep);

exit;

?>

person2.php
---------------------------------
<?php

class person {

private $_name;

public function setName($name) {

$this->_name = $name;

}

public function getName() {

return $this->_name;

}

}

$x = unserialize(urldecode($_GET['data']));

echo $x->getName();

?>

But this does not work for me....




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print "<tr><td>";
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";
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<?
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<tr> <td> </td> </tr> <tr> <td> <div align=center> Search For:
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<INPUT name=for value=<?php echo ("$search_for"); ?>>
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echo ("SELECTED"); }?>>Floral Creations <OPTION <?php if
($search_category == "Decorative Lighting") { echo
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("SELECTED"); }?>>Kitchenware & Crockery <OPTION <?php if
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Now what I need to do is make it so that only the entry for which the submit button is connected to is carried over to a third page.

At this point using variables, each button gets a different name and value such as, button 1, button 2, button 3, ...

When I click any of the buttons all the data from all the submissions get carried over to the new page instead of only the data that that button goes with.

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the
same page but from another form?

Here's my full php code:

I'm using two forms in the same page. A hidden field 'f' with values
&#391;' and
&#392;' are used to distinguish calls from one form from those from the
other.

<html>
<head><title>Database Access</title></head>
<body>

<form name="QueryForm" action="db2.php" method="POST" />

<input type="hidden" name="f" value="1" />

<input type="text" width="100" name="txtQuery"
value="select * from license_master;" /> <br/>

<input type="submit" name="Query" value="Query" /> <br/>
</form>

<?php
$s = ""; $nl = "<br/>";
switch ($_POST['f']){
case &#391;':
$conn=odbc_connect('mysqldsnone','root','katipatan g');
$sql = $_POST['txtQuery'];
$rs=odbc_exec($conn,$sql);
echo "<table width="60%">
";
while (odbc_fetch_row($rs)){
$abbr=odbc_result($rs,"abbr");
$fullname=odbc_result($rs,"fullname");
$link=odbc_result($rs,"link");
echo "<tr>
<td colspan="3" background="blue.png">
<p class="white-text">".$abbr."</p></td></tr>
";

echo "<tr><td>".$abbr."</td><td>".$fullname
."</td><td><a
href="".$link."">".$link."</a></td></tr>
";

$s .= $abbr.",".$fullname.",".$link."
";
//making the comma separated string here
}

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1) present for asking how many books they want to search for
2) display multiple rows of the same input fields depending on how many books they say they want to have searched for?i.e

title|author|publisher|etc
title|author|publisher|etc
title|author|publisher|etc

3) when these are submitted they could see these above the next part of the form where they enter their details with the option to go back and delete/amend.
4) send all the info to my colleague.

if so has anyone seen a similar script that I could take a look @ to see if I can hack it to suit my needs?

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<font color="green">This is green</font>

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script from my html doc, I have tested connectivity to the databse and
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functioning properly, the problem is I'm not sure how to get the
script to see what option the html form is sending, I thought I could
use:

$query = "SELECT * FROM table WHERE email =
'{$_GET['selecteduser']}@mydomain.com'";

but that doesn't seem to be working properly. Maybe the HTML document
is sending it correctly? Here is my form:

<form action="report_results.php" method="post">
<select name="selecteduser">
<option value="selecteduser">Select One:</option>
<option value="user1@mydomain.com">user1</option>
<option value="user2@mydomain.com">user2</option>
</select>
<input type="submit" name="submit" value="Go!">
</form>

This form calls to the php script which then takes the input from the
HTML form and processes it into the $_GET query and sends it to the
while loop in the script, I'm not sure why this is not working? Here
is my php code

PHP:
--------------------------------------------------------------------------------
<?php
$db = mysql_connect("localhost", "sqluser", "sqlpasswd") or
die("Could not connect to Mysql");
if (!$db == False)
{
mysql_select_db("mydb");
$query = "SELECT * FROM table WHERE email =
'{$_GET['selecteduser']}@mydomain.com'";

$result = mysql_query($sql,$db);
while ($row = mysql_fetch_row($result))
{
print "<tr>";
foreach ($row as $field)
{
print "<td>$field</td>";
}
print "</tr>";
}
mysql_close($cn);
}
else
{
print "Problem Connecting to the Database<br>";
}
?>
------------------------------------------------------------------------------

Passing Form Variables To A Pop-up
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Passing A Variable From A Form To Php
I don't seem to be able to send trough the variable 'language' from my
form to the php-variable $language that I want to use in my session...
I first tried in the form with a drop down menu (select) and now with
radio-buttons but it won't work... What am I doing wrong?
BTW: the variable 'toevoegen' is passed correctly from the form to the
php.

