Populating DHTML Menu From MySQL
I have a client that would like to have drop down menus added to a nav bar that is generated from MySQL. Is it possible to have a dynamically driven DHTML menu from MySQL?
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Populating A Drop Down Menu
How would I go about populating a Drop Down menu from data in MySQL? If you can show me wither a URL to learn this, or if you feel like telling me here, that would be great.
Populating City,state,country Drop Down Menu
In the registration form I have city, state, country fields. I was wondering if there was a database available on the net which has the list of states in each of the countries. That way when a user selects a country I could automatically populate the state drop down menu ...
Populating "Month" Dropdown Menu
I can get the current month to display in a text box by inserting value="<? print strftime("%B"); ?>"> into the code for that particular text box on a form but how can I populate a drop down with names of all the months with the current one being 'default' as it would be in the text box example?
Php Within Dhtml, Is That Possible?
in a dhtml page generated from php I want to include a file which is in fact the body of the dhtml page. My hosting ISP does not allow SSI but supports php includes. In the dhtml page, the generated statment <?php include('fspecs') ?> is ignored. I've the feeling that I'm overlooking something in the way php is parsing dhtml (if it does). The dhtml code saved in a file execute correctly after that...
Populating Array With Mysql Results
I'm returning a result set of one field in a table, and want to populate an array with the results. I can't for the life of me figure out a simple way to do this without using mysql_fetch_array() to cycle through the results, append that to a var, then explode that into a var and pass that. PHP Code:
Populating Arrays From MySQL Query
I have the following code: http://pastebin.com/746601 The field 'material' in 'is_material' contains multiple values for each record in 'is_details'. Because of this I have used 'is_material_lookup' as a reference lookup table containing the 'style_code' and 'material_code' which refer to their full details in the respective tables. Currently I have got the script outputting all the details and one material then in the next block of data, repeating the details with a different material. What I would like to achieve is having 1 block of data with a list of all materials in that, instead of the repeat, but sadly I can't know exactly how to do it.
Populating Dropdown With Mysql Entries
I would like to create a combobox in Flash which is populated with mysql data and programmed with php. For example: There are 3 entries in database .ie. apple, bannana, peach. Now these I want in combobox in Flash MX/flash5.
Mysql Php Dynamic Menu
I am trying to write a script that will create dynamically a menu from MySQL database. The database table is a product categories table and it has the folowing filed: category_id, parent_category_id, category_name (some other fileds are there as well but these are enough to figure out the logic) I know that I have to store all the product_categories records in a temp array and then some how go through them and store the level of each record in the menu.... If you have done something like that I suppose you know what I mean and I would much appreciate to give me a hint here ... I had a look in the phpLayersMenu from sourceforge but it is really advanced OO code and I cannot understand the logic.... My target is to create a Tree menu with no pre - defined number of records...
Mysql / Dropdown Menu
what i am trying to do is to make a system with a few input pages and edit and read pages.. so right now i got the input/edit/read pages working. (yay) But now I want to have on 1 input page a dropdown menu that reads its information from the database. and that if i go to the page i can select a value out of the db and submit that inside my form and that it reminds the value if i view or edit the page. So what i got now is a little system that is able to add/remove/edit a value inside a field called "drop01" Well now i got a other input page called "input01.php" inside this script i want to have the dropdown menu that reads its values from the "drop01" field. PHP Code:
[PEAR:QuickForm] Dynamically Change A Dropdown Menu According To Another Menu?
I've been using QuickForm for a few months now and I am now given a new challenge: I've got a search form with a dozen of dropdown menus, the first dropdown menu being "Brand". If you select either Brand A, B, C, D... Z, the second dropdown menu "Model" must be dynamically changed to model AA, AB, AC, AD..., according to the models manufactured by the brand selected in the first box. I've seen that done on quite a few sites, but never found if QuickForm had a quick & clean way of doing that.
Select List/Menu Using PHP And MYSQL
Here is my code: <select name="country" class="sidelinks"> <?php do { ?> <option value="<?php echo $row_AllCountries['country_ID']." ";?>"<?php if ($row_AllCountries['country_ID'] = $acountry) { echo "selected"; }?> > <?php echo $row_AllCountries['countryname'];?></option> <?php } while ($row_AllCountries = mysql_fetch_assoc($AllCountries)); ?> </select> A few words to describe: -$row_AllCountries['country_ID'](get from MySQL) is a unique country ID number -$row_AllCountries['countryname'](get from MySQL) is the name of the country -$acountry is the country ID number that i want to be selected when the form loads I have all the values and country names named OK...the only problem is that when the form loads it selects the last country.