<?php

session_start();
session_register('language');

echo("Taal is $language <p/>");
echo("Toevoegen=$toevoegen <p/>");
if (!IsSet($language)){

$result = mysql_query("SELECT * FROM languages ORDER BY mylanguage");
if (!$result) {
echo("<P><b>Fout bij uitvoeren query: </b>" .
mysql_error() . "</P>");
exit();
}
echo("<FORM ACTION='$PHP_SELF' METHOD='POST'><INPUT TYPE='hidden'
NAME='toevoegen' VALUE=&#391;'>");
while (($row = mysql_fetch_array($result))){
echo("<INPUT TYPE='radio' NAME='language'>".$row["mylanguage"]);
}
echo("<INPUT TYPE='submit' NAME='kies_taal' VALUE='Choose
language...'>");
echo("</FORM>");
}

else{
echo("Uw taal is $language !");
}
?>

Passing Form Data
I have a project that consists of a large quiz that displays multiple questions per page from a database and then saves those answers to another database table. The issue I'm having is with a form that consists of radio buttons and check boxes. The form is only submitting the last checked value for the check boxes rather than all checked values. I'm sure this is an easy fix but my mind is about to explode from a full day's work and a lot of time trying to figure this out, so I was wondering if someone could give me a hand. Code:

Passing Variables Through A Form
I have a setup where I am displaying lots of information, all of it comes from contact forms and is stored in a database. Then can be viewed on one page, through the scripts. One feature is that you can click on an email address to send an email to that specific user. When you click their email, the form comes up fine, and I have been playing with this for awhile.. I am having trouble getting the variables passed through so that I can send the email and update the database. Code:

Passing Form Variables
I'm trying to make a page that will let you change the order in which some items are displayed. The problem I'm having is passing back the id value of the item that you want to move up or down in the display order. Here is the code:

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Lets say response.php, with parameter ?val=data.  ie http://abc.com/response.php?val=data.

On this php page, I want to perform some processing, but ultimately dont want to display any html form with this page.  I need some way to perform my processing on this php page, then immediately redirect to another php to display the next form, with the results.  Can anyone advise on how this is achieved?

So for example, I want it to then  invoke display.php?mode=1&conf=1, which has the formal display with all the results.  All this with NO user input.

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I am trying to pass the variable ($lang) , depending on the value of this variable, the page will look different (English or French )

I guess I am doing this the wrong way, I thought by giving both images the same name, but different values, it would work.... but it is not working.

here is the HTML code of the form itself :

Code:
<!--LANGUAGE SELECTION -->
<FORM NAME="pick_lang" METHOD="post" ACTION="<? echo "$PHP_SELF"; ?>">
<table border="0" cellpadding="0" cellspacing="0" width="165">
<tr>
<td rowspan="2"><img name="shadow_drapeau_r1_c1" src="tble_img/shadow_drapeau_r1_c1.gif" width="102" height="21" border="0"></td>
<td>
<INPUT TYPE="image" BORDER="0" NAME="lang" value="en" SRC="tble_img/shadow_drapeau_r1_c2.gif" WIDTH="21" HEIGHT="14">
</td>
<td rowspan="2"><img name="shadow_drapeau_r1_c3" src="tble_img/shadow_drapeau_r1_c3.gif" width="8" height="21" border="0"></td>
<td>
<INPUT TYPE="image" BORDER="0" NAME="lang" value="fr" SRC="tble_img/shadow_drapeau_r1_c4.gif" WIDTH="21" HEIGHT="14">
</td>
<td rowspan="2"><img name="shadow_drapeau_r1_c5" src="tble_img/shadow_drapeau_r1_c5.gif" width="13" height="21" border="0"></td>
</tr>
<tr>
<td><img name="shadow_drapeau_r2_c2" src="tble_img/shadow_drapeau_r2_c2.gif" width="21" height="7" border="0"></td>
<td><img name="shadow_drapeau_r2_c4" src="tble_img/shadow_drapeau_r2_c4.gif" width="21" height="7" border="0"></td>
</tr>
</table>
</FORM>
<!--END LANGUAGE SELECTION -->

I don't want to set images with links (<A HREF="$PHP_SELF?lang=$lang"> works, but I want the URL to remain clear of data)


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