MySQL Database In A Pulldown Menu
I have a script that I am trying run with PHP, that gets the contents of a database, and then arrange them in a pulldown menu. I then have that selected Name, for instance, and then I can choose between 2 Buttons. Edit and Delete. PHP Code:
Dynamic MySQL Nav Menu Sorting
I have this dynamic menu and I want to change the order of the menu items... I added a column in the database wich has an integer value for ordering the menuitems. But the only way is by hardcoding them into the database. I would like a way to sort them with drag-and-drop or with up/down arrows. Do you think that except PHP & MYsql I will need Javascript as well ? Any ideas how to do that ?
Mysql Fetch With Drop Down Menu
Im trying to do somekind of dropdown menu taking information from the database but im not quite sure how this could be done with my knowledge. alright so lets say i have a table named: projects SELECT name FROM project. and it will put all the data found in a html drop down menu?
Simple Menu, MySQL Query Question
I'm creating simple menu. MySQL: +----+-----+----------------------+ | id | sid | Title | +----+-----+----------------------+ | 1 | 0 | Main Menu 1 | 2 | 0 | Main Menu 2 | 3 | 1 | SubMenu 1 of menu 1 | 4 | 1 | SubMenu 2 of menu 1 | 5 | 1 | SubMenu 3 of menu 1 | 6 | 2 | SubMenu 1 of menu 2 +----+-----+---------------------- What should be my query? I'm trying to select all titles, and display them: Main Menu 1 - SubMenu 1 of menu 1 - SubMenu 2 of menu 1 - SubMenu 3 of menu 1 Main Menu 2 - SubMenu 1 of menu 2
Drop Down Menu Where The Items Are From A MySQL Select Query
I am just starting programming in PHP and wonder if it is possible to have a drop down menu where the items are from a MySQL select query. I am registering people for a weekend seminar and want to have a list of valid weekends to choose from on the form. Any pointers to scripts or PHP references that will help would be appreciated. I am using the book "Build your Own Database Driven Website Using PHP & MySQL" to get me started, but also need recommendations for a general primer to php.
Search Drop Down Menu To Choose Mysql Table
I have currently made a simple PHP search script which, when data is entered in a text box and it's submitted, it queries a table in a MYSQL database and returns information. This works. However, I want to have a combo box beside the text box with options to query different tables depending on which item in the combo is selected. At the moment it searches a news articles table by content and title. But I want to adapt the script so that it searches another table which holds information on people for example. It currently gets the item from the text box with the code:
Populating A Select Box
What I want to do for members of my website is to allow them to click a button that will add their name to a list that populates a select box. I can do this on my own, but I was curious if I have to use a database in order for this to be possible.
Populating Two Combo Boxes
I have one combo box (Category) which is populated by a MySQL table using php. I am trying to use the onchange javascript to submit the value selected so that I can populate the other combo box (sub-category) based on what was previously choosen. So can anybody give me a clue on how to submit the first boxes value so that the second can see what was selected (javascript function).
Populating Dropdown List
I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:
Dymanic Populating Checkboxes
i like to retrieve a value from DB, accordingly i like to display the checkbox, either checked or not. Now im able to retrieve the value from DB, i can show even show the checkbox, but i cant make it checked???? the Code i used to display as follows, #Require the database class require_once('../dbinfoinc.php'); #Get an array containing the resulting record $query = "SELECT * FROM event"; $result = mysql_query($query); $num=mysql_numrows($result); mysql_close(); $i=0; while ($i < $num) { if(($i % 2) == 0) { $c = '"TableDetail"' } else { $c = '"TableDetail2"' } $event_id=mysql_result($result,$i,"event_id"); $event_name=mysql_result($result,$i,"event_name"); $event_publish=mysql_result($result,$i,"publish"); // if(($event_publish) == 0) { $event_publish = 'No' } // else { $event_publish = 'YES' } $take_action = 'Delete' echo "<tr> <td Class='navText' align='center' class=$c>$event_id</td> <td class='navText' class=$c>$event_name</td> <td class='navText' align='center' class=$c><input type='checkbox' name='publish' if($event_publish==1){'CHECKED'}?></td> <td class='navText' align='center' class=$c><a href='delete_event.php?event_id=$event_id'>$take_action</a></td></tr>"; $i++; } ?>
Re-populating A Form If Errors
I am learning php. I have created a simple Web page with a form. After receing the POST request, I do some error checking. In case of errors, I would like to re-post the page, but with the current values for each field. I have organized my files like this: 1) Webpage with the form (all in html, form action points to a php file) 2) php file that receives the request.
Populating Form Text Box.
I have a PHP form for entering data on-line into a mySQL table.. Because of the intended search facility, I require one field in the form to be completed with exact and precise item names and spelling. In testing, I had achieved this with look-up tables. Ideally I would like the selected item from one of five drop-down lists to autopopulate the form text field when selected. Alternatively at least the option of copy and paste. Copy and paste - for some reason will not work. Autofill worked fine on a test form with no database connection and in standard HTML and javascript, however, once the PHP is added to the page neither method works. Could anyone please point me in the direction of how to get the autofill to work?
Populating A Select Box From A Database
I have a subscription database that allows you to edit a subscribers data. For example, you enter a search term like "Bob" and it returns a list of everyone named Bob. You click the one you want and it goes to a subscriber detail page, where all of his data is populated to a form. You can directly edit this form and click save to overwrite it. The only issue is the select boxes (drop downs) - say I have four options in the drop down box, red, blue, green and black. On my details page for bob I end up with five, I have those four PLUS whatever was saved for his color, so it shows up twice. If Bob is green, my select box looks like: Green Red Blue Green Black How can I make it so that Green only shows up once?
Populating Drop Down And Table
I have a database with the following fields. Name | Company | Date values in each column could be repeated, or not. as in there could be several same names with the same company with different dates, or different names with same company. How do I populate a table with this info and have drop down boxes, so that I can narrow down the search? For example: Name | Company | Date 12 | 1 | 1929 13 | 1 | 1929 14 | 1 | 1929 12 | 2 | 1929 12 | 4 | 1929 13 | 1 | 1941 12 | 6 | 1929 So if in the drop down I select '12' under name, only those entries with 12 are shown, and then I can further sort it by selecting only '1' under Company. Hope I'm clear, I manage to complicate things when I post them.
Populating An Auto_increament Attribute
I have just designed a BD. there are companies with auto increament which are integer. When I try to populate it after i tool value from another form and try to insert it into a table i recieve an error! I don't ask the companyID value from user as it is auto increament. Don't tell me to put NULL for that entry as it didn't work as well! Code:
Populating Table Information
I am trying to dynamically generate bgcolors with to help populate some information for a site. Here is the code:
Auto Populating A Drop Down Box
Basically I'm setting up a website which needs an populated drop down box made up from all fields in a specific column of a table in a mysql db.... Here's the code I've made up using various tutorials.... <?php $user = ""; $host = "" $password = "" $dbName = "" /* make connection to database */ mysql_connect($host, $user, $password) OR DIE( "Unable to connect to database"); mysql_select_db($dbName); //did you forget this line? $sql = "SELECT model FROM usedVehicles"; $query = mysql_query($sql) or die(mysql_error() . "<br>$sql"); //use the or die(...) part ONLY IN DEVELOPMENT ?> <form action="action" method="post"> <select name="option"> <?php while ($row = mysql_fetch_array($result)) { echo "<option value="" . $row['model'] . "">" . $row['model'] . "</option> "; } ?> </select> <input type="submit"> </form> I've left out the connection details for obvious reasons... When I upload and try to test this, jus a blank drop down appears... there are definately fields in the column as I have tried the query on phpMyAdmin.
Populating Fresh Data
Im building a live web chat using php, mysql, javascript, ajax I am fine with sending and retreiving data in real time using ajax as the transfer protocol However, my problem, which is becoming a nightmare, is how to I display it !! Lets say the below is the chat screen, <div id="messages"> Jamie - Hello Peter = Hi Jamie = Nice Day Peter = I know </div> Lets say Jamie's next message is "What are you doing today". I can send that off to the database no problem and I can get peters live chat to pull that message in, however, how do I get it to display underneath Peter = I know As a practice I was using document.getelementbyid('messages').innerHTML = document.getelementbyid('messages').innerHTML + "<BR>What are you doing today" That works, but, lets just say the chat gets to 1000 lines, for each new message those 1000 lines have to be pulled out via javascript, a new line written to it and then printed back in the div Im not sure but I'd take a good guess at this not being optimal and will cause CPU load on the users machine What is the best way to do this! Chat messages are deleted after 1 minute, but that doesnt matter because by then they have already been sent the the users chat. Just incase you are thinking of completely repopulating there chat with every message they have sent since the chat started..
Reading Directories, Populating Select Box
Can anybody tell me how to read through a directory, get the file names and populate a select box(pulldown menu) with these names? I know how to loop through a directory using something like this: while ($files = readdir($handle)) { $ext=substr($file,-4); if ($files != "." && $files != ".." && $ext == ".php") { do some wild and crazy stuff here; } } It's the populating the select box (pulldown menu) while doing this that I need the help on.
Populating Form Item From SQL Enum Set Rev#2
$sql = "SHOW COLUMNS FROM table LIKE 'subject' "; $qry = mysql_query($sql) or die("Query not valid: " . mysql_error()); $res = mysql_fetch_object($qry); // This returns a row with a field 'Type' containing 'enum(...)' $res->Type = str_replace('enum('', '', $res->Type); $res->Type = str_replace('')', '', $res->Type); //now the string is something like this: one','two','three $temp = explode('','',$res->Type); //temp is an array with as much elements as the enum while ($temp) print array_pop($temp); This way is much more easier using the elements since they are elements of an array. Cleaver isn't it?
Populating A Form Wth Database Info
I've coded a piece of code which populates a form with data read from the database: $connection=mysql_connec ("localhost", "f2821842", "f2821842"); $result=mysql_select_db("QUERIES"); $query=mysql_query("Select * from Emp_Details where emp_num = '$employnum'"); while($row=mysql_fetch_array($query)) {$empname=$row['emp_name'];} <form name="webregform" action="webadmin2.php" method="post"> <input name="requiredname" type="text" size="30" value="<?php echo "$empname"; ?>"> </form> When I echo the $requiredname, I get spaces and no data, and I know that $empname is not a space-it does read a value in a database. 1. How can I get $requiredname to print a value?
Populating Dynamically Generated TextFields
If one assigns something to the value iattribute off an input /text field, that value will be displayed when the form is loaded. My problem is, when building a form dynamically, the only way I can get the text to show is by doing the above, however, as this is an update form, when the form POSTS to processUpdate.php, both the data entered by the user AND the data in the value attribute are inserted/updated. So, how does one dynamically build a form where the data is displayed in the text fields but value atttribute is not set. PHP Code:
Populating Form Fields With Variables
The script itself works fine: mail gets sent. If there are any missing fields the form displays again with a list of the missing fields, but I can't get the form fields of the reloaded form to be populated with teh existing values. PHP Code:
Populating A Drop Box With Results From Database
I have a MySQL database with a table (category) with two fields, catId (int) and category (char(50)). What I want to do is to get all category names in this database and place all of them into a dropdown box on a web page so that the user can choose from the list of available categories.
Populating Table With Text File
My web hosting service uses phpMyAdmin and at the bottom of the screen iis an area where I can upload a text file to populate a table. I have a table named groups with two fields: groups_idauto-increment primary groups_name So how do I create my text file to populate this table? I'm going to use MS Notepad. If it's set to auto-increment, do I need to include the number? If so, does it start at 0 (zero)? Would the file look like: 0,students 1,faculty 2, staff or just students faculty staff
PHP Not Populating Form Variables Passed Through POST Or GET
I"m running: Windows Xp SP2 Apache2 PHP5 MySQL4 Everything seems fine and dandy, and I can do scripting on server side, but for some reason I cannot get data from a form to be put into a variable. I have a simple form in an html page which submits, and in the php script that handles the input, none of the data in the form is going into the variables. My php.ini file does have all the GPC's in place(ie variable_order, the way they get processed).
Auto Populating Multiple Drop Downs.
im trying to create two dropdowns, i need the first one to be the category and the second one to be the subcategory. The category drop down autopopulates with the correct info from the database. and uses the table "category", the value of each drop down is represented by the "cat" field in the table (cat is basically and integer id number) and "Category" is used as what the user actually sees in the drop down (category is the actual word of the category). Once the category is selected i would like to have the sub category auto populate with everything that has the same values as the selected category (cat) Here is a break down of how the tables work. Table 1 Name: "category" Fields for Table 1: "cat" (the id number), "category" ( the actual name of the category) Table 2 Name: "subcategory" Fields for Table 2: "cat" (corresponds with the cat id from table 1 to pull the correct data), "subc" (the basic id of the subcategory), "subcat" the actual name of the subcategory. so the way i see it, have a normal drop down populated by a php query. then on change, populate subcategory drop down where cat = cat and display sub category.
Populating The Drop Down And Pressing The Submit Button
1. The first is I have two drop down menus. The first is "year" and the second is "mfr". When a user selects a year from the drop down it then populates the second drop down, mfr, from the MySQL database. Theat is working fine. But the problem I am having is the "submit" button (which I have labeled as "browse"). When I click it. Nothing happens, no action tacks place. I have looked over the code and I can't figure it out. (See Code Box 1 Below). 2. Right now the "mfr" drop down is populated by the MySQL database and reads with a list like "Acr", "Alp", etc. These are abreviations. I need to set up an array to have them instead read the entire mfr name. Example: Instead of "Acr" it needs to be "Acura". Instead of "Alp" it needs to be "Alpine". I need these full names to appear in the drop down. I know I need to do something like this (See Code Box 2 Below) but I can't get my finger on it. Code:
Populating Form From Database, Then Passing Results To Next Page
I have a multiple select input in a form that's being populated by a row from my database as such: <input type="checkbox" name="subm[]" value="$row[ID]"> That part is working fine as I can check the displayed page using View Source and see that the value is the correct row number from the database. It is then being submitted on a form by $_POST method to another page where I want to evaluate the checkboxes and display the contents of the entire row that corresponds to each value="$row[ID]" that have been checked. But I can't seem to get it to work. I'm having a problem passing the selected value. Can someone point me in the right direction? $query = ("SELECT * FROM `table`"); $result = mysql_query($query); print "<p>Data for Selections:"; print "<table border=2><tr><th>You chose:"; foreach ($_POST['subm'] as $value) { print "<tr><td>"; print "$row[ID]; "; print mysql_field_name($result, 1) . ": " . $row[name]."<br>"; print mysql_field_name($result, 2) . ": " . $row[address]."<br>"; print mysql_field_name($result, 3) . ": " . $row[city]."<br>"; print "</td></tr>"; print "</table> "; } if (!isset($_POST['subm'])){ print "<p>No matching entry "; } mysql_close();
Populating SELECT Multiple Form Field And Inserting Into Db
I have an update form where I'm trying to populate a SELECT multiple field with a list of 48 categories, from tbl work_cat. And show, as SELECTED, the one or many choices that the user had previously selected from the 48 categories which are stored in tbl cat_relations as $relation_cat. Then allow the user to update their selections and update the database. But I can't get my form to work. First problem, I can't get the SELECT field on the form to show the categories, and then I don't know where to go from there. Below are my form page and my processing page. Code:
Dynamically Populating Listboxes Based On Previous Selection
How do I populate the second listbox in this form based on the selection of the first listbox? The first listbox is populated by this query: $year_query = "SELECT distinct year FROM bench_data"; The second listbox should essentially be populated by this: $industry_query = "SELECT distinct comp_desc FROM comp_desc, benc_data where $_POST['year']=bench_data.year and bench_data.comp_key=comp_desc.comp_key"; I know this is alot to ask, but please EXPLAIN the code. I am new and need the explanation elucidated and not just supplied code that will accomplish the goal. Code:
Populating Form In Parent Window With Value From Popup Window
I have a text box in the parent window.. now i want to populate this text box with a user_id that i will get from query within a popup window.. How do i get the value from the popup window to be passed to the main window form field in php. I know how it can be done in javascript but when i tried combining javascript and php i dont get the desired result.
Getting Another Menu
how can I do to create another menu with the results from the options they choose? For example, they are looking for their grades so they choose in a first menu the carreer, in other menu the grade, and then when they finish choosing the grade, It appear automaticaly in other menu all the names of the subjects concerned to te carreer and grade given.
Php Menu
How do I have The menu and the context information display at the same time? Code:
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